2 4πε ( ) ( r θ. , symmetric about the x-axis, as shown in Figure What is the electric field E at the origin O?
|
|
- Cornelius Patrick
- 5 years ago
- Views:
Transcription
1 p E( r, θ) = cosθ 3 ( sinθ ˆi + cosθ ˆj ) + sinθ cosθ ˆi + ( cos θ 1) ˆj r ( ) ( p = cosθ sinθ ˆi + cosθ ˆj + sinθ cosθ ˆi sinθ ˆj 3 r where the trigonometric identit ( θ ) vectors ˆr and cos 1 = sin θ has been used. Since the unit ˆθ in polar coordinates can be decomposed as rˆ = sinθ ˆi + cosθ ˆj θˆ = cosθ ˆi sin θ ˆj, the electric field in polar coordinates is given b E( p r, θ ) = cosθ ˆ + sin ˆ 3 r r θ ) and the magnitude of is E 1/ p E = ( Er + Eθ ) = 3 ( 3cos θ + 1 ) r 1/.13.5 Electric Field of an Arc A thin rod with a uniform charge per unit length λ is bent into the shape of an arc of a circle of radius. The arc subtends a total angle θ, smmetric about the x-axis, as shown in Figure.13.. What is the electric field E at the origin O? Solution: Consider a differential element of length d = dθ, which makes an angle θ with the x - axis, as shown in Figure.13.(b). The amount of charge it carries is dq = λ d = λ dθ. The contribution to the electric field at O is 1 dq 1 dq 1 d de= rˆ = cos i sin j = cos i sin r ( ˆ ˆ λ θ θ θ ) ( θˆ θj ˆ) 35
2 Figure.13. (a) Geometr of charged source. (b) Charge element dq Integrating over the angle from θ to + θ, we have θ λ sinθ E i j i+ j i ( ˆ ˆ λ cos sin ) ( sin ˆ cos ˆ) 1 λ θ 1 1 = dθ θ θ θ θ ˆ = = θ θ We see that the electric field onl has the x -component, as required b a smmetr argument. If we take the limit θ π, the arc becomes a circular ring. Since sinπ =, the equation above implies that the electric field at the center of a non-conducting ring is zero. This is to be expected from smmetr arguments. On the other hand, for ver smallθ, sinθ θ and we recover the point-charge limit: 1 λθ ˆ 1 λθ ˆ 1 E i = i = Q ˆi where the total charge on the arc is Q= λ = λ( θ ) Electric Field Off the Axis of a Finite od A non-conducting rod of length with a uniform charge densit λ and a total charge Q is ling along the x -axis, as illustrated in Figure Compute the electric field at a point P, located at a distance off the axis of the rod. Figure
3 Solution: The problem can be solved b following the procedure used in Example.3. Consider a length element dx on the rod, as shown in Figure The charge carried b the element is dq = λ dx. The electric field at P produced b this element is Figure dq 1 λ dx de= rˆ = sin ˆi+ cos ˆ r x + ( θ θ j ) where the unit vector ˆr has been written in Cartesian coordinates: rˆ = sinθ ˆi+ cosθ ˆj. In the absence of smmetr, the field at P has both the x- and -components. The x- component of the electric field is de x 1 λ dx 1 λdx x 1 λx dx = sinθ = = x + x + x + 4 πε ( x + ) 3/ Integrating from x = x1 to x = x, we have E x λ x xdx λ 1 x du λ = u 4 πε = = ( x + ) u + x 3/ x 3/ 1/ x + 1 λ 1 1 λ = = x 4 x1 πε + + x + x1 + λ = ( cosθ cosθ1) x + Similarl, the -component of the electric field due to the charge element is 37
4 de 1 λ dx 1 λdx 1 λdx = cosθ = = x + x + x + 4 πε ( x + ) 3/ Integrating over the entire length of the rod, we obtain E λ x dx λ 1 θ λ = = cosθ dθ = sinθ sin 4 πε ( x + ) x 3/ 1 θ1 ( ) θ1 where we have used the result obtained in Eq. (.1.8) in completing the integration. In the infinite length limit where x1 and x +, with xi = tanθi, the corresponding angles are θ 1 = π /and θ = + π /. Substituting the values into the expressions above, we have E x 1 λ =, E = in complete agreement with the result shown in Eq. (.1.11)..14 Conceptual Questions 1. Compare and contrast Newton s law of gravitation, F = Gmm r, and Coulomb s law, F kq q r / e = 1.. Can electric field lines cross each other? Explain. 3. Two opposite charges are placed on a line as shown in the figure below. g 1 / The charge on the right is three times the magnitude of the charge on the left. Besides infinit, where else can electric field possibl be zero? 4. A test charge is placed at the point P near a positivel-charged insulating rod. 38
5 How would the magnitude and direction of the electric field change if the magnitude of the test charge were decreased and its sign changed with everthing else remaining the same? 5. An electric dipole, consisting of two equal and opposite point charges at the ends of an insulating rod, is free to rotate about a pivot point in the center. The rod is then placed in a non-uniform electric field. Does it experience a force and/or a torque?.15 Additional Problems.15.1 Three Point Charges Three point charges are placed at the corners of an equilateral triangle, as shown in Figure Figure.15.1 Three point charges Calculate the net electric force experienced b (a) the 9. µ C charge, and (b) the 6. µ C charge..15. Three Point Charges A right isosceles triangle of side a has charges q, +q and q arranged on its vertices, as shown in Figure
6 Figure.15. What is the electric field at point P, midwa between the line connecting the +q and q charges? Give the magnitude and direction of the electric field Four Point Charges Four point charges are placed at the corners of a square of side a, as shown in Figure Figure.15.3 Four point charges (a) What is the electric field at the location of charge q? (b) What is the net force on q?.15.4 Semicircular Wire A positivel charged wire is bent into a semicircle of radius, as shown in Figure Figure
7 The total charge on the semicircle is Q. However, the charge per unit length along the semicircle is non-uniform and given b λ = λ cosθ. (a) What is the relationship between λ, and Q? (b) If a charge q is placed at the origin, what is the total force on the charge?.15.5 Electric Dipole An electric dipole ling in the x-plane with a uniform electric field applied in the + x - direction is displaced b a small angle θ from its equilibrium position, as shown in Figure Figure.15.5 The charges are separated b a distance a, and the moment of inertia of the dipole is I. If the dipole is released from this position, show that its angular orientation exhibits simple harmonic motion. What is the frequenc of oscillation?.15.6 Charged Clindrical Shell and Clinder (a) A uniforml charged circular clindrical shell of radius and height h has a total charge Q. What is the electric field at a point P a distance z from the bottom side of the clinder as shown in Figure.15.6? (Hint: Treat the clinder as a set of ring charges.) Figure.15.6 A uniforml charged clinder 41
8 (b) If the configuration is instead a solid clinder of radius, height h and has a uniform volume charge densit. What is the electric field at P? (Hint: Treat the solid clinder as a set of disk charges.).15.7 Two Conducting Balls Two tin conducting balls of identical mass m and identical charge q hang from nonconducting threads of length l. Each ball forms an angle θ with the vertical axis, as shown in Figure Assume that θ is so small that tanθ sinθ. Figure.15.9 (a) Show that, at equilibrium, the separation between the balls is q r = πε mg 13 1 (b) If l = 1. 1 cm, m= 1. 1 g, and x = 5.cm, what is q?.15.8 Torque on an Electric Dipole 19 An electric dipole consists of two charges q 1 = +e and q = e ( e = C ), 9 separated b a distance d = 1 m. The electric charges are placed along the -axis as shown in Figure Figure
(a) What is the magnitude of the electric force between the proton and the electron?
.3 Solved Problems.3. Hydrogen Atom In the classical model of the hydrogen atom, the electron revolves around the proton with a radius of r = 053. 0 0 m. The magnitude of the charge of the electron and
More informationElectric Fields, Dipoles and Torque Challenge Problem Solutions
Electric Fields, Dipoles and Torque Challenge Problem Solutions Problem 1: Three charges equal to Q, +Q and +Q are located a distance a apart along the x axis (see sketch). The point P is located on the
More informationProblems set # 2 Physics 169 February 11, 2015
Prof. Anchordoqui Problems set # 2 Phsics 169 Februar 11, 2015 1. Figure 1 shows the electric field lines for two point charges separated b a small distance. (i) Determine the ratio q 1 /q 2. (ii) What
More informationPhysics 2212 K Quiz #1 Solutions Summer 2015
Physics 2212 K Quiz #1 Solutions Summer 2015 e Fundamental charge m e Mass of an electron K Coulomb constant = 1/4πϵ 0 g Magnitude of Free Fall Acceleration Unless otherwise directed, drag should be neglected.
More informationB r Solved Problems Magnetic Field of a Straight Wire
(4) Equate Iencwith d s to obtain I π r = NI NI = = ni = l π r 9. Solved Problems 9.. Magnetic Field of a Straight Wire Consider a straight wire of length L carrying a current I along the +x-direction,
More informationragsdale (zdr82) HW7 ditmire (58335) 1 The magnetic force is
ragsdale (zdr8) HW7 ditmire (585) This print-out should have 8 questions. Multiple-choice questions ma continue on the net column or page find all choices efore answering. 00 0.0 points A wire carring
More informationCouncil of Student Organizations De La Salle University Manila
Council of Student Organizations De La Salle University Manila PHYENG2 Quiz 1 Problem Solving: 1. (a) Find the magnitude and direction of the force of +Q on q o at (i) P 1 and (ii) P 2 in Fig 1a below.
More informationand Discrete Charge Distributions
Module 03: Electric Fields and Discrete Charge Distributions 1 Module 03: Outline Review: Electric Fields Charge Dipoles 2 Last Time: Gravitational & Electric Fields 3 Gravitational & Electric Fields SOURCE:
More informationPhysics 2212 GJ Quiz #1 Solutions Fall 2015
Physics 2212 GJ Quiz #1 Solutions Fall 2015 I. (14 points) A 2.0 µg dust particle, that has a charge of q = +3.0 nc, leaves the ground with an upward initial speed of v 0 = 1.0 m/s. It encounters a E =
More information= C. on q 1 to the left. Using Coulomb s law, on q 2 to the right, and the charge q 2 exerts a force F 2 on 1 ( )
Phsics Solutions to Chapter 5 5.. Model: Use the charge model. Solve: (a) In the process of charging b rubbing, electrons are removed from one material and transferred to the other because the are relativel
More informationElectric Fields and Continuous Charge Distributions Challenge Problem Solutions
Problem 1: Electric Fields and Continuous Charge Distributions Challenge Problem Solutions Two thin, semi-infinite rods lie in the same plane They make an angle of 45º with each other and they are joined
More informationFigure 17.1 The center of mass of a thrown rigid rod follows a parabolic trajectory while the rod rotates about the center of mass.
17.1 Introduction A body is called a rigid body if the distance between any two points in the body does not change in time. Rigid bodies, unlike point masses, can have forces applied at different points
More informationSimple and Physical Pendulums Challenge Problem Solutions
Simple and Physical Pendulums Challenge Problem Solutions Problem 1 Solutions: For this problem, the answers to parts a) through d) will rely on an analysis of the pendulum motion. There are two conventional
More information2 Chapter Coulomb s Law
Chapter Coulomb s Law.1 Electric Charge... -3. Coulomb's Law... -3.3 Principle of Superposition... -4 Example.1: Three Charges... -5.4 Electric Field... -6.4.1 Electric Field of Point Charges... -7.5 Electric
More informationPhysics Lecture 07
Physics 2113 Jonathan Dowling Physics 2113 Lecture 07 Electric Fields III Charles-Augustin de Coulomb (1736-1806) Electric Charges and Fields First: Given Electric Charges, We Calculate the Electric Field
More informationPhysics 22: Homework 1
Physics 22: Homework 1 The following problems encompass the topics of charge, as well as electrostatic forces, torques, and fields. 1. What is the total charge of all the electrons in 1.2 mol of diatomic
More information1. Four equal and positive charges +q are arranged as shown on figure 1.
AP Physics C Coulomb s Law Free Response Problems 1. Four equal and positive charges +q are arranged as shown on figure 1. a. Calculate the net electric field at the center of square. b. Calculate the
More informationPhysics Lecture 13
Physics 113 Jonathan Dowling Physics 113 Lecture 13 EXAM I: REVIEW A few concepts: electric force, field and potential Gravitational Force What is the force on a mass produced by other masses? Kepler s
More informationxy 2 e 2z dx dy dz = 8 3 (1 e 4 ) = 2.62 mc. 12 x2 y 3 e 2z 2 m 2 m 2 m Figure P4.1: Cube of Problem 4.1.
Problem 4.1 A cube m on a side is located in the first octant in a Cartesian coordinate system, with one of its corners at the origin. Find the total charge contained in the cube if the charge density
More informationPART A. 4cm 1 =1.4 1 =1.5. 5cm
PART A Straight Objective Type This section contains 30 multiple choice questions. Each question has 4 choices (1), (), (3) and (4) for its answer, out of which ONLY ONE is correct. 1. The apparent depth
More informationPHYS1212 Exam#2 Spring 2014
PHYS Exam# Spring 4 NAME There are 9 different pages in this quiz. Check now to see that you have all of them. CEDIT PAT A 6% PAT B 4% TOTAL % GADE All work and answers must be given in the spaces provided
More information3 Chapter. Gauss s Law
3 Chapter Gauss s Law 3.1 Electric Flux... 3-2 3.2 Gauss s Law (see also Gauss s Law Simulation in Section 3.10)... 3-4 Example 3.1: Infinitely Long Rod of Uniform Charge Density... 3-9 Example 3.2: Infinite
More informationLecture 6 - Introduction to Electricity
Lecture 6 - Introduction to Electricity A Puzzle... We are all familiar with visualizing an integral as the area under a curve. For example, a b f[x] dx equals the sum of the areas of the rectangles of
More information11.1 Introduction Galilean Coordinate Transformations
11.1 Introduction In order to describe physical events that occur in space and time such as the motion of bodies, we introduced a coordinate system. Its spatial and temporal coordinates can now specify
More informationProfs. D. Acosta, A. Rinzler, S. Hershfield. Exam 1 Solutions
PHY2049 Spring 2009 Profs. D. Acosta, A. Rinzler, S. Hershfield Exam 1 Solutions 1. What is the flux through the right side face of the shown cube if the electric field is given by E = 2xî + 3yĵ and the
More informationProblem Solving Session 10 Simple Harmonic Oscillator Solutions
MASSACHUSETTS INSTITUTE OF TECHNOLOGY Department of Physics 8.01 Problem Solving Session 10 Simple Harmonic Oscillator Solutions W13D3-0 Group Problem Gravitational Simple Harmonic Oscillator Two identical
More informationModule 24: Angular Momentum of a Point Particle
24.1 Introduction Module 24: Angular Momentum of a Point Particle When we consider a system of objects, we have shown that the external force, acting at the center of mass of the system, is equal to the
More informationQuestions Chapter 22 Electric Fields
Questions Chapter 22 Electric Fields 22-1 What is Physics? 22-2 The Electric Field 22-3 Electric Field Lines 22-4 Electric Field due to a Point Charge 22-5 Electric Field due to an Electric Dipole 22-6
More informationChapter 3 Vectors. 3.1 Vector Analysis
Chapter 3 Vectors 3.1 Vector nalysis... 1 3.1.1 Introduction to Vectors... 1 3.1.2 Properties of Vectors... 1 3.2 Coordinate Systems... 6 3.2.1 Cartesian Coordinate System... 6 3.2.2 Cylindrical Coordinate
More informationPractice Questions Exam 1/page1. PES Physics 2 Practice Exam 1 Questions. Name: Score: /.
Practice Questions Exam 1/page1 PES 110 - Physics Practice Exam 1 Questions Name: Score: /. Instructions Time allowed for this is exam is 1 hour 15 minutes 5 multiple choice (5 points) 3 to 5 written problems
More informationNear the surface of the earth, we agreed to call the force of gravity of constant.
Electric Fields 1. A field 2. Field lines 3. The Electric Field 4. Field from a dipole 5. Line charge 6. Other configurations Near the surface of the earth, we agreed to call the force of gravity of constant.
More informationChapter 21 Electric Charge and the Electric Field
Chapter 21 Electric Charge and the Electric Field 1 Electric Charge Electrostatics is the study of charges when they are stationery. Figure 1: This is Fig. 21.1 and it shows how negatively charged objects
More informationMechanics Departmental Exam Last updated November 2013
Mechanics Departmental Eam Last updated November 213 1. Two satellites are moving about each other in circular orbits under the influence of their mutual gravitational attractions. The satellites have
More informationLecture 2 Electric Fields Ch. 22 Ed. 7
1 2 Lecture 2 Electric Fields Ch. 22 Ed. 7 Cartoon - Analogous to gravitational field Topics Electric field = Force per unit Charge Electric Field Lines Electric field from more than 1 charge Electric
More information(a) This cannot be determined since the dimensions of the square are unknown. (b) 10 7 N/C (c) 10 6 N/C (d) 10 5 N/C (e) 10 4 N/C
1. 4 point charges (1 C, 3 C, 4 C and 5 C) are fixed at the vertices of a square. When a charge of 10 C is placed at the center of the square, it experiences a force of 10 7 N. What is the magnitude of
More informationTorque and Simple Harmonic Motion
Torque and Simple Harmonic Motion Recall: Fixed Axis Rotation Angle variable Angular velocity Angular acceleration Mass element Radius of orbit Kinematics!! " d# / dt! " d 2 # / dt 2!m i Moment of inertia
More informationChapter 19 Angular Momentum
Chapter 19 Angular Momentum Chapter 19 Angular Momentum... 2 19.1 Introduction... 2 19.2 Angular Momentum about a Point for a Particle... 3 19.2.1 Angular Momentum for a Point Particle... 3 19.2.2 Right-Hand-Rule
More information( )( )( ) Model: The magnetic field is that of a moving charged particle. Visualize: 10 T m/a C m/s sin T. 1.
33.3. Model: The magnetic field is that of a moving charged particle. Visualize: The first point is on the x-axis, with θ a = 90. The second point is on the y-axis, with θ b = 180, and the third point
More informationEXERCISES Chapter 15: Multiple Integrals. Evaluating Integrals in Cylindrical Coordinates
08 Chapter 5: Multiple Integrals EXERCISES 5.6 Evaluating Integrals in Clindrical Evaluate the clindrical coordinate integrals in Eercises 6... 3. 4. 5. 6. Changing Order of Integration in Clindrical The
More informationEX. Potential for uniformly charged thin ring
EX. Potential for uniformly charged thin ring Q dq r R dφ 0 V ( Z ) =? z kdq Q Q V =, dq = Rdϕ = dϕ Q r 2πR 2π 2π k Q 0 = d ϕ 0 r 2π kq 0 2π = 0 d ϕ 2π r kq 0 = r kq 0 = 2 2 R + z EX. Potential for uniformly
More informationMath Review Night: Work and the Dot Product
Math Review Night: Work and the Dot Product Dot Product A scalar quantity Magnitude: A B = A B cosθ The dot product can be positive, zero, or negative Two types of projections: the dot product is the parallel
More informationCyclotron, final. The cyclotron s operation is based on the fact that T is independent of the speed of the particles and of the radius of their path
Cyclotron, final The cyclotron s operation is based on the fact that T is independent of the speed of the particles and of the radius of their path K 1 qbr 2 2m 2 = mv = 2 2 2 When the energy of the ions
More informationy = x 3 and y = 2x 2 x. 2x 2 x = x 3 x 3 2x 2 + x = 0 x(x 2 2x + 1) = 0 x(x 1) 2 = 0 x = 0 and x = (x 3 (2x 2 x)) dx
Millersville University Name Answer Key Mathematics Department MATH 2, Calculus II, Final Examination May 4, 2, 8:AM-:AM Please answer the following questions. Your answers will be evaluated on their correctness,
More informationPHY 5246: Theoretical Dynamics, Fall Assignment # 9, Solutions. y CM (θ = 0) = 2 ρ m
PHY 546: Theoretical Dnamics, Fall 5 Assignment # 9, Solutions Graded Problems Problem (.a) l l/ l/ CM θ x In order to find the equation of motion of the triangle, we need to write the Lagrangian, with
More informationChapter 9 Uniform Circular Motion
9.1 Introduction Chapter 9 Uniform Circular Motion Special cases often dominate our study of physics, and circular motion is certainly no exception. We see circular motion in many instances in the world;
More informationChapter 17 Two Dimensional Rotational Dynamics
Chapter 17 Two Dimensional Rotational Dynamics 17.1 Introduction... 1 17.2 Vector Product (Cross Product)... 2 17.2.1 Right-hand Rule for the Direction of Vector Product... 3 17.2.2 Properties of the Vector
More informationVersion: A. Earth s gravitational field g = 9.81 N/kg Vacuum Permeability µ 0 = 4π 10 7 T m/a
PHYS 2212 GJ Quiz and Exam Formulæ & Constants Fall 2015 Fundamental Charge e = 1.602 10 19 C Mass of an Electron m e = 9.109 10 31 kg Coulomb constant K = 8.988 10 9 N m 2 /C 2 Vacuum Permittivity ϵ 0
More informationProblem Set #1 Chapter 21 10, 22, 24, 43, 47, 63; Chapter 22 7, 10, 36. Chapter 21 Problems
Problem Set #1 Chapter 1 10,, 4, 43, 47, 63; Chapter 7, 10, 36 Chapter 1 Problems 10. (a) T T m g m g (b) Before the charge is added, the cork balls are hanging verticall, so the tension is T 1 mg (0.10
More informationChapter 13: Oscillatory Motions
Chapter 13: Oscillatory Motions Simple harmonic motion Spring and Hooe s law When a mass hanging from a spring and in equilibrium, the Newton s nd law says: Fy ma Fs Fg 0 Fs Fg This means the force due
More informationMath Review 1: Vectors
Math Review 1: Vectors Coordinate System Coordinate system: used to describe the position of a point in space and consists of 1. An origin as the reference point 2. A set of coordinate axes with scales
More informationPhysics 221. Exam III Spring f S While the cylinder is rolling up, the frictional force is and the cylinder is rotating
Physics 1. Exam III Spring 003 The situation below refers to the next three questions: A solid cylinder of radius R and mass M with initial velocity v 0 rolls without slipping up the inclined plane. N
More information+2Q -2Q. (a) 672 N m 2 /C (b) 321 N m 2 /C (c) 105 N m 2 /C (d) 132 N m 2 /C (e) 251 N m 2 /C
1. The figure below shows 4 point charges located on a circle centered about the origin. The exact locations of the charges on the circle are not given. What can you say about the electric potential created
More informationPhysics 2212 K Quiz #1 Solutions Summer q in = ρv = ρah = ρa 4
Physics 2212 K Quiz #1 Solutions Summer 2016 I. (18 points A uniform infinite insulating slab of charge has a positive volume charge density ρ, and a thickness 2t, extending from t to +t in the z direction.
More informationFigure 1 Answer: = m
Q1. Figure 1 shows a solid cylindrical steel rod of length =.0 m and diameter D =.0 cm. What will be increase in its length when m = 80 kg block is attached to its bottom end? (Young's modulus of steel
More informationLecture 10 - Moment of Inertia
Lecture 10 - oment of Inertia A Puzzle... Question For any object, there are typically many ways to calculate the moment of inertia I = r 2 dm, usually by doing the integration by considering different
More informationPhysics 5A Final Review Solutions
Physics A Final Review Solutions Eric Reichwein Department of Physics University of California, Santa Cruz November 6, 0. A stone is dropped into the water from a tower 44.m above the ground. Another stone
More informationMATH 2412 Sections Fundamental Identities. Reciprocal. Quotient. Pythagorean
MATH 41 Sections 5.1-5.4 Fundamental Identities Reciprocal Quotient Pythagorean 5 Example: If tanθ = and θ is in quadrant II, find the exact values of the other 1 trigonometric functions using only fundamental
More informationPhysics 114 Exam 1 Fall 2016
Physics 114 Exam 1 Fall 2016 Name: For grading purposes (do not write here): Question 1. 1. 2. 2. 3. 3. Problem Answer each of the following questions and each of the problems. Points for each question
More informationChapter 24. Electric Potential. MFMcGraw-PHY 2426 Ch24d-Electric Potential-Revised 8/23/2012 1
Chapter 24 Electric Potential MFMcGraw-PHY 2426 Ch24d-Electric Potential-Revised 8/23/2012 1 Electric Potential 1. Potential Difference 2. Potential Due to a System of Point Charges 3. Computing the Electric
More informationGeneral Physics I. Lecture 8: Rotation of a Rigid Object About a Fixed Axis. Prof. WAN, Xin ( 万歆 )
General Physics I Lecture 8: Rotation of a Rigid Object About a Fixed Axis Prof. WAN, Xin ( 万歆 ) xinwan@zju.edu.cn http://zimp.zju.edu.cn/~xinwan/ New Territory Object In the past, point particle (no rotation,
More informationLecture 17 - Gyroscopes
Lecture 17 - Gyroscopes A Puzzle... We have seen throughout class that the center of mass is a very powerful tool for evaluating systems. However, don t let yourself get carried away with how useful it
More informationStatic Equilibrium, Gravitation, Periodic Motion
This test covers static equilibrium, universal gravitation, and simple harmonic motion, with some problems requiring a knowledge of basic calculus. Part I. Multiple Choice 1. 60 A B 10 kg A mass of 10
More informationChapter 21. Electric Fields. Lecture 2. Dr. Armen Kocharian
Chapter 21 Electric Fields Lecture 2 Dr. Armen Kocharian Electric Field Introduction The electric force is a field force Field forces can act through space The effect is produced even with no physical
More information03. Electric Field III and Electric Flux
Universit of Rhode Island DigitalCommons@URI PHY 204: lementar Phsics II Phsics Course Materials 2015 03. lectric Field III and lectric Flu Gerhard Müller Universit of Rhode Island, gmuller@uri.edu Creative
More information27 the electric field
27 the electric field With every point in space near the earth we can associate a gravitational field vector g (see Eq. 16-12). This is the gravitational acceleration that a test body, placed at that point
More informationPhysics 8.02 Exam Two Equation Sheet Spring 2004
Physics 8.0 Exam Two Equation Sheet Spring 004 closed surface EdA Q inside da points from inside o to outside I dsrˆ db 4o r rˆ points from source to observer V moving from a to b E ds 0 V b V a b E ds
More informationIn-Class Problems 30-32: Moment of Inertia, Torque, and Pendulum: Solutions
MASSACHUSETTS INSTITUTE OF TECHNOLOGY Department of Physics Physics 8.01 TEAL Fall Term 004 In-Class Problems 30-3: Moment of Inertia, Torque, and Pendulum: Solutions Problem 30 Moment of Inertia of a
More informationPhysics 121 Common Exam 1, Sample Exam 4 (Fall 2011)
Physics 11 Common Exam 1, Sample Exam 4 (Fall 011) Name (Print): 4 Digit ID: Section: Honors Code Pledge: For ethical and fairness reasons we are all pledged to comply with the provisions of the NJIT Academic
More informationElectrostatics. 4πε 2) + Q / 2 4) 4 Q
Two spheres A and B of radius a and b respectively are at the same potential The ratio of the surface charge density of A to B is: ) a / b ) b / a a / b b / a Two free protons are separated by a distance
More informationStatic Equilibrium Gravitation
Static Equilibrium Gravitation Lana Sheridan De Anza College Dec 6, 2017 Overview One more static equilibrium example Newton s Law of Universal Gravitation gravitational potential energy little g Example
More informationPH 222-3A Spring 2007
PH -3A Spring 7 ELECTRIC FIELDS Lectures,3 Chapter (Halliday/Resnick/Walker, Fundamentals of Physics 8 th edition) 1 Chapter Electric Fields In this chapter we will introduce the concept of an electric
More information1. A ring of radius α has a charge distribution on it that varies as λ(θ) = λ 0 sin(θ), where λ 0 > 0, as shown in the figure.
EACH OF THE LECTURE QUESTIONS 1-22 IS WORTH 5 POINTS I. COULOMB S LAW 1. A ring of radius α has a charge distribution on it that varies as λ(θ) = λ 0 sin(θ), where λ 0 > 0, as shown in the figure. What
More information3. A solid conducting sphere has net charge of +6nC. At electrostatic equilibrium the electric field inside the sphere is:
Conceptual Questions. Circle the best answer. (2 points each) 1. If more electric field lines point into a balloon than come out of it, you can conclude that this balloon must contain more positive charge
More informationPhysics (2): Problem set 1 solutions
Physics (2): Problem set solutions PHYS 04 Problem : Two identical charges q = nc are located on the x-axis at positions 2 cm and 2 cm. What is the electric field at the origin (centre between the two
More informationChapter 12. Recall that when a spring is stretched a distance x, it will pull back with a force given by: F = -kx
Chapter 1 Lecture Notes Chapter 1 Oscillatory Motion Recall that when a spring is stretched a distance x, it will pull back with a force given by: F = -kx When the mass is released, the spring will pull
More informationF 13. The two forces are shown if Q 2 and Q 3 are connected, their charges are equal. F 12 = F 13 only choice A is possible. Ans: Q2.
Q1. Three fixed point charges are arranged as shown in Figure 1, where initially Q 1 = 10 µc, Q = 15 µc, and Q 3 = 5 µc. If charges Q and Q 3 are connected by a very thin conducting wire and then disconnected,
More informationPHYSICS 221, FALL 2011 EXAM #2 SOLUTIONS WEDNESDAY, NOVEMBER 2, 2011
PHYSICS 1, FALL 011 EXAM SOLUTIONS WEDNESDAY, NOVEMBER, 011 Note: The unit vectors in the +x, +y, and +z directions of a right-handed Cartesian coordinate system are î, ĵ, and ˆk, respectively. In this
More informationThe distance of the object from the equilibrium position is m.
Answers, Even-Numbered Problems, Chapter..4.6.8.0..4.6.8 (a) A = 0.0 m (b).60 s (c) 0.65 Hz Whenever the object is released from rest, its initial displacement equals the amplitude of its SHM. (a) so 0.065
More informationChapter 21 Chapter 23 Gauss Law. Copyright 2014 John Wiley & Sons, Inc. All rights reserved.
Chapter 21 Chapter 23 Gauss Law Copyright 23-1 What is Physics? Gauss law relates the electric fields at points on a (closed) Gaussian surface to the net charge enclosed by that surface. Gauss law considers
More informationChapter Electric Forces and Electric Fields. Prof. Armen Kocharian
Chapter 25-26 Electric Forces and Electric Fields Prof. Armen Kocharian First Observations Greeks Observed electric and magnetic phenomena as early as 700 BC Found that amber, when rubbed, became electrified
More informationIntegrals in Electrostatic Problems
PHYS 119 Integrals in Electrostatic Problems Josh McKenney University of North Carolina at Chapel Hill (Dated: January 6, 2016) 1 FIG. 1. Three positive charges positioned at equal distances around an
More informationExam 2 Solutions. Applying the junction rule: i 1 Applying the loop rule to the left loop (LL), right loop (RL), and the full loop (FL) gives:
PHY61 Eam Solutions 1. [8 points] In the circuit shown, the resistance R 1 = 1Ω. The batter voltages are identical: ε1 = ε = ε3 = 1 V. What is the current (in amps) flowing through the middle branch from
More informationQueen s University at Kingston. Faculty of Arts and Science. Department of Physics PHYSICS 106. Final Examination.
Page 1 of 5 Queen s University at Kingston Faculty of Arts and Science Department of Physics PHYSICS 106 Final Examination April 16th, 2009 Professor: A. B. McLean Time allowed: 3 HOURS Instructions This
More informationPractice Problems for Exam 2 Solutions
MASSACHUSETTS INSTITUTE OF TECHNOLOGY Department of Physics Physics 8.01 Fall Term 008 Practice Problems for Exam Solutions Part I Concept Questions: Circle your answer. 1) A spring-loaded toy dart gun
More informationThe World According to Physics 121
The World According to Physics Objects Forces Specified by geometry and mass Gravity: F = G m m r m Others: Tension, Normal, Friction Space and Time uclidean with Galilean Invariance ordinary 3D space;;
More informationExam One Solutions. Problem 1 (25 points): answers without work shown will not be given any credit.
MASSACHUSETTS INSTITUTE OF TECHNOLOGY Department of Physics 8.02 Spring 2014 Exam One Solutions Problem 1 (25 points): answers without work shown will not be given any credit. Four point-like objects of
More informationCreated by T. Madas LINE INTEGRALS. Created by T. Madas
LINE INTEGRALS LINE INTEGRALS IN 2 DIMENSIONAL CARTESIAN COORDINATES Question 1 Evaluate the integral ( x + 2y) dx, C where C is the path along the curve with equation y 2 = x + 1, from ( ) 0,1 to ( )
More information10 3. Determine the moment of inertia of the area about the x axis.
10 3. Determine the moment of inertia of the area about the ais. m m 10 4. Determine the moment of inertia of the area about the ais. m m 10 3. Determine the moment of inertia of the shaded area about
More informationENGI 4430 Advanced Calculus for Engineering Faculty of Engineering and Applied Science Problem Set 3 Solutions [Multiple Integration; Lines of Force]
ENGI 44 Advanced Calculus for Engineering Facult of Engineering and Applied Science Problem Set Solutions [Multiple Integration; Lines of Force]. Evaluate D da over the triangular region D that is bounded
More informationOscillations. Oscillations and Simple Harmonic Motion
Oscillations AP Physics C Oscillations and Simple Harmonic Motion 1 Equilibrium and Oscillations A marble that is free to roll inside a spherical bowl has an equilibrium position at the bottom of the bowl
More informationis acting on a body of mass m = 3.0 kg and changes its velocity from an initial
PHYS 101 second major Exam Term 102 (Zero Version) Q1. A 15.0-kg block is pulled over a rough, horizontal surface by a constant force of 70.0 N acting at an angle of 20.0 above the horizontal. The block
More information4 Chapter. Electric Potential
4 Chapter Electric Potential 4.1 Potential and Potential Energy... 4-3 4.2 Electric Potential in a Uniform Field... 4-7 4.3 Electric Potential due to Point Charges... 4-8 4.3.1 Potential Energy in a System
More informationPhys101 First Major-111 Zero Version Monday, October 17, 2011 Page: 1
Monday, October 17, 011 Page: 1 Q1. 1 b The speed-time relation of a moving particle is given by: v = at +, where v is the speed, t t + c is the time and a, b, c are constants. The dimensional formulae
More informationIntegrals in cylindrical, spherical coordinates (Sect. 15.7)
Integrals in clindrical, spherical coordinates (Sect. 15.7 Integration in spherical coordinates. Review: Clindrical coordinates. Spherical coordinates in space. Triple integral in spherical coordinates.
More informationPhysics Gravitational force. 2. Strong or color force. 3. Electroweak force
Phsics 360 Notes on Griffths - pluses and minuses No tetbook is perfect, and Griffithsisnoeception. Themajorplusisthat it is prett readable. For minuses, see below. Much of what G sas about the del operator
More informationCH 24. Electric Potential
CH 24 Electric Potential [SHIVOK SP212] January 8, 2016 I. Electric Potential Energy A. Experimentally, physicists and engineers discovered that the electric force is conservative and thus has an associated
More informationSolution to phys101-t112-final Exam
Solution to phys101-t112-final Exam Q1. An 800-N man stands halfway up a 5.0-m long ladder of negligible weight. The base of the ladder is.0m from the wall as shown in Figure 1. Assuming that the wall-ladder
More informationPhysics Lecture 08: MON 02 FEB
Physics 2113 Jonathan Dowling Physics 2113 Lecture 08: MON 02 FEB Electric Fields III Charles-Augustin de Coulomb (1736-1806) Electric Charges and Fields First: Given Electric Charges, We Calculate the
More informationPhysics 169. Luis anchordoqui. Kitt Peak National Observatory. Monday, March 13, 17
Physics 169 Kitt Peak National Observatory Luis anchordoqui 1 6.1 Magnetic Field Stationary charges experienced an electric force in an electric field Moving charges experienced a magnetic force in a magnetic
More informationUNIVERSITY OF CALIFORNIA - SANTA CRUZ DEPARTMENT OF PHYSICS PHYS 110A. Homework #7. Benjamin Stahl. March 3, 2015
UNIVERSITY OF CALIFORNIA - SANTA CRUZ DEPARTMENT OF PHYSICS PHYS A Homework #7 Benjamin Stahl March 3, 5 GRIFFITHS, 5.34 It will be shown that the magnetic field of a dipole can written in the following
More information