Q.11 If S be the sum, P the product & R the sum of the reciprocals of a GP, find the value of

Size: px
Start display at page:

Download "Q.11 If S be the sum, P the product & R the sum of the reciprocals of a GP, find the value of"

Transcription

1 Brai Teasures Progressio ad Series By Abhijit kumar Jha EXERCISE I Q If the 0th term of a HP is & st term of the same HP is 0, the fid the 0 th term Q ( ) Show that l ( up to terms) = l + l 3 Q3 There are AM s betwee & 3 such that 7th mea : ( ) th mea = 5 : 9, the fid the value of Q4 Fid the sum of the series, to terms Q5 Express the recurrig decimal 0576 as a ratioal umber usig cocept of ifiite geometric series Q6 Fid the sum of the terms of the sequece Q7 The first term of a arithmetic progressio is ad the sum of the first ie terms equal to 369 The first ad the ith term of a geometric progressio coicide with the first ad the ith term of the arithmetic progressio Fid the seveth term of the geometric progressio Q8 If the p th, q th & r th terms of a AP are i GP Show that the commo ratio of the GP is q r p q Q9 If oe AM a & two GM s p & q be iserted betwee ay two give umbers the show that p 3 + q 3 = apq Q0 The sum of terms of two arithmetic series are i the ratio of (7 + ) : (4 + 7) Fid the ratio of their th term Q If S be the sum, P the product & R the sum of the reciprocals of a GP, fid the value of R P S Q The first ad last terms of a AP are a ad b There are altogether ( + ) terms A ew series is formed by multiplyig each of the first terms by the ext term Show that the sum of the ew series is (4 )(a b ) (4 )ab 6 Q3 I a AP of which a is the Ist term, if the sum of the Ist p terms is equal to zero, show that the sum of the ext q terms is a (p + q) q/(p ) Q4(a) The iterior agles of a polygo are i AP The smallest agle is 0 & the commo differece is 5 Fid the umber of sides of the polygo The iterior agles of a covex polygo form a arithmetic progressio with a commo differece of 4 Determie the umber of sides of the polygo if its largest iterior agle is 7 Q5 A AP & a HP have the same first term, the same last term & the same umber of terms ; prove that the product of the r th term from the begiig i oe series & the r th term from the ed i the other is idepedet of r Q6 Fid three umbers a, b, c betwee & 8 such that ; (i) their sum is 5 (ii) the umbers, a, b are cosecutive terms of a AP & (iii) the umbers b, c, 8 are cosecutive terms of a GP Q7 Give that a x = b y = c z = d u & a, b, c, d are i GP, show that x, y, z, u are i HP Q8 I a set of four umbers, the first three are i GP & the last three are i AP, with commo differece 6 If the first umber is the same as the fourth, fid the four umbers

2 Brai Teasures Progressio ad Series By Abhijit kumar Jha 3 Q9 Fid the sum of the first terms of the sequece : 3 4 Q0 Fid the th term ad the sum to terms of the sequece : (i) (ii) Q The AM of two umbers exceeds their GM by 5 & HM by 7 Fid the umbers Q The harmoic mea of two umbers is 4 The airthmetic mea A & the geometric mea G satisfy the relatio A + G² = 7 Fid the two umbers Q3 Sum the followig series to terms ad to ifiity : (i) (iii) (ii) r 4 r Q4 Fid the value of the sum (a) r s i i j k r r (r + ) (r + ) (r + 3) 3 35 (iv) rs r 3 s where rs is zero if r s & rs is oe if r = s j Q5 For or 0 < < /, if : x = 0 cos, y = (i) xyz = xy + z 0 si, z = 0 (ii) xyz = x + y + z cos si the : Prove that EXERCISE II Q The series of atural umbers is divided ito groups (), (, 3, 4), (5, 6, 7, 8, 9), & so o Show that the sum of the umbers i the th group is ( ) Q The sum of the squares of three distict real umbers, which are i GP is S² If their sum is S, show that ² (/3, ) (, 3) Q3 If there be m AP s begiig with uity whose commo differece is,, 3 m Show that the sum of their th terms is (m/) (m m + + ) Q4 If S represets the sum to terms of a GP whose first term & commo ratio are a & r respectively, the prove that S + S 3 + S S - = a r a r r ( ) ( r) ( r) Q5 A geometrical & harmoic progressio have the same p th, q th & r th terms a, b, c respectively Show that a (b c) log a + b (c a) log b + c (a b) log c = 0 Q6 A computer solved several problems i successio The time it took the computer to solve each successive problem was the same umber of times smaller tha the time it took to solve the precedig problem How may problems were suggested to the computer if it spet 635 mi to solve all the problems except for the first, 7 mi to solve all the problems except for the last oe, ad 35 mi to solve all the problems except for the first two? Q7 If the sum of m terms of a AP is equal to the sum of either the ext terms or the ext p terms of the same AP prove that (m + ) [(/m) (/p)] = (m + p) [(/m) (/)] ( p)

3 Brai Teasures Progressio ad Series By Abhijit kumar Jha Q8 If the roots of 0x 3 cx 54x 7 = 0 are i harmoic progressio, the fid c & all the roots Q9(a) Let a, a a be a AP Prove that : = a a a a a a a a 3 a a a a a 3 a Show that i ay arithmetic progressio a, a a ² a ² + a 3 ² a 4 ² + + a² K a² K = [K/( K )] (a ² a² K ) Q0 Let a, a,, a, a +, be a AP Let S = a + a + a a S = a + + a a S 3 = a + + a a 3 Prove that the sequece S, S, S 3, is a arithmetic progressio whose commo differece is times the commo differece of the give progressio Q If a, b, c are i HP, b, c, d are i GP & c, d, e are i AP, Show that e = ab²/(a b)² Q If a, b, c, d, e be 5 umbers such that a, b, c are i AP ; b, c, d are i GP & c, d, e are i HP the: (i) Prove that a, c, e are i GP (ii) Prove that e = ( b a)²/a (iii) If a = & e = 8, fid all possible values of b, c, d Q3 The sequece a, a, a 98 satisfies the relatio a + = a + for =,, 3, 97 ad has the sum equal to 4949 Evaluate a k 49 k Q4 If is a root of the equatio x² ( ac) x (a² + c²) ( + ac) = 0 & if HM s are iserted betwee a & c, show that the differece betwee the first & the last mea is equal to ac(a c) Q5 (a) The value of x + y + z is 5 if a, x, y, z, b are i AP while the value of ; (/x)+(/y)+(/z) is 5/3 if a, x, y, z, b are i HP Fid a & b The values of xyz is 5/ or 8/5 accordig as the series a, x, y, z, b is a AP or HP Fid the values of a & b assumig them to be positive iteger Q6 A AP, a GP & a HP have a & b for their first two terms Show that their ( + ) th terms will be i GP if b ba a b a Q7 Prove that the sum of the ifiite series Q8 If there are quatities i GP with commo ratio r & S m deotes the sum of the first m terms, show that the sum of the products of these m terms take two & two together is [r/(r + )] [S m ] [S m ]

4 Brai Teasures Progressio ad Series By Abhijit kumar Jha Q9 Fid the coditio that the roots of the equatio x 3 px + qx r = 0 may be i AP ad hece solve the equatio x 3 x + 39x 8 = 0 Q0 If ax + bx + c = 0 & a x + b x + c = 0 have a commo root & a/a, b/b, c/c are i AP, show that a, b & c are i GP Q If a, b, c be i GP & log c a, log b c, log a b be i AP, the show that the commo differece of the AP must be 3/ Q If a = & for >, a = a - + Q3 Sum to terms : (i) (ii) a, the show that < a 75 < 5 x 3x x ( x ) ( x ) ( x ) ( x ) ( x 3) a a a 3 a a a a a a 3 Q4 I a GP the ratio of the sum of the first eleve terms to the sum of the last eleve terms is /8 ad the ratio of the sum of all the terms without the first ie to the sum of all the terms without the last ie is Fid the umber of terms i the GP Q5 Give a three digit umber whose digits are three successive terms of a GP If we subtract 79 from it, we get a umber writte by the same digits i the reverse order Now if we subtract four from the hudred's digit of the iitial umber ad leave the other digits uchaged, we get a umber whose digits are successive terms of a AP Fid the umber EXERCISE III Q For ay odd iteger, 3 ( ) ( ) l 3 = [ JEE 96, ] Q x = + 3a + 6a² + 0a 3 + a < y = + 4b + 0b² + 0b 3 + b <, fid S = + 3ab + 5(ab)² + i terms of x & y [ REE 96, 6 ] Q3 The real umbers x, x, x 3 satisfyig the equatio x 3 x² + x + = 0 are i AP Fid the itervals i which ad lie [JEE 96, 3] Q4 Let p & q be roots of the equatio x x + A = 0, ad let r & s be the roots of the equatio x 8x + B = 0 If p < q < r < s are i arithmatic progressio, the A =, ad B = [ JEE 97, ] Q5 a, b, c are the first three terms of a geometric series If the harmoic mea of a & b is ad that of b & c is 36, fid the first five terms of the series [ REE '98, 6 ] Q6 Select the correct alterative(s) [ JEE '98, ] (a) Let T r be the r th term of a AP, for r =,, 3, If for some positive itegers m, we have T m = & T = m, the T m equals : (A) m (B) (C) (D) 0 m If x =, y >, z > are i GP, the x, y, are i : z (A) AP (B) HP (C) GP (D) oe of the above (c) Prove that a triagle ABC is equilateral if & oly if ta A + ta B + ta C = 3 3

5 Brai Teasures Progressio ad Series By Abhijit kumar Jha Q7(a) The harmoic mea of the roots of the equatio 5 x 4 5 x = 0 is (A) (B) 4 (C) 6 (D) 8 Let a, a,, a 0, be i AP & h, h,, h 0 be i HP If a = h = & a 0 = h 0 = 3 the a 4 h 7 is: (A) (B) 3 (C) 5 (D) 6 [ JEE '99, + out of 00 ] Q8 The sum of a ifiite geometric series is 6 ad the sum of its first terms is 60 If the iverse of its commo ratio is a iteger, fid all possible values of the commo ratio, ad the first terms of the series [ REE '99, 6 ] Q9(a) Cosider a ifiite geometric series with first term 'a' ad commo ratio r If the sum is 4 ad the secod term is 3/4, the : (A) a = 7 4, r = 3 7 (B) a =, r = 3 8 (C) a = 3, r = (D) a = 3, r = 4 If a, b, c, d are positive real umbers such that a + b + c + d =, the M = (a + b) (c + d) satisfies the relatio : (A) 0 M (B) M (C) M 3 (D) 3 M 4 [ JEE 000, Screeig, + out of 35 ] (c) The fourth power of the commo differece of a arithmetic progressio with iteger etries added to the product of ay four cosecutive terms of it Prove that the resultig sum is the square of a iteger [ JEE 000, Mais, 4 out of 00 ] Q0 Give that, are roots of the equatio, A x 4 x + = 0 ad, the roots of the equatio, B x 6 x + = 0, fid values of A ad B, such that,, & are i HP [ REE 000, 5 out of 00 ] Q The sum of roots of the equatio ax + bx + c = 0 is equal to the sum of squares of their reciprocals Fid whether bc, ca ad ab i AP, GP or HP? [ REE 00, 3 out of 00 ] Q Solve the followig equatios for x ad y log x + log 4 x + log 6 x + = y ( 4y ) 3 5 ( y ) = 4log 4 x [ REE 00, 5 out of 00 ] Q3(a) Let be the roots of x x + p = 0 ad be the roots of x 4x + q = 0 If are i GP, the the itegral values of p ad q respectively, are (A), 3 (B), 3 (C) 6, 3 (D) 6, 3 (c) If the sum of the first terms of the AP, 5, 8, is equal to the sum of the first terms of the AP 57, 59, 6,, the equals (A) 0 (B) (C) (D) 3 Let the positive umbers a, b, c, d be i AP The abc, abd, acd, bcd are (A) NOT i AP/GP/HP (C) i GP (B) i AP (D) HP [ JEE 00, Screeig, + + out of 35 ]

6 Brai Teasures Progressio ad Series By Abhijit kumar Jha (d) Let a, a be positive real umbers i GP For each, let A, G, H, be respectively, the arithmetic mea, geometric mea ad harmoic mea of a, a, a Fid a expressio for the GM of G, G, G i terms of A, A A, H, H, H [ JEE 00 (Mais); 5] Q4(a) Suppose a, b, c are i AP ad a, b, c are i GP If a < b < c ad a + b + c = 3, the the value of a is (A) (B) 3 (C) (D) 3 [JEE 00 (Screeig), 3] Let a, b be positive real umbers If a, A, A, b are i AP ; a, a, a, b are i GP ad a, H, H, b are i HP, show that G G H H A H A H ( a b) ( a b) 9ab [ JEE 00, Mais, 5 out of 60 ] c Q5 If a, b, c are i AP, a, b, c are i HP, the prove that either a = b = c or a, b, form a GP [JEE-03, Mais-4 out of 60] Q6 The first term of a ifiite geometric progressio is x ad its sum is 5 The (A) 0 x 0 (B) 0 < x < 0 (C) 0 < x < 0 (D) x > 0 [JEE 004 (Screeig)] Q7 If a, b, c are positive real umbers, the prove that [( + a) ( + b) ( + c)] 7 > 7 7 a 4 b 4 c 4 [JEE 004, 4 out of 60] Q8(a) I the quadratic equatio ax + bx + c = 0, if = b 4ac ad +, +, are i GP where, are the roots of ax + bx + c = 0, the (A) 0 (B) b = 0 (C) c = 0 (D) = 0 [JEE 005 (Screeig)] If total umber of rus scored i matches is ( 4 + ) where >, ad the rus scored i the k th match are give by k + k, where k Fid [JEE 005 (Mais), ] Q9 If A ad B = A, the fid the miimum atural umber 0 such that B > A > 0 [JEE 006, 6]

7 Brai Teasures Progressio ad Series By Abhijit kumar Jha ANSWER KEY EXERCISE I Q Q 3 µ = 4 Q 4 S = (7/8){ } Q 5 35/ Q 6 ( + )/ (² + + ) Q 7 7 Q 0 (4 6)/(8 + 3) Q Q 4 (a) 9 ; Q 6 a = 5, b = 8, c = Q 8 (8, 4,, 8) Q 9 ² Q 0 (i) + 3 ; (ii) ² ; (/6) ( + ) ( + 3) + Q 0, 30 Q 6, 3 Q 3 (i) s = (/4) [/{6(3 + ) (3 + 4) }] ; s = /4 (ii) (/5) ( + ) ( + ) ( + 3) ( + 4) 35( )( ) (iii) /( + ) (iv) S = ; S 46()( ) = Q 4 (a) (6/5) (6 ) [ ( + ) ( + )]/6 EXERCISE II Q 6 8 problems, 75 miutes Q8 C = 9 ; (3, 3/, 3/5) Q (iii) b = 4, c = 6, d = 9 OR b =, c = 6, d = 8 Q3 499 Q 5 (a) a =, b = 9 OR b =, a = 9 ; a = ; b = 3 or vice versa Q9 p 3 9pq + 7r = 0; roots are, 4, 7 Q 3 (a) x ( x ) ( x ) ( x ) Q 4 = 38 Q 5 93 Q 4 ( ) ( + )² Q S = ab ( ab) ( a) ( a ) ( a ) EXERCISE III Where a = x /3 & b = y /4 Q3 (/3) ; (/7) Q 4 3, 77 Q 5 8, 4, 7, 6, 648 Q 6 (a) C B Q 7 (a) B D Q 8 r = ± /9 ; = ; a = 44/80 OR r = ± /3 ; = 4 ; a = 08 OR r = /8 ; = ; a = 60 Q 9 (a) D A Q 0 A = 3 ; B = 8 Q AP Q x = ad y = 3 Q 3 (a) A, C, (c) D, (d) A, A, A H, H, H Q4 (a) D Q6 B Q8 (a) C, = 7 Q9 0 = 5

EXERCISE - 01 CHECK YOUR GRASP

EXERCISE - 01 CHECK YOUR GRASP J-Mathematics XRCIS - 0 CHCK YOUR GRASP SLCT TH CORRCT ALTRNATIV (ONLY ON CORRCT ANSWR). The maximum value of the sum of the A.P. 0, 8, 6,,... is - 68 60 6. Let T r be the r th term of a A.P. for r =,,,...

More information

Objective Mathematics

Objective Mathematics . If sum of '' terms of a sequece is give by S Tr ( )( ), the 4 5 67 r (d) 4 9 r is equal to : T. Let a, b, c be distict o-zero real umbers such that a, b, c are i harmoic progressio ad a, b, c are i arithmetic

More information

07 - SEQUENCES AND SERIES Page 1 ( Answers at he end of all questions ) b, z = n

07 - SEQUENCES AND SERIES Page 1 ( Answers at he end of all questions ) b, z = n 07 - SEQUENCES AND SERIES Page ( Aswers at he ed of all questios ) ( ) If = a, y = b, z = c, where a, b, c are i A.P. ad = 0 = 0 = 0 l a l

More information

SEQUENCE AND SERIES NCERT

SEQUENCE AND SERIES NCERT 9. Overview By a sequece, we mea a arragemet of umbers i a defiite order accordig to some rule. We deote the terms of a sequece by a, a,..., etc., the subscript deotes the positio of the term. I view of

More information

SEQUENCE AND SERIES. Contents. Theory Exercise Exercise Exercise Exercise

SEQUENCE AND SERIES. Contents. Theory Exercise Exercise Exercise Exercise SEQUENCE AND SERIES Cotets Topic Page No. Theory 0-0 Exercise - 05-09 Exercise - 0-3 Exercise - 3-7 Exercise - 8-9 Aswer Key 0 - Syllabus Arithmetic, geometric ad harmoic progressios, arithmetic, geometric

More information

SEQUENCES AND SERIES

SEQUENCES AND SERIES Sequeces ad 6 Sequeces Ad SEQUENCES AND SERIES Successio of umbers of which oe umber is desigated as the first, other as the secod, aother as the third ad so o gives rise to what is called a sequece. Sequeces

More information

VERY SHORT ANSWER TYPE QUESTIONS (1 MARK)

VERY SHORT ANSWER TYPE QUESTIONS (1 MARK) VERY SHORT ANSWER TYPE QUESTIONS ( MARK). If th term of a A.P. is 6 7 the write its 50 th term.. If S = +, the write a. Which term of the sequece,, 0, 7,... is 6? 4. If i a A.P. 7 th term is 9 ad 9 th

More information

Progressions. ILLUSTRATION 1 11, 7, 3, -1, i s an A.P. whose first term is 11 and the common difference 7-11=-4.

Progressions. ILLUSTRATION 1 11, 7, 3, -1, i s an A.P. whose first term is 11 and the common difference 7-11=-4. Progressios SEQUENCE A sequece is a fuctio whose domai is the set N of atural umbers. REAL SEQUENCE A Sequece whose rage is a subset of R is called a real sequece. I other words, a real sequece is a fuctio

More information

CHAPTER - 9 SEQUENCES AND SERIES KEY POINTS A sequece is a fuctio whose domai is the set N of atural umbers. A sequece whose rage is a subset of R is called a real sequece. Geeral A.P. is, a, a + d, a

More information

EXERCISE a a a 5. + a 15 NEETIIT.COM

EXERCISE a a a 5. + a 15 NEETIIT.COM - Dowlod our droid App. Sigle choice Type Questios EXERCISE -. The first term of A.P. of cosecutive iteger is p +. The sum of (p + ) terms of this series c be expressed s () (p + ) () (p + ) (p + ) ()

More information

[ 11 ] z of degree 2 as both degree 2 each. The degree of a polynomial in n variables is the maximum of the degrees of its terms.

[ 11 ] z of degree 2 as both degree 2 each. The degree of a polynomial in n variables is the maximum of the degrees of its terms. [ 11 ] 1 1.1 Polyomial Fuctios 1 Algebra Ay fuctio f ( x) ax a1x... a1x a0 is a polyomial fuctio if ai ( i 0,1,,,..., ) is a costat which belogs to the set of real umbers ad the idices,, 1,...,1 are atural

More information

BRAIN TEASURES TRIGONOMETRICAL RATIOS BY ABHIJIT KUMAR JHA EXERCISE I. or tan &, lie between 0 &, then find the value of tan 2.

BRAIN TEASURES TRIGONOMETRICAL RATIOS BY ABHIJIT KUMAR JHA EXERCISE I. or tan &, lie between 0 &, then find the value of tan 2. EXERCISE I Q Prove that cos² + cos² (+ ) cos cos cos (+ ) ² Q Prove that cos ² + cos (+ ) + cos (+ ) Q Prove that, ta + ta + ta + cot cot Q Prove that : (a) ta 0 ta 0 ta 60 ta 0 (b) ta 9 ta 7 ta 6 + ta

More information

LEVEL I. ,... if it is known that a 1

LEVEL I. ,... if it is known that a 1 LEVEL I Fid the sum of first terms of the AP, if it is kow tht + 5 + 0 + 5 + 0 + = 5 The iterior gles of polygo re i rithmetic progressio The smllest gle is 0 d the commo differece is 5 Fid the umber of

More information

3sin A 1 2sin B. 3π x is a solution. 1. If A and B are acute positive angles satisfying the equation 3sin A 2sin B 1 and 3sin 2A 2sin 2B 0, then A 2B

3sin A 1 2sin B. 3π x is a solution. 1. If A and B are acute positive angles satisfying the equation 3sin A 2sin B 1 and 3sin 2A 2sin 2B 0, then A 2B 1. If A ad B are acute positive agles satisfyig the equatio 3si A si B 1 ad 3si A si B 0, the A B (a) (b) (c) (d) 6. 3 si A + si B = 1 3si A 1 si B 3 si A = cosb Also 3 si A si B = 0 si B = 3 si A Now,

More information

ARITHMETIC PROGRESSION

ARITHMETIC PROGRESSION CHAPTER 5 ARITHMETIC PROGRESSION Poits to Remember :. A sequece is a arragemet of umbers or objects i a defiite order.. A sequece a, a, a 3,..., a,... is called a Arithmetic Progressio (A.P) if there exists

More information

SEQUENCES AND SERIES

SEQUENCES AND SERIES Chapter 9 SEQUENCES AND SERIES Natural umbers are the product of huma spirit. DEDEKIND 9. Itroductio I mathematics, the word, sequece is used i much the same way as it is i ordiary Eglish. Whe we say that

More information

SEQUENCES AND SERIES

SEQUENCES AND SERIES 9 SEQUENCES AND SERIES INTRODUCTION Sequeces have may importat applicatios i several spheres of huma activities Whe a collectio of objects is arraged i a defiite order such that it has a idetified first

More information

MISCELLANEOUS SEQUENCES & SERIES QUESTIONS

MISCELLANEOUS SEQUENCES & SERIES QUESTIONS MISCELLANEOUS SEQUENCES & SERIES QUESTIONS Questio (***+) Evaluate the followig sum 30 r ( 2) 4r 78. 3 MP2-V, 75,822,200 Questio 2 (***+) Three umbers, A, B, C i that order, are i geometric progressio

More information

Solutions for May. 3 x + 7 = 4 x x +

Solutions for May. 3 x + 7 = 4 x x + Solutios for May 493. Prove that there is a atural umber with the followig characteristics: a) it is a multiple of 007; b) the first four digits i its decimal represetatio are 009; c) the last four digits

More information

Topic 1 2: Sequences and Series. A sequence is an ordered list of numbers, e.g. 1, 2, 4, 8, 16, or

Topic 1 2: Sequences and Series. A sequence is an ordered list of numbers, e.g. 1, 2, 4, 8, 16, or Topic : Sequeces ad Series A sequece is a ordered list of umbers, e.g.,,, 8, 6, or,,,.... A series is a sum of the terms of a sequece, e.g. + + + 8 + 6 + or... Sigma Notatio b The otatio f ( k) is shorthad

More information

PUTNAM TRAINING INEQUALITIES

PUTNAM TRAINING INEQUALITIES PUTNAM TRAINING INEQUALITIES (Last updated: December, 207) Remark This is a list of exercises o iequalities Miguel A Lerma Exercises If a, b, c > 0, prove that (a 2 b + b 2 c + c 2 a)(ab 2 + bc 2 + ca

More information

Find a formula for the exponential function whose graph is given , 1 2,16 1, 6

Find a formula for the exponential function whose graph is given , 1 2,16 1, 6 Math 4 Activity (Due by EOC Apr. ) Graph the followig epoetial fuctios by modifyig the graph of f. Fid the rage of each fuctio.. g. g. g 4. g. g 6. g Fid a formula for the epoetial fuctio whose graph is

More information

Unit 6: Sequences and Series

Unit 6: Sequences and Series AMHS Hoors Algebra 2 - Uit 6 Uit 6: Sequeces ad Series 26 Sequeces Defiitio: A sequece is a ordered list of umbers ad is formally defied as a fuctio whose domai is the set of positive itegers. It is commo

More information

Chapter 6. Progressions

Chapter 6. Progressions Chapter 6 Progressios Evidece is foud that Babyloias some 400 years ago, kew of arithmetic ad geometric progressios. Amog the Idia mathematicias, Aryabhata (470 AD) was the first to give formula for the

More information

PROGRESSIONS AND SERIES

PROGRESSIONS AND SERIES PROGRESSIONS AND SERIES A sequece is lso clled progressio. We ow study three importt types of sequeces: () The Arithmetic Progressio, () The Geometric Progressio, () The Hrmoic Progressio. Arithmetic Progressio.

More information

Lesson-2 PROGRESSIONS AND SERIES

Lesson-2 PROGRESSIONS AND SERIES Lesso- PROGRESSIONS AND SERIES Arithmetic Progressio: A sequece of terms is sid to be i rithmetic progressio (A.P) whe the differece betwee y term d its preceedig term is fixed costt. This costt is clled

More information

2) 3 π. EAMCET Maths Practice Questions Examples with hints and short cuts from few important chapters

2) 3 π. EAMCET Maths Practice Questions Examples with hints and short cuts from few important chapters EAMCET Maths Practice Questios Examples with hits ad short cuts from few importat chapters. If the vectors pi j + 5k, i qj + 5k are colliear the (p,q) ) 0 ) 3) 4) Hit : p 5 p, q q 5.If the vectors i j

More information

SINGLE CORRECT ANSWER TYPE QUESTIONS: TRIGONOMETRY 2 2

SINGLE CORRECT ANSWER TYPE QUESTIONS: TRIGONOMETRY 2 2 Class-Jr.X_E-E SIMPLE HOLIDAY PACKAGE CLASS-IX MATHEMATICS SUB BATCH : E-E SINGLE CORRECT ANSWER TYPE QUESTIONS: TRIGONOMETRY. siθ+cosθ + siθ cosθ = ) ) ). If a cos q, y bsi q, the a y b ) ) ). The value

More information

INEQUALITIES BJORN POONEN

INEQUALITIES BJORN POONEN INEQUALITIES BJORN POONEN 1 The AM-GM iequality The most basic arithmetic mea-geometric mea (AM-GM) iequality states simply that if x ad y are oegative real umbers, the (x + y)/2 xy, with equality if ad

More information

Lesson 10: Limits and Continuity

Lesson 10: Limits and Continuity www.scimsacademy.com Lesso 10: Limits ad Cotiuity SCIMS Academy 1 Limit of a fuctio The cocept of limit of a fuctio is cetral to all other cocepts i calculus (like cotiuity, derivative, defiite itegrals

More information

THE KENNESAW STATE UNIVERSITY HIGH SCHOOL MATHEMATICS COMPETITION PART II Calculators are NOT permitted Time allowed: 2 hours

THE KENNESAW STATE UNIVERSITY HIGH SCHOOL MATHEMATICS COMPETITION PART II Calculators are NOT permitted Time allowed: 2 hours THE 06-07 KENNESAW STATE UNIVERSITY HIGH SCHOOL MATHEMATICS COMPETITION PART II Calculators are NOT permitted Time allowed: hours Let x, y, ad A all be positive itegers with x y a) Prove that there are

More information

Section 7 Fundamentals of Sequences and Series

Section 7 Fundamentals of Sequences and Series ectio Fudametals of equeces ad eries. Defiitio ad examples of sequeces A sequece ca be thought of as a ifiite list of umbers. 0, -, -0, -, -0...,,,,,,. (iii),,,,... Defiitio: A sequece is a fuctio which

More information

LINEAR RECURSION RELATIONS - LESSON FOUR SECOND-ORDER LINEAR RECURSION RELATIONS

LINEAR RECURSION RELATIONS - LESSON FOUR SECOND-ORDER LINEAR RECURSION RELATIONS LINEAR RECURSION RELATIONS - LESSON FOUR SECOND-ORDER LINEAR RECURSION RELATIONS BROTHER ALFRED BROUSSEAU St. Mary's College, Califoria Give a secod-order liear recursio relatio (.1) T. 1 = a T + b T 1,

More information

Chapter 7: Numerical Series

Chapter 7: Numerical Series Chapter 7: Numerical Series Chapter 7 Overview: Sequeces ad Numerical Series I most texts, the topic of sequeces ad series appears, at first, to be a side topic. There are almost o derivatives or itegrals

More information

Sequences, Sums, and Products

Sequences, Sums, and Products CSCE 222 Discrete Structures for Computig Sequeces, Sums, ad Products Dr. Philip C. Ritchey Sequeces A sequece is a fuctio from a subset of the itegers to a set S. A discrete structure used to represet

More information

Zeros of Polynomials

Zeros of Polynomials Math 160 www.timetodare.com 4.5 4.6 Zeros of Polyomials I these sectios we will study polyomials algebraically. Most of our work will be cocered with fidig the solutios of polyomial equatios of ay degree

More information

XT - MATHS Grade 12. Date: 2010/06/29. Subject: Series and Sequences 1: Arithmetic Total Marks: 84 = 2 = 2 1. FALSE 10.

XT - MATHS Grade 12. Date: 2010/06/29. Subject: Series and Sequences 1: Arithmetic Total Marks: 84 = 2 = 2 1. FALSE 10. ubject: eries ad equeces 1: Arithmetic otal Mars: 8 X - MAH Grade 1 Date: 010/0/ 1. FALE 10 Explaatio: his series is arithmetic as d 1 ad d 15 1 he sum of a arithmetic series is give by [ a ( ] a represets

More information

Complex Numbers Solutions

Complex Numbers Solutions Complex Numbers Solutios Joseph Zoller February 7, 06 Solutios. (009 AIME I Problem ) There is a complex umber with imagiary part 64 ad a positive iteger such that Fid. [Solutio: 697] 4i + + 4i. 4i 4i

More information

First selection test, May 1 st, 2008

First selection test, May 1 st, 2008 First selectio test, May st, 2008 Problem. Let p be a prime umber, p 3, ad let a, b be iteger umbers so that p a + b ad p 2 a 3 + b 3. Show that p 2 a + b or p 3 a 3 + b 3. Problem 2. Prove that for ay

More information

Chapter 6 Overview: Sequences and Numerical Series. For the purposes of AP, this topic is broken into four basic subtopics:

Chapter 6 Overview: Sequences and Numerical Series. For the purposes of AP, this topic is broken into four basic subtopics: Chapter 6 Overview: Sequeces ad Numerical Series I most texts, the topic of sequeces ad series appears, at first, to be a side topic. There are almost o derivatives or itegrals (which is what most studets

More information

It is always the case that unions, intersections, complements, and set differences are preserved by the inverse image of a function.

It is always the case that unions, intersections, complements, and set differences are preserved by the inverse image of a function. MATH 532 Measurable Fuctios Dr. Neal, WKU Throughout, let ( X, F, µ) be a measure space ad let (!, F, P ) deote the special case of a probability space. We shall ow begi to study real-valued fuctios defied

More information

Eton Education Centre JC 1 (2010) Consolidation quiz on Normal distribution By Wee WS (wenshih.wordpress.com) [ For SAJC group of students ]

Eton Education Centre JC 1 (2010) Consolidation quiz on Normal distribution By Wee WS (wenshih.wordpress.com) [ For SAJC group of students ] JC (00) Cosolidatio quiz o Normal distributio By Wee WS (weshih.wordpress.com) [ For SAJC group of studets ] Sped miutes o this questio. Q [ TJC 0/JC ] Mr Fruiti is the ower of a fruit stall sellig a variety

More information

Chapter 6 Infinite Series

Chapter 6 Infinite Series Chapter 6 Ifiite Series I the previous chapter we cosidered itegrals which were improper i the sese that the iterval of itegratio was ubouded. I this chapter we are goig to discuss a topic which is somewhat

More information

ADDITIONAL MATHEMATICS FORM 5 MODULE 2

ADDITIONAL MATHEMATICS FORM 5 MODULE 2 PROGRAM DIDIK CEMERLANG AKADEMIK SPM ADDITIONAL MATHEMATICS FORM 5 MODULE 2 PROGRESSIONS (Geometric Progressio) ORGANISED BY: JABATAN PELAJARAN NEGERI PULAU PINANG CHAPTER 2 : GEOMETRIC PROGRESSIONS Cotets

More information

Coffee Hour Problems of the Week (solutions)

Coffee Hour Problems of the Week (solutions) Coffee Hour Problems of the Week (solutios) Edited by Matthew McMulle Otterbei Uiversity Fall 0 Week. Proposed by Matthew McMulle. A regular hexago with area 3 is iscribed i a circle. Fid the area of a

More information

ARITHMETIC PROGRESSIONS

ARITHMETIC PROGRESSIONS CHAPTER 5 ARITHMETIC PROGRESSIONS (A) Mai Cocepts ad Results A arithmetic progressio (AP) is a list of umbers i which each term is obtaied by addig a fixed umber d to the precedig term, except the first

More information

+ {JEE Advace 03} Sept 0 Name: Batch (Day) Phoe No. IT IS NOT ENOUGH TO HAVE A GOOD MIND, THE MAIN THING IS TO USE IT WELL Marks: 00. If A (α, β) = (a) A( α, β) = A( α, β) (c) Adj (A ( α, β)) = Sol : We

More information

CSE 1400 Applied Discrete Mathematics Number Theory and Proofs

CSE 1400 Applied Discrete Mathematics Number Theory and Proofs CSE 1400 Applied Discrete Mathematics Number Theory ad Proofs Departmet of Computer Scieces College of Egieerig Florida Tech Sprig 01 Problems for Number Theory Backgroud Number theory is the brach of

More information

CHAPTER 10 INFINITE SEQUENCES AND SERIES

CHAPTER 10 INFINITE SEQUENCES AND SERIES CHAPTER 10 INFINITE SEQUENCES AND SERIES 10.1 Sequeces 10.2 Ifiite Series 10.3 The Itegral Tests 10.4 Compariso Tests 10.5 The Ratio ad Root Tests 10.6 Alteratig Series: Absolute ad Coditioal Covergece

More information

We are mainly going to be concerned with power series in x, such as. (x)} converges - that is, lims N n

We are mainly going to be concerned with power series in x, such as. (x)} converges - that is, lims N n Review of Power Series, Power Series Solutios A power series i x - a is a ifiite series of the form c (x a) =c +c (x a)+(x a) +... We also call this a power series cetered at a. Ex. (x+) is cetered at

More information

Objective Mathematics

Objective Mathematics 6. If si () + cos () =, the is equal to :. If <

More information

TEACHER CERTIFICATION STUDY GUIDE

TEACHER CERTIFICATION STUDY GUIDE COMPETENCY 1. ALGEBRA SKILL 1.1 1.1a. ALGEBRAIC STRUCTURES Kow why the real ad complex umbers are each a field, ad that particular rigs are ot fields (e.g., itegers, polyomial rigs, matrix rigs) Algebra

More information

IIT JAM Mathematical Statistics (MS) 2006 SECTION A

IIT JAM Mathematical Statistics (MS) 2006 SECTION A IIT JAM Mathematical Statistics (MS) 6 SECTION A. If a > for ad lim a / L >, the which of the followig series is ot coverget? (a) (b) (c) (d) (d) = = a = a = a a + / a lim a a / + = lim a / a / + = lim

More information

Seunghee Ye Ma 8: Week 5 Oct 28

Seunghee Ye Ma 8: Week 5 Oct 28 Week 5 Summary I Sectio, we go over the Mea Value Theorem ad its applicatios. I Sectio 2, we will recap what we have covered so far this term. Topics Page Mea Value Theorem. Applicatios of the Mea Value

More information

(A sequence also can be thought of as the list of function values attained for a function f :ℵ X, where f (n) = x n for n 1.) x 1 x N +k x N +4 x 3

(A sequence also can be thought of as the list of function values attained for a function f :ℵ X, where f (n) = x n for n 1.) x 1 x N +k x N +4 x 3 MATH 337 Sequeces Dr. Neal, WKU Let X be a metric space with distace fuctio d. We shall defie the geeral cocept of sequece ad limit i a metric space, the apply the results i particular to some special

More information

SOLUTIONS TO PRISM PROBLEMS Junior Level 2014

SOLUTIONS TO PRISM PROBLEMS Junior Level 2014 SOLUTIONS TO PRISM PROBLEMS Juior Level 04. (B) Sice 50% of 50 is 50 5 ad 50% of 40 is the secod by 5 0 5. 40 0, the first exceeds. (A) Oe way of comparig the magitudes of the umbers,,, 5 ad 0.7 is 4 5

More information

Math 299 Supplement: Real Analysis Nov 2013

Math 299 Supplement: Real Analysis Nov 2013 Math 299 Supplemet: Real Aalysis Nov 203 Algebra Axioms. I Real Aalysis, we work withi the axiomatic system of real umbers: the set R alog with the additio ad multiplicatio operatios +,, ad the iequality

More information

11 C 90. Through what angle has it turned in 10 seconds? cos24 +cos55 +cos125 +cos204 +cos300 =½. Prove that :

11 C 90. Through what angle has it turned in 10 seconds? cos24 +cos55 +cos125 +cos204 +cos300 =½. Prove that : Class - XI Maths Assigmet 0-07 Topic : Trigoometry Q If the agular diameter of the moo by 0, how far from the eye a coi of diameter cm be kept to hide the moo? cm Q Fid the agle betwee the miute had of

More information

Solutions to Math 347 Practice Problems for the final

Solutions to Math 347 Practice Problems for the final Solutios to Math 347 Practice Problems for the fial 1) True or False: a) There exist itegers x,y such that 50x + 76y = 6. True: the gcd of 50 ad 76 is, ad 6 is a multiple of. b) The ifiimum of a set is

More information

In number theory we will generally be working with integers, though occasionally fractions and irrationals will come into play.

In number theory we will generally be working with integers, though occasionally fractions and irrationals will come into play. Number Theory Math 5840 otes. Sectio 1: Axioms. I umber theory we will geerally be workig with itegers, though occasioally fractios ad irratioals will come ito play. Notatio: Z deotes the set of all itegers

More information

= = =

= = = Sec 5.8 Sec 6. Mathematical Modelig (Arithmetic & Geometric Series) Name: Carl Friedrich Gauss is probably oe of the most oted complete mathematicias i history. As the story goes, he was potetially recogiized

More information

Elementary Algebra and Geometry

Elementary Algebra and Geometry 1 Elemetary Algera ad Geometry 1.1 Fudametal Properties (Real Numers) a + = + a Commutative Law for Additio (a + ) + c = a + ( + c) Associative Law for Additio a + 0 = 0 + a Idetity Law for Additio a +

More information

Created by T. Madas SERIES. Created by T. Madas

Created by T. Madas SERIES. Created by T. Madas SERIES SUMMATIONS BY STANDARD RESULTS Questio (**) Use stadard results o summatios to fid the value of 48 ( r )( 3r ). 36 FP-B, 66638 Questio (**+) Fid, i fully simplified factorized form, a expressio

More information

2.4 - Sequences and Series

2.4 - Sequences and Series 2.4 - Sequeces ad Series Sequeces A sequece is a ordered list of elemets. Defiitio 1 A sequece is a fuctio from a subset of the set of itegers (usually either the set 80, 1, 2, 3,... < or the set 81, 2,

More information

3 Gauss map and continued fractions

3 Gauss map and continued fractions ICTP, Trieste, July 08 Gauss map ad cotiued fractios I this lecture we will itroduce the Gauss map, which is very importat for its coectio with cotiued fractios i umber theory. The Gauss map G : [0, ]

More information

Infinite Sequences and Series

Infinite Sequences and Series Chapter 6 Ifiite Sequeces ad Series 6.1 Ifiite Sequeces 6.1.1 Elemetary Cocepts Simply speakig, a sequece is a ordered list of umbers writte: {a 1, a 2, a 3,...a, a +1,...} where the elemets a i represet

More information

Poornima University, For any query, contact us at: ,18

Poornima University, For any query, contact us at: ,18 AIEEE/1/MAHS 1 S. No Questios Solutios Q.1 he circle passig through (1, ) ad touchig the axis of x at (, ) also passes through the poit (a) (, ) (b) (, ) (c) (, ) (d) (, ) Q. ABCD is a trapezium such that

More information

Proof of Goldbach s Conjecture. Reza Javaherdashti

Proof of Goldbach s Conjecture. Reza Javaherdashti Proof of Goldbach s Cojecture Reza Javaherdashti farzijavaherdashti@gmail.com Abstract After certai subsets of Natural umbers called Rage ad Row are defied, we assume (1) there is a fuctio that ca produce

More information

Sequences, Mathematical Induction, and Recursion. CSE 2353 Discrete Computational Structures Spring 2018

Sequences, Mathematical Induction, and Recursion. CSE 2353 Discrete Computational Structures Spring 2018 CSE 353 Discrete Computatioal Structures Sprig 08 Sequeces, Mathematical Iductio, ad Recursio (Chapter 5, Epp) Note: some course slides adopted from publisher-provided material Overview May mathematical

More information

1. By using truth tables prove that, for all statements P and Q, the statement

1. By using truth tables prove that, for all statements P and Q, the statement Author: Satiago Salazar Problems I: Mathematical Statemets ad Proofs. By usig truth tables prove that, for all statemets P ad Q, the statemet P Q ad its cotrapositive ot Q (ot P) are equivalet. I example.2.3

More information

FINALTERM EXAMINATION Fall 9 Calculus & Aalytical Geometry-I Questio No: ( Mars: ) - Please choose oe Let f ( x) is a fuctio such that as x approaches a real umber a, either from left or right-had-side,

More information

Regn. No. North Delhi : 33-35, Mall Road, G.T.B. Nagar (Opp. Metro Gate No. 3), Delhi-09, Ph: ,

Regn. No. North Delhi : 33-35, Mall Road, G.T.B. Nagar (Opp. Metro Gate No. 3), Delhi-09, Ph: , . Sectio-A cotais 30 Multiple Choice Questios (MCQ). Each questio has 4 choices (a), (b), (c) ad (d), for its aswer, out of which ONLY ONE is correct. From Q. to Q.0 carries Marks ad Q. to Q.30 carries

More information

3.2 Properties of Division 3.3 Zeros of Polynomials 3.4 Complex and Rational Zeros of Polynomials

3.2 Properties of Division 3.3 Zeros of Polynomials 3.4 Complex and Rational Zeros of Polynomials Math 60 www.timetodare.com 3. Properties of Divisio 3.3 Zeros of Polyomials 3.4 Complex ad Ratioal Zeros of Polyomials I these sectios we will study polyomials algebraically. Most of our work will be cocered

More information

September 2012 C1 Note. C1 Notes (Edexcel) Copyright - For AS, A2 notes and IGCSE / GCSE worksheets 1

September 2012 C1 Note. C1 Notes (Edexcel) Copyright   - For AS, A2 notes and IGCSE / GCSE worksheets 1 September 0 s (Edecel) Copyright www.pgmaths.co.uk - For AS, A otes ad IGCSE / GCSE worksheets September 0 Copyright www.pgmaths.co.uk - For AS, A otes ad IGCSE / GCSE worksheets September 0 Copyright

More information

IYGB. Special Extension Paper E. Time: 3 hours 30 minutes. Created by T. Madas. Created by T. Madas

IYGB. Special Extension Paper E. Time: 3 hours 30 minutes. Created by T. Madas. Created by T. Madas YGB Special Extesio Paper E Time: 3 hours 30 miutes Cadidates may NOT use ay calculator. formatio for Cadidates This practice paper follows the Advaced Level Mathematics Core ad the Advaced Level Further

More information

Define and Use Sequences and Series

Define and Use Sequences and Series . a., A..A; P..A, P..B TEKS Defie ad Use Sequeces ad Series Before You idetified ad wrote fuctios. Now You will recogize ad write rules for umber patters. Why? So you ca fid agle measures, as i Ex.. Key

More information

LESSON 2: SIMPLIFYING RADICALS

LESSON 2: SIMPLIFYING RADICALS High School: Workig with Epressios LESSON : SIMPLIFYING RADICALS N.RN.. C N.RN.. B 5 5 C t t t t t E a b a a b N.RN.. 4 6 N.RN. 4. N.RN. 5. N.RN. 6. 7 8 N.RN. 7. A 7 N.RN. 8. 6 80 448 4 5 6 48 00 6 6 6

More information

a= x+1=4 Q. No. 2 Let T r be the r th term of an A.P., for r = 1,2,3,. If for some positive integers m, n. we 1 1 Option 2 1 1

a= x+1=4 Q. No. 2 Let T r be the r th term of an A.P., for r = 1,2,3,. If for some positive integers m, n. we 1 1 Option 2 1 1 Q. No. th term of the sequece, + d, + d,.. is Optio + d Optio + (- ) d Optio + ( + ) d Optio Noe of these Correct Aswer Expltio t =, c.d. = d t = + (h- )d optio (b) Q. No. Let T r be the r th term of A.P.,

More information

Section 11.8: Power Series

Section 11.8: Power Series Sectio 11.8: Power Series 1. Power Series I this sectio, we cosider geeralizig the cocept of a series. Recall that a series is a ifiite sum of umbers a. We ca talk about whether or ot it coverges ad i

More information

ENGI Series Page 6-01

ENGI Series Page 6-01 ENGI 3425 6 Series Page 6-01 6. Series Cotets: 6.01 Sequeces; geeral term, limits, covergece 6.02 Series; summatio otatio, covergece, divergece test 6.03 Stadard Series; telescopig series, geometric series,

More information

Section 6.4: Series. Section 6.4 Series 413

Section 6.4: Series. Section 6.4 Series 413 ectio 64 eries 4 ectio 64: eries A couple decides to start a college fud for their daughter They pla to ivest $50 i the fud each moth The fud pays 6% aual iterest, compouded mothly How much moey will they

More information

Starting with a time of 1 second, the partial sums of the time series form the sequence 1, 3 2, 7 4, 1 5

Starting with a time of 1 second, the partial sums of the time series form the sequence 1, 3 2, 7 4, 1 5 - OBJECTIVE Determie whether a series is coverget or diverget. Coverget ad Diverget Series HISTORY The Greek philosopher Zeo of Elea (c. 90 30 B.C.) proposed several perplexig riddles, or paradoxes. Oe

More information

SOLVED EXAMPLES

SOLVED EXAMPLES Prelimiaries Chapter PELIMINAIES Cocept of Divisibility: A o-zero iteger t is said to be a divisor of a iteger s if there is a iteger u such that s tu I this case we write t s (i) 6 as ca be writte as

More information

Addition: Property Name Property Description Examples. a+b = b+a. a+(b+c) = (a+b)+c

Addition: Property Name Property Description Examples. a+b = b+a. a+(b+c) = (a+b)+c Notes for March 31 Fields: A field is a set of umbers with two (biary) operatios (usually called additio [+] ad multiplicatio [ ]) such that the followig properties hold: Additio: Name Descriptio Commutativity

More information

APPENDIX F Complex Numbers

APPENDIX F Complex Numbers APPENDIX F Complex Numbers Operatios with Complex Numbers Complex Solutios of Quadratic Equatios Polar Form of a Complex Number Powers ad Roots of Complex Numbers Operatios with Complex Numbers Some equatios

More information

CONTENTS. Course Goals. Course Materials Lecture Notes:

CONTENTS. Course Goals. Course Materials Lecture Notes: INTRODUCTION Ho Chi Mih City OF Uiversity ENVIRONMENTAL of Techology DESIGN Faculty Chapter of Civil 1: Orietatio. Egieerig Evaluatio Departmet of mathematical of Water Resources skill Egieerig & Maagemet

More information

The Advantage Testing Foundation Solutions

The Advantage Testing Foundation Solutions The Advatage Testig Foudatio 202 Problem I the morig, Esther biked from home to school at a average speed of x miles per hour. I the afteroo, havig let her bike to a fried, Esther walked back home alog

More information

Progression. CATsyllabus.com. CATsyllabus.com. Sequence & Series. Arithmetic Progression (A.P.) n th term of an A.P.

Progression. CATsyllabus.com. CATsyllabus.com. Sequence & Series. Arithmetic Progression (A.P.) n th term of an A.P. Pogessio Sequece & Seies A set of umbes whose domai is a eal umbe is called a SEQUENCE ad sum of the sequece is called a SERIES. If a, a, a, a 4,., a, is a sequece, the the expessio a + a + a + a 4 + a

More information

11.1 Arithmetic Sequences and Series

11.1 Arithmetic Sequences and Series 11.1 Arithmetic Sequeces ad Series A itroductio 1, 4, 7, 10, 13 9, 1, 7, 15 6., 6.6, 7, 7.4 ππ+, 3, π+ 6 Arithmetic Sequeces ADD To get ext term 35 1 7. 3π + 9, 4, 8, 16, 3 9, 3, 1, 1/ 3 1,1/ 4,1/16,1/

More information

NICK DUFRESNE. 1 1 p(x). To determine some formulas for the generating function of the Schröder numbers, r(x) = a(x) =

NICK DUFRESNE. 1 1 p(x). To determine some formulas for the generating function of the Schröder numbers, r(x) = a(x) = AN INTRODUCTION TO SCHRÖDER AND UNKNOWN NUMBERS NICK DUFRESNE Abstract. I this article we will itroduce two types of lattice paths, Schröder paths ad Ukow paths. We will examie differet properties of each,

More information

Sequences and Limits

Sequences and Limits Chapter Sequeces ad Limits Let { a } be a sequece of real or complex umbers A ecessary ad sufficiet coditio for the sequece to coverge is that for ay ɛ > 0 there exists a iteger N > 0 such that a p a q

More information

Math 2412 Review 3(answers) kt

Math 2412 Review 3(answers) kt Math 4 Review 3(aswers) kt A t A e. If the half-life of radium is 690 years, ad you have 0 grams ow, how much will be preset i 50 years (rouded to three decimal places)?. The decay of radium is modeled

More information

Exam 2 CMSC 203 Fall 2009 Name SOLUTION KEY Show All Work! 1. (16 points) Circle T if the corresponding statement is True or F if it is False.

Exam 2 CMSC 203 Fall 2009 Name SOLUTION KEY Show All Work! 1. (16 points) Circle T if the corresponding statement is True or F if it is False. 1 (1 poits) Circle T if the correspodig statemet is True or F if it is False T F For ay positive iteger,, GCD(, 1) = 1 T F Every positive iteger is either prime or composite T F If a b mod p, the (a/p)

More information

Substitute these values into the first equation to get ( z + 6) + ( z + 3) + z = 27. Then solve to get

Substitute these values into the first equation to get ( z + 6) + ( z + 3) + z = 27. Then solve to get Problem ) The sum of three umbers is 7. The largest mius the smallest is 6. The secod largest mius the smallest is. What are the three umbers? [Problem submitted by Vi Lee, LCC Professor of Mathematics.

More information

Unit 4: Polynomial and Rational Functions

Unit 4: Polynomial and Rational Functions 48 Uit 4: Polyomial ad Ratioal Fuctios Polyomial Fuctios A polyomial fuctio y px ( ) is a fuctio of the form p( x) ax + a x + a x +... + ax + ax+ a 1 1 1 0 where a, a 1,..., a, a1, a0are real costats ad

More information

VIVEKANANDA VIDYALAYA MATRIC HR SEC SCHOOL FIRST MODEL EXAM (A) 10th Standard Reg.No. : MATHEMATICS - MOD EXAM 1(A)

VIVEKANANDA VIDYALAYA MATRIC HR SEC SCHOOL FIRST MODEL EXAM (A) 10th Standard Reg.No. : MATHEMATICS - MOD EXAM 1(A) Time : 0:30:00 Hrs VIVEKANANDA VIDYALAYA MATRIC HR SEC SCHOOL FIRST MODEL EXAM 018-19(A) 10th Stadard Reg.No. : MATHEMATICS - MOD EXAM 1(A) Total Mark : 100 I. CHOOSE THE BEST ANSWER WITH CORRECT OPTION:-

More information

COMPUTING SUMS AND THE AVERAGE VALUE OF THE DIVISOR FUNCTION (x 1) + x = n = n.

COMPUTING SUMS AND THE AVERAGE VALUE OF THE DIVISOR FUNCTION (x 1) + x = n = n. COMPUTING SUMS AND THE AVERAGE VALUE OF THE DIVISOR FUNCTION Abstract. We itroduce a method for computig sums of the form f( where f( is ice. We apply this method to study the average value of d(, where

More information

(a) (b) All real numbers. (c) All real numbers. (d) None. to show the. (a) 3. (b) [ 7, 1) (c) ( 7, 1) (d) At x = 7. (a) (b)

(a) (b) All real numbers. (c) All real numbers. (d) None. to show the. (a) 3. (b) [ 7, 1) (c) ( 7, 1) (d) At x = 7. (a) (b) Chapter 0 Review 597. E; a ( + )( + ) + + S S + S + + + + + + S lim + l. D; a diverges by the Itegral l k Test sice d lim [(l ) ], so k l ( ) does ot coverge absolutely. But it coverges by the Alteratig

More information

THE ASSOCIATION OF MATHEMATICS TEACHERS OF INDIA Screening Test - Bhaskara Contest (NMTC at JUNIOR LEVEL IX & X Standards) Saturday, 27th August 2016.

THE ASSOCIATION OF MATHEMATICS TEACHERS OF INDIA Screening Test - Bhaskara Contest (NMTC at JUNIOR LEVEL IX & X Standards) Saturday, 27th August 2016. THE ASSOCIATION OF MATHEMATICS TEACHERS OF INDIA Screeig Test - Bhaskara Cotest (NMTC at JUNIOR LEVEL I & Stadards) Saturday, 7th August 06. Note : Note : () Fill i the respose sheet with your Name, Class,

More information

SAFE HANDS & IIT-ian's PACE EDT-10 (JEE) SOLUTIONS

SAFE HANDS & IIT-ian's PACE EDT-10 (JEE) SOLUTIONS . If their mea positios coicide with each other, maimum separatio will be A. Now from phasor diagram, we ca clearly see the phase differece. SAFE HANDS & IIT-ia's PACE ad Aswer : Optio (4) 5. Aswer : Optio

More information