02 - COMPLEX NUMBERS Page 1 ( Answers at the end of all questions ) l w l = 1, then z lies on

Size: px
Start display at page:

Download "02 - COMPLEX NUMBERS Page 1 ( Answers at the end of all questions ) l w l = 1, then z lies on"

Transcription

1 0 - COMPLEX NUMBERS Page ( ) If the cube roots of uity are,,, the the roots of the equatio ( x - ) + 8 = 0 are ( a ) -, - +, - - ( b ) -, -, -, ( c ) -, -, - ( d ) -, +, + [ AIEEE 005 ] ( ) If z ad z are two o-zero complex umbers such that l z + l = l z l + l z l, the arg z - arg z is equal to ( a ) ( ) If w = z z - i ( b ) - ( c ) 0 ( d ) - ad l w l =, the z lies o [ AIEEE 005 ] ( a ) a ellipse ( b ) a circle ( d ) a straig t lie ( d ) a parabola [ AIEEE 005 ] ( ) Let z, w be complex umbers such that z + i w = 0 ad arg zw =. The arg z equals ( a ) ( b ) ( c ) ( 5 ) If z = x - y ad z = p + iq, the ( d ) 5 x p p y + q + q is equal to [ AIEEE 00 ] ( a ) ( b ) - ( c ) ( d ) - [ AIEEE 00 ] 6 ) If l z - l = l z l +, the z lies o ( a ) the real axis ( b ) the imagiary axis ( c ) a circle ( c ) a ellipse [ AIEEE 00 ] ( 7 ) Let z ad z be two roots of the equatio z + az + b = 0, z beig complex. Further assume that the origi, z ad z form a equilateral triagle. The ( a ) a = b ( b ) a = b ( c ) a = b ( d ) a = b [ AIEEE 00 ]

2 0 - COMPLEX NUMBERS Page ( 8 ) If z ad w are two o-zero complex umbers such that l zw l = ad ( 9 ) If Arg ( z ) - Arg ( w ) =, the z w is equal to ( a ) ( b ) - ( c ) i ( d ) - i [ AIEEE 00 ] x + i - i =, the the value of smallest positive iteger is gi by ( a ) x = ( b ) x = ( c ) x = + ( d ) x = + [ AIEEE 00 ] ( 0 ) If,, are the cube roots of uity, the the alue of = ( ) If is ( a ) ( b ) 0 ( c ) ( d ) [ AIEEE 00 ] c + i = a ib, where a, b, c are real, the the value of a + b is c - i ( a ) ( b ) ( c ) c ( d ) - c [ AIEEE 00 ] ( ) If z = x + y, the l z - l = l z - l represets ( a ) x xis ( b ) y-axis ( c ) a circle ( d ) lie parallel to y-axis [ AIEEE 00 ] If the cube roots of uity are, ad, the the value of + ( a ) ( b ) - ( c ) ( d ) [ AIEEE 00 ] is ( ) If a = cos α + i si α ad b = cos β + i si β, the the value of ab + ab is ( a ) si ( α + β ) ( b ) cos ( α + β ) ( c ) si ( α - β ) ( d ) cos ( α - β ) [ AIEEE 00 ]

3 0 - COMPLEX NUMBERS Page ( 5 ) If α is cube root of uity, the for N, the value of α + + α + 5 is ( a ) - ( b ) 0 ( c ) ( d ) [ AIEEE 00 ] ( 6 ) Four poits P ( -, 0 ), Q (, 0 ), R ( -, ) ad S ( -, - ) are give o a complex plae, equatio of the locus of the shaded regio excludig the boudaries is give by ( a ) l z + l > ad l arg ( z + ) l < ( b ) l z + l > ad l arg ( z + ) l < ( c ) l z - l > ad l arg ( z - ) l < ( d ) l z - l > ad l arg ( z - ) l < [ IIT 005 ] ( 7 ) If is cube root of uity ( ), the the least value of where is a positive iteger such that ( + ) = ( + ) is ( a ) ( b ) ( c ) 5 ( d ) 6 [ IIT 00 ] ( 8 ) The complex umber z is such that l z l =, z - ad = of is ( a ) ( 9 ) Let = l z + l ( b ) - l z + l ( c ) l z + l z -, the real part z + ( d ) 0 [ IIT 00 ] - + i. The the value of the determiat - - is ( a ) ( b ) ( - ) ( c ) ( d ) ( - ) [ IIT 00 ] ( 0 ) For all complex umbers z, z satisfyig l z l = ad l z - - i l = 5, the miimum value of l z - z l is ( a ) 0 ( b ) ( c ) 7 ( d ) 7 [ IIT 00 ]

4 0 - COMPLEX NUMBERS Page ( ) The complex umbers z, z ad z satisfyig of a triagle which is z - z - i = are the vertices z - z ( a ) of area zero ( b ) right-agled isosceles ( c ) equilateral ( d ) obtuse-agled isosceles [ IIT 00 ] ( ) If z ad z be th roots of uity which subted a right gle at the origi, the must be of the form ( a ) k + ( b ) k + ( c ) k + ( d ) k [ IIT 00 ] ( ) If arg ( z ) < 0, the arg ( - z ) - arg ( z ) = ( a ) ( b ) - ( c ) - ( ) If z, z ad z are complex umbers such that l z l = l z l = l z l = + + =, the l z + z + z l is z z ( d ) [ IIT 000 ] ( a ) ( b ) < ( c ) > ( d ) [ IIT 000 ] 65 i ( 5 ) If i = - th + 5 i is equal to ( a ) - i ( b ) - + i ( c ) i ( d ) - i [ IIT 999 ] ( 6 ) If is a imagiary cube root of uity, the ( + - ) 7 equals ( a ) 8 ( b ) - 8 ( c ) 8 ( d ) - 8 [ IIT 998 ] ( 7 ) The value of the sum ( i + i + ), where i = -, equals = ( a ) i ( b ) i - ( c ) - i ( d ) 0 [ IIT 998 ]

5 ( 8 ) If 6i 0 - i i - i 0 - COMPLEX NUMBERS Page 5 = x + iy, the ( a ) x =, y = ( b ) x =, y = ( c ) x = 0, y = ( d ) x = 0, y = 0 [ IIT 998 ] ( 9 ) For positive itegers,, the value of the expressio ( ) ( ) ( ) i i i ( i 7 ) , where i = - is a real umber if ad oly if ( a ) = + ( b ) = - ( c ) = ( d ) >, > 0 [ IIT 996 ] ( 0 ) If ( ) is a cube root of uity a ( + ) 7 = A + B, the A ad B are respectively the umbers ( a ) 0, ( b ), ( c ), 0 ( d ) -, [ IIT 995 ] ( ) If ( ) is a cube root of uity, the - i - i + i - i equals ( a ) 0 ( b ) ( c ) i ( d ) [ IIT 995 ] ( ) If z ad be two o-zero complex umbers such that l z l = l l ad Arg z + Arg =, the z equals a ) ( b ) - ( c ) ( d ) - [ IIT 995 ] ( ) If z ad w be two complex umbers such that l z l, l w l ad l z + iw l = l z - iw l =, the z equals ( a ) or i ( b ) i or - i ( c ) or - ( d ) i or - [ IIT 995 ] ( ) The complex umbers si x + i cos x ad cos x - i si x are cojugate to each other for ( a ) x = ( b ) x = 0 ( c ) x = ( + / ) ( d ) o value of x [ IIT 988 ]

6 0 - COMPLEX NUMBERS Page 6 ( 5 ) If z ad z are two o-zero complex umbers such that l z + z l = l z l + l z l, the arg z - arg z is equal to ( a ) - ( b ) - 6 k ( 6 ) The value of si 7 k = ( c ) 0 ( d ) k - i cos is 7 ( e ) [ II 987 ] ( a ) - ( b ) 0 ( c ) - i ( d ) i ( e ) oe of these [ IIT 987 ] ( 7 ) Let z ad z be complex umbers such that z z ad l z l = l z l. If z has z positive real part ad z has egative imagia y part, the + z may be z - z ( a ) zero ( b ) real ad positive ( c ) real ad egative ( d ) purely imagiary ( e ) oe of hese [ IIT 986 ] ( 8 ) If a, b, c ad u, v, w re complex umbers represetig the vertices of two triagles such that c = ( - r ) a + b ad w = ( - r ) u + rv, where r is a complex umber, the the two riagles ( a ) have the same area ( b ) are similar ( c ) are cogruet ( d ) oe of these [ IIT 985 ] ( 9 ) If z = a + b ad z = c + id are complex umbers such that l z l = l z l = ad Re ( z z ) = 0, the the pair of complex umbers w = a + ic ad w = b + id s tisfies ( a ) l w l = ( b ) l w l = ( c ) Re ( w w ) = 0 ( d ) oe of these [ IIT 985 ] ( 0 ) If z = x + iy ad w = z - - iz, the l w l = implies that, i the complex plae, i ( a ) z lies o the imagiary axis ( b ) z lies o the real axis ( c ) z lies o the uit circle ( d ) Noe of these [ IIT 98 ]

7 0 - COMPLEX NUMBERS Page 7 ( ) The poits z, z, z, z i the complex plae are the vertices of a parallelogram take i order if ad oly if ( a ) z + z = z + z ( b ) z + z = z + z ( c ) z + z = z + z ( d ) Noe of these [ IIT 98 ] ( ) The iequality l z - l < l z - l represets the regio give by ( ) If z = ( a ) Re ( z ) > 0 ( b ) Re ( z ) < 0 ( c ) Re ( z ) > ( d ) oe of these [ IIT 98 ] 5 5 i i + + -, the ( a ) Re ( z ) = 0 ( b ) Im ( z ) = 0 ( c ) Re ( z ) > 0, Im ( z ) > 0 ( d ) Re ( z ) > 0, Im ( z ) < 0 [ IIT 98 ] ( ) If the cube roots of uity are,, the the roots of the equatio ( x - ) + 8 = 0 are ( a ) -, +, ( b ) -, -, - ( c ) -, -, - ( d ) oe of these [ IIT 979 ] Aswers c c c c d b c d a b a d b b b a b d b b c d a a c d b d d b a b c d a,e d a,d b a,b,c b b d b b

COMPLEX NUMBERS AND DE MOIVRE'S THEOREM SYNOPSIS. Ay umber of the form x+iy where x, y R ad i = - is called a complex umber.. I the complex umber x+iy, x is called the real part ad y is called the imagiary

More information

Presentation of complex number in Cartesian and polar coordinate system

Presentation of complex number in Cartesian and polar coordinate system a + bi, aεr, bεr i = z = a + bi a = Re(z), b = Im(z) give z = a + bi & w = c + di, a + bi = c + di a = c & b = d The complex cojugate of z = a + bi is z = a bi The sum of complex cojugates is real: z +

More information

JEE(Advanced) 2018 TEST PAPER WITH SOLUTION (HELD ON SUNDAY 20 th MAY, 2018)

JEE(Advanced) 2018 TEST PAPER WITH SOLUTION (HELD ON SUNDAY 20 th MAY, 2018) JEE(Advaced) 08 TEST PAPER WITH SOLUTION (HELD ON SUNDAY 0 th MAY, 08) PART- : JEE(Advaced) 08/Paper- SECTION. For ay positive iteger, defie ƒ : (0, ) as ƒ () j ta j j for all (0, ). (Here, the iverse

More information

SINGLE CORRECT ANSWER TYPE QUESTIONS: TRIGONOMETRY 2 2

SINGLE CORRECT ANSWER TYPE QUESTIONS: TRIGONOMETRY 2 2 Class-Jr.X_E-E SIMPLE HOLIDAY PACKAGE CLASS-IX MATHEMATICS SUB BATCH : E-E SINGLE CORRECT ANSWER TYPE QUESTIONS: TRIGONOMETRY. siθ+cosθ + siθ cosθ = ) ) ). If a cos q, y bsi q, the a y b ) ) ). The value

More information

Objective Mathematics

Objective Mathematics 6. If si () + cos () =, the is equal to :. If <

More information

COMPLEX NUMBER. Every Complex Number Can Be Regarded As. Purely imaginary if a = 0. (A) 0 (B) 2i (C) 2i (D) 2

COMPLEX NUMBER. Every Complex Number Can Be Regarded As. Purely imaginary if a = 0. (A) 0 (B) 2i (C) 2i (D) 2 J-Mathematics COMPLX NUMBR. DFINITION : Complex umbers are defied as expressios of the form a + ib where a, b R & i = by i.e. = a + ib. a is called real part of (Re ) ad b is called imagiary part of (Im

More information

MEI STRUCTURED MATHEMATICS FURTHER CONCEPTS FOR ADVANCED MATHEMATICS, FP1. Practice Paper FP1-C

MEI STRUCTURED MATHEMATICS FURTHER CONCEPTS FOR ADVANCED MATHEMATICS, FP1. Practice Paper FP1-C MEI Mathematics i Educatio ad Idustry MEI STRUCTURED MATHEMATICS FURTHER CONCEPTS FOR ADVANCED MATHEMATICS, FP Practice Paper FP-C Additioal materials: Aswer booklet/paper Graph paper MEI Examiatio formulae

More information

Complex Numbers Solutions

Complex Numbers Solutions Complex Numbers Solutios Joseph Zoller February 7, 06 Solutios. (009 AIME I Problem ) There is a complex umber with imagiary part 64 ad a positive iteger such that Fid. [Solutio: 697] 4i + + 4i. 4i 4i

More information

Stanford Math Circle January 21, Complex Numbers

Stanford Math Circle January 21, Complex Numbers Staford Math Circle Jauary, 007 Some History Tatiaa Shubi (shubi@mathsjsuedu) Complex Numbers Let us try to solve the equatio x = 5x + x = is a obvious solutio Also, x 5x = ( x )( x + x + ) = 0 yields

More information

Mathematics Extension 2

Mathematics Extension 2 009 HIGHER SCHOOL CERTIFICATE EXAMINATION Mathematics Etesio Geeral Istructios Readig time 5 miutes Workig time hours Write usig black or blue pe Board-approved calculators may be used A table of stadard

More information

BITSAT MATHEMATICS PAPER III. For the followig liear programmig problem : miimize z = + y subject to the costraits + y, + y 8, y, 0, the solutio is (0, ) ad (, ) (0, ) ad ( /, ) (0, ) ad (, ) (d) (0, )

More information

Chapter 13: Complex Numbers

Chapter 13: Complex Numbers Sectios 13.1 & 13.2 Comple umbers ad comple plae Comple cojugate Modulus of a comple umber 1. Comple umbers Comple umbers are of the form z = + iy,, y R, i 2 = 1. I the above defiitio, is the real part

More information

Assignment ( ) Class-XI. = iii. v. A B= A B '

Assignment ( ) Class-XI. = iii. v. A B= A B ' Assigmet (8-9) Class-XI. Proe that: ( A B)' = A' B ' i A ( BAC) = ( A B) ( A C) ii A ( B C) = ( A B) ( A C) iv. A B= A B= φ v. A B= A B ' v A B B ' A'. A relatio R is dified o the set z of itegers as:

More information

AIEEE 2004 (MATHEMATICS)

AIEEE 2004 (MATHEMATICS) AIEEE 00 (MATHEMATICS) Importat Istructios: i) The test is of hours duratio. ii) The test cosists of 75 questios. iii) The maimum marks are 5. iv) For each correct aswer you will get marks ad for a wrog

More information

WBJEE MATHEMATICS

WBJEE MATHEMATICS WBJEE - 06 MATHEMATICS Q.No. 0 A C B B 0 B B A B 0 C A C C 0 A B C C 05 A A B C 06 B C B C 07 B C A D 08 C C C A 09 D D C C 0 A C A B B C B A A C A B D A A A B B D C 5 B C C C 6 C A B B 7 C A A B 8 C B

More information

SLIP TEST 3 Chapter 2,3 and 6. Part A Answer all the questions Each question carries 1 mark 1 x 1 =1.

SLIP TEST 3 Chapter 2,3 and 6. Part A Answer all the questions Each question carries 1 mark 1 x 1 =1. STD XII TIME 1hr 15 mi SLIP TEST Chapter 2, ad 6 Max.Marks 5 Part A Aswer all the questios Each questio carries 1 mark 1 x 1 =1 1. The equatio of the plae passig through the poit (2, 1, 1) ad the lie of

More information

BRAIN TEASURES TRIGONOMETRICAL RATIOS BY ABHIJIT KUMAR JHA EXERCISE I. or tan &, lie between 0 &, then find the value of tan 2.

BRAIN TEASURES TRIGONOMETRICAL RATIOS BY ABHIJIT KUMAR JHA EXERCISE I. or tan &, lie between 0 &, then find the value of tan 2. EXERCISE I Q Prove that cos² + cos² (+ ) cos cos cos (+ ) ² Q Prove that cos ² + cos (+ ) + cos (+ ) Q Prove that, ta + ta + ta + cot cot Q Prove that : (a) ta 0 ta 0 ta 60 ta 0 (b) ta 9 ta 7 ta 6 + ta

More information

Complex Analysis Spring 2001 Homework I Solution

Complex Analysis Spring 2001 Homework I Solution Complex Aalysis Sprig 2001 Homework I Solutio 1. Coway, Chapter 1, sectio 3, problem 3. Describe the set of poits satisfyig the equatio z a z + a = 2c, where c > 0 ad a R. To begi, we see from the triagle

More information

Patterns in Complex Numbers An analytical paper on the roots of a complex numbers and its geometry

Patterns in Complex Numbers An analytical paper on the roots of a complex numbers and its geometry IB MATHS HL POTFOLIO TYPE Patters i Complex Numbers A aalytical paper o the roots of a complex umbers ad its geometry i Syed Tousif Ahmed Cadidate Sessio Number: 0066-009 School Code: 0066 Sessio: May

More information

4755 Mark Scheme June Question Answer Marks Guidance M1* Attempt to find M or 108M -1 M 108 M1 A1 [6] M1 A1

4755 Mark Scheme June Question Answer Marks Guidance M1* Attempt to find M or 108M -1 M 108 M1 A1 [6] M1 A1 4755 Mark Scheme Jue 05 * Attempt to fid M or 08M - M 08 8 4 * Divide by their determiat,, at some stage Correct determiat, (A0 for det M= 08 stated, all other OR 08 8 4 5 8 7 5 x, y,oe 8 7 4xy 8xy dep*

More information

ANSWERS SOLUTIONS iiii i. and 1. Thus, we have. i i i. i, A.

ANSWERS SOLUTIONS iiii i. and 1. Thus, we have. i i i. i, A. 013 ΜΑΘ Natioal Covetio ANSWERS (1) C A A A B (6) B D D A B (11) C D D A A (16) D B A A C (1) D B C B C (6) D C B C C 1. We have SOLUTIONS 1 3 11 61 iiii 131161 i 013 013, C.. The powers of i cycle betwee

More information

Mathematics Extension 2

Mathematics Extension 2 004 HIGHER SCHOOL CERTIFICATE EXAMINATION Mathematics Etesio Geeral Istructios Readig time 5 miutes Workig time hours Write usig black or blue pe Board-approved calculators may be used A table of stadard

More information

De Moivre s Theorem - ALL

De Moivre s Theorem - ALL De Moivre s Theorem - ALL. Let x ad y be real umbers, ad be oe of the complex solutios of the equatio =. Evaluate: (a) + + ; (b) ( x + y)( x + y). [6]. (a) Sice is a complex umber which satisfies = 0,.

More information

REVISION SHEET FP1 (MEI) ALGEBRA. Identities In mathematics, an identity is a statement which is true for all values of the variables it contains.

REVISION SHEET FP1 (MEI) ALGEBRA. Identities In mathematics, an identity is a statement which is true for all values of the variables it contains. The mai ideas are: Idetities REVISION SHEET FP (MEI) ALGEBRA Before the exam you should kow: If a expressio is a idetity the it is true for all values of the variable it cotais The relatioships betwee

More information

07 - SEQUENCES AND SERIES Page 1 ( Answers at he end of all questions ) b, z = n

07 - SEQUENCES AND SERIES Page 1 ( Answers at he end of all questions ) b, z = n 07 - SEQUENCES AND SERIES Page ( Aswers at he ed of all questios ) ( ) If = a, y = b, z = c, where a, b, c are i A.P. ad = 0 = 0 = 0 l a l

More information

MEI STRUCTURED MATHEMATICS FURTHER CONCEPTS FOR ADVANCED MATHEMATICS, FP1. Practice Paper FP1-B

MEI STRUCTURED MATHEMATICS FURTHER CONCEPTS FOR ADVANCED MATHEMATICS, FP1. Practice Paper FP1-B MEI Mathematics i Educatio ad Idustry MEI STRUCTURED MATHEMATICS FURTHER CONCEPTS FOR ADVANCED MATHEMATICS, FP Practice Paper FP-B Additioal materials: Aswer booklet/paper Graph paper MEI Examiatio formulae

More information

REVISION SHEET FP1 (MEI) ALGEBRA. Identities In mathematics, an identity is a statement which is true for all values of the variables it contains.

REVISION SHEET FP1 (MEI) ALGEBRA. Identities In mathematics, an identity is a statement which is true for all values of the variables it contains. the Further Mathematics etwork wwwfmetworkorguk V 07 The mai ideas are: Idetities REVISION SHEET FP (MEI) ALGEBRA Before the exam you should kow: If a expressio is a idetity the it is true for all values

More information

CARIBBEAN EXAMINATIONS COUNCIL CARIBBEAN SECONDARY EDUCATION EXAMINATION ADDITIONAL MATHEMATICS. Paper 02 - General Proficiency

CARIBBEAN EXAMINATIONS COUNCIL CARIBBEAN SECONDARY EDUCATION EXAMINATION ADDITIONAL MATHEMATICS. Paper 02 - General Proficiency TEST CODE 01254020 FORM TP 2015037 MAY/JUNE 2015 CARIBBEAN EXAMINATIONS COUNCIL CARIBBEAN SECONDARY EDUCATION CERTIFICATE@ EXAMINATION ADDITIONAL MATHEMATICS Paper 02 - Geeral Proficiecy 2 hours 40 miutes

More information

WBJEE Answer Keys by Aakash Institute, Kolkata Centre

WBJEE Answer Keys by Aakash Institute, Kolkata Centre WBJEE - 7 Aswer Keys by, Kolkata Cetre MATHEMATICS Q.No. B A C B A C A B 3 D C B B 4 B C D D 5 D A B B 6 C D B B 7 B C C A 8 B B A A 9 A * B D C C B B D A A D B B C B 3 A D D D 4 C B A A 5 C B B B 6 C

More information

MID-YEAR EXAMINATION 2018 H2 MATHEMATICS 9758/01. Paper 1 JUNE 2018

MID-YEAR EXAMINATION 2018 H2 MATHEMATICS 9758/01. Paper 1 JUNE 2018 MID-YEAR EXAMINATION 08 H MATHEMATICS 9758/0 Paper JUNE 08 Additioal Materials: Writig Paper, MF6 Duratio: hours DO NOT OPEN THIS BOOKLET UNTIL YOU ARE TOLD TO DO SO READ THESE INSTRUCTIONS FIRST Write

More information

2 Geometric interpretation of complex numbers

2 Geometric interpretation of complex numbers 2 Geometric iterpretatio of complex umbers 2.1 Defiitio I will start fially with a precise defiitio, assumig that such mathematical object as vector space R 2 is well familiar to the studets. Recall that

More information

( ) D) E) NOTA

( ) D) E) NOTA 016 MAΘ Natioal Covetio 1. Which Greek mathematicia do most historias credit with the discovery of coic sectios as a solutio to solvig the Delia problem, also kow as doublig the cube? Eratosthees Meaechmus

More information

Log1 Contest Round 1 Theta Equations & Inequalities. 4 points each. 5 points each. 7, a c d. 9, find the value of the product abcd.

Log1 Contest Round 1 Theta Equations & Inequalities. 4 points each. 5 points each. 7, a c d. 9, find the value of the product abcd. 013 01 Log1 Cotest Roud 1 Theta Equatios & Iequalities Name: poits each 1 Solve for x : x 3 38 Fid the greatest itegral value of x satisfyig the iequality x x 3 7 1 3 3 xy71 Fid the ordered pair solutio

More information

Narayana IIT/NEET Academy INDIA IIT_XI-IC_SPARK 2016_P1 Date: Max.Marks: 186

Narayana IIT/NEET Academy INDIA IIT_XI-IC_SPARK 2016_P1 Date: Max.Marks: 186 Narayaa IIT/NEET Academy INDIA IIT_XI-IC_SPARK 6_P Date: 5--8 Max.Marks: 86 KEY SHEET PHYSICS B B c 4 B 5 c 6 ac 7 ac 8 ac 9 ad abc bc acd ad 4 5 6 6 7 6 8 4 CHEMISTRY 9 c b c a a 4 bc 5 ab 6 abcd 7 ab

More information

+ {JEE Advace 03} Sept 0 Name: Batch (Day) Phoe No. IT IS NOT ENOUGH TO HAVE A GOOD MIND, THE MAIN THING IS TO USE IT WELL Marks: 00. If A (α, β) = (a) A( α, β) = A( α, β) (c) Adj (A ( α, β)) = Sol : We

More information

MATHEMATICS Code No. 13 INSTRUCTIONS

MATHEMATICS Code No. 13 INSTRUCTIONS DO NOT OPEN THIS TEST BOOKLET UNTIL YOU ARE ASKED TO DO SO COMBINED COMPETITIVE (PRELIMINARY) EXAMINATION, 0 Serial No. MATHEMATICS Code No. A Time Allowed : Two Hours Maimum Marks : 00 INSTRUCTIONS. IMMEDIATELY

More information

Section 1.1. Calculus: Areas And Tangents. Difference Equations to Differential Equations

Section 1.1. Calculus: Areas And Tangents. Difference Equations to Differential Equations Differece Equatios to Differetial Equatios Sectio. Calculus: Areas Ad Tagets The study of calculus begis with questios about chage. What happes to the velocity of a swigig pedulum as its positio chages?

More information

Review Problems Math 122 Midterm Exam Midterm covers App. G, B, H1, H2, Sec , 8.9,

Review Problems Math 122 Midterm Exam Midterm covers App. G, B, H1, H2, Sec , 8.9, Review Problems Math Midterm Exam Midterm covers App. G, B, H, H, Sec 8. - 8.7, 8.9, 9.-9.7 Review the Cocept Check problems: Page 6/ -, Page 690/- 0 PART I: True-False Problems Ch. 8. Page 6 True-False

More information

APPENDIX F Complex Numbers

APPENDIX F Complex Numbers APPENDIX F Complex Numbers Operatios with Complex Numbers Complex Solutios of Quadratic Equatios Polar Form of a Complex Number Powers ad Roots of Complex Numbers Operatios with Complex Numbers Some equatios

More information

Complex Numbers. Brief Notes. z = a + bi

Complex Numbers. Brief Notes. z = a + bi Defiitios Complex Numbers Brief Notes A complex umber z is a expressio of the form: z = a + bi where a ad b are real umbers ad i is thought of as 1. We call a the real part of z, writte Re(z), ad b the

More information

Calculus. Ramanasri. Previous year Questions from 2016 to

Calculus. Ramanasri. Previous year Questions from 2016 to ++++++++++ Calculus Previous ear Questios from 6 to 99 Ramaasri 7 S H O P NO- 4, S T F L O O R, N E A R R A P I D F L O U R M I L L S, O L D R A J E N D E R N A G A R, N E W D E L H I. W E B S I T E :

More information

Solutions for May. 3 x + 7 = 4 x x +

Solutions for May. 3 x + 7 = 4 x x + Solutios for May 493. Prove that there is a atural umber with the followig characteristics: a) it is a multiple of 007; b) the first four digits i its decimal represetatio are 009; c) the last four digits

More information

MATHEMATICS. 61. The differential equation representing the family of curves where c is a positive parameter, is of

MATHEMATICS. 61. The differential equation representing the family of curves where c is a positive parameter, is of MATHEMATICS 6 The differetial equatio represetig the family of curves where c is a positive parameter, is of Order Order Degree (d) Degree (a,c) Give curve is y c ( c) Differetiate wrt, y c c y Hece differetial

More information

05 - PERMUTATIONS AND COMBINATIONS Page 1 ( Answers at the end of all questions )

05 - PERMUTATIONS AND COMBINATIONS Page 1 ( Answers at the end of all questions ) 05 - PERMUTATIONS AND COMBINATIONS Page 1 ( Aswers at the ed of all questios ) ( 1 ) If the letters of the word SACHIN are arraged i all possible ways ad these words are writte out as i dictioary, the

More information

CALCULUS BASIC SUMMER REVIEW

CALCULUS BASIC SUMMER REVIEW CALCULUS BASIC SUMMER REVIEW NAME rise y y y Slope of a o vertical lie: m ru Poit Slope Equatio: y y m( ) The slope is m ad a poit o your lie is, ). ( y Slope-Itercept Equatio: y m b slope= m y-itercept=

More information

Math 210A Homework 1

Math 210A Homework 1 Math 0A Homework Edward Burkard Exercise. a) State the defiitio of a aalytic fuctio. b) What are the relatioships betwee aalytic fuctios ad the Cauchy-Riema equatios? Solutio. a) A fuctio f : G C is called

More information

Objective Mathematics

Objective Mathematics . If sum of '' terms of a sequece is give by S Tr ( )( ), the 4 5 67 r (d) 4 9 r is equal to : T. Let a, b, c be distict o-zero real umbers such that a, b, c are i harmoic progressio ad a, b, c are i arithmetic

More information

EXERCISE - 01 CHECK YOUR GRASP

EXERCISE - 01 CHECK YOUR GRASP J-Mathematics XRCIS - 0 CHCK YOUR GRASP SLCT TH CORRCT ALTRNATIV (ONLY ON CORRCT ANSWR). The maximum value of the sum of the A.P. 0, 8, 6,,... is - 68 60 6. Let T r be the r th term of a A.P. for r =,,,...

More information

Poornima University, For any query, contact us at: ,18

Poornima University, For any query, contact us at: ,18 AIEEE/1/MAHS 1 S. No Questios Solutios Q.1 he circle passig through (1, ) ad touchig the axis of x at (, ) also passes through the poit (a) (, ) (b) (, ) (c) (, ) (d) (, ) Q. ABCD is a trapezium such that

More information

The Advantage Testing Foundation Solutions

The Advantage Testing Foundation Solutions The Advatage Testig Foudatio 202 Problem I the morig, Esther biked from home to school at a average speed of x miles per hour. I the afteroo, havig let her bike to a fried, Esther walked back home alog

More information

C. Complex Numbers. x 6x + 2 = 0. This equation was known to have three real roots, given by simple combinations of the expressions

C. Complex Numbers. x 6x + 2 = 0. This equation was known to have three real roots, given by simple combinations of the expressions C. Complex Numbers. Complex arithmetic. Most people thik that complex umbers arose from attempts to solve quadratic equatios, but actually it was i coectio with cubic equatios they first appeared. Everyoe

More information

PHYSICS 116A Homework 2 Solutions

PHYSICS 116A Homework 2 Solutions PHYSICS 6A Homework 2 Solutios I. [optioal] Boas, Ch., 6, Qu. 30 (proof of the ratio test). Just follow the hits. If ρ, the ratio of succcessive terms for is less tha, the hits show that the terms of the

More information

Q.11 If S be the sum, P the product & R the sum of the reciprocals of a GP, find the value of

Q.11 If S be the sum, P the product & R the sum of the reciprocals of a GP, find the value of Brai Teasures Progressio ad Series By Abhijit kumar Jha EXERCISE I Q If the 0th term of a HP is & st term of the same HP is 0, the fid the 0 th term Q ( ) Show that l (4 36 08 up to terms) = l + l 3 Q3

More information

Math 5C Discussion Problems 2

Math 5C Discussion Problems 2 Math iscussio Problems Path Idepedece. Let be the striaght-lie path i R from the origi to (3, ). efie f(x, y) = xye xy. (a) Evaluate f dr. (b) Evaluate ((, 0) + f) dr. (c) Evaluate ((y, 0) + f) dr.. Let

More information

SS3 QUESTIONS FOR 2018 MATHSCHAMP. 3. How many vertices has a hexagonal prism? A. 6 B. 8 C. 10 D. 12

SS3 QUESTIONS FOR 2018 MATHSCHAMP. 3. How many vertices has a hexagonal prism? A. 6 B. 8 C. 10 D. 12 SS3 QUESTIONS FOR 8 MATHSCHAMP. P ad Q are two matrices such that their dimesios are 3 by 4 ad 4 by 3 respectively. What is the dimesio of the product PQ? 3 by 3 4 by 4 3 by 4 4 by 3. What is the smallest

More information

MTH Assignment 1 : Real Numbers, Sequences

MTH Assignment 1 : Real Numbers, Sequences MTH -26 Assigmet : Real Numbers, Sequeces. Fid the supremum of the set { m m+ : N, m Z}. 2. Let A be a o-empty subset of R ad α R. Show that α = supa if ad oly if α is ot a upper boud of A but α + is a

More information

Chapter 1. Complex Numbers. Dr. Pulak Sahoo

Chapter 1. Complex Numbers. Dr. Pulak Sahoo Chapter 1 Complex Numbers BY Dr. Pulak Sahoo Assistat Professor Departmet of Mathematics Uiversity Of Kalyai West Begal, Idia E-mail : sahoopulak1@gmail.com 1 Module-2: Stereographic Projectio 1 Euler

More information

Substitute these values into the first equation to get ( z + 6) + ( z + 3) + z = 27. Then solve to get

Substitute these values into the first equation to get ( z + 6) + ( z + 3) + z = 27. Then solve to get Problem ) The sum of three umbers is 7. The largest mius the smallest is 6. The secod largest mius the smallest is. What are the three umbers? [Problem submitted by Vi Lee, LCC Professor of Mathematics.

More information

Simple Polygons of Maximum Perimeter Contained in a Unit Disk

Simple Polygons of Maximum Perimeter Contained in a Unit Disk Discrete Comput Geom (009) 1: 08 15 DOI 10.1007/s005-008-9093-7 Simple Polygos of Maximum Perimeter Cotaied i a Uit Disk Charles Audet Pierre Hase Frédéric Messie Received: 18 September 007 / Revised:

More information

CET MOCK TEST If a,b,c are p, q and r terms repectively of a G.P., then (q-r)loga+(r-p)logb+(p-q)logc= a)0 b) 1 c)-1 d)abc

CET MOCK TEST If a,b,c are p, q and r terms repectively of a G.P., then (q-r)loga+(r-p)logb+(p-q)logc= a)0 b) 1 c)-1 d)abc CET MOCK TEST 5 SUB:MATHEMATICS MARKS:60 TOTAL DURATION MARKS FOR ASWERING:70MINUTES th th th 0. If a,b,c are p, q ad r terms repectively of a G.P., the (q-r)loga+(r-p)logb+(p-q)logc= a)0 b) c)- d)abc

More information

NATIONAL SENIOR CERTIFICATE GRADE 12

NATIONAL SENIOR CERTIFICATE GRADE 12 NAIONAL SENI CERIFICAE GRADE MAHEMAICS P NOVEMBER 00 MEMANDUM MARKS: 50 his memoradum cosists of 7 pages. Mathematics/P DoE/November 00 QUESION.. x ( x 4) 5.... x 4x 5 0 ( x 5)( x + ) 0 x 5 or x 4x 0x

More information

Friday 20 May 2016 Morning

Friday 20 May 2016 Morning Oxford Cambridge ad RSA Friday 0 May 06 Morig AS GCE MATHEMATICS (MEI) 4755/0 Further Cocepts for Advaced Mathematics (FP) QUESTION PAPER * 6 8 6 6 9 5 4 * Cadidates aswer o the Prited Aswer Boo. OCR supplied

More information

Appendix F: Complex Numbers

Appendix F: Complex Numbers Appedix F Complex Numbers F1 Appedix F: Complex Numbers Use the imagiary uit i to write complex umbers, ad to add, subtract, ad multiply complex umbers. Fid complex solutios of quadratic equatios. Write

More information

MEI Conference 2009 Stretching students: A2 Core

MEI Conference 2009 Stretching students: A2 Core MEI Coferece 009 Stretchig studets: A Core Preseter: Berard Murph berard.murph@mei.org.uk Workshop G How ca ou prove that these si right-agled triagles fit together eactl to make a 3-4-5 triagle? What

More information

MATH spring 2008 lecture 3 Answers to selected problems. 0 sin14 xdx = x dx. ; (iv) x +

MATH spring 2008 lecture 3 Answers to selected problems. 0 sin14 xdx = x dx. ; (iv) x + MATH - sprig 008 lecture Aswers to selected problems INTEGRALS. f =? For atiderivatives i geeral see the itegrals website at http://itegrals.wolfram.com. (5-vi (0 i ( ( i ( π ; (v π a. This is example

More information

6.003 Homework #3 Solutions

6.003 Homework #3 Solutions 6.00 Homework # Solutios Problems. Complex umbers a. Evaluate the real ad imagiary parts of j j. π/ Real part = Imagiary part = 0 e Euler s formula says that j = e jπ/, so jπ/ j π/ j j = e = e. Thus the

More information

VITEEE 2018 MATHEMATICS QUESTION BANK

VITEEE 2018 MATHEMATICS QUESTION BANK VITEEE 8 MTHEMTICS QUESTION BNK, C = {,, 6}, the (B C) Ques. Give the sets {,,},B {, } is {} {,,, } {,,, } {,,,,, 6} Ques. s. d ( si cos ) c ta log( ta 6 Ques. The greatest umer amog 9,, 7 is ) c c cot

More information

TEAM RELAYS MU ALPHA THETA STATE 2009 ROUND NAMES THETA

TEAM RELAYS MU ALPHA THETA STATE 2009 ROUND NAMES THETA TEAM RELAYS MU ALPHA THETA STATE 009 ROUND SCHOOL NAMES THETA ALPHA MU What is the product of 3 ad 7? Roud ) 98 Richard s age is curretly twice Brya s age. Twelve years ago, Richard s age was three times

More information

GULF MATHEMATICS OLYMPIAD 2014 CLASS : XII

GULF MATHEMATICS OLYMPIAD 2014 CLASS : XII GULF MATHEMATICS OLYMPIAD 04 CLASS : XII Date of Eamiatio: Maimum Marks : 50 Time : 0:30 a.m. to :30 p.m. Duratio: Hours Istructios to cadidates. This questio paper cosists of 50 questios. All questios

More information

Coffee Hour Problems of the Week (solutions)

Coffee Hour Problems of the Week (solutions) Coffee Hour Problems of the Week (solutios) Edited by Matthew McMulle Otterbei Uiversity Fall 0 Week. Proposed by Matthew McMulle. A regular hexago with area 3 is iscribed i a circle. Fid the area of a

More information

Objective Mathematics

Objective Mathematics -0 {Mais & Advace} B.E.(CIVIL), MNIT,JAIPUR(Rajastha) Copyright L.K.Sharma 0. Er. L.K.Sharma a egieerig graduate from NIT, Jaipur (Rajastha), {Gold medalist, Uiversity of Rajastha} is a well kow ame amog

More information

Assignment 1 : Real Numbers, Sequences. for n 1. Show that (x n ) converges. Further, by observing that x n+2 + x n+1

Assignment 1 : Real Numbers, Sequences. for n 1. Show that (x n ) converges. Further, by observing that x n+2 + x n+1 Assigmet : Real Numbers, Sequeces. Let A be a o-empty subset of R ad α R. Show that α = supa if ad oly if α is ot a upper boud of A but α + is a upper boud of A for every N. 2. Let y (, ) ad x (, ). Evaluate

More information

PAPER : IIT-JAM 2010

PAPER : IIT-JAM 2010 MATHEMATICS-MA (CODE A) Q.-Q.5: Oly oe optio is correct for each questio. Each questio carries (+6) marks for correct aswer ad ( ) marks for icorrect aswer.. Which of the followig coditios does NOT esure

More information

UNIVERSITY OF NORTHERN COLORADO MATHEMATICS CONTEST. First Round For all Colorado Students Grades 7-12 November 3, 2007

UNIVERSITY OF NORTHERN COLORADO MATHEMATICS CONTEST. First Round For all Colorado Students Grades 7-12 November 3, 2007 UNIVERSITY OF NORTHERN COLORADO MATHEMATICS CONTEST First Roud For all Colorado Studets Grades 7- November, 7 The positive itegers are,,, 4, 5, 6, 7, 8, 9,,,,. The Pythagorea Theorem says that a + b =

More information

NBHM QUESTION 2007 Section 1 : Algebra Q1. Let G be a group of order n. Which of the following conditions imply that G is abelian?

NBHM QUESTION 2007 Section 1 : Algebra Q1. Let G be a group of order n. Which of the following conditions imply that G is abelian? NBHM QUESTION 7 NBHM QUESTION 7 NBHM QUESTION 7 Sectio : Algebra Q Let G be a group of order Which of the followig coditios imply that G is abelia? 5 36 Q Which of the followig subgroups are ecesarily

More information

CATHOLIC JUNIOR COLLEGE General Certificate of Education Advanced Level Higher 2 JC2 Preliminary Examination MATHEMATICS 9740/01

CATHOLIC JUNIOR COLLEGE General Certificate of Education Advanced Level Higher 2 JC2 Preliminary Examination MATHEMATICS 9740/01 CATHOLIC JUNIOR COLLEGE Geeral Certificate of Educatio Advaced Level Higher JC Prelimiary Examiatio MATHEMATICS 9740/0 Paper 4 Aug 06 hours Additioal Materials: List of Formulae (MF5) Name: Class: READ

More information

MOCK TEST - 02 COMMON ENTRANCE TEST 2012 SUBJECT: MATHEMATICS Time: 1.10Hrs Max. Marks 60 Questions 60. then x 2 =

MOCK TEST - 02 COMMON ENTRANCE TEST 2012 SUBJECT: MATHEMATICS Time: 1.10Hrs Max. Marks 60 Questions 60. then x 2 = MOCK TEST - 0 COMMON ENTRANCE TEST 0 SUBJECT: MATHEMATICS Time:.0Hrs Max. Marks 60 Questios 60. The value of si cot si 3 cos sec + + 4 4 a) 0 b) c) 4 6 + x x. If Ta - α + x + x the x a) cos α b) Taα c)

More information

PUTNAM TRAINING, 2008 COMPLEX NUMBERS

PUTNAM TRAINING, 2008 COMPLEX NUMBERS PUTNAM TRAINING, 008 COMPLEX NUMBERS (Last updated: December 11, 017) Remark. This is a list of exercises o Complex Numbers Miguel A. Lerma Exercises 1. Let m ad two itegers such that each ca be expressed

More information

Regn. No. North Delhi : 33-35, Mall Road, G.T.B. Nagar (Opp. Metro Gate No. 3), Delhi-09, Ph: ,

Regn. No. North Delhi : 33-35, Mall Road, G.T.B. Nagar (Opp. Metro Gate No. 3), Delhi-09, Ph: , . Sectio-A cotais 30 Multiple Choice Questios (MCQ). Each questio has 4 choices (a), (b), (c) ad (d), for its aswer, out of which ONLY ONE is correct. From Q. to Q.0 carries Marks ad Q. to Q.30 carries

More information

THE ASSOCIATION OF MATHEMATICS TEACHERS OF INDIA Screening Test - Bhaskara Contest (NMTC at JUNIOR LEVEL IX & X Standards) Saturday, 27th August 2016.

THE ASSOCIATION OF MATHEMATICS TEACHERS OF INDIA Screening Test - Bhaskara Contest (NMTC at JUNIOR LEVEL IX & X Standards) Saturday, 27th August 2016. THE ASSOCIATION OF MATHEMATICS TEACHERS OF INDIA Screeig Test - Bhaskara Cotest (NMTC at JUNIOR LEVEL I & Stadards) Saturday, 7th August 06. Note : Note : () Fill i the respose sheet with your Name, Class,

More information

GRADE 12 JUNE 2016 MATHEMATICS P2

GRADE 12 JUNE 2016 MATHEMATICS P2 NATIONAL SENIOR CERTIFICATE GRADE 1 JUNE 016 MATHEMATICS P MARKS: 150 TIME: 3 hours *MATHE* This questio paper cosists of 11 pages, icludig 1 iformatio sheet, ad a SPECIAL ANSWER BOOK. MATHEMATICS P (EC/JUNE

More information

NATIONAL SENIOR CERTIFICATE GRADE 12

NATIONAL SENIOR CERTIFICATE GRADE 12 NATIONAL SENIOR CERTIFICATE GRADE 1 MATHEMATICS P SEPTEMBER 016 MARKS: 150 TIME: 3 hours This questio paper cosists of 13 pages, 1 iformatio sheet ad a aswer book. INSTRUCTIONS AND INFORMATION Read the

More information

3. Z Transform. Recall that the Fourier transform (FT) of a DT signal xn [ ] is ( ) [ ] = In order for the FT to exist in the finite magnitude sense,

3. Z Transform. Recall that the Fourier transform (FT) of a DT signal xn [ ] is ( ) [ ] = In order for the FT to exist in the finite magnitude sense, 3. Z Trasform Referece: Etire Chapter 3 of text. Recall that the Fourier trasform (FT) of a DT sigal x [ ] is ω ( ) [ ] X e = j jω k = xe I order for the FT to exist i the fiite magitude sese, S = x [

More information

JEE ADVANCED 2013 PAPER 1 MATHEMATICS

JEE ADVANCED 2013 PAPER 1 MATHEMATICS Oly Oe Optio Correct Type JEE ADVANCED 0 PAPER MATHEMATICS This sectio cotais TEN questios. Each has FOUR optios (A), (B), (C) ad (D) out of which ONLY ONE is correct.. The value of (A) 5 (C) 4 cot cot

More information

2) 3 π. EAMCET Maths Practice Questions Examples with hints and short cuts from few important chapters

2) 3 π. EAMCET Maths Practice Questions Examples with hints and short cuts from few important chapters EAMCET Maths Practice Questios Examples with hits ad short cuts from few importat chapters. If the vectors pi j + 5k, i qj + 5k are colliear the (p,q) ) 0 ) 3) 4) Hit : p 5 p, q q 5.If the vectors i j

More information

RADICAL EXPRESSION. If a and x are real numbers and n is a positive integer, then x is an. n th root theorems: Example 1 Simplify

RADICAL EXPRESSION. If a and x are real numbers and n is a positive integer, then x is an. n th root theorems: Example 1 Simplify Example 1 Simplify 1.2A Radical Operatios a) 4 2 b) 16 1 2 c) 16 d) 2 e) 8 1 f) 8 What is the relatioship betwee a, b, c? What is the relatioship betwee d, e, f? If x = a, the x = = th root theorems: RADICAL

More information

1. Complex numbers. Chapter 13: Complex Numbers. Modulus of a complex number. Complex conjugate. Complex numbers are of the form

1. Complex numbers. Chapter 13: Complex Numbers. Modulus of a complex number. Complex conjugate. Complex numbers are of the form Comple umbers ad comple plae Comple cojugate Modulus of a comple umber Comple umbers Comple umbers are of the form Sectios 3 & 32 z = + i,, R, i 2 = I the above defiitio, is the real part of z ad is the

More information

3 Show in each case that there is a root of the given equation in the given interval. a x 3 = 12 4

3 Show in each case that there is a root of the given equation in the given interval. a x 3 = 12 4 C Worksheet A Show i each case that there is a root of the equatio f() = 0 i the give iterval a f() = + 7 (, ) f() = 5 cos (05, ) c f() = e + + 5 ( 6, 5) d f() = 4 5 + (, ) e f() = l (4 ) + (04, 05) f

More information

Representing transformations by matrices

Representing transformations by matrices Teachig Further Mathematics FP Give each pair of studets a copy of the sheet below elarged oto A. Represetig trasformatios by matrices Studets have to multiply the matri by the positio vector of each verte

More information

This paper consists of 10 pages with 10 questions. All the necessary working details must be shown.

This paper consists of 10 pages with 10 questions. All the necessary working details must be shown. Mathematics - HG Mar 003 Natioal Paper INSTRUCTIONS.. 3. 4. 5. 6. 7. 8. 9. This paper cosists of 0 pages with 0 questios. A formula sheet is icluded o page 0 i the questio paper. Detach it ad use it to

More information

PAIR OF STRAIGHT LINES.

PAIR OF STRAIGHT LINES. PAIR OF STRAIGHT LINES PREVIOUS EAMCET BITS 1. The value of λ with λ < 16 suh that x 1xy + 1y + 5x + λy 3 = represets a pair of straight lies, is [EAMCET 9] 1) 1 ) 9 3) 1 4)9 As: Sol. Δ= λ= 9. The area

More information

A Recurrence Formula for Packing Hyper-Spheres

A Recurrence Formula for Packing Hyper-Spheres A Recurrece Formula for Packig Hyper-Spheres DokeyFt. Itroductio We cosider packig of -D hyper-spheres of uit diameter aroud a similar sphere. The kissig spheres ad the kerel sphere form cells of equilateral

More information

SAFE HANDS & IIT-ian's PACE EDT-10 (JEE) SOLUTIONS

SAFE HANDS & IIT-ian's PACE EDT-10 (JEE) SOLUTIONS . If their mea positios coicide with each other, maimum separatio will be A. Now from phasor diagram, we ca clearly see the phase differece. SAFE HANDS & IIT-ia's PACE ad Aswer : Optio (4) 5. Aswer : Optio

More information

MAT 271 Project: Partial Fractions for certain rational functions

MAT 271 Project: Partial Fractions for certain rational functions MAT 7 Project: Partial Fractios for certai ratioal fuctios Prerequisite kowledge: partial fractios from MAT 7, a very good commad of factorig ad complex umbers from Precalculus. To complete this project,

More information

IYGB. Special Extension Paper E. Time: 3 hours 30 minutes. Created by T. Madas. Created by T. Madas

IYGB. Special Extension Paper E. Time: 3 hours 30 minutes. Created by T. Madas. Created by T. Madas YGB Special Extesio Paper E Time: 3 hours 30 miutes Cadidates may NOT use ay calculator. formatio for Cadidates This practice paper follows the Advaced Level Mathematics Core ad the Advaced Level Further

More information

Analytic Continuation

Analytic Continuation Aalytic Cotiuatio The stadard example of this is give by Example Let h (z) = 1 + z + z 2 + z 3 +... kow to coverge oly for z < 1. I fact h (z) = 1/ (1 z) for such z. Yet H (z) = 1/ (1 z) is defied for

More information

TEACHER CERTIFICATION STUDY GUIDE

TEACHER CERTIFICATION STUDY GUIDE COMPETENCY 1. ALGEBRA SKILL 1.1 1.1a. ALGEBRAIC STRUCTURES Kow why the real ad complex umbers are each a field, ad that particular rigs are ot fields (e.g., itegers, polyomial rigs, matrix rigs) Algebra

More information

Padasalai.net Special- Centum Coaching Team. Question Paper

Padasalai.net Special- Centum Coaching Team. Question Paper Padasalai.et Special- Cetum Coachig Team Questio Paper 7-8 (7-8) PART III MATHEMATICS Xll std ( ENGLISH VERSION) TIME ALLOWED: 3 HRS MAXIMUM MARKS: INSTRUCTIONS : ) Check the questio paper for fairess

More information

Lecture 7: Polar representation of complex numbers

Lecture 7: Polar representation of complex numbers Lecture 7: Polar represetatio of comple umbers See FLAP Module M3.1 Sectio.7 ad M3. Sectios 1 ad. 7.1 The Argad diagram I two dimesioal Cartesia coordiates (,), we are used to plottig the fuctio ( ) with

More information

EdExcel Further Pure 2

EdExcel Further Pure 2 EdExcel Further Pure 2 Complex Numbers Section : Loci in the Argand diagram Multiple Choice Test Questions 1 are about the following loci: P: z i = 2 Q: z i = z R: arg( z i) = S: z i = 2 z 1) Which of

More information