Today in Physics 217: separation of variables IV
|
|
- Oswin Howard
- 5 years ago
- Views:
Transcription
1 Today i Physics 27: separatio of variables IV Separatio i cylidrical coordiates Exaple of the split cylider (solutio sketched at right) More o orthogoality of trig fuctios ad Fourier s trick V = V V = E V 8 October 22 Physics 27, Fall 22
2 Separatio of variables i cylidrical coordiates I Griffiths proble 3.23, o hoework 6, you did the setup of the separatio solutio to all Laplace-equatio probles i cylidrical geoetry. Recall that the Laplace equatio i cylidrical coordiates is V V V V = s + + = s s s s φ z If you kow a priori that V does t deped o z ifiite cylider, boudary coditios idepedet of z the the last ter drops out V V s + s s s 2 2 = s φ 2 8 October 22 Physics 27, Fall 22 2
3 Separatio of variables i cylidrical coordiates (cotiued) V( s, φ) = S( s) Φ( φ) : So you tried a solutio of the for s d ds d Φ s + Sds ds 2 = = Φ dφ ad solved the resultig radial ad agular ordiary differetial equatios to obtai particular solutios: 2 d Φ 2 2 = Φ Φ ( φ) = Acos φ + Bsi φ dφ d ds 2 ad s s = S S( s) = Cr + Dr ds ds with a additioal radial solutio for = : d ds s s = S( s) = Cls + D ds ds 8 October 22 Physics 27, Fall
4 Separatio of variables i cylidrical coordiates (cotiued) Fro the periodicity of the agular solutio you also deduced that =,,2,3, The ost geeral solutio is a liear cobiatio of all of these solutios, for all values of, which you wrote as ( φ ) V s, = C ls+ D = ( Cs Ds )( Acos φ Bsi φ) You applied this solutio i a cocrete exaple, Griffiths proble 3.24, i which you were able to avoid the use of Fourier s trick. Now for oe i which you ca t. 8 October 22 Physics 27, Fall 22 4
5 The split cylider Exaple. A log, thi-wall coductig cylidrical tube with radius R a sall sectio of which is show at right is split i half legthwise. The two halves are isulated fro oe aother; oe is held at potetial V ad the other is grouded. Fid the potetial iside the tube. z y R V = V V = x 8 October 22 Physics 27, Fall 22 5
6 The solutio: V s, φ = C ls+ D ( ) The split cylider (cotiued) = ( Cs Ds )( Acos φ Bsi φ) Boudary coditios: iv. = V at s= R, φ = π ii. V = at s = R, φ = π iii. V fiite at s = Apply the last oe first: the ter Ds approaches ifiity at s = uless D =. Siilarly, C =. 8 October 22 Physics 27, Fall 22 6
7 More o trig fuctio orthogoality Now apply the first two boudary coditios. This will be coveietly doe i cocert with the applicatio of Fourier s trick to extract the rest of the coefficiets iside the su. Ad this will be a good place to fill i soe ore details about the orthogoality of the trig fuctios. Last Friday we showed that π π si y si ydy = δ Obviously we also have 2 si y si ydy = πδ. 8 October 22 Physics 27, Fall 22 7
8 More o trig fuctio orthogoality (cotiued) But what about cosies? It goes just like the derivatio for sies, startig with two itegratios by parts: = cosx cos xdx = cosx si x + si x si xdx Thus For =, Itegrate this by parts oce: 2 = π 2 π = si x cos x + cos x cos xdx 2 2 ( ) cosx cosxdx =, or cos x cosxdx =. 2 2 cos xdx = cos wdw. 8 October 22 Physics 27, Fall 22 8
9 More o trig fuctio orthogoality (cotiued) = 2 2 cos wdw = cos wsi w + si wdw Thus ad ( 2 2 ) = cos w + si w dw = dw = π cos xdx = π cosx cos xdx = πδ. 8 October 22 Physics 27, Fall 22 9
10 More o trig fuctio orthogoality (cotiued) The there are products of sies ad cosies to cosider: = cosx si xdx = si x si x si x cosxdx Recall the trig idetity ( ) si u+ v = si ucos v+ cosusi v: cosx si xdx si xdx cosx si xdx = ( + ) + ( ) cos + x cosx sixdx = =. + So, oce agai, this shows that ( ) cosx si xdx =. 8 October 22 Physics 27, Fall 22
11 More o trig fuctio orthogoality (cotiued) For the case =, recall the trig idetity 4π So it s zero whether = or ot. Suary: Now back to that cylider: 2cosusiu= si2 u: 4π cosx si xdx = si 2xdx = si udu = cos u = cosx cos xdx = si x si xdx =πδ, cos x si xdx =. 8 October 22 Physics 27, Fall 22
12 The split cylider (cotiued) What s left of the solutio: (, φ) ( cos φ si φ) V s = Cs A + B = Let s apply the first two boudary coditios, while extractig the A : ( ) = ( + ) V R, φ cosφdφ C R A cosφ B siφ cosφdφ = π V cos φdφ = CR ( Aπδ + ), as we just foud. = V π si φ = πa C R A C = 8 October 22 Physics 27, Fall 22 2
13 The split cylider (cotiued) Now work o the Bs by itegratig everythig with ( ) = ( + ) V R, φ siφdφ C R A cosφ B siφ siφdφ = π V si φdφ = CR ( + Bπδ), as we just foud. = V π cos φ = πb CR V ( ) = π BC R = if is eve, 2 if it's odd. si φ : 8 October 22 Physics 27, Fall 22 3
14 The split cylider (cotiued) So replace with 2+ i the su: = BC ( φ) 2V π R V s, = B C s siφ = 2V s = π R =,3,5,... = si φ 2+ 2V s = si ( 2 + ) φ. π 2+ R 8 October 22 Physics 27, Fall 22 4
PARTIAL DIFFERENTIAL EQUATIONS SEPARATION OF VARIABLES
Diola Bagayoko (0 PARTAL DFFERENTAL EQUATONS SEPARATON OF ARABLES. troductio As discussed i previous lectures, partial differetial equatios arise whe the depedet variale, i.e., the fuctio, varies with
More informationChapter 4. Fourier Series
Chapter 4. Fourier Series At this poit we are ready to ow cosider the caoical equatios. Cosider, for eample the heat equatio u t = u, < (4.) subject to u(, ) = si, u(, t) = u(, t) =. (4.) Here,
More informationA second look at separation of variables
A secod look at separatio of variables Assumed that u(x,t)x(x)t(t) Pluggig this ito the wave, diffusio, or Laplace equatio gave two ODEs The solutios to those ODEs subject to boudary ad iitial coditios
More informationUNIVERSITY OF CALIFORNIA - SANTA CRUZ DEPARTMENT OF PHYSICS PHYS 116C. Problem Set 4. Benjamin Stahl. November 6, 2014
UNIVERSITY OF CALIFORNIA - SANTA CRUZ DEPARTMENT OF PHYSICS PHYS 6C Problem Set 4 Bejami Stahl November 6, 4 BOAS, P. 63, PROBLEM.-5 The Laguerre differetial equatio, x y + ( xy + py =, will be solved
More informationLecture 4 Conformal Mapping and Green s Theorem. 1. Let s try to solve the following problem by separation of variables
Lecture 4 Coformal Mappig ad Gree s Theorem Today s topics. Solvig electrostatic problems cotiued. Why separatio of variables does t always work 3. Coformal mappig 4. Gree s theorem The failure of separatio
More informationProblem. Consider the sequence a j for j N defined by the recurrence a j+1 = 2a j + j for j > 0
GENERATING FUNCTIONS Give a ifiite sequece a 0,a,a,, its ordiary geeratig fuctio is A : a Geeratig fuctios are ofte useful for fidig a closed forula for the eleets of a sequece, fidig a recurrece forula,
More informationAcoustic Field inside a Rigid Cylinder with a Point Source
Acoustic Field iside a Rigid Cylider with a Poit Source 1 Itroductio The ai objectives of this Deo Model are to Deostrate the ability of Coustyx to odel a rigid cylider with a poit source usig Coustyx
More informationFourier Series and their Applications
Fourier Series ad their Applicatios The fuctios, cos x, si x, cos x, si x, are orthogoal over (, ). m cos mx cos xdx = m = m = = cos mx si xdx = for all m, { m si mx si xdx = m = I fact the fuctios satisfy
More informationNotes 19 Bessel Functions
ECE 638 Fall 17 David R. Jackso Notes 19 Bessel Fuctios Notes are from D. R. Wilto, Dept. of ECE 1 Cylidrical Wave Fuctios Helmholtz equatio: ψ + k ψ = I cylidrical coordiates: ψ 1 ψ 1 ψ ψ ρ ρ ρ ρ φ z
More informationAssignment Number 3 Solutions
Math 4354, Assigmet Number 3 Solutios 1. u t (x, t) = u xx (x, t), < x (1) u(, t) =, u(, t) = u(x, ) = x ( 1) +1 u(x, t) = e t si(x). () =1 Solutio: Look for simple solutios i the form u(x, t) =
More informationPhys 6303 Final Exam Solutions December 19, 2012
Phys 633 Fial Exam s December 19, 212 You may NOT use ay book or otes other tha supplied with this test. You will have 3 hours to fiish. DO YOUR OWN WORK. Express your aswers clearly ad cocisely so that
More informationQuestion 1: The magnetic case
September 6, 018 Corell Uiversity, Departmet of Physics PHYS 337, Advace E&M, HW # 4, due: 9/19/018, 11:15 AM Questio 1: The magetic case I class, we skipped over some details, so here you are asked to
More informationChapter 8. Euler s Gamma function
Chapter 8 Euler s Gamma fuctio The Gamma fuctio plays a importat role i the fuctioal equatio for ζ(s that we will derive i the ext chapter. I the preset chapter we have collected some properties of the
More informationSOME TRIGONOMETRIC IDENTITIES RELATED TO POWERS OF COSINE AND SINE FUNCTIONS
Folia Mathematica Vol. 5, No., pp. 4 6 Acta Uiversitatis Lodziesis c 008 for Uiversity of Lódź Press SOME TRIGONOMETRIC IDENTITIES RELATED TO POWERS OF COSINE AND SINE FUNCTIONS ROMAN WITU LA, DAMIAN S
More informationradians A function f ( x ) is called periodic if it is defined for all real x and if there is some positive number P such that:
Fourier Series. Graph of y Asix ad y Acos x Amplitude A ; period 36 radias. Harmoics y y six is the first harmoic y y six is the th harmoics 3. Periodic fuctio A fuctio f ( x ) is called periodic if it
More information1. Hydrogen Atom: 3p State
7633A QUANTUM MECHANICS I - solutio set - autum. Hydroge Atom: 3p State Let us assume that a hydroge atom is i a 3p state. Show that the radial part of its wave fuctio is r u 3(r) = 4 8 6 e r 3 r(6 r).
More informationOrthogonal Functions
Royal Holloway Uiversity of odo Departet of Physics Orthogoal Fuctios Motivatio Aalogy with vectors You are probably failiar with the cocept of orthogoality fro vectors; two vectors are orthogoal whe they
More informationCalculus 2 Test File Fall 2013
Calculus Test File Fall 013 Test #1 1.) Without usig your calculator, fid the eact area betwee the curves f() = 4 - ad g() = si(), -1 < < 1..) Cosider the followig solid. Triagle ABC is perpedicular to
More informationMath 12 Final Exam, May 11, 2011 ANSWER KEY. 2sinh(2x) = lim. 1 x. lim e. x ln. = e. (x+1)(1) x(1) (x+1) 2. (2secθ) 5 2sec2 θ dθ.
Math Fial Exam, May, ANSWER KEY. [5 Poits] Evaluate each of the followig its. Please justify your aswers. Be clear if the it equals a value, + or, or Does Not Exist. coshx) a) L H x x+l x) sihx) x x L
More informationProblem Cosider the curve give parametrically as x = si t ad y = + cos t for» t» ß: (a) Describe the path this traverses: Where does it start (whe t =
Mathematics Summer Wilso Fial Exam August 8, ANSWERS Problem 1 (a) Fid the solutio to y +x y = e x x that satisfies y() = 5 : This is already i the form we used for a first order liear differetial equatio,
More informationMATH2007* Partial Answers to Review Exercises Fall 2004
MATH27* Partial Aswers to Review Eercises Fall 24 Evaluate each of the followig itegrals:. Let u cos. The du si ad Hece si ( cos 2 )(si ) (u 2 ) du. si u 2 cos 7 u 7 du Please fiish this. 2. We use itegratio
More informationMATH Exam 1 Solutions February 24, 2016
MATH 7.57 Exam Solutios February, 6. Evaluate (A) l(6) (B) l(7) (C) l(8) (D) l(9) (E) l() 6x x 3 + dx. Solutio: D We perform a substitutio. Let u = x 3 +, so du = 3x dx. Therefore, 6x u() x 3 + dx = [
More informationECE Spring Prof. David R. Jackson ECE Dept. Notes 20
ECE 6341 Sprig 016 Prof. David R. Jackso ECE Dept. Notes 0 1 Spherical Wave Fuctios Cosider solvig ψ + k ψ = 0 i spherical coordiates z φ θ r y x Spherical Wave Fuctios (cot.) I spherical coordiates we
More informationSolutions to Final Exam Review Problems
. Let f(x) 4+x. Solutios to Fial Exam Review Problems Math 5C, Witer 2007 (a) Fid the Maclauri series for f(x), ad compute its radius of covergece. Solutio. f(x) 4( ( x/4)) ( x/4) ( ) 4 4 + x. Sice the
More information2. Fourier Series, Fourier Integrals and Fourier Transforms
Mathematics IV -. Fourier Series, Fourier Itegrals ad Fourier Trasforms The Fourier series are used for the aalysis of the periodic pheomea, which ofte appear i physics ad egieerig. The Fourier itegrals
More informationENGI Series Page 6-01
ENGI 3425 6 Series Page 6-01 6. Series Cotets: 6.01 Sequeces; geeral term, limits, covergece 6.02 Series; summatio otatio, covergece, divergece test 6.03 Stadard Series; telescopig series, geometric series,
More informationCalculus 2 - D. Yuen Final Exam Review (Version 11/22/2017. Please report any possible typos.)
Calculus - D Yue Fial Eam Review (Versio //7 Please report ay possible typos) NOTE: The review otes are oly o topics ot covered o previous eams See previous review sheets for summary of previous topics
More information1 1 2 = show that: over variables x and y. [2 marks] Write down necessary conditions involving first and second-order partial derivatives for ( x0, y
Questio (a) A square matrix A= A is called positive defiite if the quadratic form waw > 0 for every o-zero vector w [Note: Here (.) deotes the traspose of a matrix or a vector]. Let 0 A = 0 = show that:
More informationSECTION 2 Electrostatics
SECTION Electrostatics This sectio, based o Chapter of Griffiths, covers effects of electric fields ad forces i static (timeidepedet) situatios. The topics are: Electric field Gauss s Law Electric potetial
More informationChapter 10 Partial Differential Equations and Fourier Series
Math-33 Chapter Partial Differetial Equatios November 6, 7 Chapter Partial Differetial Equatios ad Fourier Series Math-33 Chapter Partial Differetial Equatios November 6, 7. Boudary Value Problems for
More informationSOLUTION SET VI FOR FALL [(n + 2)(n + 1)a n+2 a n 1 ]x n = 0,
4. Series Solutios of Differetial Equatios:Special Fuctios 4.. Illustrative examples.. 5. Obtai the geeral solutio of each of the followig differetial equatios i terms of Maclauri series: d y (a dx = xy,
More informationAssignment 1 : Real Numbers, Sequences. for n 1. Show that (x n ) converges. Further, by observing that x n+2 + x n+1
Assigmet : Real Numbers, Sequeces. Let A be a o-empty subset of R ad α R. Show that α = supa if ad oly if α is ot a upper boud of A but α + is a upper boud of A for every N. 2. Let y (, ) ad x (, ). Evaluate
More informationThe Non-homogeneous Diffusion Equation
The No-hoogeeous Diffusio Equatio The o-hoogeeous diffusio equatio, with sources, has the geeral for, 2 r,t a 2 r,t Fr,t t a 2 is real ad The hoogeeous diffusio equatio, 2 r,t a 2 t r,t ca be solved by
More informationChapter 6 Infinite Series
Chapter 6 Ifiite Series I the previous chapter we cosidered itegrals which were improper i the sese that the iterval of itegratio was ubouded. I this chapter we are goig to discuss a topic which is somewhat
More informationQuiz. Use either the RATIO or ROOT TEST to determine whether the series is convergent or not.
Quiz. Use either the RATIO or ROOT TEST to determie whether the series is coverget or ot. e .6 POWER SERIES Defiitio. A power series i about is a series of the form c 0 c a c a... c a... a 0 c a where
More information8.3 Perturbation theory
8.3 Perturbatio theory Slides: Video 8.3.1 Costructig erturbatio theory Text referece: Quatu Mechaics for Scietists ad gieers Sectio 6.3 (u to First order erturbatio theory ) Perturbatio theory Costructig
More informationCalculus 2 Test File Spring Test #1
Calculus Test File Sprig 009 Test #.) Without usig your calculator, fid the eact area betwee the curves f() = - ad g() = +..) Without usig your calculator, fid the eact area betwee the curves f() = ad
More informationClass #25 Wednesday, April 19, 2018
Cla # Wedesday, April 9, 8 PDE: More Heat Equatio with Derivative Boudary Coditios Let s do aother heat equatio problem similar to the previous oe. For this oe, I ll use a square plate (N = ), but I m
More informationWe are mainly going to be concerned with power series in x, such as. (x)} converges - that is, lims N n
Review of Power Series, Power Series Solutios A power series i x - a is a ifiite series of the form c (x a) =c +c (x a)+(x a) +... We also call this a power series cetered at a. Ex. (x+) is cetered at
More informationThe Binomial Multi- Section Transformer
4/4/26 The Bioial Multisectio Matchig Trasforer /2 The Bioial Multi- Sectio Trasforer Recall that a ulti-sectio atchig etwork ca be described usig the theory of sall reflectios as: where: ( ω ) = + e +
More informationFourier Series and the Wave Equation
Fourier Series ad the Wave Equatio We start with the oe-dimesioal wave equatio u u =, x u(, t) = u(, t) =, ux (,) = f( x), u ( x,) = This represets a vibratig strig, where u is the displacemet of the strig
More informationMost text will write ordinary derivatives using either Leibniz notation 2 3. y + 5y= e and y y. xx tt t
Itroductio to Differetial Equatios Defiitios ad Termiolog Differetial Equatio: A equatio cotaiig the derivatives of oe or more depedet variables, with respect to oe or more idepedet variables, is said
More informationDefine a Markov chain on {1,..., 6} with transition probability matrix P =
Pla Group Work 0. The title says it all Next Tie: MCMC ad Geeral-state Markov Chais Midter Exa: Tuesday 8 March i class Hoework 4 due Thursday Uless otherwise oted, let X be a irreducible, aperiodic Markov
More informationChapter 8. Euler s Gamma function
Chapter 8 Euler s Gamma fuctio The Gamma fuctio plays a importat role i the fuctioal equatio for ζ(s) that we will derive i the ext chapter. I the preset chapter we have collected some properties of the
More informationA) is empty. B) is a finite set. C) can be a countably infinite set. D) can be an uncountable set.
M.A./M.Sc. (Mathematics) Etrace Examiatio 016-17 Max Time: hours Max Marks: 150 Istructios: There are 50 questios. Every questio has four choices of which exactly oe is correct. For correct aswer, 3 marks
More information(a) (b) All real numbers. (c) All real numbers. (d) None. to show the. (a) 3. (b) [ 7, 1) (c) ( 7, 1) (d) At x = 7. (a) (b)
Chapter 0 Review 597. E; a ( + )( + ) + + S S + S + + + + + + S lim + l. D; a diverges by the Itegral l k Test sice d lim [(l ) ], so k l ( ) does ot coverge absolutely. But it coverges by the Alteratig
More informationProf. Dr. I. Nasser Phys 571, T131 5-Nov-13 Green function.doc. 2 ρ(r)
Gree fuctio.doc Solutio of ihomogeeous ordiary differetial equatios usig Gree's fuctios G(, ') (9.7, 10.5) Historical Itroductio: Gree's fuctios are auiliary fuctios i the solutio of liear partial differetial
More informationApply change-of-basis formula to rewrite x as a linear combination of eigenvectors v j.
Eigevalue-Eigevector Istructor: Nam Su Wag eigemcd Ay vector i real Euclidea space of dimesio ca be uiquely epressed as a liear combiatio of liearly idepedet vectors (ie, basis) g j, j,,, α g α g α g α
More informationThe Binomial Multi-Section Transformer
4/15/2010 The Bioial Multisectio Matchig Trasforer preset.doc 1/24 The Bioial Multi-Sectio Trasforer Recall that a ulti-sectio atchig etwork ca be described usig the theory of sall reflectios as: where:
More information9.3 Power Series: Taylor & Maclaurin Series
9.3 Power Series: Taylor & Maclauri Series If is a variable, the a ifiite series of the form 0 is called a power series (cetered at 0 ). a a a a a 0 1 0 is a power series cetered at a c a a c a c a c 0
More informationChapter 4 Postulates & General Principles of Quantum Mechanics
Chapter 4 Postulates & Geeral Priciples of Quatu Mechaics Backgroud: We have bee usig quite a few of these postulates already without realizig it. Now it is tie to forally itroduce the. State of a Syste
More informationLC Oscillations. di Q. Kirchoff s loop rule /27/2018 1
L Oscillatios Kirchoff s loop rule I di Q VL V L dt ++++ - - - - L 3/27/28 , r Q.. 2 4 6 x 6.28 I. f( x) f( x).. r.. 2 4 6 x 6.28 di dt f( x) Q Q cos( t) I Q si( t) di dt Q cos( t) 2 o x, r.. V. x f( )
More informationPhysics 324, Fall Dirac Notation. These notes were produced by David Kaplan for Phys. 324 in Autumn 2001.
Physics 324, Fall 2002 Dirac Notatio These otes were produced by David Kapla for Phys. 324 i Autum 2001. 1 Vectors 1.1 Ier product Recall from liear algebra: we ca represet a vector V as a colum vector;
More informationLecture 11: A Fourier Transform Primer
PHYS 34 Fall 1 ecture 11: A Fourier Trasform Primer Ro Reifeberger Birck aotechology Ceter Purdue Uiversity ecture 11 1 f() I may edeavors, we ecouter sigals that eriodically reeat f(t) T t Such reeatig
More informationLecture 7: Fourier Series and Complex Power Series
Math 1d Istructor: Padraic Bartlett Lecture 7: Fourier Series ad Complex Power Series Week 7 Caltech 013 1 Fourier Series 1.1 Defiitios ad Motivatio Defiitio 1.1. A Fourier series is a series of fuctios
More information1 Generating functions for balls in boxes
Math 566 Fall 05 Some otes o geeratig fuctios Give a sequece a 0, a, a,..., a,..., a geeratig fuctio some way of represetig the sequece as a fuctio. There are may ways to do this, with the most commo ways
More informationj=1 dz Res(f, z j ) = 1 d k 1 dz k 1 (z c)k f(z) Res(f, c) = lim z c (k 1)! Res g, c = f(c) g (c)
Problem. Compute the itegrals C r d for Z, where C r = ad r >. Recall that C r has the couter-clockwise orietatio. Solutio: We will use the idue Theorem to solve this oe. We could istead use other (perhaps
More informationPAPER : IIT-JAM 2010
MATHEMATICS-MA (CODE A) Q.-Q.5: Oly oe optio is correct for each questio. Each questio carries (+6) marks for correct aswer ad ( ) marks for icorrect aswer.. Which of the followig coditios does NOT esure
More informationN14/5/MATHL/HP1/ENG/TZ0/XX/M MARKSCHEME. November 2014 MATHEMATICS. Higher Level. Paper pages
N4/5/MATHL/HP/ENG/TZ0/XX/M MARKSCHEME November 04 MATHEMATICS Higher Level Paper 0 pages N4/5/MATHL/HP/ENG/TZ0/XX/M This markscheme is the property of the Iteratioal Baccalaureate ad must ot be reproduced
More informationComparison Study of Series Approximation. and Convergence between Chebyshev. and Legendre Series
Applied Mathematical Scieces, Vol. 7, 03, o. 6, 3-337 HIKARI Ltd, www.m-hikari.com http://d.doi.org/0.988/ams.03.3430 Compariso Study of Series Approimatio ad Covergece betwee Chebyshev ad Legedre Series
More informationBinomial transform of products
Jauary 02 207 Bioial trasfor of products Khristo N Boyadzhiev Departet of Matheatics ad Statistics Ohio Norther Uiversity Ada OH 4580 USA -boyadzhiev@ouedu Abstract Give the bioial trasfors { b } ad {
More information62. Power series Definition 16. (Power series) Given a sequence {c n }, the series. c n x n = c 0 + c 1 x + c 2 x 2 + c 3 x 3 +
62. Power series Defiitio 16. (Power series) Give a sequece {c }, the series c x = c 0 + c 1 x + c 2 x 2 + c 3 x 3 + is called a power series i the variable x. The umbers c are called the coefficiets of
More informationLøsningsførslag i 4M
Norges tekisk aturviteskapelige uiversitet Istitutt for matematiske fag Side 1 av 6 Løsigsførslag i 4M Oppgave 1 a) A sketch of the graph of the give f o the iterval [ 3, 3) is as follows: The Fourier
More informationNew Version of the Rayleigh Schrödinger Perturbation Theory: Examples
New Versio of the Rayleigh Schrödiger Perturbatio Theory: Examples MILOŠ KALHOUS, 1 L. SKÁLA, 1 J. ZAMASTIL, 1 J. ČÍŽEK 2 1 Charles Uiversity, Faculty of Mathematics Physics, Ke Karlovu 3, 12116 Prague
More informationf(x) dx as we do. 2x dx x also diverges. Solution: We compute 2x dx lim
Math 3, Sectio 2. (25 poits) Why we defie f(x) dx as we do. (a) Show that the improper itegral diverges. Hece the improper itegral x 2 + x 2 + b also diverges. Solutio: We compute x 2 + = lim b x 2 + =
More information7.) Consider the region bounded by y = x 2, y = x - 1, x = -1 and x = 1. Find the volume of the solid produced by revolving the region around x = 3.
Calculus Eam File Fall 07 Test #.) Fid the eact area betwee the curves f() = 8 - ad g() = +. For # - 5, cosider the regio bouded by the curves y =, y = 3 + 4. Produce a solid by revolvig the regio aroud
More information: Transforms and Partial Differential Equations
Trasforms ad Partial Differetial Equatios 018 SUBJECT NAME : Trasforms ad Partial Differetial Equatios SUBJECT CODE : MA 6351 MATERIAL NAME : Part A questios REGULATION : R013 WEBSITE : wwwharigaeshcom
More information3. Z Transform. Recall that the Fourier transform (FT) of a DT signal xn [ ] is ( ) [ ] = In order for the FT to exist in the finite magnitude sense,
3. Z Trasform Referece: Etire Chapter 3 of text. Recall that the Fourier trasform (FT) of a DT sigal x [ ] is ω ( ) [ ] X e = j jω k = xe I order for the FT to exist i the fiite magitude sese, S = x [
More informationSalmon: Lectures on partial differential equations. 3. First-order linear equations as the limiting case of second-order equations
3. First-order liear equatios as the limitig case of secod-order equatios We cosider the advectio-diffusio equatio (1) v = 2 o a bouded domai, with boudary coditios of prescribed. The coefficiets ( ) (2)
More informationSECTION 2.6 THE SECOND ALTERNATIVE
54 SECTION 2.6 THE SECOND ALTERNATIVE We ow discuss the probles where the Secod Alterative holds. The suppositio is that there is a otrivial solutio for L(y) =, B (y) = B 2 (y) =. The Fredhol Theores assure
More informationMathematics Extension 1
016 Bored of Studies Trial Eamiatios Mathematics Etesio 1 3 rd ctober 016 Geeral Istructios Total Marks 70 Readig time 5 miutes Workig time hours Write usig black or blue pe Black pe is preferred Board-approved
More informationSOLUTIONS TO EXAM 3. Solution: Note that this defines two convergent geometric series with respective radii r 1 = 2/5 < 1 and r 2 = 1/5 < 1.
SOLUTIONS TO EXAM 3 Problem Fid the sum of the followig series 2 + ( ) 5 5 2 5 3 25 2 2 This series diverges Solutio: Note that this defies two coverget geometric series with respective radii r 2/5 < ad
More information(s)h(s) = K( s + 8 ) = 5 and one finite zero is located at z 1
ROOT LOCUS TECHNIQUE 93 should be desiged differetly to eet differet specificatios depedig o its area of applicatio. We have observed i Sectio 6.4 of Chapter 6, how the variatio of a sigle paraeter like
More informationn n 2 + 4i = lim 2 n lim 1 + 4x 2 dx = 1 2 tan ( 2i 2 x x dx = 1 2 tan 1 2 = 2 n, x i = a + i x = 2i
. ( poits) Fid the limits. (a) (6 poits) lim ( + + + 3 (6 poits) lim h h h 6 微甲 - 班期末考解答和評分標準 +h + + + t3 dt. + 3 +... + 5 ) = lim + i= + i. Solutio: (a) lim i= + i = lim i= + ( i ) = lim x i= + x i =
More information1 Approximating Integrals using Taylor Polynomials
Seughee Ye Ma 8: Week 7 Nov Week 7 Summary This week, we will lear how we ca approximate itegrals usig Taylor series ad umerical methods. Topics Page Approximatig Itegrals usig Taylor Polyomials. Defiitios................................................
More informationSeunghee Ye Ma 8: Week 5 Oct 28
Week 5 Summary I Sectio, we go over the Mea Value Theorem ad its applicatios. I Sectio 2, we will recap what we have covered so far this term. Topics Page Mea Value Theorem. Applicatios of the Mea Value
More informationRay Optics Theory and Mode Theory. Dr. Mohammad Faisal Dept. of EEE, BUET
Ray Optics Theory ad Mode Theory Dr. Mohammad Faisal Dept. of, BUT Optical Fiber WG For light to be trasmitted through fiber core, i.e., for total iteral reflectio i medium, > Ray Theory Trasmissio Ray
More informationPROBLEMS AND SOLUTIONS 2
PROBEMS AND SOUTIONS Problem 5.:1 Statemet. Fid the solutio of { u tt = a u xx, x, t R, u(x, ) = f(x), u t (x, ) = g(x), i the followig cases: (b) f(x) = e x, g(x) = axe x, (d) f(x) = 1, g(x) =, (f) f(x)
More informationMark Lundstrom Spring SOLUTIONS: ECE 305 Homework: Week 5. Mark Lundstrom Purdue University
Mark udstrom Sprig 2015 SOUTIONS: ECE 305 Homework: Week 5 Mark udstrom Purdue Uiversity The followig problems cocer the Miority Carrier Diffusio Equatio (MCDE) for electros: Δ t = D Δ + G For all the
More informationSphericalHarmonicY. Notations. Primary definition. Specific values. Traditional name. Traditional notation. Mathematica StandardForm notation
SphericalHaroicY Notatios Traditioal ae Spherical haroic Traditioal otatio Y, φ Matheatica StadardFor otatio SphericalHaroicY,,, φ Priary defiitio 05.0.0.000.0 Y, φ φ P cos ; 05.0.0.000.0 Y 0 k, φ k k
More informationHigher Course Plan. Calculus and Relationships Expressions and Functions
Higher Course Pla Applicatios Calculus ad Relatioships Expressios ad Fuctios Topic 1: The Straight Lie Fid the gradiet of a lie Colliearity Kow the features of gradiets of: parallel lies perpedicular lies
More informationAppendix: The Laplace Transform
Appedix: The Laplace Trasform The Laplace trasform is a powerful method that ca be used to solve differetial equatio, ad other mathematical problems. Its stregth lies i the fact that it allows the trasformatio
More informationInfinite Series and Improper Integrals
8 Special Fuctios Ifiite Series ad Improper Itegrals Ifiite series are importat i almost all areas of mathematics ad egieerig I additio to umerous other uses, they are used to defie certai fuctios ad to
More informationENGI 9420 Engineering Analysis Assignment 3 Solutions
ENGI 9 Egieerig Aalysis Assigmet Solutios Fall [Series solutio of ODEs, matri algebra; umerical methods; Chapters, ad ]. Fid a power series solutio about =, as far as the term i 7, to the ordiary differetial
More informationApplication 10.5D Spherical Harmonic Waves
Applicatio 10.5D Spherical Haroic Waves I probles ivolvig regios that ejoy spherical syetry about the origi i space, it is appropriate to use spherical coordiates. The 3-diesioal Laplacia for a fuctio
More informationwhere c is a scaling constant, 0, 0,. r c sinh cos csinh cos cos, csinh cos sin, ccosh sin U csinh sin sin, csinh sin cos,0
MATH 38:Partial Differetial Equatios Solutios to The Secod Midterm DEGENERATE ELLIPSOID COORDINATES. Problem PROOF: Give csih si cos, y csihsi si, z ccoshcos, where c is a scalig costat,,,. r We compute
More informationPhysics 219 Summary of linear response theory
1 Physics 219 Suary of liear respose theory I. INTRODUCTION We apply a sall perturbatio of stregth f(t) which is switched o gradually ( adiabatically ) fro t =, i.e. the aplitude of the perturbatio grows
More informationQuantization and Special Functions
Otocec 6.-9.0.003 Quatizatio ad Special Fuctios Christia B. Lag Ist. f. theoret. Physik Uiversität Graz Cotets st lecture Schrödiger equatio Eigevalue equatios -dimesioal problems Limitatios of Quatum
More informationComplete Solutions to Supplementary Exercises on Infinite Series
Coplete Solutios to Suppleetary Eercises o Ifiite Series. (a) We eed to fid the su ito partial fractios gives By the cover up rule we have Therefore Let S S A / ad A B B. Covertig the suad / the by usig
More informationR is a scalar defined as follows:
Math 8. Notes o Dot Product, Cross Product, Plaes, Area, ad Volumes This lecture focuses primarily o the dot product ad its may applicatios, especially i the measuremet of agles ad scalar projectio ad
More informationSequences and Series of Functions
Chapter 6 Sequeces ad Series of Fuctios 6.1. Covergece of a Sequece of Fuctios Poitwise Covergece. Defiitio 6.1. Let, for each N, fuctio f : A R be defied. If, for each x A, the sequece (f (x)) coverges
More informationMTH Assignment 1 : Real Numbers, Sequences
MTH -26 Assigmet : Real Numbers, Sequeces. Fid the supremum of the set { m m+ : N, m Z}. 2. Let A be a o-empty subset of R ad α R. Show that α = supa if ad oly if α is ot a upper boud of A but α + is a
More informationMath F15 Rahman
Math 2-009 F5 Rahma Week 0.9 Covergece of Taylor Series Sice we have so may examples for these sectios ad it s usually a simple matter of recallig the formula ad pluggig i for it, I ll simply provide the
More informationNumerical Methods in Fourier Series Applications
Numerical Methods i Fourier Series Applicatios Recall that the basic relatios i usig the Trigoometric Fourier Series represetatio were give by f ( x) a o ( a x cos b x si ) () where the Fourier coefficiets
More information1 Lecture 2: Sequence, Series and power series (8/14/2012)
Summer Jump-Start Program for Aalysis, 202 Sog-Yig Li Lecture 2: Sequece, Series ad power series (8/4/202). More o sequeces Example.. Let {x } ad {y } be two bouded sequeces. Show lim sup (x + y ) lim
More informationNotes The Incremental Motion Model:
The Icremetal Motio Model: The Jacobia Matrix I the forward kiematics model, we saw that it was possible to relate joit agles θ, to the cofiguratio of the robot ed effector T I this sectio, we will see
More informationMa 530 Infinite Series I
Ma 50 Ifiite Series I Please ote that i additio to the material below this lecture icorporated material from the Visual Calculus web site. The material o sequeces is at Visual Sequeces. (To use this li
More informationSolution: APPM 1360 Final Spring 2013
APPM 36 Fial Sprig 3. For this proble let the regio R be the regio eclosed by the curve y l( ) ad the lies, y, ad y. (a) (6 pts) Fid the area of the regio R. (b) (6 pts) Suppose the regio R is revolved
More informationMath 113, Calculus II Winter 2007 Final Exam Solutions
Math, Calculus II Witer 7 Fial Exam Solutios (5 poits) Use the limit defiitio of the defiite itegral ad the sum formulas to compute x x + dx The check your aswer usig the Evaluatio Theorem Solutio: I this
More information