Sec: SR-IIT-IZ Dt: 22/12/2018 Time: 3Hrs JEE MAIN QP (IRTM-18) Max.Marks: 360
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1 Sec: SR-IIT-IZ Dt: //08 Time: Hrs JEE MIN QP (IRTM-8) Max.Marks: 0 MTHS KEY PHYSICS KEY CHEMISTRY KEY MTHS HINTS B n B 0 5. P n 5 4..!! B n B! 90 P n C C C B n B P n 8 Once you replace negative thoughts with positive ones, you ll start having positive results. Page
2 Narayana IIT cademy SR-IIT-IZ - JEE MIN (IRTM-8) EX::DT:: // B n B C C P n C 4 C C 8 8 R. P R. P. C E n E E 4 P E n E 5 C 5 5 C C R. P 5 5 B n B P n 9 4 R. P E 5 5 CE G. E n E C C n 0 E C C 5 59 R. P n 99. n B P B P B PB P B PB G. E. P B P 0., , R. P q R. P q q Where P q 5 8. a a a a P PB 5 R. P 8 Odds in favour = 5 : 9. Conceptual B n B 0. P n 7 Once you replace negative thoughts with positive ones, you ll start having positive results. Page
3 Narayana IIT cademy SR-IIT-IZ - JEE MIN (IRTM-8) EX::DT:: //8. E ne E 0 5 C C0 C C C C4 C5 C P E n E. ~ ( p (~ q)) ~ p ~ (~ q) (~ p) q. 4. Correct result is (~ p ~ q) ( r s) So, ~ ( p q) ( r s). 5. The combined variance, is given by n d n d n n Corrected variance Conceptual. e e 8. Mean 9. Number of boys = b, Number of girls = g. b5 g 4 b g 50 b : g 4 : x 8 xi 8 i i i S. D.. PHYSICS HINTS. Let be the declination at the place. s is clear from Fig. V tan H cos V tan o H cos tan tan V H sin sin tan cos Once you replace negative thoughts with positive ones, you ll start having positive results. Page
4 Narayana IIT cademy SR-IIT-IZ - JEE MIN (IRTM-8) EX::DT:: //8 tan tan tan. magnetic susceptibility 499 bsolute permeability H / m Permeability of medium H / m 8. In both the devices magnetic field changes with time.hence in both devices energy losses must be less. Hence, area enclosed within hysteresis loops must be less. 40. B BH at null points 0 m BH 4 d M M 4 0 M 0.m 4. B B B B 4 5 a e v a B H T 4. Conceptual 4. For damped oscillator 0e bt 0 b b b 0e, 0 e 0 e Here and are the properties of soft ferro magnets X H ni 000 / m 0 X X0 Solenoid can be replaced by a bar magnet of length 0cm and pole strength m 0. m m d 0. 4 (5X0 ) 0 4 BS 0.X0 T 4 (5X0 ) 0 4 BN.5X0 T Once you replace negative thoughts with positive ones, you ll start having positive results. Page 4
5 Narayana IIT cademy SR-IIT-IZ - JEE MIN (IRTM-8) EX::DT:: //8 4 B.X0 T 50. If and be the apparent dips shown by the dip circle in the two perpendicular positions, the true dip is given by cot cot cot 0 0 or, cot 45 cot 0 cot or, cot / 0 or, cot 0.8 giving 5. F / m 5. x0 b 0 m Here damping is zero b 0 5. Saturation dipole moment = (Number of atoms) ( vg. magnetic moment of atoms) VP N. m M b 0 Hz 0 5, 5 4Hz so reduced by Hz or 0% m Total dipole moment = = 5.4 JT B Using curie law, m T Final dipole moment 5.4.JT 0.0 CHEMISTRY HINTS. Hg + O Hg O + O. Polythionic acid, H S n O Total S S bond = n Number of S with zero oxidation state = n Number of S with + 5 oxidation state = Number of d p bond = 4. Element X may be Cl, Br or I. The most acidic oxyacid of X is HXO F acts as oxidizing agent with water. 5F + 5H O 0HF + O + O I does not react with water. 5. Total number of lone pairs = Total number of S S bonds = 8. NaSO HCldil NaCl SO H O Y NaS HCldil NaCl HS B Y Once you replace negative thoughts with positive ones, you ll start having positive results. Page 5
6 Narayana IIT cademy SR-IIT-IZ - JEE MIN (IRTM-8) EX::DT:: //8 7. Zn H SO dil ZnSO H 4 4 Zn H SO conc. ZnSO SO H O I Cl is polar and Br is non-polar. 9. Correct order of bond dissociation energy:- Cl > Br > F > I 70. Due to resonance both O O bond lengths are equal. 7. HCl on reaction with iron produces Fe HCl FeCl H Liberation of hydrogen prevents the formation of ferric chloride (Ref. NCERT book example 7.8) 7. Correct order of acidic strength is:- HClO < HClO < HClO < HClO 4 7. H O Cr O H CrO H O 4 5 Bluecolor 7 CrO H SO Cr ( SO ) H O O H F H I H B r H C l Hydrogen bonding 80. HO Cl HCl HOCl HOCl HCl O dipole dipole attraction (vanderwaal s forces) Coloured + (O) Color less 8. n interhalogen compound is more reactive than halogen. 8. It reduces iodine in basic medium. I HO OH I HO O 8. ml of 0 volumes HO gives 0 ml O at STP 50mL of 0 volumes HO gives 50 0 ml O at STP 84. HO e OH, HO OH e O HO. P 8SOCl 4PCl 4SO S Cl MnO 4 (green) + H O + O MnO 4 (pale pink) + KOH + O Pb( CH COO) H S PbS CH COOH 88. PbS O PbSO4 O 89. 4HCl O CuCl Cl H O g g / Cl * * * Paper Setter : NLR-CO-PLUS SUBJECT LECT. NME PHONE NO. MTHS Sri. SSTRY PHYSICS Sri. D.SRINIVS RO CHEMISTRY Sri. MEHT Once you replace negative thoughts with positive ones, you ll start having positive results. Page
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