Coulomb s Law and Electric Fields
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1 Physics 102: Lecture 02 Coulomb s Law and Electric Fields Today we will get some practice using Coulomb s Law learn the concept of an Electric Field Physics 102: Lecture 2, Slide 1
2 Recall Coulomb s Law Magnitude of the force between charges q 1 and q 2 separated a distance r: Force is F = k q 1 q 2 /r 2 k = 9x10 9 Nm 2 /C 2 attractive if q 1 and q 2 have opposite sign repulsive if q 1 and q 2 have same sign Units: q s have units of Coulombs (C) charge on proton is 1.6 x C r has units of m F has units of N Physics 102: Lecture 2, Slide 2
3 Three Charges Calculate force on +2μC charge due to other two charges Draw forces Calculate force from +7μC charge Calculate force from 7μC charge Add (VECTORS!) Q=+7.0μC Q=+2.0μC 4 m 6 m F 7 Q=-7.0 μc Physics 102: Lecture 2, Slide 3
4 Physics 102: Lecture 2, Slide 4
5 Three Charges Calculate force on +2μC charge due to other two charges Calculate force from +7μC charge Calculate force from 7μC charge Add (VECTORS!) Q=+2.0μC F +7 4 m Q=+7.0μC 6 m Q=-7.0 μc Physics 102: Lecture 2, Slide 5
6 Three Charges F F F Calculate force on +2μC charge due to other two charges Calculate force from +7μC charge Calculate force from 7μC charge Add (VECTORS!) F = k q 1 q 2 /r (9 10 )(2 10 )(7 10 ) = N 25 3 = 5 10 N (9 10 )(2 10 )(7 10 ) = N 25 3 F N = Q=+7.0μC Q=+2.0μC 5 m 4 m 6 m F +7 F -7 Q=-7.0 μc Physics 102: Lecture 2, Slide 6
7 Adding Vectors F +7 +F -7 Q=+2.0μC F +7 5 m 4 m F -7 Q=+7.0μC 6 m Q=-7.0 μc Physics 102: Lecture 2, Slide 7
8 Physics 102: Lecture 2, Slide 8
9 Adding Vectors F +7 +F -7 y components cancel x components: F = F +7,x + F -7,x Q=+2.0μC F +7 F F +7,x = (3/5)F +7 F -7,x = (3/5)F -7 5 m 4 m F -7 F = (3/5)(5+5)x10-3 N=6 x 10-3 N Q=+7.0μC 6 m Q=-7.0 μc Physics 102: Lecture 2, Slide 9
10 Electric Field Charged particles create electric fields. Direction is the same as for the force that a + charge would feel at that location. Magnitude given by: E F/q = kq/r 2 Q p =1.6x10-19 C + r = 1x10-10 m E E = ( )( )/(10-10 ) 2 N = N/C (to the right) Physics 102: Lecture 2, Slide 10
11 Preflight 2.3 What is the direction of the electric field at point B? 1) Left 2) Right 3) Zero A y B x Physics 102: Lecture 2, Slide 11
12 Physics 102: Lecture 2, Slide 12
13 ACT: E Field What is the direction of the electric field at point C? A. Left Red is negative B. Right Blue is positive C. Zero y C x Physics 102: Lecture 2, Slide 13
14 Comparison: Electric Force vs. Electric Field Electric Force (F) - the actual force felt by a charge at some location. Electric Field (E) - found for a location only tells what the electric force would be if a charge were located there: F = Eq Both are vectors, with magnitude and direction. Add x & y components. Direction determines sign. Physics 102: Lecture 2, Slide 14
15 Physics 102: Lecture 2, Slide 15
16 Physics 102: Lecture 2, Slide 16
17 Preflight 2.2 What is the direction of the electric field at point A? 1) Up 2) Down 3) Left 4) Right 5) Zero Red is negative Blue is positive A y B x Physics 102: Lecture 2, Slide 17
18 ACT: E Field II What is the direction of the electric field at point A, if the two positive charges have equal magnitude? A. Up Red is negative B. Down Blue is positive C. Right D. Left E. Zero A y B x Physics 102: Lecture 2, Slide 18
19 Electric Field of a Point Charge N/C N/C N/C N/C E This is becoming a mess!!! Physics 102: Lecture 2, Slide 19
20 Physics 102: Lecture 2, Slide 20
21 Closeness of lines shows field strength - lines never cross # lines at surface Q Arrow gives direction of E - Start on +, end on - Electric Field Lines Physics 102: Lecture 2, Slide 21
22 Preflight 2.5 X A Y B Charge A is Field lines start on positive charge, end on negative. 1) positive 2) negative 3) unknown Physics 102: Lecture 2, Slide 22
23 Preflight 2.6 X A Y B Compare the ratio of charges Q A / Q B # lines proportional to Q 1) Q A = 0.5Q B 2) Q A = Q B 3) Q A = 2 Q B Physics 102: Lecture 2, Slide 23
24 Physics 102: Lecture 2, Slide 24
25 Preflight 2.8 X A Y B The electric field is stronger when the lines are located closer to one another. The magnitude of the electric field at point X is greater than at point Y 1) True 2) False Density of field lines gives E Physics 102: Lecture 2, Slide 25
26 ACT: E Field Lines B A Compare the magnitude of the electric field at point A and B 1) E A >E B 2) E A =E B 3) E A <E B Physics 102: Lecture 2, Slide 26
27 E inside of conductor Conductor electrons free to move Electrons feels electric force - will move until they feel no more force (F=0) F=Eq: if F=0 then E=0 E=0 inside a conductor (Always!) Physics 102: Lecture 2, Slide 27
28 Physics 102: Lecture 2, Slide 28
29 Preflight 2.10 X A Y B "Charge A" is actually a small, charged metal ball (a conductor). The magnitude of the electric field inside the ball is: (1) Negative (2) Zero (3) Positive Physics 102: Lecture 2, Slide 29
30 Demo: electric field lines Physics 102: Lecture 2, Slide 30
31 Recap E Field has magnitude and direction: E F/q Calculate just like Coulomb s law Careful when adding vectors Electric Field Lines Density gives strength (# proportional to charge.) Arrow gives direction (Start + end on -) Conductors Electrons free to move E=0 Physics 102: Lecture 2, Slide 31
32 To Do Do your preflight by 6:00 AM. Physics 102: Lecture 2, Slide 32
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