5. Solving recurrences

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1 5. Solvig recurreces

2 Time Complexity Alysis of Merge Sort T( ) 0 if 1 2T ( / 2) otherwise sortig oth hlves mergig Q. How to prove tht the ru-time of merge sort is O( )? A. 2

3 Time Complexity Alysis of Merge Sort T( ) 0 if 1 2T ( / 2) otherwise sortig oth hlves mergig Q. How to prove tht the ru-time of merge sort is O( )? A. We hve see severl methods: Recursio tree Sustitutio (y iductio) 3

4 Proof y Recursio Tree T( ) 0 if 1 2T ( / 2) otherwise sortig oth hlves mergig #odes(merge time): T() T(/2) T(/2) 2(/2) T(/4) T(/4) T( / 2 k ) T(/4) T(/4) 2 4(/4)... 2 k ( / 2 k )... T(2 ) T(2 ) T(2 ) T(2) T(2 ) T(2 ) T(2 ) T(2 ) T(1) T(1) T(1) T(1) T(1) T(1) T(1) T(1) T(1) T(1) T(1) T(1) T(1) T(1) T(1) T(1) /2 (2) merge time: 2

5 Proof y Iductio/Sustitutio (whe is power of 2) Clim. If T() stisfies this recurrece, the T() = 2. T( ) 0 if 1 2T ( / 2) otherwise sortig oth hlves mergig ssume is power of 2 Pf. (y iductio o ) 5

6 Proof y Iductio/Sustitutio (whe is power of 2) Clim. If T() stisfies this recurrece, the T() = 2. T( ) 0 if 1 2T ( / 2) otherwise sortig oth hlves mergig ssume is power of 2 Pf. (y iductio o ) Bse cse: = 1. Iductio hypothesis: T() = 2. Step: show tht T(2) = 2 2 (2). Q. How do we proof this step? Now for 2 (ot +1 s we re used to)! 6

7 Proof y Iductio/Sustitutio (whe is power of 2) Clim. If T() stisfies this recurrece, the T() = 2. T( ) 0 if 1 2T ( / 2) otherwise sortig oth hlves mergig ssume is power of 2 Pf. (y iductio o ) Bse cse: = 1. Iductio hypothesis: T() = 2. Step: show tht T(2) = 2 2 (2). Now for 2 (ot +1 s we re used to)! T (2 ) 2T ( ) (2 ) Iductio hypothesis 7

8 Proof y Iductio/Sustitutio (whe is power of 2) Clim. If T() stisfies this recurrece, the T() = 2. T( ) 0 if 1 2T ( / 2) otherwise sortig oth hlves mergig ssume is power of 2 Pf. (y iductio o ) Bse cse: = 1. Iductio hypothesis: T() = 2. Step: show tht T(2) = 2 2 (2). Now for 2 (ot +1 s we re used to)! T (2) 2T () (2) (2) (2) 8

9 Proof y Iductio/Sustitutio (with roudig) Clim. If T() stisfies the followig recurrece, the T(). T( ) 0 if 1 T / 2 T / 2 mergig solve left hlf solve right hlf otherwise 2 Pf. (y iductio o ) Bse cse: = 1. Defie 1 = / 2, 2 = / 2. Hypothesis: ssume true for 1, 2,..., 1. Step: 9

10 Proof y Iductio/Sustitutio (with roudig) Clim. If T() stisfies the followig recurrece, the T(). T( ) 0 if 1 T / 2 T / 2 mergig solve left hlf solve right hlf otherwise 2 Pf. (cotiued) Step: T ( ) T ( 1 ) T ( 2 ) Iductio hypothesis 10

11 Proof y Iductio/Sustitutio (with roudig) Clim. If T() stisfies the followig recurrece, the T(). T( ) 0 if 1 T / 2 mergig solve left hlf solve right hlf T / 2 otherwise 2 Pf. (cotiued) Step: T ( ) T ( 1 ) T ( 2 )

12 Proof y Iductio/Sustitutio (with roudig) Clim. If T() stisfies the followig recurrece, the T(). T( ) 0 if 1 T / 2 mergig solve left hlf solve right hlf T / 2 otherwise 2 Pf. (cotiued) Step: T ( ) T ( 1 ) T ( 2 ) ( 1 ) 1 /2 2 / 2 2 / Becuse right side is iteger, roudig to erest iteger is OK. 12

13 Time Complexity Alysis of Merge Sort T( ) 0 if 1 2T ( / 2) otherwise sortig oth hlves mergig Q. How to prove tht the ru-time of merge sort is O( )? A. We hve see severl methods: Recursio tree Sustitutio (y iductio) 13

14 Time Complexity Alysis of Merge Sort T( ) 0 if 1 2T ( / 2) otherwise sortig oth hlves mergig Q. How to prove tht the ru-time of merge sort is O( )? A. We hve see severl methods: Recursio tree Sustitutio (y iductio) We do t like proofs. C t you give us geerl rule for the complexity of recursive fuctios? 14

15 Geerl Recursio Tree for 1, 1, T( ) (1) if 1 T ( /) f ( ) otherwise recursive clls comiig 15

16 Geerl Recursio Tree for 1, 1, T( ) (1) if 1 T ( /) f ( ) otherwise recursive clls comiig #odes(time): T() f() T(/) T(/) T(/) f(/) 16

17 -1+ Geerl Recursio Tree for 1, 1, T( ) (1) if 1 T ( /) f ( ) otherwise recursive clls comiig #odescomiig: T() f() T(/) T(/) T(/) f(/) T(/ 2 ) T(/ 2 ) T( / k ) T(/ 2 ) T(/ 2 ) 2 f(/ 2 )... k f( / k )... T(1) T(1) T(1) T(1) T(1) T(1 ) opertios i the leves T(1) T(1) 1 k 0 k f(1) f k

18 Mster Method for 1, 1, T( ) (1) if 1 T ( /) f ( ) otherwise recursive clls comiig So, T ( ) 1 k 0 where first term is cost of ll suprolems of size 1, d secod term cost for comiig i ech level. k f k Three commo cses: Ruig time domited y cost t leves Ruig time evely distriuted throughout the tree Ruig time domited y cost t root Cosequetly, to solve the recurrece, we eed oly to chrcterize the domit term, or f () 18

19 Mster Method Give recurrece of the form T( ) T ( /) f () We c distiguish three commo cses: 1. Ruig time domited y cost t leves: if f ( ) O the T ( ) for ε > 0 2. Ruig time evely distriuted throughout the tree: if f ( ) the T ( ) 3. Ruig time domited y cost t root: if f ( ) the T ( ) f ( ) for ε > 0 If f() stisfies regulrity coditio: f(/) c f() for some c < 1 (polyomils lwys do) The mster method cot solve every recurrece of this form. 19

20 Summry Mster Method Extrct,, d f() from give recurrece Determie Compre f() d symptoticlly Determie pproprite Mster Method cse d pply: 1. Ruig time domited y cost t leves: if f ( ) O the T ( ) for ε > 0 2. Ruig time evely distriuted throughout the tree: if f ( ) the T ( ) 3. Ruig time domited y cost t root: if f ( ) the T ( ) f ( ) for ε > 0 Cse 3: Oly If f() stisfies regulrity coditio: f(/) c f() for some c < 1 (polyomils lwys do) 20

21 Exmples Extrct,, d f() from give recurrece Determie Compre f() d symptoticlly Determie pproprite Mster Method cse, d pply Exmple. Alyze Merge Sort usig the Mster Method: T ( ) 2T ( / 2) ( ) 2, 2; 2 2 Q. Wht is domit? (leves, equl, root ode) 21

22 Exmples Extrct,, d f() from give recurrece Determie Compre f() d symptoticlly Determie pproprite Mster Method cse, d pply Exmple. Alyze Merge Sort usig the Mster Method: T ( ) 2T ( / 2) ( ) 2, f ( ) 2; ( ) this is cse 2, T ( ) 2 2 f ( ), so 22

23 Exmples Biry-serch(A, p, r, s): q(p+r)/2 if A[q]=s the retur q else if A[q]>s the Biry-serch(A, p, q-1, s) else Biry-serch(A, q+1, r, s) Q. Alyze complexity of iry serch usig the mster method (1 mi) A. Alysis: T ( ) T ( / 2) 1 23

24 Exmples Biry-serch(A, p, r, s): q(p+r)/2 if A[q]=s the retur q else if A[q]>s the Biry-serch(A, p, q-1, s) else Biry-serch(A, q+1, r, s) Q. Alyze complexity of iry serch usig the mster method (1 mi) A. Alysis: T ( ) T ( / 2) 1 1, 2; f ( ) (1) This is cse 2, T ( ) 2 1 f ( ), so: 0 (1) 24

25 Exmples Q. Use the mster method to solve the followig recurrece reltio: T ( ) 9T ( / 3) A. Alysis: 9, 3; f ( ) ( ) Q. Wht is domit? (leves, equl, root ode) 25

26 Exmples Q. Use the mster method to solve the followig recurrece reltio: T ( ) A. Alysis: 9, f ( ) This is cse 1, 9T ( / 3) 3; ( ) T ( ) f () O 2, so: 26

27 Exmples Q. Use the mster method to solve the followig recurrece reltio: T ( ) 3T ( / 4) A. Alysis: 3, 4; f ( ) ( ) Q. Wht is domit? (leves, equl, root ode) 27

28 Exmples Q. Use the mster method to solve the followig recurrece reltio: T ( ) 3T ( / 4) A. Alysis: 3, f ( ) This is cse 3, 4; ( ) 4 3 f () 0.793, so: f ( ) T ( ) WARNING: is ot polyomil Check regulrity coditio. Check regulrity coditio: f ( / ) 3( / 4) ( / 4) (3 / 4) cf ( ) OK, for exmple for c=3/4 (d this c < 1) 28

29 Exmples Q. Use the mster method to solve the followig recurrece reltio: T ( ) 2T ( / 2) A. Alysis: 2, 2; 2 2 f ( ) ( ) Q. Wht is domit? (leves, equl, root ode) 29

30 Exmples Q. Use the mster method to solve the followig recurrece reltio: T ( ) 2T ( / 2) A. Alysis: 2, f ( ) 2; ( ) 2 2 I ll e ck! This is ot cse 3, f (), for c>0, or oe of the others! Bck to sustitutio method d iductio proof (try 2 ). Becuse c for c>0 is ( ), so 1+c is ( ) so is ot ( 1+c ) 30

31 Exmples Q. Use the mster method to solve the followig recurrece reltio: T ( ) 4T ( / 2) 3 A. Alysis: 4, 2; f ( ) ( 3 ) Q. Wht is domit? (leves, equl, root ode) 31

32 Exmples Q. Use the mster method to solve the followig recurrece reltio: T ( ) 4T ( / 2) 3 A. Alysis: 4, 2; f ( ) This is cse 3, ( Check regulrity coditio: 3 ) f () 3 f ( ) T ( ) f ( / ), so: 3 3 / 2 (4 / 8) cf ( ) OK, for exmple for c=3/4 (d this c < 1) 4 32

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