Force and Motion. Force

Size: px
Start display at page:

Download "Force and Motion. Force"

Transcription

1 Force d Motio Cocept of Force Newto s hree Lws ypes of Forces Free body lysis Equilibrium Noequilibrium Frictio Problem Solvig Force A Force is push or pull tht is exerted o object by some other object. Forces c rise whe two objects touch ech other (but some forces ct over distce) Forces re vector qutities! Hd exerts force o Box Chpter 4 mteril 1

2 Clssifyig Forces Cotct forces c rise whe oe thig ctully touches other s i the cse of () force trsmitted through solid sprig or (b) the hdle of wgo, or (c) the mometry cotct betwee foot d footbll. Field forces re forces tht c ct t distce. Exmples re (d) the grvittiol force tht oe mss exerts o other, (e) the electrosttic force tht oe chrge exerts o other, d (f) the mgetic force tht mget exerts o piece of iro. Clssifyig Forces Four Bsic Forces of Nture: 1) Strog Nucler Force 2) Electromgetic Force 3) Wek Nucler Force 4) Grvittiol Forces We c clssify d qutify these forces by mesurig their effects i ture i the cotext of Newto s Lws of motio. Chpter 4 mteril 2

3 Newto s First Lw 1) A object t rest remis t rest, d object i motio cotiues i motio with costt velocity (tht is, i stright lie with costt speed) uless it experieces et exterl force. his priciple otes tht the tedecy of y object is resist y chge i its motio (i.e., to resist ccelertio) et exterl force mes the vector sum of ll the forces tht ct o object. If ΣF =0, the =0 he tedecy to resist chge i motio is clled ierti. he mesure of object s ierti is its mss. Newto s 2d Lw 2) he ccelertio of object is directly proportiol to the et force ctig o it d iversely proportiol to its mss I equtio form, this is expressed by the well-kow which is relly 3 equtios... ΣF = m ΣF x = m x, ΣF y = m y, ΣF z = m z oe for ech sclr compoet of the vector et force. Chpter 4 mteril 3

4 Newto s 2d Lw he reltioship betwee force, mss d ccelertio depicted by Newto s 2d Lw suggests turl uit for force: [F] =[m][]=m L/ 2 he SI uit of force is the ewto(n) 1 N = 1 kg m/s 2 So, force d mss hve differet uits. A object s mss is mesure of its ierti. A object s weight is mesure of how much grvittiol force the erth exerts o tht object. Newto s hird Lw 3) If two objects iterct, the force exerted o object 1 by object 2 is equl i mgitude but opposite i directio to the force exerted o object 2 by object 1. 1 F 12 F 21 2 F 12 = F 21 Chpter 4 mteril 4

5 Newto s hird Lw All forces come i pirs! If ctio force cts o oe object, there is rectio force tht cts o other object. he rectio force NEVER cts o the sme object tht the ctio force does!! Box exerts force o Hd Hd exerts force o Box F HB F BH F HB = F BH Newto s Lws of Motio 1) A object t rest remis t rest, d object i motio cotiues i motio with costt velocity (tht is, i stright lie with costt speed) uless it experieces et exterl force 2) he ccelertio of object is directly proportiol to the et force ctig o it d iversely proportiol to its mss 3) If two objects iterct, the force exerted o object 1 by object 2 is equl i mgitude but opposite i directio to the force exerted o object 2 by object 1. Chpter 4 mteril 5

6 ypes of Forces 1) Weight A object of mss m, er the surfce of the erth is subject to weight force, w=mg. his force is directed verticlly dowwrds towrds the groud. 2) Norml Force If two objects re i cotct, they my ech exert force o the other. he compoet of this cotct force tht is perpediculr (orml) to the surfces i cotct is clled orml force. Norml forces re lwys ted to push to objects prt, ever pull them together 3) esio Force Cbles, strigs d ropes c ll exert tesio force o the object to which the rope is ttched. his force is directed log the lie of the rope d is the sme mgitude throughout the legth of (mssless) rope. he directio of the rope my be chged by pulley, which will chge the directio of the force, but ot its mgitude. 5 kg w = 49 N Free Body Alysis Free body lysis is recipe for determiig ll the forces tht ct o mechicl system, d the determiig how the motio of the mechicl system is ffected by these forces. Equilibrium Exmple: A mss,, sits o horizotl frictioless surfce. It is ttched to wll by horizotl cble (1) d to hgig mss,, by other cble (2) which psses over the pulley. Wht is the tesio force i cble (1) d wht is the tesio force i cble (2)? (1) (2) Frictioless pulley Chpter 4 mteril 6

7 Blocks d pulley t rest Equilibrium Blocks d pulley t rest wo seprte systems Ech mss is system! Chpter 4 mteril 7

8 Blocks d pulley t rest Erth, Left Cble, m Right Cble, 2 ble top (4) Erth, Cble (2) Blocks d pulley t rest 1 w 1 Use third lw to determie y ctio-rectio pirs of forces. Here, the tesio force,, is the sme o ech block. w 2 Chpter 4 mteril 8

9 Blocks d pulley t rest 1 w 1 = 0 i this cse w 2 Blocks d pulley t rest 1 +y 1 w 1 Ech object my hve its ow coordite system. +x 1 w 2 +y 2 Chpter 4 mteril 9

10 Blocks d pulley t rest 1 +y 1 w 1 +x 1 w 2 +y 2 Blocks d pulley t rest Solve Newto s 2d Slidig mss: Hgig mss: +y 2 w 2 = g +y 1 Coclusio: 1 +x 1 w 1 = g 1 = = w 2 = g he tesio i ech rope is equl to the weight of the hgig mss. Chpter 4 mteril 10

11 Blocks d pulley i motio No-equilibrium We ow cut the cble holdig to the wll! Wht is the tesio i the remiig cble? Wht is the ccelertio of the blocks, d? Blocks d pulley i motio wo seprte systems Ech mss is system!. s before! Chpter 4 mteril 11

12 Blocks d pulley i motio Erth, Cble, ble top (3) Erth, Cble (2) Blocks d pulley i motio w 1 Use third lw to determie y ctio-rectio pirs of forces. Here, the tesio force,, is the sme o ech block. w 2 Chpter 4 mteril 12

13 Blocks d pulley i motio w 1 Ech block ccelertes with the sme mgitude,, but i differet directios. w 2 Blocks d pulley i motio +y 1 w 1 Ech object my hve its ow coordite system. It is coveiet to rrge thigs so tht both blocks hve positive ccelertio. +x 1 +y 2 w 2 Chpter 4 mteril 13

14 Blocks d pulley i motio +y 1 w 1 +x 1 w 2 +y 2 Blocks d pulley i motio Solve Newto s 2d Slidig mss: Hgig mss: Fy = m2 Fx = m 1 mg 2 = m 2 = m 1 +y 2 w 2 = g +y 1 +x 1 w 1 = g Coclusio: wo equtios i two ukows (, ) = g - = Solutios: mg 2 = m1 + m2 mmg 1 2 = m + m 1 2 Chpter 4 mteril 14

15 ) sttic frictio wo surfces i cotct resist the tedecy to begi slidig over ech other. his resistce force is clled sttic frictio, f s here is mximum mout of sttic frictio tht c be provided betwee two surfces. Its mgitude depeds oly o the ture of the mterils i cotct d how firmly they re pressed together. f s,mx = µ s µ s : coefficiet of sttic frictio : orml force b) kietic frictio Oce f s,mx is exceeded, the two surfces begi to slide over ech other, but they do t slide freely. he slidig motio is resisted by the force of kietic frictio, f k. he mgitude of f k is give by: f k = µ k µ k : coefficiet of kietic frictio : orml force Frictio ble: Coefficiets of frictio* Frictio µ s µ k Steel o steel Alumium o steel Copper o steel Rubber o cocrete Wood o wood Glss o glss Wxed wood o wet sow Wxed wood o dry sow Metl o metl (lubricted) Ice o ice eflo o teflo Syovil joits i hums he mgitude of the frictiol force depeds o the ture of the two surfces tht re i cotct. Some mterils re more sticky or slippery th others. he stickiess is expressed by the dimesioless coefficiet of frictio. Lots of frictio betwee rubber d cocrete Low frictio i syovil joits *Approximte vlues Chpter 4 mteril 15

16 Frictio Stick-slip Frictio for brss o brss A brss brick is plced o the bed of millig mchie (lso mde of brss.) he bed moves t costt speed to the left d drgs the brick with it util the force exerted by the sprig (ttched to the brick) exceeds f s,mx, t which poit, the brick slides to the right util sttic frictio tkes over gi d the brick sticks to the bed gi d the process repets. Chpter 4 mteril 16

Force and Motion. Force. Classifying Forces. Physics 11- Summer /21/01. Chapter 4 material 1. Forces are vector quantities!

Force and Motion. Force. Classifying Forces. Physics 11- Summer /21/01. Chapter 4 material 1. Forces are vector quantities! Force d Motio Cocept of Force Newto s hree Lws ypes of Forces Free body lysis Equilibrium Noequilibrium Frictio Problem Solvig Force A Force is push or pull tht is exerted o object by some other object.

More information

Graphing Review Part 3: Polynomials

Graphing Review Part 3: Polynomials Grphig Review Prt : Polomils Prbols Recll, tht the grph of f ( ) is prbol. It is eve fuctio, hece it is smmetric bout the bout the -is. This mes tht f ( ) f ( ). Its grph is show below. The poit ( 0,0)

More information

Vectors. Vectors in Plane ( 2

Vectors. Vectors in Plane ( 2 Vectors Vectors i Ple ( ) The ide bout vector is to represet directiol force Tht mes tht every vector should hve two compoets directio (directiol slope) d mgitude (the legth) I the ple we preset vector

More information

Lecture 38 (Trapped Particles) Physics Spring 2018 Douglas Fields

Lecture 38 (Trapped Particles) Physics Spring 2018 Douglas Fields Lecture 38 (Trpped Prticles) Physics 6-01 Sprig 018 Dougls Fields Free Prticle Solutio Schrödiger s Wve Equtio i 1D If motio is restricted to oe-dimesio, the del opertor just becomes the prtil derivtive

More information

Theorem 5.3 (Continued) The Fundamental Theorem of Calculus, Part 2: ab,, then. f x dx F x F b F a. a a. f x dx= f x x

Theorem 5.3 (Continued) The Fundamental Theorem of Calculus, Part 2: ab,, then. f x dx F x F b F a. a a. f x dx= f x x Chpter 6 Applictios Itegrtio Sectio 6. Regio Betwee Curves Recll: Theorem 5.3 (Cotiued) The Fudmetl Theorem of Clculus, Prt :,,, the If f is cotiuous t ever poit of [ ] d F is tiderivtive of f o [ ] (

More information

The momentum of a body of constant mass m moving with velocity u is, by definition, equal to the product of mass and velocity, that is

The momentum of a body of constant mass m moving with velocity u is, by definition, equal to the product of mass and velocity, that is Newtons Lws 1 Newton s Lws There re three lws which ber Newton s nme nd they re the fundmentls lws upon which the study of dynmics is bsed. The lws re set of sttements tht we believe to be true in most

More information

Dynamics: Newton s Laws of Motion

Dynamics: Newton s Laws of Motion Lecture 7 Chpter 4 Physics I 09.25.2013 Dynmics: Newton s Lws of Motion Solving Problems using Newton s lws Course website: http://fculty.uml.edu/andriy_dnylov/teching/physicsi Lecture Cpture: http://echo360.uml.edu/dnylov2013/physics1fll.html

More information

Add Maths Formulae List: Form 4 (Update 18/9/08)

Add Maths Formulae List: Form 4 (Update 18/9/08) Add Mths Formule List: Form 4 (Updte 8/9/08) 0 Fuctios Asolute Vlue Fuctio f ( ) f( ), if f( ) 0 f( ), if f( ) < 0 Iverse Fuctio If y f( ), the Rememer: Oject the vlue of Imge the vlue of y or f() f()

More information

SPH3UW Unit 7.5 Snell s Law Page 1 of Total Internal Reflection occurs when the incoming refraction angle is

SPH3UW Unit 7.5 Snell s Law Page 1 of Total Internal Reflection occurs when the incoming refraction angle is SPH3UW Uit 7.5 Sell s Lw Pge 1 of 7 Notes Physis Tool ox Refrtio is the hge i diretio of wve due to hge i its speed. This is most ommoly see whe wve psses from oe medium to other. Idex of refrtio lso lled

More information

GRAPHING LINEAR EQUATIONS. Linear Equations. x l ( 3,1 ) _x-axis. Origin ( 0, 0 ) Slope = change in y change in x. Equation for l 1.

GRAPHING LINEAR EQUATIONS. Linear Equations. x l ( 3,1 ) _x-axis. Origin ( 0, 0 ) Slope = change in y change in x. Equation for l 1. GRAPHING LINEAR EQUATIONS Qudrt II Qudrt I ORDERED PAIR: The first umer i the ordered pir is the -coordite d the secod umer i the ordered pir is the y-coordite. (, ) Origi ( 0, 0 ) _-is Lier Equtios Qudrt

More information

HIGHER SCHOOL CERTIFICATE EXAMINATION MATHEMATICS 3 UNIT (ADDITIONAL) AND 3/4 UNIT (COMMON) Time allowed Two hours (Plus 5 minutes reading time)

HIGHER SCHOOL CERTIFICATE EXAMINATION MATHEMATICS 3 UNIT (ADDITIONAL) AND 3/4 UNIT (COMMON) Time allowed Two hours (Plus 5 minutes reading time) HIGHER SCHOOL CERTIFICATE EXAMINATION 999 MATHEMATICS 3 UNIT (ADDITIONAL) AND 3/ UNIT (COMMON) Time llowed Two hours (Plus 5 miutes redig time) DIRECTIONS TO CANDIDATES Attempt ALL questios. ALL questios

More information

BC Calculus Review Sheet

BC Calculus Review Sheet BC Clculus Review Sheet Whe you see the words. 1. Fid the re of the ubouded regio represeted by the itegrl (sometimes 1 f ( ) clled horizotl improper itegrl). This is wht you thik of doig.... Fid the re

More information

The Definite Riemann Integral

The Definite Riemann Integral These otes closely follow the presettio of the mteril give i Jmes Stewrt s textook Clculus, Cocepts d Cotexts (d editio). These otes re iteded primrily for i-clss presettio d should ot e regrded s sustitute

More information

S. Socrate 2013 K. Qian

S. Socrate 2013 K. Qian S. Socrte 213 K. Qi odig Coditios o ech Sectio () pplied lodig oly log the is () of the br. The oly iterl resultt t y sectios is the il force N() Fid N()log the br (il force digrm) by cuttig the br t ech

More information

Phys101 Lecture 4,5 Dynamics: Newton s Laws of Motion

Phys101 Lecture 4,5 Dynamics: Newton s Laws of Motion Phys101 Lecture 4,5 Dynics: ewton s Lws of Motion Key points: ewton s second lw is vector eqution ction nd rection re cting on different objects ree-ody Digrs riction Inclines Ref: 4-1,2,3,4,5,6,7,8,9.

More information

PROBLEM Copyright McGraw-Hill Education. Permission required for reproduction or display. SOLUTION. v 1 = 4 km/hr = 1.

PROBLEM Copyright McGraw-Hill Education. Permission required for reproduction or display. SOLUTION. v 1 = 4 km/hr = 1. PROLEM 13.119 35,000 Mg ocea lier has a iitial velocity of 4 km/h. Neglectig the frictioal resistace of the water, determie the time required to brig the lier to rest by usig a sigle tugboat which exerts

More information

Content: Essential Calculus, Early Transcendentals, James Stewart, 2007 Chapter 1: Functions and Limits., in a set B.

Content: Essential Calculus, Early Transcendentals, James Stewart, 2007 Chapter 1: Functions and Limits., in a set B. Review Sheet: Chpter Cotet: Essetil Clculus, Erly Trscedetls, Jmes Stewrt, 007 Chpter : Fuctios d Limits Cocepts, Defiitios, Lws, Theorems: A fuctio, f, is rule tht ssigs to ech elemet i set A ectly oe

More information

BITSAT MATHEMATICS PAPER. If log 0.0( ) log 0.( ) the elogs to the itervl (, ] () (, ] [,+ ). The poit of itersectio of the lie joiig the poits i j k d i+ j+ k with the ple through the poits i+ j k, i

More information

PROGRESSIONS AND SERIES

PROGRESSIONS AND SERIES PROGRESSIONS AND SERIES A sequece is lso clled progressio. We ow study three importt types of sequeces: () The Arithmetic Progressio, () The Geometric Progressio, () The Hrmoic Progressio. Arithmetic Progressio.

More information

is completely general whenever you have waves from two sources interfering. 2

is completely general whenever you have waves from two sources interfering. 2 MAKNG SENSE OF THE EQUATON SHEET terferece & Diffrctio NTERFERENCE r1 r d si. Equtio for pth legth differece. r1 r is completely geerl. Use si oly whe the two sources re fr wy from the observtio poit.

More information

Chapter System of Equations

Chapter System of Equations hpter 4.5 System of Equtios After redig th chpter, you should be ble to:. setup simulteous lier equtios i mtrix form d vice-vers,. uderstd the cocept of the iverse of mtrix, 3. kow the differece betwee

More information

=> PARALLEL INTERCONNECTION. Basic Properties LTI Systems. The Commutative Property. Convolution. The Commutative Property. The Distributive Property

=> PARALLEL INTERCONNECTION. Basic Properties LTI Systems. The Commutative Property. Convolution. The Commutative Property. The Distributive Property Lier Time-Ivrit Bsic Properties LTI The Commuttive Property The Distributive Property The Associtive Property Ti -6.4 / Chpter Covolutio y ] x ] ] x ]* ] x ] ] y] y ( t ) + x( τ ) h( t τ ) dτ x( t) * h(

More information

Chapter 30: Reflection and Refraction

Chapter 30: Reflection and Refraction Chpter 30: Reflectio d Refrctio The ture of light Speed of light (i vcuum) c.9979458 x 0 8 m/s mesured ut it is ow the defiitio Michelso s 878 Rottig Mirror Experimet Germ Americ physicist A.A. Michelso

More information

16 Newton s Laws #3: Components, Friction, Ramps, Pulleys, and Strings

16 Newton s Laws #3: Components, Friction, Ramps, Pulleys, and Strings Chpter 16 Newton s Lws #3: Components, riction, Rmps, Pulleys, nd Strings 16 Newton s Lws #3: Components, riction, Rmps, Pulleys, nd Strings When, in the cse of tilted coordinte system, you brek up the

More information

HIGHER SCHOOL CERTIFICATE EXAMINATION MATHEMATICS 4 UNIT (ADDITIONAL) Time allowed Three hours (Plus 5 minutes reading time)

HIGHER SCHOOL CERTIFICATE EXAMINATION MATHEMATICS 4 UNIT (ADDITIONAL) Time allowed Three hours (Plus 5 minutes reading time) HIGHER SCHOOL CERTIFICATE EXAMINATION 998 MATHEMATICS 4 UNIT (ADDITIONAL) Time llowed Three hours (Plus 5 miutes redig time) DIRECTIONS TO CANDIDATES Attempt ALL questios ALL questios re of equl vlue All

More information

[Q. Booklet Number]

[Q. Booklet Number] 6 [Q. Booklet Numer] KOLKATA WB- B-J J E E - 9 MATHEMATICS QUESTIONS & ANSWERS. If C is the reflecto of A (, ) i -is d B is the reflectio of C i y-is, the AB is As : Hits : A (,); C (, ) ; B (, ) y A (,

More information

Correct answer: 0 m/s 2. Explanation: 8 N

Correct answer: 0 m/s 2. Explanation: 8 N Version 001 HW#3 - orces rts (00223) 1 his print-out should hve 15 questions. Multiple-choice questions my continue on the next column or pge find ll choices before nswering. Angled orce on Block 01 001

More information

Fig. 1. I a. V ag I c. I n. V cg. Z n Z Y. I b. V bg

Fig. 1. I a. V ag I c. I n. V cg. Z n Z Y. I b. V bg ymmetricl Compoets equece impedces Although the followig focuses o lods, the results pply eqully well to lies, or lies d lods. Red these otes together with sectios.6 d.9 of text. Cosider the -coected lced

More information

S(x)along the bar (shear force diagram) by cutting the bar at x and imposing force_y equilibrium.

S(x)along the bar (shear force diagram) by cutting the bar at x and imposing force_y equilibrium. mmetric leder Bems i Bedig Lodig Coditios o ech ectio () pplied -Forces & z-omets The resultts t sectio re: the bedig momet () d z re sectio smmetr es the sher force () [ for sleder bems stresses d deformtio

More information

Taylor Polynomials. The Tangent Line. (a, f (a)) and has the same slope as the curve y = f (x) at that point. It is the best

Taylor Polynomials. The Tangent Line. (a, f (a)) and has the same slope as the curve y = f (x) at that point. It is the best Tylor Polyomils Let f () = e d let p() = 1 + + 1 + 1 6 3 Without usig clcultor, evlute f (1) d p(1) Ok, I m still witig With little effort it is possible to evlute p(1) = 1 + 1 + 1 (144) + 6 1 (178) =

More information

Chapter Real Numbers

Chapter Real Numbers Chpter. - Rel Numbers Itegers: coutig umbers, zero, d the egtive of the coutig umbers. ex: {,-3, -, -,,,, 3, } Rtiol Numbers: quotiets of two itegers with ozero deomitor; termitig or repetig decimls. ex:

More information

Algebra II, Chapter 7. Homework 12/5/2016. Harding Charter Prep Dr. Michael T. Lewchuk. Section 7.1 nth roots and Rational Exponents

Algebra II, Chapter 7. Homework 12/5/2016. Harding Charter Prep Dr. Michael T. Lewchuk. Section 7.1 nth roots and Rational Exponents Algebr II, Chpter 7 Hrdig Chrter Prep 06-07 Dr. Michel T. Lewchuk Test scores re vilble olie. I will ot discuss the test. st retke opportuit Sturd Dec. If ou hve ot tke the test, it is our resposibilit

More information

13.4 Work done by Constant Forces

13.4 Work done by Constant Forces 13.4 Work done by Constnt Forces We will begin our discussion of the concept of work by nlyzing the motion of n object in one dimension cted on by constnt forces. Let s consider the following exmple: push

More information

Week 13 Notes: 1) Riemann Sum. Aim: Compute Area Under a Graph. Suppose we want to find out the area of a graph, like the one on the right:

Week 13 Notes: 1) Riemann Sum. Aim: Compute Area Under a Graph. Suppose we want to find out the area of a graph, like the one on the right: Week 1 Notes: 1) Riem Sum Aim: Compute Are Uder Grph Suppose we wt to fid out the re of grph, like the oe o the right: We wt to kow the re of the red re. Here re some wys to pproximte the re: We cut the

More information

In an algebraic expression of the form (1), like terms are terms with the same power of the variables (in this case

In an algebraic expression of the form (1), like terms are terms with the same power of the variables (in this case Chpter : Algebr: A. Bckgroud lgebr: A. Like ters: I lgebric expressio of the for: () x b y c z x y o z d x... p x.. we cosider x, y, z to be vribles d, b, c, d,,, o,.. to be costts. I lgebric expressio

More information

A wire. 100 kg. Fig. 1.1

A wire. 100 kg. Fig. 1.1 1 Fig. 1.1 shows circulr cylinder of mss 100 kg being rised by light, inextensible verticl wire. There is negligible ir resistnce. wire 100 kg Fig. 1.1 (i) lculte the ccelertion of the cylinder when the

More information

= 40 N. Q = 60 O m s,k

= 40 N. Q = 60 O m s,k Multiple Choice ( 6 Points Ech ): F pp = 40 N 20 kg Q = 60 O m s,k = 0 1. A 20 kg box is pulled long frictionless floor with n pplied force of 40 N. The pplied force mkes n ngle of 60 degrees with the

More information

Unit 1. Extending the Number System. 2 Jordan School District

Unit 1. Extending the Number System. 2 Jordan School District Uit Etedig the Number System Jord School District Uit Cluster (N.RN. & N.RN.): Etedig Properties of Epoets Cluster : Etedig properties of epoets.. Defie rtiol epoets d eted the properties of iteger epoets

More information

moment = m! x, where x is the length of the moment arm.

moment = m! x, where x is the length of the moment arm. th 1206 Clculus Sec. 6.7: omets d Ceters of ss I. Fiite sses A. Oe Dimesiol Cses 1. Itroductio Recll the differece etwee ss d Weight.. ss is the mout of "stuff" (mtter) tht mkes up oject.. Weight is mesure

More information

MATRIX ALGEBRA, Systems Linear Equations

MATRIX ALGEBRA, Systems Linear Equations MATRIX ALGEBRA, Systes Lier Equtios Now we chge to the LINEAR ALGEBRA perspective o vectors d trices to reforulte systes of lier equtios. If you fid the discussio i ters of geerl d gets lost i geerlity,

More information

ELLIPSE. 1. If the latus rectum of an ellipse be equal to half of its minor axis, then its eccentricity is [Karnataka CET 2000]

ELLIPSE. 1. If the latus rectum of an ellipse be equal to half of its minor axis, then its eccentricity is [Karnataka CET 2000] ELLIPSE. If the ltus rectum of ellipse e equl to hlf of its mior is, the its eccetricit is [Krtk CET 000] / / / d /. The legth of the ltus rectum of the ellipse is [MNR 7, 0, ] / / / d 0/. Eccetricit of

More information

Friction is a force that resists the motion between two objects in contact with one another.

Friction is a force that resists the motion between two objects in contact with one another. AP Physics rictio rictio! You ve heard that word, hec, maybe you ve eve used it. So what i the world is frictio? We've all heard about it ad blame it for all sorts of thigs. It is the cause of may problems,

More information

Exponents and Radical

Exponents and Radical Expoets d Rdil Rule : If the root is eve d iside the rdil is egtive, the the swer is o rel umber, meig tht If is eve d is egtive, the Beuse rel umber multiplied eve times by itself will be lwys positive.

More information

GRADE 12 SEPTEMBER 2016 MATHEMATICS P1

GRADE 12 SEPTEMBER 2016 MATHEMATICS P1 NATIONAL SENIOR CERTIFICATE GRADE SEPTEMBER 06 MATHEMATICS P MARKS: 50 TIME: 3 hours *MATHE* This questio pper cosists of pges icludig iformtio sheet MATHEMATICS P (EC/SEPTEMBER 06 INSTRUCTIONS AND INFORMATION

More information

2a a a 2a 4a. 3a/2 f(x) dx a/2 = 6i) Equation of plane OAB is r = λa + µb. Since C lies on the plane OAB, c can be expressed as c = λa +

2a a a 2a 4a. 3a/2 f(x) dx a/2 = 6i) Equation of plane OAB is r = λa + µb. Since C lies on the plane OAB, c can be expressed as c = λa + -6-5 - - - - 5 6 - - - - - - / GCE A Level H Mths Nov Pper i) z + z 6 5 + z 9 From GC, poit of itersectio ( 8, 9 6, 5 ). z + z 6 5 9 From GC, there is o solutio. So p, q, r hve o commo poits of itersectio.

More information

334 MATHS SERIES DSE MATHS PREVIEW VERSION B SAMPLE TEST & FULL SOLUTION

334 MATHS SERIES DSE MATHS PREVIEW VERSION B SAMPLE TEST & FULL SOLUTION MATHS SERIES DSE MATHS PREVIEW VERSION B SAMPLE TEST & FULL SOLUTION TEST SAMPLE TEST III - P APER Questio Distributio INSTRUCTIONS:. Attempt ALL questios.. Uless otherwise specified, ll worig must be

More information

Chapter 10: The Z-Transform Adapted from: Lecture notes from MIT, Binghamton University Dr. Hamid R. Rabiee Fall 2013

Chapter 10: The Z-Transform Adapted from: Lecture notes from MIT, Binghamton University Dr. Hamid R. Rabiee Fall 2013 Sigls & Systems Chpter 0: The Z-Trsform Adpted from: Lecture otes from MIT, Bighmto Uiversity Dr. Hmid R. Rbiee Fll 03 Lecture 5 Chpter 0 Lecture 6 Chpter 0 Outlie Itroductio to the -Trsform Properties

More information

Closed Newton-Cotes Integration

Closed Newton-Cotes Integration Closed Newto-Cotes Itegrtio Jmes Keeslig This documet will discuss Newto-Cotes Itegrtio. Other methods of umericl itegrtio will be discussed i other posts. The other methods will iclude the Trpezoidl Rule,

More information

Mathematics Extension 2

Mathematics Extension 2 05 Bored of Studies Tril Emitios Mthemtics Etesio Writte by Crrotsticks & Trebl Geerl Istructios Totl Mrks 00 Redig time 5 miutes. Workig time 3 hours. Write usig blck or blue pe. Blck pe is preferred.

More information

( a n ) converges or diverges.

( a n ) converges or diverges. Chpter Ifiite Series Pge of Sectio E Rtio Test Chpter : Ifiite Series By the ed of this sectio you will be ble to uderstd the proof of the rtio test test series for covergece by pplyig the rtio test pprecite

More information

MA123, Chapter 9: Computing some integrals (pp )

MA123, Chapter 9: Computing some integrals (pp ) MA13, Chpter 9: Computig some itegrls (pp. 189-05) Dte: Chpter Gols: Uderstd how to use bsic summtio formuls to evlute more complex sums. Uderstd how to compute its of rtiol fuctios t ifiity. Uderstd how

More information

sin m a d F m d F m h F dy a dy a D h m h m, D a D a c1cosh c3cos 0

sin m a d F m d F m h F dy a dy a D h m h m, D a D a c1cosh c3cos 0 Q1. The free vibrtio of the plte is give by By ssumig h w w D t, si cos w W x y t B t Substitutig the deflectio ito the goverig equtio yields For the plte give, the mode shpe W hs the form h D W W W si

More information

10.5 Power Series. In this section, we are going to start talking about power series. A power series is a series of the form

10.5 Power Series. In this section, we are going to start talking about power series. A power series is a series of the form 0.5 Power Series I the lst three sectios, we ve spet most of tht time tlkig bout how to determie if series is coverget or ot. Now it is time to strt lookig t some specific kids of series d we will evetully

More information

Particle in a Box. and the state function is. In this case, the Hermitian operator. The b.c. restrict us to 0 x a. x A sin for 0 x a, and 0 otherwise

Particle in a Box. and the state function is. In this case, the Hermitian operator. The b.c. restrict us to 0 x a. x A sin for 0 x a, and 0 otherwise Prticle i Box We must hve me where = 1,,3 Solvig for E, π h E = = where = 1,,3, m 8m d the stte fuctio is x A si for 0 x, d 0 otherwise x ˆ d KE V. m dx I this cse, the Hermiti opertor 0iside the box The

More information

National Quali cations AHEXEMPLAR PAPER ONLY

National Quali cations AHEXEMPLAR PAPER ONLY Ntiol Quli ctios AHEXEMPLAR PAPER ONLY EP/AH/0 Mthemtics Dte Not pplicble Durtio hours Totl mrks 00 Attempt ALL questios. You my use clcultor. Full credit will be give oly to solutios which coti pproprite

More information

Things I Should Know In Calculus Class

Things I Should Know In Calculus Class Thigs I Should Kow I Clculus Clss Qudrtic Formul = 4 ± c Pythgore Idetities si cos t sec cot csc + = + = + = Agle sum d differece formuls ( ) ( ) si ± y = si cos y± cos si y cos ± y = cos cos ym si si

More information

: : 8.2. Test About a Population Mean. STT 351 Hypotheses Testing Case I: A Normal Population with Known. - null hypothesis states 0

: : 8.2. Test About a Population Mean. STT 351 Hypotheses Testing Case I: A Normal Population with Known. - null hypothesis states 0 8.2. Test About Popultio Me. Cse I: A Norml Popultio with Kow. H - ull hypothesis sttes. X1, X 2,..., X - rdom smple of size from the orml popultio. The the smple me X N, / X X Whe H is true. X 8.2.1.

More information

Lecture 8. Newton s Laws. Applications of the Newton s Laws Problem-Solving Tactics. Physics 105; Fall Inertial Frames: T = mg

Lecture 8. Newton s Laws. Applications of the Newton s Laws Problem-Solving Tactics. Physics 105; Fall Inertial Frames: T = mg Lecture 8 Applictions of the ewton s Lws Problem-Solving ctics http://web.njit.edu/~sireno/ ewton s Lws I. If no net force ocects on body, then the body s velocity cnnot chnge. II. he net force on body

More information

F x = 2x λy 2 z 3 = 0 (1) F y = 2y λ2xyz 3 = 0 (2) F z = 2z λ3xy 2 z 2 = 0 (3) F λ = (xy 2 z 3 2) = 0. (4) 2z 3xy 2 z 2. 2x y 2 z 3 = 2y 2xyz 3 = ) 2

F x = 2x λy 2 z 3 = 0 (1) F y = 2y λ2xyz 3 = 0 (2) F z = 2z λ3xy 2 z 2 = 0 (3) F λ = (xy 2 z 3 2) = 0. (4) 2z 3xy 2 z 2. 2x y 2 z 3 = 2y 2xyz 3 = ) 2 0 微甲 07- 班期中考解答和評分標準 5%) Fid the poits o the surfce xy z = tht re closest to the origi d lso the shortest distce betwee the surfce d the origi Solutio Cosider the Lgrge fuctio F x, y, z, λ) = x + y + z

More information

[ 20 ] 1. Inequality exists only between two real numbers (not complex numbers). 2. If a be any real number then one and only one of there hold.

[ 20 ] 1. Inequality exists only between two real numbers (not complex numbers). 2. If a be any real number then one and only one of there hold. [ 0 ]. Iequlity eists oly betwee two rel umbers (ot comple umbers).. If be y rel umber the oe d oly oe of there hold.. If, b 0 the b 0, b 0.. (i) b if b 0 (ii) (iii) (iv) b if b b if either b or b b if

More information

ALGEBRA II CHAPTER 7 NOTES. Name

ALGEBRA II CHAPTER 7 NOTES. Name ALGEBRA II CHAPTER 7 NOTES Ne Algebr II 7. th Roots d Rtiol Expoets Tody I evlutig th roots of rel ubers usig both rdicl d rtiol expoet ottio. I successful tody whe I c evlute th roots. It is iportt for

More information

We will begin by supplying the proof to (a).

We will begin by supplying the proof to (a). (The solutios of problem re mostly from Jeffrey Mudrock s HWs) Problem 1. There re three sttemet from Exmple 5.4 i the textbook for which we will supply proofs. The sttemets re the followig: () The spce

More information

 n. A Very Interesting Example + + = d. + x3. + 5x4. math 131 power series, part ii 7. One of the first power series we examined was. 2!

 n. A Very Interesting Example + + = d. + x3. + 5x4. math 131 power series, part ii 7. One of the first power series we examined was. 2! mth power series, prt ii 7 A Very Iterestig Emple Oe of the first power series we emied ws! + +! + + +!! + I Emple 58 we used the rtio test to show tht the itervl of covergece ws (, ) Sice the series coverges

More information

Impedance Matching Equation: Developed Using Wheeler s Methodology

Impedance Matching Equation: Developed Using Wheeler s Methodology Impedce Mtchig Equtio: Developed Usig Wheeler s Methodology IEEE Log Isld Sectio Ates & Propgtio Society Presettio December 4, 0 y Alfred R. Lopez Outlie. ckgroud Iformtio. The Impedce Mtchig Equtio. The

More information

Mathematics Extension 2

Mathematics Extension 2 04 Bored of Studies Tril Emitios Mthemtics Etesio Writte b Crrotsticks & Trebl Geerl Istructios Totl Mrks 00 Redig time 5 miutes. Workig time 3 hours. Write usig blck or blue pe. Blck pe is preferred.

More information

Section 6.3: Geometric Sequences

Section 6.3: Geometric Sequences 40 Chpter 6 Sectio 6.: Geometric Sequeces My jobs offer ul cost-of-livig icrese to keep slries cosistet with ifltio. Suppose, for exmple, recet college grdute fids positio s sles mger erig ul slry of $6,000.

More information

Impedance Matching Equation: Developed Using Wheeler s Methodology

Impedance Matching Equation: Developed Using Wheeler s Methodology Impedce Mtchig Equtio: Developed Usig Wheeler s Methodology IEEE Log Isld Sectio Ates & Propgtio Society Presettio December 4, 03 By Alfred R. Lopez Outlie. Bckgroud Iformtio. The Impedce Mtchig Equtio

More information

Name: A2RCC Midterm Review Unit 1: Functions and Relations Know your parent functions!

Name: A2RCC Midterm Review Unit 1: Functions and Relations Know your parent functions! Nme: ARCC Midterm Review Uit 1: Fuctios d Reltios Kow your pret fuctios! 1. The ccompyig grph shows the mout of rdio-ctivity over time. Defiitio of fuctio. Defiitio of 1-1. Which digrm represets oe-to-oe

More information

Chapter Real Numbers

Chapter Real Numbers Chpter. - Rel Numbers Itegers: coutig umbers, zero, d the egtive of the coutig umbers. ex: {,-3, -, -, 0,,, 3, } Rtiol Numbers: quotiets of two itegers with ozero deomitor; termitig or repetig decimls.

More information

PhysicsAndMathsTutor.com

PhysicsAndMathsTutor.com PhysicsAdMthsTutor.com PhysicsAdMthsTutor.com Jue 009 4. Give tht y rsih ( ), > 0, () fid d y d, givig your swer s simplified frctio. () Leve lk () Hece, or otherwise, fid 4 d, 4 [ ( )] givig your swer

More information

Handout #2. Introduction to Matrix: Matrix operations & Geometric meaning

Handout #2. Introduction to Matrix: Matrix operations & Geometric meaning Hdout # Title: FAE Course: Eco 8/ Sprig/5 Istructor: Dr I-Mig Chiu Itroductio to Mtrix: Mtrix opertios & Geometric meig Mtrix: rectgulr rry of umers eclosed i pretheses or squre rckets It is covetiolly

More information

MTH 146 Class 16 Notes

MTH 146 Class 16 Notes MTH 46 Clss 6 Notes 0.4- Cotiued Motivtio: We ow cosider the rc legth of polr curve. Suppose we wish to fid the legth of polr curve curve i terms of prmetric equtios s: r f where b. We c view the cos si

More information

Discrete Mathematics I Tutorial 12

Discrete Mathematics I Tutorial 12 Discrete Mthemtics I Tutoril Refer to Chpter 4., 4., 4.4. For ech of these sequeces fid recurrece reltio stisfied by this sequece. (The swers re ot uique becuse there re ifiitely my differet recurrece

More information

Mathematics [Summary]

Mathematics [Summary] Mthemtics [Summry] Uits d Coversios. m = 00 cm. km = 000 m 3. cm = 0 mm 4. mi = 60 s 5. h = 60 mi = 3600 s 6. kg = 000 g 7. to = 000 kg 8. litre = 000 ml = 000 cm 3 9. $ = 00 0. 3.6 km/h = m/s. m = 0 000

More information

EXPONENTS AND LOGARITHMS

EXPONENTS AND LOGARITHMS 978--07-6- Mthemtis Stdrd Level for IB Diplom Eerpt EXPONENTS AND LOGARITHMS WHAT YOU NEED TO KNOW The rules of epoets: m = m+ m = m ( m ) = m m m = = () = The reltioship etwee epoets d rithms: = g where

More information

The Exponential Function

The Exponential Function The Epoetil Fuctio Defiitio: A epoetil fuctio with bse is defied s P for some costt P where 0 d. The most frequetly used bse for epoetil fuctio is the fmous umber e.788... E.: It hs bee foud tht oyge cosumptio

More information

Fast Fourier Transform 1) Legendre s Interpolation 2) Vandermonde Matrix 3) Roots of Unity 4) Polynomial Evaluation

Fast Fourier Transform 1) Legendre s Interpolation 2) Vandermonde Matrix 3) Roots of Unity 4) Polynomial Evaluation Algorithm Desig d Alsis Victor Admchi CS 5-45 Sprig 4 Lecture 3 J 7, 4 Cregie Mello Uiversit Outlie Fst Fourier Trsform ) Legedre s Iterpoltio ) Vdermode Mtri 3) Roots of Uit 4) Polomil Evlutio Guss (777

More information

8.1 Arc Length. What is the length of a curve? How can we approximate it? We could do it following the pattern we ve used before

8.1 Arc Length. What is the length of a curve? How can we approximate it? We could do it following the pattern we ve used before 8.1 Arc Legth Wht is the legth of curve? How c we pproximte it? We could do it followig the ptter we ve used efore Use sequece of icresigly short segmets to pproximte the curve: As the segmets get smller

More information

DETERMINANT. = 0. The expression a 1. is called a determinant of the second order, and is denoted by : y + c 1

DETERMINANT. = 0. The expression a 1. is called a determinant of the second order, and is denoted by : y + c 1 NOD6 (\Dt\04\Kot\J-Advced\SMP\Mths\Uit#0\NG\Prt-\0.Determits\0.Theory.p65. INTRODUCTION : If the equtios x + b 0, x + b 0 re stisfied by the sme vlue of x, the b b 0. The expressio b b is clled determit

More information

The limit comparison test

The limit comparison test Roerto s Notes o Ifiite Series Chpter : Covergece tests Sectio 4 The limit compriso test Wht you eed to kow lredy: Bsics of series d direct compriso test. Wht you c ler here: Aother compriso test tht does

More information

General properties of definite integrals

General properties of definite integrals Roerto s Notes o Itegrl Clculus Chpter 4: Defiite itegrls d the FTC Sectio Geerl properties of defiite itegrls Wht you eed to kow lredy: Wht defiite Riem itegrl is. Wht you c ler here: Some key properties

More information

Lesson-2 PROGRESSIONS AND SERIES

Lesson-2 PROGRESSIONS AND SERIES Lesso- PROGRESSIONS AND SERIES Arithmetic Progressio: A sequece of terms is sid to be i rithmetic progressio (A.P) whe the differece betwee y term d its preceedig term is fixed costt. This costt is clled

More information

0 otherwise. sin( nx)sin( kx) 0 otherwise. cos( nx) sin( kx) dx 0 for all integers n, k.

0 otherwise. sin( nx)sin( kx) 0 otherwise. cos( nx) sin( kx) dx 0 for all integers n, k. . Computtio of Fourier Series I this sectio, we compute the Fourier coefficiets, f ( x) cos( x) b si( x) d b, i the Fourier series To do this, we eed the followig result o the orthogolity of the trigoometric

More information

Chapter 7 Infinite Series

Chapter 7 Infinite Series MA Ifiite Series Asst.Prof.Dr.Supree Liswdi Chpter 7 Ifiite Series Sectio 7. Sequece A sequece c be thought of s list of umbers writte i defiite order:,,...,,... 2 The umber is clled the first term, 2

More information

Prior distributions. July 29, 2002

Prior distributions. July 29, 2002 Prior distributios Aledre Tchourbov PKI 357, UNOmh, South 67th St. Omh, NE 688-694, USA Phoe: 4554-64 E-mil: tchourb@cse.ul.edu July 9, Abstrct This documet itroduces prior distributios for the purposes

More information

1. The 0.1 kg particle has a speed v = 10 m/s as it passes the 30 position shown. The coefficient of kinetic friction between the particle and the

1. The 0.1 kg particle has a speed v = 10 m/s as it passes the 30 position shown. The coefficient of kinetic friction between the particle and the 1. The 0.1 kg pticle h peed v = 10 m/ it pe the 30 poitio how. The coefficiet of kietic fictio betwee the pticle d the veticl ple tck i m k = 0.0. Detemie the mgitude of the totl foce exeted by the tck

More information

Similar idea to multiplication in N, C. Divide and conquer approach provides unexpected improvements. Naïve matrix multiplication

Similar idea to multiplication in N, C. Divide and conquer approach provides unexpected improvements. Naïve matrix multiplication Next. Covered bsics of simple desig techique (Divided-coquer) Ch. of the text.. Next, Strsse s lgorithm. Lter: more desig d coquer lgorithms: MergeSort. Solvig recurreces d the Mster Theorem. Similr ide

More information

Options: Calculus. O C.1 PG #2, 3b, 4, 5ace O C.2 PG.24 #1 O D PG.28 #2, 3, 4, 5, 7 O E PG #1, 3, 4, 5 O F PG.

Options: Calculus. O C.1 PG #2, 3b, 4, 5ace O C.2 PG.24 #1 O D PG.28 #2, 3, 4, 5, 7 O E PG #1, 3, 4, 5 O F PG. O C. PG.-3 #, 3b, 4, 5ce O C. PG.4 # Optios: Clculus O D PG.8 #, 3, 4, 5, 7 O E PG.3-33 #, 3, 4, 5 O F PG.36-37 #, 3 O G. PG.4 #c, 3c O G. PG.43 #, O H PG.49 #, 4, 5, 6, 7, 8, 9, 0 O I. PG.53-54 #5, 8

More information

Pre-Calculus - Chapter 3 Sections Notes

Pre-Calculus - Chapter 3 Sections Notes Pre-Clculus - Chpter 3 Sectios 3.1-3.4- Notes Properties o Epoets (Review) 1. ( )( ) = + 2. ( ) =, (c) = 3. 0 = 1 4. - = 1/( ) 5. 6. c Epoetil Fuctios (Sectio 3.1) Deiitio o Epoetil Fuctios The uctio deied

More information

Math 8 Winter 2015 Applications of Integration

Math 8 Winter 2015 Applications of Integration Mth 8 Winter 205 Applictions of Integrtion Here re few importnt pplictions of integrtion. The pplictions you my see on n exm in this course include only the Net Chnge Theorem (which is relly just the Fundmentl

More information

SM2H. Unit 2 Polynomials, Exponents, Radicals & Complex Numbers Notes. 3.1 Number Theory

SM2H. Unit 2 Polynomials, Exponents, Radicals & Complex Numbers Notes. 3.1 Number Theory SMH Uit Polyomils, Epoets, Rdicls & Comple Numbers Notes.1 Number Theory .1 Addig, Subtrctig, d Multiplyig Polyomils Notes Moomil: A epressio tht is umber, vrible, or umbers d vribles multiplied together.

More information

Second Mean Value Theorem for Integrals By Ng Tze Beng. The Second Mean Value Theorem for Integrals (SMVT) Statement of the Theorem

Second Mean Value Theorem for Integrals By Ng Tze Beng. The Second Mean Value Theorem for Integrals (SMVT) Statement of the Theorem Secod Me Vlue Theorem for Itegrls By Ng Tze Beg This rticle is out the Secod Me Vlue Theorem for Itegrls. This theorem, first proved y Hoso i its most geerlity d with extesio y ixo, is very useful d lmost

More information

( ) k ( ) 1 T n 1 x = xk. Geometric series obtained directly from the definition. = 1 1 x. See also Scalars 9.1 ADV-1: lim n.

( ) k ( ) 1 T n 1 x = xk. Geometric series obtained directly from the definition. = 1 1 x. See also Scalars 9.1 ADV-1: lim n. Sclrs-9.0-ADV- Algebric Tricks d Where Tylor Polyomils Come From 207.04.07 A.docx Pge of Algebric tricks ivolvig x. You c use lgebric tricks to simplify workig with the Tylor polyomils of certi fuctios..

More information

SOLUTION OF SYSTEM OF LINEAR EQUATIONS. Lecture 4: (a) Jacobi's method. method (general). (b) Gauss Seidel method.

SOLUTION OF SYSTEM OF LINEAR EQUATIONS. Lecture 4: (a) Jacobi's method. method (general). (b) Gauss Seidel method. SOLUTION OF SYSTEM OF LINEAR EQUATIONS Lecture 4: () Jcobi's method. method (geerl). (b) Guss Seidel method. Jcobi s Method: Crl Gustv Jcob Jcobi (804-85) gve idirect method for fidig the solutio of system

More information

1.3 Continuous Functions and Riemann Sums

1.3 Continuous Functions and Riemann Sums mth riem sums, prt 0 Cotiuous Fuctios d Riem Sums I Exmple we sw tht lim Lower() = lim Upper() for the fuctio!! f (x) = + x o [0, ] This is o ccidet It is exmple of the followig theorem THEOREM Let f be

More information

Chapter #5 EEE Control Systems

Chapter #5 EEE Control Systems Sprig EEE Chpter #5 EEE Cotrol Sytem Deig Bed o Root Locu Chpter / Sprig EEE Deig Bed Root Locu Led Cotrol (equivlet to PD cotrol) Ued whe the tedy tte propertie of the ytem re ok but there i poor performce,

More information

Set 1 Paper 2. 1 Pearson Education Asia Limited 2014

Set 1 Paper 2. 1 Pearson Education Asia Limited 2014 . C. A. C. B 5. C 6. A 7. D 8. B 9. C 0. C. D. B. A. B 5. C 6. C 7. C 8. B 9. C 0. A. A. C. B. A 5. C 6. C 7. B 8. D 9. B 0. C. B. B. D. D 5. D 6. C 7. B 8. B 9. A 0. D. D. B. A. C 5. C Set Pper Set Pper

More information

,... are the terms of the sequence. If the domain consists of the first n positive integers only, the sequence is a finite sequence.

,... are the terms of the sequence. If the domain consists of the first n positive integers only, the sequence is a finite sequence. Chpter 9 & 0 FITZGERALD MAT 50/5 SECTION 9. Sequece Defiitio A ifiite sequece is fuctio whose domi is the set of positive itegers. The fuctio vlues,,, 4,...,,... re the terms of the sequece. If the domi

More information

Crushed Notes on MATH132: Calculus

Crushed Notes on MATH132: Calculus Mth 13, Fll 011 Siyg Yg s Outlie Crushed Notes o MATH13: Clculus The otes elow re crushed d my ot e ect This is oly my ow cocise overview of the clss mterils The otes I put elow should ot e used to justify

More information

Section 4.8. D v(t j 1 ) t. (4.8.1) j=1

Section 4.8. D v(t j 1 ) t. (4.8.1) j=1 Difference Equtions to Differentil Equtions Section.8 Distnce, Position, nd the Length of Curves Although we motivted the definition of the definite integrl with the notion of re, there re mny pplictions

More information