( ) 2 ( ) 9.80 m s Pa kg m 9.80 m s m
|
|
- Emily Warren
- 5 years ago
- Views:
Transcription
1 Cpter luid Mecnics P. M = ρ V = ( k π( iron M = 0. k P P = = = 6. 0 N π ( P. Te Ert s surfce re is Tis fce is te eit of te ir: so te ss of te ir is π R. Te fce pusin inrd over tis re ounts to 0 0 ( π = P = P R ( π = = P R 0 ( π R ( N π ( P0 8 = = = k 9.80 s 5 P.6 ( P= P + ρ = P 0 k 9.80 s P =.0 0 P Te ue pressure is te difference in pressure beteen te ter outside nd te ir inside te subrine, ic e suppose is t.00 tospere. 7 Pue = P P0 = ρ =.00 0 P Te resultnt inrd fce on te ptole is ten = P = π = 7 5 ue.00 0 P N P.7 = 80.0 k 9.80 s = 78 N Wen te cup brely suppts te student, te nl fce of te ceilin is zero nd te cup is in equilibriu. ( P = = P = 78 = = = P IG. P.7
2 P. Te pressure on te botto due to te ter is So, Pb b = ρ z= b.96 0 P = P = On ec end, Pvere ( On te side, Pvere ( N don = = P 0.0 = 96 kn outrd = = P 60.0 = 588 kn outrd P.6 ( Usin te definition of density, e ve 00 ter = = = ρter 5.00 c.00 c 0.0 c Sketc t te rit represents te sitution fter of ercury te ter is dded. volue s been displced by ter in te rit tube. Te dditionl volue of ercury no in te left tube is. Since te totl volue of ercury s not cned, = = IG. P.6 ( t te level of te ercury ter interfce in te rit tube, e y rite te bsolute pressure s: P= P0 + ρter Te pressure t tis se level in te left tube is iven by P= P0 + ρh( + = P0 + ρter ic, usin eqution ( bove, reduces to ρh + = ρter ρter = ρ + / H Tus, te level of ercury s risen distnce of = (.00 c ( 0.0 c (.6 c ( + 0.0/ 50.0 P.7 P0 ρ.66 0 P : = 0.90 c bove te iinl level. P= P0 +Δ P0 = P = P Δ = Δ = 5 5 P.0 ( Te blloon is nerly in equilibriu: = B = 0 y y eliu pylod ρir V ρeliu V pylod = 0 Tis reduces to ( ρ ρ V.9 k 0.79 k ( 00 pylod ir eliu pylod Siilrly, = = = k
3 ( ρ ρ V.9 k k ( 00 pylod ir ydroen pylod = = = 80 k Te surroundin ir does te liftin, nerly te se f te to blloons. P.7 ( ccdin to rciedes, B= ρtervter =.00 c But B Weit of block ρ V ( c ( 0.0 c = = = = ood ood = ( = so = 0.0( = 7.00 c B= + M ere M = ss of led.00 ( 0.0 = 0.650( M M = ( ( 0.0 = 0.50( 0.0 = 800 =.80 k P.7 lo rte Q = s = v v Q / s π (0.0 = = =.6 s P.9 In te reservoir, te ue pressure is.00 N Δ P = = ro te eqution of continuity: v = v ( 5 ( v =.00 0 v v = (.00 0 Tus, is neliible in coprison to. v Ten, fro Bernoulli s eqution: v v P P P + ρv + ρy = ρv + ρy P.5 Wen te blloon coes into equilibriu, e ust ve B y =, blloon, He, strin = 0 He, strin is te eit of te strin bove te round, nd B is te buoynt fce. No, blloon blloon, He He ir = = ρ V B= ρ V nd, strin strin = L IG. P.5
4 Terefe, e ve ρ L irvblloon ρh ev strin = 0 ivin = ( ρ ρ V ir H e blloon strin ( π L k 0.00 / 0.50 k = (.00 = k P.5 Consider te dir nd pply Bernoulli s eqution to points nd B, tkin y = 0 t te level of point B, nd reconizin tt v is pproxitely zero. Tis ives: P + ρ( 0 + ρ( Lsinθ L B Vlve = PB + ρvb + ρ( 0 θ No, reconize tt P = PB = Ptospere since bot points re open to te tospere (nelectin vrition of tosperic pressure it ltitude. Tus, e obtin IG. P.5 vb = ( Lsin θ = ( 9.80 s 0.0 (.00 sin 0.0 vb =. s No te proble reduces to one of projectile otion it vyi = vb sin 0.0 = 6.6 s. Ten, v = v + ( Δy ives t te top of te rc (ere y = yx nd v = 0 yf yi 0 = ( 6.6 s + ( 9.80 s ( yx 0 y =.5 ( bove te level ere te ter eeres. x yf P.55 t equilibriu, y = 0 : B sprin, He, blloon = 0 ivin kl B ( = = + sprin He blloon But B= eit of displced ir = ρ V ir nd He = ρhe Terefe, e ve: kl = ρirvρhev blloon V IG. P.55 L = ( ρ ρ V ir H e blloon k
5 ro te dt iven, L =.9 k 0.80 k k 9.80 s 90.0 N Tus, tis ives L = 0.60 P.66 Let s stnd f te ede of te cube, f te dept of iersion, ρ stnd f te density of te, ρ stnd f density of ter, nd ρ stnd f density of te lcool. ( ccdin to rciedes s principle, t equilibriu e ve ρ s = ρ s = s ρ ρ Wit ρ = k ρ =.00 0 k nd s = 0.0 e et = 0.0( 0.97 = We ssue tt te top of te cube is still bove te lcool surfce. Lettin stnd f te tickness of te lcool lyer, e ve ρ s + ρ s = ρ s so ρ ρ = s ρ ρ Wit nd ρ = k = 5.00 = =.. e obtin (c Here = s, so rciedes s principle ives ( ( ( ρ ρ ( ρ ρ ( ( ρ s + ρ s s = ρ s ρ + ρ s = ρ s = s = 0.0 =
6 P.67 Enery f te fluid-ert syste is conserved. ( K+ U +Δ E = K+ U i ec f L = + v 0 v = L = s =. s P.68 ( Te flo rte, v, s iven y be expressed s follos: 5.0 liters = = 0.0 s 0.8 liters s 8 c s Te re of te fucet tp is π c, so e cn find te velocity s 8 c s flo rte v = = = 65 c s =.65 s π c We coose point to be in te entrnce pipe nd point to be t te fucet tp. v = v ives v = 0.95 s. Bernoulli s eqution is: nd ives P P = ρ v v + y y ρ P P = 0 k.65 s 0.95 s 0 k 9.80 s.00 + ( ( ( P P P ue = =. 0 P P.7 ( diverin stre lines tt pss just bove nd just belo te ydrofoil e ve P + ρy + ρv = P + ρy + ρv b t t t b b Inin te buoynt fce ens tkin yt yb Pt + ρ( nvb = Pb+ ρv b Pb Pt = ρvb( n P P v n Te lift fce is ( b t = ρ b(
7 liftoff, ρvb ( n = M v b M = ρ ( n Te speed of te bot reltive to te se ust be nerly equl to tis speed of te ter belo te ydrofoil reltive to te bot. (c v ( n ρ = M ( 800 k 9.8 s = = 9.5 s k.70
UCSD Phys 4A Intro Mechanics Winter 2016 Ch 4 Solutions
USD Phys 4 Intro Mechnics Winter 06 h 4 Solutions 0. () he 0.0 k box restin on the tble hs the free-body dir shown. Its weiht 0.0 k 9.80 s 96 N. Since the box is t rest, the net force on is the box ust
More informationME 354 Tutorial, Week#11 Non-Reacting Mixtures Psychrometrics Applied to a Cooling Tower
ME 5 Tutoril, Week# Non-Recting Mixtures Psychroetrics Applied to Cooling Toer Wter exiting the condenser of poer plnt t 5 C enters cooling toer ith ss flo rte of 5000 kg/s. A stre of cooled ter is returned
More informationChapter 2 Differentiation
Cpter Differentition. Introduction In its initil stges differentition is lrgely mtter of finding limiting vlues, wen te vribles ( δ ) pproces zero, nd to begin tis cpter few emples will be tken. Emple..:
More informationPhysics Dynamics: Atwood Machine
plce of ind F A C U L Y O F E D U C A I O N Deprtent of Curriculu nd Pedoy Physics Dynics: Atwood Mchine Science nd Mthetics Eduction Reserch Group Supported by UBC echin nd Lernin Enhnceent Fund 0-04
More informationV E L O C I T Y a n d V E L O C I T Y P R E S S U R E I n A I R S Y S T E M S
V E L O C I T Y n d V E L O C I T Y R E S S U R E I n A I R S Y S T E M S A nlysis of fluid systes using ir re usully done voluetric bsis so the pressure version of the Bernoulli eqution is used. This
More informationSOLUTIONS TO CONCEPTS CHAPTER
1. m = kg S = 10m Let, ccelertion =, Initil velocity u = 0. S= ut + 1/ t 10 = ½ ( ) 10 = = 5 m/s orce: = = 5 = 10N (ns) SOLUIONS O CONCEPS CHPE 5 40000. u = 40 km/hr = = 11.11 m/s. 3600 m = 000 kg ; v
More informationENSC 461 Tutorial, Week#9 Non-Reacting Mixtures Psychrometrics Applied to a Cooling Tower
ENSC 61 Tutoril, Week#9 Non-Recting Mixtures Psychroetrics Applied to Cooling Toer Wter exiting the condenser of poer plnt t 5C enters cooling toer ith ss flo rte of 15000 kg/s. A stre of cooled ter is
More informationMath 20C Multivariable Calculus Lecture 5 1. Lines and planes. Equations of lines (Vector, parametric, and symmetric eqs.). Equations of lines
Mt 2C Multivrible Clculus Lecture 5 1 Lines nd plnes Slide 1 Equtions of lines (Vector, prmetric, nd symmetric eqs.). Equtions of plnes. Distnce from point to plne. Equtions of lines Slide 2 Definition
More informationPage 1. Motion in a Circle... Dynamics of Circular Motion. Motion in a Circle... Motion in a Circle... Discussion Problem 21: Motion in a Circle
Dynics of Circulr Motion A boy ties rock of ss to the end of strin nd twirls it in the erticl plne. he distnce fro his hnd to the rock is. he speed of the rock t the top of its trectory is. Wht is the
More informationPhysics 218 Exam 2 Spring 2011, Sections , 526, 528
Physics 8 Exa Sprin, Sections 53-55, 56, 58 Do not fill out the inforation below until instructed to do so! Nae Sinature Student ID E- ail Section # : Solutions in RED Rules of the exa:. ou have the full
More informationPHYS 601 HW3 Solution
3.1 Norl force using Lgrnge ultiplier Using the center of the hoop s origin, we will describe the position of the prticle with conventionl polr coordintes. The Lgrngin is therefore L = 1 2 ṙ2 + 1 2 r2
More informationSolutions to Problems Integration in IR 2 and IR 3
Solutions to Problems Integrtion in I nd I. For ec of te following, evlute te given double integrl witout using itertion. Insted, interpret te integrl s, for emple, n re or n verge vlue. ) dd were is te
More informationThe Atwood Machine OBJECTIVE INTRODUCTION APPARATUS THEORY
The Atwood Mchine OBJECTIVE To derive the ening of Newton's second lw of otion s it pplies to the Atwood chine. To explin how ss iblnce cn led to the ccelertion of the syste. To deterine the ccelertion
More informationCHAPTER 10 LAGRANGIAN MECHANICS
CHAPTER LAGRANGIAN MECHANICS. Solution ( t (, t + αη ( t ( t (, t +αη ( t where (, t sinωt nd (, cos t ω ωt T V k ω t J α ω dt so: ( ( t t + + ( ω cosωt αη ω ( sinωt αη dt t t t α t J ( α ω ( cos ωt sin
More informationMethods for solving the radiative transfer equation. Part 3: Discreteordinate. 1. Discrete-ordinate method for the case of isotropic scattering.
ecture Metos for sov te rtve trsfer equto. rt 3: Dscreteorte eto. Obectves:. Dscrete-orte eto for te cse of sotropc sctter..geerzto of te screte-orte eto for ooeeous tospere. 3. uerc peetto of te screte-orte
More informationJURONG JUNIOR COLLEGE
JURONG JUNIOR COLLEGE 2010 JC1 H1 8866 hysics utoril : Dynmics Lerning Outcomes Sub-topic utoril Questions Newton's lws of motion 1 1 st Lw, b, e f 2 nd Lw, including drwing FBDs nd solving problems by
More informationOXFORD H i g h e r E d u c a t i o n Oxford University Press, All rights reserved.
Renshw: Mths for Econoics nswers to dditionl exercises Exercise.. Given: nd B 5 Find: () + B + B 7 8 (b) (c) (d) (e) B B B + B T B (where 8 B 6 B 6 8 B + B T denotes the trnspose of ) T 8 B 5 (f) (g) B
More informationEN40: Dynamics and Vibrations. Midterm Examination Tuesday March
EN4: Dynaics and ibrations Midter Exaination Tuesday Marc 4 14 Scool of Engineering Brown University NAME: General Instructions No collaboration of any kind is peritted on tis exaination. You ay bring
More informationSOLUTIONS TO CONCEPTS CHAPTER 6
SOLUIONS O CONCEPS CHAPE 6 1. Let ss of the block ro the freebody digr, 0...(1) velocity Agin 0 (fro (1)) g 4 g 4/g 4/10 0.4 he co-efficient of kinetic friction between the block nd the plne is 0.4. Due
More information4.2 - Richardson Extrapolation
. - Ricardson Extrapolation. Small-O Notation: Recall tat te big-o notation used to define te rate of convergence in Section.: Definition Let x n n converge to a number x. Suppose tat n n is a sequence
More informationMath 0230 Calculus 2 Lectures
Mth Clculus Lectures Chpter 7 Applictions of Integrtion Numertion of sections corresponds to the text Jmes Stewrt, Essentil Clculus, Erly Trnscendentls, Second edition. Section 7. Ares Between Curves Two
More informationSOLUTIONS TO CONCEPTS CHAPTER 10
SOLUTIONS TO CONCEPTS CHPTE 0. 0 0 ; 00 rev/s ; ; 00 rd/s 0 t t (00 )/4 50 rd /s or 5 rev/s 0 t + / t 8 50 400 rd 50 rd/s or 5 rev/s s 400 rd.. 00 ; t 5 sec / t 00 / 5 8 5 40 rd/s 0 rev/s 8 rd/s 4 rev/s
More informationME 309 Fluid Mechanics Fall 2006 Solutions to Exam3. (ME309_Fa2006_soln3 Solutions to Exam 3)
Fll 6 Solutions to Exm3 (ME39_F6_soln3 Solutions to Exm 3) Fll 6. ( pts totl) Unidirectionl Flow in Tringulr Duct (A Multiple-Choice Problem) We revisit n old friend, the duct with n equilterl-tringle
More informationPhysics Courseware Physics I
Definition of pressure: Force Area ysics Courseware ysics I Bernoulli Hydrostatics equation: B A Bernoulli s equation: roblem.- In a carburetor (scematically sown in te fiure) calculate te minimum speed
More informationIncluded in this hand-out are five examples of problems requiring the solution of a system of linear algebraic equations.
he Lecture Notes, Dept. of heical Engineering, Univ. of TN, Knoville - D. Keffer, 5/9/98 (updated /) Eaple pplications of systes of linear equations Included in this hand-out are five eaples of probles
More informationPhys101 Lecture 4,5 Dynamics: Newton s Laws of Motion
Phys101 Lecture 4,5 Dynics: ewton s Lws of Motion Key points: ewton s second lw is vector eqution ction nd rection re cting on different objects ree-ody Digrs riction Inclines Ref: 4-1,2,3,4,5,6,7,8,9.
More informationSolution to HW 4, Ma 1c Prac 2016
Solution to HW 4 M c Prc 6 Remrk: every function ppering in this homework set is sufficiently nice t lest C following the jrgon from the textbook we cn pply ll kinds of theorems from the textbook without
More informationDiscussion Question 1A P212, Week 1 P211 Review: 2-D Motion with Uniform Force
Discussion Question 1A P1, Week 1 P11 Review: -D otion with Unifor Force The thetics nd phsics of the proble below re siilr to probles ou will encounter in P1, where the force is due to the ction of n
More informationUNIT # 06 (PART I) SIMPLE HARMONIC MOTION EXERCISE I
UNIT # 6 (PRT I) SIMPLE HRMONIC MOTION EXERCISE I. f Hz. - - O O. sin t t 5 or 6 6 Phse difference () 5 O R JEE-Physics or 6 6 / cos fro phser () Node6\E : \Dt\\Kot\JEE-dvnced\SMP\Phy\Solution\Unit 5 &
More informationQuasi-geostrophic motion
Capter 8 Quasi-eostropic motion Scale analysis for synoptic-scale motions Simplification of te basic equations can be obtained for synoptic scale motions. Consider te Boussinesq system ρ is assumed to
More informationVector Spaces in Physics 8/6/2015. Chapter 4. Practical Examples.
Vector Spaces in Physics 8/6/15 Chapter 4. Practical Exaples. In this chapter we will discuss solutions to two physics probles where we ae use of techniques discussed in this boo. In both cases there are
More informationr = cos θ + 1. dt ) dt. (1)
MTHE 7 Proble Set 5 Solutions (A Crdioid). Let C be the closed curve in R whose polr coordintes (r, θ) stisfy () Sketch the curve C. r = cos θ +. (b) Find pretriztion t (r(t), θ(t)), t [, b], of C in polr
More information(4.2) -Richardson Extrapolation
(.) -Ricardson Extrapolation. Small-O Notation: Recall tat te big-o notation used to define te rate of convergence in Section.: Suppose tat lim G 0 and lim F L. Te function F is said to converge to L as
More informationParabola Exercise 1 2,6 Q.1 (A) S(0, 1) directric x + 2y = 0 PS = PM. x y x y 2y 1 x 2y Q.2 (D) y 2 = 18 x. 2 = 3t. 2 t 3 Q.
Prbol Exercise Q. (A) S(0, ) directric x + y = 0 PS = PM x y x y 5 5 x y y x y Q. (D) y = 8 x (t, t) t t = t t 8 4 8 t,t, 4 9 4,6 Q. (C) y 4 x 5 Eqution of directrix is x + = 0 x 0 5 Q.4 y = 8x M P t,t
More informationPHYSICS. (c) m D D m. v vt. (c) 3. Width of the river = d = 800 m m/s. 600m. B 800m v m,r. (b) 1000m. v w
PHYSICS T. T 8 k/hr = /s, ' Hz, ' 7 Hz T. r D D D,. r D D. D. D.... g/c. Width o the rier = d = 8 w /s B 8,r P O. sin t cos., on the copring this eqution, with sin t cos k =, k =. k. /s w Q. =, 9 9 = 8,
More informationChapter 14 - Fluids. Pressure is defined as the perpendicular force on a surface per unit surface area.
Chapter 4 - Fluids This chapter deals ith fluids, hich means a liquid or a as. It covers both fluid statics (fluids at rest) and fluid dynamics (fluids in motion). Pressure in a fluid Pressure is defined
More informationSection 15.6 Directional Derivatives and the Gradient Vector
Section 15.6 Directional Derivatives and te Gradient Vector Finding rates of cange in different directions Recall tat wen we first started considering derivatives of functions of more tan one variable,
More informationChapter 14. Gas-Vapor Mixtures and Air-Conditioning. Study Guide in PowerPoint
Chpter 14 Gs-Vpor Mixtures nd Air-Conditioning Study Guide in PowerPoint to ccopny Therodynics: An Engineering Approch, 5th edition by Yunus A. Çengel nd Michel A. Boles We will be concerned with the ixture
More informationTypes of forces. Types of Forces
pes of orces pes of forces. orce of Grvit: his is often referred to s the weiht of n object. It is the ttrctive force of the erth. And is lws directed towrd the center of the erth. It hs nitude equl to
More informationDynamics - Midterm Exam Type 1
Dynaics - Midter Exa 06.11.2017- Type 1 1. Two particles of ass and 2 slide on two vertical sooth uides. They are connected to each other and to the ceilin by three sprins of equal stiffness and of zero
More information1. Viscosities: μ = ρν. 2. Newton s viscosity law: 3. Infinitesimal surface force df. 4. Moment about the point o, dm
3- Fluid Mecnics Clss Emple 3: Newton s Viscosit Lw nd Se Stess 3- Fluid Mecnics Clss Emple 3: Newton s Viscosit Lw nd Se Stess Motition Gien elocit field o ppoimted elocit field, we wnt to be ble to estimte
More informationCHAPTER 5 Newton s Laws of Motion
CHAPTER 5 Newton s Lws of Motion We ve been lerning kinetics; describing otion without understnding wht the cuse of the otion ws. Now we re going to lern dynics!! Nno otor 103 PHYS - 1 Isc Newton (1642-1727)
More informationGraduate Students do all problems. Undergraduate students choose three problems.
OPTI 45/55 Midterm Due: Februr, Grdute Students do ll problems. Undergrdute students choose three problems.. Google Erth is improving the resolution of its globl mps with dt from the SPOT5 stellite. The
More informationPatrice Cassagnard Université Montesquieu Bordeaux IV LAREefi. Abstract
A useful grpicl metod under Cournot competition Ptrice Cssgnrd Université Montesquieu Bordeux IV LAEefi Astrct Tis note proposes grpicl pproc useful in gme teor. Tis metod consists in representing incentives
More informationChapter 2. Numerical Integration also called quadrature. 2.2 Trapezoidal Rule. 2.1 A basic principle Extending the Trapezoidal Rule DRAWINGS
S Cpter Numericl Integrtion lso clled qudrture Te gol of numericl integrtion is to pproximte numericlly. f(x)dx Tis is useful for difficult integrls like sin(x) ; sin(x ); x + x 4 Or worse still for multiple-dimensionl
More informationTest 2 Review. 1. Find the determinant of the matrix below using (a) cofactor expansion and (b) row reduction. A = 3 2 =
Test Review Find te determinant of te matrix below using (a cofactor expansion and (b row reduction Answer: (a det + = (b Observe R R R R R R R R R Ten det B = (((det Hence det Use Cramer s rule to solve:
More informationAverage Rate of Change (AROC) The average rate of change of y over an interval is equal to change in
Averge Rte o Cnge AROC Te verge rte o cnge o y over n intervl is equl to b b y y cngein y cnge in. Emple: Find te verge rte o cnge o te unction wit rule 5 s cnges rom to 5. 4 4 6 5 4 0 0 5 5 5 5 & 4 5
More informationContact Analysis on Large Negative Clearance Four-point Contact Ball Bearing
Avilble online t www.sciencedirect.co rocedi ngineering 7 0 74 78 The Second SR Conference on ngineering Modelling nd Siultion CMS 0 Contct Anlysis on Lrge Negtive Clernce Four-point Contct Bll Bering
More informationa) Read over steps (1)- (4) below and sketch the path of the cycle on a P V plot on the graph below. Label all appropriate points.
Prole 3: Crnot Cyle of n Idel Gs In this prole, the strting pressure P nd volue of n idel gs in stte, re given he rtio R = / > of the volues of the sttes nd is given Finlly onstnt γ = 5/3 is given You
More informationProf. Anchordoqui. Problems set # 4 Physics 169 March 3, 2015
Prof. Anchordoui Problems set # 4 Physics 169 Mrch 3, 15 1. (i) Eight eul chrges re locted t corners of cube of side s, s shown in Fig. 1. Find electric potentil t one corner, tking zero potentil to be
More informationCHAPTER 18 MOTION IN A CIRCLE
EXERCISE, Pae 6 CHAPTER 8 MOTION IN A CIRCLE. A locomotive travels around a curve of 0 m radius. If te orizontal trust on te outer rail is of te locomotive weit, determine te speed of te locomotive. Te
More informationHYPERBOLA. AIEEE Syllabus. Total No. of questions in Ellipse are: Solved examples Level # Level # Level # 3..
HYPERBOLA AIEEE Sllus. Stndrd eqution nd definitions. Conjugte Hperol. Prmetric eqution of te Hperol. Position of point P(, ) wit respect to Hperol 5. Line nd Hperol 6. Eqution of te Tngent Totl No. of
More informationME 321: FLUID MECHANICS-I
6/07/08 ME 3: LUID MECHANI-I Dr. A.B.M. Toufique Hasan Professor Department of Mechanical Engineering Bangladesh Universit of Engineering & Technolog (BUET), Dhaka Lecture- 4/07/08 Momentum Principle teacher.buet.ac.bd/toufiquehasan/
More information1 Review: Volumes of Solids (Stewart )
Lecture : Some Bic Appliction of Te Integrl (Stewrt 6.,6.,.,.) ul Krin eview: Volume of Solid (Stewrt 6.-6.) ecll: we d provided two metod for determining te volume of olid of revolution. Te rt w by dic
More informationChapter E - Problems
Chpter E - Problems Blinn Collee - Physic425 - Terry Honn Problem E.1 () Wht is the centripetl (rdil) ccelertion of point on the erth's equtor? (b) Give n expression for the centripetl ccelertion s function
More informationApplications of Bernoulli s theorem. Lecture - 7
Applictions of Bernoulli s theorem Lecture - 7 Prcticl Applictions of Bernoulli s Theorem The Bernoulli eqution cn be pplied to gret mny situtions not just the pipe flow we hve been considering up to now.
More informationPage 1. Physics 131: Lecture 22. SHM and Circles. Today s Agenda. Position. Velocity. Position and Velocity. Acceleration. v Asin.
Physics 3: ecture Today s enda Siple haronic otion Deinition Period and requency Position, velocity, and acceleration Period o a ass on a sprin Vertical sprin Enery and siple haronic otion Enery o a sprin
More informationOscillations Equations 0. Out of the followin functions representin otion of a particle which represents SHM I) y = sinωt cosωt 3 II) y = sin ωt III) IV) 3 y = 5cos 3ωt 4 y = + ωt+ ω t a) Only IV does
More informationMath 31A Discussion Notes Week 4 October 20 and October 22, 2015
Mat 3A Discussion Notes Week 4 October 20 and October 22, 205 To prepare for te first midterm, we ll spend tis week working eamples resembling te various problems you ve seen so far tis term. In tese notes
More information1.2. Linear Variable Coefficient Equations. y + b "! = a y + b " Remark: The case b = 0 and a non-constant can be solved with the same idea as above.
1 12 Liner Vrible Coefficient Equtions Section Objective(s): Review: Constnt Coefficient Equtions Solving Vrible Coefficient Equtions The Integrting Fctor Method The Bernoulli Eqution 121 Review: Constnt
More information) = slugs/ft 3. ) = lb ft/s. ) = ft/s
1. Make use of Tables 1. in the text book (See the last page in this assignent) to express the following quantities in SI units: (a) 10. in./in, (b) 4.81 slugs, (c).0 lb, (d) 7.1 ft/s, (e) 0.04 lb s/ft.
More informationNotes: Most of the material in this chapter is taken from Young and Freedman, Chap. 12.
Capter 6. Fluid Mecanics Notes: Most of te material in tis capter is taken from Young and Freedman, Cap. 12. 6.1 Fluid Statics Fluids, i.e., substances tat can flow, are te subjects of tis capter. But
More informationTopic 6b Finite Difference Approximations
/8/8 Course Instructor Dr. Rymond C. Rump Oice: A 7 Pone: (95) 747 6958 E Mil: rcrump@utep.edu Topic 6b Finite Dierence Approximtions EE 486/5 Computtionl Metods in EE Outline Wt re inite dierence pproximtions?
More informationExpansion of Gases. It is decided to verify oyle's law over a wide range of teperature and pressures. he ost suitable gas to be selected for this purpose is ) Carbon dioxide ) Heliu 3) Oxygen 4) Hydrogen.
More informationThe Spring. Consider a spring, which we apply a force F A to either stretch it or compress it
The Spring Consider spring, which we pply force F A to either stretch it or copress it F A - unstretched -F A 0 F A k k is the spring constnt, units of N/, different for different terils, nuber of coils
More informationChem/Biochem 471 Exam 3 12/18/08 Page 1 of 7 Name:
Che/Bioche 47 Exa /8/08 Pae of 7 Please leave the exa paes stapled toether. The forulas are on a separate sheet. This exa has 5 questions. You ust answer at least 4 of the questions. You ay answer ore
More information12 Basic Integration in R
14.102, Mt for Economists Fll 2004 Lecture Notes, 10/14/2004 Tese notes re primrily bsed on tose written by Andrei Bremzen for 14.102 in 2002/3, nd by Mrek Pyci for te MIT Mt Cmp in 2003/4. I ve mde only
More informationChapter Torque equals the diver s weight x distance from the pivot. List your variables and solve for distance.
Chapter 9 1. Put F 1 along the x axis. Add the three y-coponents (which total 0) and solve for the y- coponent of F 3. Now add the x-coponents of all three vectors (which total 0) and solve for the x-coponent
More informationFundamental Theorem of Calculus
Funmentl Teorem of Clculus Liming Png 1 Sttement of te Teorem Te funmentl Teorem of Clculus is one of te most importnt teorems in te istory of mtemtics, wic ws first iscovere by Newton n Leibniz inepenently.
More informationProblem T1. Main sequence stars (11 points)
Proble T1. Main sequence stars 11 points Part. Lifetie of Sun points i..7 pts Since the Sun behaves as a perfectly black body it s total radiation power can be expressed fro the Stefan- Boltzann law as
More informationFunction Composition and Chain Rules
Function Composition and s James K. Peterson Department of Biological Sciences and Department of Matematical Sciences Clemson University Marc 8, 2017 Outline 1 Function Composition and Continuity 2 Function
More informationHomework: 5, 9, 19, 25, 31, 34, 39 (p )
Hoework: 5, 9, 19, 5, 31, 34, 39 (p 130-134) 5. A 3.0 kg block is initilly t rest on horizontl surfce. A force of gnitude 6.0 nd erticl force P re then pplied to the block. The coefficients of friction
More informationCOUPLED OSCILLATORS. Two identical pendulums
COUPED OSCIATORS A real physical object can be rearded as a lare nuber of siple oscillators coupled toether (atos and olecules in solids. The question is: how does the couplin affect the behavior of each
More informationA we connect it in series with a capacitor of capacitance C 160 F. C The circuit thus carries an alternating sinusoidal current i.
I-(7 points) Deterination of a characteristic of a coil In order to deterine the resistance r of a coil of inductance 0 03 H, A we connect it in series with a capacitor of capacitance C 160F across the
More informationFreely propagating jet
Freely propgting jet Introduction Gseous rectnts re frequently introduced into combustion chmbers s jets. Chemicl, therml nd flow processes tht re tking plce in the jets re so complex tht nlyticl description
More informationECE 330 POWER CIRCUITS AND ELECTROMECHANICS LECTURE 17 FORCES OF ELECTRIC ORIGIN ENERGY APPROACH(1)
ECE 330 POWER CIRCUITS AND ELECTROMECHANICS LECTURE 17 FORCES OF ELECTRIC ORIGIN ENERGY APPROACH(1) Aknowledgent-These hndouts nd leture notes given in lss re bsed on teril fro Prof. Peter Suer s ECE 330
More informationUniversity of Washington Department of Chemistry Chemistry 453 Winter Quarter 2015
Lecture : Transition State Teory. tkins & DePaula: 7.6-7.7 University o Wasinton Departent o Ceistry Ceistry 453 Winter Quarter 05. ctivated Kinetics Kinetic rate uations are overned by several principles.
More informationVerification Analysis of the Redi Rock Wall
Verifiction Mnul no. Updte 06/06 Verifiction Anlysis of the Redi Rock Wll Progr File Redi Rock Wll Deo_v_etric_en_0.grr In this verifiction nul you will find hnd-de verifiction nlysis of the Redi Rock
More informationUniversity of Houston, Department of Mathematics Numerical Analysis II
University of Houston, Deprtment of Mtemtics Numericl Anlysis II 6 Glerkin metod, finite differences nd colloction 6.1 Glerkin metod Consider sclr 2nd order ordinry differentil eqution in selfdjoint form
More information6. The Momentum Equation
6. The Momentum Equation [This material relates predominantly to modules ELP034, ELP035] 6. Definition of the momentum equation Applications of the momentum equation: 6. The force due to the flow around
More informationExponents and Powers
EXPONENTS AND POWERS 9 Exponents nd Powers CHAPTER. Introduction Do you know? Mss of erth is 5,970,000,000,000, 000, 000, 000, 000 kg. We hve lredy lernt in erlier clss how to write such lrge nubers ore
More information8A Review Solutions. Roger Mong. February 24, 2007
8A Review Solutions Roer Mon Ferury 24, 2007 Question We ein y doin Free Body Dirm on the mss m. Since the rope runs throuh the lock 3 times, the upwrd force on the lock is 3T. (Not ecuse there re 3 pulleys!)
More informationSection 4.7 Inverse Trigonometric Functions
Section 7 Inverse Trigonometric Functions 89 9 Domin: 0, q Rnge: -q, q Zeros t n, n nonnegtive integer 9 Domin: -q, 0 0, q Rnge: -q, q Zeros t, n non-zero integer Note: te gr lso suggests n te end-bevior
More informationDiscussion Introduction P212, Week 1 The Scientist s Sixth Sense. Knowing what the answer will look like before you start.
Discussion Introduction P1, Week 1 The Scientist s Sith Sense As scientist or engineer, uch of your job will be perforing clcultions, nd using clcultions perfored by others. You ll be doing plenty of tht
More informationChapter 18 Two-Port Circuits
Cpter 8 Two-Port Circuits 8. Te Terminl Equtions 8. Te Two-Port Prmeters 8.3 Anlysis of te Terminted Two-Port Circuit 8.4 nterconnected Two-Port Circuits Motivtion Tévenin nd Norton equivlent circuits
More informationStudy fluid dynamics. Understanding Bernoulli s Equation.
Chapter Objectives Study fluid dynamics. Understanding Bernoulli s Equation. Chapter Outline 1. Fluid Flow. Bernoulli s Equation 3. Viscosity and Turbulence 1. Fluid Flow An ideal fluid is a fluid that
More informationLEARNING FROM MISTAKES
AP Central Quetion of te Mont May 3 Quetion of te Mont By Lin McMullin LEARNING FROM MISTAKES Ti i te firt Quetion of te Mont tat ill appear on te Calculu ection of AP Central. Tee are not AP Exam quetion,
More informationPractice. Page 1. Fluids. Fluids. Fluids What parameters do we use to describe fluids? Mass m Volume V
Fluids t ordinary teperature, atter exists in one of three states (5 if you include plasa and Bose-Einstein condensate). Solid - has a shape and fors a surface Liquid - has no shape but fors a surface
More informationtdec110 Lecture # 9 Optimization Overview
tdec0 Lecture # 9 Optimization Overview Most "real-worl" problems are concerne wit maximizing or minimizing some quantity or entity. Te calculus is te tool tat te engineer uses to fin te BEST SOLUTIONS
More informationChapter 9. Arc Length and Surface Area
Chpter 9. Arc Length nd Surfce Are In which We ppl integrtion to stud the lengths of curves nd the re of surfces. 9. Arc Length (Tet 547 553) P n P 2 P P 2 n b P i ( i, f( i )) P i ( i, f( i )) distnce
More information13.4 Work done by Constant Forces
13.4 Work done by Constnt Forces We will begin our discussion of the concept of work by nlyzing the motion of n object in one dimension cted on by constnt forces. Let s consider the following exmple: push
More informationLecture Note 4: Numerical differentiation and integration. Xiaoqun Zhang Shanghai Jiao Tong University
Lecture Note 4: Numericl differentition nd integrtion Xioqun Zng Sngi Jio Tong University Lst updted: November, 0 Numericl Anlysis. Numericl differentition.. Introduction Find n pproximtion of f (x 0 ),
More informationAP Calculus. Fundamental Theorem of Calculus
AP Clculus Fundmentl Theorem of Clculus Student Hndout 16 17 EDITION Click on the following link or scn the QR code to complete the evlution for the Study Session https://www.surveymonkey.com/r/s_sss Copyright
More informationPHYS 1443 Section 003 Lecture #21 Wednesday, Nov. 19, 2003 Dr. Mystery Lecturer
PHYS 443 Section 003 Lecture # Wednesday, Nov. 9, 003 Dr. Mystery Lecturer. Fluid Dyanics : Flow rate and Continuity Equation. Bernoulli s Equation 3. Siple Haronic Motion 4. Siple Bloc-Spring Syste 5.
More informationTutorial 2 (Solution) 1. An electron is confined to a one-dimensional, infinitely deep potential energy well of width L = 100 pm.
Seester 007/008 SMS0 Modern Pysics Tutorial Tutorial (). An electron is confined to a one-diensional, infinitely deep potential energy well of widt L 00 p. a) Wat is te least energy te electron can ave?
More informationIn this chapter we will study sound waves and concentrate on the following topics:
Chapter 17 Waves II In this chapter we will study sound waves and concentrate on the following topics: Speed of sound waves Relation between displaceent and pressure aplitude Interference of sound waves
More informationMath 115 ( ) Yum-Tong Siu 1. Lagrange Multipliers and Variational Problems with Constraints. F (x,y,y )dx
Mth 5 2006-2007) Yum-Tong Siu Lgrnge Multipliers nd Vritionl Problems with Constrints Integrl Constrints. Consider the vritionl problem of finding the extremls for the functionl J[y] = F x,y,y )dx with
More informationPROBLEM 11.3 SOLUTION
PROBLEM.3 The verticl motion of mss A is defined by the reltion x= 0 sin t+ 5cost+ 00, where x nd t re expressed in mm nd seconds, respectively. Determine () the position, velocity nd ccelertion of A when
More informationPhysics 4A Solutions to Chapter 15 Homework
Physics 4A Solutions to Chapter 15 Hoework Chapter 15 Questions:, 8, 1 Exercises & Probles 6, 5, 31, 41, 59, 7, 73, 88, 90 Answers to Questions: Q 15- (a) toward -x (b) toward +x (c) between -x and 0 (d)
More informationFluids and Buoyancy. 1. What will happen to the scale reading as the mass is lowered?
Fluids and Buoyancy. Wat will appen to te scale reading as te mass is lowered? M Using rcimedes Principle: any body fully or partially submerged in a fluid is buoyed up by a force equal to te weigt of
More information