ME 375 FINAL EXAM Friday, May 6, 2005

Size: px
Start display at page:

Download "ME 375 FINAL EXAM Friday, May 6, 2005"

Transcription

1 ME 375 FINAL EXAM Friay, May 6, 005 Divisio: Kig 11:30 / Cuigham :30 (circle oe) Name: Istructios (1) This is a close book examiatio, but you are allowe three crib sheets. () You have two hours to work all the problems o the exam. (3) Use the solutio proceure we have iscusse: what are you give, what are you aske to fi, what are your assumptios, what is your solutio, oes your solutio make sese. You must show all of your work to receive ay creit. (4) You must write eatly a shoul use a logical format to solve the problems. You are ecourage to really thik about the problems before you start to solve them. Please write your ame i the top right-ha corer of each page. (5) A table of Laplace trasform pairs a properties of Laplace trasforms is attache at the e of this exam set. Sectio A Sectio B Problems Score Problems Score 1. (10) 1. (5). (6). (0) 3. (6) 3. (30) 4. (6) 4. (5) 5. (8) 6. (15) 7. (15) 8. (6) 9. (6) 10. (8) 11. (6) 1. (8) Total (A) /100 Total (B) /100 Total (A+B) /00

2 December 7, 005 Name A.1 (10%) Usig Laplace trasforms, fi the total respose ( t) of motio give by: whe the iput () t y + 8 y + 16y = 3u 0 = y 0 =. u is a uit step, y ( ) 0, a ( ) 0 y of a system with the equatio

3 December 7, 005 Name 3 A. (6%) A two-egree-of-freeom mechaical system is escribe by the followig two ifferetial equatios: x1+ 3x 1 x + 5x1 5x = 0 4 x x + 3x 5x + 5x = F 1 1 Write the equatios i Laplace omai a explai how to etermie the trasfer fuctio X 1 (s)/f(s) A.3 (6%) The motio of a system is govere by y + 4 y + 9y = 7u, where y is the output of the system a u is the iput of the system. Give the trasfer fuctio from the iput to the output. Next, fi the poles of the trasfer fuctio a etermie the stability of this system, givig a brief explaatio.

4 December 7, 005 Name 4 A.4 (6%) A seco orer system is escribe by y + y + 5y = 0u( t), where y is the output of the system, a u is the iput of the system. Fi the atural frequecy, ampig ratio, a static gai of this system. A.5 (8%) The steay-state torque-spee relatioship for a c motor is give by the followig formula: KT RAB + KT K b TL = ei ωss RA RA where e i is the omial iput voltage. Give the torque costat, K T, the back emf costat, K b, a the spee loa map below, calculate the armature resistace, R, a the bearig ampig, B. A K T K b N m = amp V sec = ra T L N m e i = 6 V ra 37 sec ω ss

5 December 7, 005 Name 5 A.6 (15%) Draw a iagram of a aalogous mass-sprig-amper mechaical system for the electrical system show i the figure below. Assume force is the effort variable a velocity is the flow variable.

6 December 7, 005 Name 6 A.7 (15%) As a egieer for a appliace maufacturer, you ee to moel a turkey roastig i a covectio ove. The covective air flow i the ove is kept at the set temperature, T ove, the covective heat trasfer coefficiet is hove bir, a the turkey has a heat trasfer area, A bir. Assume that as the turkey cooks its temperature is uiform throughout, T bir. hove bir, Abir T bir T ove (a) Derive the ifferetial equatio that escribes the evolutio of the temperature of the roastig turkey, T bir, where the iput is T ove. (Assume the turkey has heat capacity c p a mass m bir.) (b) I terms of the moel parameters you efie i (a), how log oes it take for the turkey temperature, T bir, to rise to withi 1% of its fial temperature?

7 December 7, 005 Name 7 A.8 (6%) Use block iagram methos to fi the correspoig G(s) for a uity feeback system give the o-uity feeback system show i the figure. A.9 (6%) The performace requiremets of a automotive cruise cotrol are less tha percet overshoot a lest tha secos two-percet settlig time. Sketch the regio that satisfies these performace criteria o the complex plae below Imagiary Axis Real Axis

8 December 7, 005 Name 8 A.10 (8%) Fi the steay-state respose y ss (t) of a system with trasfer fuctio 0 G ( s) = whe the iput is u ( t) = si(5t). Make sure you compute all require terms. s + s + 5 A.11 (6%) Give the followig trasfer fuctio: y(t) is the output a u(t) is the iput. s + 6 G ( s) =, etermie the ODE if s + s + 5

9 December 7, 005 Name 9 A.1 (8%) The step respose of a staar seco-orer system (assume ζ < 1) with iitial coitios is give by K ω 1 s y( 0) + y ( 0) + ζω y( 0) Y () s = + s + ζω + ω s s + ζω + ω where ω = ω 1 ζ. ( ) The Partial Fractio Expasio for this system is give below. ( ) Y () s = A + s s + ( 0) + ζω y( 0) B ω C ( s + ζω ) y( 0) ( s + ζω ) ω ζω s + ω ( s + ζω ) ( ) s + ω s + ζω ζω + ω + s + ω y ω (a) Above the Partial Fractio Expasio, ietify the free a force portios of the respose. (b) Below the Partial Fractio Expasio, ietify the trasiet a steay-state portios of the respose.

10 December 7, 005 Name 10 B.1 (5%) Sketch the root locus for the followig close-loop characteristic equatio: ( s + 5) 1+ K = 0 s + 4 s + 16 Be sure to calculate (a clearly label) ay asympototes, break-i/break-away poits, arrival/eparture agles, a imagiary axis crossigs (if ay) Imagiary Axis Real Axis State the rage of gai K for which this system is stable.

11 December 7, 005 Name 11

12 December 7, 005 Name 1 B. (0%) Give the followig Boe iagram etermie the trasfer fuctio:

13 December 7, 005 Name 13 B.3 (30%) Give the followig c motor feeback system with cotroller C () s, R(s) + E(s) - C() s 1 s s ( + ) Y(s) esig a PD cotroller, C() s K K s = +, usig the followig steps. p (a) Determie the esire performace regio o the complex plae below usig the followig performace criteria: t s % 1sec % OS 5% Imagiary Axis Real Axis

14 December 7, 005 Name 14 (b) Use the itersectio poits of the performace costrait lies as the esire close-loop pole locatios, p 1 a p, a use these to write the esire close-loop characteristic equatio. (Hit: ( s + p1 ) ( s + p ) = 0 where p 1 a p may be complex cojugates.) Multiply the equatio out to get a sigle polyomial. (c) Write out the actual close-loop characteristic equatio where you let C() s K + K s Leave K p a K as variables i your polyomial. =. p () Compare coefficiets betwee the esire close-loop characteristic equatio a the actual close-loop characteristic equatio to calculate the values for K a K. This metho esures that the root locus will pass through the esire close-loop pole locatios. p

15 December 7, 005 Name 15 (f) Fially, usig the values for K p a system. Remember that C() s K s + p = K ( s a) efie by K you calculate i () raw the root locus for this K = + K such that the cotroller gai is K a = p. K K = K a the cotroller zero locatio is efie by

16 December 7, 005 Name 16 B.4 (5%) Give the followig mechaical system: (a) Draw the free boy iagrams: (b) Write the elemetal equatios (c) Determie the equatios of motios

17 December 7, 005 Name 17 Laplace Trasform Pairs f F (s) Commet () t δ () t 1 Uit Impulse 1 for t > 0 t for > 0 1 s 1 s t at e si ( ωt) cos ( ωt) () t s s 1 s + a ω + ω s + ω Uit Step Uit Ramp Expoetial Sie Cosie f F (s) Fuctio f () t t f t () t s ( s) f ( 0 ) sf First Derivative 1 f 0 th F () ( ) ( ) s s f 0 s! s t + 1 f () t F ( s + a ) e at at te ( ) t e at e at si ωt 1 s + a! + ( s + a) 1 ( ) ( s + a) + ω ( s + a) cos( ) ( s + a) + ω e at ωt + Iitial Value Theorem f ( 0 ) = lim sf( s) ω s Fial Value Theorem lim f ( t) = lim sf( s) t s 0 t Derivative

Course Outline. Problem Identification. Engineering as Design. Amme 3500 : System Dynamics and Control. System Response. Dr. Stefan B.

Course Outline. Problem Identification. Engineering as Design. Amme 3500 : System Dynamics and Control. System Response. Dr. Stefan B. Course Outlie Amme 35 : System Dyamics a Cotrol System Respose Week Date Cotet Assigmet Notes Mar Itrouctio 8 Mar Frequecy Domai Moellig 3 5 Mar Trasiet Performace a the s-plae 4 Mar Block Diagrams Assig

More information

Dynamic Response of Linear Systems

Dynamic Response of Linear Systems Dyamic Respose of Liear Systems Liear System Respose Superpositio Priciple Resposes to Specific Iputs Dyamic Respose of st Order Systems Characteristic Equatio - Free Respose Stable st Order System Respose

More information

Mechatronics II Laboratory Exercise 5 Second Order Response

Mechatronics II Laboratory Exercise 5 Second Order Response Mechatroics II Laboratory Exercise 5 Seco Orer Respose Theoretical Backgrou Seco orer ifferetial equatios approximate the yamic respose of may systems. The respose of a geeric seco orer system ca be see

More information

Automatic Control Systems

Automatic Control Systems Automatic Cotrol Sytem Lecture-5 Time Domai Aalyi of Orer Sytem Emam Fathy Departmet of Electrical a Cotrol Egieerig email: emfmz@yahoo.com Itrouctio Compare to the implicity of a firt-orer ytem, a eco-orer

More information

Generalizing the DTFT. The z Transform. Complex Exponential Excitation. The Transfer Function. Systems Described by Difference Equations

Generalizing the DTFT. The z Transform. Complex Exponential Excitation. The Transfer Function. Systems Described by Difference Equations Geeraliig the DTFT The Trasform M. J. Roberts - All Rights Reserved. Edited by Dr. Robert Akl 1 The forward DTFT is defied by X e jω = x e jω i which = Ω is discrete-time radia frequecy, a real variable.

More information

Course Outline. Designing Control Systems. Proportional Controller. Amme 3500 : System Dynamics and Control. Root Locus. Dr. Stefan B.

Course Outline. Designing Control Systems. Proportional Controller. Amme 3500 : System Dynamics and Control. Root Locus. Dr. Stefan B. Amme 3500 : System Dyamics ad Cotrol Root Locus Course Outlie Week Date Cotet Assigmet Notes Mar Itroductio 8 Mar Frequecy Domai Modellig 3 5 Mar Trasiet Performace ad the s-plae 4 Mar Block Diagrams Assig

More information

Chapter 7: The z-transform. Chih-Wei Liu

Chapter 7: The z-transform. Chih-Wei Liu Chapter 7: The -Trasform Chih-Wei Liu Outlie Itroductio The -Trasform Properties of the Regio of Covergece Properties of the -Trasform Iversio of the -Trasform The Trasfer Fuctio Causality ad Stability

More information

EE Control Systems

EE Control Systems Copyright FL Lewis 7 All rights reserved Updated: Moday, November 1, 7 EE 4314 - Cotrol Systems Bode Plot Performace Specificatios The Bode Plot was developed by Hedrik Wade Bode i 1938 while he worked

More information

6.003 Homework #3 Solutions

6.003 Homework #3 Solutions 6.00 Homework # Solutios Problems. Complex umbers a. Evaluate the real ad imagiary parts of j j. π/ Real part = Imagiary part = 0 e Euler s formula says that j = e jπ/, so jπ/ j π/ j j = e = e. Thus the

More information

Mechatronics. Time Response & Frequency Response 2 nd -Order Dynamic System 2-Pole, Low-Pass, Active Filter

Mechatronics. Time Response & Frequency Response 2 nd -Order Dynamic System 2-Pole, Low-Pass, Active Filter Time Respose & Frequecy Respose d -Order Dyamic System -Pole, Low-Pass, Active Filter R 4 R 7 C 5 e i R 1 C R 3 - + R 6 - + e out Assigmet: Perform a Complete Dyamic System Ivestigatio of the Two-Pole,

More information

Chapter 4 : Laplace Transform

Chapter 4 : Laplace Transform 4. Itroductio Laplace trasform is a alterative to solve the differetial equatio by the complex frequecy domai ( s = σ + jω), istead of the usual time domai. The DE ca be easily trasformed ito a algebraic

More information

Class 07 Time domain analysis Part II 2 nd order systems

Class 07 Time domain analysis Part II 2 nd order systems Class 07 Time domai aalysis Part II d order systems Time domai aalysis d order systems iput S output Secod order systems of the type α G(s) as + bs + c Time domai aalysis d order systems iput S α as +

More information

2.004 Dynamics and Control II Spring 2008

2.004 Dynamics and Control II Spring 2008 MIT OpeCourseWare http://ocw.mit.edu 2.004 Dyamics ad Cotrol II Sprig 2008 For iformatio about citig these materials or our Terms of Use, visit: http://ocw.mit.edu/terms. Massachusetts Istitute of Techology

More information

CALCULUS BASIC SUMMER REVIEW

CALCULUS BASIC SUMMER REVIEW CALCULUS BASIC SUMMER REVIEW NAME rise y y y Slope of a o vertical lie: m ru Poit Slope Equatio: y y m( ) The slope is m ad a poit o your lie is, ). ( y Slope-Itercept Equatio: y m b slope= m y-itercept=

More information

Answer: 1(A); 2(C); 3(A); 4(D); 5(B); 6(A); 7(C); 8(C); 9(A); 10(A); 11(A); 12(C); 13(C)

Answer: 1(A); 2(C); 3(A); 4(D); 5(B); 6(A); 7(C); 8(C); 9(A); 10(A); 11(A); 12(C); 13(C) Aswer: (A); (C); 3(A); 4(D); 5(B); 6(A); 7(C); 8(C); 9(A); 0(A); (A); (C); 3(C). A two loop positio cotrol system is show below R(s) Y(s) + + s(s +) - - s The gai of the Tacho-geerator iflueces maily the

More information

The z-transform. 7.1 Introduction. 7.2 The z-transform Derivation of the z-transform: x[n] = z n LTI system, h[n] z = re j

The z-transform. 7.1 Introduction. 7.2 The z-transform Derivation of the z-transform: x[n] = z n LTI system, h[n] z = re j The -Trasform 7. Itroductio Geeralie the complex siusoidal represetatio offered by DTFT to a represetatio of complex expoetial sigals. Obtai more geeral characteristics for discrete-time LTI systems. 7.

More information

The Z-Transform. (t-t 0 ) Figure 1: Simplified graph of an impulse function. For an impulse, it can be shown that (1)

The Z-Transform. (t-t 0 ) Figure 1: Simplified graph of an impulse function. For an impulse, it can be shown that (1) The Z-Trasform Sampled Data The geeralied fuctio (t) (also kow as the impulse fuctio) is useful i the defiitio ad aalysis of sampled-data sigals. Figure below shows a simplified graph of a impulse. (t-t

More information

Z - Transform. It offers the techniques for digital filter design and frequency analysis of digital signals.

Z - Transform. It offers the techniques for digital filter design and frequency analysis of digital signals. Z - Trasform The -trasform is a very importat tool i describig ad aalyig digital systems. It offers the techiques for digital filter desig ad frequecy aalysis of digital sigals. Defiitio of -trasform:

More information

Chapter 2 Feedback Control Theory Continued

Chapter 2 Feedback Control Theory Continued Chapter Feedback Cotrol Theor Cotiued. Itroductio I the previous chapter, the respose characteristic of simple first ad secod order trasfer fuctios were studied. It was show that first order trasfer fuctio,

More information

3. Z Transform. Recall that the Fourier transform (FT) of a DT signal xn [ ] is ( ) [ ] = In order for the FT to exist in the finite magnitude sense,

3. Z Transform. Recall that the Fourier transform (FT) of a DT signal xn [ ] is ( ) [ ] = In order for the FT to exist in the finite magnitude sense, 3. Z Trasform Referece: Etire Chapter 3 of text. Recall that the Fourier trasform (FT) of a DT sigal x [ ] is ω ( ) [ ] X e = j jω k = xe I order for the FT to exist i the fiite magitude sese, S = x [

More information

ECE 422/522 Power System Operations & Planning/Power Systems Analysis II : 6 - Small Signal Stability

ECE 422/522 Power System Operations & Planning/Power Systems Analysis II : 6 - Small Signal Stability ECE 4/5 Power System Operatios & Plaig/Power Systems Aalysis II : 6 - Small Sigal Stability Sprig 014 Istructor: Kai Su 1 Refereces Kudur s Chapter 1 Saadat s Chapter 11.4 EPRI Tutorial s Chapter 8 Power

More information

BENDING FREQUENCIES OF BEAMS, RODS, AND PIPES Revision S

BENDING FREQUENCIES OF BEAMS, RODS, AND PIPES Revision S BENDING FREQUENCIES OF BEAMS, RODS, AND PIPES Revisio S By Tom Irvie Email: tom@vibratioata.com November, Itrouctio The fuametal frequecies for typical beam cofiguratios are give i Table. Higher frequecies

More information

732 Appendix E: Previous EEE480 Exams. Rules: One sheet permitted, calculators permitted. GWC 352,

732 Appendix E: Previous EEE480 Exams. Rules: One sheet permitted, calculators permitted. GWC 352, 732 Aedix E: Previous EEE0 Exams EEE0 Exam 2, Srig 2008 A.A. Rodriguez Rules: Oe 8. sheet ermitted, calculators ermitted. GWC 32, 9-372 Problem Aalysis of a Feedback System Cosider the feedback system

More information

Dr. Seeler Department of Mechanical Engineering Fall 2009 Lafayette College ME 479: Control Systems and Mechatronics Design and Analysis

Dr. Seeler Department of Mechanical Engineering Fall 2009 Lafayette College ME 479: Control Systems and Mechatronics Design and Analysis Dr. Seeler Departmet of Mechaical Egieerig Fall 009 Lafayette College ME 479: Cotrol Systems ad Mechatroics Desig ad Aalysis Lab 0: Review of the First ad Secod Order Step Resposes The followig remarks

More information

Solution of EECS 315 Final Examination F09

Solution of EECS 315 Final Examination F09 Solutio of EECS 315 Fial Examiatio F9 1. Fid the umerical value of δ ( t + 4ramp( tdt. δ ( t + 4ramp( tdt. Fid the umerical sigal eergy of x E x = x[ ] = δ 3 = 11 = ( = ramp( ( 4 = ramp( 8 = 8 [ ] = (

More information

UNIVERSITY OF BOLTON SCHOOL OF ENGINEERING BENG (HONS) IN MECHANICAL ENGINEERING SEMESTER 1 EXAMINATION 2016/2017

UNIVERSITY OF BOLTON SCHOOL OF ENGINEERING BENG (HONS) IN MECHANICAL ENGINEERING SEMESTER 1 EXAMINATION 2016/2017 UNIVERSITY OF BOLTON TW30 SCHOOL OF ENGINEERING BENG (HONS) IN MECHANICAL ENGINEERING SEMESTER EXAMINATION 06/07 ADVANCED THERMOFLUIDS & CONTROL SYSTEMS MODULE NO: AME6005 Date: Thursday Jauary 07 Time:

More information

Lab(8) controller design using root locus

Lab(8) controller design using root locus Lab(8) cotroller desig usig root locus I this lab we will lear how to desig a cotroller usig root locus but before this we eed to aswer the followig questios: What is root locus? What is the purpose of

More information

COMM 602: Digital Signal Processing

COMM 602: Digital Signal Processing COMM 60: Digital Sigal Processig Lecture 4 -Properties of LTIS Usig Z-Trasform -Iverse Z-Trasform Properties of LTIS Usig Z-Trasform Properties of LTIS Usig Z-Trasform -ve +ve Properties of LTIS Usig Z-Trasform

More information

Solutions. Number of Problems: 4. None. Use only the prepared sheets for your solutions. Additional paper is available from the supervisors.

Solutions. Number of Problems: 4. None. Use only the prepared sheets for your solutions. Additional paper is available from the supervisors. Quiz November 4th, 23 Sigals & Systems (5-575-) P. Reist & Prof. R. D Adrea Solutios Exam Duratio: 4 miutes Number of Problems: 4 Permitted aids: Noe. Use oly the prepared sheets for your solutios. Additioal

More information

d dx where k is a spring constant

d dx where k is a spring constant Vorlesug IX Harmoic Oscillator 1 Basic efiitios a properties a classical mechaics Oscillator is efie as a particle subject to a liear force fiel The force F ca be epresse i terms of potetial fuctio V F

More information

The structure of Fourier series

The structure of Fourier series The structure of Fourier series Valery P Dmitriyev Lomoosov Uiversity, Russia Date: February 3, 2011) Fourier series is costructe basig o the iea to moel the elemetary oscillatio 1, +1) by the expoetial

More information

CAMI Education linked to CAPS: Mathematics. Grade The main topics in the FET Mathematics Curriculum NUMBER

CAMI Education linked to CAPS: Mathematics. Grade The main topics in the FET Mathematics Curriculum NUMBER - 1 - CAMI Eucatio like to CAPS: Grae 1 The mai topics i the FET Curriculum NUMBER TOPIC 1 Fuctios Number patters, sequeces a series 3 Fiace, growth a ecay 4 Algebra 5 Differetial Calculus 6 Probability

More information

Introduction to Signals and Systems, Part V: Lecture Summary

Introduction to Signals and Systems, Part V: Lecture Summary EEL33: Discrete-Time Sigals ad Systems Itroductio to Sigals ad Systems, Part V: Lecture Summary Itroductio to Sigals ad Systems, Part V: Lecture Summary So far we have oly looked at examples of o-recursive

More information

Exponential Moving Average Pieter P

Exponential Moving Average Pieter P Expoetial Movig Average Pieter P Differece equatio The Differece equatio of a expoetial movig average lter is very simple: y[] x[] + (1 )y[ 1] I this equatio, y[] is the curret output, y[ 1] is the previous

More information

Lecture 6 Testing Nonlinear Restrictions 1. The previous lectures prepare us for the tests of nonlinear restrictions of the form:

Lecture 6 Testing Nonlinear Restrictions 1. The previous lectures prepare us for the tests of nonlinear restrictions of the form: Eco 75 Lecture 6 Testig Noliear Restrictios The previous lectures prepare us for the tests of oliear restrictios of the form: H 0 : h( 0 ) = 0 versus H : h( 0 ) 6= 0: () I this lecture, we cosier Wal,

More information

MEM 255 Introduction to Control Systems: Analyzing Dynamic Response

MEM 255 Introduction to Control Systems: Analyzing Dynamic Response MEM 55 Itroductio to Cotrol Systems: Aalyzig Dyamic Respose Harry G. Kwaty Departmet of Mechaical Egieerig & Mechaics Drexel Uiversity Outlie Time domai ad frequecy domai A secod order system Via partial

More information

Appendix: The Laplace Transform

Appendix: The Laplace Transform Appedix: The Laplace Trasform The Laplace trasform is a powerful method that ca be used to solve differetial equatio, ad other mathematical problems. Its stregth lies i the fact that it allows the trasformatio

More information

1the 1it is said to be overdamped. When 1, the roots of

1the 1it is said to be overdamped. When 1, the roots of Homework 3 AERE573 Fall 08 Due 0/8(M) ame PROBLEM (40pts) Cosider a D order uderdamped system trasfer fuctio H( s) s ratio 0 The deomiator is the system characteristic polyomial P( s) s s (a)(5pts) Use

More information

(average number of points per unit length). Note that Equation (9B1) does not depend on the

(average number of points per unit length). Note that Equation (9B1) does not depend on the EE603 Class Notes 9/25/203 Joh Stesby Appeix 9-B: Raom Poisso Poits As iscusse i Chapter, let (t,t 2 ) eote the umber of Poisso raom poits i the iterval (t, t 2 ]. The quatity (t, t 2 ) is a o-egative-iteger-value

More information

MASSACHUSETTS INSTITUTE OF TECHNOLOGY Department of Electrical Engineering and Computer Science. BACKGROUND EXAM September 30, 2004.

MASSACHUSETTS INSTITUTE OF TECHNOLOGY Department of Electrical Engineering and Computer Science. BACKGROUND EXAM September 30, 2004. MASSACHUSETTS INSTITUTE OF TECHNOLOGY Departmet of Electrical Egieerig ad Computer Sciece 6.34 Discrete Time Sigal Processig Fall 24 BACKGROUND EXAM September 3, 24. Full Name: Note: This exam is closed

More information

Cork Institute of Technology Bachelor of Science (Honours) in Applied Physics and Instrumentation-Award - (NFQ Level 8)

Cork Institute of Technology Bachelor of Science (Honours) in Applied Physics and Instrumentation-Award - (NFQ Level 8) ork Istitute of Techology Bachelor of Sciece (Hoours) i Applied Physics ad Istrumetatio-Award - (NFQ Level 8) Istructios Aswer Four questios, at least TWO questios from each Sectio. Use separate aswer

More information

University of California at Berkeley College of Engineering Department of Electrical Engineering and Computer Sciences

University of California at Berkeley College of Engineering Department of Electrical Engineering and Computer Sciences A Uiversity of Califoria at Berkeley College of Egieerig Departmet of Electrical Egieerig ad Computer Scieces U N I V E R S T H E I T Y O F LE T TH E R E B E LI G H T C A L I F O R N 8 6 8 I A EECS : Sigals

More information

1 1 2 = show that: over variables x and y. [2 marks] Write down necessary conditions involving first and second-order partial derivatives for ( x0, y

1 1 2 = show that: over variables x and y. [2 marks] Write down necessary conditions involving first and second-order partial derivatives for ( x0, y Questio (a) A square matrix A= A is called positive defiite if the quadratic form waw > 0 for every o-zero vector w [Note: Here (.) deotes the traspose of a matrix or a vector]. Let 0 A = 0 = show that:

More information

CDS 101: Lecture 8.2 Tools for PID & Loop Shaping

CDS 101: Lecture 8.2 Tools for PID & Loop Shaping CDS : Lecture 8. Tools for PID & Loop Shapig Richard M. Murray 7 November 4 Goals: Show how to use loop shapig to achieve a performace specificatio Itroduce ew tools for loop shapig desig: Ziegler-Nichols,

More information

Transfer Function Analysis

Transfer Function Analysis Trasfer Fuctio Aalysis Free & Forced Resposes Trasfer Fuctio Syste Stability ME375 Trasfer Fuctios - Free & Forced Resposes Ex: Let s s look at a stable first order syste: τ y + y = Ku Take LT of the I/O

More information

Sinusoidal Steady-state Analysis

Sinusoidal Steady-state Analysis Siusoidal Steady-state Aalysis Complex umber reviews Phasors ad ordiary differetial equatios Complete respose ad siusoidal steady-state respose Cocepts of impedace ad admittace Siusoidal steady-state aalysis

More information

Frequency Response Methods

Frequency Response Methods Frequecy Respose Methods The frequecy respose Nyquist diagram polar plots Bode diagram magitude ad phase Frequecy domai specificatios Frequecy Respose Methods I precedig chapters the respose ad performace

More information

Solutions of Chapter 5 Part 1/2

Solutions of Chapter 5 Part 1/2 Page 1 of 8 Solutios of Chapter 5 Part 1/2 Problem 5.1-1 Usig the defiitio, compute the -trasform of x[] ( 1) (u[] u[ 8]). Sketch the poles ad eros of X[] i the plae. Solutio: Accordig to the defiitio,

More information

Solutions to Final Exam Review Problems

Solutions to Final Exam Review Problems . Let f(x) 4+x. Solutios to Fial Exam Review Problems Math 5C, Witer 2007 (a) Fid the Maclauri series for f(x), ad compute its radius of covergece. Solutio. f(x) 4( ( x/4)) ( x/4) ( ) 4 4 + x. Sice the

More information

Complex Numbers Solutions

Complex Numbers Solutions Complex Numbers Solutios Joseph Zoller February 7, 06 Solutios. (009 AIME I Problem ) There is a complex umber with imagiary part 64 ad a positive iteger such that Fid. [Solutio: 697] 4i + + 4i. 4i 4i

More information

Dynamic System Response

Dynamic System Response Solutio of Liear, Costat-Coefficiet, Ordiary Differetial Equatios Classical Operator Method Laplace Trasform Method Laplace Trasform Properties 1 st -Order Dyamic System Time ad Frequecy Respose d -Order

More information

School of Mechanical Engineering Purdue University. ME375 Frequency Response - 1

School of Mechanical Engineering Purdue University. ME375 Frequency Response - 1 Case Study ME375 Frequecy Respose - Case Study SUPPORT POWER WIRE DROPPERS Electric trai derives power through a patograph, which cotacts the power wire, which is suspeded from a cateary. Durig high-speed

More information

Calculus 2 - D. Yuen Final Exam Review (Version 11/22/2017. Please report any possible typos.)

Calculus 2 - D. Yuen Final Exam Review (Version 11/22/2017. Please report any possible typos.) Calculus - D Yue Fial Eam Review (Versio //7 Please report ay possible typos) NOTE: The review otes are oly o topics ot covered o previous eams See previous review sheets for summary of previous topics

More information

NATIONAL SENIOR CERTIFICATE GRADE 12

NATIONAL SENIOR CERTIFICATE GRADE 12 NATIONAL SENIOR CERTIFICATE GRADE MATHEMATICS P FEBRUARY/MARCH 03 MARKS: 50 TIME: 3 hours This questio paper cosists of pages, 3 diagram sheets ad iformatio sheet. Please tur over Mathematics/P DBE/Feb.

More information

Chapter 2 Transformations and Expectations

Chapter 2 Transformations and Expectations Chapter Trasformatios a Epectatios Chapter Distributios of Fuctios of a Raom Variable Problem: Let be a raom variable with cf F ( ) If we efie ay fuctio of, say g( ) g( ) is also a raom variable whose

More information

: Transforms and Partial Differential Equations

: Transforms and Partial Differential Equations Trasforms ad Partial Differetial Equatios 018 SUBJECT NAME : Trasforms ad Partial Differetial Equatios SUBJECT CODE : MA 6351 MATERIAL NAME : Part A questios REGULATION : R013 WEBSITE : wwwharigaeshcom

More information

Contents Kreatryx. All Rights Reserved.

Contents Kreatryx. All Rights Reserved. Cotets Maual for K-Notes... Basics of Cotrol Systems... 3 Sigal Flow Graphs... 7 Time Respose Aalysis... 0 Cotrol System Stability... 6 Root locus Techique... 8 Frequecy Domai Aalysis... Bode Plots...

More information

Digital signal processing: Lecture 5. z-transformation - I. Produced by Qiangfu Zhao (Since 1995), All rights reserved

Digital signal processing: Lecture 5. z-transformation - I. Produced by Qiangfu Zhao (Since 1995), All rights reserved Digital sigal processig: Lecture 5 -trasformatio - I Produced by Qiagfu Zhao Sice 995, All rights reserved DSP-Lec5/ Review of last lecture Fourier trasform & iverse Fourier trasform: Time domai & Frequecy

More information

EE Midterm Test 1 - Solutions

EE Midterm Test 1 - Solutions EE35 - Midterm Test - Solutios Total Poits: 5+ 6 Bous Poits Time: hour. ( poits) Cosider the parallel itercoectio of the two causal systems, System ad System 2, show below. System x[] + y[] System 2 The

More information

Control Principles 2. 1 System Elements and Analogies. Learning Outcomes

Control Principles 2. 1 System Elements and Analogies. Learning Outcomes Cotrol Priciples 2 Learig Outcomes This chapter buils upo a extes the basic priciples of cotrol systems that are ealt with i Cotrol Priciples 1. O completio you shoul be able to: 1 Appreciate the ifferet

More information

EXPERIMENT OF SIMPLE VIBRATION

EXPERIMENT OF SIMPLE VIBRATION EXPERIMENT OF SIMPLE VIBRATION. PURPOSE The purpose of the experimet is to show free vibratio ad damped vibratio o a system havig oe degree of freedom ad to ivestigate the relatioship betwee the basic

More information

IYGB. Special Extension Paper E. Time: 3 hours 30 minutes. Created by T. Madas. Created by T. Madas

IYGB. Special Extension Paper E. Time: 3 hours 30 minutes. Created by T. Madas. Created by T. Madas YGB Special Extesio Paper E Time: 3 hours 30 miutes Cadidates may NOT use ay calculator. formatio for Cadidates This practice paper follows the Advaced Level Mathematics Core ad the Advaced Level Further

More information

Definition of z-transform.

Definition of z-transform. - Trasforms Frequecy domai represetatios of discretetime sigals ad LTI discrete-time systems are made possible with the use of DTFT. However ot all discrete-time sigals e.g. uit step sequece are guarateed

More information

EE 4343 Lab#4 PID Control Design of Rigid Bodies

EE 4343 Lab#4 PID Control Design of Rigid Bodies EE 44 Lab#4 PID Cotrol Desig of Rigid Bodies Prepared by: Stacy Caso E-mail: scaso@arri.uta.edu Updated: July 9, 1999 This lab demostrates some key cocepts associated with proportioal plus derivative (PD

More information

Test One (Answer Key)

Test One (Answer Key) CS395/Ma395 (Sprig 2005) Test Oe Name: Page 1 Test Oe (Aswer Key) CS395/Ma395: Aalysis of Algorithms This is a closed book, closed otes, 70 miute examiatio. It is worth 100 poits. There are twelve (12)

More information

MAT 271 Project: Partial Fractions for certain rational functions

MAT 271 Project: Partial Fractions for certain rational functions MAT 7 Project: Partial Fractios for certai ratioal fuctios Prerequisite kowledge: partial fractios from MAT 7, a very good commad of factorig ad complex umbers from Precalculus. To complete this project,

More information

EDEXCEL NATIONAL CERTIFICATE UNIT 4 MATHEMATICS FOR TECHNICIANS OUTCOME 4 - CALCULUS

EDEXCEL NATIONAL CERTIFICATE UNIT 4 MATHEMATICS FOR TECHNICIANS OUTCOME 4 - CALCULUS EDEXCEL NATIONAL CERTIFICATE UNIT 4 MATHEMATICS FOR TECHNICIANS OUTCOME 4 - CALCULUS TUTORIAL 1 - DIFFERENTIATION Use the elemetary rules of calculus arithmetic to solve problems that ivolve differetiatio

More information

ME260W Mid-Term Exam Instructor: Xinyu Huang Date: Mar

ME260W Mid-Term Exam Instructor: Xinyu Huang Date: Mar ME60W Mid-Term Exam Istrutor: Xiyu Huag Date: Mar-03-005 Name: Grade: /00 Problem. A atilever beam is to be used as a sale. The bedig momet M at the gage loatio is P*L ad the strais o the top ad the bottom

More information

1 Cabin. Professor: What is. Student: ln Cabin oh Log Cabin! Professor: No. Log Cabin + C = A Houseboat!

1 Cabin. Professor: What is. Student: ln Cabin oh Log Cabin! Professor: No. Log Cabin + C = A Houseboat! MATH 4 Sprig 0 Exam # Tuesday March st Sectios: Sectios 6.-6.6; 6.8; 7.-7.4 Name: Score: = 00 Istructios:. You will have a total of hour ad 50 miutes to complete this exam.. A No-Graphig Calculator may

More information

Math 142, Final Exam. 5/2/11.

Math 142, Final Exam. 5/2/11. Math 4, Fial Exam 5// No otes, calculator, or text There are poits total Partial credit may be give Write your full ame i the upper right corer of page Number the pages i the upper right corer Do problem

More information

The z-transform can be used to obtain compact transform-domain representations of signals and systems. It

The z-transform can be used to obtain compact transform-domain representations of signals and systems. It 3 4 5 6 7 8 9 10 CHAPTER 3 11 THE Z-TRANSFORM 31 INTRODUCTION The z-trasform ca be used to obtai compact trasform-domai represetatios of sigals ad systems It provides ituitio particularly i LTI system

More information

Some Nonlinear Equations with Double Solutions: Soliton and Chaos

Some Nonlinear Equations with Double Solutions: Soliton and Chaos Some Noliear Equatios with Double Solutios: Solito a Chaos Yi-Fag Chag Departmet of Physics, Yua Uiversity, Kumig, 659, Chia (E-mail: yifagchag@hotmail.com) Abstract The fuametal characteristics of solito

More information

CHAPTER 1 BASIC CONCEPTS OF INSTRUMENTATION AND MEASUREMENT

CHAPTER 1 BASIC CONCEPTS OF INSTRUMENTATION AND MEASUREMENT CHAPTER 1 BASIC CONCEPTS OF INSTRUMENTATION AND MEASUREMENT 1.1 Classificatio of istrumets Aalog istrumet The measure parameter value is isplay by the moveable poiter. The poiter will move cotiuously with

More information

MATH 2411 Spring 2011 Practice Exam #1 Tuesday, March 1 st Sections: Sections ; 6.8; Instructions:

MATH 2411 Spring 2011 Practice Exam #1 Tuesday, March 1 st Sections: Sections ; 6.8; Instructions: MATH 411 Sprig 011 Practice Exam #1 Tuesday, March 1 st Sectios: Sectios 6.1-6.6; 6.8; 7.1-7.4 Name: Score: = 100 Istructios: 1. You will have a total of 1 hour ad 50 miutes to complete this exam.. A No-Graphig

More information

Chapter 7 z-transform

Chapter 7 z-transform Chapter 7 -Trasform Itroductio Trasform Uilateral Trasform Properties Uilateral Trasform Iversio of Uilateral Trasform Determiig the Frequecy Respose from Poles ad Zeros Itroductio Role i Discrete-Time

More information

Question1 Multiple choices (circle the most appropriate one):

Question1 Multiple choices (circle the most appropriate one): Philadelphia Uiversity Studet Name: Faculty of Egieerig Studet Number: Dept. of Computer Egieerig Fial Exam, First Semester: 2014/2015 Course Title: Digital Sigal Aalysis ad Processig Date: 01/02/2015

More information

Voltage controlled oscillator (VCO)

Voltage controlled oscillator (VCO) Voltage cotrolled oscillator (VO) Oscillatio frequecy jl Z L(V) jl[ L(V)] [L L (V)] L L (V) T VO gai / Logf Log 4 L (V) f f 4 L(V) Logf / L(V) f 4 L (V) f (V) 3 Lf 3 VO gai / (V) j V / V Bi (V) / V Bi

More information

Ch3 Discrete Time Fourier Transform

Ch3 Discrete Time Fourier Transform Ch3 Discrete Time Fourier Trasform 3. Show that the DTFT of [] is give by ( k). e k 3. Determie the DTFT of the two sided sigal y [ ],. 3.3 Determie the DTFT of the causal sequece x[ ] A cos( 0 ) [ ],

More information

6.003 Homework #12 Solutions

6.003 Homework #12 Solutions 6.003 Homework # Solutios Problems. Which are rue? For each of the D sigals x [] through x 4 [] below), determie whether the coditios listed i the followig table are satisfied, ad aswer for true or F for

More information

mx bx kx F t. dt IR I LI V t, Q LQ RQ V t,

mx bx kx F t. dt IR I LI V t, Q LQ RQ V t, Lecture 5 omplex Variables II (Applicatios i Physics) (See hapter i Boas) To see why complex variables are so useful cosider first the (liear) mechaics of a sigle particle described by Newto s equatio

More information

School of Mechanical Engineering Purdue University. ME375 Transfer Functions - 1

School of Mechanical Engineering Purdue University. ME375 Transfer Functions - 1 Trasfer Fuctio Aalysis Free & Forced Resposes Trasfer Fuctio Syste Stability ME375 Trasfer Fuctios - 1 Free & Forced Resposes Ex: Let s look at a stable first order syste: y y Ku Take LT of the I/O odel

More information

Difference Equation Construction (1) ENGG 1203 Tutorial. Difference Equation Construction (2) Grow, baby, grow (1)

Difference Equation Construction (1) ENGG 1203 Tutorial. Difference Equation Construction (2) Grow, baby, grow (1) ENGG 03 Tutorial Differece Equatio Costructio () Systems ad Cotrol April Learig Objectives Differece Equatios Z-trasform Poles Ack.: MIT OCW 6.0, 6.003 Newto s law of coolig states that: The chage i a

More information

3. Calculus with distributions

3. Calculus with distributions 6 RODICA D. COSTIN 3.1. Limits of istributios. 3. Calculus with istributios Defiitio 4. A sequece of istributios {u } coverges to the istributio u (all efie o the same space of test fuctios) if (φ, u )

More information

1. Do the following sequences converge or diverge? If convergent, give the limit. Explicitly show your reasoning. 2n + 1 n ( 1) n+1.

1. Do the following sequences converge or diverge? If convergent, give the limit. Explicitly show your reasoning. 2n + 1 n ( 1) n+1. Solutio: APPM 36 Review #3 Summer 4. Do the followig sequeces coverge or iverge? If coverget, give the limit. Eplicitly show your reasoig. a a = si b a = { } + + + 6 c a = e Solutio: a Note si a so, si

More information

Chapter 3. z-transform

Chapter 3. z-transform Chapter 3 -Trasform 3.0 Itroductio The -Trasform has the same role as that played by the Laplace Trasform i the cotiuous-time theorem. It is a liear operator that is useful for aalyig LTI systems such

More information

Problem Cosider the curve give parametrically as x = si t ad y = + cos t for» t» ß: (a) Describe the path this traverses: Where does it start (whe t =

Problem Cosider the curve give parametrically as x = si t ad y = + cos t for» t» ß: (a) Describe the path this traverses: Where does it start (whe t = Mathematics Summer Wilso Fial Exam August 8, ANSWERS Problem 1 (a) Fid the solutio to y +x y = e x x that satisfies y() = 5 : This is already i the form we used for a first order liear differetial equatio,

More information

6.003 Homework #12 Solutions

6.003 Homework #12 Solutions 6.003 Homework # Solutios Problems. Which are rue? For each of the D sigals x [] through x 4 [] (below), determie whether the coditios listed i the followig table are satisfied, ad aswer for true or F

More information

radians A function f ( x ) is called periodic if it is defined for all real x and if there is some positive number P such that:

radians A function f ( x ) is called periodic if it is defined for all real x and if there is some positive number P such that: Fourier Series. Graph of y Asix ad y Acos x Amplitude A ; period 36 radias. Harmoics y y six is the first harmoic y y six is the th harmoics 3. Periodic fuctio A fuctio f ( x ) is called periodic if it

More information

Butterworth LC Filter Designer

Butterworth LC Filter Designer Butterworth LC Filter Desiger R S = g g 4 g - V S g g 3 g R L = Fig. : LC filter used for odd-order aalysis g R S = g 4 g V S g g 3 g - R L = useful fuctios ad idetities Uits Costats Table of Cotets I.

More information

k=1 s k (x) (3) and that the corresponding infinite series may also converge; moreover, if it converges, then it defines a function S through its sum

k=1 s k (x) (3) and that the corresponding infinite series may also converge; moreover, if it converges, then it defines a function S through its sum 0. L Hôpital s rule You alreay kow from Lecture 0 that ay sequece {s k } iuces a sequece of fiite sums {S } through S = s k, a that if s k 0 as k the {S } may coverge to the it k= S = s s s 3 s 4 = s k.

More information

Section A assesses the Units Numerical Analysis 1 and 2 Section B assesses the Unit Mathematics for Applied Mathematics

Section A assesses the Units Numerical Analysis 1 and 2 Section B assesses the Unit Mathematics for Applied Mathematics X0/70 NATIONAL QUALIFICATIONS 005 MONDAY, MAY.00 PM 4.00 PM APPLIED MATHEMATICS ADVANCED HIGHER Numerical Aalysis Read carefully. Calculators may be used i this paper.. Cadidates should aswer all questios.

More information

Written exam Digital Signal Processing for BMT (8E070). Tuesday November 1, 2011, 09:00 12:00.

Written exam Digital Signal Processing for BMT (8E070). Tuesday November 1, 2011, 09:00 12:00. Techische Uiversiteit Eidhove Fac. Biomedical Egieerig Writte exam Digital Sigal Processig for BMT (8E070). Tuesday November, 0, 09:00 :00. (oe page) ( problems) Problem. s Cosider a aalog filter with

More information

Analysis of the No-Load Characteristic of the Moving Coil Linear Compressor

Analysis of the No-Load Characteristic of the Moving Coil Linear Compressor Purdue Uiversity Purdue e-pubs Iteratioal Compressor Egieerig Coferece School of Mechaical Egieerig 008 Aalysis of the No-Load Characteristic of the Movig Coil Liear Compressor Yigbai Xie North Chia Electric

More information

x x x Using a second Taylor polynomial with remainder, find the best constant C so that for x 0,

x x x Using a second Taylor polynomial with remainder, find the best constant C so that for x 0, Math Activity 9( Due with Fial Eam) Usig first ad secod Taylor polyomials with remaider, show that for, 8 Usig a secod Taylor polyomial with remaider, fid the best costat C so that for, C 9 The th Derivative

More information

AP Calculus BC Review Chapter 12 (Sequences and Series), Part Two. n n th derivative of f at x = 5 is given by = x = approximates ( 6)

AP Calculus BC Review Chapter 12 (Sequences and Series), Part Two. n n th derivative of f at x = 5 is given by = x = approximates ( 6) AP Calculus BC Review Chapter (Sequeces a Series), Part Two Thigs to Kow a Be Able to Do Uersta the meaig of a power series cetere at either or a arbitrary a Uersta raii a itervals of covergece, a kow

More information

EE / EEE SAMPLE STUDY MATERIAL. GATE, IES & PSUs Signal System. Electrical Engineering. Postal Correspondence Course

EE / EEE SAMPLE STUDY MATERIAL. GATE, IES & PSUs Signal System. Electrical Engineering. Postal Correspondence Course Sigal-EE Postal Correspodece Course 1 SAMPLE STUDY MATERIAL Electrical Egieerig EE / EEE Postal Correspodece Course GATE, IES & PSUs Sigal System Sigal-EE Postal Correspodece Course CONTENTS 1. SIGNAL

More information

Fourier Series and the Wave Equation

Fourier Series and the Wave Equation Fourier Series ad the Wave Equatio We start with the oe-dimesioal wave equatio u u =, x u(, t) = u(, t) =, ux (,) = f( x), u ( x,) = This represets a vibratig strig, where u is the displacemet of the strig

More information

The state space model needs 5 parameters, so it is not as convenient to use in this control study.

The state space model needs 5 parameters, so it is not as convenient to use in this control study. Trasfer fuctio for of the odel G θ K ω 2 θ / v θ / v ( s) = = 2 2 vi s + 2ζωs + ω The followig slides detail a derivatio of this aalog eter odel both as state space odel ad trasfer fuctio (TF) as show

More information

2.3 Warmup. Graph the derivative of the following functions. Where necessary, approximate the derivative.

2.3 Warmup. Graph the derivative of the following functions. Where necessary, approximate the derivative. . Warmup Grap te erivative of te followig fuctios. Were ecessar, approimate te erivative. Differetiabilit Must a fuctio ave a erivative at eac poit were te fuctio is efie? Or If f a is efie, must f ( a)

More information