Homework. Chap 5. Simple mixtures. Exercises: 5B.8(a), 5C.4(b), 5C.10(a), 5F.2(a)

Size: px
Start display at page:

Download "Homework. Chap 5. Simple mixtures. Exercises: 5B.8(a), 5C.4(b), 5C.10(a), 5F.2(a)"

Transcription

1 Homework Cha 5. Simle mitures Eercises: 5.8(a), 5C.4(b), 5C.10(a), 5F.2(a) Problems: 5.5, 5.1, 5.4, 5.9, 5.10, 5C.3, 5C.4, 5C.5, 5C.6, 5C.7, 5C.8, Itegrated activities: 5.5, 5.8, 5.10,

2 Cha 5. Simle mitures (mitures that do ot react) The artial roerties of mitures: Use artial molar quatities chemical otetial, artial molar V(), etc t equilibrium, μ of a secies is the same i every hase Hery s law & Raoult s law i terms of mole fractio Effect of solute o roerties of a solutio: Lowerig vaor of the solvet Elevatio of T b Colligative roerties Deressio of T f (deedig o # of solute) Osmotic μ of a real miture: i terms of activity 2

3 5 장 -1 수업목표. Simle mitures dg Vd SdT d Chemical otetial: d G J J, T, ' Δ mi G of two erfect gas: mi G l l 0 of liquids: l for gas: o l o Raoult s law: l Hery s law: K ( m K )? 3

4 5. The thermodyamic descritio of mitures 5.1 Partial molar quatities Partial molar V : V J V J, T, ' the chage i V er mole of added to a large V of the miture V For biary miture (, ), V V dv d d, T,, T, dv V d V d V V d 0 0 V d V d V d 0 0 V V V 4

5 5.1(b) Partial molar Gibbs eergy the chemical otetial for a substace i a miture For a biary miture, G J J G For a system of comoets,, etc, dg = Vd SdT becomes, T, dg Vd SdT d d T, Fudametal equatio of chemical thermodyamics t cost. T ad, dg d d dw d d add,ma ' No-easio work ca arise from the chagig comositio of a system 5

6 5.1(c) The wider sigificace of the chemical otetial G U V TS U G V TS du dg dv Vd SdT TdS du ( Vd SdT du TdS dv d d J G J d d ) dv Vd SdT TdS, T, ' t cost. S ad V, du d d J U J S, V, ' J H J S,, ' J J T, V, ' 6

7 5.1(d) The Gibbs-Duhem equatio d J J J of oe comoet of a miture caot chage ideedetly of of the other comoets. The same lie of reasoig alies to all artial molar quatities 0 For a biary miture, recall that dg d d G dg d d d d d d 0 d d 7

8 5.2 The thermodyamics of miig the miig is sotaeous ΔG < 0 (a) Δ mi G of erfect gases o o l l o μ o : stadard chemical otetial : i the uit of bar o o l l o o l l G i G f mig G f Gi l l l l G l l 0 mi,, 8

9 5.2 The thermodyamics of miig the miig is sotaeous ΔG < 0 (b) Other thermodyamic miig fuctios G l l 0 mi Recall that G T, S G T mi mis,, R l l 0 mi H mi G T mi S 0 For a erfect gas, drivig force for miig solely comes from S (o iteractio betwee molecules) 9

10 (Sulemet): () l() +(1-) l(1-) l()+(1-)l(1-) l()+(1-)l(1-)

11 5.2 The thermodyamics of miig G l l 0 mi miig two erfect gases S R l l 0 mi 11

12 E 5.3 (185) 3.0 mol of H 2 (g) ad 1.0 mol o N 2 (g) are i two equal comartmets at 25. Calculate G mi whe the artitio is removed. Let the iitial, N 2 efore miig:, fter miig: N, 2 H G N H H N N H o o H l l 2 H 2 H 2 N 2 N 2 N2 o o 3.0 mol l mol l G i H N 2 2 o 3 o G f 3.0 mol H l 1.0 mol N l mig G f Gi 3.0 mol l 1.0 mol l mol l l 6.9 kj

13 5.3 The chemical otetials of liquids For ure substaces: (at eq., μ liq = μ vaor ) o ( g) l ( l) o l I the resece of aother substace l o l l l l l 13

14 5.3(a) Ideal solutios l Eerimetally Raoult foud that Raoult s law For a ideal solutios: (obey Raoult s law throughout the comositio rage from ure to ure : good whe two comoets are structurally similar) l 14

15 For ideal solutios: l Strog deviatios from ideality by dissimilar liquids Eve some solutios deart sigificatly from Raoult s law, it is a good aroimatio for the roerties of the solvet if the solutio is dilute 15

16 E 5.4 (189) The vaor ressure of each comoet i a miture (acetoe + chloroform) were measured at 35 C C /kpa /kpa Cofirm that the miture coforms to Raoult s law for the major comoet ad Hery s law for the mior comoet. Fid the Hery s law costats. 16

17 5.3(b) Ideal-dilute solutios Dilute solutio solvet: a slightly modified ure liquid solute: etirely differet from its ure state Ideal-dilute solutios, but Hery s law K? : emirical costat K? Practically, m K m = mol/1 kg m O bis 5.4 (190) the molar solubility of O 2 i water at 25 O 21 kpa mol kg K kpa kg mol O 2 O 2 H2O O O m m kg L mm 17

18 5 장 -2 수업목표. The roerties of solutio Miig ideal solutios: mi G l l Colligative roerties (deeds oly o # of solute articles) l T T b f va fus 2 H H 2 K K b f m m M r 1000 m Osmotic ressure, Π: va t Hoff eq: Real solutio: J 1 J 18

19 G 5. The roerties of solutios 5.1 Liquid mitures (a) Ideal solutios (miscible all the time) i l T l G R f G l l mi S R l l mi mi H 0 Same as that for two ideal gases (E ave of - iteractios i the miture is the same as E ave of - ad - iteractios i the ure liquids) 19

20 Real solutios iteractios are all differet: miscible, immiscible, artially miscible 5.1(b) Ecess fuctios ad regular solutios Ecess fuctios: X E mi X H 0 mi mi X ideal the etet to which the solutios are oideal Ideal solutios (miscible all the time) Regular solutios: S E = 0, H E 0 20

21 5.2 Colligative roerties deeds oly o the # of solute articles reset, ot their idetity E, T b, T f, osmotic ressure (Π) ssumtios: the solute is oly i liquid solvet (ot volatile, ot dissolved i the solid solvet) (a) Commo features of colligative roerties l Whe solute is reset, the disorder of the liquid is higher tha that of the ure liquid, ad there is a decreased tedecy to acquire the disorder characteristic of the vaor. 21

22 5.2(b) T b T K m b b t T b, ( g) ( l) ( l) l ( g) ( l) vag l vah TvaS vah 1 1 R T T va T T va T 2 T H H R T T R b 2 H va T M r Sice m (see et slid e) 1000 l l 1 va S T va vas T vah T 0 Pure solvet: 0 va H T vah T va va va R R H T va S T S T S ! for l 1 H Tb H va H 2 2 va M r m 1000 K m b where 2 H Kb va M r

23 m 1 edi r m : i 1 kg of for 1 kg of : m M r m 1 molal water solutio ( m 1): for 1 kg of 1000 kg of for 1 kg of 1000 M 1, :1 kg 1000 M kg of water: 55.6 M 18 r r M r 18 1 m

24 T 2 5.2(c) T f K m f f fush where K f 2 H fus M r 1000 t Tf, ( s) ( l) ( l) l ( s) ( l) fusg l d fusg l dt d l 1 d fusg 1 fush 2 dt R dt T R T l 1 T fush d l dt 1 T 2 R T T fush 1 dt T 2 R T fush 1 1 l l 1 R T T fush 1 1 fush T T R T T R TT fush T 2 R T 2 T H fus 24

25 5.2(d) Solubility l fush 1 1 R Tf T Highly questioable No solvet roerties ( s) ( l) ( l) l ( s) ( l) fusg l d fusg l dt d l 1 d fusg 1 fush 2 dt R dt T R T l 1 T fush d l dt 0 T 2 R f T T fush 1 dt T 2 R f T l fush 1 1 R T Tf fush T T R TT f f 25

26 5.2(e) Osmosis ( ush i Greek) the sotaeous assage of a ure solvet ito a solutio searated from it by a semiermeable membrae Osmotic ressure, Π: that must be alied to the solutio to sto the iflu of solvet 26

27 Osmotic ressure, Π: that must be alied to the solutio to sto the iflu of solvet va t Hoff eq: ( ) ( ) ( ) l ( ) ( ) V m, m, m, m, l V d V l l 1 V V V d Real solutio: J 1 J : Osmotic virial coefficiet 27

28 E 5.2 (200) Π of solutios of PVC i cycloheae at 298 K are measured. The ressure are eressed i terms of the heights of solutio ( = g cm -3 ) i balace with Π. Determie the molar mass of the olymer. M M c/(g dm -3 ) h/cm (h/c)/(cm g -1 dm 3 ) h R c 2 c T gm gm Plot h/c vs, c get itercet g J K mol 298 K cm g 2 3 kg m 9.81 m s m kg kg mol dm 1 J J 1 J c, gh M c c gh 1 M M h c 1 c gm M 2 gm gm c 28

PhysChem05 CHEMICAL POTENTIAL CHEMICAL POTENTIAL CHEMICAL POTENTIAL CHEMICAL POTENTIAL CHEMICAL POTENTIAL I. CHEMICAL POTENTIAL OF AN IDEAL GAS

PhysChem05 CHEMICAL POTENTIAL CHEMICAL POTENTIAL CHEMICAL POTENTIAL CHEMICAL POTENTIAL CHEMICAL POTENTIAL I. CHEMICAL POTENTIAL OF AN IDEAL GAS he cocet of calculatio of the chemical otetial i oe- ad multi-comoet systems I. Chemical otetial of a ideal gas II. Chemical otetial of real gases. Fugacity III. Chemical otetial of liquids IV. Chemical

More information

Chapter 5. Simple Mixtures Fall Semester Physical Chemistry 1 (CHM2201)

Chapter 5. Simple Mixtures Fall Semester Physical Chemistry 1 (CHM2201) Chapter 5. Simple Mixtures 2011 Fall Semester Physical Chemistry 1 (CHM2201) Contents The thermodynamic description of mixtures 5.1 Partial molar quantities 5.2 The thermodynamic of Mixing 5.3 The chemical

More information

Simple Mixtures. Chapter 7 of Atkins: Section

Simple Mixtures. Chapter 7 of Atkins: Section Simple Mixtures Chapter 7 of Atkins: Section 7.5-7.8 Colligative Properties Boiling point elevation Freezing point depression Solubility Osmotic Pressure Activities Solvent Activity Solute Activity Regular

More information

Lecture 6. NONELECTROLYTE SOLUTONS

Lecture 6. NONELECTROLYTE SOLUTONS Lecture 6. NONELECTROLYTE SOLUTONS NONELECTROLYTE SOLUTIONS SOLUTIONS single phase homogeneous mixture of two or more components NONELECTROLYTES do not contain ionic species. CONCENTRATION UNITS percent

More information

What is Physical Chemistry. Physical Chemistry for Chemical Engineers CHEM251. Basic Characteristics of a Gas

What is Physical Chemistry. Physical Chemistry for Chemical Engineers CHEM251. Basic Characteristics of a Gas 7/6/0 hysical Chemistry for Chemical Egieers CHEM5 What is hysical Chemistry hysical Chemistry is the study of the uderlyig physical priciples that gover the properties ad behaviour of chemical systems

More information

Liquids and Solutions Crib Sheet

Liquids and Solutions Crib Sheet Liquids and Solutions Crib Sheet Determining the melting point of a substance from its solubility Consider a saturated solution of B in a solvent, A. Since the solution is saturated, pure solid B is in

More information

Chapter 14: Chemical Equilibrium

Chapter 14: Chemical Equilibrium hapter 14: hemical Equilibrium 46 hapter 14: hemical Equilibrium Sectio 14.1: Itroductio to hemical Equilibrium hemical equilibrium is the state where the cocetratios of all reactats ad products remai

More information

Unit 5. Gases (Answers)

Unit 5. Gases (Answers) Uit 5. Gases (Aswers) Upo successful completio of this uit, the studets should be able to: 5. Describe what is meat by gas pressure.. The ca had a small amout of water o the bottom to begi with. Upo heatig

More information

Chemical Kinetics CHAPTER 14. Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop. CHAPTER 14 Chemical Kinetics

Chemical Kinetics CHAPTER 14. Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop. CHAPTER 14 Chemical Kinetics Chemical Kietics CHAPTER 14 Chemistry: The Molecular Nature of Matter, 6 th editio By Jesperso, Brady, & Hyslop CHAPTER 14 Chemical Kietics Learig Objectives: Factors Affectig Reactio Rate: o Cocetratio

More information

17 Phonons and conduction electrons in solids (Hiroshi Matsuoka)

17 Phonons and conduction electrons in solids (Hiroshi Matsuoka) 7 Phoos ad coductio electros i solids Hiroshi Matsuoa I this chapter we will discuss a miimal microscopic model for phoos i a solid ad a miimal microscopic model for coductio electros i a simple metal.

More information

Chapter 4. Fourier Series

Chapter 4. Fourier Series Chapter 4. Fourier Series At this poit we are ready to ow cosider the caoical equatios. Cosider, for eample the heat equatio u t = u, < (4.) subject to u(, ) = si, u(, t) = u(, t) =. (4.) Here,

More information

Phase Equilibrium: Preliminaries

Phase Equilibrium: Preliminaries Phase Equilibrium: Preliminaries Phase diagrams for two one component systems, CO 2 and H 2 O, are shown below. The main items to note are the following: The lines represent equilibria between two phases.

More information

Solutions to Equilibrium Practice Problems

Solutions to Equilibrium Practice Problems Solutios to Equilibrium Practice Problems Chem09 Fial Booklet Problem 1. Solutio: PO 4 10 eq The expressio for K 3 5 P O 4 eq eq PO 4 10 iit 1 M I (a) Q 1 3, the reactio proceeds to the right. 5 5 P O

More information

Special Modeling Techniques

Special Modeling Techniques Colorado School of Mies CHEN43 Secial Modelig Techiques Secial Modelig Techiques Summary of Toics Deviatio Variables No-Liear Differetial Equatios 3 Liearizatio of ODEs for Aroximate Solutios 4 Coversio

More information

General Physical Chemistry I

General Physical Chemistry I General Physical Chemistry I Lecture 14 Aleksey Kocherzhenko April 9, 2015" Last time " Chemical potential " Partial molar property the contribution per mole that a substance makes to an overall property

More information

9.4.3 Fundamental Parameters. Concentration Factor. Not recommended. See Extraction factor. Decontamination Factor

9.4.3 Fundamental Parameters. Concentration Factor. Not recommended. See Extraction factor. Decontamination Factor 9.4.3 Fudametal Parameters Cocetratio Factor Not recommeded. See Extractio factor. Decotamiatio Factor The ratio of the proportio of cotamiat to product before treatmet to the proportio after treatmet.

More information

Effect of adding an ideal inert gas, M

Effect of adding an ideal inert gas, M Effect of adding an ideal inert gas, M Add gas M If there is no change in volume, then the partial pressures of each of the ideal gas components remains unchanged by the addition of M. If the reaction

More information

School of Chemical & Biological Engineering, Konkuk University

School of Chemical & Biological Engineering, Konkuk University School of Chemical & iological Engineering, Konkuk University Lecture 7 Ch. 5 Simple Mixtures Colligative properties Prof. Yo-Sep Min Physical Chemistry I, Spring 2009 Ch. 5-2 he presence of a solute in

More information

7 Simple mixtures. Solutions to exercises. Discussion questions. Numerical exercises

7 Simple mixtures. Solutions to exercises. Discussion questions. Numerical exercises 7 Simple mixtures Solutions to exercises Discussion questions E7.1(b For a component in an ideal solution, Raoult s law is: p xp. For real solutions, the activity, a, replaces the mole fraction, x, and

More information

TEACHER CERTIFICATION STUDY GUIDE

TEACHER CERTIFICATION STUDY GUIDE COMPETENCY 1. ALGEBRA SKILL 1.1 1.1a. ALGEBRAIC STRUCTURES Kow why the real ad complex umbers are each a field, ad that particular rigs are ot fields (e.g., itegers, polyomial rigs, matrix rigs) Algebra

More information

Subject : Chemistry Class : XII Chapter-2.Solutions Work Sheet ( WS 2. 1) Topic- 2.1 Henry s & Raoult s Laws

Subject : Chemistry Class : XII Chapter-2.Solutions Work Sheet ( WS 2. 1) Topic- 2.1 Henry s & Raoult s Laws Work Sheet ( WS 2. 1) Topic- 2.1 Henry s & Raoult s Laws Name -. Class/ sec.. Roll No.. A. Fill in the blanks: 1. Solutions are mixtures of two or more than two components. 2. Generally, the component

More information

Nonequilibrium Excess Carriers in Semiconductors

Nonequilibrium Excess Carriers in Semiconductors Lecture 8 Semicoductor Physics VI Noequilibrium Excess Carriers i Semicoductors Noequilibrium coditios. Excess electros i the coductio bad ad excess holes i the valece bad Ambiolar trasort : Excess electros

More information

J. Serb. Chem. Soc. 82 (4) S208 S220 (2017) Supplementary material

J. Serb. Chem. Soc. 82 (4) S208 S220 (2017) Supplementary material J. Serb. Chem. Soc. 82 (4) S8 S2 (7) Supplemetary material SUPPLEMENARY MAERIAL O Experimetal measuremets ad modellig of solvet activity ad surface tesio of biary mixtures of poly(viyl pyrrolidoe) i water

More information

Lecture 6 Chi Square Distribution (χ 2 ) and Least Squares Fitting

Lecture 6 Chi Square Distribution (χ 2 ) and Least Squares Fitting Lecture 6 Chi Square Distributio (χ ) ad Least Squares Fittig Chi Square Distributio (χ ) Suppose: We have a set of measuremets {x 1, x, x }. We kow the true value of each x i (x t1, x t, x t ). We would

More information

FUGACITY. It is simply a measure of molar Gibbs energy of a real gas.

FUGACITY. It is simply a measure of molar Gibbs energy of a real gas. FUGACITY It is simly a measure of molar Gibbs energy of a real gas. Modifying the simle equation for the chemical otential of an ideal gas by introducing the concet of a fugacity (f). The fugacity is an

More information

dn i where we have used the Gibbs equation for the Gibbs energy and the definition of chemical potential

dn i where we have used the Gibbs equation for the Gibbs energy and the definition of chemical potential Chem 467 Sulement to Lectures 33 Phase Equilibrium Chemical Potential Revisited We introduced the chemical otential as the conjugate variable to amount. Briefly reviewing, the total Gibbs energy of a system

More information

Lecture 6 Chi Square Distribution (χ 2 ) and Least Squares Fitting

Lecture 6 Chi Square Distribution (χ 2 ) and Least Squares Fitting Lecture 6 Chi Square Distributio (χ ) ad Least Squares Fittig Chi Square Distributio (χ ) Suppose: We have a set of measuremets {x 1, x, x }. We kow the true value of each x i (x t1, x t, x t ). We would

More information

Nernst Equation. Nernst Equation. Electric Work and Gibb's Free Energy. Skills to develop. Electric Work. Gibb's Free Energy

Nernst Equation. Nernst Equation. Electric Work and Gibb's Free Energy. Skills to develop. Electric Work. Gibb's Free Energy Nerst Equatio Skills to develop Eplai ad distiguish the cell potetial ad stadard cell potetial. Calculate cell potetials from kow coditios (Nerst Equatio). Calculate the equilibrium costat from cell potetials.

More information

SOLUTIONS Homogeeous mixture: Substaces which dissolve with each other thoroughly to form a uiform mixture is called homogeeous mixture. Eg: Water + Salt. Solutios: homogeeous mixture formed with two or

More information

The Second Law: The Machinery

The Second Law: The Machinery The Second Law: The Machinery Chater 5 of Atkins: The Second Law: The Concets Sections 3.7-3.9 8th Ed, 3.3 9th Ed; 3.4 10 Ed.; 3E 11th Ed. Combining First and Second Laws Proerties of the Internal Energy

More information

Thermodynamic condition for equilibrium between two phases a and b is G a = G b, so that during an equilibrium phase change, G ab = G a G b = 0.

Thermodynamic condition for equilibrium between two phases a and b is G a = G b, so that during an equilibrium phase change, G ab = G a G b = 0. CHAPTER 5 LECTURE NOTES Phases and Solutions Phase diagrams for two one component systems, CO 2 and H 2 O, are shown below. The main items to note are the following: The lines represent equilibria between

More information

MATH 10550, EXAM 3 SOLUTIONS

MATH 10550, EXAM 3 SOLUTIONS MATH 155, EXAM 3 SOLUTIONS 1. I fidig a approximate solutio to the equatio x 3 +x 4 = usig Newto s method with iitial approximatio x 1 = 1, what is x? Solutio. Recall that x +1 = x f(x ) f (x ). Hece,

More information

Chemical Engineering 160/260 Polymer Science and Engineering. Model for Polymer Solutions February 5, 2001

Chemical Engineering 160/260 Polymer Science and Engineering. Model for Polymer Solutions February 5, 2001 Chemical Egieerig 60/60 Polymer Sciece ad Egieerig Lecture 9 - Flory-Huggis Model for Polymer Solutios February 5, 00 Read Sperlig, Chapter 4 Objectives! To develop the classical Flory-Huggis theory for

More information

5.4 Liquid Mixtures. G i. + n B. = n A. )+ n B. + RT ln x A. + RT ln x B. G = nrt ( x A. ln x A. Δ mix. + x B S = nr( x A

5.4 Liquid Mixtures. G i. + n B. = n A. )+ n B. + RT ln x A. + RT ln x B. G = nrt ( x A. ln x A. Δ mix. + x B S = nr( x A 5.4 Liquid Mixtures Key points 1. The Gibbs energy of mixing of two liquids to form an ideal solution is calculated in the same way as for two perfect gases 2. A regular solution is one in which the entropy

More information

- Applications: In chemistry, this effect is often used to determine the molecular weight of an unknown molecule.

- Applications: In chemistry, this effect is often used to determine the molecular weight of an unknown molecule. 73 FREEZING POINT DEPRESSION concentration of solute (molality) Freezing point depression constant (for SOLVENT) Freezing point depression: The amount the freezing temperature is LOWERED by the solute.

More information

We now turn to considerations of mixtures. To keep our discussion reasonably simple,

We now turn to considerations of mixtures. To keep our discussion reasonably simple, 143 Lecture 23 We now turn to considerations of mixtures. To kee our discussion reasonably simle, we will limit our discussion to non-reacting systems, and to non-ionic systems. In other words, we will

More information

Unit 4: Polynomial and Rational Functions

Unit 4: Polynomial and Rational Functions 48 Uit 4: Polyomial ad Ratioal Fuctios Polyomial Fuctios A polyomial fuctio y px ( ) is a fuctio of the form p( x) ax + a x + a x +... + ax + ax+ a 1 1 1 0 where a, a 1,..., a, a1, a0are real costats ad

More information

(a) (b) All real numbers. (c) All real numbers. (d) None. to show the. (a) 3. (b) [ 7, 1) (c) ( 7, 1) (d) At x = 7. (a) (b)

(a) (b) All real numbers. (c) All real numbers. (d) None. to show the. (a) 3. (b) [ 7, 1) (c) ( 7, 1) (d) At x = 7. (a) (b) Chapter 0 Review 597. E; a ( + )( + ) + + S S + S + + + + + + S lim + l. D; a diverges by the Itegral l k Test sice d lim [(l ) ], so k l ( ) does ot coverge absolutely. But it coverges by the Alteratig

More information

Lecture 3. Electron and Hole Transport in Semiconductors

Lecture 3. Electron and Hole Transport in Semiconductors Lecture 3 lectro ad Hole Trasort i Semicoductors I this lecture you will lear: How electros ad holes move i semicoductors Thermal motio of electros ad holes lectric curret via lectric curret via usio Semicoductor

More information

Appendix: The Laplace Transform

Appendix: The Laplace Transform Appedix: The Laplace Trasform The Laplace trasform is a powerful method that ca be used to solve differetial equatio, ad other mathematical problems. Its stregth lies i the fact that it allows the trasformatio

More information

Brief reminder of the previous lecture

Brief reminder of the previous lecture Brief reminder of the previous lecture partial molar quantities: contribution of each component to the properties of mixtures V j V = G µ = j n j n j pt,, n pt,, n dg = Vdp SdT + µ dn + µ dn +... A A B

More information

All Excuses must be taken to 233 Loomis before 4:15, Monday, April 30.

All Excuses must be taken to 233 Loomis before 4:15, Monday, April 30. Miscellaeous Notes The ed is ear do t get behid. All Excuses must be take to 233 Loomis before 4:15, Moday, April 30. The PYS 213 fial exam times are * 8-10 AM, Moday, May 7 * 8-10 AM, Tuesday, May 8 ad

More information

Properties and Tests of Zeros of Polynomial Functions

Properties and Tests of Zeros of Polynomial Functions Properties ad Tests of Zeros of Polyomial Fuctios The Remaider ad Factor Theorems: Sythetic divisio ca be used to fid the values of polyomials i a sometimes easier way tha substitutio. This is show by

More information

Solutions to Final Exam Review Problems

Solutions to Final Exam Review Problems . Let f(x) 4+x. Solutios to Fial Exam Review Problems Math 5C, Witer 2007 (a) Fid the Maclauri series for f(x), ad compute its radius of covergece. Solutio. f(x) 4( ( x/4)) ( x/4) ( ) 4 4 + x. Sice the

More information

Material Balances on Reactive Processes F&R

Material Balances on Reactive Processes F&R Material Balaces o Reactive Processes F&R 4.6-4.8 What does a reactio do to the geeral balace equatio? Accumulatio = I Out + Geeratio Cosumptio For a reactive process at steady-state, the geeral balace

More information

Chapter 5 Gases A Summary

Chapter 5 Gases A Summary Chapter 5 Gases A Summary 5. ressure A. roperties of gases. Gases uiformly fill ay cotaier. Gases are easily compressed 3. Gases mix completely with ay other gas 4. Gases exert pressure o their surroudigs

More information

Physics Supplement to my class. Kinetic Theory

Physics Supplement to my class. Kinetic Theory Physics Supplemet to my class Leaers should ote that I have used symbols for geometrical figures ad abbreviatios through out the documet. Kietic Theory 1 Most Probable, Mea ad RMS Speed of Gas Molecules

More information

concentration of solute (molality) Freezing point depression constant (for SOLVENT)

concentration of solute (molality) Freezing point depression constant (for SOLVENT) 74 FREEZING POINT DEPRESSION concentration of solute (molality) Freezing point depression constant (for SOLVENT) Freezing point depression: The amount the freezing temperature is LOWERED by the solute.

More information

LECTURE 6 NON ELECTROLYTE SOLUTION

LECTURE 6 NON ELECTROLYTE SOLUTION LECTURE 6 NON ELECTROLYTE SOLUTION Ch 45.5 pplied Phy Chem First Sem 2014-15 Ch 45.5 Exam II September 1/3 (Multiple Choice/Problem Solving) Coverage: Second/Third Laws of Thermodynamics Nonelectrolyte

More information

MATH Exam 1 Solutions February 24, 2016

MATH Exam 1 Solutions February 24, 2016 MATH 7.57 Exam Solutios February, 6. Evaluate (A) l(6) (B) l(7) (C) l(8) (D) l(9) (E) l() 6x x 3 + dx. Solutio: D We perform a substitutio. Let u = x 3 +, so du = 3x dx. Therefore, 6x u() x 3 + dx = [

More information

70 Example: If a solution is m citric acid, what is the molar concentration (M) of the solution? The density of the solution is 1.

70 Example: If a solution is m citric acid, what is the molar concentration (M) of the solution? The density of the solution is 1. 70 Example: If a solution is 0.688 m citric acid, what is the molar concentration (M) of the solution? The density of the solution is 1.049 g/ml molality definition molarity definition To solve the problem,

More information

1. Hydrogen Atom: 3p State

1. Hydrogen Atom: 3p State 7633A QUANTUM MECHANICS I - solutio set - autum. Hydroge Atom: 3p State Let us assume that a hydroge atom is i a 3p state. Show that the radial part of its wave fuctio is r u 3(r) = 4 8 6 e r 3 r(6 r).

More information

General Chemistry revisited

General Chemistry revisited General Chemistry revisited A(g) + B(g) C(g) + D(g) We said that G = H TS where, eg, H = f H(C) + f H(D) - f H(A) - f H(B) G < 0 implied spontaneous to right G > 0 implied spontaneous to left In a very

More information

Chapter 11. General Chemistry. Chapter 11/1

Chapter 11. General Chemistry. Chapter 11/1 Chapter 11 Solutions and Their Properties Professor Sam Sawan General Chemistry 84.122 Chapter 11/1 Solutions Solution: A homogeneous mixture. Solvent: The major component. Solute: A minor component. Copyright

More information

Design for Manufacture. 3. Thermodynamics

Design for Manufacture. 3. Thermodynamics Desig for Maufacture 3. hermodyamics hermodyamics hermodyamics study of heat related matter i motio. Major developmets durig 650-850 850 Egieerig thermodyamics maily cocered with work producig or utilisig

More information

Curve Sketching Handout #5 Topic Interpretation Rational Functions

Curve Sketching Handout #5 Topic Interpretation Rational Functions Curve Sketchig Hadout #5 Topic Iterpretatio Ratioal Fuctios A ratioal fuctio is a fuctio f that is a quotiet of two polyomials. I other words, p ( ) ( ) f is a ratioal fuctio if p ( ) ad q ( ) are polyomials

More information

P 1 V V V T V V. AP Chemistry A. Allan Chapter 5 - Gases

P 1 V V V T V V. AP Chemistry A. Allan Chapter 5 - Gases A Chemistry A. Alla Chapter 5 - Gases 5. ressure A. roperties of gases. Gases uiformly fill ay cotaier. Gases are easily compressed 3. Gases mix completely with ay other gas 4. Gases exert pressure o their

More information

m m 3 mol Pa = Pa or bar At this pressure the system must also be at approximately 1000 K.

m m 3 mol Pa = Pa or bar At this pressure the system must also be at approximately 1000 K. 5. PHASES AND SOLUTIONS n Thermodynamics of Vapor Pressure 5.. At equilibrium, G(graphite) G(diamond); i.e., G 2 0. We are given G 2900 J mol. ( G/ P) T V V 2.0 g mol.95 0 6 m 3 mol Holding T constant

More information

MCT242: Electronic Instrumentation Lecture 2: Instrumentation Definitions

MCT242: Electronic Instrumentation Lecture 2: Instrumentation Definitions Faculty of Egieerig MCT242: Electroic Istrumetatio Lecture 2: Istrumetatio Defiitios Overview Measuremet Error Accuracy Precisio ad Mea Resolutio Mea Variace ad Stadard deviatio Fiesse Sesitivity Rage

More information

Physical Chemistry Chapter 4 The Properties of Mixtures

Physical Chemistry Chapter 4 The Properties of Mixtures Physical Chemistry Chapter 4 The Properties of Mixtures by Izirwan Bin Izhab FKKSA izirwan@ump.edu.my Chapter Description Aims Determine the fugacity and fugacity coefficients for pure species using generic

More information

f(x) dx as we do. 2x dx x also diverges. Solution: We compute 2x dx lim

f(x) dx as we do. 2x dx x also diverges. Solution: We compute 2x dx lim Math 3, Sectio 2. (25 poits) Why we defie f(x) dx as we do. (a) Show that the improper itegral diverges. Hece the improper itegral x 2 + x 2 + b also diverges. Solutio: We compute x 2 + = lim b x 2 + =

More information

VAPOR PRESSURE LOWERING - Described by RAOULT'S LAW

VAPOR PRESSURE LOWERING - Described by RAOULT'S LAW 73 VAPOR PRESSURE LOWERING - Described by RAOULT'S LAW partial pressure of the VAPOR of solvent molecules. mole fraction of component A vapor pressure of pure component A (depends on temperature) partial

More information

A. Much too slow. C. Basically about right. E. Much too fast

A. Much too slow. C. Basically about right. E. Much too fast Geeral Questio 1 t this poit, we have bee i this class for about a moth. It seems like this is a good time to take stock of how the class is goig. g I promise ot to look at idividual resposes, so be cadid!

More information

CHEE 221: Chemical Processes and Systems

CHEE 221: Chemical Processes and Systems CHEE 221: Chemical Processes ad Systems Module 3. Material Balaces with Reactio Part a: Stoichiometry ad Methodologies (Felder & Rousseau Ch 4.6 4.8 ot 4.6c ) Material Balaces o Reactive Processes What

More information

Thermodynamics (Revision 1)

Thermodynamics (Revision 1) hermodyamics (Revisio ) hermodyamics study of heat related to matter i motio. Egieerig thermodyamics maily cocered with work producig or utilisig machies such as egies, turbies ad compressors together

More information

UNIT 9.SOLUTIONS.

UNIT 9.SOLUTIONS. BOOK BACK QUESTION AND ANSWERS: 31.Define (i) molality (ii) Normality (i) molality (ii) Normality UNIT 9.SOLUTIONS Number of moles of solute Molality(m) = Mass of the solvent( in Kg) Number of gram equivalengt

More information

Solutions and Their Properties

Solutions and Their Properties Chapter 11 Solutions and Their Properties Solutions: Definitions A solution is a homogeneous mixture. A solution is composed of a solute dissolved in a solvent. When two compounds make a solution, the

More information

x =!b ± b2! 4ac 2a moles particles solution (expt) moles solute dissolved (calculated conc ) i =

x =!b ± b2! 4ac 2a moles particles solution (expt) moles solute dissolved (calculated conc ) i = Properties of Solution Practice Exam Solutions Name (last) (First) Read all questions before you start. Show all work and explain your answers. Report all numerical answers to the proper number of sig.

More information

RADICAL EXPRESSION. If a and x are real numbers and n is a positive integer, then x is an. n th root theorems: Example 1 Simplify

RADICAL EXPRESSION. If a and x are real numbers and n is a positive integer, then x is an. n th root theorems: Example 1 Simplify Example 1 Simplify 1.2A Radical Operatios a) 4 2 b) 16 1 2 c) 16 d) 2 e) 8 1 f) 8 What is the relatioship betwee a, b, c? What is the relatioship betwee d, e, f? If x = a, the x = = th root theorems: RADICAL

More information

The underlying prerequisite to the application of thermodynamic principles to natural systems is that the system under consideration should be at equilibrium. http://eps.mcgill.ca/~courses/c220/ Reversible

More information

Physical Properties of Solutions

Physical Properties of Solutions Physical Properties of Solutions Physical Properties of Solutions Types of Solutions (13.1) A Molecular View of the Solution Process (13.2) Concentration Units (13.3) Effect of Temperature on Solubility

More information

Chapter 13. Ions in aqueous Solutions And Colligative Properties

Chapter 13. Ions in aqueous Solutions And Colligative Properties Chapter 13 Ions in aqueous Solutions And Colligative Properties Compounds in Aqueous Solution Dissociation The separation of ions that occurs when an ionic compound dissolves H2O NaCl (s) Na+ (aq) + Cl-

More information

Calculus 2 - D. Yuen Final Exam Review (Version 11/22/2017. Please report any possible typos.)

Calculus 2 - D. Yuen Final Exam Review (Version 11/22/2017. Please report any possible typos.) Calculus - D Yue Fial Eam Review (Versio //7 Please report ay possible typos) NOTE: The review otes are oly o topics ot covered o previous eams See previous review sheets for summary of previous topics

More information

Freezing point depression - The freezing temperature of a SOLUTION gets lower as the CONCENTRATION of a solution increases.

Freezing point depression - The freezing temperature of a SOLUTION gets lower as the CONCENTRATION of a solution increases. 73 COLLIGATIVE PROPERTIES - properties unique to solutions. - depend only on the CONCENTRATION of a solution and not the IDENTITY of the solute** **ionic solutes: Remember that they dissociate into MULTIPLE

More information

The time evolution of the state of a quantum system is described by the time-dependent Schrödinger equation (TDSE): ( ) ( ) 2m "2 + V ( r,t) (1.

The time evolution of the state of a quantum system is described by the time-dependent Schrödinger equation (TDSE): ( ) ( ) 2m 2 + V ( r,t) (1. Adrei Tokmakoff, MIT Departmet of Chemistry, 2/13/2007 1-1 574 TIME-DEPENDENT QUANTUM MECHANICS 1 INTRODUCTION 11 Time-evolutio for time-idepedet Hamiltoias The time evolutio of the state of a quatum system

More information

Different kinds of Mathematical Induction

Different kinds of Mathematical Induction Differet ids of Mathematical Iductio () Mathematical Iductio Give A N, [ A (a A a A)] A N () (First) Priciple of Mathematical Iductio Let P() be a propositio (ope setece), if we put A { : N p() is true}

More information

Chemistry 531 Spring 2009 Problem Set 6 Solutions

Chemistry 531 Spring 2009 Problem Set 6 Solutions Chemistry 531 Sring 2009 Problem Set 6 Solutions 1. In a thermochemical study of N 2, the following heat caacity data were found: t 0 C,m d 27.2Jmol 1 K 1 f t b f C,m d 23.4Jmol 1 K 1 C,m d 11.4Jmol 1

More information

Name: Discussion Section:

Name: Discussion Section: CBE 141: Chemical Engineering Thermodynamics, Spring 2017, UC Berkeley Midterm 2 FORM B March 23, 2017 Time: 80 minutes, closed-book and closed-notes, one-sided 8 ½ x 11 equation sheet allowed lease show

More information

ERT 318 UNIT OPERATIONS

ERT 318 UNIT OPERATIONS ERT 318 UNIT OPERATIONS DISTILLATION W. L. McCabe, J. C. Smith, P. Harriot, Uit Operatios of Chemical Egieerig, 7 th editio, 2005. 1 Outlie: Batch distillatio (pg. 724) Cotiuous distillatio with reflux

More information

75 A solution of 2.500g of unknown dissolved in g of benzene has a freezing point of C. What is the molecular weight of the unknown?

75 A solution of 2.500g of unknown dissolved in g of benzene has a freezing point of C. What is the molecular weight of the unknown? 75 A solution of 2.500g of unknown dissolved in 100.0 g of benzene has a freezing point of 4.880 C. What is the molecular weight of the unknown? Solving for Cm (molality) will allow us to calculate how

More information

Apply change-of-basis formula to rewrite x as a linear combination of eigenvectors v j.

Apply change-of-basis formula to rewrite x as a linear combination of eigenvectors v j. Eigevalue-Eigevector Istructor: Nam Su Wag eigemcd Ay vector i real Euclidea space of dimesio ca be uiquely epressed as a liear combiatio of liearly idepedet vectors (ie, basis) g j, j,,, α g α g α g α

More information

Chemistry 163B. Concluding Factoids. and. Comments

Chemistry 163B. Concluding Factoids. and. Comments Chemistry 163B Concluding Factoids and Comments 1 neuron, resting potential http://projects.gw.utwente.nl/pi/sim/bovt/concep4.gif http://www.uta.edu/biology/westmoreland/classnotes/144/chapter_48_files/image009.jpg

More information

Appendix D Some Portfolio Theory Math for Water Supply

Appendix D Some Portfolio Theory Math for Water Supply DESALINATION, WITH A GRAIN OF SALT A CALIFORNIA PERSPECTIVE 9 Appedix D Some Portfolio Theory Math for Water Supply Costat-Reliability-Beefit Uit Costs The reliability ad cost of differet water-supply

More information

Announcements, Nov. 19 th

Announcements, Nov. 19 th Aoucemets, Nov. 9 th Lecture PRS Quiz topic: results Chemical through Kietics July 9 are posted o the course website. Chec agaist Kietics LabChec agaist Kietics Lab O Fial Exam, NOT 3 Review Exam 3 ad

More information

HE ATOM & APPROXIMATION METHODS MORE GENERAL VARIATIONAL TREATMENT. Examples:

HE ATOM & APPROXIMATION METHODS MORE GENERAL VARIATIONAL TREATMENT. Examples: 5.6 4 Lecture #3-4 page HE ATOM & APPROXIMATION METHODS MORE GENERAL VARIATIONAL TREATMENT Do t restrict the wavefuctio to a sigle term! Could be a liear combiatio of several wavefuctios e.g. two terms:

More information

The Quark Puzzle A 3D printable model and/or paper printable puzzle that allows students to learn the laws of colour charge through inquiry.

The Quark Puzzle A 3D printable model and/or paper printable puzzle that allows students to learn the laws of colour charge through inquiry. The Quark Puzzle A 3D pritable model ad/or paper pritable puzzle that allows studets to lear the laws of colour charge through iquiry. It is available at this lik: https://zeodo.org/record/1252868#.w3ft-gzauk

More information

Exercises and Problems

Exercises and Problems HW Chapter 4: Oe-Dimesioal Quatum Mechaics Coceptual Questios 4.. Five. 4.4.. is idepedet of. a b c mu ( E). a b m( ev 5 ev) c m(6 ev ev) Exercises ad Problems 4.. Model: Model the electro as a particle

More information

Homework #4 Chapter 17

Homework #4 Chapter 17 oework #4 hapter 17 roperties o Solutios 1. a) NO(s) + (aq) + NO - (aq) ) NaSO4(s) Na + (aq) + SO4 - (aq) c) Al(NO)(s) Al + (aq) + NO - (aq) d) SrBr(s) Sr + (aq) + Br - (aq) e) KlO4(s) K + (aq) + lo4 -

More information

Thermodynamics of solids 5. Unary systems. Kwangheon Park Kyung Hee University Department of Nuclear Engineering

Thermodynamics of solids 5. Unary systems. Kwangheon Park Kyung Hee University Department of Nuclear Engineering Thermodynamics of solids 5. Unary systems Kwangheon ark Kyung Hee University Department of Nuclear Engineering 5.1. Unary heterogeneous system definition Unary system: one component system. Unary heterogeneous

More information

Solutions to Problem Set 9

Solutions to Problem Set 9 Solutions to Problem Set 9 1. When possible, we want to write an equation with the quantity on the ordinate in terms of the quantity on the abscissa for each pf the labeled curves. A B C p CHCl3 = K H

More information

Z - Transform. It offers the techniques for digital filter design and frequency analysis of digital signals.

Z - Transform. It offers the techniques for digital filter design and frequency analysis of digital signals. Z - Trasform The -trasform is a very importat tool i describig ad aalyig digital systems. It offers the techiques for digital filter desig ad frequecy aalysis of digital sigals. Defiitio of -trasform:

More information

In algebra one spends much time finding common denominators and thus simplifying rational expressions. For example:

In algebra one spends much time finding common denominators and thus simplifying rational expressions. For example: 74 The Method of Partial Fractios I algebra oe speds much time fidig commo deomiators ad thus simplifyig ratioal epressios For eample: + + + 6 5 + = + = = + + + + + ( )( ) 5 It may the seem odd to be watig

More information

Chapter 11 Problems: 11, 15, 18, 20-23, 30, 32-35, 39, 41, 43, 45, 47, 49-51, 53, 55-57, 59-61, 63, 65, 67, 70, 71, 74, 75, 78, 81, 85, 86, 93

Chapter 11 Problems: 11, 15, 18, 20-23, 30, 32-35, 39, 41, 43, 45, 47, 49-51, 53, 55-57, 59-61, 63, 65, 67, 70, 71, 74, 75, 78, 81, 85, 86, 93 Chapter 11 Problems: 11, 15, 18, 20-23, 30, 32-35, 39, 41, 43, 45, 47, 49-51, 53, 55-57, 59-61, 63, 65, 67, 70, 71, 74, 75, 78, 81, 85, 86, 93 Chapter 11 Properties of Solutions Types of mixtures: homogenous

More information

Problem 4: Evaluate ( k ) by negating (actually un-negating) its upper index. Binomial coefficient

Problem 4: Evaluate ( k ) by negating (actually un-negating) its upper index. Binomial coefficient Problem 4: Evaluate by egatig actually u-egatig its upper idex We ow that Biomial coefficiet r { where r is a real umber, is a iteger The above defiitio ca be recast i terms of factorials i the commo case

More information

Chapter 13. Characteristics of a Solution. Example of A Homogenous Mixtures. Solutions

Chapter 13. Characteristics of a Solution. Example of A Homogenous Mixtures. Solutions Chapter 13 Solutions Characteristics of a Solution A solution is a homogeneous mixture A solution is composed of a: Solute: the substance in lesser amount Solvent: the substance in greater amount Two liquid

More information

COLLIGATIVE PROPERTIES. Engr. Yvonne Ligaya F. Musico 1

COLLIGATIVE PROPERTIES. Engr. Yvonne Ligaya F. Musico 1 COLLIGATIVE PROPERTIES Engr. Yvonne Ligaya F. Musico 1 Colligative Properties Properties that depend on the collective effect of the number of solute particles. Engr. Yvonne Ligaya F. Musico 2 COLLEGATIVE

More information

Complex Numbers Solutions

Complex Numbers Solutions Complex Numbers Solutios Joseph Zoller February 7, 06 Solutios. (009 AIME I Problem ) There is a complex umber with imagiary part 64 ad a positive iteger such that Fid. [Solutio: 697] 4i + + 4i. 4i 4i

More information

ON SUPERSINGULAR ELLIPTIC CURVES AND HYPERGEOMETRIC FUNCTIONS

ON SUPERSINGULAR ELLIPTIC CURVES AND HYPERGEOMETRIC FUNCTIONS ON SUPERSINGULAR ELLIPTIC CURVES AND HYPERGEOMETRIC FUNCTIONS KEENAN MONKS Abstract The Legedre Family of ellitic curves has the remarkable roerty that both its eriods ad its suersigular locus have descritios

More information

--Lord Kelvin, May 3rd, 1883

--Lord Kelvin, May 3rd, 1883 Whe you ca measure what you are speakig about ad express it i umbers, you kow somethig about it; but whe you caot measure it, whe you caot express it i umbers, you kowledge is of a meager ad usatisfactory

More information

Semiconductors. PN junction. n- type

Semiconductors. PN junction. n- type Semicoductors. PN juctio We have reviously looked at the electroic roerties of itrisic, - tye ad - time semicoductors. Now we will look at what haes to the electroic structure ad macroscoic characteristics

More information