ANSWERS, HINTS & SOLUTIONS HALF COURSE TEST VIII PAPER-2
|
|
- Esther Watts
- 5 years ago
- Views:
Transcription
1 AIITS-HCT-VIII (Paper-)-PCM(Sol)-JEE(Advanced)/7 In JEE Advanced 06, FIITJEE Students bag 6 in Top 00 AIR, 7 in Top 00 AIR, 8 in Top 00 AIR. 4 Students from Long Term Classroom/ Integrated School Program & 44 Students from All Programs have qualified in JEE Advanced, 06 FIITJEE ALL INDIA INTEGRATED TEST SERIES JEE(Advanced)-07 ANSWERS, HINTS & SOLUTIONS HALF COURSE TEST VIII PAPER- ANSWERS KEY Q. No. PHYSICS CHEMISTRY MATHEMATICS. C C A. C A C. C B A 4. B A A. C C D 6. A A A 7. B D C 8. B D A 9. A, C C, D B, C 0. A, B B, D A, C. A, C A, B, C A, B. A, B, D A, B, C A, B, C, D. A C B 4. B D B. A D D 6. B A B 7. D B C 8. A A B FIITJEE Ltd., FIITJEE House, 9-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -006, Ph , 66949, Fa 694
2 AIITS-HCT-VIII (Paper-)-PCM(Sol)-JEE(Advanced)/7 Physics PART I SECTION A mm 0 0. Equivalent mass m m 0 Mechanical energy at any instant mr v mv k r mv k 4 d 0 kv 0 dt m a k T 0 a 00 m e 0 0. y = 0 y y y = f y 0 4k f 4 y f 4 ma 4 0 4k m a 6k. Let length of wire be L T sin = mg T = mg...() strain L L L L stress Y strain T A L T Y A mg AY...() L FIITJEE Ltd., FIITJEE House, 9-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -006, Ph , 66949, Fa 694
3 AIITS-HCT-VIII (Paper-)-PCM(Sol)-JEE(Advanced)/7 4. mg mg sin( t ) k k At t = 0, = 0, mg mg cos t k k mg [ cos t] k mg k mg k Origin (negative etremity) Equilibrium position Positive etremity. Stress at stress mg mg, strain AL ALY du A d = energy density stress strain m g du YAL m g L 6AY [ d] 0 6. d T sin dm (A )Rd dm dmw R T YL R w A L L w R L Y L = R L R L R w R R Y d T sin d d T sin 4 9. Gravitational field inside the cavity is E Gr where is mass density and r is separation between centre of sphere and centre of cavity. Applying law of Conservation of energy : GMm GMm mv 0 esc R 4R Solving V esc 88GM. 4R 0. KAd d H K( rl) dr dr r dr KL d r H r dq H KL( ) 80 dt r ln r dm L 80 dt FIITJEE Ltd., FIITJEE House, 9-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -006, Ph , 66949, Fa 694
4 4 AIITS-HCT-VIII (Paper-)-PCM(Sol)-JEE(Advanced)/7 dm 80 (80 Cal/gm)= Cal/sec dt 4. dm 000 kg/sec dt 4.. Impulse = change in momentum (v v ) (i ˆ ˆj) As impulse is in the normal direction of colliding surface tan tan 90 tan. 6. A ' A 4 A tan 7 4 y A sin(wt K 7 ). A A 6A A dv dy -4. a a av av y 0 dt dt dvy ay 0 a total a ˆ ˆ ˆ i a y j av 0 i dt ay cos (ay) v a a cos t total normal acceleration 0 a v0y (ay) v 0 a a sin N total we have, av (ay) 0 v 0 a total a n -6. From conservation of momentum = V sin + sin cos V = m/s V V ( sin ) 9 90 V 0 sin 6 also e 0.7 cos 4 also I sin = I 9 I = NS 0 m/s V d sin m/s FIITJEE Ltd., FIITJEE House, 9-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -006, Ph , 66949, Fa 694
5 AIITS-HCT-VIII (Paper-)-PCM(Sol)-JEE(Advanced)/7 7. c p c v = R c c p v c v = c p = = 9 = R R c v A = c p A = R c v = B R R 7 c p = 7R B c n c pa B pb nb c n c va B vb nb n B = moles = R = R 8. Bulk Modulus B = P Compressibility K = B = P K = = P P P P Since the process is adiabatic, P V = P V V P = P V = P = P V V K = P = P P n A ng RT ( ) 8. T P = = = 4.9T V V V V K = 9 9 T = T Pa. V SECTION C. Let man catches ball at time t = T sec. For ball y ais Sy Uyt ayt 0 (0sin7)T ( g)t 40 sin7 T g u rel t = 0 v=0 m/s t = T v T? FIITJEE Ltd., FIITJEE House, 9-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -006, Ph , 66949, Fa 694
6 6 AIITS-HCT-VIII (Paper-)-PCM(Sol)-JEE(Advanced)/7 Displacement of ball w.r.t. train in horizontal direction is zero (S ball/t ) (U ball/t )t (a ball/ T )t y 0 (0cos7) ( a T ) 40 a r For train 40 VT UT art 0 VT 4 m/s ] B = 7 A. Form linear momentum conservative (for collision B & C) v0 mv0 mv v A B A C B C V 0 V 0 V 0 f = mg a A FBD A f B C g aa mg,abc g aa /B va/b UA /B aa/bsa /B a AC v0 g 0 L v 0 6 L m g For equilibrium of block B F 0 and Fy 0 Fy 0 ; N N mg mg N For equilibrium of block A N N F F 0 N ( ) or F [ ] mg ( ) = 4 N ( 0.4) ( 0.4) 0.6 F mg N N N N y 4 y FIITJEE Ltd., FIITJEE House, 9-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -006, Ph , 66949, Fa 694
7 7 AIITS-HCT-VIII (Paper-)-PCM(Sol)-JEE(Advanced)/7 4. This happens of after collision both ball and inclined plane have same horizontal velocities say V say V be initial velocity of ball V y be vertical velocity of ball after collision, m mass of ball, m mass of inclined plane Conservation of linear momentum in horizontal direction mv (m m )V...() coefficient of restitution = [V sin (V sin Vy cos )] 0 V sin y V cos V sin...() Component of velocity of ball along the inclined plane remain same V cos V cos V sin...() y Vy sin (V V )cos using() & () Vy cos V sin V V tan V V V ( tan )...(4) (m m )V m V...() Divide m m cot ; m cot 0 m m tan. V + V = (/) () = V V Solving V 4 speed = ( ) ( / 4) 7 = 8.7 m/s 6 0m/s 60 V V FIITJEE Ltd., FIITJEE House, 9-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -006, Ph , 66949, Fa 694
8 8 AIITS-HCT-VIII (Paper-)-PCM(Sol)-JEE(Advanced)/7 Chemistry PART II SECTION A. Lattice energy > Hydration Energy compound insoluble. 7. h h 0 = / mv v = 0 h = hv 0 = 4ev hc 9 4ev J = NaOH CaO R COOH R H Na CO. G = Gº + RT lnq At equilibrium G = 0, Q = K Gº =.0 RT log K 4. Gº =.0 RT log K 460 logk K K CD AB = 0.8 C 0.68 A. Cl is o-p-directing 6. CH CH CH CH conc. NHO CH NO CH NO SECTION C. nh h n =. PSO. KP ; P.P SO O on solving P 8P SO SO K PSO P 4PSO 4PO FIITJEE Ltd., FIITJEE House, 9-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -006, Ph , 66949, Fa 694
9 9 AIITS-HCT-VIII (Paper-)-PCM(Sol)-JEE(Advanced)/7 4. Ph COOH 4 HOOC Ph Ph HOOC COOH Ph Ph HOOC COOH Ph Ph HOOC COOH Ph Ph HOOC COOH Ph All Cis (All Trans). OH H OH H O FIITJEE Ltd., FIITJEE House, 9-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -006, Ph , 66949, Fa 694
10 0 AIITS-HCT-VIII (Paper-)-PCM(Sol)-JEE(Advanced)/7 Mathematics PART III SECTION A. z 6i Im(z) is parabola having focus 6i and directri as real ais (arg z) min =, (arg z)ma = 4 4 arg(z) 4 4 Arg (z) Arg z = arg (z)., sin y sin y 0 =, y = n - / ni Hence number of ordered pair solution (, y) is 4.. f '() = 4( ) ( + ) ( + ) = 0 =, - y = f() f(-) = positive - - f() = positive f(-) = K < 0 K < 9 f(-) = 7 + K > 0 K > - 7 f() = K < 0 K < 9 K (-7, 9) 4. ( + ) n = C 0 + C + C +.C n n. We have C + C + C + C 7 +.= n- () ( + i) n = C 0 + C i + C i + C i C C + C C = n n sin () 4. () () C + C = n n sin 4 Put n = 6. 6 C + 6 C C =.. cos cos y cos y cos y cos y cos cos y.cos y cos cos y = cos sin y cos ( cos y) = sin y cos sin y 4sin y cos y = cos cos y cos sin y FIITJEE Ltd., FIITJEE House, 9-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -006, Ph , 66949, Fa 694
11 AIITS-HCT-VIII (Paper-)-PCM(Sol)-JEE(Advanced)/7 cos = cos y sec cos y sec cos y. 6. y + y + y = + + (y ) + ( y ) + (y ) = 0 R D 0 (y ) 4 ( y ). (y ) 0 (y ) ((y )) 0 (y y + ) (y + y ) 0 ( y )(y ) 0 (y + ) (y ) 0 y, 7. () + (y) + (4z) () (y) (y (4z) (4z) () = 0 a + b + c ab bc ca = 0 a b b c c a 0 a = b = c = y = 4z = z =,y,z y =, z 4 4 y = z, y, z are in H.P z 8. Let the number is 4 6 We must have < < < 4 < < 6 Clearly no digit can be zero. Thus total number of such numbers = 9 C 6 = 9 C 9. Sin 4 (k + sin ) + sin (k + ) = sin Sin 4 (k+ ) sin 6 + sin (k+) = 6 4 sin sin sin k + = = sin k 4 sin sin sin sin FIITJEE Ltd., FIITJEE House, 9-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -006, Ph , 66949, Fa 694
12 AIITS-HCT-VIII (Paper-)-PCM(Sol)-JEE(Advanced)/7. Given circles touch eternally at real ais. So, the centre C of the desired circles lies on real ais, which has radius r. thus CC = CC = + r. C C = C C = CC = r ( + r) = + ( r) r = / So, the centre of desired circle is at + or 7. SO, required equation of circles are 7 z and z Y C C C (, 0) (, 0) C X. Equation of line through A, (4, ) is 4 y r cos sin A (4 + rcos, + rsin). 4 + rcos = 8 r = 4 sec. AB = 4 sec. Similarly AC = cosec 6 9 cos sin AB AC So AB + AC = 4 4sin cos cos sin sin. ae =, a = ( + ) = ) e 4. Foci are S (, ) and S (4, ) SN PS 40 S N PS. The line L meets the parabola, a a a a a 6 a 0. But and a a 6 a 6 a a, a C : y at the points for which 6. If a > 0, then a =. Coordinates of A and B are (, 6) and (, ) respectively. Equation C : is y or y coordinates of the verte O of the parabola C are (0, -). Slope of OA =, slope of OB = the angle between OA and OB is tan tan / FIITJEE Ltd., FIITJEE House, 9-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -006, Ph , 66949, Fa 694
13 AIITS-HCT-VIII (Paper-)-PCM(Sol)-JEE(Advanced)/7 7. z z and z z z, z, z form an equilateral triangle z z z arg z z, z = 8. z + z + z = z = 0, SECTION C 4y 4 y. Equation can be written as, b = 6 9 P P P P P P b. an an an a a a... a a a n n n Adding we get n r a a a a r n n an an an 4 = 9 It can be logically seen that n cannot be greater than 7 and for a to be positive integer only n = 7 is satisfied 9 n 7,a We know that in case of ellipse if PMN CQ then PM = b, PN = a hence a =9, b = 7.. Let, be the roots in 0, then the roots will be,,, and,,, Sum = (since product of roots is one) FIITJEE Ltd., FIITJEE House, 9-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -006, Ph , 66949, Fa 694
ALL INDIA TEST SERIES
AITS-CRT-I-(Paper-)-PCM (Sol)-JEE(Advanced)/7 In JEE Advanced 06, FIITJEE Students bag 6 in Top 00 AIR, 75 in Top 00 AIR, 8 in Top 500 AIR. 54 Students from Long Term Classroom/ Integrated School Program
More informationANSWERS, HINTS & SOLUTIONS HALF COURSE TEST VII (Paper-2)
AIITS-HCT-VII-(Paper-)-PCM(S)-JEE(Advanced)/ FIITJEE Students From All Programs have bagged in Top 00, 66 in Top 00 and 7 in Top 00 All India Ranks. FIITJEE Performance in JEE (Advanced), 0: FIITJEE Students
More informationALL INDIA TEST SERIES
AITS-FT-I (Paper-)-PCM(Sol)-JEE(Advanced)/5 FIITJEE Students From All Programs have bagged 4 in Top, 66 in Top and 74 in Top 5 All India Ranks. FIITJEE Performance in JEE (Advanced), 4: 5 FIITJEE Students
More informationANSWERS, HINTS & SOLUTIONS HALF COURSE TEST VII (Paper - 1) Q. No. PHYSICS CHEMISTRY MATHEMATICS. 1. p); (D q, r) p) (D s) 2.
1 AIITS-HCT-VII (Paper-1)-PCM (Sol)-JEE(Advanced)/16 FIITJEE Students From All Programs have bagged in Top 100, 77 in Top 00 and 05 in Top 500 All India Ranks. FIITJEE Performance in JEE (Advanced), 015:
More informationALL INDIA TEST SERIES
AITS-CRT-I PCM(S)-JEE(Main)/4 From assroom/integrated School Programs 7 in Top, in Top, 54 in Top, 6 in Top 5 All India Ranks & 4 Students from assroom /Integrated School Programs & 7 Students from All
More informationALL INDIA TEST SERIES
AITS-CRT-I-PCM (Sol)-JEE(Main)/7 In JEE Advanced 6, FIITJEE Students bag 36 in Top AIR, 75 in Top AIR, 83 in Top 5 AIR. 354 Students from Long Term Classroom/ Integrated School Program & 443 Students from
More informationALL INDIA TEST SERIES
From Classroom/Integrated School Programs 7 in Top 0, 3 in Top 00, 54 in Top 300, 06 in Top 500 All India Ranks & 34 Students from Classroom /Integrated School Programs & 373 Students from All Programs
More informationANSWERS, HINTS & SOLUTIONS
AIITS-PT-IV-PCM(SOL)-JEE(Main)/6 FIITJEE Students From All Programs have bagged in Top 00, 77 in Top 00 and 05 in Top 500 All India Ranks. FIITJEE Performance in JEE (Advanced), 05: 455 FIITJEE Students
More informationFIITJEE JEE(Main)
AITS-FT-II-PCM-Sol.-JEE(Main)/7 In JEE Advanced 06, FIITJEE Students bag 6 in Top 00 AIR, 75 in Top 00 AIR, 8 in Top 500 AIR. 54 Students from Long Term Classroom/ Integrated School Program & 44 Students
More informationPART B MATHEMATICS (2) (4) = +
JEE (MAIN)--CMP - PAR B MAHEMAICS. he circle passing through (, ) and touching the axis of x at (, ) also passes through the point () (, ) () (, ) () (, ) (4) (, ) Sol. () (x ) + y + λy = he circle passes
More informationFIITJEE SOLUTION TO AIEEE-2005 MATHEMATICS
FIITJEE SOLUTION TO AIEEE-5 MATHEMATICS. If A A + I =, then the inverse of A is () A + I () A () A I () I A. () Given A A + I = A A A A + A I = A (Multiplying A on both sides) A - I + A - = or A = I A..
More informationANSWERS, HINTS & SOLUTIONS HALF COURSE TEST VII PAPER-2
IITS-HT-VII (Paper-)-PM(Sol)-JEE(dvanced)/7 In JEE dvanced 06, IITJEE Students bag 6 in Top 00 IR, 75 in Top 00 IR, 8 in Top 500 IR. 5 Students from Long Term lassroom/ Integrated School Program & Students
More informationALL INDIA TEST SERIES
ITS-FT-V-(Paper-) PCM(Sol)-JEE(dvanced)/5 FIITJEE Students From ll Programs have bagged in Top, 66 in Top and 7 in Top 5 ll India Ranks. FIITJEE Performance in JEE (dvanced), : 5 FIITJEE Students from
More informationALL INDIA TEST SERIES
From Long Term Classroom Programs and Medium / Short Classroom Program 4 in Top 0, 0 in Top 0, 4 in Top 00, 75 in Top 00, 59 in Top 500 Ranks & 54 t o t a l s e l e c t i o n s i n I I T - J E E 0 FIITJEE
More informationSOLUTIONS SECTION I: CHEMISTRY
P. CH CH CH CH H CH CH CH CH SLUTINS SECTIN I: CHEMISTRY S N NaH yellow I. CH CH CH CH C CH CH CH C Na CHI H H. H Ea 4..9 = loga.r769 Ea. = loga.r667 Ea = 4.7 4 cal mol - CH CH Cl H C CN H C CH 5. Cl h
More informationQ. No. PHYSICS CHEMISTRY MATHEMATICS
AITS-CRT-I (Paper-)-PCM(Sol)-JEE(Advaced)/5 FIITJEE Studets From All Programs have bagged 4 i Top 00, 66 i Top 00 ad 74 i Top 500 All Idia Raks. FIITJEE Performace i JEE (Advaced), 04: 5 FIITJEE Studets
More informationALL INDIA TEST SERIES
AITS-FT-V-PCM(S)-JEE(Main)/4 Fro Classroo/Integrated School Progras 7 in Top, in Top, 54 in Top, 6 in Top 5 All India Ranks & 4 Students fro Classroo /Integrated School Progras & 7 Students fro All Progras
More informationALL INDIA TEST SERIES
Frm Classrm/Integrated Schl Prgrams 7 in Tp, in Tp, 5 in Tp, 6 in Tp 5 ll India Ranks & Students frm Classrm /Integrated Schl Prgrams & 7 Students frm ll Prgrams have been warded a Rank in JEE (dvanced),
More informationALL INDIA TEST SERIES
1 AITS-FT-I-(Paper-)-PM(Sol)-JEE(Advanced)/16 FIITJEE Students From lassroom / Integrated School Programs have secured to Zonal, 6 State & 18 ity Topper Ranks. in Top 1, 78 in Top and 5 in Top 5 All India
More informationNarayana IIT Academy
INDIA Sec: Jr. IIT_N10(CHAINA) JEE-MAIN Date: 7-08-18 Time: 08:00 AM to 11:00 AM CTM- Ma.Marks: 60 KEY SHEET MATHS 1 4 5 6 7 8 9 10 4 4 1 11 1 1 14 15 16 17 18 19 0 4 1 1 4 1 4 5 6 7 8 9 0 4 4 4 1 PHYSICS
More informationComplete Syllabus of Class XI & XII
Regd. Office : Aakash Tower, 8, Pusa Road, New Delhi-0005 Ph.: 0-7656 Fa : 0-767 MM : 0 Sample Paper : Campus Recruitment Test Time : ½ Hr. Mathematics (Engineering) Complete Syllabus of Class XI & XII
More informationIMPORTANT QUESTIONS FOR INTERMEDIATE PUBLIC EXAMINATIONS IN MATHS-IB
` KUKATPALLY CENTRE IMPORTANT QUESTIONS FOR INTERMEDIATE PUBLIC EXAMINATIONS IN MATHS-IB 017-18 FIITJEE KUKATPALLY CENTRE: # -97, Plot No1, Opp Patel Kunta Huda Park, Vijaynagar Colony, Hyderabad - 500
More informationJEE Main 2017 Answers & Explanations
Test Booklet Code A JEE Main 7 Answers & Eplanations Physics Chemistry M athematics 6 6 6 76 7 7 6 77 8 8 6 78 9 9 6 79 5 5 5 65 8 6 6 5 66 8 7 7 5 67 8 8 8 5 68 8 9 9 5 69 8 5 55 7 85 6 56 7 86 7 57 7
More informationNarayana IIT Academy
INDIA XI_IC_SPARK ime : 3 Hours JEE-MAIN CP -5 Date: 5-0-8 Max Marks : 360 KEY SHEE PHYSICS.. 3. 4. 5. 6. 7. 8. 9. 0... 3. 4. 5. 6. 7. 8. 9. 0... 3. 4. 5. 6. 7. 8. 9. 30. CHEMISRY 3. 3. 33. 34. 35. 36.
More informationNarayana IIT Academy INDIA Sec: Sr. IIT-IZ GTA-7 Date: Time: 02:00 PM to 05:00 PM 2012_P2 Max.Marks:198
Narayana IIT Academy INDIA Sec: Sr. IIT-IZ GTA-7 Date: --7 Time: : PM to 5: PM _P Max.Marks:98 KEY SHEET PHYSICS D C D 4 A 5 A 6 A 7 A 8 C 9 C A A C D 4 5 AC 6 A 7 C 8 AD 9 ACD D CHEMISTY D A 4 A 5 6 C
More informationNarayana IIT Academy
INDIA Sec: Sr. IIT_IZ Jee-Advanced Date: 8--7 Time: 9: AM to : Noon 5_P MDEL Max.Marks:64 KEY SHEET PHYSICS 3 3 5 4 9 5 8 6 5 7 9 8 4 9 ABC ACD BD BC 3 ABD 4 BC 5 BCD 6 ABC 7 ABC 8 CD 9 A-PRST B-PST C-PRS
More informationALL INDIA TEST SERIES
Fom Classoom/Integated School Pogams 7 in Top 0, in Top 00, 54 in Top 00, 06 in Top 500 All India Ranks & 4 Students fom Classoom /Integated School Pogams & 7 Students fom All Pogams have been Awaded a
More informationWBJEEM Answer Keys by Aakash Institute, Kolkata Centre MATHEMATICS
WBJEEM - 05 Answer Keys by, Kolkata Centre MATHEMATICS Q.No. μ β γ δ 0 B A A D 0 B A C A 0 B C A * 04 C B B C 05 D D B A 06 A A B C 07 A * C A 08 D C D A 09 C C A * 0 C B D D B C A A D A A B A C A B 4
More informationNARAYANA I I T / P M T A C A D E M Y. C o m m o n P r a c t i c e T e s t 05 XII-IC SPARK Date:
1. (A). (C). (B). (B) 5. (A) 6. (B) 7. (B) 8. (A) 9. (A) 1. (D) 11. (C) 1. (B) 1. (A) 1. (D) 15. (B) NARAYANA I I T / P M T A C A D E M Y C o m m o n P r a c t i c e T e s t 5 XII-IC SPARK Date: 9.1.17
More informationNational Quali cations
National Quali cations AH017 X70/77/11 Mathematics of Mechanics MONDAY, 9 MAY 1:00 PM :00 PM Total marks 100 Attempt ALL questions. You may use a calculator. Full credit will be given only to solutions
More informationMathematics Extension 2
0 HIGHER SCHOOL CERTIFICATE EXAMINATION Mathematics Etension General Instructions Reading time 5 minutes Working time hours Write using black or blue pen Black pen is preferred Board-approved calculators
More informationPRACTICE PAPER 6 SOLUTIONS
PRACTICE PAPER 6 SOLUTIONS SECTION A I.. Find the value of k if the points (, ) and (k, 3) are conjugate points with respect to the circle + y 5 + 8y + 6. Sol. Equation of the circle is + y 5 + 8y + 6
More informationRao IIT Academy/ ISC - Board 2018_Std XII_Mathematics_QP + Solutions JEE MEDICAL-UG BOARDS KVPY NTSE OLYMPIADS. XII - ISC Board
Rao IIT Academy/ ISC - Board 8_Std XII_Mathematics_QP + Solutions JEE MEDICAL-UG BOARDS KVPY NTSE OLYMPIADS XII - ISC Board MATHEMATICS - QP + SOLUTIONS Date: 6..8 Ma. Marks : Question SECTION - A (8 Marks)
More informationSAMPLE TEST - 3. Time Allotted: 3 Hours Maximum Marks: 360
FIITJEE - JEE (Main) SAMPLE TEST - Time Allotted: Hours Maimum Marks: 60 Do not open this Test Booklet until you are asked to do so. Please read the instructions carefully. You are allotted 5 minutes specifically
More informationy mx 25m 25 4 circle. Then the perpendicular distance of tangent from the centre (0, 0) is the radius. Since tangent
Mathematics. The sides AB, BC and CA of ABC have, 4 and 5 interior points respectively on them as shown in the figure. The number of triangles that can be formed using these interior points is () 80 ()
More informationObjective Mathematics
. A tangent to the ellipse is intersected by a b the tangents at the etremities of the major ais at 'P' and 'Q' circle on PQ as diameter always passes through : (a) one fied point two fied points (c) four
More informationSOLUTIONS. 1. Since each compete two times with each other, hence boys Vs Boys total plays =
Mathematics SOLUTIONS 1. Since each compete two times with each other, hence boys Vs Boys total plays =. m c Boys Vs Girls total plays = 4m As per given condition. m c = 84 + 4m m 5m 84 = 0 m 1m + 7m 84
More informationL.41/42. Pre-Leaving Certificate Examination, Applied Mathematics. Marking Scheme. Ordinary Pg. 2. Higher Pg. 21.
L./ Pre-Leaving Certificate Examination, 0 Applied Mathematics Marking Scheme Ordinary Pg. Higher Pg. Page of 6 exams Pre-Leaving Certificate Examination, 0 Applied Mathematics Ordinary Level Marking Scheme
More informationFIITJEE Talent Reward Exam
FIITJEE Talent Reward Eam PAPER Time: Hours Instructions: for student presently in Class 11 CODE A11 A Maimum Marks: 70 Caution: Question Paper CODE as given above MUST be correctly marked in the answer
More information02. If (x, y) is equidistant from (a + b, b a) and (a b, a + b), then (A) x + y = 0 (B) bx ay = 0 (C) ax by = 0 (D) bx + ay = 0 (E) ax + by =
0. π/ sin d 0 sin + cos (A) 0 (B) π (C) 3 π / (D) π / (E) π /4 0. If (, y) is equidistant from (a + b, b a) and (a b, a + b), then (A) + y = 0 (B) b ay = 0 (C) a by = 0 (D) b + ay = 0 (E) a + by = 0 03.
More informationALL INDIA TEST SERIES
FIITJEE JEE (Advanced)-018 PART TEST I Paper ALL INDIA TEST SERIES Time Allotted: 3 Hours Maimum Marks: 31 Pleas e r ead th e instructions carefully. You are allotted 5 minutes specifically for this purpose.
More information1 is equal to. 1 (B) a. (C) a (B) (D) 4. (C) P lies inside both C & E (D) P lies inside C but outside E. (B) 1 (D) 1
Single Correct Q. Two mutuall perpendicular tangents of the parabola = a meet the ais in P and P. If S is the focus of the parabola then l a (SP ) is equal to (SP ) l (B) a (C) a Q. ABCD and EFGC are squares
More informationMATHEMATICS 4 UNIT (ADDITIONAL) HIGHER SCHOOL CERTIFICATE EXAMINATION. Time allowed Three hours (Plus 5 minutes reading time)
N E W S O U T H W A L E S HIGHER SCHOOL CERTIFICATE EXAMINATION 997 MATHEMATICS UNIT (ADDITIONAL) Time allowed Three hours (Plus 5 minutes reading time) DIRECTIONS TO CANDIDATES Attempt ALL questions.
More informationJEE MAIN 2013 Mathematics
JEE MAIN 01 Mathematics 1. The circle passing through (1, ) and touching the axis of x at (, 0) also passes through the point (1) (, 5) () (5, ) () (, 5) (4) ( 5, ) The equation of the circle due to point
More informationALL INDIA TEST SERIES
AITS-FT-I-(Paper-)-PM(S)-JEE(Advanced)/ Frm Lng Term lassrm Prgrams and Medium / Shrt lassrm Prgram in Tp 0, 0 in Tp 0, in Tp 00, 75 in Tp 00, 59 in Tp 500 Ranks & 5 t t a l s e l e c t i n s i n I I T
More informationNarayana IIT Academy
INDI Sec: LT-IIT-SPRK Jee-dvanced Date: -3-8 Time: 3. 4_P MODEL Ma.Marks:8 KEY SHEET RPT-4 PHYSICS,B,C,D,B,C,D 3 B,C 4,C,D 5,B,C 6,B,C,D 7,B,C,D 8,B,C,D 9,B,C,D,B,D 6 4 3 5 4 4 5 3 6 3 7 6 8 4 9 5 8 CHEMISTRY,C,D,C
More informationKing Fahd University of Petroleum and Minerals Physics Department Physics 101 Recitation Term 131 Fall 013 Quiz # 4 Section 10 A 1.50-kg block slides down a frictionless 30.0 incline, starting from rest.
More informationContents. Page. Mark Schemes C1 3 C2 9 C3 15 C4 21 FP1 27 FP2 31 FP3 35 M1 39 M2 45 M3 51 S1 57 S2 61 S3 65
GCE AS/A MATHEMATICS Specimen Assessment Materials Contents Page Mark Schemes C C 9 C 5 C FP 7 FP FP 5 9 M 5 M 5 S 57 S 6 S 65 GCE AS/A MATHEMATICS Specimen Assessment Materials WELSH JOINT EDUCATION
More informationFigure 1 Answer: = m
Q1. Figure 1 shows a solid cylindrical steel rod of length =.0 m and diameter D =.0 cm. What will be increase in its length when m = 80 kg block is attached to its bottom end? (Young's modulus of steel
More informationMENTORS EDUSERV SCHOLASTIC APTITUDE TEST (ME-SAT) SAMPLE TEST PAPER
MENTORS EDUSERV SCHOLASTIC APTITUDE TEST (ME-SAT) SAMPLE TEST PAPER [For Students presently in Class 11 going to Class 1 in 019] (Stream: Engineering) Time : hours Maximum Marks: 19 DO NOT BREAK THE SEALS
More informationNational Quali cations
National Quali cations AH08 X70/77/ Mathematics of Mechanics TUESDAY, 9 MAY :00 PM :00 PM Total marks 00 Attempt ALL questions. You may use a calculator. Full credit will be given only to solutions which
More information2013 Applied Mathematics Mechanics. Advanced Higher. Finalised Marking Instructions
0 Applied Mathematics Mechanics Advanced Higher Finalised ing Instructions Scottish Qualifications Authority 0 The information in this publication may be reproduced to support SQA qualifications only on
More information698 Chapter 11 Parametric Equations and Polar Coordinates
698 Chapter Parametric Equations and Polar Coordinates 67. 68. 69. 70. 7. 7. 7. 7. Chapter Practice Eercises 699 75. (a Perihelion a ae a( e, Aphelion ea a a( e ( Planet Perihelion Aphelion Mercur 0.075
More information150 with positive x-axis and passing through
` KUKATPALLY CENTRE IPE MAT IB Important Questions FIITJEE KUKATPALLY CENTRE: # -97, Plot No, Opp Patel Kunta Huda Park, Vijaynagar Colony, Hyderabad - 5 7 Ph: 4-6463 Regd Off: 9A, ICES House, Kalu Sarai,
More informationANSWERS, HINTS & SOLUTIONS PART TEST I PAPER-2 ANSWERS KEY
AITS-PT-I (Paper-)-PCM-JEE(Advaced)/8 FIITJEE JEE(Advaced)-8 ANSWERS, HINTS & SOLUTIONS PART TEST I PAPER- ANSWERS KEY Q. No. PHYSICS Q. No. CHEMISTRY Q. No. MATHEMATICS ALL INDIA TEST SERIES. D. B 7.
More informationWEEKLY TEST-2 GZRS-1902 (JEE ADVANCED PATTERN)
WEEKLY TEST- GZRS-90 (JEE DVNCED PTTERN) Test Date: 0--07 [ ] WT- (dv) GZRS-90_0..07. (B) PHYSICS ngle between a and p is : p a = cos a.p a p = cos 8 (6 9) (64 6) = cos 4 50 Clearly both are not perpendicular,
More informationNarayana IIT Academy
INDIA Sec: Jr IIT_IZ CUT-18 Date: 18-1-17 Time: 07:30 AM to 10:30 AM 013_P MaxMarks:180 KEY SHEET PHYSICS 1 ABCD ACD 3 AC 4 BD 5 AC 6 ABC 7 ACD 8 ABC 9 A 10 A 11 A 1 C 13 B 14 C 15 B 16 C 17 A 18 B 19
More informationSydney Grammar School
Sydney Grammar School. (a) Evaluate π 0 sinn x cos xdx. (b) Evaluate x 0 x+ dx. (c) (i) Express 6 u in the form A 4 unit mathematics Trial HSC Examination 993 4 u + B 4+u (ii) Use the substitution u =
More informationNarayana IIT Academy
NDA Sec: Sr. T_Z Jee-Advanced Date: 9-01-18 Time: 0:00 PM to 05:00 PM 011_P Model Max.Marks: 40 KEY SHEET CHEMSTRY 1 C D A 4 B 5 B 6 C 7 A 8 A 9 ABC 10 ABCD 11 ABC 1 ABC 1 8 14 9 15 1 16 7 17 6 18 19 A-PQS,
More informationNARAYANA I I T / N E E T A C A D E M Y. C o m m o n P r a c t i c e T e s t 1 3 XI-IC SPARK Date: PHYSICS CHEMISTRY MATHEMATICS
. (C). (C) 3. (A) 4. (B) 5. (C) 6. (A) 7. (B) 8. (A) 9. (B) 0. (B). (D). (D) 3. (A) 4. (C) 5. (D) NARAYANA I I T / N E E T A C A D E M Y XIS-IC-IIT-SPARK (8..7) C o m m o n P r a c t i c e T e s t 3 XI-IC
More informationGOVERNMENT OF KARNATAKA KARNATAKA STATE PRE-UNIVERSITY EDUCATION EXAMINATION BOARD SCHEME OF VALUATION. Subject : MATHEMATICS Subject Code : 35
GOVERNMENT OF KARNATAKA KARNATAKA STATE PRE-UNIVERSITY EDUCATION EXAMINATION BOARD II YEAR PUC EXAMINATION MARCH APRIL 0 SCHEME OF VALUATION Subject : MATHEMATICS Subject Code : 5 PART A Write the prime
More information2 nd ORDER O.D.E.s SUBSTITUTIONS
nd ORDER O.D.E.s SUBSTITUTIONS Question 1 (***+) d y y 8y + 16y = d d d, y 0, Find the general solution of the above differential equation by using the transformation equation t = y. Give the answer in
More informationPHYS1131 HIGHER PHYSICS 1A SOLUTIONS Homework Problem Set 1. To calculate the time taken, we substitute d=10 m into the above equation.
PHYS1131 HIGHER PHYSICS 1A SOLUTIONS Homework Problem Set 1 Q1. We use the equations of uniform accelerated motion with zero initial displacement and velocity. y 1 = " 1 gt where t is measured in seconds.
More informationL.41/42. Pre-Leaving Certificate Examination, Applied Mathematics. Marking Scheme. Ordinary Pg. 4. Higher Pg. 21.
L.4/4 Pre-Leaving Certificate Examination, 0 Applied Mathematics Marking Scheme Ordinary Pg. 4 Higher Pg. Page of 44 exams Pre-Leaving Certificate Examination, 0 Applied Mathematics Ordinary & Higher Level
More informationQuestion number 1 to 8 carries 2 marks each, 9 to 16 carries 4 marks each and 17 to 18 carries 6 marks each.
IIT-JEE5-PH- FIITJEE Solutions to IITJEE 5 Mains Paper Time: hours Physics Note: Question number to 8 carries marks each, 9 to 6 carries marks each and 7 to 8 carries 6 marks each. Q. A whistling train
More informationMath Bank - 6. What is the area of the triangle on the Argand diagram formed by the complex number z, -iz, z iz? (a) z 2 (b) 2 z 2
Math Bank - 6 Q.) Suppose A represents the symbol, B represents the symbol 0, C represents the symbol, D represents the symbol 0 and so on. If we divide INDIA by AGRA, then which one of the following is
More informationDIFFERENTIAL EQUATION
MDE DIFFERENTIAL EQUATION NCERT Solved eamples upto the section 9. (Introduction) and 9. (Basic Concepts) : Eample : Find the order and degree, if defined, of each of the following differential equations
More information63487 [Q. Booklet Number]
WBJEE - 0 (Answers & Hints) 687 [Q. Booklet Number] Regd. Office : Aakash Tower, Plot No., Sector-, Dwarka, New Delhi-0075 Ph. : 0-7656 Fa : 0-767 ANSWERS & HINTS for WBJEE - 0 by & Aakash IIT-JEE MULTIPLE
More informationUNITS, DIMENSION AND MEASUREMENT
UNITS, DIMENSION AND MEASUREMENT Measurement of large distance (Parallax Method) D = b θ Here D = distance of the planet from the earth. θ = parallax angle. b = distance between two place of observation
More informationJEE (Advanced) 2018 MATHEMATICS QUESTION BANK
JEE (Advanced) 08 MATHEMATICS QUESTION BANK Ans. A [ : a multiple of ] and B [ : a multiple of 5], then A B ( A means complement of A) A B A B A B A B A { : 5 0}, B {, }, C {,5}, then A ( B C) {(, ), (,
More informationANSWERS, HINTS & SOLUTIONS HALF COURSE TEST VII (Main)
AIITS-HT-VII-PM-JEE(Mai)-Sol./7 I JEE Advaced 06, FIITJEE Studets bag 6 i Top 00 AIR, 7 i Top 00 AIR, 8 i Top 00 AIR. Studets fom Log Tem lassoom/ Itegated School Pogam & Studets fom All Pogams have qualified
More informationThomas Whitham Sixth Form Mechanics in Mathematics
Thomas Whitham Sixth Form Mechanics in Mathematics 6/0/00 Unit M Rectilinear motion with constant acceleration Vertical motion under gravity Particle Dynamics Statics . Rectilinear motion with constant
More informationFIITJEE - JEE (Main) SAMPLE TEST - 1. Important Instructions: Maximum Marks: 360. Time Allotted: 3 Hours. Name of the Candidate (in Capital Letters) :
FIITJEE - JEE (Main) SAMPLE TEST - Time Allotted: Hours Maximum Marks: 60 Do not open this Test Booklet until you are asked to do so. Please read the instructions carefully. You are allotted 5 minutes
More informationEngineering Mechanics
2019 MPROVEMENT Mechanical Engineering Engineering Mechanics Answer Key of Objective & Conventional Questions 1 System of forces, Centoriod, MOI 1. (c) 2. (b) 3. (a) 4. (c) 5. (b) 6. (c) 7. (b) 8. (b)
More informationSPECIALIST MATHEMATICS
Victorian Certificate of Education 00 SUPERVISOR TO ATTACH PROCESSING LABEL HERE STUDENT NUMBER Letter Figures Words SPECIALIST MATHEMATICS Written eamination Monday November 00 Reading time:.00 pm to.5
More informationDistance travelled time taken and if the particle is a distance s(t) along the x-axis, then its instantaneous speed is:
Chapter 1 Kinematics 1.1 Basic ideas r(t) is the position of a particle; r = r is the distance to the origin. If r = x i + y j + z k = (x, y, z), then r = r = x 2 + y 2 + z 2. v(t) is the velocity; v =
More informationMATHEMATICS. r Statement I Statement II p q ~p ~q ~p q q p ~(p ~q) F F T T F F T F T T F T T F T F F T T T F T T F F F T T
MATHEMATICS Directions : Questions number to 5 are Assertion-Reason type questions. Each of these questions contains two statements : Statement- (Assertion) and Statement- (Reason). Each of these questions
More informationPHYS 1114, Lecture 33, April 10 Contents:
PHYS 1114, Lecture 33, April 10 Contents: 1 This class is o cially cancelled, and has been replaced by the common exam Tuesday, April 11, 5:30 PM. A review and Q&A session is scheduled instead during class
More information2016 SEC 4 ADDITIONAL MATHEMATICS CW & HW
FEB EXAM 06 SEC 4 ADDITIONAL MATHEMATICS CW & HW Find the values of k for which the line y 6 is a tangent to the curve k 7 y. Find also the coordinates of the point at which this tangent touches the curve.
More informationQUESTION BANK ON. CONIC SECTION (Parabola, Ellipse & Hyperbola)
QUESTION BANK ON CONIC SECTION (Parabola, Ellipse & Hyperbola) Question bank on Parabola, Ellipse & Hyperbola Select the correct alternative : (Only one is correct) Q. Two mutually perpendicular tangents
More informationYEAR 13 - Mathematics Pure (C3) Term 1 plan
Week Topic YEAR 13 - Mathematics Pure (C3) Term 1 plan 2016-2017 1-2 Algebra and functions Simplification of rational expressions including factorising and cancelling. Definition of a function. Domain
More information1 A proper factor of an integer N is a positive integer, not 1 or N, that divides N.
Section A: Pure Mathematics 1 A proper factor of an integer N is a positive integer, not 1 or N, that divides N. Show that 3 2 5 3 has exactly 10 proper factors. Determine how many other integers of the
More informationRAJASTHAN P.E.T. MATHS-1995
RAJASTHAN P.E.T. MATHS-1995 1. The equation of the normal to the circle x2 + y2 = a2 at point (x y ) will be : (1) x y - xy = (2) xx - yy = (3) x y + xy = (4) xx + yy = 2. Equation of the bisector of the
More informationUniversity of Malta. Junior College
University of Malta Junior College Subject: Advanced Applied Mathematics Date: June Time: 9. -. End of Year Test Worked Solutions Question (a) W µ o 4W At Equilibrium: esolving vertically esolving horizontally
More informationNarayana IIT Academy
--7_Sr.T_Z_JEE-ADV_(_P)_CTA-4_Key &Sol s Narayana T Academy NDA Sec: Sr.T_Z JEE ADVANCE Date: --7 Time: : PM to 5: PM -P-Model Max Marks: 4 KEY & SOLUTONS KEY SHEET CHEMSTRY C C C 4 D 5 A 6 A 7 B 8 C 9
More informationPART A. 4cm 1 =1.4 1 =1.5. 5cm
PART A Straight Objective Type This section contains 30 multiple choice questions. Each question has 4 choices (1), (), (3) and (4) for its answer, out of which ONLY ONE is correct. 1. The apparent depth
More informationGet Discount Coupons for your Coaching institute and FREE Study Material at Force System
Get Discount Coupons for your Coaching institute and FEE Study Material at www.pickmycoaching.com Mechanics Force System When a member of forces simultaneously acting on the body, it is known as force
More informationPOINT. Preface. The concept of Point is very important for the study of coordinate
POINT Preface The concept of Point is ver important for the stud of coordinate geometr. This chapter deals with various forms of representing a Point and several associated properties. The concept of coordinates
More informationFOUNDATION STUDIES EXAMINATIONS June PHYSICS Semester One February Main
FOUNDATION STUDIES EXAMINATIONS June 203 PHYSICS Semester One February Main Time allowed 2 hours for writing 0 minutes for reading This paper consists of 4 questions printed on 0 pages. PLEASE CHECK BEFORE
More informationAPPLICATIONS OF DERIVATIVES OBJECTIVES. The approimate increase in the area of a square plane when each side epands from c m to.0 cm is () 0.00 sq. cm () 0.006 sq. cm () 0.06 sq. cm () None. If y log then
More informationBLUE PRINT FOR MODEL QUESTION PAPER 3 BLUE PRINT
Unit Chapter Number Number of teaching Hours Weightage of marks Mark Marks 3 Marks 5 Marks (Theory) 5 Marks (Numerica l Problem) BLUE PRINT FOR MODEL QUESTION PAPER 3 Class : I PUC Subject : PHYSICS (33)
More informationFOUNDATION STUDIES EXAMINATIONS April PHYSICS First Paper February Program 2007
FOUNDATION STUDIES EXAMINATIONS April 2007 HYSICS First aper February rogram 2007 Time allowed hour for writing 0 minutes for reading This paper consists of 3 questions printed on 5 pages. LEASE CHECK
More information2013 HSC Mathematics Extension 2 Marking Guidelines
3 HSC Mathematics Extension Marking Guidelines Section I Multiple-choice Answer Key Question Answer B A 3 D 4 A 5 B 6 D 7 C 8 C 9 B A 3 HSC Mathematics Extension Marking Guidelines Section II Question
More informationObjective Mathematics
Chapter No - ( Area Bounded by Curves ). Normal at (, ) is given by : y y. f ( ) or f ( ). Area d ()() 7 Square units. Area (8)() 6 dy. ( ) d y c or f ( ) c f () c f ( ) As shown in figure, point P is
More informationHSC - BOARD MATHEMATICS (40) - SOLUTIONS
Date: 8..5 Q. (A) SECTION - I (i) (d) A () (ii) (c) A A I 6 6 6 A I 64 I I A A 6 (iii) (a) fg cos A cos HSC - BOARD - 5 MATHEMATICS (4) - SOLUTIONS cos cos ch () hy g fy c...(i) Comparing with A Hy By
More informationTime: 1 hour 30 minutes
Paper Reference(s) 6678/01 Edexcel GCE Mechanics M2 Gold Level G3 Time: 1 hour 30 minutes Materials required for examination Mathematical Formulae (Pink) Items included with question papers Nil Candidates
More informationMathematics Extension 1
NORTH SYDNEY GIRLS HIGH SCHOOL 05 TRIAL HSC EXAMINATION Mathematics Etension General Instructions Reading Time 5 minutes Working Time hours Write using black or blue pen Black pen is preferred Board approved
More informationN - W = 0. + F = m a ; N = W. Fs = 0.7W r. Ans. r = 9.32 m
91962_05_R1_p0479-0512 6/5/09 3:53 PM Page 479 R1 1. The ball is thrown horizontally with a speed of 8 m>s. Find the equation of the path, y = f(x), and then determine the ball s velocity and the normal
More informationPROBLEMS 13 - APPLICATIONS OF DERIVATIVES Page 1
PROBLEMS - APPLICATIONS OF DERIVATIVES Page ( ) Water seeps out of a conical filter at the constant rate of 5 cc / sec. When the height of water level in the cone is 5 cm, find the rate at which the height
More informationIIT JEE Maths Paper 2
IIT JEE - 009 Maths Paper A. Question paper format: 1. The question paper consists of 4 sections.. Section I contains 4 multiple choice questions. Each question has 4 choices (A), (B), (C) and (D) for
More information