t.lu ]pt.com :sies}u{ X } UEJ if definition definition ) examples topology top B={ sin Then t eu Examples : lr( concepts Examples XEBCU topology?
|
|
- Marcus Copeland
- 5 years ago
- Views:
Transcription
1 Basic nsn metric inite Re on teu need on etc hen J Review o opology concepts o what a ology? 3 JCPC UEJ ti tlu 3 U UZEJ U NUZEJ Examples space RLP C[ 0 ]y complement RE lry R air CEO ]pt com 2 How to generate a ology? B and sub 8 s B B B sin sies}u } UEJ i txe U BEB EBCU 3 i Examples lr B a b acb a be Q } B
2 i criterion J UEJ Un on 4 closed subsets limit points closure t closed xe U txe U txea # t n B Y?i # i Yi } + $ nbhd U o x U to so xct t 7 x mbhd U o UN > UC Examples 5 Subspace ology by universal B and S C subset U UEJ property ii continuous h s continuous 7 " h ioh ioh continuous Z Example C C C then [ N s the closure C n o 6 product ology Jz Bx Ux E EJZ } universal property 7 Quotient ology h /ti Z oh C i x r i s continuous x ~ l i 3 Y s surjeetive UEY i U c x C ~ i cx C x [ ] /~ a Y h continuous oh s conti he e ail quotient an ti Y cx gluing points in [ x ] together
3 Quotient connected such locally Y on the inest that continuous universal property Y g i yzl9 g s continuous coat c got Continuity Y continuous i UEJY U C Jx ; n terms o ; or or closed subsets read notes Y cont k FL z Y continuous YUL a C td i i C closed ti i y Ud Y cont Y cont # # ly lai i Ua Y continuous Y continuous homeomorphm y and onto are continuous embedding Example x an embedding 0 x x 2 op 0 o z * normal 2 Connected path * * components path connected R [ RC [ 0 ] # txt } C s closed components read the notes connected 3 Compact Lo ] inite complement metric spaces uniorm continuity extreme value theorem Read the notes 26 7
4 Jr rom closed UK Jk lu Review the property Prove 3 a that t K C compact 2 2 C s 3k xez i check Proo o space s the set o U C satying in K a ology on 3 such that 3 C Jk c z n in 3 K n } C 2 x n n in 3 by ZNK closed in K in C } 2 n K xn x xe Znk xe 2 C compact z Y z Y are continuous maps o spaces i let xy i E i x zcxz } 4 Given y i the subspace xy r ix the product hen a prone that the projections x i s continuous j 2 Prove that the map ixy s i z s Y called an map i t UC CY Proo al xxz# in i U yuz 2 o xy i s given by U Uz U c Uzt z t suices to prove that U y Uz C s U xyvz YU xu U Uz y Check U Uzn y * U i C UZ z s z U s continuous Uixy Uz C
5 let Prove suppose Write i } Let Prove Review 2 have the with subsets & 2 } be a that subsets o x i 2 } are o the Ux u orm 2 space where C U and U are n 2 B C C are connected and Bnc t $ that 3 U C 2 s a connected subset o x 2 } Proo n element in a o 2 Ux 2 or ik } where U E x so subsets o 2 are W!±Ui 2 } U ;Yyjx i } U ±Ui W ; W U Yu i jej } u U u so W Ux U 2 U C U U are n czl as a djoint union o subsets win u WZ where W U U ix 2 Wz Uz U i 2 i CU ; n ti Win BU u C 2 WZ Bauzlxl U ki 2 hus WW BU u 3027 u nv u Cnn 2 Bx u C2 B BNU UCBU c v Cnw cnv C connected suppose CN Cnz C C C z then o ± CNBC BC UZB BNU BnUz B BC Uz hus Win$ connected
6 Need C Y F Review example 2 Y s a projection between spaces Prove that i Y s compact then closed a closed i t C closed FC CY closed map Y called Proo C Y closed C C closed ^ C txe tiwxyc*gyjn By the ube Lemma? Y 7 an nbhd U o x in Ux Y C xy C Y s UyUy yxuy C xy x Y C n YEY C xxy U yi C Uyi Y i t YEY xxy E x Y mbhd Uy o y and y o such that compact 7 Y ;YnEY n ake ny U # Uyi Y xy C xy C Y i hus C Ux Y Y x xe U C El
7 suppose Review example 3 Y a map x cxi xe } C Y between spaces Y Hausdor # and compact Prove that continuous C i Y s closed Proo Need Y to x y E Y cxl ty in Y which s Hausdor 7 djoint sets U and the U ye Un x y e i U C s Y Gg unv x Y s a closed map since Y compact CY closed need to prove that C C s closed Y Y in t d x ix eicly # the a C n x t t closed closed d closed n
CHOW S LEMMA. Matthew Emerton
CHOW LEMMA Matthew Emerton The aim o this note is to prove the ollowing orm o Chow s Lemma: uppose that : is a separated inite type morphism o Noetherian schemes. Then (or some suiciently large n) there
More informationT h e C S E T I P r o j e c t
T h e P r o j e c t T H E P R O J E C T T A B L E O F C O N T E N T S A r t i c l e P a g e C o m p r e h e n s i v e A s s es s m e n t o f t h e U F O / E T I P h e n o m e n o n M a y 1 9 9 1 1 E T
More informationthat a w r o n g has been committed recognize where the responsibility
Z- XX q q J U Y ' G G, w, 142 16, U, j J ' B ' B B k - J, 5 6 5:30 7:00, $125;, -, 10:00 $300;, 4:00, 6:00, B C U 000 2:00, J $125; ' :, q C, k w G x q k w w w w q ' 60,, w q, w w k w w - G w z w w w C
More informationTopological properties
CHAPTER 4 Topological properties 1. Connectedness Definitions and examples Basic properties Connected components Connected versus path connected, again 2. Compactness Definition and first examples Topological
More informationMath General Topology Fall 2012 Homework 8 Solutions
Math 535 - General Topology Fall 2012 Homework 8 Solutions Problem 1. (Willard Exercise 19B.1) Show that the one-point compactification of R n is homeomorphic to the n-dimensional sphere S n. Note that
More informationNAME: Mathematics 205A, Fall 2008, Final Examination. Answer Key
NAME: Mathematics 205A, Fall 2008, Final Examination Answer Key 1 1. [25 points] Let X be a set with 2 or more elements. Show that there are topologies U and V on X such that the identity map J : (X, U)
More informationH r# W im FR ID A Y, :Q q ro B E R 1 7,.,1 0 1 S. NEPTUNE TH RHE. Chancelor-Sherlll Act. on Ballot at ^yisii/
( # Y Q q 7 G Y G K G Q ( ) _ ( ) x z \ G 9 [ 895 G $ K K G x U Y 6 / q Y x 7 K 3 G? K x z x Y Y G U UY ( x G 26 $ q QUY K X Y 92 G& j x x ]( ] q ] x 2 ] 22 (? ] Y Y $ G x j 88 89 $5 Y ] x U $ 852 $ ((
More informationON THE HK COMPLETIONS OF SEQUENCE SPACES. Abduallah Hakawati l, K. Snyder2 ABSTRACT
An-Najah J. Res. Vol. II. No. 8, (1994) A. Allah Hakawati & K. Snyder ON THE HK COMPLETIONS OF SEQUENCE SPACES Abduallah Hakawati l, K. Snyder2 2.;.11 1 Le Ile 4) a.ti:;11 1 Lai 131 1 ji HK j; ) 1 la.111
More informationGENERALIZED ABSTRACT NONSENSE: CATEGORY THEORY AND ADJUNCTIONS
GENERALIZED ABSTRACT NONSENSE: CATEGORY THEORY AND ADJUNCTIONS CHRIS HENDERSON Abstract. This paper will move through the basics o category theory, eventually deining natural transormations and adjunctions
More informationMTG 5316/4302 FALL 2018 REVIEW FINAL
MTG 5316/4302 FALL 2018 REVIEW FINAL JAMES KEESLING Problem 1. Define open set in a metric space X. Define what it means for a set A X to be connected in a metric space X. Problem 2. Show that if a set
More informationlif {Kn} is a decreasing sequence of non-empty subsets of X such 5. wm.spaces and Closed Maps
16 Proc. Japan Acad., 46 (1970) [Vol. 46, 5. wm.spaces and Closed Maps By Tadashi ISHII Utsunomiya University (Comm. by Kinjir6 KIINUGI, M.Z.A., Jan. 12, 1970) 1. Introduction. In our previous paper [5],
More informationMath 216A. A gluing construction of Proj(S)
Math 216A. A gluing construction o Proj(S) 1. Some basic deinitions Let S = n 0 S n be an N-graded ring (we ollows French terminology here, even though outside o France it is commonly accepted that N does
More informationCONVERGENT SEQUENCES IN SEQUENCE SPACES
MATHEMATICS CONVERGENT SEQUENCES IN SEQUENCE SPACES BY M. DORLEIJN (Communicated by Prof. J. F. KoKSMA at the meeting of January 26, 1957) In the theory of sequence spaces, given by KoTHE and ToEPLITZ
More informationTHE PRODUCT OF A LINDELÖF SPACE WITH THE SPACE OF IRRATIONALS UNDER MARTIN'S AXIOM
proceedings of the american mathematical society Volume 110, Number 2, October 1990 THE PRODUCT OF A LINDELÖF SPACE WITH THE SPACE OF IRRATIONALS UNDER MARTIN'S AXIOM K. ALSTER (Communicated by Dennis
More informationChapter 3 Second Order Linear Equations
Partial Differential Equations (Math 3303) A Ë@ Õæ Aë áöß @. X. @ 2015-2014 ú GA JË@ É Ë@ Chapter 3 Second Order Linear Equations Second-order partial differential equations for an known function u(x,
More informationHr(X1) + Hr(X2) - Hr(Xl n X2) <- H,+,(Xi U X2),
~~~~~~~~A' A PROBLEM OF BING* BY R. L. WILDER DEPARTMENT OF MATHEMATICS, UNIVERSITY OF MICHIGAN, ANN ARBOR Communicated July 8, 1965 1. In a recent paper,' R. H. Bing utilized (and proved) a lemma to the
More informationP a g e 5 1 of R e p o r t P B 4 / 0 9
P a g e 5 1 of R e p o r t P B 4 / 0 9 J A R T a l s o c o n c l u d e d t h a t a l t h o u g h t h e i n t e n t o f N e l s o n s r e h a b i l i t a t i o n p l a n i s t o e n h a n c e c o n n e
More informationNon commutative Khintchine inequalities and Grothendieck s theo
Non commutative Khintchine inequalities and Grothendieck s theorem Nankai, 2007 Plan Non-commutative Khintchine inequalities 1 Non-commutative Khintchine inequalities 2 µ = Uniform probability on the set
More informationImplicit Functions, Curves and Surfaces
Chapter 11 Implicit Functions, Curves and Surfaces 11.1 Implicit Function Theorem Motivation. In many problems, objects or quantities of interest can only be described indirectly or implicitly. It is then
More informationMH 7500 THEOREMS. (iii) A = A; (iv) A B = A B. Theorem 5. If {A α : α Λ} is any collection of subsets of a space X, then
MH 7500 THEOREMS Definition. A topological space is an ordered pair (X, T ), where X is a set and T is a collection of subsets of X such that (i) T and X T ; (ii) U V T whenever U, V T ; (iii) U T whenever
More informationMAT 578 FUNCTIONAL ANALYSIS EXERCISES
MAT 578 FUNCTIONAL ANALYSIS EXERCISES JOHN QUIGG Exercise 1. Prove that if A is bounded in a topological vector space, then for every neighborhood V of 0 there exists c > 0 such that tv A for all t > c.
More informationLINEAR ALGEBRA SUMMARY SHEET.
LINEAR ALGEBRA SUMMARY SHEET RADON ROSBOROUGH https://intuitiveexplanationscom/linear-algebra-summary-sheet/ This document is a concise collection of many of the important theorems of linear algebra, organized
More informationREPRESENTATIONS FOR A SPECIAL SEQUENCE
REPRESENTATIONS FOR A SPECIAL SEQUENCE L. CARLITZ* RICHARD SCOVILLE Dyke University, Durham,!\!orth Carolina VERNERE.HOGGATTJR. San Jose State University, San Jose, California Consider the sequence defined
More informationInfinite-dimensional cohomology of SL 2
Infinite-dimensional cohomology of SL 2 ( Z[t, t 1 ] ) Sarah Cobb June 5, 2015 Abstract For J an integral domain and F its field of fractions, we construct a map from the 3-skeleton of the classifying
More informationCALCULUS. Berkant Ustaoğlu CRYPTOLOUNGE.NET
CALCULUS Berkant Ustaoğlu CRYPTOLOUNGE.NET Secant 1 Definition Let f be defined over an interval I containing u. If x u and x I then f (x) f (u) Q = x u is the difference quotient. Also if h 0, such that
More information7. Quotient and Bi.quotient Spaces o M.spaces
No. 1] Proc. Japan Acad., 4 (1969 25 7. Quotient and Bi.quotient Spaces o M.spaces By Jun-iti NAGATA I Department of Mathematics, University of Pittsburgh (Comm. by Kinjir KUNUGI, M. J. A., Jan. 13, 1969
More informationP a g e 3 6 of R e p o r t P B 4 / 0 9
P a g e 3 6 of R e p o r t P B 4 / 0 9 p r o t e c t h um a n h e a l t h a n d p r o p e r t y fr om t h e d a n g e rs i n h e r e n t i n m i n i n g o p e r a t i o n s s u c h a s a q u a r r y. J
More informationON ADDITIVE PARTITIONS OF SETS OF POSITIVE INTEGERS
Discrete Mathematics 36 (1981) 239-245 North-Holland Publishing Company ON ADDITIVE PARTITIONS OF SETS OF POSITIVE INTEGERS Ronald J. EVANS Deparfmenf of Mafhemaks, Uniuersity of California, San Diego,
More informationREAD T H E DATE ON LABEL A blue m a r k a r o u n d this notice will call y o u r attention to y o u r LOWELL. MICHIGAN, THURSDAY, AUGUST 29.
B U D D B < / UDY UU 29 929 VU XXXV Y B 5 2 $25 25 25 U 6 B j 3 $8 D D D VD V D D V D B B % B 2 D - Q 22: 5 B 2 3 Z D 2 5 B V $ 2 52 2 $5 25 25 $ Y Y D - 8 q 2 2 6 Y U DD D D D Y!! B D V!! XU XX D x D
More informationMrs. Joseph Snell Laid lo Rest at 63. Union Service to. Open Lenten Season
U N x» C V YK O CN C 4 94 C N Y O UCC j! j q? N C 5 : 72 92 776 45 74 5 N N : ( z ) N 7 q 6 N 4 C U V O N 6 27 2 7: C 2 C V x N O 2 C C 79 z N \ 27 97 O C 5 N C K C 97 97 N C 4 N C j K ; 26 5 2 25 C K
More information1 Directional Derivatives and Differentiability
Wednesday, January 18, 2012 1 Directional Derivatives and Differentiability Let E R N, let f : E R and let x 0 E. Given a direction v R N, let L be the line through x 0 in the direction v, that is, L :=
More informationTHE FIXED POINT PROPERTY FOR CONTINUA APPROXIMATED FROM WITHIN BY PEANO CONTINUA WITH THIS PROPERTY
PROCEEDINGS OF THE AMERICAN MATHEMATICAL SOCIETY Volume 91, Number 3, July 1984 THE FIXED POINT PROPERTY FOR CONTINUA APPROXIMATED FROM WITHIN BY PEANO CONTINUA WITH THIS PROPERTY AKIRA TOMINAGA ABSTRACT.
More informationTrade Patterns, Production networks, and Trade and employment in the Asia-US region
Trade Patterns, Production networks, and Trade and employment in the Asia-U region atoshi Inomata Institute of Developing Economies ETRO Development of cross-national production linkages, 1985-2005 1985
More informationMATH 304 Linear Algebra Lecture 15: Linear transformations (continued). Range and kernel. Matrix transformations.
MATH 304 Linear Algebra Lecture 15: Linear transformations (continued). Range and kernel. Matrix transformations. Linear mapping = linear transformation = linear function Definition. Given vector spaces
More informationand the union is open in X. If12U j for some j, then12 [ i U i and bx \ [ i (X \ U i ) U i = \ i ( b X \ U i )= \ i
29. Mon, Nov. 3 Locally compact Hausdor spaces are a very nice class of spaces (almost as good as compact Hausdor ). In fact, any such space is close to a compact Hausdor space. Definition 29.1. A compactification
More informationLecture 31 INTEGRATION
Lecture 3 INTEGRATION Substitution. Example. x (let u = x 3 +5 x3 +5 du =3x = 3x 3 x 3 +5 = du 3 u du =3x ) = 3 u du = 3 u = 3 u = 3 x3 +5+C. Example. du (let u =3x +5 3x+5 = 3 3 3x+5 =3 du =3.) = 3 du
More informationB553 Lecture 3: Multivariate Calculus and Linear Algebra Review
B553 Lecture 3: Multivariate Calculus and Linear Algebra Review Kris Hauser December 30, 2011 We now move from the univariate setting to the multivariate setting, where we will spend the rest of the class.
More informationCrew of25 Men Start Monday On Showboat. Many Permanent Improvements To Be Made;Project Under WPA
U G G G U 2 93 YX Y q 25 3 < : z? 0 (? 8 0 G 936 x z x z? \ 9 7500 00? 5 q 938 27? 60 & 69? 937 q? G x? 937 69 58 } x? 88 G # x 8 > x G 0 G 0 x 8 x 0 U 93 6 ( 2 x : X 7 8 G G G q x U> x 0 > x < x G U 5
More informationl(y j ) = 0 for all y j (1)
Problem 1. The closed linear span of a subset {y j } of a normed vector space is defined as the intersection of all closed subspaces containing all y j and thus the smallest such subspace. 1 Show that
More informationEconomics 620, Lecture 2: Regression Mechanics (Simple Regression)
1 Economics 620, Lecture 2: Regression Mechanics (Simple Regression) Observed variables: y i ; x i i = 1; :::; n Hypothesized (model): Ey i = + x i or y i = + x i + (y i Ey i ) ; renaming we get: y i =
More informationWeak Topologies, Reflexivity, Adjoint operators
Chapter 2 Weak Topologies, Reflexivity, Adjoint operators 2.1 Topological vector spaces and locally convex spaces Definition 2.1.1. [Topological Vector Spaces and Locally convex Spaces] Let E be a vector
More informationDiff. Eq. App.( ) Midterm 1 Solutions
Diff. Eq. App.(110.302) Midterm 1 Solutions Johns Hopkins University February 28, 2011 Problem 1.[3 15 = 45 points] Solve the following differential equations. (Hint: Identify the types of the equations
More informationi c Robert C. Gunning
c Robert C. Gunning i ii MATHEMATICS 218: NOTES Robert C. Gunning January 27, 2010 ii Introduction These are notes of honors courses on calculus of several variables given at Princeton University during
More informationint cl int cl A = int cl A.
BAIRE CATEGORY CHRISTIAN ROSENDAL 1. THE BAIRE CATEGORY THEOREM Theorem 1 (The Baire category theorem. Let (D n n N be a countable family of dense open subsets of a Polish space X. Then n N D n is dense
More information4 Countability axioms
4 COUNTABILITY AXIOMS 4 Countability axioms Definition 4.1. Let X be a topological space X is said to be first countable if for any x X, there is a countable basis for the neighborhoods of x. X is said
More informationReal Analysis Math 131AH Rudin, Chapter #1. Dominique Abdi
Real Analysis Math 3AH Rudin, Chapter # Dominique Abdi.. If r is rational (r 0) and x is irrational, prove that r + x and rx are irrational. Solution. Assume the contrary, that r+x and rx are rational.
More informationN C GM L P, u u y Du J W P: u,, uy u y j S, P k v, L C k u, u GM L O v L v y, u k y v v QV v u, v- v ju, v, u v u S L v: S u E x y v O, L O C u y y, k
Qu V vu P O B x 1361, Bu QLD 4575 C k N 96 N EWSLEE NOV/ DECE MBE 2015 E N u uu L O C 21 Nv, 2 QV v Py Cu Lv Su, 23 2 5 N v, 4 2015 u G M v y y : y quu u C, u k y Bu k v, u u vy v y y C k! u,, uu G M u
More informationSolving First Order PDEs
Solving Ryan C. Trinity University Partial Differential Equations January 21, 2014 Solving the transport equation Goal: Determine every function u(x, t) that solves u t +v u x = 0, where v is a fixed constant.
More informationMetric Spaces and Topology
Chapter 2 Metric Spaces and Topology From an engineering perspective, the most important way to construct a topology on a set is to define the topology in terms of a metric on the set. This approach underlies
More informationHypographs of Upper Semi-continuous Maps and Continuous Maps on a Bounded Open Interval
American Journal of Applied Mathematics 216; 42): 75-79 http://www.sciencepublishinggroup.com/j/ajam doi: 1.11648/j.ajam.21642.12 ISSN: 233-43 Print); ISSN: 233-6X Online) Hypographs of Upper Semi-continuous
More information(z 0 ) = lim. = lim. = f. Similarly along a vertical line, we fix x = x 0 and vary y. Setting z = x 0 + iy, we get. = lim. = i f
. Holomorphic Harmonic Functions Basic notation. Considering C as R, with coordinates x y, z = x + iy denotes the stard complex coordinate, in the usual way. Definition.1. Let f : U C be a complex valued
More informationTools from Lebesgue integration
Tools from Lebesgue integration E.P. van den Ban Fall 2005 Introduction In these notes we describe some of the basic tools from the theory of Lebesgue integration. Definitions and results will be given
More informationSobolev Spaces. Chapter Hölder spaces
Chapter 2 Sobolev Spaces Sobolev spaces turn out often to be the proper setting in which to apply ideas of functional analysis to get information concerning partial differential equations. Here, we collect
More informationAnalysis Comprehensive Exam Questions Fall F(x) = 1 x. f(t)dt. t 1 2. tf 2 (t)dt. and g(t, x) = 2 t. 2 t
Analysis Comprehensive Exam Questions Fall 2. Let f L 2 (, ) be given. (a) Prove that ( x 2 f(t) dt) 2 x x t f(t) 2 dt. (b) Given part (a), prove that F L 2 (, ) 2 f L 2 (, ), where F(x) = x (a) Using
More informationDIFFERENTIAL GEOMETRY 1 PROBLEM SET 1 SOLUTIONS
DIFFERENTIAL GEOMETRY PROBLEM SET SOLUTIONS Lee: -4,--5,-6,-7 Problem -4: If k is an integer between 0 and min m, n, show that the set of m n matrices whose rank is at least k is an open submanifold of
More informationABSOLUTE F. SPACES A. H. STONE
ABSOLUTE F. SPACES A. H. STONE 1. Introduction. All spaces referred to in this paper are assumed to be metric (or, more accurately, metrizable); metrics are denoted by symbols like p. A space X is said
More informationTopology Part of the Qualify Exams of Department of Mathematics, Texas A&M University Prepared by Zhang, Zecheng
Topology Part of the Qualify Exams of Department of Mathematics, Texas A&M University Prepared by Zhang, Zecheng Remark 0.1. This is a solution Manuel to the topology questions of the Topology Geometry
More informationSpring -07 TOPOLOGY III. Conventions
Spring -07 TOPOLOGY III Conventions In the following, a space means a topological space (unless specified otherwise). We usually denote a space by a symbol like X instead of writing, say, (X, τ), and we
More informationSolution Sheet 3. Solution Consider. with the metric. We also define a subset. and thus for any x, y X 0
Solution Sheet Throughout this sheet denotes a domain of R n with sufficiently smooth boundary. 1. Let 1 p
More informationExtra Problems and Examples
Extra Problems and Examples Steven Bellenot October 11, 2007 1 Separation of Variables Find the solution u(x, y) to the following equations by separating variables. 1. u x + u y = 0 2. u x u y = 0 answer:
More informationLOWELL. MICHIGAN, THURSDAY, MAY 23, Schools Close. method of distribution. t o t h e b o y s of '98 a n d '18. C o m e out a n d see t h e m get
UY Y 99 U XXX 5 Q == 5 K 8 9 $8 7 Y Y 8 q 6 Y x) 5 7 5 q U «U YU x q Y U ) U Z 9 Y 7 x 7 U x U x 9 5 & U Y U U 7 8 9 x 5 x U x x ; x x [ U K»5 98 8 x q 8 q K x Y Y x K Y 5 ~ 8» Y x ; ; ; ; ; ; 8; x 7;
More informationTOPOLOGY HW 2. x x ± y
TOPOLOGY HW 2 CLAY SHONKWILER 20.9 Show that the euclidean metric d on R n is a metric, as follows: If x, y R n and c R, define x + y = (x 1 + y 1,..., x n + y n ), cx = (cx 1,..., cx n ), x y = x 1 y
More informationCommentationes Mathematicae Universitatis Carolinae
Commentationes Mathematicae Universitatis Carolinae Aleš Pultr An analogon of the fixed-point theorem and its application for graphs Commentationes Mathematicae Universitatis Carolinae, Vol. 4 (1963),
More informationScilab Textbook Companion for Linear Algebra and Its Applications by D. C. Lay 1
Scilab Textbook Companion for Linear Algebra and Its Applications by D. C. Lay 1 Created by Animesh Biyani B.Tech (Pursuing) Electrical Engineering National Institute Of Technology, Karnataka College Teacher
More informationON β-spaces, ^-SPACES AND k(x)
PACIFIC JOURNAL OF MATHEMATICS Vol. 47, No. 2, 1973 ON β-spaces, ^-SPACES AND k(x) E. MICHAEL Two examples of Avspaces which are not A -spaces are constructed; one of them is a σ-compact cosmic space,
More informationNOWHERE LOCALLY UNIFORMLY CONTINUOUS FUNCTIONS
NOWHERE LOCALLY UNIFORMLY CONTINUOUS FUNCTIONS K. Jarosz Southern Illinois University at Edwardsville, IL 606, and Bowling Green State University, OH 43403 kjarosz@siue.edu September, 995 Abstract. Suppose
More informationDefinition 6.1. A metric space (X, d) is complete if every Cauchy sequence tends to a limit in X.
Chapter 6 Completeness Lecture 18 Recall from Definition 2.22 that a Cauchy sequence in (X, d) is a sequence whose terms get closer and closer together, without any limit being specified. In the Euclidean
More informationB 1 = {B(x, r) x = (x 1, x 2 ) H, 0 < r < x 2 }. (a) Show that B = B 1 B 2 is a basis for a topology on X.
Math 6342/7350: Topology and Geometry Sample Preliminary Exam Questions 1. For each of the following topological spaces X i, determine whether X i and X i X i are homeomorphic. (a) X 1 = [0, 1] (b) X 2
More informationTOPOLOGIE ET GÉOMÉTRIE DIFFÉRENTIELLE CATÉGORIQUES. Closed categories and topological vector spaces
CAHIERS DE TOPOLOGIE ET GÉOMÉTRIE DIFFÉRENTIELLE CATÉGORIQUES MICHAEL BARR Closed categories and topological vector spaces Cahiers de topologie et géométrie différentielle catégoriques, tome 17, n o 3
More informationFour-coloring P 6 -free graphs. I. Extending an excellent precoloring
Four-coloring P 6 -free graphs. I. Extending an excellent precoloring Maria Chudnovsky Princeton University, Princeton, NJ 08544 Sophie Spirkl Princeton University, Princeton, NJ 08544 Mingxian Zhong Columbia
More information12 16 = (12)(16) = 0.
Homework Assignment 5 Homework 5. Due day: 11/6/06 (5A) Do each of the following. (i) Compute the multiplication: (12)(16) in Z 24. (ii) Determine the set of units in Z 5. Can we extend our conclusion
More informationCLOPEN SETS IN HYPERSPACES1
PROCEEDINGS OF THE AMERICAN MATHEMATICAL Volume 54, January 1976 SOCIETY CLOPEN SETS IN HYPERSPACES1 PAUL BANKSTON Abstract. Let A' be a space and let H(X) denote its hyperspace (= all nonempty closed
More informationLOWELL/ JOURNAL. crew of the schooner Reuben Doud, swept by the West India hurricane I Capt William Lennon alone on the
LELL/ UL V 9 X 9 LELL E UU 3 893 L E UY V E L x Y VEEL L E Y 5 E E X 6 UV 5 Y 6 x E 8U U L L 5 U 9 L Q V z z EE UY V E L E Y V 9 L ) U x E Y 6 V L U x z x Y E U 6 x z L V 8 ( EVY LL Y 8 L L L < 9 & L LLE
More informationThe set of points at which a polynomial map is not proper
ANNALES POLONICI MATHEMATICI LVIII3 (1993) The set of points at which a polynomial map is not proper by Zbigniew Jelonek (Kraków) Abstract We describe the set of points over which a dominant polynomial
More informationTheorem The following are equivalent (assuming the other standard set theory axioms):
Chapter 1 Sets Notation: f : X Y A X B Y f(a) := {f(a) a A} Y f 1 (B) := {x X f(x) B} Note: f 1 ( α I V α ) = α I f 1 (V α ) f 1 ( α I V α ) = α I f 1 (V α ) f(p Q) = f(p) f(q) but in general f(p Q) f(p)
More informationc) LC=Cl+C2+C3; C1:x=dx=O; C2: y=1-x; C3:y=dy=0 1 ydx-xdy (1-x)~x-x(-dx)+ = Jdldx = 1.
4. Line Integrals in the Plane 4A. Plane Vector Fields 4A- a) All vectors in the field are identical; continuously differentiable everywhere. b) he vector at P has its tail at P and head at the origin;
More informationMath 5210, Definitions and Theorems on Metric Spaces
Math 5210, Definitions and Theorems on Metric Spaces Let (X, d) be a metric space. We will use the following definitions (see Rudin, chap 2, particularly 2.18) 1. Let p X and r R, r > 0, The ball of radius
More informationSolutions to Problem Set 1
Solutions to Problem Set 1 18.904 Spring 2011 Problem 1 Statement. Let n 1 be an integer. Let CP n denote the set of all lines in C n+1 passing through the origin. There is a natural map π : C n+1 \ {0}
More informationChair Susan Pilkington called the meeting to order.
PGE PRK D RECREO DVOR COMMEE REGUR MEEG MUE MOD, JU, Ru M h P P d R d Cmm hd : m Ju,, h Cu Chmb C H P, z Ch u P dd, Mmb B C, Gm Cu D W Bd mmb b: m D, d Md z ud mmb : C M, J C P Cmmu Dm D, Km Jh Pub W M,
More informationPOINTWISE PRODUCTS OF UNIFORMLY CONTINUOUS FUNCTIONS
SARAJEVO JOURNAL OF MATHEMATICS Vol.1 (13) (2005), 117 127 POINTWISE PRODUCTS OF UNIFORMLY CONTINUOUS FUNCTIONS SAM B. NADLER, JR. Abstract. The problem of characterizing the metric spaces on which the
More informationMAS331: Metric Spaces Problems on Chapter 1
MAS331: Metric Spaces Problems on Chapter 1 1. In R 3, find d 1 ((3, 1, 4), (2, 7, 1)), d 2 ((3, 1, 4), (2, 7, 1)) and d ((3, 1, 4), (2, 7, 1)). 2. In R 4, show that d 1 ((4, 4, 4, 6), (0, 0, 0, 0)) =
More informationENGI 4430 PDEs - d Alembert Solutions Page 11.01
ENGI 4430 PDEs - d Alembert Solutions Page 11.01 11. Partial Differential Equations Partial differential equations (PDEs) are equations involving functions of more than one variable and their partial derivatives
More informationPESTICIDE STORAGE & HANDLING Paul Sumner, Senior Public Service Associate Biological & Agricultural Engineering
O & HNIN OI **Y N Y -N: II O & HNIN u u, i ui vi i igi & giuu giig iv xi vi, Uiviy gi, g giuu vi i, Wy u I? I i uy, ii ig u y - i ikig. uy, i ii uig i gi ikig. Hv, i ii uy u, y ug gu k i y iy uig ixig
More informationProjection-valued measures and spectral integrals
Projection-valued measures and spectral integrals Jordan Bell jordan.bell@gmail.com Department of Mathematics, University of Toronto April 16, 2014 Abstract The purpose of these notes is to precisely define
More informationMany of you got these steps reversed or otherwise out of order.
Problem 1. Let (X, d X ) and (Y, d Y ) be metric spaces. Suppose that there is a bijection f : X Y such that for all x 1, x 2 X. 1 10 d X(x 1, x 2 ) d Y (f(x 1 ), f(x 2 )) 10d X (x 1, x 2 ) Show that if
More informationSECTION v 2 x + v 2 y, (5.1)
CHAPTER 5 5.1 Normed Spaces SECTION 5.1 171 REAL AND COMPLEX NORMED, METRIC, AND INNER PRODUCT SPACES So far, our studies have concentrated only on properties of vector spaces that follow from Definition
More informationQUOTIENTS OF F-SPACES
QUOTIENTS OF F-SPACES by N. J. KALTON (Received 6 October, 1976) Let X be a non-locally convex F-space (complete metric linear space) whose dual X' separates the points of X. Then it is known that X possesses
More informationand A T. T O S O L O LOWELL. MICHIGAN. THURSDAY. NOVEMBER and Society Seriously Hurt Ann Arbor News Notes Thursday Eve
M-M- M N > N B W MN UY NVMB 22 928 VUM XXXV --> W M B B U M V N QUY Y Q W M M W Y Y N N M 0 Y W M Y x zz MM W W x M x B W 75 B 75 N W Y B W & N 26 B N N M N W M M M MN M U N : j 2 YU N 9 M 6 -- -
More informationLOCALLY ^-CLOSED SPACES AND RIM /»-CLOSED SPACES
PROCEEDINGS OF THE AMERICAN MATHEMATICAL SOCIETY Volume 87. Number.1. March luk.l LOCALLY ^-CLOSED SPACES AND RIM /»-CLOSED SPACES DIX H. PETTEY i Abstract. It is shown in this paper that for P = T2 or
More informationP. ERDÖS 2. We need several lemmas or the proo o the upper bound in (1). LEMMA 1. { d ( (k)) r 2 < x (log x)c5. This result is due to van der Corput*.
ON THE SUM E d( (k)). k=i 7 ON THE SUM E d ( (k)) k-, P. ERDÖS*. 1. Let d(n) denote the number o divisors o a positive integer n, and let (k) be an irreducible polynomial o degree l with integral coe icients.
More informationSOLUTIONS TO EXERCISES FOR. MATHEMATICS 133 Part 2. I. Topics from linear algebra
SOLUTIONS TO EXERCISES FOR MATHEMATICS 133 Part Fall 013 NOTE ON ILLUSTRATIONS. Drawings for several of the solutions in this file are available in the following document: http://math.ucr.edu/ res/math133/math133solutionsa.figures.f13.pdf
More informationMTG 6316 HOMEWORK Spring 2017
MTG 636 HOMEWORK Spring 207 0. (Section 26, #2) Let p : X! Y be a closed continuous surjective map such that p (y) is compact, for each y 2 Y. (Such a map is called a perfect map.) Show that if Y is compact,
More informationSEPARATED AND PROPER MORPHISMS
SEPARATED AND PROPER MORPHISMS BRIAN OSSERMAN Last quarter, we introduced the closed diagonal condition or a prevariety to be a prevariety, and the universally closed condition or a variety to be complete.
More informationfur \ \,,^N/ D7,,)d.s) 7. The champion and Runner up of the previous year shall be allowed to play directly in final Zone.
OUL O GR SODRY DUTO, ODS,RT,SMTUR,USWR.l ntuctin f cnuct f Kbi ( y/gil)tunent f 2L-Lg t. 2.. 4.. 6. Mtche hll be lye e K ule f ene f tie t tie Dutin f ech tch hll be - +0 (Rece)+ = M The ticint f ech Te
More informationIntroductory Analysis I Fall 2014 Homework #5 Solutions
Introductory Analysis I Fall 2014 Homework #5 Solutions 6. Let M be a metric space, let C D M. Now we can think of C as a subset of the metric space M or as a subspace of the metric space D (D being a
More informationIntroduction to Topology
Introduction to Topology Randall R. Holmes Auburn University Typeset by AMS-TEX Chapter 1. Metric Spaces 1. Definition and Examples. As the course progresses we will need to review some basic notions about
More informationSolving First Order PDEs
Solving Ryan C. Trinity University Partial Differential Equations Lecture 2 Solving the transport equation Goal: Determine every function u(x, t) that solves u t +v u x = 0, where v is a fixed constant.
More informationCHAPTER I. Rings. Definition A ring R is a set with two binary operations, addition + and
CHAPTER I Rings 1.1 Definitions and Examples Definition 1.1.1. A ring R is a set with two binary operations, addition + and multiplication satisfying the following conditions for all a, b, c in R : (i)
More informationLOWELL JOURNAL NEWS FROM HAWAII.
U # 2 3 Z7 B 2 898 X G V ; U» VU UU U z z 5U G 75 G } 2 B G G G G X G U 8 Y 22 U B B B G G G Y «j / U q 89 G 9 j YB 8 U z U - V - 2 z j _ ( UU 9 -! V G - U GB 8 j - G () V B V Y 6 G B j U U q - U z «B
More informationMAS113 CALCULUS II SPRING 2008, QUIZ 5 SOLUTIONS. x 2 dx = 3y + y 3 = x 3 + c. It can be easily verified that the differential equation is exact, as
MAS113 CALCULUS II SPRING 008, QUIZ 5 SOLUTIONS Quiz 5a Solutions (1) Solve the differential equation y = x 1 + y. (1 + y )y = x = (1 + y ) = x = 3y + y 3 = x 3 + c. () Solve the differential equation
More information