General Chemistry I The Mole Map. Dr. Koni Stone Chapter 3, clicker 3
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1 General Chemistry I The Mole Map Dr. Koni Stone Chapter 3, clicker 3
2 How many moles of sodium carbonate are in 50.5 grams of sodium carbonate? A. 106 moles B x 10-1 moles C moles D x 103 E. None of these
3 How many moles of sodium carbonate are in 50.5 grams of sodium carbonate? A. 106 moles B x 10-1 moles C moles D x 103 E. None of these
4 The Mole Map How to get from grams of one thing to grams of another.
5 The Mole Map How to get from grams of one thing to grams of another. Divide by Multiply by
6 Multiply by Divide by How many grams of carbon dioxide are produced when 55 grams of pentane (C5H12) are combusted? 1. Translate the words into symbols C5 H12 O2 CO2 H2O 2. Balance the equation C5 H12 8 O2 5 CO2 6 H2O
7 Multiply by Divide by How many grams of carbon dioxide are produced when 55 grams of pentane (C5H12) are combusted? 1. Translate the words into symbols C5 H12 O2 CO2 H2O 2. Balance the equation C5 H12 8 O2 5 CO2 6 H2O 3. Use the mole map 55 grams C5H12 X Mole C5H12 72 grams X 5 moles CO2. x 44 grams 1 mole C5H12 C5H12 Mole CO2 CO2 = 1.7 x 102 grams of CO2
8 Multiply by Divide by How much oxygen is needed to burn 42 grams of butane (C4H10)? 1. Translate the words into symbols C4 H10 O2 2. Balance the equation C4 H10 13/2 O2 CO2 4 CO2 H2O 5 H2O Multiply everything by 2 to get rid of the fraction.
9 Multiply by Divide by How much oxygen is needed to burn 42 grams of butane (C4H10)? 1. Translate the words into symbols C4 H10 O2 2. Balance the equation 2 C4 H10 CO2 8 CO2 13 O2 H2O 10 H2O 3. Use the mole map 42 grams C4H10 X Mole C4H10 58 grams X 13 moles O2. x 32 grams 2 mole C4H10 Mole O2 = 1.5 x 102 grams of O2
10 Divide by Multiply by How much water is produced when 122 grams of propane (C3H8) is burned? A. B. C. D. E x x None of these
11 Multiply by Divide by How much water is produced when 122 grams of propane (C3H8) is burned? 1. Translate the words into symbols C3 H8 O2 2. Balance the equation C3 H8 CO2 3 CO2 5 O2 H2O 4 H2O 3. Use the mole map 122 grams C3H8 X Mole C3H8 44 grams X 4 moles H2O x 18 grams mole C3H8 Mole H2O = 2.00 x 102 grams of H2 O
12 Multiply by Divide by How much copper metal is produced when 5.4 grams of copper(i) sulfide reacts with oxygen to form copper metal and sulfur dioxide gas. 1. Translate the words into symbols 2. Balance the equation 3. Use the mole map A. B. C. D. E x 10-1 grams Cu(s) 2.7 x 101 grams Cu(s) 4.3 grams Cu(s) 1.1 grams Cu(s) None of these
13 Divide by Multiply by How much copper metal is produced when 5.4 grams of copper(i) sulfide reacts with oxygen to form copper metal and sulfur dioxide gas. 1. Translate the words into symbols 2. Balance the equation 3. Use the mole map
14 Divide by Multiply by How much copper metal is produced when 5.4 grams of copper(i) sulfide reacts with oxygen to form copper metal and sulfur dioxide gas. 1. Translate the words into symbols Cu2S 2. Balance the equation Cu2S O2 Cu(s) O2 2 Cu(s) SO2 (g) SO2 (g) 3. Use the mole map 5.4 grams Cu2S X mole Cu2S 159 grams X 2 moles Cu(s) x 63.5 grams mole Cu2S mole Cu(s) = 4.3 grams of Cu(s)
15 What is Limiting? When masses of both reactants are given you don t know which one will get used up and which one will be in excess. If you are making sandwiches and each sandwich needs one piece of cheese and two slices of bread, how many sandwiches can you make if you have 24 slices of cheese and 20 slices of bread? What will be leftover? How much will be leftover? A. 10 sandwiches, 14 extra slices of cheese B. 20 sandwiches, 4 extra slices of cheese C. 24 sandwiches, nothing extra D. 12 sandwiches, 2 extra slices of bread E. None of these
16 What is Limiting? When masses of both reactants are given you don t know which one will get used up and which one will be in excess. If you are making sandwiches and each sandwich needs one piece of cheese and two slices of bread, how many sandwiches can you make if you have 24 slices of cheese and 20 slices of bread? What will be leftover? How much will be leftover? A. 10 sandwiches, 14 extra slices of cheese B. 20 sandwiches, 4 extra slices of cheese C. 24 sandwiches, nothing extra D. 12 sandwiches, 2 extra slices of bread E. None of these Bread is the limiting reagent
17 What is Limiting? Sulfur trioxide and water react to form sulfuric acid (H2SO4). How much sulfuric acid can be made from the reaction of 20 grams of sulfur trioxide and 10 grams of water? Divide by Multiply by Use the mole map for both reactants, the reactant that gives the smallest amount of product is the limiting reagent.
18 What are the steps? Translate the words to symbols Balance the equation SO 3 H 2 O > H 2 SO 4 Use the mole map for each reactant The reactant that gives the smallest amount of product is the limiting reagent. 20 grams SO 3 X mole SO 3 X 1 moles H 2 SO 4. x 98 grams 80 grams 1 mole SO 3 C5H12 mole H 2 SO 4 CO2 10 grams H 2 O X mole H 2 O X 1 moles H 2 SO 4. x 98 grams 18 grams 1 mole H 2 O C5H12 mole H 2 SO 4 CO2 = 24.5 g = g
19 How much carbon dioxide can be formed from the combustion of 26 grams of propane (C 3 H 8 ) with 100 grams of oxygen? A. 30 B. 23 C. 43 D. 45 E. None of these
20 How much water can be formed from the combustion of 26 grams of propane (C 3 H 8 ) with 52 grams of oxygen? Translate the words to symbols Balance the equation Use the mole map for each reactant C 3 H 8 5 O 2 > 3 CO 2 4 H 2 O The reactant that gives the smallest amount of product is the limiting reagent. 26 grams C 3 H 8 X mole C 3 H 8 X 4 moles H 2 O. x 18 grams 44 grams 1 mole C 3 H 8 C5H12 mole H 2 O CO2 52 grams O 2 X mole O 2 X 4 moles H 2 O x 18 grams 32 grams 5 mole O 2 C5H12 mole H 2 O CO2 = 43 g = 23 g
21 How much carbon dioxide can be formed from the combustion of 26 grams of propane (C 3 H 8 ) with 100 grams of oxygen? A. 30 B. 23 C. 43 D. 45 E. None of these
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