1(a)(i ) For one loop in correct quadrant(s) For two more loops. Continuous and broken lines Dependent on previous B1B1 M1 A1. For.
|
|
- Roderick McCarthy
- 6 years ago
- Views:
Transcription
1 7 Mark Scheme Jauary (a)(i ) (ii) Area is r dθ (b) a a ( θ + a ( + cos θ ) dθ d si θ ) (c) Puttig taθ Itegral is OR a cos θ dθ arcsi arcsi sec θ dθ sec θ cosθ siθ dθ M Puttig siθ A Itegral is θ A M A B B B M A M A B M AA M A M AA M A For oe loop i correct quadrat(s) For two more loops Cotiuous ad broke lies Depedet o previous BB For cos θ dθ For a correct itegral epressio icludig limits (may be implied by later work) For cos θ dθ θ + si θ Accept.a For arcsi For ad Depedet o previous M For ay ta substitutio For (sec θ ) sec θ ad Icludig limits of θ For ay sie substitutio For dθ For chagig to limits of θ Depedet o previous M
2 7 Mark Scheme Jauary (i) w, arg w θ w *, arg w* θ j w, arg jw θ + B B ft BB ft B (ii) jθ jθ jθ jθ ( + w)( + w*) + e + e + ( e )( e ) M + (cosθ + jsi θ ) + (cosθ jsi θ ) + + cosθ jθ (iii) jθ 8 jθ C + js e e + e... e e jθ jθ jθ e + e + jθ jθ e ( + e jθ ( + e )( + ( + + cosθ e e jθ + cosθ cos θ + cosθ C + cosθ si θ siθ S + cosθ jθ jθ ) e ) jθ ) jθ jθ e + e + cosθ A M A (ag) M M A M A M A (ag) A 8 w * ad jw i correct positios relative to their w i first quadrat Give B for at least two poits i correct quadrats jθ for w * e for + correctly obtaied for w (cosθ + jsi θ ) for cos θ correctly obtaied Obtaiig a geometric series Summig a ifiite geometric series Usig comple cojugate of deom Equatig real or imagiary parts Correctly obtaied
3 7 Mark Scheme Jauary (i) ( λ) [ ( λ)( λ) ] [ ( λ) ] + [ ( λ) ] ( λ)( λ + 7λ) (λ ) + (λ + ) λ + λ 9λ (ii) Whe λ, (iii) (iv) (v) ( λ + )( λ + λ ) ( λ + )( λ )( λ + 7) Other eigevalues are, 7 + y + z y + z y + y z z z, + y OR A eigevector is 8 8 M P D 7 8 M M A M 7 (vi) By CHT, M + M 9M I M + M 9I M M M + M I 7 9 M A A (ag) B M A M M A M AA B ft M A ft B M A Evaluatig det( M λ I) Allow oe omissio ad two sig errors det( M λ I) correct Correctly obtaied ( is required) or showig that ( λ + ) is a factor, ad deducig that is a root for (λ + ) quadratic factor At least two equatios Solvig to obtai a eigevector Appropriate vector product Evaluatio of vector product Ay method for verifyig or fidig a eigevector see or implied (ft) (codoe eigevalues i wrog order) Order must be cosistet with P (whe B has bee awarded) Codoe omissio of I Codoe dividig by M
4 7 Mark Scheme Jauary (a) ( e e ) + ( e e (e e )(e + e + ) e ) 8, l, l M M M AA A ft Epoetial form Quadratic i e Solvig to obtai a value of e Eact logarithmic form from positive values of e Depedet o M (b) (c)(i) OR c 8 c c c + M, M c AA ± l, ± l M l, l A e (e e ) d ( [ ] e e ( e ) ( ) + ( ) 9 + ) M M A A B Obtaiig quadratic i c (or s) ( s + s 8 ) Solvig to obtai a value of c (or s) or s, Logarithmic form (icludig ± if c) cao Epoetial form Itegratig to obtai a multiple of e Give B for ay o-zero multiple of this (ii) [ arsih( ) ] ( arsih( ) ) l + + l 9 + arsih( ) ( d ) M A ft B M M A (ag) Itegratio by parts applied to arsih( ) for d Usig both limits (provided both give o-zero values) Logarithmic form for arsih (itermediate step required)
5 7 Mark Scheme Jauary (i), (ii) (iii) k y + Asymptote is dy ( d y k < k > )( (k + ) ( ) ( ) ( ) k )() dy whe d Whe, k + > dy dy < whe <, > whe > d d Hece there is a miimum whe (iv) Curve crosses y whe k ) So curve crosses this asymptote ( k B M A B B B B M A A (ag) M A (ag) M A (ag) Dividig out or B for y stated k < for LH ad RH sectios for cetral sectio, with positive itercepts o both aes k > for LH ad cetral sectios for RH sectio, crossig -ais Usig quotiet rule (or equivalet) Ay correct form Correctly show d y or evaluatig whe d d y or k > whe 8 d
6 7 Mark Scheme Jauary (v) k < B Asymptotes show Itercepts k ad k idicated Miimum o positive y-ais Maimum show Give B for miimum ad maimum o cetral sectio k > B Asymptotes show Itercepts k ad k idicated Miimum o positive y-ais RH sectio crosses y ad approaches it from above Give B for RH sectio approachig both asymptotes correctly
7 7 Mark Scheme Jue (a)(i) B B Correct shape for < θ < icludig maimum i st quadrat Correct form at O ad o etra sectios (ii) (b)(i) (ii) Area is r dθ a ( + cosθ ) d θ a (θ + ( + ) a f ( ) sec ( f ( ) sec a ( + ( + ) cosθ + + cos θ ) dθ siθ + + ) ta( si θ ) f( ), f (), f () f( ) ) OR g ( u ) sec u (where g( u) ta u ) B g ( u) sec u ta u B g( ), g ( ), g ( ) M h h + ) f( ) g(... BAA ( + + ( h h h h ) d h +... ) ( h h h + h h ) M A B BB ft M A B B 7 For itegral of ( + cosθ ) For a correct itegral epressio icludig limits (may be implied by later work) Usig cos θ + cos θ Itegratio of cos θ ad cos θ Evaluatio usig si ( ± ) Ay correct form M Evaluatig f () or f () BAA M A ft A (ag) Codoe sec etc Evaluatig g ( ) or g ( ) Usig series ad itegratig (ft requires three o-zero terms) Correctly show Allow ft from + k + with k
8 7 Mark Scheme Jue (a)(i) z + z cos θ, z jsi θ z BB (ii) z z z z z + z z si θ cos θ + + z z z cos θ cos θ cos θ + si θ cos θ cos θ cos θ cos θ + ( A, B, C, D ) B M A M A ft A Epasio z z Usig z + θ cos with z, or. Allow M if used i partial epasio, or if omitted, etc (b)(i) + j, arg( + j) BB Accept.7;.79, (ii) r θ, 7,, 9, 7 B B Accept,., etc Accept.,.,.,.,. 7 Give B for three correct Give B for oe correct Deduct mark (maimum) if degrees used (,, 9, 8, ) + k ears B; with k,,,, ears B B Give B for four poits correct, or B ft for five poits (iii) e j j p, q j M A Eact evaluatio of a fifth root Give B for correct aswer stated or obtaied by ay other method
9 7 Mark Scheme Jue (i) M k k 8k k k M A M A M A Evaluatig determiat For ( k) must be simplified Fidig at least four cofactors At least siged cofactors correct Trasposig matri of cofactors ad dividig by determiat Fully correct OR Elemetary row operatios applied to M (LHS) ad I (RHS), ad obtaiig at least two zeros i LHS M Obtaiig oe row i LHS cosistig of two zeros ad a multiple of ( k) A or elemetary colum operatios Obtaiig oe row i RHS which is a multiple of a row of the iverse matri A Obtaiig two zeros i every row i LHS M Completig process to fid iverse MA (ii) y z 9 m M M M Substitutig k 7 ito iverse Correct use of iverse Evaluatig matri product m, y m, z m + A ft Give A ft for oe correct Accept usimplified forms or solutio left i matri form OR e.g. elimiatig, y z y z m M y m M m, y m, z m + A Elimiatig oe variable i two differet ways Obtaiig oe of, y, z Give M for ay other valid method leadig to oe of, y, z i terms of m Give A for oe correct (iii) Elimiatig, y + z y + z p For solutios, p M A M Elimiatig oe variable i two differet ways Two correct equatios Depedet o previous M OR Replacig oe colum of matri with colum from RHS, ad evaluatig determiat M determiat + p or p A For solutios, det M Depedet o previous M
10 7 Mark Scheme Jue OR Ay other method leadig to a equatio from which p could be foud M Correct equatio A Let z λ, p λ, y 8 λ, z λ A M (or M) A 7 Obtaiig a lie of solutios Give M whe M for fidig p or + λ, y λ, z 8 λ or λ, y + λ, z λ Accept z, y 8 z or y + z etc
11 7 Mark Scheme Jue (i) + sih + [ + ( e ( e cosh ( e + e e ) + e ) ] ) B B B (ag) For ( e e ) e + e For cosh ( e + e ) For completio (ii) ( + sih ) + sih M Usig (i) sih + sih ( sih )(sih + ) sih, M AA Solvig to obtai a value of sih arsih( ) l( ) l A ft arsih( ) l( + + ) l( ) A ft or l( + ) SR Give A for ± l, ± l( ) (iii) OR e + e e e + M (e )(e + )(e + e ) AA l, l( ) AA ft l (cosh ) d sih l 9 l l (iv) Put cosh u whe, u whe, u ar cosh l 9 d l l 9 sih l (sih u)(sih u du) 9 u du M AA M A (ag) M B A A Obtaiig a liear or quadratic factor For (e ) ad (e + e ) Epressig i itegrable form or ( e + e ) d or e e ) 8 8 ( l l For e 9 ad e 9 M for just statig etc Correctly obtaied Ay cosh substitutio sih( l ) For l Not awarded for arcosh Limits ot required 9
12 7 Mark Scheme Jue (i) B At least two cusps clearly show Give B for at least two arches Has cusps Periodic / Symmetrical i y-ais / Has maima / Is ever below the -ais B B Ay other feature (ii) B At least two miima (zero gradiet) clearly show Give B for geeral shape correct (at least two cycles) The curve has o cusps B For descriptio of ay differece (iii) (A) B At least two loops Give B for geeral shape correct (at least oe cycle) (B) (C) dy siθ d cosθ dy d is ifiite whe cosθ ( si ) Hece width of loop is ( ) θ M A M A M M (iv) k. B A (ag) Correct method of differetiatio Allow M if iverted siθ Allow k cosθ Ay correct value of θ Fidig width of loop Correctly obtaied Codoe egative aswer Give B for a value betwee ad (iclusive)
13 7 Mark Scheme Ja 7 (a)(i) (ii) Area is r dθ (b) (c)(i) (ii) kθ a (e ) d a kθ e k a ( e k + OR k ) d arcta arcta M Puttig taθ A Itegral is dθ A M A f ( ) ta, f () f ( ) sec, f () f ( ) sec ta, f () f ( ) sec + sec ta, f () ta + () +... ( )! h h ta d + (h h + 7h h h ( + h h h ) ( h + ) d 9 h ) θ B B M A M A M AA M A B M A B ft M A ft A ag Correct shape for θ Correct shape for θ Requires decreasig r o at least oe ais Igore other values of θ kθ For (e ) dθ For a correct itegral epressio icludig limits (may be implied by later work) (Codoe reversed limits) Obtaiig a multiple of e kθ as the itegral For arcta For ad Depedet o first M For ay ta substitutio For dθ For chagig to limits of θ Depedet o first M Obtaiig f ( ) For f () ad f () correct ft requires term ad at least oe other to be o-zero Obtaiig a polyomial to itegrate For + 9 ft requires at least two o-zero terms
14 7 Mark Scheme Ja 7 (a)(i) w, arg w z w z, arg z w, arg ( ) ( ) z B BB BB ft Deduct mark if aswers give i form r(cosθ + jsi θ ) but modulus ad argumet ot stated. Accept degrees ad decimal appros (ii) w (cos + jsi ) z + j M A Accept. +. j (b)(i) jθ e jθ + e (cos θ jsi cos θ θ ) + (cos θ + jsi θ ) M A For either bracketed epressio + e jθ e e jθ jθ (e jθ ( cos + e θ ) jθ ) M A ag OR + e jθ + cosθ + jsiθ cos θ + jsi θ cos θ M cos θ (cos θ + jsi θ ) jθ e cos θ A (ii) C + js + e ( + e ) C cos( e jθ θ j jθ cos θ ) cos S si( θ ) cos S si( C cos( θ ) cos + e θ ) cos θ θ θ jθ e jθ θ si( θ ) ta( θ cos( θ ) θ ) M MA M A A B ag Usig (i) to obtai a form from which the real ad imagiary parts ca be writte dow θ j Allow ft from C + js e ay 7 real fuctio of ad θ
15 7 Mark Scheme Ja 7 (i) k k ) ( ) ( det P k k k k P Whe, P k M A M M A ft B ag Evaluatig at least three cofactors Fully correct method for iverse Ft from wrog determiat Correctly obtaied (ii) M M M Eigevalues are,, M AAA For oe evaluatio OR M Eigevalues are,, A A Obtaiig a eigevalue (e.g. by solvig λ λ λ + ) Give A for oe correct Verifyig give eigevectors, likig with eigevalues correctly (iii) M BB MA B ft M A A ag 8 For ad see (for B, these must be cosistet) For SD S (MA if order wrog) or + + Evaluatig product of matrices Ay correct form
16 7 Mark Scheme Ja 7 OR Prove M A+ B by iductio Whe, A+ B M B k k Assumig M A+ B, k k M + AM+ BM MA A k ( B ) AA + A+ k B A True for k True for k + ; hece true for all positive itegers A or k+ k M MA+ MB Depedet o previous 7 marks
17 7 Mark Scheme Ja 7 (i) If arcosh, cosh y y y (e + e y ) y e e + e y ± y M M M ad + must be correct ± y y Sice y, e, so e + A (ii) (iii) OR arcosh y l( +.9. l(. +. (l l ) l ) l( ) d arcosh 9 ( arcosh. arcosh ) l( + 9 ) ) M AA l l sih ( + sih ) l 9 A dy ( + sih )sih (cosh )(cosh ) d ( + sih ) dy d 9 whe 8sih 9 ( + sih ) sih sih + sih, Whe sih, cosh, l( + ) Whe Poit is l( + ), sih, cosh 7, l( + Poit is l( + 7), 7 7) A ag M AA M A M A M M M A ag AA 8 For arcosh (or ay cosh substitutio) For ad (or cosh u ad du ) (or limits of u i logarithmic form) For l( k + k...) Give M for l( k+ k...) For ad l( + 9) Usig quotiet rule Ay correct form 9 (or l( + ) Quadratic i sih (or product of two quadratics i e ) Solvig quadratic to obtai at least oe value of sih (or e ) Obtaiig i logarithmic form (must use a correct formula for arsih) SR BB for verifyig y ad dy whe l( ) d 9 +
18 7 Mark Scheme Ja 7 Alteratives for Q (i) l( + ) l( + ) cosh l( + ) (e + e ) Sice ( + + ) + ( + + ) l( + ) >, arcosh l( + ) M M M A A If y arcosh the l( + ) l(cosh y+ cosh y) l(cosh y+ sih y) sice sih y > y l(e ) y M M A M A 7
19 7 Mark Scheme Ja 7 (i) k B B Geeral shape correct Cusp at O clearly show k. B B Geeral shape correct Dimple correctly show k B (ii) Cusp B (iii) Whe k, there are poits Whe k., there are poits Whe k, there are poits B (iv) (v) (vi) k cos θ + cos θ d k siθ cosθ siθ dθ siθ ( k + cosθ ) whe θ,, or cosθ For just two poits, k d r + ( k + cosθ ) r cosθ k + cos θ ( k + si θ ) Sice cos θ, k d k + + ( k + cosθ ) cosθ Whe k is large, k + k, so d k Curve is very early a circle, with cetre (, ) ad radius k k B B M A M A M A ag M A Give B for two cases correct Allow k > or si θ 8
20 7 Mark Scheme Jue 7 (a)(i) B Must iclude a sharp poit at O ad have ifiite gradiet at θ Give B for r icreasig from zero for < θ <, or decreasig to zero for < θ < (ii) Area is r dθ a ( cosθ ) d θ a a (b) Put siθ ( ) cos θ + ( + cos θ) dθ a si si ) θ θ + θ ( ) Itegral is taθ ( si θ ) cosθ dθ 8cos θ (cosθ ) dθ sec θ dθ M A B BB ft B M A M A ag For itegral of ( cosθ) For a correct itegral epressio icludig limits (may be implied by later work) Usig cos θ ( + cos θ ) Itegratig Accept.78a or cosθ Limits ot required For a + b cosθ ad k cos θ sec θ dθ taθ SR If tahu is used M for sih( l ) A for ( ) (ma / ) 8 (c)(i) f ( ) B Give B for ay o-zero real multiple of this (or for etc) si y (ii) f ( ) ( ( + ) + f ( ) C f () C +...) f ( ) M A M A Biomial epasio ( terms, ) Epasio of ( ) correct (accept usimplified form) Itegratig series for f ( ) Must obtai a o-zero C ot required term 7
21 7 Mark Scheme Jue 7 OR by repeated differetiatio () Fidig f ( ) Evaluatig () f () ( 88) f ( ) +... M M A ft f ( ) +... A Must obtai a o-zero value ft from (c)(i) whe B give 8
22 7 Mark Scheme Jue 7 (a) (cosθ + jsiθ ) c + jc s c s jc s + cs + js Equatig imagiary parts si θ c ( s s c s + s ) s ( s ) s + s M M A M s s siθ si + s s + s θ + si θ + s A ag (b)(i) + j 8, arg( + j) r θ θ, BB B ft B ft M A Accept.8;., (Implies B for 8 ) Oe correct (Implies B for Addig or subtractig ) Accept θ + k, k,, (ii) B Give B for two of B, C, M i the correct quadrats Give B ft for all four poits i the correct quadrats (iii) w arg w ( + ) 7 B ft B Accept.7 Accept.8 (iv) w ( ) 7 8 arg( w ) w 8 j 7 ( cos + jsi ) M A ft A Obtaiig either modulus or argumet Both correct (ft) Allow from arg w etc SR If B, C iterchaged o diagram (ii) B (iii) B B for (iv) MAA 9
23 7 Mark Scheme Jue 7 (i) det( M λ I) ( λ)[( λ)( λ) ] [( λ) + ] + [ ( λ)] ( λ )( + λ + λ ) ( λ) + ( + λ) 8 + 9λ + λ λ λ + λ 8λ + λ λ Characteristic equatio is λ λ 8λ (ii) λ ( λ 8)( λ + ) (iii) (iv) Other eigevalues are 8, Whe λ 8, + y + z 8 ( + y z 8y y z 8z y ad z ; eigevector is Whe λ, + y + z + y z y P M y, z ; eigevector is D 8 M 8M M M + 8M M M (M M + 8M + 8M) + 8M + 9M ) M A M A ag M A M M A M M A B ft M A M M A 8 Obtaiig det( M λ I) Ay correct form Simplificatio Solvig to obtai a o-zero value Two idepedet equatios Obtaiig a o-zero eigevector ( + y+ z 8 etc ca ear MM ) Two idepedet equatios Obtaiig a o-zero eigevector B if P is clearly sigular Order must be cosistet with P whe B has bee eared
24 7 Mark Scheme Jue 7 (a) d arsih 9 + arsih 9 l( + + ) l M A A M A For arsih or for ay sih substitutio For or for sih u For or for du OR M For l( k + k +... ) [ Give M for l( a + b +... ) ] l( ) AA or l( + + ) 9 l 8 l l A (b)(i) sih cosh ( e ( e sih e e ) ) ( e + e ) M A (e e )(e For completio + e ) (e e ) (ii) dy sih sih d For statioary poits, sih sih cosh, y 7 ( ± ) l( sih ( cosh ) sih or cosh + 9 ) l 9 y l, y 9 BB M A A ag A ag B 7 Whe epoetial form used, give B for ay terms correctly differetiated d y Solvig to obtai a value of d sih, cosh or e ( or stated) Correctly obtaied Correctly obtaied The last AA ag ca be replaced by BB ag for a full verificatio (iii) sih sih 8 l l 9 9 BB M A ag Whe epoetial form used, give B for ay terms correctly itegrated Eact evaluatio of sih(l ) ad sih( l )
25 7 Mark Scheme Jue 7 (i) k B B Maimum o LH brach ad miimum o RH brach Crossig aes correctly B B Two braches with positive gradiet Crossig aes correctly k k. B B Maimum o LH brach ad miimum o RH brach Crossig positive y-ais ad miimum i first quadrat (ii) ( + k)( k) + k + k y + k k( k + ) k + + k Straight lie whe k( k + ) k, k M A (ag) BB Workig i either directio For completio (iii)(a) Hyperbola B (B) k y k B B
26 7 Mark Scheme Jue 7 (iv) B B B B B Asymptotes correctly draw Curve approachig asymptotes correctly (both braches) Itercept o y-ais, ad ot crossig the -ais Poits A ad B marked, with miimum poit betwee them Poits A ad B at the same height ( y )
27 7 Mark Scheme Jauary 8 7 (FP) Further Methods for Advaced Mathematics (a) (b)(i) (ii) Area is a a ( cos θ ) d a a f ( ) + ( f ( ) f () θ ( cos θ + ( + cos θ )) [ θ si θ + si θ ] ( + ) + ) ( + ( + ) ) 8 dθ M A B BBB ft A M A M A B For ( cos θ ) dθ Correct itegral epressio icludig limits (may be implied by later work) For cos θ ( + cos θ ) Itegratig a + b cos θ + c cos θ [ Ma B if aswer icorrect ad o mark has previously bee 7 lost ] d Applyig arcta u du + u dy or d sec y Applyig chai (or quotiet) rule Stated; or appearig i series Accept. f (), f () 8 arcta( + ) M AA ft Evaluatig f () or f () For ad ft provided coefficiets are o-zero (iii) h ( h ( + h h + + h ( h +...) d h h ) +... h h h ) M A ft A ag Itegratig (award if is missed) for Allow ft from a + + c provided that a Codoe a proof which eglects h
28 7 Mark Scheme Jauary 8 (a) j jθ th roots of j e are r e where r θ 8 k θ + 8 θ 7,, B B M A Accept Implied by at least two correct (ft) further values or statig k,, (), M A Poits at vertices of a square cetre O or correct poits (ft) or poit i each quadrat (b)(i) jθ jθ jθ jθ ( e )( e ) e e + (ii) jθ (e + e cosθ jθ OR ( cosθ jsiθ )( cosθ + jsiθ ) M ( cosθ ) + si θ A cosθ + (cos θ + si θ ) cosθ A C + js e e e jθ jθ jθ e ( ( e jθ + e jθ jθ ( ( e ) ) e cosθ C siθ S jθ jθ + 8 e jθ jθ e )( e jθ )( e ) + ( + ) jθ jθ e + cosθ + + cos( + ) θ + cosθ si( + ) θ + cosθ + ) + e + e ) jθ jθ si θ cos θ M A A ag M M A M A M A ag A 9 jθ jθ For e e Obtaiig a geometric series Summig (M for sum to ifiity) Give A for two correct terms i umerator Equatig real (or imagiary) parts
29 7 Mark Scheme Jauary 8 (i) Characteristic equatio is (7 λ)( λ) + λ λ + λ, Whe λ, 7 y y 7 + y y y y, eigevector is Whe λ, 7 y y M AA M M A or y ca be awarded for either eigevalue Equatio relatig ad y or ay (o-zero) multiple 7 + y y y y, eigevector is M A 8 SR ( M λi) λ ca ear MAAMMAMA (ii) P D B ft B ft B if P is sigular For B, the order must be cosistet
30 7 Mark Scheme Jauary 8 (iii) P P D M + + P P P P D M a + b + c d M M A ft B ft M A ag A 8 May be implied Depedet o MM For P or Obtaiig at least oe elemet i a product of three matrices Give A for oe of b, c, d correct SR If P D P M is used, ma marks are MMABMAA (d should be correct) SR If their P is sigular, ma marks are MMABM
31 7 Mark Scheme Jauary 8 (i) (e + e ) k e k e + e k ± k k ± k M M or cosh + sih e or k± k e l( k + k ) or l( k k ) ( k + k )( k k ) k ( k ) l( k k ) l( ) l( k + k + k k ) A M Oe value sufficiet or cosh is a eve fuctio (or equivalet) ± l( k + k ) A ag (ii) M For arcosh or d arcosh A A l( λ + λ...) or ay cosh substitutio For arcosh or coshu or l( + ) or l( + ) For or du ( arcosh (iii) sih sih cosh cosh (or sih ) ± l( + 8) arcosh ) ( l( + ) l( + ) ) OR e e + e (e )(e e + ) M B l( ± 8) A M A M M B A Eact umerical logarithmic form Obtaiig a value for or l( ± 8) cosh or ( e e )(e + e ) (iv) dy cosh cosh d If d y the cosh ( cosh ) d cosh cosh + Discrimiat D Sice D < there are o solutios B M M A Usig cosh cosh Cosiderig D, or completig square, or cosiderig turig poit
32 7 Mark Scheme Jauary 8 OR Gradiet g cosh cosh B g sih sih sih ( cosh ) whe (oly) M g cosh 8 cosh whe M Ma value g whe So g is ever equal to A Fial A requires a complete proof showig this is the oly turig poit
33 7 Mark Scheme Jauary 8 (i) λ λ λ BBB cusp loop BB (ii) B (iii) Itersects itself whe y (iv) ± t ( ± ) λ λ, + λ λ 7 d y t λ dt λ t ± λ λ + λ + λ λ λ y ± ( ) ( ) λ ± λ ± λ (v) From asymptote, a 8 aλ From itersectio poit, + λ λ From maimum poit, b λ 7 b 7 M A A M A ag M A ag B M A M A Two differet features (cusp, loop, asymptote) correctly idetified Oe value sufficiet
34 7 Mark Scheme Jue 8 7 (FP) Further Methods for Advaced Mathematics (a)(i) r cosθ, y r siθ M (M for cos θ, y siθ ) ( r cos θ + r si θ ) r ( r cosθ )( r siθ ) r cosθ si θ A r cosθ si θ A ag (ii) B Loop i st quadrat B Loop i th quadrat (b) OR Put d arcsi arcsi M siθ A d dθ A MA (c)(i) l( + ) (ii) l( ) + l l( + ) l( ) B M AA M A B B M A Fully correct curve Curve may be draw usig cotiuous or broke lies i ay combiatio For arcsi For ad Eact umerical value Depedet o first M (MA for / ) Ay sie substitutio For dθ M depedet o first M Accept usimplified forms Obtaied from two correct series Terms eed ot be added If M, the B for + +
35 7 Mark Scheme Jue 8 (iii) r (r + ) r l (i) z 8, arg z (ii) z * 8, arg z* z w 8 8 arg( z w) + z w arg( 8 8 z w ) 7 7 ( z cos( ) + jsi( ) w j a b, (iii) r 8 θ k θ + 7, (iv) θ 7 j 7 j ) l w * 8 e, so e k z * 8 e j 8 e j k So e z * j w 8 e ( 7 + ) j j j 8 e j w* j ( 8 e, so e j w k ) +... B B B ag BB B ft B ft B ft B ft B ft M A B ft B M A B ft M A ft M A ft 7 Terms eed ot be added For see or implied Satisfactory completio Must be give separately Remaider may be give i epoetial or r cjsθ form (B for 7 ) (B if left as 8/8) If M, the BB for ad Accept 8 Implied by oe further correct (ft) value Igore values outside the required rage Matchig w* to a cube root with 7 argumet ad k or ft r ft is 8 Matchig z* to a cube root with argumet May be implied r ft is z * Matchig jw to a cube root with argumet May be implied OR M for arg( j w) + arg w (implied by or ) r ft is 8
36 7 Mark Scheme Jue 8 (i) k + Q k k k Whe k, Q 8 (ii) P, D M PDP (iii) Characteristic equatio is ( λ )( λ+ )( λ ) λ λ λ+ M M + MI M M + M M (M + M I) + M M M 9I a, b, c 9 M A M A M A BB B M A B M A M A Evaluatio of determiat (must ivolve k) For ( k ) Fidig at least four cofactors (icludig oe ivolvig k) Si siged cofactors correct (icludig oe ivolvig k) Trasposig ad dividig by det Depedet o previous MM Q correct (i terms of k) ad result for k stated After, SC for Q whe k obtaied correctly with some workig For B, order must be cosistet Give B for M P DP or 8 Good attempt at multiplyig two matrices (o more tha errors), leavig third matri i correct positio 7 Give A for five elemets correct Correct M implies BMA -8 elemets correct implies BMA I ay correct form (Codoe omissio of ) M satisfies the characteristic equatio Correct epaded form (Codoe omissio of I ) 7
37 7 Mark Scheme Jue 8 (i) cosh [ (e + e ) ] (e + + e ) + + sih [ (e e )] (e e ) cosh sih ( ) OR cosh + sih (e + e ) + (e e ) e B cosh sih (e + e ) (e e ) e B B B B ag For completio cosh sih e e B Completio (iii) (ii) ( + sih ) + 9sih sih + 9sih 9 sih, l, l( + ) OR e + 9e e 9e + (e e )(e + e ) M M e, + AA l, l( + ) AA ft dy 8cosh sih+ 9cosh d cosh (8sih + 9) oly whe sih cosh ( ) 9 7 y + 9 ( ) M M AA AA ft B B M A (M for sih ) Obtaiig a value for sih Eact logarithmic form Dep o MM Ma A if ay etra values give Quadratic ad / or liear factors Obtaiig a value for e Igore etra values Depedet o MM Ma A if ay etra values give Just l ears MMAAAA Ay correct form 9 7 or y (sih + ) +... ( ) Correctly showig there is oly oe solutio Eact evaluatio of y or cosh or cosh Give B (replacig MA) for. or better (iv) l ( + cosh + 9sih )d [ sih 9cosh ] l l l+ 8 M A M A ag Epressig i itegrable form Give A for two terms correct sih(l ) ( ) Must see both terms for M Must also see cosh(l ) ( + ) for A 8
38 7 Mark Scheme Jue 8 OR l 9 (e + + e + (e e ))d l 9 9 e e e e M A l M l+ A ag 8 (i) λ. λ λ Epaded epoetial form (M if the is omitted) Give A for three terms correct e l l ad e both see Must also see e ad e for A l l BBB (ii) Ellipse B (iii) y cos( θ ) Maimum y whe θ M A ag or si( θ + ) dy OR siθ + cosθ whe θ M dθ y + A (iv) + cos cos si + si y λ θ θ θ θ λ + cos θ + cosθsiθ + si θ ( λ + )( si θ) + ( + )si θ λ + λ + ( λ )si θ λ θ + y + λ θ + y + λ Whe si, Whe si, Sice si θ, distace from O, + y, is betwee + ad + λ λ M M A ag M M A ag Usig cos θ si θ (v) Whe λ, + y Curve is a circle (cetre O) with radius M A 9
39 7 Mark Scheme Jue 8 (vi) B A, E at maimum distace from O C, G at miimum distace from O B, F are statioary poits D, H are o the -ais Give ½ mark for each poit, the roud dow Special properties must be clear from diagram, or stated Ma if curve is ot the correct shape
40 7 Mark Scheme Jauary 9 7 (FP) Further Methods for Advaced Mathematics (a)(i) f () cos f () M Derivatives cos, si, cos, si, cos f () si f () f () cos f () A Correct sigs f () si f () f () cos f () A Correct values. Dep o previous A A (ag) www cos +... (ii) cos sec E o.e. + ( + a + b ) M Multiply to obtai terms i ad Terms correct i ay form + a + b a+ A (may ot be collected) a, b a+ Correctly obtaied by ay method: a B must ot just be stated b B Correctly obtaied by ay method (b)(i) (ii)(a) (ii)(b) y arcta a a ta y M d dy a sec y A Or sec y (a) ta y ad attempt to differetiate both sides dy d a d dy a( + ta y) A Use sec y + ta y o.e. dy a A (ag) www d a + d arcta + M A A SC: Use derivative of arcta ad Chai Rule (properly show) arcta aloe, or ay ta substitutio ad, or dθ without limits Evaluated i terms of d d + M arcta aloe, or ay ta substitutio + A ad, or dθ without limits ( ) arcta A Evaluated i terms of 9
41 7 Mark Scheme Jauary 9 (i) Modulus B Must be separate B Accept,. Argumet c (ii) B G: A i first quadrat, argumet - j A B G,, a e B arg b ± M j b e, e 7 j j j (iii) ( ) Aft B i secod quadrat, same mod B i fourth quadrat, same mod Symmetry G: poits ad at least of above, or B, B o aes, or BOB straight lie, or BOB refle Must be i required form (accept r, θ /) Rotate by addig (or subtractig) / to (or from) argumet. Must be / Both. Ft value of r for a. Must be i required form, but do t pealise twice z e e M ( ) 8 or see 8 A (ag) www Others are ad θ j re θ where r M Add to argumet more tha oce,,, Correct costat r ad five values of θ., A Accept θ i [, ] or i degrees (iv) - G G poits o vertices of regular heago Correctly positioed ( roots o real ais). Igore scales SC if G ad poits correctly plotted j j j j (iv) w ze e e e M arg w cos + j si + j A Or B G Same modulus as z (v) w j j j j e 8e M Or z e 8 e 8j A cao. Evaluated 8
42 7 Mark Scheme Jauary 9 (a)(i) Regio for (ii) (ii) Area rdθ a ta θ dθ G G G r icreasig with θ Correct for θ / (igore etra) Gradiet less tha at O M Itegral epressio ivolvig ta θ Attempt to epress ta θ i terms of sec a θ d θ M sec θ ta a θ θ A ta θ θ ad limits, a A A if e.g. triagle this aswer G Mark regio o graph [ ] (b)(i) Characteristic equatio is (. λ)(.7 λ). M λ.9λ. λ,. A.8.8 Whe λ,.. y (M λi) M below.8 +.8y,..y M At least oe equatio relatig ad y y, eigevector is o.e. A..8 Whe λ.,..8 y. +.8y M At least oe equatio relatig ad y 8 eigevector is o.e. A 8 (ii) Q B if Q is sigular. Must label Bft correctly D Bft. If order cosistet. Dep o BB B eared 7
43 7 Mark Scheme Jauary 9 (a)(i) cosh ( ) e e + ( e + + e ) sih ( ) e e ( e + e Both epressios (M if o middle ) M term) ad subtractio cosh sih ( + ) A (ag) www OR cosh + sih e cosh sih e Both, ad multiplicatio cosh sih e e A Completio (ii)(a) cosh + sih + ta y Use of cosh + sih ad sih M ta y sec y A tah sih ta y si y cosh sec y (ii)(b) arsih l( + arsih(ta y) l(ta y + l(ta y + sec y) A (ag) www + ) M Attempt to use l form of arsih + ta y ) A A (ag) www e e OR sih ta y ta y e e ta y M Arrage as quadratic ad solve for e e ta y ± ta y + A o.e. l(ta y + sec y) A www (b)(i) y artah tah y M tah y ad attempt to differetiate d dy sech y dy d sech y tah y Or sech y dy d A Or B for www (ii) (iii) Itegral [ ] artah artah A B ( )( ) A( + ) + B( ) A ½, B ½ d + d + M A (ag) M A artah or ay tah substitutio www M Log itegrals + l + l + + cor l + c o.e. A d l + l + l M Correct form of partial fractios ad attempt to evaluate costats www. Codoe omitted modulus sigs ad costat After scored, SC for correct aswer Substitutio of ½ ad ½ see aywhere (or correct use of, ½) artah l artah l A (ag) www 8 7
44 7 Mark Scheme Jauary 9 (i) y - - G G G Symmetry i horizotal ais (, ) to (, ) (, ) to (, ) (ii)(a) a >. B a <. B (ii)(b) Circle: r is costat B Shape ad reaso (ii)(c) The two loops get closer together B The shape becomes more early circular B (ii)(d) Cusp B a. B 7 (iii) + a cos θ cos θ a B Equatio If a >., < < ad there are two values a of θ i [, ], arccos a ad + arccos a These differ by arccos a arccos a arcta a Tagets are y ad y a M A (ag) M A A Relatig arccos to arcta by triagle or ta θ sec θ a Aft Negative of above a is real for a >. if a > E 8 8 8
45 7 Mark Scheme Jue 9 7 (FP) Further Methods for Advaced Mathematics (a)(i) l( + ) Series for l( ) as far as l( )... B s.o.i. + l l( + ) l( ) M Seeig series subtracted A Valid for < < B Iequalities must be strict (ii) + + ( ) + M Correct method of solutio (b)(i) l A M B for ½ stated Substitutig their ito their series i (a) (i), eve if outside rage of validity. Series must have at least two terms SR: if > correct terms see i (i), allow a better aswer to d.p..9 ( d.p.) A Must be decimal places y... G G G r() a, r(/) a/ idicated Symmetry i θ / Correct basic shape: flat at θ /, ot vertical or horizotal at eds, o dimple Igore beyod θ (ii) r + y r + r si θ M Usig y r si θ a r( + si θ) ( + si θ) + si θ a A (ag) r a y + y (a y) M A + y a ay + y ay a y a a A Usig r + y i r + y a Usimplified A correct fial aswer, ot spoiled
46 7 Mark Scheme Jue 9 (i) λ M λi λ λ det(m λi) ( λ)[( λ)( λ)] + [( λ)] M ( λ)(λ ) + ( λ) A λ λ + λ + 7 det M 7 Attempt at det(m λi) with all elemets preset. Allow sig errors Usimplified. Allow sigs reversed. Codoe omissio of B (ii) f (λ) λ λ + λ + 7 f ( ) + 7 eigevalue B Showig satisfies a correct characteristic equatio f (λ) (λ + )(λ λ + 7) M Obtaiig quadratic factor λ λ + 7 (λ ) + so o real roots A www (M λi)s, λ (M λi)s (λ)s M below y z + y z Obtaiig equatios relatig, y M + z ad z z y z z + z z M Obtaiig equatios relatig two variables to a third. Dep. o first M s A Or ay o-zero multiple. M Solutio by ay method, e.g. use y. of multiple of s, but M if s itself z. quoted without further work., y., z. A Give A if ay two correct 9 C-H: a matri satisfies its ow characteristic (iii) equatio B Idea of λ M M M + M + 7I M M M 7I B (ag) Must be derived www. Codoe omitted I M M I 7M M Multiplyig by M M M + M I A o.e. 8 (iv) M 8 M Correct attempt to fid M M Usig their (iii) or A SC for aswer without workig
47 7 Mark Scheme Jue 9 OR Matri of cofactors: 7 M Adjugate matri 7 : det M 7 M Fidig at least four cofactors Trasposig ad dividig by determiat. Dep. o M above 9
48 7 Mark Scheme Jue 9 (a)(i) (ii) G Correct basic shape (positive gradiet, through (, )) y arcsi si y si y ad attempt to diff. both M sides d dy cos y A Or cos y dy d dy d cos y Positive square root because gradiet positive d arcsi (b) C + js jθ jθ jθ e + e + e This is a geometric series with first term a j e θ, commo ratio r jθ a e Sum to ifiity r e e e e e jθ jθ jθ jθ 9e e 9e e + jθ jθ jθ jθ 9cos ( θ + jsiθ) cos ( θ jsiθ) ( cos θ jsi θ) ( cos θ + jsi θ) cosθ + j siθ cos θ cosθ C cos θ jθ A B M A A www. SC if quoted without workig Dep. o graph of a icreasig fuctio arcsi fuctio aloe, or ay sie substitutio, or dθ www without limits Evaluated i terms of M Formig C + js as a series of powers Idetifyig geometric series ad M attemptig sum to ifiity or to terms j e θ A Correct a ad r jθ e ( ) jθ e A Sum to ifiity Multiplyig umerator ad jθ deomiator by e o.e. M* Or writig i terms of trig fuctios ad realisig the deomiator M M A M Multiplyig out umerator ad deomiator. Dep. o M* Valid attempt to epress i terms of trig fuctios. If trig fuctios used from start, M for usig the compoud agle formulae ad Pythagoras Dep. o M* Equatig real ad imagiary parts. Dep. o M* 7
49 7 Mark Scheme Jue 9 cosθ cosθ siθ S cosθ A (ag) A o.e. 9 8
50 7 Mark Scheme Jue 9 u u e + e (i) cosh u cosh u u e + + e u u u B ( ) u u e e + e + + e cosh u u e e u u u + e + e B cosh u cosh u B (ag) Completio www (ii) arsih y sih y e e y Epressig y i epoetial form M (, must be correct) e ye (e y) y (e y) y + e y ± y + e y ± y + Reachig e by quadratic formula M or completig the square. Codoe o ± Take + because e > Or argumet of l must be B positive l(y + y + ) Completio www but A (ag) idepedet of B (iii) sih u d d du cosh u M ad substitutig for all du elemets + sih + cosh A Substitutig for all elemets correctly cosh udu coshu+ du M Simplifyig to a itegrable form sih u + u + c A u u Ay form, e.g. e e + u Codoe omissio of + c throughout sih u cosh u + u + c Usig double agle formula ad + + arsih + c M attempt to epress cosh u i terms of + c A (ag) Completio www (iv) t + t + (t + ) + B Completig the square t + t+ dt ( t+ ) + dt + d + + arsih M A Simplifyig to a itegrable form, by substitutig t + s.o.i. or complete alterative method Correct limits cosistet with their method see aywhere 9
51 7 Mark Scheme Jue arsih M + l( + ) (l( + ) + ) A (ag) Usig (iii) or otherwise reachig the result of itegratio, ad usig limits Completio www. Codoe 8 etc. 8
52 7 Mark Scheme Jue 9 (i) If a, agle OCP so P is ( cos, si ) M P (, ) A (ag) Completio www OR Circle ( ) + y, lie y + ( ) + ( + ) M Complete algebraic method to fid ± ad hece P A Q ( +, ) B (ii) cos OCP a Attempt to fid cos OCP ad si M a + OCP i terms of a si OCP a + A Both correct P is (a a cos OCP, a si OCP) P (a a, a ) a + a + A (ag) Completio www OR Circle ( a) + y a, lie y + a ( a) + + a Complete algebraic method to a M fid (iii) a ± Q (a + a a+ ± + + a a a + a a a + a a +, ad hece P. a +. A A a ) B G G G Gft Usimplified Locus of P ( st & rd quadrats) through (, ) Locus of P termiates at (, ) Locus of P: fully correct shape Locus of Q ( d & th quadrats: dotted) reflectio of locus of P i y-ais As a, P (, ) B Stated separately As a, y co-ordiate of P B Stated a a a + a as a M Attempt to cosider y as a A Completio www 8 (iv) POQ 9 B Agle i semicircle B o.e. Loci cross at 9 B 8
53 7 Mark Scheme Jauary 7 (FP) Further Methods for Advaced Mathematics (a) y arcta u, y arcta u du d dy du u dy d + u + + ( ) OR ta y sec y dy d sec y + ta y + dy + d ( ) MA A M A A Usig Chai Rule Correct derivative i ay form Correct derivative i terms of Rearragig for or ad differetiatig implicitly M Itegral i form k arcta arcta ( ) d + A k arcta arcta A (ag) (b)(i) r cos θ, y r si θ, + y r M Usig at least oe of these + y y + r r cos θ si θ + A LHS A RHS r ½r si θ + r r si θ + r ( si θ) r siθ A (ag) Clearly obtaied SR: r si θ, y r cos θ used MAAA ma. (ii) Ma r is B Occurs whe si θ M Attemptig to solve Both. Accept degrees. θ, A A if etras i rage Mi r B Occurs whe si θ M Attemptig to solve (must be ) θ 7 Both. Accept degrees., A A if etras i rage
54 7 Mark Scheme Jauary (iii) y... G Closed curve, roughly elliptical, with. o poits or dets G Major ais alog y 8 (a) cos θ + j si θ (cos θ + j si θ) M Usig de Moivre cos θ + cos θ j si θ + cos θ j si θ + cos θ j si θ + cos θ j si θ + j si θ M Usig biomial theorem appropriately cos θ cos θ si θ + cos θ si Correct real part. Must evaluate θ + j( ) A powers of j cos θ cos θ cos θ si θ + cos θ si θ M Equatig real parts cos θ cos θ(cos θ) + cos θ(cos θ) M Replacig si θ by cos θ cos θ cos θ + cos θ A a, b, c (b) C + js M Formig series C + js as epoetials (c) ( ) jθ+ j θ+ jθ e + e e A Need ot see whole series This is a G.P. M Attemptig to sum fiite or ifiite G.P. jθ a e, r e j Correct a, r used or stated, ad terms A Must see j Sum e jθ e e e j j jθ j Numerator ( e ) ad j e so sum E Covicig eplaatio that sum C ad S E C S. Dep. o previous E Both E marks dep. o marks above 7 t e + t+ t B Igore terms i higher powers t t M Substitutig Maclauri series t e t+ t A t ( ) + t t+... Suitable maipulatio ad use of M t+ t + t biomial theorem OR t + + t t t t t Hece t t e t OR ( e )( t) ( t t...)( t) t M A A (ag) + + M Substitutig Maclauri series A Correct epressio t + terms i t M Multiplyig out t t t e A Covicig eplaatio 8
55 7 Mark Scheme Jauary M Evaluatig determiat (i) a + a A a M a a M Fidig at least four cofactors a A Si siged cofactors correct M Trasposig ad dividig by det Whe a, (ii) y b z M A M M correct (i terms of a) ad result for a stated SR: After scored, SC for M whe a, obtaied correctly with some workig Attemptig to multiply ( b ) T by give matri (M if wrog order) M Multiplyig out 8, y b, z b A A for oe correct OR + y b y b o.e. M Elimiatig oe ukow i ways Or e.g. + z b, Or e.g. y z b, y z 7 M Solve to obtai oe value. Dep. o M above Oe ukow correct A After M, SC for value of M Fidig the other two ukows 8 y b, z b A Both correct (iii) e.g. y b + M Elimiatig oe ukow i ways y AA Two correct equatios Or e.g. + z b, + z Or e.g. y + z b, y + z 7 Cosistet if b + M Attemptig to fid b b Solutio is a lie A B 7 8
56 7 Mark Scheme Jauary (i) e e sih e + e sih + ( sih e e ) e + e + B e + e e + e cosh B Correct completio sih sih cosh B Both correct derivatives sih sih cosh B Correct completio (ii) cosh + sih ( + sih ) + sih M Usig idetity sih + sih A Correct quadratic ( sih )(sih + ) M Solvig quadratic sih ¼, A Both arsih(¼) l( + 7 ) A Must evaluate arsih() l( + ) A OR e e e e + + ( e e )( e e ) M Use of arsih l( + + ) o.e. Must obtai at least oe value of + MA Factorisig quartic e + ± 7 or ± MA Solvig either quadratic l( + 7 ) or l( + ) MAA Usig l (depedet o first M) 7 (iii) cosh t t t e + e t t e e + M Formig quadratic i e t t t ( e )( e ) M Solvig quadratic t e, t ±l A d arcosh B A (ag) Covicig workig arcosh arcosh M Substitutig limits l A A for ±l OR d l ( + ) B l 8 l M Substitutig limits l A 7 8 7
57 7 Mark Scheme Jauary (i) Horz. projectio of QP k cos θ B Vert. projectio of QP k si θ B Subtract OQ ta θ B Clearly obtaied (ii) k k y y.... k ½ k G G Loop Cusp y y G G (iii)(a) for all k, y ais is a asymptote B Both (B) k B (C) k > B (iv) Crosses itself at (, ) k cos θ ½ θ M Obtaiig a value of θ curve crosses itself at A Accept (v) y 8 si θ ta θ dy dθ 8 cos θ sec θ 8 cos θ at highest poit cos θ cos θ 8 cos θ ± M Complete method givig θ θ at top A y A Both (vi) RHS ( ) k cosθ ( k k cos θ) k cos θ M Epressig oe side i terms of θ ( k cosθ ) k si θ k cos θ ( ) k cosθ ta θ M Usig trig idetities (( k cosθ taθ ) ) ( si θ ta θ) k LHS E 8 8
58 GCE Mathematics (MEI) Advaced GCE 7 Further Methods for Advaced Mathematics (FP) Mark Scheme for Jue Oford Cambridge ad RSA Eamiatios
59 7 Mark Scheme Jue (a)(i) f (t) arcsi t f (t) t f (t) ( ) t t ( ) t ( ) t B Ay form t M Usig Chai Rule (ii) f () arcsi ( + ½) f () arcsi (½) (b) f () ( ) ad f () ( ( ) ) f () f () + f () + 9 A (ag) B (ag) M A (ag) obtaied clearly from f () www Clear substitutio of or t ½ f () + M Evaluatig f () ad dividig by term i is 9 A Accept.8 or better (c) Area rdθ a a dθ ( + θ) a + θ a + a d 9+ G G Complete spiral with r() < r() r() a, r() a/ idicated or r() > r(/) > r() > r(/) > r() Dep. o G above Ma. G if ot fully correct dθ M Itegral epressio ivolvig r ( + θ) A M A d 9 + arcta M AA Correct result of itegratio with correct limits Substitutig limits ito a epressio of the form k. Dep. o M above + θ arcta ad arcta M Substitutig limits. Dep. o M above A Evaluated i terms of 9
60 7 Mark Scheme Jue (a) z + cosθ, z z z jsiθ B Both z z z z + z + M Epadig z z z z z z z z + z z z M Itroducig sies (ad possibly cosies) j si θ j si θ j si θ + j si θ of multiple agles A RHS si θ si θ si θ + si θ 8 Aft Divisio by (j) A 8, B, C (b)(i) th roots of 9j 9 j e j are re θ where r B Accept 9 θ B 8 θ k + M 8 θ 7,, A Implied by at least two correct (ft) further values Or statig k (),,, Allow argumets i rage θ w (ii) Mid-poit of SP has argumet 8 ad modulus of Argumet of w 8 M A B B Poits at vertices of a square cetre O or correct poits (ft) or poit i each quadrat ad modulus 9 M A G Multiplyig argumet by ad modulus raised to power of Both correct w plotted o imag. ais above level of P
61 7 Mark Scheme Jue (a)(i) λ + λ λ + (λ )(λ + λ ) B Substitutig λ or factorisig λ or λ + λ M Obtaiig ad solvig a quadratic (λ )(λ + ) λ ½, λ AA (ii) M B M v v Give B for oe compoet with the B wrog sig M Recogisig that the solutio is a M multiple of the give RHS, y, z A Correct multiple (iii) λ + λ λ + M + M M + I M Usig Cayley-Hamilto Theorem M M + M I M M + M M M Multiplyig by M M ( M + M I) + M M M Substitutig for M M 7 M M + I A, C A 7, B (b) N PDP B Order must be correct where D B ad P B For BB, order must be cosistet P Bft Ft their P N M Attemptig matri product A a c OR Let N b d a c a+ c B Or b d b d + a c a c B Or b d b d a + c, a + c B b + d, b + d B a, c ; b, d MA Solvig both pairs of equatios 9
62 7 Mark Scheme Jue (i) sih cosh e + e e (ii) e e e M Usig epoetial defiitios ad multiplyig or factorisig sih A (ag) Differetiatig, cosh cosh + sih B Oe side correct cosh cosh + sih B Correct completio y (iii) Volume ( cosh ) d M ( cosh ) G cosh cosh + d A cosh cosh + d M Correct shape ad through origi d A correct epaded itegral epressio icludig limits, (may be implied by later work) Attemptig to obtai a itegrable form Dep. o M above sih sih + A Give A for two terms correct sih sih 8.7 A d.p. required. Codoe y cosh + sih dy sih + cosh d B Ay correct form At S.P. sih + cosh sih cosh + cosh M Settig derivative equal to zero ad usig idetity cosh ( sih + ) M Solvig dy to obtai value of sih d cosh (rejected) A Repudiatig cosh sih A 7 M Usig log form of arsih, or settig up l + ad solvig quadratic i e A A if etra roots quoted 7 8
63 7 Mark Scheme Jue (i)(a) Circle (B) B G Sketch of circle, cetre (, ) G Sketch of squarer circle o same aes (C) Square B (D) B Give BB for ot all o-strict or y B uclear (ii)(a) Odd roots eist for all real umbers B Ay equivalet eplaatio (B) Lie B Sketch isufficiet y (C) (D) Asymptote: + y y G B (iii) G G Lie + y outside uit square Lies y ad o uit square (iv)(a) G G if curve beyod (, ) or (, ), y B Accept strict, or idicatio o graph (B) Limit is a plus sig where for y ad vice versa Gft B B Give G for a partial attempt. Ft from (iii) o shape 8
64 GCE Mathematics (MEI) Advaced GCE Uit 7: Further Methods for Advaced Mathematics Mark Scheme for Jauary Oford Cambridge ad RSA Eamiatios
65 7 Mark Scheme Jauary (a)(i) r cos θ, y r si θ, + y r M Usig at least oe of these r (cos θ + si θ) r r(cos θ + si θ) + y + y A (ag) Workig must be covicig + y y ( ) + (y ) which is a circle cetre (, ) radius M Recogise as circle or appropriate algebra leadig to ( a) + (y b) r (ii) Area (b)(i) G G M Attempt at complete circle with cetre i first quadrat A circle with cetre ad radius idicated, or cetre (, ) idicated ad passig through (, ), or (, ) ad (, ) idicated ad passig through (, ) cos si d Itegral epressio ivolvig r i terms of θ cos si cos si d M Multiplyig out si cosd A cos θ + si θ used cos si etc. A Correct result of itegratio with correct limits. Give A for oe error M Substitutig limits. Dep. o both Ms A Mark fial aswer 7 f( ) M Usig Chai Rule A Correct derivative i ay form f( )... M Correctly usig biomial epasio (ii)... 8 A Correct epasio f... c M Itegratig at least two terms A But c because arcta() A Idepedet 9
66 7 Mark Scheme Jauary (a)(i) z + z cos θ B z z j si θ B (ii) (z + z ) z + z + z + + z + z + z M Epadig (z + z ) z + z + (z + z ) + (z + z ) + cos θ cos θ + cos θ + cos θ + cos θ cos cos cos cos θ M Usig z + z cos θ with, or. Allow M if omitted, etc. cos cos cos A (ag) (iii) (z z ) z + z (z + z ) + (z + z ) B si θ cos θ cos θ + cos θ M Usig (i) as i part (ii) A Correct epressio i ay form si θ cos cos cos cos θ si θ cos cos M Attemptig to add or subtract A OR cos θ (cos θ + ) B This used cos θ cos θ + 8 cos θ + M Obtaiig a epressio for cos θ cos θ cos θ + cos θ A Correct epressio i ay form cos θ si θ cos θ cos θ + cos θ cos cos MA Attemptig to add or subtract j (b)(i) z 8e z e j Correctly maipulatig modulus ad M argumet j7 e A 8, 7 or. Codoe r(c + js) j z 9 8e z e j Correctly maipulatig modulus ad M argumet j 9 e A, or. Codoe r(c + js) 9 9 w z z (ii) z z e e j j7 e 7 9 j 8 j 9 e Lies i secod quadrat G G M A A Moduli approimately correct Argumets approimately correct Give GG for two poits approimately correct Correctly maipulatig modulus ad argumet Accept ay equivalet form 9
67 7 Mark Scheme Jauary (i) det(m λi) ( λ)[( λ)( λ) + 8] M Obtaiig det(m λi) + [( λ) ] + [8 + ( λ)] A Ay correct form ( λ)(λ λ + ) + (λ) + ( λ) λ + λ λ + 8λ + λ M Simplificatio λ λ + 8λ A (ag) www, but codoe omissio of (ii) λ λ + 8λ M Factorisig ad obtaiig a quadratic. If M, give B for substitutig λ (λ )(λ λ + ) A Correct quadratic λ λ + b ac 8 M Cosiderig discrimiat o.e. so o other real eigevalues A Coclusio from correct evidece www (iii) λ y z y + z z + y z M Two idepedet equatios z k, y k M Obtaiig a o-zero eigevector eigevector is A eigevector with uit legth is v B Magitude of M v is B Must be a magitude (iv) λ λ + 8λ M M + 8M I M Use of Cayley-Hamilto Theorem M M + 8I M M M Multiplyig by M (M M + 8I) ad rearragig A Must cotai I
68 7 Mark Scheme Jauary (i) sih t + 7 cosh t 8 (et e t ) + 7 (et + e t ) 8 M Substitutig correct epoetial forms e t + e t 8 e t 8e t + M Obtaiig quadratic i e t (e t )(e t ) M Solvig to obtai at least oe value of e t e t or AA Codoe etra values t l( ) or l( ) A These two values o.e. oly. Eact form (ii) dy d sih + cosh or 8e + e B sih + cosh sih + 7 cosh 8 l( ) or l( ) l( ) or l( ) M Complete method to obtai a value A Both co-ordiates i ay eact form l( ) y ( l( ), ) l( ) y ( l( ), ) B Both y co-ordiates dy sih + cosh d tah 7 or e etc. M Ay complete method No solutios because < tah < or e > etc. A (ag) www (,) G G Curve (ot st. lie) with correct geeral shape (positive gradiet throughout) Curve through (, ). Depedet o last G 8 a cosh 7sih d M Attemptig itegratio (iii) 7 a sih cosh 7 sih a cosh a 7 sih a + 7 cosh a 8 A Correct result of itegratio a l( ) or l( ) a l( ) or l( ) M Usig both limits ad a complete method to obtai a value of a a l( ) ( l( ) < ) A Must reject l( ), but reaso eed ot be give 8
69 7 Mark Scheme Jauary (i) a y.. a y G a. G y.. G M Evidece s.o.i. of further ivestigatio (A) Loops whe a > A (B) Cusps whe a A 7 (ii) If, t t M Cosiderig effect o t but y(t) y(t) A (ag) Effect o y Curve is symmetrical i the y-ais B (iii) dy d asi t M Usig Chai Rule acost A dy a si t t ad ± d A Values of t t T.P. is (, a) A t ± T.P. are (±, + a) A Both, i ay form (iv) a : both t ad give the poit (, ) B (ag) Verificatio Gradiets are a ad a (or ad ) Hece agle is arcta( ). radias M A Complete method for agle Accept (or ) 8
70 GCE Mathematics (MEI) Advaced GCE Uit 7: Further Methods for Advaced Mathematics Mark Scheme for Jue Oford Cambridge ad RSA Eamiatios
71 7 Mark Scheme Jue 7 (FP) Further Methods for Advaced Mathematics (a)(i) a d (ii) Area si G G Correct geeral shape icludig symmetry i vertical ais Correct form at O ad o etra sectios. Depedet o first G For a otherwise correct curve with a sharp poit at the bottom, award GG M Itegral epressio ivolvig ( si θ) a si si d M A Epadig Correct itegral epressio, icl. limits (which may be implied by later work) a si cos d si cos Correct result of itegratio. a cos si A Give A for oe error a A Depedet o previous A 7 (b)(i) M arcta aloe, or ay ta substitutio d d arcta A ad A Evaluated i terms of (ii) ta θ M Ay ta substitutio d sec θ dθ sec d sec cos d AA sec, sec Itegratig a cos bθ ad usig cosistet M limits. Depedet o M above si a Aft si b b A 8
72 7 Mark Scheme Jue (a) cos θ + j si θ (cos θ + j si θ) c + c js c s c js + cs + js M Epadig M Separatig real ad imagiary parts. Depedet o first M cos θ c c s + cs A Alterative: c c + c si θ c s c s + s A Alterative: s s + s cscs s ta θ c c s cs tt t M Usig ta θ si ad simplifyig t t cos t t t t t A (ag) (b)(i) arg( ) fifth roots have r B ad θ B No credit for argumets i degrees z j e, j e, e j, 7 j e, M Addig (or subtractig) 9 j e A All correct. Allow θ < (ii) (iii) arg(w) G G B w cos M Aft (iv) w cos e j w cos e j which is real if si B Poits at vertices of regular petago, with oe o egative real ais Poits correctly labelled Attemptig to fid legth F.t. (positive) r from (i) w cos a cos M A Attemptig the th power of his modulus i (iii), or attemptig the modulus of the th power here Accept.9 or better 8
73 7 Mark Scheme Jue (i) det(m) ( ) + ( 8) + k( ) M Obtaiig det(m) i terms of k k A o iverse if k A Accept k after correct determiat Evaluatig at least four cofactors M (icludig oe ivolvig k) k k Si siged cofactors correct A M k k (icludig oe ivolvig k) k 9 Trasposig ad dividig by det(m). M Depedet o previous MM A 7 M Settig k ad multiplyig (ii) A (iii) is a eigevector correspodig to a eigevalue of B B For credit here, / scored i (ii) Accept ivariat poit (iv) + y t, + y, + y t M Elimiatig oe variable i two differet ways (or 9 + 8z t +, + z t, + z ) (or 9y 9z t, y z t, y z ) A Two correct equatios For solutios, t M Validly obtaiig a value of t t A M λ, y λ, z λ A Straight lie B Obtaiig geeral solutio by settig oe ukow λ ad fidig other two i terms of λ (accept ukow istead of λ) Accept sheaf. Idepedet of all previous marks 7 8
74 7 Mark Scheme Jue y y (i) cosh y e e (ii) e y e y y e e y e y l( ) y B Usig correct epoetial defiitio M Obtaiig quadratic i e M M y ±l( ) A (ag) arcosh() l( ) because this is the pricipal value d M arcosh AA arcosh arcosh l d Solvig quadratic A B M 7 Validly attemptig to justify ± i prited aswer Referece to arcosh as a fuctio, or correctly to domais/rages arcosh aloe, or ay cosh substitutio, Substitutig limits ad usig (i) correctly at ay stage (or usig limits of u i logarithmic form). Dep. o first M y l OR l l 8 l M AA A l k k... Give M for l k k..., l o.e. l A (iii) cosh cosh cosh ( cosh ) M Attemptig to epress cosh i terms of cosh cosh cosh + ( cosh )(cosh ) M Solvig quadratic to obtai at least oe real value of cosh cosh (rejected) A Or factor cosh or cosh A l Aft F.t. cosh k, k > l F.t. other value. Ma. AA if additioal Aft real values quoted 8
75 7 Mark Scheme Jue (i) (A) m,. y.. (B) m,. G Negative parabola from (,) to (,), symmetrical about.. y (C) m,. G Bell-shape from (,) to (,), symmetrical about.; flat eds, ad obviously differet to (A). y.. (D) m,. G Skewed curve from (,) to (,), maimum to left of.. y.. (ii) Whe m, the curve is symmetrical Echagig m ad reflects the curve. (iii) If m >, the maimum is to the right of. B o.e. As m icreases relative to, the maimum poit moves further to the right B m dy m m m y d m m dy maimum at m d G Skewed curve from (,) to (,), maimum to right of. B B M A M m A Give BB if the idea is correct but vaguely epressed Usig product rule Ay correct form Settig derivative ad solvig to fid a value of other tha or
GCE. Mathematics (MEI) Mark Scheme for January Advanced GCE Unit 4756: Further Methods for Advanced Mathematics PMT
GCE Mathematics (MEI) Advaced GCE Uit 476: Further Methods for Advaced Mathematics Mark Scheme for Jauar Oford Cambridge ad RSA Eamiatios 476 Mark Scheme Jauar (a) (i) a d ta a sec M Differetiatig with
More informationFurther Methods for Advanced Mathematics (FP2) WEDNESDAY 9 JANUARY 2008
ADVANCED GCE 7/ MATHEMATICS (MEI) Furter Metods for Advaced Matematics (F) WEDNESDAY 9 JANUARY 8 Additioal materials: Aswer Booklet (8 pages) Grap paper MEI Eamiatio Formulae ad Tables (MF) Afteroo Time:
More information4755 Mark Scheme June Question Answer Marks Guidance M1* Attempt to find M or 108M -1 M 108 M1 A1 [6] M1 A1
4755 Mark Scheme Jue 05 * Attempt to fid M or 08M - M 08 8 4 * Divide by their determiat,, at some stage Correct determiat, (A0 for det M= 08 stated, all other OR 08 8 4 5 8 7 5 x, y,oe 8 7 4xy 8xy dep*
More informationCALCULUS BASIC SUMMER REVIEW
CALCULUS BASIC SUMMER REVIEW NAME rise y y y Slope of a o vertical lie: m ru Poit Slope Equatio: y y m( ) The slope is m ad a poit o your lie is, ). ( y Slope-Itercept Equatio: y m b slope= m y-itercept=
More informationSeptember 2012 C1 Note. C1 Notes (Edexcel) Copyright - For AS, A2 notes and IGCSE / GCSE worksheets 1
September 0 s (Edecel) Copyright www.pgmaths.co.uk - For AS, A otes ad IGCSE / GCSE worksheets September 0 Copyright www.pgmaths.co.uk - For AS, A otes ad IGCSE / GCSE worksheets September 0 Copyright
More informationNational Quali cations SPECIMEN ONLY
AH Natioal Quali catios SPECIMEN ONLY SQ/AH/0 Mathematics Date Not applicable Duratio hours Total s 00 Attempt ALL questios. You may use a calculator. Full credit will be give oly to solutios which cotai
More informationDe Moivre s Theorem - ALL
De Moivre s Theorem - ALL. Let x ad y be real umbers, ad be oe of the complex solutios of the equatio =. Evaluate: (a) + + ; (b) ( x + y)( x + y). [6]. (a) Sice is a complex umber which satisfies = 0,.
More informationREVISION SHEET FP1 (MEI) ALGEBRA. Identities In mathematics, an identity is a statement which is true for all values of the variables it contains.
The mai ideas are: Idetities REVISION SHEET FP (MEI) ALGEBRA Before the exam you should kow: If a expressio is a idetity the it is true for all values of the variable it cotais The relatioships betwee
More informationEDEXCEL STUDENT CONFERENCE 2006 A2 MATHEMATICS STUDENT NOTES
EDEXCEL STUDENT CONFERENCE 006 A MATHEMATICS STUDENT NOTES South: Thursday 3rd March 006, Lodo EXAMINATION HINTS Before the eamiatio Obtai a copy of the formulae book ad use it! Write a list of ad LEARN
More informationREVISION SHEET FP1 (MEI) ALGEBRA. Identities In mathematics, an identity is a statement which is true for all values of the variables it contains.
the Further Mathematics etwork wwwfmetworkorguk V 07 The mai ideas are: Idetities REVISION SHEET FP (MEI) ALGEBRA Before the exam you should kow: If a expressio is a idetity the it is true for all values
More informationSection 1 of Unit 03 (Pure Mathematics 3) Algebra
Sectio 1 of Uit 0 (Pure Mathematics ) Algebra Recommeded Prior Kowledge Studets should have studied the algebraic techiques i Pure Mathematics 1. Cotet This Sectio should be studied early i the course
More informationAPPENDIX F Complex Numbers
APPENDIX F Complex Numbers Operatios with Complex Numbers Complex Solutios of Quadratic Equatios Polar Form of a Complex Number Powers ad Roots of Complex Numbers Operatios with Complex Numbers Some equatios
More information9795 FURTHER MATHEMATICS
CAMBRIDGE INTERNATIONAL EXAMINATIONS Pre-U Certificate MARK SCHEME for the May/Jue series 9795 FURTHER MATHEMATICS 9795/ Paper (Further Pure Mathematics, maximum raw mark This mark scheme is published
More information( ) ( ) ( ) ( ) ( + ) ( )
LSM Nov. 00 Cotet List Mathematics (AH). Algebra... kow ad use the otatio!, C r ad r.. kow the results = r r + + = r r r..3 kow Pascal's triagle. Pascal's triagle should be eteded up to = 7...4 kow ad
More informationAppendix F: Complex Numbers
Appedix F Complex Numbers F1 Appedix F: Complex Numbers Use the imagiary uit i to write complex umbers, ad to add, subtract, ad multiply complex umbers. Fid complex solutios of quadratic equatios. Write
More informationGCE. Mathematics. Mark Scheme for January Advanced GCE Unit 4727: Further Pure Mathematics 3. physicsandmathstutor.com
GCE Mathematics Advaced GCE Uit 77: Further Pure Mathematics Mark Scheme for Jauary 0 Oford Cambridge ad RSA Eamiatios OCR (Oford Cambridge ad RSA) is a leadig UK awardig body, providig a wide rage of
More informationFor use only in Badminton School November 2011 C2 Note. C2 Notes (Edexcel)
For use oly i Badmito School November 0 C Note C Notes (Edecel) Copyright www.pgmaths.co.uk - For AS, A otes ad IGCSE / GCSE worksheets For use oly i Badmito School November 0 C Note Copyright www.pgmaths.co.uk
More informationHonors Calculus Homework 13 Solutions, due 12/8/5
Hoors Calculus Homework Solutios, due /8/5 Questio Let a regio R i the plae be bouded by the curves y = 5 ad = 5y y. Sketch the regio R. The two curves meet where both equatios hold at oce, so where: y
More informationHigher Course Plan. Calculus and Relationships Expressions and Functions
Higher Course Pla Applicatios Calculus ad Relatioships Expressios ad Fuctios Topic 1: The Straight Lie Fid the gradiet of a lie Colliearity Kow the features of gradiets of: parallel lies perpedicular lies
More informationREVISION SHEET FP2 (OCR) CALCULUS. x x 0.5. x x 1.5. π π. Standard Calculus of Inverse Trig and Hyperbolic Trig Functions = + = + arcsin x = +
the Further Mathematics etwork wwwfmetworkorguk V 7 REVISION SHEET FP (OCR) CALCULUS The mai ideas are: Calculus usig iverse trig fuctios & hperbolic trig fuctios ad their iverses Maclauri series Differetiatig
More informationFriday 20 May 2016 Morning
Oxford Cambridge ad RSA Friday 0 May 06 Morig AS GCE MATHEMATICS (MEI) 4755/0 Further Cocepts for Advaced Mathematics (FP) QUESTION PAPER * 6 8 6 6 9 5 4 * Cadidates aswer o the Prited Aswer Boo. OCR supplied
More informationFor use only in [the name of your school] 2014 FP2 Note. FP2 Notes (Edexcel)
For use oly i [the ame of your school] 04 FP Note FP Notes (Edexcel) Copyright wwwpgmathscouk - For AS, A otes ad IGCSE / GCSE worksheets For use oly i [the ame of your school] 04 FP Note BLANK PAGE Copyright
More informationFurther Concepts for Advanced Mathematics (FP1) MONDAY 2 JUNE 2008
ADVANCED SUBSIDIARY GCE 4755/0 MATHEMATICS (MEI) Further Cocepts for Advaced Mathematics (FP) MONDAY JUNE 008 Additioal materials: Aswer Booklet (8 pages) Graph paper MEI Examiatio Formulae ad Tables (MF)
More informationTopic 5 [434 marks] (i) Find the range of values of n for which. (ii) Write down the value of x dx in terms of n, when it does exist.
Topic 5 [44 marks] 1a (i) Fid the rage of values of for which eists 1 Write dow the value of i terms of 1, whe it does eist Fid the solutio to the differetial equatio 1b give that y = 1 whe = π (cos si
More informationFurther Concepts for Advanced Mathematics (FP1) MONDAY 2 JUNE 2008
ADVANCED SUBSIDIARY GCE 4755/0 MATHEMATICS (MEI) Further Cocepts for Advaced Mathematics (FP) MONDAY JUNE 008 Additioal materials: Aswer Booklet (8 pages) Graph paper MEI Examiatio Formulae ad Tables (MF)
More information1 1 2 = show that: over variables x and y. [2 marks] Write down necessary conditions involving first and second-order partial derivatives for ( x0, y
Questio (a) A square matrix A= A is called positive defiite if the quadratic form waw > 0 for every o-zero vector w [Note: Here (.) deotes the traspose of a matrix or a vector]. Let 0 A = 0 = show that:
More informationN14/5/MATHL/HP1/ENG/TZ0/XX/M MARKSCHEME. November 2014 MATHEMATICS. Higher Level. Paper pages
N4/5/MATHL/HP/ENG/TZ0/XX/M MARKSCHEME November 04 MATHEMATICS Higher Level Paper 0 pages N4/5/MATHL/HP/ENG/TZ0/XX/M This markscheme is the property of the Iteratioal Baccalaureate ad must ot be reproduced
More informationIYGB. Special Extension Paper E. Time: 3 hours 30 minutes. Created by T. Madas. Created by T. Madas
YGB Special Extesio Paper E Time: 3 hours 30 miutes Cadidates may NOT use ay calculator. formatio for Cadidates This practice paper follows the Advaced Level Mathematics Core ad the Advaced Level Further
More informationMATHEMATICS 9740 (HIGHER 2)
VICTORIA JUNIOR COLLEGE PROMOTIONAL EXAMINATION MATHEMATICS 970 (HIGHER ) Frida 6 Sept 0 8am -am hours Additioal materials: Aswer Paper List of Formulae (MF5) READ THESE INSTRUCTIONS FIRST Write our ame
More informationTopic 1 2: Sequences and Series. A sequence is an ordered list of numbers, e.g. 1, 2, 4, 8, 16, or
Topic : Sequeces ad Series A sequece is a ordered list of umbers, e.g.,,, 8, 6, or,,,.... A series is a sum of the terms of a sequece, e.g. + + + 8 + 6 + or... Sigma Notatio b The otatio f ( k) is shorthad
More information) + 2. Mathematics 2 Outcome 1. Further Differentiation (8/9 pers) Cumulative total = 64 periods. Lesson, Outline, Approach etc.
Further Differetiatio (8/9 pers Mathematics Outcome Go over the proofs of the derivatives o si ad cos. [use y = si => = siy etc.] * Ask studets to fid derivative of cos. * Ask why d d (si = (cos see graphs.
More informationZ ß cos x + si x R du We start with the substitutio u = si(x), so du = cos(x). The itegral becomes but +u we should chage the limits to go with the ew
Problem ( poits) Evaluate the itegrals Z p x 9 x We ca draw a right triagle labeled this way x p x 9 From this we ca read off x = sec, so = sec ta, ad p x 9 = R ta. Puttig those pieces ito the itegralrwe
More information9231 FURTHER MATHEMATICS
CAMBRIDGE INTERNATIONAL EXAMINATIONS GCE Advaced Level MARK SCHEME for the October/vember series 9 FURTHER MATHEMATICS 9/ Paper, maximum raw mark This mark scheme is published as a aid to teachers ad cadidates,
More informationComplex Numbers Solutions
Complex Numbers Solutios Joseph Zoller February 7, 06 Solutios. (009 AIME I Problem ) There is a complex umber with imagiary part 64 ad a positive iteger such that Fid. [Solutio: 697] 4i + + 4i. 4i 4i
More information+ {JEE Advace 03} Sept 0 Name: Batch (Day) Phoe No. IT IS NOT ENOUGH TO HAVE A GOOD MIND, THE MAIN THING IS TO USE IT WELL Marks: 00. If A (α, β) = (a) A( α, β) = A( α, β) (c) Adj (A ( α, β)) = Sol : We
More informationx x x Using a second Taylor polynomial with remainder, find the best constant C so that for x 0,
Math Activity 9( Due with Fial Eam) Usig first ad secod Taylor polyomials with remaider, show that for, 8 Usig a secod Taylor polyomial with remaider, fid the best costat C so that for, C 9 The th Derivative
More informationMEI STRUCTURED MATHEMATICS FURTHER CONCEPTS FOR ADVANCED MATHEMATICS, FP1. Practice Paper FP1-B
MEI Mathematics i Educatio ad Idustry MEI STRUCTURED MATHEMATICS FURTHER CONCEPTS FOR ADVANCED MATHEMATICS, FP Practice Paper FP-B Additioal materials: Aswer booklet/paper Graph paper MEI Examiatio formulae
More informationIn algebra one spends much time finding common denominators and thus simplifying rational expressions. For example:
74 The Method of Partial Fractios I algebra oe speds much time fidig commo deomiators ad thus simplifyig ratioal epressios For eample: + + + 6 5 + = + = = + + + + + ( )( ) 5 It may the seem odd to be watig
More informationTECHNIQUES OF INTEGRATION
7 TECHNIQUES OF INTEGRATION Simpso s Rule estimates itegrals b approimatig graphs with parabolas. Because of the Fudametal Theorem of Calculus, we ca itegrate a fuctio if we kow a atiderivative, that is,
More informationGCE Further Mathematics (6360) Further Pure Unit 2 (MFP2) Textbook. Version: 1.5
GCE Further Mathematics (660) Further Pure Uit (MFP) Tetbook Versio: 5 MFP Tetbook A-level Further Mathematics 660 Further Pure : Cotets Chapter : Comple umbers 4 Itroductio 5 The geeral comple umber 5
More informationAH Checklist (Unit 3) AH Checklist (Unit 3) Matrices
AH Checklist (Uit 3) AH Checklist (Uit 3) Matrices Skill Achieved? Kow that a matrix is a rectagular array of umbers (aka etries or elemets) i paretheses, each etry beig i a particular row ad colum Kow
More informationAP Calculus BC Review Applications of Derivatives (Chapter 4) and f,
AP alculus B Review Applicatios of Derivatives (hapter ) Thigs to Kow ad Be Able to Do Defiitios of the followig i terms of derivatives, ad how to fid them: critical poit, global miima/maima, local (relative)
More informationComplex Numbers. Brief Notes. z = a + bi
Defiitios Complex Numbers Brief Notes A complex umber z is a expressio of the form: z = a + bi where a ad b are real umbers ad i is thought of as 1. We call a the real part of z, writte Re(z), ad b the
More informationPhysicsAndMathsTutor.com. Mark Scheme (Results) Summer GCE Core Mathematics C2 (6664) Paper 1
Mark Scheme (Results) Summer 01 GCE Core Mathematics C (6664) Paper 1 Edecel ad BTEC Qualificatios Edecel ad BTEC qualificatios come from Pearso, the world s leadig learig compay. We provide a wide rage
More informationMEI Conference 2009 Stretching students: A2 Core
MEI Coferece 009 Stretchig studets: A Core Preseter: Berard Murph berard.murph@mei.org.uk Workshop G How ca ou prove that these si right-agled triagles fit together eactl to make a 3-4-5 triagle? What
More informationMATHEMATICS (Three hours and a quarter)
MATHEMATICS (Three hours ad a quarter) (The first fiftee miutes of the eamiatio are for readig the paper oly. Cadidates must NOT start writig durig this time.) Aswer Questio from Sectio A ad questios from
More informationf t dt. Write the third-degree Taylor polynomial for G
AP Calculus BC Homework - Chapter 8B Taylor, Maclauri, ad Power Series # Taylor & Maclauri Polyomials Critical Thikig Joural: (CTJ: 5 pts.) Discuss the followig questios i a paragraph: What does it mea
More information9231 FURTHER MATHEMATICS
CAMBRIDGE INTERNATIONAL EXAMINATIONS GCE Advaced Level www.xtremepapers.com MARK SCHEME for the October/vember series 9 FURTHER MATHEMATICS 9/ Paper, maximum raw mark This mark scheme is published as a
More informationWELSH JOINT EDUCATION COMMITTEE 3.00 CYD-BWYLLGOR ADDYSG CYMRU MARKING SCHEMES JANUARY 2007 MATHEMATICS
MS WELSH JOINT EDUCATION COMMITTEE.00 CYD-BWYLLGOR ADDYSG CYMRU Geeral Certificate of Educatio Advaced Subsidiary/Advaced Tystysgrif Addysg Gyffrediol Uwch Gyfraol/Uwch MARKING SCHEMES JANUARY 007 MATHEMATICS
More informationVICTORIA JUNIOR COLLEGE Preliminary Examination. Paper 1 September 2015
VICTORIA JUNIOR COLLEGE Prelimiary Eamiatio MATHEMATICS (Higher ) 70/0 Paper September 05 Additioal Materials: Aswer Paper Graph Paper List of Formulae (MF5) 3 hours READ THESE INSTRUCTIONS FIRST Write
More informationCondensed. Mathematics. General Certificate of Education Advanced Level Examination January Unit Further Pure 4.
Geeral Certificate of Educatio Advaced Level Examiatio Jauary 0 Mathematics MFP4 Uit Further Pure 4 Friday Jauary 0 9.00 am to 0.30 am For this paper you must have: the blue AQA booklet of formulae ad
More informationSNAP Centre Workshop. Basic Algebraic Manipulation
SNAP Cetre Workshop Basic Algebraic Maipulatio 8 Simplifyig Algebraic Expressios Whe a expressio is writte i the most compact maer possible, it is cosidered to be simplified. Not Simplified: x(x + 4x)
More informationMath 142, Final Exam. 5/2/11.
Math 4, Fial Exam 5// No otes, calculator, or text There are poits total Partial credit may be give Write your full ame i the upper right corer of page Number the pages i the upper right corer Do problem
More informationCalculus with Analytic Geometry 2
Calculus with Aalytic Geometry Fial Eam Study Guide ad Sample Problems Solutios The date for the fial eam is December, 7, 4-6:3p.m. BU Note. The fial eam will cosist of eercises, ad some theoretical questios,
More informationNATIONAL SENIOR CERTIFICATE GRADE 12
NAIONAL SENI CERIFICAE GRADE MAHEMAICS P NOVEMBER 008 MEMANDUM MARKS: 0 his memoradum cosists of pages. Copright reserved Please tur over Mathematics/P DoE/November 008 NSC Memoradum Cotiued Accurac will
More informationJEE(Advanced) 2018 TEST PAPER WITH SOLUTION (HELD ON SUNDAY 20 th MAY, 2018)
JEE(Advaced) 08 TEST PAPER WITH SOLUTION (HELD ON SUNDAY 0 th MAY, 08) PART- : JEE(Advaced) 08/Paper- SECTION. For ay positive iteger, defie ƒ : (0, ) as ƒ () j ta j j for all (0, ). (Here, the iverse
More information9231 FURTHER MATHEMATICS
CMRIDGE INTERNTIONL EXMINTIONS Cambridge Iteratioal dvaced Level MRK SCHEME for the May/Jue series 9 FURTHER MTHEMTICS 9/ Paper (Paper ), maimum raw mark This mark scheme is published as a aid to teachers
More informationProblem Cosider the curve give parametrically as x = si t ad y = + cos t for» t» ß: (a) Describe the path this traverses: Where does it start (whe t =
Mathematics Summer Wilso Fial Exam August 8, ANSWERS Problem 1 (a) Fid the solutio to y +x y = e x x that satisfies y() = 5 : This is already i the form we used for a first order liear differetial equatio,
More informationA.1 Algebra Review: Polynomials/Rationals. Definitions:
MATH 040 Notes: Uit 0 Page 1 A.1 Algera Review: Polyomials/Ratioals Defiitios: A polyomial is a sum of polyomial terms. Polyomial terms are epressios formed y products of costats ad variales with whole
More informationwww.olieexamhelp.com www.olieexamhelp.com CAMBRIDGE INTERNATIONAL EXAMINATIONS GCE Advaced Level MARK SCHEME for the October/vember series 9 FURTHER MATHEMATICS 9/ Paper, maximum raw mark This mark scheme
More informationPresentation of complex number in Cartesian and polar coordinate system
a + bi, aεr, bεr i = z = a + bi a = Re(z), b = Im(z) give z = a + bi & w = c + di, a + bi = c + di a = c & b = d The complex cojugate of z = a + bi is z = a bi The sum of complex cojugates is real: z +
More informationAIEEE 2004 (MATHEMATICS)
AIEEE 00 (MATHEMATICS) Importat Istructios: i) The test is of hours duratio. ii) The test cosists of 75 questios. iii) The maimum marks are 5. iv) For each correct aswer you will get marks ad for a wrog
More informationM1 for method for S xy. M1 for method for at least one of S xx or S yy. A1 for at least one of S xy, S xx, S yy correct. M1 for structure of r
Questio 1 (i) EITHER: 1 S xy = xy x y = 198.56 1 19.8 140.4 =.44 x x = 1411.66 1 19.8 = 15.657 1 S xx = y y = 1417.88 1 140.4 = 9.869 14 Sxy -.44 r = = SxxSyy 15.6579.869 = 0.76 1 S yy = 14 14 M1 for method
More information(c) Write, but do not evaluate, an integral expression for the volume of the solid generated when R is
Calculus BC Fial Review Name: Revised 7 EXAM Date: Tuesday, May 9 Remiders:. Put ew batteries i your calculator. Make sure your calculator is i RADIAN mode.. Get a good ight s sleep. Eat breakfast. Brig:
More informationModule Summary Sheets. C1, Introduction to Advanced Mathematics (Version B reference to new book)
MEI Mathematics i Educatio ad Idustry MEI Structured Mathematics Module Summary Sheets C, Itroductio to Advaced Mathematics (Versio B referece to ew book) Topic : Mathematical Processes ad Laguage Topic
More informationENGI 9420 Engineering Analysis Assignment 3 Solutions
ENGI 9 Egieerig Aalysis Assigmet Solutios Fall [Series solutio of ODEs, matri algebra; umerical methods; Chapters, ad ]. Fid a power series solutio about =, as far as the term i 7, to the ordiary differetial
More informationAH Checklist (Unit 2) AH Checklist (Unit 2) Proof Theory
AH Checklist (Uit ) AH Checklist (Uit ) Proof Theory Skill Achieved? Kow that a setece is ay cocateatio of letters or symbols that has a meaig Kow that somethig is true if it appears psychologically covicig
More informationMath 113 Exam 3 Practice
Math Exam Practice Exam 4 will cover.-., 0. ad 0.. Note that eve though. was tested i exam, questios from that sectios may also be o this exam. For practice problems o., refer to the last review. This
More informationChanges for version 1.2 include further corrections to chapter 4 and a correction to the numbering of the exercises in chapter 5.
Versio 0507 klm Chages for versio icluded the isertio of a ew chapter 5 for the 007 specificatio ad some mior mathematical correctios i chapters ad 4 Please ote that these are ot side-barred Chages for
More informationThe type of limit that is used to find TANGENTS and VELOCITIES gives rise to the central idea in DIFFERENTIAL CALCULUS, the DERIVATIVE.
NOTES : LIMITS AND DERIVATIVES Name: Date: Period: Iitial: LESSON.1 THE TANGENT AND VELOCITY PROBLEMS Pre-Calculus Mathematics Limit Process Calculus The type of it that is used to fid TANGENTS ad VELOCITIES
More informationMATHEMATICS. 61. The differential equation representing the family of curves where c is a positive parameter, is of
MATHEMATICS 6 The differetial equatio represetig the family of curves where c is a positive parameter, is of Order Order Degree (d) Degree (a,c) Give curve is y c ( c) Differetiate wrt, y c c y Hece differetial
More informationChapter 2 The Solution of Numerical Algebraic and Transcendental Equations
Chapter The Solutio of Numerical Algebraic ad Trascedetal Equatios Itroductio I this chapter we shall discuss some umerical methods for solvig algebraic ad trascedetal equatios. The equatio f( is said
More informationAS Further Mathematics
AS Further Mathematics Paper Mark scheme Specime Versio. Mark schemes are prepared by the Lead Assessmet Writer ad cosidered, together with the relevat questios, by a pael of subject teachers. This mark
More informationMTH Assignment 1 : Real Numbers, Sequences
MTH -26 Assigmet : Real Numbers, Sequeces. Fid the supremum of the set { m m+ : N, m Z}. 2. Let A be a o-empty subset of R ad α R. Show that α = supa if ad oly if α is ot a upper boud of A but α + is a
More informationFUNCTIONS (11 UNIVERSITY)
FINAL EXAM REVIEW FOR MCR U FUNCTIONS ( UNIVERSITY) Overall Remiders: To study for your eam your should redo all your past tests ad quizzes Write out all the formulas i the course to help you remember
More informationComplete Solutions to Supplementary Exercises on Infinite Series
Coplete Solutios to Suppleetary Eercises o Ifiite Series. (a) We eed to fid the su ito partial fractios gives By the cover up rule we have Therefore Let S S A / ad A B B. Covertig the suad / the by usig
More informationMathematics Extension 2
004 HIGHER SCHOOL CERTIFICATE EXAMINATION Mathematics Etesio Geeral Istructios Readig time 5 miutes Workig time hours Write usig black or blue pe Board-approved calculators may be used A table of stadard
More informationU8L1: Sec Equations of Lines in R 2
MCVU U8L: Sec. 8.9. Equatios of Lies i R Review of Equatios of a Straight Lie (-D) Cosider the lie passig through A (-,) with slope, as show i the diagram below. I poit slope form, the equatio of the lie
More informationPRACTICE FINAL/STUDY GUIDE SOLUTIONS
Last edited December 9, 03 at 4:33pm) Feel free to sed me ay feedback, icludig commets, typos, ad mathematical errors Problem Give the precise meaig of the followig statemets i) a f) L ii) a + f) L iii)
More informationLESSON 2: SIMPLIFYING RADICALS
High School: Workig with Epressios LESSON : SIMPLIFYING RADICALS N.RN.. C N.RN.. B 5 5 C t t t t t E a b a a b N.RN.. 4 6 N.RN. 4. N.RN. 5. N.RN. 6. 7 8 N.RN. 7. A 7 N.RN. 8. 6 80 448 4 5 6 48 00 6 6 6
More informationRADICAL EXPRESSION. If a and x are real numbers and n is a positive integer, then x is an. n th root theorems: Example 1 Simplify
Example 1 Simplify 1.2A Radical Operatios a) 4 2 b) 16 1 2 c) 16 d) 2 e) 8 1 f) 8 What is the relatioship betwee a, b, c? What is the relatioship betwee d, e, f? If x = a, the x = = th root theorems: RADICAL
More informationMID-YEAR EXAMINATION 2018 H2 MATHEMATICS 9758/01. Paper 1 JUNE 2018
MID-YEAR EXAMINATION 08 H MATHEMATICS 9758/0 Paper JUNE 08 Additioal Materials: Writig Paper, MF6 Duratio: hours DO NOT OPEN THIS BOOKLET UNTIL YOU ARE TOLD TO DO SO READ THESE INSTRUCTIONS FIRST Write
More information3 Show in each case that there is a root of the given equation in the given interval. a x 3 = 12 4
C Worksheet A Show i each case that there is a root of the equatio f() = 0 i the give iterval a f() = + 7 (, ) f() = 5 cos (05, ) c f() = e + + 5 ( 6, 5) d f() = 4 5 + (, ) e f() = l (4 ) + (04, 05) f
More informationMTH112 Trigonometry 2 2 2, 2. 5π 6. cscθ = 1 sinθ = r y. secθ = 1 cosθ = r x. cotθ = 1 tanθ = cosθ. central angle time. = θ t.
MTH Trigoometry,, 5, 50 5 0 y 90 0, 5 0,, 80 0 0 0 (, 0) x, 7, 0 5 5 0, 00 5 5 0 7,,, Defiitios: siθ = opp. hyp. = y r cosθ = adj. hyp. = x r taθ = opp. adj. = siθ cosθ = y x cscθ = siθ = r y secθ = cosθ
More informationP.3 Polynomials and Special products
Precalc Fall 2016 Sectios P.3, 1.2, 1.3, P.4, 1.4, P.2 (radicals/ratioal expoets), 1.5, 1.6, 1.7, 1.8, 1.1, 2.1, 2.2 I Polyomial defiitio (p. 28) a x + a x +... + a x + a x 1 1 0 1 1 0 a x + a x +... +
More informationTEMASEK JUNIOR COLLEGE, SINGAPORE JC One Promotion Examination 2014 Higher 2
TEMASEK JUNIOR COLLEGE, SINGAPORE JC Oe Promotio Eamiatio 04 Higher MATHEMATICS 9740 9 Septemer 04 Additioal Materials: Aswer paper 3 hours List of Formulae (MF5) READ THESE INSTRUCTIONS FIRST Write your
More informationHKDSE Exam Questions Distribution
HKDSE Eam Questios Distributio Sample Paper Practice Paper DSE 0 Topics A B A B A B. Biomial Theorem. Mathematical Iductio 0 3 3 3. More about Trigoometric Fuctios, 0, 3 0 3. Limits 6. Differetiatio 7
More informationMathematics Extension 1
016 Bored of Studies Trial Eamiatios Mathematics Etesio 1 3 rd ctober 016 Geeral Istructios Total Marks 70 Readig time 5 miutes Workig time hours Write usig black or blue pe Black pe is preferred Board-approved
More information6.003 Homework #3 Solutions
6.00 Homework # Solutios Problems. Complex umbers a. Evaluate the real ad imagiary parts of j j. π/ Real part = Imagiary part = 0 e Euler s formula says that j = e jπ/, so jπ/ j π/ j j = e = e. Thus the
More informationStudent s Printed Name:
Studet s Prited Name: Istructor: XID: C Sectio: No questios will be aswered durig this eam. If you cosider a questio to be ambiguous, state your assumptios i the margi ad do the best you ca to provide
More informationG r a d e 1 1 P r e - C a l c u l u s M a t h e m a t i c s ( 3 0 S )
G r a d e 1 1 P r e - C a l c u l u s M a t h e m a t i c s ( 3 0 S ) Grade 11 Pre-Calculus Mathematics (30S) is desiged for studets who ited to study calculus ad related mathematics as part of post-secodary
More informationApply change-of-basis formula to rewrite x as a linear combination of eigenvectors v j.
Eigevalue-Eigevector Istructor: Nam Su Wag eigemcd Ay vector i real Euclidea space of dimesio ca be uiquely epressed as a liear combiatio of liearly idepedet vectors (ie, basis) g j, j,,, α g α g α g α
More informationWe are mainly going to be concerned with power series in x, such as. (x)} converges - that is, lims N n
Review of Power Series, Power Series Solutios A power series i x - a is a ifiite series of the form c (x a) =c +c (x a)+(x a) +... We also call this a power series cetered at a. Ex. (x+) is cetered at
More informationANSWERS SOLUTIONS iiii i. and 1. Thus, we have. i i i. i, A.
013 ΜΑΘ Natioal Covetio ANSWERS (1) C A A A B (6) B D D A B (11) C D D A A (16) D B A A C (1) D B C B C (6) D C B C C 1. We have SOLUTIONS 1 3 11 61 iiii 131161 i 013 013, C.. The powers of i cycle betwee
More information2 f(x) dx = 1, 0. 2f(x 1) dx d) 1 4t t6 t. t 2 dt i)
Math PracTest Be sure to review Lab (ad all labs) There are lots of good questios o it a) State the Mea Value Theorem ad draw a graph that illustrates b) Name a importat theorem where the Mea Value Theorem
More informationINTEGRATION BY PARTS (TABLE METHOD)
INTEGRATION BY PARTS (TABLE METHOD) Suppose you wat to evaluate cos d usig itegratio by parts. Usig the u dv otatio, we get So, u dv d cos du d v si cos d si si d or si si d We see that it is ecessary
More informationCalculus 2 - D. Yuen Final Exam Review (Version 11/22/2017. Please report any possible typos.)
Calculus - D Yue Fial Eam Review (Versio //7 Please report ay possible typos) NOTE: The review otes are oly o topics ot covered o previous eams See previous review sheets for summary of previous topics
More informationAlgebra II Notes Unit Seven: Powers, Roots, and Radicals
Syllabus Objectives: 7. The studets will use properties of ratioal epoets to simplify ad evaluate epressios. 7.8 The studet will solve equatios cotaiig radicals or ratioal epoets. b a, the b is the radical.
More informationThe z-transform. 7.1 Introduction. 7.2 The z-transform Derivation of the z-transform: x[n] = z n LTI system, h[n] z = re j
The -Trasform 7. Itroductio Geeralie the complex siusoidal represetatio offered by DTFT to a represetatio of complex expoetial sigals. Obtai more geeral characteristics for discrete-time LTI systems. 7.
More information