ALL INDIA TEST SERIES

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1 AITS-FT-V-PCM(S)-JEE(Main)/4 Fro Classroo/Integrated School Progras 7 in Top, in Top, 54 in Top, 6 in Top 5 All India Ranks & 4 Students fro Classroo /Integrated School Progras & 7 Students fro All Progras have been Awarded a Rank in JEE (Advanced), FIITJEE JEE(Main), 4 ALL INDIA TEST SERIES ANSWERS, HINTS & SLUTINS FULL TEST V (Main) Q. No. PHYSICS CHEMISTRY MATHEMATICS. B A C. C C B. A B C 4. D D B 5. C C B 6. A B A 7. D D A 8. B D B 9. C B C. B A D. C B C. C C B. A B D 4. B C B 5. A D A 6. C D C 7. C B B 8. B C C 9. D B A. A B A. A C B. B B B. B D C 4. C D B 5. C C C 6. D A A 7. C B C 8. C C D 9. C A B. D A C FIITJEE Ltd., FIITJEE House, 9-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -6, Ph 466, , Fax 6594

2 AITS-FT-V-PCM(S)-JEE(Main)/4 Physics PART I. Viscosity of gases increases & that of liquid decreases.. u T gcos. x t dv v 4 v 8x dx So graph is parabolic 4. The galvanoeter will not show any deflection. 5. When bar becoes vertical g so V g B q g q g If I G then it becoes a balanced whetstone bridge c 8. E Q A Qd V Ed A Q/ d d 9. Apply gaus theore qin E4r q E E 4 r r field depends only on r. FIITJEE Ltd., FIITJEE House, 9-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -6, Ph 466, , Fax 6594

3 AITS-FT-V-PCM(S)-JEE(Main)/4. r cos 8r r cos cf cfo f c vs cos r c cf c 4 r θ v scos θ v s A. A sin t t 6 A A sin t t T t t T / 6 6 A P Q A/ A h. kx h bdxgx h x o h h h kxh b g hx x dx b g h h bgh kxh bg `x 6 6k 4 b g h PE kx k 6k 4 b g h 7k. When pure rolling starts friction reduces to zero. So plank does not have any acceleration so surface is horizontal. K x (h-x) 4. F f a r a fr r F F a a Ft vc F P F V.t f 5. r I r r r r I r FIITJEE Ltd., FIITJEE House, 9-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -6, Ph 466, , Fax 6594

4 AITS-FT-V-PCM(S)-JEE(Main)/ P. 8 v v 8 / sec. 7. As there does not exist any external horizontal force so X coordinate of centre of ass will not charge position of lower end is, 8. h gt h t g v h v at a g V g h a 9. The aplitude of the resultant wave is 4 4 cos 9 5 R V I. R V I R V I R V I %. Miniu energy transferred in the for of proton fro CE v v v in KEin vin.6.4ev..6.6ev. 4. pnpdt d d d p n dt p Nd. N A. Activity A A A t/ FIITJEE Ltd., FIITJEE House, 9-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -6, Ph 466, , Fax 6594

5 4.. f f f 5 R eq f eq and feq This. Also AITS-FT-V-PCM(S)-JEE(Main)/4 μ. 5. For iage to be coincident, either the rays should retrace or the iage due to the lens should fored just at the pole of the irror in thin case. The iage fored due to lens is at c (f) be fro the lens. Thus either this iage should be at centre of curvature of the convex irror or at the pole of the irror. Hence 6c or c should be the separation between the lens and the irror. 6. no of fringes shifted x t 7. frequency of vibration of wire will be equal to the frequency of the source hence f = 4Hz 8. R 5 I and V are in phase xc x L. and Z R Vrs thus Irs A. Z 9. Q U W V U Q nrt n V Q nrt n T Also, T 4K. for, V T T K. P P V V. Soe quantity of ice will elt and the equilibriu teperature will be c FIITJEE Ltd., FIITJEE House, 9-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -6, Ph 466, , Fax 6594

6 AITS-FT-V-PCM(S)-JEE(Main)/4 6 Cheistry PART II. SiCl4 4H H4Si 4 4HCl PCl5 4H HP4 5HCl BCl H B H HCl. IV Pt NH NH IV Pt Cl and ore stereo isoers are possible. Cl NH Cl (ptically active) cis Cl NH (ptically inactive) trans. SiH4 4H Si.H 4H Al NaH H NaAl H Zn HS4 ZnS4 H XeF6 H Xe 6HF 6. B.. of H = I B.. of H 7. With NH, CH NH and (CH ) NH, (BH )(BH L ) is fored. 9. Ag, Pb and Bi for corresponding thiosulphate.. P4 NaH H NaHP PH 4Na S Na S Na S 4 4H P H P PH 4. Due to axiu, -diaxial interaction.. H C H (highly stable anion). FIITJEE Ltd., FIITJEE House, 9-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -6, Ph 466, , Fax 6594

7 7 AITS-FT-V-PCM(S)-JEE(Main)/4. H H H C CH 4. H I CF CF HI CHF I 5. (A) S H H S (B) (C) H S S H Due to tautoeris the product will becoe raceic ixture. CH CH H C CH H H C C H H H H 6. All are stronger than carbonic acid. CH CH 7. CH C C CH H CH C C CH H., -addition does not yield syn-broinated product. R. CV (for onoatoic gas) We know q E W q q ncv T q nt C V q q R C CV R nt q / C M Metallic oxide. V 8 g g g No. of equivalents of M = no. of equivalents of FIITJEE Ltd., FIITJEE House, 9-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -6, Ph 466, , Fax 6594

8 AITS-FT-V-PCM(S)-JEE(Main)/4 8 8 E E 4. ph of aqueous solution of salt of weak acid and weak base is given by ph 7 pka pkb 5. H and are produced at cathode and anode respectively. At cathode: H e H H F ol At anode: H 4H 4e ol F Total volue of gases =.4 L H. L.6 L 6. s-orbital is spherically syetrical.. Due to strong H-bond between acetone and chlorofor, vapour pressure is less than that of ideal solution. FIITJEE Ltd., FIITJEE House, 9-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -6, Ph 466, , Fax 6594

9 9 AITS-FT-V-PCM(S)-JEE(Main)/4 Matheatics PART III. df x dx. Last two digits should be,, 4, 5, 6, 64, 7, 76. sinb sinc sina sinb sinc LHS, RHS sin B = sin C and sin A = 4. Line joining (, 6) and 8, will subtend a right angle at focus (a, ) 5. (x )(x x ) =, x = (x )(x )(y 4) =, x =, x = No triangle possible 6. Clearly sin A A 7. ae, b 4 =, a 4 8. Fro to 9, there are 9 = 9 digits Fro to 99, there are 9 = 8 digits and so on So finally total digits will take 666 pages 9.. n n x n n n n n n n n n 4. cos x = cos x x = x, x =,. Put sin x = t. q = and p = 4. Consider f(x) = cos x e x, apply Roll s theore x lnx t lnx dt x 9 AC cos 6º FIITJEE Ltd., FIITJEE House, 9-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -6, Ph 466, , Fax 6594

10 AITS-FT-V-PCM(S)-JEE(Main)/4 AC = 9 R 9 8. AC = BC = 54 Mid point of AB D = (,, ) dr s of DC = (4,, 4) Equation of plane is x y z =. P(x) = (x ) (x ). Put y =. x n x n.. x = (x r )(x r )... (x r n ) Put x =. Let b ˆi ˆj kˆ 4. Total ways 4 5 Favourable = 4 5 P(E) C C C 4 5. I / t e dt / t e cos t 6. Lines will intersect if { =, } y = x 9. b = or b = or b = or FIITJEE Ltd., FIITJEE House, 9-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -6, Ph 466, , Fax 6594

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