CHEM 1451 Lab Week 09 Colligative Properties Postlab Report. Coach s Name

Size: px
Start display at page:

Download "CHEM 1451 Lab Week 09 Colligative Properties Postlab Report. Coach s Name"

Transcription

1 Instructions To complete the table entry titled Measured, copy your measurement that you made in the previous week. If you ran the experiment again to obtain a different measurement, then check the box above the table so that your Coach will know why the numbers are different from the ones reported in the Prelab and Data. Although there will be no points for completing a table entry, one point will be deducted if the data is missing or for the incorrect use of significant figures and units. So make sure to write them down correctly. Part A: Preparing Solutions Solution B Measured Mass of NaCl Measured Volume of Water 1. Answer each question with correct significant figures and units. You must show calculations for determining each quantity. If necessary, use the molar mass of NaCl = g/mol. a. Determine the number of moles of NaCl in the solution. (5 points) b. Determine the number of moles of all solutes (both cations and anions) from the number of moles of NaCl that you determined above. For this question, in addition to your calculation, explain the idea behind your calculation. (5 points) c. Determine the mass (in kg) of solvent (assume that the density of water is g/ml). (5 points) d. Determine the molality (in m or mol/kg) of all solutes. (5 points) 1

2 Solution C Measured Mass of NaCl Measured Volume of Water 2. Answer each question with correct significant figures and units. You must show calculations for determining each quantity. If necessary, use the molar mass of NaCl = g/mol. a. Determine the number of moles of NaCl in the solution. (5 points) b. Determine the number of moles of all solutes (both cations and anions) from the number of moles of NaCl that you determined above. For this question, in addition to your calculation, explain the idea behind your calculation. (5 points) c. Determine the mass (in kg) of solvent (assume that the density of water is g/ml). (5 points) d. Determine the molality (in m or mol/kg) of all solutes. (5 points) 2

3 Solution D Measured Mass of NaCl Measured Volume of Water 3. Answer each question with correct significant figures and units. You must show calculations for determining each quantity. If necessary, use the molar mass of NaCl = g/mol. a. Determine the number of moles of NaCl in the solution. (5 points) b. Determine the number of moles of all solutes (both cations and anions) from the number of moles of NaCl that you determined above. For this question, in addition to your calculation, explain the idea behind your calculation. (5 points) c. Determine the mass (in kg) of solvent (assume that the density of water is g/ml). (5 points) d. Determine the molality (in m or mol/kg) of all solutes. (5 points) 3

4 Part C: Measuring the Freezing Point of Water Measure Freezing Point of Water Part D: Measuring the Freezing Point of NaCl Solutions Measured Freezing Point of Solution B Measured Freezing Point of Solution C Measured Freezing Point of Solution D 4. Using the measured freezing point of distilled water in Part C, calculate the freezing point depression T for NaCl solutions from Part D. The freezing point depression T is calculated by the following formula. T = (Measured freezing point of water in Part C) (Measured freezing point in Part D) a. Determine the freezing point depression T for Solution B. Show your calculation. (5 points) b. Determine the freezing point depression T for Solution C. Show your calculation. (5 points) c. Determine the freezing point depression T for Solution D. Show your calculation. (5 points) 4

5 5. Determine the molal freezing point depression constant (K f) (in C kg/mol) of water by using the data of three NaCl solutions. Use Equation 3 in the Background and Procedure file, the molality values of all solutes from Questions 1-3 and the freezing point depression ( T) from Question 4. In your calculation, rewrite the symbol m (the molality) as mol/kg so that the molal freezing point depression constant will have the correct unit. Make sure to show all your work to receive credits. a. Use the data of Solution B and determine the molal freezing point depression constant (K f) (in C kg/mol) of water. (5 points) b. Use the data of Solution C and determine the molal freezing point depression constant (K f) (in C kg/mol) of water. (5 points) c. Use the data of Solution D and determine the molal freezing point depression constant (K f) (in C kg/mol) of water. (5 points) 5

6 6. Analysis of Results a. Determine the average value of three molal freezing point depression constant (K f) values of water from Question 5 (in C kg/mol). (5 points) b. The published value for K f of water is 1.86 C kg/mol (use this as the true value). Determine the % error of the average value of the molal freezing point depression constant that you found in Question 6 a. average value true value %error = 100% true value The % error is an example of the mixed operation. In order to receive the full credits, make sure to show each step of calculations. In other words, show the result of the calculation in the numerator explicitly before dividing the numbers. (5 points) 6

64 previous solution

64 previous solution 64 previous solution mole fraction (definition) 1 - Convert 29.6 grams sodium sulfate to moles. We already did this to find molality, so we can re-use the number. 2 - This is the total moles of both sodium

More information

Intermolecular Forces

Intermolecular Forces Intermolecular Forces! When two molecules approach one another, they are attracted to some extent! Polar molecules are attracted through the electrostatic interaction of their dipole moments! Non-polar

More information

CH 222 Chapter Eleven Concept Guide

CH 222 Chapter Eleven Concept Guide CH 222 Chapter Eleven Concept Guide 1. Molality A 4.5 M nitric acid solution contains 65.0 g of HNO 3 in 288 g of solution. What is the molality of this solution? Molality is calculated by dividing the

More information

Colligative properties CH102 General Chemistry, Spring 2011, Boston University

Colligative properties CH102 General Chemistry, Spring 2011, Boston University Colligative properties CH12 General Chemistry, Spring 211, Boston University here are four colligative properties. vapor-pressure lowering boiling-point elevation freezing-point depression osmotic pressure

More information

70 Example: If a solution is m citric acid, what is the molar concentration (M) of the solution? The density of the solution is 1.

70 Example: If a solution is m citric acid, what is the molar concentration (M) of the solution? The density of the solution is 1. 70 Example: If a solution is 0.688 m citric acid, what is the molar concentration (M) of the solution? The density of the solution is 1.049 g/ml molality definition molarity definition To solve the problem,

More information

Chapter 11. Properties of Solutions Solutions

Chapter 11. Properties of Solutions Solutions Chapter 11. Properties of Solutions Solutions Homogeneous Mixture 1 Solution Composition Equivalent moles of solute (mol) Acid-Base reaction Molarity (M) = liter of solution (L) 1 eq: the quantity of acid

More information

REVIEW EXAM 1 CHAP 11 &12

REVIEW EXAM 1 CHAP 11 &12 REVIEW EXAM 1 CHAP 11 &12 1.In a 0.1 molar solution of NaCl in water, which one of the following will be closest to 0.1? A) The mole fraction of NaCl. B) The mass fraction of NaCl. C) The mass percent

More information

AP CHEMISTRY CHAPTER 8 PROBLEM SET #3. 1. Determine if the following pairs would form a solution. Explain your answer. a.

AP CHEMISTRY CHAPTER 8 PROBLEM SET #3. 1. Determine if the following pairs would form a solution. Explain your answer. a. NAME: AP CHEMISTRY CHAPTER 8 PROBLEM SET #3 1. Determine if the following pairs would form a solution. Explain your answer. a. C 2 H 6 and water b. PbCl 2 and water c. I 2 and water d. F 2 and CH 4 2.

More information

SOLUTION CONCENTRATIONS

SOLUTION CONCENTRATIONS SOLUTION CONCENTRATIONS The amount of solute in a solution (concentration) is an important property of the solution. A dilute solution contains small quantities of solute relative to the solvent, while

More information

Concentration of Solutions

Concentration of Solutions Chapter 11 Textbook Assigned Problems Exercises Concentration of Solutions 25. Because the density of water is 1.00 g/ml, 100.0 ml of water has a mass of 100. g. density = = 1.06 g/ml = 1.06 g/cm 3 mol

More information

Required math skills:

Required math skills: Quantitative Chemical Analysis Required math skills: ACCURATE ACCURATE NOT Accurate PRECISE NOT precise PRECISE Add Add Subtract Multiply Divide Powers Powers Logarithms Random error systematic error 1

More information

Salting The Roads Colligative Property. B. Types. A. Definition

Salting The Roads Colligative Property. B. Types. A. Definition Salting The Roads Colligative Property A. Definition property that depends on the concentration of solute particles, not their identity Unit 11: Solutions Lesson 11.3: Colligative Properties 68 B. Types

More information

SOLVING EMPIRICAL FORMULA PROBLEMS

SOLVING EMPIRICAL FORMULA PROBLEMS SOLVING EMPIRICAL FORMULA PROBLEMS Why do we want to use Empirical Formulas? 1)Substances that do not consist of discrete units, such as in a crystal (ionic solid) of NaCl---we dont want to write Na456Cl910

More information

Lab 3: Determination of molar mass by freezing point depression

Lab 3: Determination of molar mass by freezing point depression Chemistry 162 The following write-up may be inaccurate for the particular chemicals or equipment we are using. Be prepared to modify your materials/procedure sections when performing the exercise. Please

More information

B. Types. Salting The Roads. A. Definition 4/21/2015. Unit 11: Solutions Lesson 11.3: Colligative Properties 68. Colligative Property

B. Types. Salting The Roads. A. Definition 4/21/2015. Unit 11: Solutions Lesson 11.3: Colligative Properties 68. Colligative Property Salting The Roads Unit 11: Solutions Lesson 11.3: Colligative Properties 68 Colligative Property A. Definition property that depends on the concentration of solute particles, not their identity B. Types

More information

Solutions and Their Properties

Solutions and Their Properties Chapter 11 Solutions and Their Properties Solutions: Definitions A solution is a homogeneous mixture. A solution is composed of a solute dissolved in a solvent. When two compounds make a solution, the

More information

Unit 7. Solution Concentrations and Colligative Properties

Unit 7. Solution Concentrations and Colligative Properties Unit 7 Solution Concentrations and Colligative Properties Molarity Most widely used concentration unit [HCl] means concentration of HCl in mol/l Notice volume is total volume of solution Molarity (M)=

More information

Chapter 13. Characteristics of a Solution. Example of A Homogenous Mixtures. Solutions

Chapter 13. Characteristics of a Solution. Example of A Homogenous Mixtures. Solutions Chapter 13 Solutions Characteristics of a Solution A solution is a homogeneous mixture A solution is composed of a: Solute: the substance in lesser amount Solvent: the substance in greater amount Two liquid

More information

Soluble: A solute that dissolves in a specific solvent. Insoluble: A solute that will not dissolve in a specific solvent. "Like Dissolves Like"

Soluble: A solute that dissolves in a specific solvent. Insoluble: A solute that will not dissolve in a specific solvent. Like Dissolves Like Solutions Homogeneous Mixtures Solutions: Mixtures that contain two or more substances called the solute and the solvent where the solute dissolves in the solvent so the solute and solvent are not distinguishable

More information

CHEM1109 Answers to Problem Sheet Isotonic solutions have the same osmotic pressure. The osmotic pressure, Π, is given by:

CHEM1109 Answers to Problem Sheet Isotonic solutions have the same osmotic pressure. The osmotic pressure, Π, is given by: CHEM1109 Answers to Problem Sheet 5 1. Isotonic solutions have the same osmotic pressure. The osmotic pressure, Π, is given by: Π = MRT where M is the molarity of the solution. Hence, M = Π 5 (8.3 10 atm)

More information

Use the Equations given in your notes to solve the Colligative Property Questions. Freezing Boiling Point ( C)

Use the Equations given in your notes to solve the Colligative Property Questions. Freezing Boiling Point ( C) Colligative Properties of Solvents 8.HW Colligative Properties.doc Use the Equations given in your notes to solve the Colligative Property Questions. ΔT b m K b, ΔT f m Solvent Formula Freezing Point (

More information

AP CHEMISTRY CHAPTER 8 PROBLEM SET #2. (Questions 1-3) Select the letter of the answer that best completes the statement or answers the question.

AP CHEMISTRY CHAPTER 8 PROBLEM SET #2. (Questions 1-3) Select the letter of the answer that best completes the statement or answers the question. NAME: AP CHEMISTRY CHAPTER 8 PROBLEM SET #2 (Questions 1-3) Select the letter of the answer that best completes the statement or answers the question. 1. 2. 3. According to Raoult s Law, which statement

More information

concentration of solute (molality) Freezing point depression constant (for SOLVENT)

concentration of solute (molality) Freezing point depression constant (for SOLVENT) 74 FREEZING POINT DEPRESSION concentration of solute (molality) Freezing point depression constant (for SOLVENT) Freezing point depression: The amount the freezing temperature is LOWERED by the solute.

More information

SOLUTIONS CHAPTER 13

SOLUTIONS CHAPTER 13 SOLUTIONS CHAPTER 13 SOLUTIONS Solutions, also known as homogeneous mixtures, are composed of two components: solute and solvent. In a sugar-water solution, water acts as a solvent (dissolving medium);

More information

75 A solution of 2.500g of unknown dissolved in g of benzene has a freezing point of C. What is the molecular weight of the unknown?

75 A solution of 2.500g of unknown dissolved in g of benzene has a freezing point of C. What is the molecular weight of the unknown? 75 A solution of 2.500g of unknown dissolved in 100.0 g of benzene has a freezing point of 4.880 C. What is the molecular weight of the unknown? Solving for Cm (molality) will allow us to calculate how

More information

Week 14/Tu: Lecture Units 33 & 34

Week 14/Tu: Lecture Units 33 & 34 Week 14/Tu: Lecture Units 33 & 34 Exam 3 Unit 33: Colligative Properties -- Vapor pressure of solutions -- Freezing, boiling of solutions -- Osmotic pressure Unit 34: Introduction to Equilibria -- Rate

More information

1) Define the following terms: a) solution, b) miscible, c) hydration, d) percent by mass (solute), e) colligative property, f) hypotonic.

1) Define the following terms: a) solution, b) miscible, c) hydration, d) percent by mass (solute), e) colligative property, f) hypotonic. Problems - Chapter 13 (with solutions) 1) Define the following terms: a) solution, b) miscible, c) hydration, d) percent by mass (solute), e) colligative property, f) hypotonic. a) solution - A homogeneous

More information

Freezing Point Depression: Can oceans freeze? Teacher Advanced Version

Freezing Point Depression: Can oceans freeze? Teacher Advanced Version Freezing Point Depression: Can oceans freeze? Teacher Advanced Version Freezing point depression describes the process where the temperature at which a liquid freezes is lowered by adding another compound.

More information

Solutions The federal government and state governments set standards limiting the amount of contaminants allowed in drinking water.

Solutions The federal government and state governments set standards limiting the amount of contaminants allowed in drinking water. Solutions The federal government and state governments set standards limiting the amount of contaminants allowed in drinking water. 16.1 Properties of Solutions 16. Concentrations of Solutions 16. Colligative

More information

ANSWERS CIRCLE CORRECT SECTION

ANSWERS CIRCLE CORRECT SECTION CHEMISTRY 162 - EXAM I June 08, 2009 Name: SIGN: RU ID Number Choose the one best answer for each question and write the letter preceding it in the appropriate space on this answer sheet. Only the answer

More information

PSI AP Chemistry: Solutions Practice Problems

PSI AP Chemistry: Solutions Practice Problems PSI AP Chemistry: Solutions Practice Problems Name Solutions: Mixtures, Solubility and Concentration Classwork 1. A student determined that there were 0.032 grams of oxygen gas dissolved in a 200.0 ml

More information

4/21/2015. But what about freezing? When water freezes, it has to form a crystal lattice.

4/21/2015. But what about freezing? When water freezes, it has to form a crystal lattice. 68 69 70 71 72 Salting The Roads Unit 11: Solutions Lesson 11.3: Colligative Properties A. Definition Colligative Property property that depends on the concentration of solute particles, not their identity

More information

Concentration of Solutions

Concentration of Solutions Section 3 10C, 10D Main Ideas Molarity is moles of solute per liter of solution Molality is moles of solute per kilogram of solvent 10C calculate the concentration of solutions in units of molarity; 10D

More information

Freezing point depression - The freezing temperature of a SOLUTION gets lower as the CONCENTRATION of a solution increases.

Freezing point depression - The freezing temperature of a SOLUTION gets lower as the CONCENTRATION of a solution increases. 73 COLLIGATIVE PROPERTIES - properties unique to solutions. - depend only on the CONCENTRATION of a solution and not the IDENTITY of the solute** **ionic solutes: Remember that they dissociate into MULTIPLE

More information

Properties of Solutions

Properties of Solutions Properties of Solutions Reading: Ch 11, section 8 Ch 12, sections 1-8 * = important homework question Homework: Chapter 11: 85*, 87 Chapter 12: 29, 33, 35, 41, 51*, 53, 55, 63*, 65, 67*, 69, 71, 75*, 79*,

More information

Chem 1C Midterm 2 Practice Test 1

Chem 1C Midterm 2 Practice Test 1 Chem 1C Midterm 2 Practice Test 1 First initial of last name Name Perm Number All work must be shown on the exam for partial credit. Points will be taken off for incorrect or missing units. Calculators

More information

- Applications: In chemistry, this effect is often used to determine the molecular weight of an unknown molecule.

- Applications: In chemistry, this effect is often used to determine the molecular weight of an unknown molecule. 73 FREEZING POINT DEPRESSION concentration of solute (molality) Freezing point depression constant (for SOLVENT) Freezing point depression: The amount the freezing temperature is LOWERED by the solute.

More information

Chapter 12.4 Colligative Properties of Solutions Objectives List and define the colligative properties of solutions. Relate the values of colligative

Chapter 12.4 Colligative Properties of Solutions Objectives List and define the colligative properties of solutions. Relate the values of colligative Chapter 12.4 Colligative Properties of Solutions Objectives List and define the colligative properties of solutions. Relate the values of colligative properties to the concentrations of solutions. Calculate

More information

1) Define the following terms: a) solution, b) miscible, c) hydration, d) percent by mass (solute), e) colligative property, f) hypotonic.

1) Define the following terms: a) solution, b) miscible, c) hydration, d) percent by mass (solute), e) colligative property, f) hypotonic. Problems - Chapter 13 (with solutions) 1) Define the following terms: a) solution, b) miscible, c) hydration, d) percent by mass (solute), e) colligative property, f) hypotonic. a) solution - A homogeneous

More information

Sample Problem. (b) Mass % H 2 SO 4 = kg H 2 SO 4 /1.046 kg total = 7.04%

Sample Problem. (b) Mass % H 2 SO 4 = kg H 2 SO 4 /1.046 kg total = 7.04% A Sample 0.750 M solution Problem of H 2 SO 4 in water has a density of 1.046 g/ml at 20ºC. What is the concentration in (a) mole fraction, (b) mass percent, (c) molality (MM = 98.086 g/mol)? (a) Since

More information

FORMULA SHEET (tear off)

FORMULA SHEET (tear off) FORMULA SHEET (tear off) N A = 6.022 x 10 23 C = ( 5 / 9 ) ( F - 32) F = ( 9 / 5 )( C) + 32 1 amu = 1.661 x 10-27 kg C = K - 273.15 K = C + 273.15 1 atm = 760 torr = 760 mm Hg 1 atm = 1.013 bar pv = nrt

More information

FORMULA SHEET (tear off)

FORMULA SHEET (tear off) FORMULA SHEET (tear off) N A = 6.022 x 10 23 C = ( 5 / 9 ) ( F - 32) F = ( 9 / 5 )( C) + 32 1 amu = 1.661 x 10-27 kg C = K - 273.15 K = C + 273.15 1 atm = 760 torr = 760 mm Hg 1 atm = 1.013 bar pv = nrt

More information

Physical Properties of Solutions

Physical Properties of Solutions Physical Properties of Solutions Chapter 12 Copyright The McGraw-Hill Companies, Inc. Permission required for reproduction or display. 12.1- Types of solutions A solution is a homogenous mixture of 2 or

More information

x =!b ± b2! 4ac 2a moles particles solution (expt) moles solute dissolved (calculated conc ) i =

x =!b ± b2! 4ac 2a moles particles solution (expt) moles solute dissolved (calculated conc ) i = Properties of Solution Practice Exam Solutions Name (last) (First) Read all questions before you start. Show all work and explain your answers. Report all numerical answers to the proper number of sig.

More information

Chapter 11: Properties of Solutions

Chapter 11: Properties of Solutions Chapter 11: Properties of Solutions Apr 1 11:01 AM 11.1 Solution Composition Solve problems relating to the mass percent, mole fraction and molality. Mar 26 1:09 PM 1 Molarity (M) is defined as moles of

More information

Bushra Javed Valencia College CHM 1046 Chapter 12 - Solutions

Bushra Javed Valencia College CHM 1046 Chapter 12 - Solutions Bushra Javed Valencia College CHM 1046 Chapter 12 - Solutions 1 Chapter 12 :Solutions Tentative Outline 1. Introduction to solutions. 2. Types of Solutions 3. Solubility and the Solution Process: Saturated,

More information

How many carbon atoms are in 1 mol of sucrose (C 12 H 22 O 11 )? A) 7.23 x B) 6.02 x C) 5.02 x D) 12 E) 342

How many carbon atoms are in 1 mol of sucrose (C 12 H 22 O 11 )? A) 7.23 x B) 6.02 x C) 5.02 x D) 12 E) 342 Question 1 How many carbon atoms are in 1 mol of sucrose (C 12 H 22 O 11 )? A) 7.23 x 10 24 B) 6.02 x 10 23 C) 5.02 x 10 22 D) 12 E) 342 3-1 Question 2 Calculate the mass % of hydrogen in ammonium bicarbonate.

More information

PSI AP Chemistry Solutions Practice Problems

PSI AP Chemistry Solutions Practice Problems PSI AP Chemistry Solutions Practice Problems Name Solutions: Mixtures, Solubility and Concentration Classwork 1. A student determined that there were 0.032 grams of oxygen gas dissolved in a 200.0 ml sample

More information

Department of Chemistry University of Texas at Austin

Department of Chemistry University of Texas at Austin Colligative Properties Supplemental Worksheet PROBLEM #1: Give the molecular formula, the van t Hoff factor for the following Ionic Compounds as well as guess the solubility of the compounds. If you cannot

More information

1. All the solutions have the same molality. 2. All the solutions have the same molarity.

1. All the solutions have the same molality. 2. All the solutions have the same molarity. I. (41 points) A. (12 points) Write your answers on the blanks provided. 1. Which of the following solutes would be more soluble in water? a. CH 3 OH or C 17 H 35 OH b. C 2 H 5 Cl or NaCl c. CHCl 3 or

More information

3.Which of the following has the highest melting temperature? A) H 2 O B) CO 2 C) S 8 D) MgF 2 E) P 4

3.Which of the following has the highest melting temperature? A) H 2 O B) CO 2 C) S 8 D) MgF 2 E) P 4 2. Which if the following is the correct order of boiling points for KNO 3, CH 3 OH, C 2 H 6, Ne? A) Ne < CH 3 OH < C 2 H 6 < KNO 3 B) KNO 3 < CH 3 OH < C 2 H 6 < Ne C) Ne < C 2 H 6 < KNO 3 < CH 3 OH D)

More information

CHEM-102 EXAM I Name Fall 2004 Section

CHEM-102 EXAM I Name Fall 2004 Section CHEM-102 EXAM I Name Fall 2004 Section 10 11 12 Version A (Circle one) Instructions: 1. Put your name and section number on both page 1 and the answer key. Do not detach the answer key from the back of

More information

UNIT 2 SOLUTION. Q. 1. The vapour pressure of deliquescent substance is less or more than that of water vapours in air?

UNIT 2 SOLUTION. Q. 1. The vapour pressure of deliquescent substance is less or more than that of water vapours in air? UNIT 2 SOLUTION 1 MARK QUESTIONS Q. 1. The vapour pressure of deliquescent substance is less or more than that of water vapours in air? Ans. Less than that of water vapours in air. Q. 2. If is the degree

More information

Announcements. It is critical that you are keeping up. Ask or see me if you need help. Lecture slides updated and homework solutions posted.

Announcements. It is critical that you are keeping up. Ask or see me if you need help. Lecture slides updated and homework solutions posted. Announcements Dec. 18 Hour Exam 1 C-109 Start time 6PM Coverage is Chapter 12 and 13. 10-multiple choice 3-fairly short problems 3-longer problem solving 100 point Exam Lecture slides updated and homework

More information

Ion Speciation. OCN 623 Chemical Oceanography. Speciation defines the chemical reactivity of elements in the ocean

Ion Speciation. OCN 623 Chemical Oceanography. Speciation defines the chemical reactivity of elements in the ocean Ion Speciation OCN 623 Chemical Oceanography Speciation defines the chemical reactivity of elements in the ocean Affects residence time e.g. anions vs cations Affects biological uptake e.g. Fe species

More information

Module 2: Solutions The Science of Mixing : Have you ever been in a wrong mix?

Module 2: Solutions The Science of Mixing : Have you ever been in a wrong mix? PART 1 Name: All matter around us exists in a mixed state. Chemists look at the atomic level and try to explain why certain matters mix homogeneously (uniformly) and certain types of matters (or compounds)

More information

Chapter Solutions. MockTime.com. (a) M urea (b) 0.01 M KNO3 (c) 0.01 M Na2 SO4 (d) M glucose Ans: (c)

Chapter Solutions. MockTime.com. (a) M urea (b) 0.01 M KNO3 (c) 0.01 M Na2 SO4 (d) M glucose Ans: (c) 47 Chapter Solutions 1. Freezing point of an aqueous solution is ( 0.186) C. Elevation of boiling point of the same solution is K b = 0.512 C,Kf = 1.86 C, find the increase in boiling point. [2002] (a)

More information

1) Define the following terms: a) solution, b) miscible, c) hydration, d) percent by mass (solute), e) colligative property, f) hypotonic.

1) Define the following terms: a) solution, b) miscible, c) hydration, d) percent by mass (solute), e) colligative property, f) hypotonic. Problems - Chapter 13 (with solutions) 1) Define the following terms: a) solution, b) miscible, c) hydration, d) percent by mass (solute), e) colligative property, f) hypotonic. a) solution - A homogeneous

More information

Solutes (Particularly Ions) are Structure Breakers

Solutes (Particularly Ions) are Structure Breakers Solutes (Particularly Ions) are Structure Breakers More accurately they form new structures Reorient some water molecules Cause new associations Modify properties Alter much of the Physical Chem. (Physicochemical

More information

September 28, Possibly Useful Information: 1) ( ) ( ) ( ) ( ) ( ) R = L atm / mol K. 2) ( ) ( ) ( ) h = 6.

September 28, Possibly Useful Information: 1) ( ) ( ) ( ) ( ) ( ) R = L atm / mol K. 2) ( ) ( ) ( ) h = 6. Name Student ID # CEMISTRY 122 [Tyvoll] EXAM I September 28, 2007 1 2 3 4 5 Possibly Useful Information: 1) ( ) ( ) ( ) ( ) ( ) R = 0.0821 L atm / mol K 2) ( ) ( ) ( ) h = 6.63 x 10-34 J s 3) ( ) ( ) (

More information

Factors that Effect the Rate of Solvation

Factors that Effect the Rate of Solvation Factors that Effect the Rate of Solvation Rate of Solvation there are three ways to increase collisions between the solvent and the solute. agitating the mixture increasing the surface area of the solute

More information

Chemistry 102 Spring 2019 Discussion #4 Chapters 11 and 12 Student name TA name Section

Chemistry 102 Spring 2019 Discussion #4 Chapters 11 and 12 Student name TA name Section Chemistry 102 Spring 2019 Discussion #4 Chapters 11 and 12 Student name TA name Section Things you should know when you finish the Discussion hand out: Average molar kinetic energy = E = M u 2 rms 2 =

More information

Experiment 1 Molecular Weight Determination from Freezing Point Depression

Experiment 1 Molecular Weight Determination from Freezing Point Depression CEAC 104 GENERAL CHEMISTRY Experiment 1 Molecular Weight Determination from Freezing Point Depression Purpose: To learn colligative properties and to determine the molecular weight of sulfur by using one

More information

Colligative Properties

Colligative Properties Colligative Properties! Consider three beakers: " 50.0 g of ice " 50.0 g of ice + 0.15 moles NaCl " 50.0 g of ice + 0.15 moles sugar (sucrose)! What will the freezing temperature of each beaker be? " Beaker

More information

Molality. Molality (m) is the number of moles of solute per kilogram of solvent. mol of solute kg solvent. Molality ( m) =

Molality. Molality (m) is the number of moles of solute per kilogram of solvent. mol of solute kg solvent. Molality ( m) = Molality Molality (m) is the number of moles of solute per kilogram of solvent. Molality ( m) = mol of solute kg solvent Sample Problem Calculate the molality of a solution of 13.5g of KF dissolved in

More information

Week 12/Th: Lecture Units 31 & 32

Week 12/Th: Lecture Units 31 & 32 Week 12/Th: Lecture Units 31 & 32 Unit 30: Chemical Spontaneity -- entropy, 2 nd Law of Thermo -- free energy -- spontaneity Unit 31: Phase Equilibria -- liquid / gas -- phase diagrams -- phase boundaries

More information

11/4/2017. General Chemistry CHEM 101 (3+1+0) Dr. Mohamed El-Newehy. Chapter 4 Physical Properties of Solutions

11/4/2017. General Chemistry CHEM 101 (3+1+0) Dr. Mohamed El-Newehy.   Chapter 4 Physical Properties of Solutions General Chemistry CHEM 11 (3+1+) Dr. Mohamed El-Newehy http://fac.ksu.edu.sa/melnewehy Chapter 4 Physical Properties of Solutions 1 Types of Solutions A solution is a homogenous mixture of 2 or more substances.

More information

6, Physical Chemistry -II (Statistical Thermodynamics, Chemical Dynamics, Electrochemistry and Macromolecules)

6, Physical Chemistry -II (Statistical Thermodynamics, Chemical Dynamics, Electrochemistry and Macromolecules) Subject Paper No and Title Module No and Title Module Tag 6, Physical -II (Statistical Thermodynamics, Chemical Dynamics, Electrochemistry and Macromolecules) 25, Activity and Mean Activity coefficient

More information

Chapter 11: Properties of Solutions - Their Concentrations and Colligative Properties. Chapter Outline

Chapter 11: Properties of Solutions - Their Concentrations and Colligative Properties. Chapter Outline Chapter 11: Properties of Solutions - Their Concentrations and Colligative Properties Chapter Outline 11.1 Energy Changes when Substances Dissolve 11.2 Vapor Pressure 11.3 Mixtures of Volatile Substances

More information

Additional Chapter 7 Homework Problems: Due with chapter 7 homework, show your work for full credit!

Additional Chapter 7 Homework Problems: Due with chapter 7 homework, show your work for full credit! Additional Chapter 7 Homework Problems: Due with chapter 7 homework, show your work for full credit! Note: If you are struggling with these, see the chapter 7 worksheet titled: Molarity, Molality, Osmolality,

More information

Chapter 11 Problems: 11, 15, 18, 20-23, 30, 32-35, 39, 41, 43, 45, 47, 49-51, 53, 55-57, 59-61, 63, 65, 67, 70, 71, 74, 75, 78, 81, 85, 86, 93

Chapter 11 Problems: 11, 15, 18, 20-23, 30, 32-35, 39, 41, 43, 45, 47, 49-51, 53, 55-57, 59-61, 63, 65, 67, 70, 71, 74, 75, 78, 81, 85, 86, 93 Chapter 11 Problems: 11, 15, 18, 20-23, 30, 32-35, 39, 41, 43, 45, 47, 49-51, 53, 55-57, 59-61, 63, 65, 67, 70, 71, 74, 75, 78, 81, 85, 86, 93 Chapter 11 Properties of Solutions Types of mixtures: homogenous

More information

1) Define the following terms: a) solution, b) miscible, c) hydration, d) percent by mass (solute), e) colligative property, f) hypotonic.

1) Define the following terms: a) solution, b) miscible, c) hydration, d) percent by mass (solute), e) colligative property, f) hypotonic. Problems - Chapter 13 (with solutions) 1) Define the following terms: a) solution, b) miscible, c) hydration, d) percent by mass (solute), e) colligative property, f) hypotonic. a) solution - A homogeneous

More information

CHEM N-7 November 2005

CHEM N-7 November 2005 CHEM1909 2005-N-7 November 2005 Calcium chloride (3.42 g) is completely dissolved in 200 ml of water at 25.00 ºC in a coffee cup calorimeter. The temperature of the water after dissolution is 27.95 ºC.

More information

SOLUTIONS. Chapter Test B. A. Matching. Column A. Column B. Name Date Class. 418 Core Teaching Resources

SOLUTIONS. Chapter Test B. A. Matching. Column A. Column B. Name Date Class. 418 Core Teaching Resources 16 SOLUTIONS Chapter Test B A. Matching Match each term in Column B to the correct description in Column A. Write the letter of the correct term on the line. Column A Column B 1. the number of moles of

More information

Colligative Properties

Colligative Properties Colligative Properties Vapor pressures have been defined as the pressure over a liquid in dynamic equilibrium between the liquid and gas phase in a closed system. The vapor pressure of a solution is different

More information

Chapter 12. Properties of Solutions

Chapter 12. Properties of Solutions Chapter 12. Properties of Solutions What we will learn: Types of solutions Solution process Interactions in solution Types of concentration Concentration units Solubility and temperature Solubility and

More information

ESSENTIAL EXPERIMENTS CHEMISTRY

ESSENTIAL EXPERIMENTS CHEMISTRY ESSENTIAL EXPERIMENTS for CHEMISTRY Morrison Scodellaro Sample Experiment Freezing Point Depression For additional information email: smg_order@smglabbooks.com Fax: 1-800-201-4587 Phone: 1-800-201-4587

More information

1. Which molecule will have the strongest intermolecular forces? _D. 2. Which molecule will have the weakest intermolecular forces?

1. Which molecule will have the strongest intermolecular forces? _D. 2. Which molecule will have the weakest intermolecular forces? Use the following information to answer questions 1-5: 1. Which molecule will have the strongest intermolecular forces? _D 2. Which molecule will have the weakest intermolecular forces? _C 3. What is the

More information

Department of Chemistry University of Texas at Austin

Department of Chemistry University of Texas at Austin Colligative Properties Supplemental Worksheet PROBLEM #1: Give the molecular formula, the van t hoff factor for the following Ionic Compounds as well as guess the solubility of the compounds. If you cannot

More information

Lecture 31: Solutions 5

Lecture 31: Solutions 5 Lecture 31: Solutions 5 Read: BLB 13.5 13.6 HW: BLB 13:9,58,61,67,69,75 Sup13:12 18 Know: colligative properties vapor pressure lowering boiling point elevation freezing point depression osmotic pressure

More information

CHEMISTRY XL-14A PHYSICAL EQUILIBRIUM. August 13, 2011 Robert Iafe

CHEMISTRY XL-14A PHYSICAL EQUILIBRIUM. August 13, 2011 Robert Iafe CHEMISTRY XL-14A PHYSICAL EQUILIBRIUM August 13, 2011 Robert Iafe Chapter Overview 2 Phases and Phase Transitions Solubility Colligative Properties Binary Liquid Mixtures Phases and Phase Transitions 3

More information

Quantitative Chemical

Quantitative Chemical Welcome to Analytical Chemistry Quantitative Chemical Analysis The textbook for this course is Quantitative Chemical Analysis Seventh Edition by Dan Harris ( 2007, W.H. Freeman & Company) http://ebooks.bfwpub.com/qchem

More information

2011, Robert Ayton. All rights reserved.

2011, Robert Ayton. All rights reserved. Solutions Outline 1. Solubility 2. Concentration Calculations 3. Colligative Properties 4. Freezing Point Depression or Boiling Point Elevation Problems 5. Graphs of Colligative Properties Review 1. Solubility

More information

Let's look at the following "reaction" Mixtures. water + salt > "salt water"

Let's look at the following reaction Mixtures. water + salt > salt water Mixtures What happens to the properties (phase changes) when we make a solution? Let's look at the following "reaction" water + salt ------> "salt water" Which has the higher entropy? A. The water + the

More information

WYSE Academic Challenge Sectional Chemistry 2005 SOLUTION SET

WYSE Academic Challenge Sectional Chemistry 2005 SOLUTION SET WYSE Academic Challenge Sectional Chemistry 2005 SOLUTION SET 1. Correct answer: c. Since the ion has a 2- charge, this means there are two extra electrons as compared to protons, so the ion must be sulfur

More information

COLLIGATIVE PROPERTIES. Engr. Yvonne Ligaya F. Musico 1

COLLIGATIVE PROPERTIES. Engr. Yvonne Ligaya F. Musico 1 COLLIGATIVE PROPERTIES Engr. Yvonne Ligaya F. Musico 1 Colligative Properties Properties that depend on the collective effect of the number of solute particles. Engr. Yvonne Ligaya F. Musico 2 COLLEGATIVE

More information

Solutions. Experiment 11. Various Types of Solutions. Solution: A homogenous mixture consisting of ions or molecules

Solutions. Experiment 11. Various Types of Solutions. Solution: A homogenous mixture consisting of ions or molecules Solutions Solution: A homogenous mixture consisting of ions or molecules -Assignment: Ch 15 Questions & Problems : 5, (15b,d), (17a, c), 19, 21, 23, 27, (33b,c), 39, (43c,d),45b, 47, (49b,d), (55a,b),

More information

An aqueous solution is 8.50% ammonium chloride by mass. The density of the solution is g/ml Find: molality, mole fraction, molarity.

An aqueous solution is 8.50% ammonium chloride by mass. The density of the solution is g/ml Find: molality, mole fraction, molarity. 66 An aqueous solution is 8.50% ammonium chloride by mass. The density of the solution is 1.024 g/ml Find: molality, mole fraction, molarity. Find molality: mass percent molality Assuming 100 g solution,

More information

EXPERIMENT 8 Determining K sp

EXPERIMENT 8 Determining K sp EXPERIMENT 8 Determining K sp Introduction The solubility product constant, or K sp of a compound is an equilibrium constant that describes the degree to which a solid dissolves in water. The K sp is calculated

More information

Chapter 11: Properties of Solutions - Their Concentrations and Colligative Properties. Chapter Outline

Chapter 11: Properties of Solutions - Their Concentrations and Colligative Properties. Chapter Outline Chapter 11: Properties of Solutions - Their Concentrations and Colligative Properties Chapter Outline 11.1 Energy Changes when Substances Dissolve 11.2 Vapor Pressure 11.3 Mixtures of Volatile Substances

More information

ALE 24. Colligative Properties (Part 2)

ALE 24. Colligative Properties (Part 2) Name Chem 162, Section: Group Number: ALE 24. Colligative Properties (Part 2) (Reference: 13.6 Silberberg 5 th edition) Why is calcium chloride spread on highways in the North during the Winter? The Model:

More information

Gilbert Kirss Foster. Chapter 11. Properties of Solutions. Their Concentrations and Colligative Properties

Gilbert Kirss Foster. Chapter 11. Properties of Solutions. Their Concentrations and Colligative Properties Gilbert Kirss Foster Chapter 11 Properties of Solutions Their Concentrations and Colligative Properties Chapter Outline 11.1 Energy Changes when Substances Dissolve 11.2 Vapor Pressure 11.3 Mixtures of

More information

Today is Wednesday, January 10 th, 2018

Today is Wednesday, January 10 th, 2018 In This Lesson: Molarity (Lesson 2 of 4) Today is Wednesday, January 10 th, 2018 Stuff You Need: Calculator Periodic Table Polyatomic Ion List Worksheet Pre-Class: Earlier in the year I used hydrogen peroxide

More information

Mixtures. What happens to the properties (phase changes) when we make a solution? Principles of Chemistry II. Vanden Bout

Mixtures. What happens to the properties (phase changes) when we make a solution? Principles of Chemistry II. Vanden Bout Mixtures What happens to the properties (phase changes) when we make a solution? Let's look at the following "reaction" water + salt ------> "salt water" Which has the higher entropy? A. The water + the

More information

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Chapter 13 MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) The process of solute particles being surrounded by solvent particles is known as. A)

More information

Colligative properties Answers from the handout 4 and 5 Refer to Page in the text book Mahaffy

Colligative properties Answers from the handout 4 and 5 Refer to Page in the text book Mahaffy Colligative properties Answers from the handout 4 and 5 Refer to Page 466-478 in the text book Mahaffy R = 8.314 [J/(mol K)] = 8.314 [(L kpa)/(mol K)] = 0.0806 [(L atm)/(mol K)] = 0.08314 [(L bar)/(mol

More information

Colligative Properties. Vapour pressure Boiling point Freezing point Osmotic pressure

Colligative Properties. Vapour pressure Boiling point Freezing point Osmotic pressure Colligative Properties Vapour pressure Boiling point Freezing point Osmotic pressure Learning objectives Describe meaning of colligative property Use Raoult s law to determine vapor pressure of solutions

More information

CHEMISTRY 122 [Tyvoll] PRACTICE EXAM II Possibly Useful Information: 2) ( ) ( ) ( ) ( ) ( ) R = L atm/mol K

CHEMISTRY 122 [Tyvoll] PRACTICE EXAM II Possibly Useful Information: 2) ( ) ( ) ( ) ( ) ( ) R = L atm/mol K Name Student ID # CHEMISTRY 122 [Tyvoll] PRACTICE EXAM II Spring 2008 1 2 3 4 5 Possibly Useful Information: 1) ( ) ( ) ( ) ( ) ( ) d (H 2 O) = 1.00 g/ml 2) ( ) ( ) ( ) ( ) ( ) R = 0.0821 L atm/mol K 3)

More information

Find molality: mass percent. molality Assume a basis of 100g solution, then find moles ammonium chloride: Find mass water: So molality is:

Find molality: mass percent. molality Assume a basis of 100g solution, then find moles ammonium chloride: Find mass water: So molality is: 66 An aqueous solution is 8.50% ammonium chloride by mass. The density of the solution is 1.024 g/ml Find: molality, mole fraction, molarity. Find molality: mass percent molality Assume a basis of 100g

More information

DATE: POGIL: Colligative Properties Part 2

DATE: POGIL: Colligative Properties Part 2 NAME: AP Chemistry DATE: POGIL: Colligative Properties Part 2 Why? In the winter, up here in the Great White North, people spread calcium chloride onto walkways to prevent them from icing over. Why do

More information