JEE-2015 : Advanced Paper 1 Answers and Explanations

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1 CODE 5 JEE-5 : Advced Pper Aswers d Epltios Physics Chemistry Mthemtics A,C 8 A 8 5 A,D,C 7 B,C B,D 5 5 C,D A,C A 5 B,C B,D D 5 B,D 5 5 D 5 5 A 5 55 A,B 7 C C 5 A,D 7 7 B 7 7 A,B,C A,C 8 8 A,B,C B,C,D 8 58 B,C 9 A,B,D 9 See Sol. 9 A,C,D 9 See Sol. 9 A,D 59 See Sol. B See Sol. C See Sol. 5 A,B,C See Sol.. If g g h R PART - I : PHYSICS GMm GMm mv R R v GM R v esc v.. 7 For disc rollig without slippig MR v mv + K E R mv K E Now, mv + mg() mv + mg(7) ( ) mv v mg() v v v v 7 m/s.. P R T P A P B R A.TA RBTB T T A B R B R / / TA T B Now ccordig to wie s lw λ A T B λ T B A......

2 . Fuel vilble power iitil power 8 Required power fter hlf lives, the power output will become power required 5. For wve trvelig i wter the equivlet distce is µ times the geometricl For mim µ d + d + mλ d + ( µ ) mλ d + 9 m λ m λ d Hece, P. 7 For ir s medium Mirror + v u f f, u 5 v cm m For les v u f f + u m Totl mgifictio m m M For medium s µ 7/ No chge for mirror but for the les ( g ) f 7 ( g ) f From (i) d (ii) 5 f cm for les u cm + 5 f cm v cm m 7 M 7 (i) (ii) M 7. M / Ö/ The flu pssig through the ple is / th of the totl flu emitted by the wire. λl φ. hc φe λ φ A, B, D Oe mole of H + oe mole of helium. t temp T C C v T+ v T /RT + 5/RT U 8RT RT (A) is correct (B) I gs miture v v C C C C v+ v γrt M P + P M + + v v mi He RT 5RT......

3 vmi RT v 5RT 5 He (B) is correct cm v (C) rms 8RT µ M v, He 8RT µ v, H 8RT µ ech divisio of mi scle cm 8 vhe 8RT π vh µ 8RT (D) is correct 5 divisio of vc div of mi scle 5 (distce of vc) cm cm 8. B R (7 ) R equvilt resistce 5 5 RR ( 5 / ) R + R 5 ( + 5 / ) A, C hv ev + φ hc ev +φ λ ev hc φ λ µΩ grph of λ vs v will be st lie (optio C) v vs λ will be decresig curve optio (A). B, C cm mi scle is divided i 8 equl divisios. screw guge divisios o circulr scle 5 divisio of vc divisio o mi scle. (distce of vc) cm. L.C.5. cm.5 cm Optio A: pitch.5.5 cm LC.5cm.5cm.5 mm Optio B is correct lest cout of lier scle.5 cm distce of pitch. cm L.C..cm.mm Optio C is correct.. A, C h ML T c LT FL G M solvig we get [M L T ], c, b M kh.c.g optio (A) is correct. Similrly if L kh.c b.g c [ML T ] [LT ] b [M L T ] c c + b + c + b + c solvig we get,c,b L kh.c.g Optio C is correct

4 . B, D E m( ω) b mω E m(r ω) E E ω R ω m ω, mω (m ω ) b (m ) E E ω R m E ω b mω R m(rω ) mω ω ω ω E ω 5. D, C Agulr mometum will remi coserved. Iitil gulr mometum MR w M M 8 MR w MR + R + w R R + R R 9 R R B Soc Su d for light rys to become prllel o the d refrctig surfce..5.5 u u cm +.5 Imge of P is cm wy from refrtig surfce s..5.5 Imge P will be formed t + v 5.5 v 5 u 5 v v 5 d cm 8. A, B, C Mgitude of force is proportiol to the legth of the wire betwee the eds i uiform mgetic field. (A) is correct, (B) is correct, (C) is correct 9. A R, T B P, T, S C Q, T, R D P, Q, R s 9 R R 5 R 5. C +q chrge will more i SHM, q chrge will more log directio of its displcemet becuse it will eperiece et ttrctive force towrds oe of the wire.. (A) P, Q, R, T U U () U du () d U U F t, F, F, F......

5 (B) (C) (D) for >, F > force will be wy from equibrium If, F, U U t, U U Sice the eergy of prticle is it will ever rech origi, oscillte bout, becuse t, it is t equilibrium & force is restorig. U U U(),F(), F (), prticle will oscillte bout origi Q (Q), & (S) PQRS U U F e e / / + + U / F e, F, F, F Sice Fα, prticle eperiece s ttrctive force towrds. t, U, prticle will ot oscillte bout. P, R, T F() U F() U, F, F, F for >, F() ve for <, F() ve force is ot lwys towrds. t U,U U U + >, F () ve, <, F () + ve Prticle oscillte bout, where its potetil eergy.. 8 N N. PART - II : CHEMISTRY Fe + SCN [Fe(SCN) ] + Fe + CN [Fe(CN) ] + Spi oly mgetic momet ( + ) B.M. For [Fe(SCN) ], No. of upired electros 5(5 + ) 5 ; For [Fe(CN) ], No. of upired electros ( + ).7 Differece.7 ;.7 ;. BeCl, N O, NO +, N. 5. M M + e + + G FE G J 8.5 kj So, o. of moles of M + oidized As T f T T So, T f (.558).558 m. K f.8 Now, T f ik f m.558 i.8. So formul is [Co(NH ) 5 Cl]Cl

6 7. Two chirl ceter So stereoisomers A, C, D + Fe + H O OH Fe + H + O + H O. C As the rectio is eothermic. So icrese of temperture yields i less productio of NH.. A I CCP rrgemet O So o. of Al + So o. of Mg +. B, D. A So octhederl holes ocupied by Al + So tetrhederl holes ocupied by Mg + 8 O HO CH CH O O ( ). D CH C CH CH 5. A. C CH CH T H, CH CH C CH CHBr Br is wek bse, so it follows, dditio. 7. A, B, C Cr + is reducig get d itself oidises to Cr +. M + is oidizig get d reduces itself to M +. O 8. B, C, D I electrolysis process to obti copper, impure copper is mde ode while pure copper is mde cthode usig CuSO solutio. 9. A P, Q, S Siderite FeCO B T Mlchite Cu CO (OH) C Q, R Buite Al(OH) or Al O D R Clmie ZCO Argetite Ag S. A R, T B P, Q, S C P, Q, S D P, Q, S, T PART - III : MATHEMATICS. 8 Let be Beroulli RV, Probbility to chieve J heds i trils P [ j] C J p j ( p) Aj P [ ] P [ < ] P [] P [] f( ),f( + ) f( + ) f( ) < + + f() i derevig fuctio f 8 Now f(7) >. 8 9 f( 8) <. 5 mi 8. 5 C m C C 5C 5 m

7 . Equtio of orml t (,y ) to prbol y y y y t (, ) to y + y y ( ) r + Norml t (, ) to y ( ) y + ( ) y r + r. f( ) f + [ ], >, > <, >,,<, > [ ] +,+ f( + ), + > < < > 5. f I d + f + d+ + d+ I π F cos cos π cos + cos π f( ) d cos + cos + π f( ) d cos + cos + π π f( ) 8cos +. si + π cos( si) + cos + π f( ) cos 5 cos si cos si cos cos ( si cos ) si cos ( ) ( ) si + cos si cos si + cos si + si + si

8 5 5 si + + [ ] si,π totl solutios re Imge of y 5 bout + y + is, y t, y ± distce betwee A & B Distce betwee (, ) & (, ) 9.A,D ( ) f h ( ) hf 5. A, B, C g > the f ' g' > f g( ) < g' ( ) < h e > the h' e > e < e < ge the e g'e > > e g < g'e < ( f( h( ) )) ( ( )) ( f ) f( ) f() e f > the hf f'.e f > f e f < f'.e f < π π π f ( ) si si si & g( ) si π si π, π π.si π si π, π f( ), π π π f ( g( ) ) si si.si si, h f g f' lim g' π π π π cos si si..cos si. cos π π cos π π π π π g( f ( ) ) sisi.si si.si,.si 5. A, D, C Q 5. C, D c + b+ c P b R + b b+ c + b.c c b.c bccosθ θ.b b cos 5 7 θ b+ c ( b c) b b b + b bsi( ) 8 5. B, C C C C C C C ( +α) α ( + d) α ( + α) ( +α) α ( + d) α ( + α) ( +α) α ( + d) α ( + α)

9 +α + α + α α +α + α + α +α + α + α 5. A,D P t, t C C C O 5. B, D 55. A, B +α + α α α +α + α α +α + α α C C C +α α α +α α +α α ( +α) ( +α) α +α R R R R R R ( +α) α + α ( + α) α [ + α 8 α] 8α 8α 8α 8α α 8 α, 9, 9 t Q, t (Slope of OP) (Slope of OQ) t t Are of OPQ t t + t + t t t + t + t 7 t t tt t t ( )( ) t + t + 7 ( ) ( ) tt + t + t t t t + t t t + ( )( ) t t 8 t ±, ± P (, ), (, )

10 57. A, C + e y' + ye, If d e ( e + log ) e e + e e e e y' + y e + + e y. + e + k t, y k y 58. B, C + + e dy ( + e ) ( + ) e d + e Let h() + e e e h () e e e e ( + ) e < for (, ) h ( ) + e + e e > e h() + < the h () hs root i (, ) 59. (A) Projectio of α+βo i i ( i + j ) i + j α i +βi. α + β α + α + α α α+β (B) f( ) < b + for cotiuity b + < f' ( ) b for differetibility b +, (D) b + b b ( + b) () + q () + b 5 + q () b (5 + q) 5+ q b + q + 5+ q + + q 5 + q + + ( ) 5 + ( ) 7 + 5, ( q,5 5 q, A Q B P, Q C P, Q, R, S, T D Q, T. A P, R, S B P C P, Q D S, T......

is completely general whenever you have waves from two sources interfering. 2

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