Simplification and Strengthening of Weyl s Definition of Asymptotic Equal Distribution of Two Families of Finite Sets
|
|
- Anis Henry
- 5 years ago
- Views:
Transcription
1 Simplifictio d Stregtheig of Weyl s Defiitio of Asymptotic Equl Distributio of Two Fmilies of Fiite Sets Willim F. Trech Triity Uiversity, S Atoio, Texs, USA; wtrech@triity.edu Milig ddress: 95 Pie Le, Woodld Prk, CO USA Published i CUBO, A MATHEMATICAL JOURNAL, Vol. 6, No. 3 (47 54), October 2004 Abstrct Suppose tht < < b <, u u 2 u b, d v v 2 v b,. We simplify d streghthe Weyl s defiitio of symptotic equl distributio of U = {{u i} } d V = {{v i} } by showig tht the followig sttemets re equivlet: (i) (F(ui) F(vi)) = 0 for ll F C[, b]. (ii) ui vi = 0. (iii) F(ui) F(vi) = 0 for ll F C[, b]. Itroductio The followig defiitio is due to H. Weyl [, p. 62]. Defiitio. Suppose tht < < b <, {u i } [, b], d {v i} [, b],. The U = {{u i } } d V = {{v i } } re symptoticlly eqully distributed if (F(u i ) F(v i )) = 0, F C[, b].
2 2 Willim F. Trech We preset simple ecessry d sufficiet coditio for symptotic equl distributio d poit out tht stroger coclusio is implicit i Defiitio.. Without loss of geerlity, we my ssume tht u u 2 u b, v v 2 v b,. () Theorem.2 If () holds the the followig ssertios re equivlet: (F(u i ) F(v i )) = 0, F C[, b]; (2) u i v i = 0; (3) F(u i ) F(v i ) = 0, F C[, b]. (4) Obviously, (4) implies (2). The proof tht (3) implies (4) (Sectio 2) is strightforwrd. Our mi effort is devoted to showig tht (2) implies (3). Theorem.2 is specil cse of more geerl results i [4] cocerig symptotic reltioships betwee the eigevlues or sigulr vlues of two ifiite sequeces of mtrices {A } = d {B } = relted i some wy tht it is ot ecessry to specify here. However, [4] is quite techicl d of iterest mily to the lier lgebr commuity. We thik it is worthwhile to preset Theorem.2 i this expository rticle ddressed to lrger udiece. Give Theorem.2, we suggest replcig Defiitio. by the followig simpler defiitio while berig i mid tht (3) implies (4). Defiitio.3 U = {{u i } } d V = {{v i } } re symptoticlly eqully distributed if () holds d u i v i = 0. 2 Proof tht (3) implies (4) Suppose tht F C[, b] d ɛ > 0. By the Weierstrss pproximtio theorem, there is polyomil P such tht By the trigle iequlity, F(x) P(x) < ɛ/2, x b. F(u i ) F(v i ) F(u i ) P(u i ) + P(u i ) P(v i ) + P(v i ) F(v i ) < P(u i ) P(v i ) + ɛ. (5)
3 Asymptotic Equl Distributio 3 Let M = mx x b P (x). By the me vlue theorem, This d (5) imply tht From this d (3), P(u i ) P(v i ) M u i v i. F(u i ) F(v i ) < ɛ + M sup u i v i. F(u i ) F(v i ) ɛ. Sice ɛ is rbitrry, this implies (4). 3 Four Required Lemms We eed the followig lemms to show tht (2) implies (3). Lemm 3. (Helly s First Theorem) Let {φ m } m= be ifiite sequece of fuctios o [, b] d suppose tht there is fiite umber K such tht φ m (x) K, x b, d V b (φ m ) K, m. The there is subsequece of {φ m } m= tht coverges t every poit of [, b] to fuctio of bouded vritio o [, b]. Lemm 3.2 (Helly s Secod Theorem) Let {φ m } m= be ifiite sequece of fuctios o [, b] such tht V b (φ m ) K <, m, d The V b (φ) K d m φ m(x) = φ(x), x b. m F(x)dφ m (x) = F(x)dφ(x), F C[, b]. Lemm 3.3 Suppose tht φ() = φ(b) = 0, φ is of bouded vritio o [, b], d F(x)dφ(x) = 0, F C[, b]. The φ(x) = 0 t ll poits of cotiuity of φ. Thus, φ(x) 0 for t most coutbly my vlues of x. For proofs of Lemms , see [2, p. 222], [2, p. 233], d [3, p. ]. The followig lemm is lso kow [5, p. 08], but we iclude its short proof for coveiece.
4 4 Willim F. Trech Lemm 3.4 Suppose tht x x 2 x d y y 2 y. Let {l, l 2,...l } be permuttio of {, 2,..., } d defie The Q(l, l 2,..., l ) = (x i y li ) 2. Q(l, l 2,..., l ) Q(, 2,..., ). (6) Proof The proof is by iductio. Let P be the stted propositio. P is trivil. Suppose tht > d P is true. If l =, P implies P. If l = s <, choose r so tht l r =, d defie l i if i r d i, l i = s if i = r, if i =. The Q(l, l 2,..., l ) Q(l, l 2,..., l ) = (x y s ) 2 + (x r y ) 2 Sice l =, P implies tht Q(l, l 2,..., l ) Q(, 2,..., ). (x y ) 2 (x r y s ) 2 Therefore (7) implies (6), which completes the iductio. 4 Proof tht (2) implies (3) We will show tht if (2) holds the From Schwrz s iequlity, = 2(x x r )(y y s ) 0. (7) (u i v i ) 2 = 0. (8) u i v i ( ) /2 (u i v i ) 2, so (8) implies (3). The proof of (8) is by cotrdictio. If (8) is flse, there is ɛ 0 > 0 d icresig sequece {l k } k= of positive itegers such tht l k l k (u ilk v ilk ) 2 ɛ 0, k. (9)
5 Asymptotic Equl Distributio 5 However, we will show tht if (2) holds, the y icresig sequece {l k } k= of positive itegers hs subsequece { k } k= such tht k k k (u ik v ik ) 2 = 0, (0) cotrdictig (9). If S is set, let crd S be the crdility of S. For x b, let ν (x;u) = crd { i u i < x } d ν (x;v) = crd { i v i < x }. () Defie d If F C[, b], the ρ (x;u) = ρ (x;v) = { ν (x;u)/, x < b,, x = b, { ν (x;v)/, x < b,, x = b. (2) (3) d F(u i ) = F(v i ) = F(x)dρ (x;u) (4) F(x)dρ (x;v) (5) [2, p. 23]. The sequeces {ρ ( ;U)} = d {ρ ( ;V)} = both stisfy the hypotheses of Lemm 3.. Therefore, there is subsequece {m k } k= of {l k} k= such tht γ(x;u) := ρ m k (x;u) (6) k exists for x b, d there is subsequece { k } k= of {m k} k= such tht exists for x b. Clerly, (6) implies tht γ(x;v) := k ρ k (x;v) (7) γ(x;u) = k ρ k (x;u), x b. (8) From () (3), γ( ; U) d γ( ; V) re odecresig, γ(;u) = γ(;v) = 0, d γ(b;u) = γ(b;v) =. (9) Therefore, (7), (8), d Lemm 3.2 imply tht k F(x)dρ k (x;u) = F(x)dγ(x;U), F C[, b], (20)
6 6 Willim F. Trech d k F(x)dρ k (x;v) = Now (2), (4), (5) (20), d (2) imply tht F(x)dγ(x;V), F C[, b]. (2) F(x)dγ(x;U) = F(x)dγ(x;V), F C[, b]. This, (9), d Lemm 3.3 with φ = γ( ;U) γ( ;V) imply tht γ(x;u) = γ(x;v) except for t most coutbly my vlues of x i [, b]. If ɛ > 0, choose 0,,..., m so tht d Let Defie d The d = 0 < < < m = b, j j < ɛ, j m, (22) γ( j ;U) = γ( j ;V), j m. (23) I j = [ j, j ), j m, I m = [ m, m ]. ν k ( ;U), j =, U jk = ν k ( j ;U) ν k ( j ;U), 2 j m, k ν k ( m ;U), j = m, ν k ( ;V), j =, V jk = ν k ( j ;V) ν k ( j ;V), 2 j m, k ν k ( m ;V), j = m. U jk = crd { i uik I j }, Vjk = crd { i vik I j }, from (2), (3), (7), (8), d (23). Sice U jk V jk = 0, j m, (24) k k d mi(u jk, V jk ) = U jk + V jk U jk V jk, 2 m m U jk = V jk = k, j= j=
7 Asymptotic Equl Distributio 7 it follows tht where From (24), m mi(u jk, V jk ) = k r k, (25) j= r k = 2 m U jk V jk. j= r k = 0. (26) k k From (22) d (25), there is permuttio τ k of {,..., k } such tht for k r k vlues of i; hece k Now Lemm 3.4 implies tht Hece, from (26), (u ik v τk(i), k ) 2 < ɛ (u ik v τk(i), k ) 2 < k ɛ + r k (b ) 2. k (u ik v ik ) 2 < k ɛ + r k (b ) 2. sup k k k (u ik v ik ) 2 ɛ. Sice ɛ is rbitrry, this implies (0), which completes the proof. 5 Ackowledgmet I thk Professor Polo Tilli for suggestio tht ebled me to complete the proof i Sectio 4. Refereces [] U. Greder, G. Szegö, Toeplitz Forms d Their Applictios, Uiv. of Clifori Press, Berkeley d Los Ageles, 958. [2] I. P. Ntso, Theory of Fuctios of Rel Vrible, Frederick Ugr Publishig Co., New York, 955. [3] F. Riesz d B. Sz. Ngy, Fuctiol Alysis, Frederick Ugr Publishig Co., New York, 955.
8 8 Willim F. Trech [4] W. F. Trech, Absolute equl distributio of fmilies of fiite sets, Lier Algebr Appl. 367 (2003), [5] J. H. Wilkiso, The Algebric Eigevlue Problem, Clredo Press, Oxford, 965.
Convergence rates of approximate sums of Riemann integrals
Jourl of Approximtio Theory 6 (9 477 49 www.elsevier.com/locte/jt Covergece rtes of pproximte sums of Riem itegrls Hiroyuki Tski Grdute School of Pure d Applied Sciece, Uiversity of Tsukub, Tsukub Ibrki
More informationCertain sufficient conditions on N, p n, q n k summability of orthogonal series
Avilble olie t www.tjs.com J. Nolier Sci. Appl. 7 014, 7 77 Reserch Article Certi sufficiet coditios o N, p, k summbility of orthogol series Xhevt Z. Krsiqi Deprtmet of Mthemtics d Iformtics, Fculty of
More informationMATH 104 FINAL SOLUTIONS. 1. (2 points each) Mark each of the following as True or False. No justification is required. y n = x 1 + x x n n
MATH 04 FINAL SOLUTIONS. ( poits ech) Mrk ech of the followig s True or Flse. No justifictio is required. ) A ubouded sequece c hve o Cuchy subsequece. Flse b) A ifiite uio of Dedekid cuts is Dedekid cut.
More informationConvergence rates of approximate sums of Riemann integrals
Covergece rtes of pproximte sums of Riem itegrls Hiroyuki Tski Grdute School of Pure d Applied Sciece, Uiversity of Tsuku Tsuku Irki 5-857 Jp tski@mth.tsuku.c.jp Keywords : covergece rte; Riem sum; Riem
More informationMath 104: Final exam solutions
Mth 14: Fil exm solutios 1. Suppose tht (s ) is icresig sequece with coverget subsequece. Prove tht (s ) is coverget sequece. Aswer: Let the coverget subsequece be (s k ) tht coverges to limit s. The there
More informationReview of the Riemann Integral
Chpter 1 Review of the Riem Itegrl This chpter provides quick review of the bsic properties of the Riem itegrl. 1.0 Itegrls d Riem Sums Defiitio 1.0.1. Let [, b] be fiite, closed itervl. A prtitio P of
More informationReversing the Arithmetic mean Geometric mean inequality
Reversig the Arithmetic me Geometric me iequlity Tie Lm Nguye Abstrct I this pper we discuss some iequlities which re obtied by ddig o-egtive expressio to oe of the sides of the AM-GM iequlity I this wy
More informationSecond Mean Value Theorem for Integrals By Ng Tze Beng. The Second Mean Value Theorem for Integrals (SMVT) Statement of the Theorem
Secod Me Vlue Theorem for Itegrls By Ng Tze Beg This rticle is out the Secod Me Vlue Theorem for Itegrls. This theorem, first proved y Hoso i its most geerlity d with extesio y ixo, is very useful d lmost
More informationWe will begin by supplying the proof to (a).
(The solutios of problem re mostly from Jeffrey Mudrock s HWs) Problem 1. There re three sttemet from Exmple 5.4 i the textbook for which we will supply proofs. The sttemets re the followig: () The spce
More informationBasic Limit Theorems
Bsic Limit Theorems The very "cle" proof of L9 usig L8 ws provided to me by Joh Gci d it ws this result which ispired me to write up these otes. Absolute Vlue Properties: For rel umbers x, d y x x if x
More informationChapter 7 Infinite Series
MA Ifiite Series Asst.Prof.Dr.Supree Liswdi Chpter 7 Ifiite Series Sectio 7. Sequece A sequece c be thought of s list of umbers writte i defiite order:,,...,,... 2 The umber is clled the first term, 2
More informationn 2 + 3n + 1 4n = n2 + 3n + 1 n n 2 = n + 1
Ifiite Series Some Tests for Divergece d Covergece Divergece Test: If lim u or if the limit does ot exist, the series diverget. + 3 + 4 + 3 EXAMPLE: Show tht the series diverges. = u = + 3 + 4 + 3 + 3
More information3.7 The Lebesgue integral
3 Mesure d Itegrtio The f is simple fuctio d positive wheever f is positive (the ltter follows from the fct tht i this cse f 1 [B,k ] = for ll k, ). Moreover, f (x) f (x). Ideed, if x, the there exists
More informationSequence and Series of Functions
6 Sequece d Series of Fuctios 6. Sequece of Fuctios 6.. Poitwise Covergece d Uiform Covergece Let J be itervl i R. Defiitio 6. For ech N, suppose fuctio f : J R is give. The we sy tht sequece (f ) of fuctios
More informationis infinite. The converse is proved similarly, and the last statement of the theorem is clear too.
12. No-stdrd lysis October 2, 2011 I this sectio we give brief itroductio to o-stdrd lysis. This is firly well-developed field of mthemtics bsed o model theory. It dels ot just with the rels, fuctios o
More informationMAS221 Analysis, Semester 2 Exercises
MAS22 Alysis, Semester 2 Exercises Srh Whitehouse (Exercises lbelled * my be more demdig.) Chpter Problems: Revisio Questio () Stte the defiitio of covergece of sequece of rel umbers, ( ), to limit. (b)
More informationAdvanced Calculus Test File Spring Test 1
Advced Clculus Test File Sprig 009 Test Defiitios - Defie the followig terms.) Crtesi product of A d B.) The set, A, is coutble.) The set, A, is ucoutble 4.) The set, A, is ifiite 5.) The sets A d B re
More informationReview of Sections
Review of Sectios.-.6 Mrch 24, 204 Abstrct This is the set of otes tht reviews the mi ides from Chpter coverig sequeces d series. The specific sectios tht we covered re s follows:.: Sequces..2: Series,
More informationf(bx) dx = f dx = dx l dx f(0) log b x a + l log b a 2ɛ log b a.
Eercise 5 For y < A < B, we hve B A f fb B d = = A B A f d f d For y ɛ >, there re N > δ >, such tht d The for y < A < δ d B > N, we hve ba f d f A bb f d l By ba A A B A bb ba fb d f d = ba < m{, b}δ
More informationProbability for mathematicians INDEPENDENCE TAU
Probbility for mthemticis INDEPENDENCE TAU 2013 21 Cotets 2 Cetrl limit theorem 21 2 Itroductio............................ 21 2b Covolutio............................ 22 2c The iitil distributio does
More information[ 20 ] 1. Inequality exists only between two real numbers (not complex numbers). 2. If a be any real number then one and only one of there hold.
[ 0 ]. Iequlity eists oly betwee two rel umbers (ot comple umbers).. If be y rel umber the oe d oly oe of there hold.. If, b 0 the b 0, b 0.. (i) b if b 0 (ii) (iii) (iv) b if b b if either b or b b if
More informationANALYSIS HW 3. f(x + y) = f(x) + f(y) for all real x, y. Demonstration: Let f be such a function. Since f is smooth, f exists.
ANALYSIS HW 3 CLAY SHONKWILER () Fid ll smooth fuctios f : R R with the property f(x + y) = f(x) + f(y) for ll rel x, y. Demostrtio: Let f be such fuctio. Sice f is smooth, f exists. The The f f(x + h)
More informationProbability and Stochastic Processes: A Friendly Introduction for Electrical and Computer Engineers Roy D. Yates and David J.
Probbility d Stochstic Processes: A Friedly Itroductio for Electricl d Computer Egieers Roy D. Ytes d Dvid J. Goodm Problem Solutios : Ytes d Goodm,4..4 4..4 4..7 4.4. 4.4. 4..6 4.6.8 4.6.9 4.7.4 4.7.
More informationPOWER SERIES R. E. SHOWALTER
POWER SERIES R. E. SHOWALTER. sequeces We deote by lim = tht the limit of the sequece { } is the umber. By this we me tht for y ε > 0 there is iteger N such tht < ε for ll itegers N. This mkes precise
More informationAN INEQUALITY OF GRÜSS TYPE FOR RIEMANN-STIELTJES INTEGRAL AND APPLICATIONS FOR SPECIAL MEANS
RGMIA Reserch Report Collectio, Vol., No., 998 http://sci.vut.edu.u/ rgmi/reports.html AN INEQUALITY OF GRÜSS TYPE FOR RIEMANN-STIELTJES INTEGRAL AND APPLICATIONS FOR SPECIAL MEANS S.S. DRAGOMIR AND I.
More informationTest Info. Test may change slightly.
9. 9.6 Test Ifo Test my chge slightly. Short swer (0 questios 6 poits ech) o Must choose your ow test o Tests my oly be used oce o Tests/types you re resposible for: Geometric (kow sum) Telescopig (kow
More informationTHE NATIONAL UNIVERSITY OF IRELAND, CORK COLÁISTE NA hollscoile, CORCAIGH UNIVERSITY COLLEGE, CORK SUMMER EXAMINATION 2005 FIRST ENGINEERING
OLLSCOIL NA héireann, CORCAIGH THE NATIONAL UNIVERSITY OF IRELAND, CORK COLÁISTE NA hollscoile, CORCAIGH UNIVERSITY COLLEGE, CORK SUMMER EXAMINATION 2005 FIRST ENGINEERING MATHEMATICS MA008 Clculus d Lier
More information1. (25 points) Use the limit definition of the definite integral and the sum formulas to compute. [1 x + x2
Mth 3, Clculus II Fil Exm Solutios. (5 poits) Use the limit defiitio of the defiite itegrl d the sum formuls to compute 3 x + x. Check your swer by usig the Fudmetl Theorem of Clculus. Solutio: The limit
More informationChapter 5. The Riemann Integral. 5.1 The Riemann integral Partitions and lower and upper integrals. Note: 1.5 lectures
Chpter 5 The Riem Itegrl 5.1 The Riem itegrl Note: 1.5 lectures We ow get to the fudmetl cocept of itegrtio. There is ofte cofusio mog studets of clculus betwee itegrl d tiderivtive. The itegrl is (iformlly)
More informationReal Analysis Fall 2004 Take Home Test 1 SOLUTIONS. < ε. Hence lim
Real Aalysis Fall 004 Take Home Test SOLUTIONS. Use the defiitio of a limit to show that (a) lim si = 0 (b) Proof. Let ε > 0 be give. Defie N >, where N is a positive iteger. The for ε > N, si 0 < si
More informationThe Reimann Integral is a formal limit definition of a definite integral
MATH 136 The Reim Itegrl The Reim Itegrl is forml limit defiitio of defiite itegrl cotiuous fuctio f. The costructio is s follows: f ( x) dx for Reim Itegrl: Prtitio [, ] ito suitervls ech hvig the equl
More information(1 q an+b ). n=0. n=0
AN ELEMENTARY DERIVATION OF THE ASYMPTOTICS OF PARTITION FUNCTIONS Diel M Ke Abstrct Let S,b { + b : 0} where is iteger Let P,b deote the umber of prtitios of ito elemets of S,b I prticulr, we hve the
More informationSequences and Series of Functions
Chapter 6 Sequeces ad Series of Fuctios 6.1. Covergece of a Sequece of Fuctios Poitwise Covergece. Defiitio 6.1. Let, for each N, fuctio f : A R be defied. If, for each x A, the sequece (f (x)) coverges
More informationContent: Essential Calculus, Early Transcendentals, James Stewart, 2007 Chapter 1: Functions and Limits., in a set B.
Review Sheet: Chpter Cotet: Essetil Clculus, Erly Trscedetls, Jmes Stewrt, 007 Chpter : Fuctios d Limits Cocepts, Defiitios, Lws, Theorems: A fuctio, f, is rule tht ssigs to ech elemet i set A ectly oe
More informationSOME IDENTITIES BETWEEN BASIC HYPERGEOMETRIC SERIES DERIVING FROM A NEW BAILEY-TYPE TRANSFORMATION
SOME IDENTITIES BETWEEN BASIC HYPERGEOMETRIC SERIES DERIVING FROM A NEW BAILEY-TYPE TRANSFORMATION JAMES MC LAUGHLIN AND PETER ZIMMER Abstrct We prove ew Biley-type trsformtio reltig WP- Biley pirs We
More informationf(t)dt 2δ f(x) f(t)dt 0 and b f(t)dt = 0 gives F (b) = 0. Since F is increasing, this means that
Uiversity of Illiois t Ur-Chmpig Fll 6 Mth 444 Group E3 Itegrtio : correctio of the exercises.. ( Assume tht f : [, ] R is cotiuous fuctio such tht f(x for ll x (,, d f(tdt =. Show tht f(x = for ll x [,
More information( a n ) converges or diverges.
Chpter Ifiite Series Pge of Sectio E Rtio Test Chpter : Ifiite Series By the ed of this sectio you will be ble to uderstd the proof of the rtio test test series for covergece by pplyig the rtio test pprecite
More informationRemarks: (a) The Dirac delta is the function zero on the domain R {0}.
Sectio Objective(s): The Dirc s Delt. Mi Properties. Applictios. The Impulse Respose Fuctio. 4.4.. The Dirc Delt. 4.4. Geerlized Sources Defiitio 4.4.. The Dirc delt geerlized fuctio is the limit δ(t)
More informationINFINITE SERIES. ,... having infinite number of terms is called infinite sequence and its indicated sum, i.e., a 1
Appedix A.. Itroductio As discussed i the Chpter 9 o Sequeces d Series, sequece,,...,,... hvig ifiite umber of terms is clled ifiite sequece d its idicted sum, i.e., + + +... + +... is clled ifite series
More informationAbel type inequalities, complex numbers and Gauss Pólya type integral inequalities
Mthemticl Commuictios 31998, 95-101 95 Abel tye iequlities, comlex umbers d Guss Póly tye itegrl iequlities S. S. Drgomir, C. E. M. Perce d J. Šude Abstrct. We obti iequlities of Abel tye but for odecresig
More informationMATH 312 Midterm I(Spring 2015)
MATH 3 Midterm I(Sprig 05) Istructor: Xiaowei Wag Feb 3rd, :30pm-3:50pm, 05 Problem (0 poits). Test for covergece:.. 3.. p, p 0. (coverges for p < ad diverges for p by ratio test.). ( coverges, sice (log
More informationPrinciples of Mathematical Analysis
Ciro Uiversity Fculty of Scieces Deprtmet of Mthemtics Priciples of Mthemticl Alysis M 232 Mostf SABRI ii Cotets Locl Study of Fuctios. Remiders......................................2 Tylor-Youg Formul..............................
More information0 otherwise. sin( nx)sin( kx) 0 otherwise. cos( nx) sin( kx) dx 0 for all integers n, k.
. Computtio of Fourier Series I this sectio, we compute the Fourier coefficiets, f ( x) cos( x) b si( x) d b, i the Fourier series To do this, we eed the followig result o the orthogolity of the trigoometric
More informationSOME SHARP OSTROWSKI-GRÜSS TYPE INEQUALITIES
Uiv. Beogrd. Publ. Elektroteh. Fk. Ser. Mt. 8 006 4. Avilble electroiclly t http: //pefmth.etf.bg.c.yu SOME SHARP OSTROWSKI-GRÜSS TYPE INEQUALITIES Zheg Liu Usig vrit of Grüss iequlity to give ew proof
More informationBIRKHOFF ERGODIC THEOREM
BIRKHOFF ERGODIC THEOREM Abstract. We will give a proof of the poitwise ergodic theorem, which was first proved by Birkhoff. May improvemets have bee made sice Birkhoff s orgial proof. The versio we give
More informationSUTCLIFFE S NOTES: CALCULUS 2 SWOKOWSKI S CHAPTER 11
UTCLIFFE NOTE: CALCULU WOKOWKI CHAPTER Ifiite eries Coverget or Diverget eries Cosider the sequece If we form the ifiite sum 0, 00, 000, 0 00 000, we hve wht is clled ifiite series We wt to fid the sum
More informationMetric Space Properties
Metric Space Properties Math 40 Fial Project Preseted by: Michael Brow, Alex Cordova, ad Alyssa Sachez We have already poited out ad will recogize throughout this book the importace of compact sets. All
More information{ } { S n } is monotonically decreasing if Sn
Sequece A sequece is fuctio whose domi of defiitio is the set of turl umers. Or it c lso e defied s ordered set. Nottio: A ifiite sequece is deoted s { } S or { S : N } or { S, S, S,...} or simply s {
More informationMath 341 Lecture #31 6.5: Power Series
Math 341 Lecture #31 6.5: Power Series We ow tur our attetio to a particular kid of series of fuctios, amely, power series, f(x = a x = a 0 + a 1 x + a 2 x 2 + where a R for all N. I terms of a series
More informationLinear Programming. Preliminaries
Lier Progrmmig Prelimiries Optimiztio ethods: 3L Objectives To itroduce lier progrmmig problems (LPP To discuss the stdrd d coicl form of LPP To discuss elemetry opertio for lier set of equtios Optimiztio
More informationd) If the sequence of partial sums converges to a limit L, we say that the series converges and its
Ifiite Series. Defiitios & covergece Defiitio... Let {a } be a sequece of real umbers. a) A expressio of the form a + a +... + a +... is called a ifiite series. b) The umber a is called as the th term
More informationMath 140B - Notes. Neil Donaldson. September 2, 2009
Mth 40B - Notes Neil Doldso September 2, 2009 Itroductio This clss cotiues from 40A. The mi purpose of the clss is to mke bsic clculus rigorous.. Nottio We will observe the followig ottio throughout this
More informationThe limit comparison test
Roerto s Notes o Ifiite Series Chpter : Covergece tests Sectio 4 The limit compriso test Wht you eed to kow lredy: Bsics of series d direct compriso test. Wht you c ler here: Aother compriso test tht does
More information1 Lecture 2: Sequence, Series and power series (8/14/2012)
Summer Jump-Start Program for Aalysis, 202 Sog-Yig Li Lecture 2: Sequece, Series ad power series (8/4/202). More o sequeces Example.. Let {x } ad {y } be two bouded sequeces. Show lim sup (x + y ) lim
More information10.1 Sequences. n term. We will deal a. a n or a n n. ( 1) n ( 1) n 1 2 ( 1) a =, 0 0,,,,, ln n. n an 2. n term.
0. Sequeces A sequece is a list of umbers writte i a defiite order: a, a,, a, a is called the first term, a is the secod term, ad i geeral eclusively with ifiite sequeces ad so each term Notatio: the sequece
More informationRiemann Integral and Bounded function. Ng Tze Beng
Riem Itegrl d Bouded fuctio. Ng Tze Beg I geerlistio of re uder grph of fuctio, it is ormlly ssumed tht the fuctio uder cosidertio e ouded. For ouded fuctio, the rge of the fuctio is ouded d hece y suset
More informationThe Borel-Cantelli Lemma and its Applications
The Borel-Catelli Lemma ad its Applicatios Ala M. Falleur Departmet of Mathematics ad Statistics The Uiversity of New Mexico Albuquerque, New Mexico, USA Dig Li Departmet of Electrical ad Computer Egieerig
More informationStatistics for Financial Engineering Session 1: Linear Algebra Review March 18 th, 2006
Sttistics for Ficil Egieerig Sessio : Lier Algebr Review rch 8 th, 6 Topics Itroductio to trices trix opertios Determits d Crmer s rule Eigevlues d Eigevectors Quiz The cotet of Sessio my be fmilir to
More informationConvergence of random variables. (telegram style notes) P.J.C. Spreij
Covergece of radom variables (telegram style otes).j.c. Spreij this versio: September 6, 2005 Itroductio As we kow, radom variables are by defiitio measurable fuctios o some uderlyig measurable space
More informationMATH 112: HOMEWORK 6 SOLUTIONS. Problem 1: Rudin, Chapter 3, Problem s k < s k < 2 + s k+1
MATH 2: HOMEWORK 6 SOLUTIONS CA PRO JIRADILOK Problem. If s = 2, ad Problem : Rudi, Chapter 3, Problem 3. s + = 2 + s ( =, 2, 3,... ), prove that {s } coverges, ad that s < 2 for =, 2, 3,.... Proof. The
More information10.5 Test Info. Test may change slightly.
0.5 Test Ifo Test my chge slightly. Short swer (0 questios 6 poits ech) o Must choose your ow test o Tests my oly be used oce o Tests/types you re resposible for: Geometric (kow sum) Telescopig (kow sum)
More informationChapter System of Equations
hpter 4.5 System of Equtios After redig th chpter, you should be ble to:. setup simulteous lier equtios i mtrix form d vice-vers,. uderstd the cocept of the iverse of mtrix, 3. kow the differece betwee
More informationThe Weierstrass Approximation Theorem
The Weierstrss Approximtio Theorem Jmes K. Peterso Deprtmet of Biologicl Scieces d Deprtmet of Mthemticl Scieces Clemso Uiversity Februry 26, 2018 Outlie The Wierstrss Approximtio Theorem MtLb Implemettio
More informationSection IV.6: The Master Method and Applications
Sectio IV.6: The Mster Method d Applictios Defiitio IV.6.1: A fuctio f is symptoticlly positive if d oly if there exists rel umer such tht f(x) > for ll x >. A cosequece of this defiitio is tht fuctio
More informationMTH 146 Class 16 Notes
MTH 46 Clss 6 Notes 0.4- Cotiued Motivtio: We ow cosider the rc legth of polr curve. Suppose we wish to fid the legth of polr curve curve i terms of prmetric equtios s: r f where b. We c view the cos si
More informationTaylor Polynomials. The Tangent Line. (a, f (a)) and has the same slope as the curve y = f (x) at that point. It is the best
Tylor Polyomils Let f () = e d let p() = 1 + + 1 + 1 6 3 Without usig clcultor, evlute f (1) d p(1) Ok, I m still witig With little effort it is possible to evlute p(1) = 1 + 1 + 1 (144) + 6 1 (178) =
More informationSection 5.5. Infinite Series: The Ratio Test
Differece Equatios to Differetial Equatios Sectio 5.5 Ifiite Series: The Ratio Test I the last sectio we saw that we could demostrate the covergece of a series a, where a 0 for all, by showig that a approaches
More informationA general theory of minimal increments for Hirsch-type indices and applications to the mathematical characterization of Kosmulski-indices
Mlysi Jourl of Librry & Iformtio Sciece, Vol. 9, o. 3, 04: 4-49 A geerl theory of miiml icremets for Hirsch-type idices d pplictios to the mthemticl chrcteriztio of Kosmulski-idices L. Egghe Uiversiteit
More informationRiemann Integration. Chapter 1
Mesure, Itegrtio & Rel Alysis. Prelimiry editio. 8 July 2018. 2018 Sheldo Axler 1 Chpter 1 Riem Itegrtio This chpter reviews Riem itegrtio. Riem itegrtio uses rectgles to pproximte res uder grphs. This
More informationANSWERS TO MIDTERM EXAM # 2
MATH 03, FALL 003 ANSWERS TO MIDTERM EXAM # PENN STATE UNIVERSITY Problem 1 (18 pts). State ad prove the Itermediate Value Theorem. Solutio See class otes or Theorem 5.6.1 from our textbook. Problem (18
More informationTheorem 3. A subset S of a topological space X is compact if and only if every open cover of S by open sets in X has a finite subcover.
Compactess Defiitio 1. A cover or a coverig of a topological space X is a family C of subsets of X whose uio is X. A subcover of a cover C is a subfamily of C which is a cover of X. A ope cover of X is
More information11.5 Alternating Series, Absolute and Conditional Convergence
.5.5 Alteratig Series, Absolute ad Coditioal Covergece We have see that the harmoic series diverges. It may come as a surprise the to lear that ) 2 + 3 4 + + )+ + = ) + coverges. To see this, let s be
More informationCourse 121, , Test III (JF Hilary Term)
Course 2, 989 9, Test III (JF Hilry Term) Fridy 2d Februry 99, 3. 4.3pm Aswer y THREE questios. Let f: R R d g: R R be differetible fuctios o R. Stte the Product Rule d the Quotiet Rule for differetitig
More informationWeek 13 Notes: 1) Riemann Sum. Aim: Compute Area Under a Graph. Suppose we want to find out the area of a graph, like the one on the right:
Week 1 Notes: 1) Riem Sum Aim: Compute Are Uder Grph Suppose we wt to fid out the re of grph, like the oe o the right: We wt to kow the re of the red re. Here re some wys to pproximte the re: We cut the
More informationSUTCLIFFE S NOTES: CALCULUS 2 SWOKOWSKI S CHAPTER 11
SUTCLIFFE S NOTES: CALCULUS SWOKOWSKI S CHAPTER Ifiite Series.5 Altertig Series d Absolute Covergece Next, let us cosider series with both positive d egtive terms. The simplest d most useful is ltertig
More informationDEPARTMENT OF ELECTRICAL &ELECTRONICS ENGINEERING SIGNALS AND SYSTEMS. Assoc. Prof. Dr. Burak Kelleci. Spring 2018
DEPARTMENT OF ELECTRICAL &ELECTRONICS ENGINEERING SIGNALS AND SYSTEMS Assoc. Prof. Dr. Bur Kelleci Sprig 8 OUTLINE The Z-Trsform The Regio of covergece for the Z-trsform The Iverse Z-Trsform Geometric
More informationInfinite Series Sequences: terms nth term Listing Terms of a Sequence 2 n recursively defined n+1 Pattern Recognition for Sequences Ex:
Ifiite Series Sequeces: A sequece i defied s fuctio whose domi is the set of positive itegers. Usully it s esier to deote sequece i subscript form rther th fuctio ottio.,, 3, re the terms of the sequece
More informationMath 132, Fall 2009 Exam 2: Solutions
Math 3, Fall 009 Exam : Solutios () a) ( poits) Determie for which positive real umbers p, is the followig improper itegral coverget, ad for which it is diverget. Evaluate the itegral for each value of
More informationsin(n) + 2 cos(2n) n 3/2 3 sin(n) 2cos(2n) n 3/2 a n =
60. Ratio ad root tests 60.1. Absolutely coverget series. Defiitio 13. (Absolute covergece) A series a is called absolutely coverget if the series of absolute values a is coverget. The absolute covergece
More informationM17 MAT25-21 HOMEWORK 5 SOLUTIONS
M17 MAT5-1 HOMEWORK 5 SOLUTIONS 1. To Had I Cauchy Codesatio Test. Exercise 1: Applicatio of the Cauchy Codesatio Test Use the Cauchy Codesatio Test to prove that 1 diverges. Solutio 1. Give the series
More informationNotes #3 Sequences Limit Theorems Monotone and Subsequences Bolzano-WeierstraßTheorem Limsup & Liminf of Sequences Cauchy Sequences and Completeness
Notes #3 Sequeces Limit Theorems Mootoe ad Subsequeces Bolzao-WeierstraßTheorem Limsup & Limif of Sequeces Cauchy Sequeces ad Completeess This sectio of otes focuses o some of the basics of sequeces of
More informationClosed Newton-Cotes Integration
Closed Newto-Cotes Itegrtio Jmes Keeslig This documet will discuss Newto-Cotes Itegrtio. Other methods of umericl itegrtio will be discussed i other posts. The other methods will iclude the Trpezoidl Rule,
More information1+x 1 + α+x. x = 2(α x2 ) 1+x
Math 2030 Homework 6 Solutios # [Problem 5] For coveiece we let α lim sup a ad β lim sup b. Without loss of geerality let us assume that α β. If α the by assumptio β < so i this case α + β. By Theorem
More informationDifferent kinds of Mathematical Induction
Differet ids of Mathematical Iductio () Mathematical Iductio Give A N, [ A (a A a A)] A N () (First) Priciple of Mathematical Iductio Let P() be a propositio (ope setece), if we put A { : N p() is true}
More information1.3 Continuous Functions and Riemann Sums
mth riem sums, prt 0 Cotiuous Fuctios d Riem Sums I Exmple we sw tht lim Lower() = lim Upper() for the fuctio!! f (x) = + x o [0, ] This is o ccidet It is exmple of the followig theorem THEOREM Let f be
More informationSUBSERIES CONVERGENCE AND SEQUENCE-EVALUATION CONVERGENCE. Min-Hyung Cho, Hong Taek Hwang and Won Sok Yoo. n t j x j ) = f(x 0 ) f(x j ) < +.
Kagweo-Kyugki Math. Jour. 6 (1998), No. 2, pp. 331 339 SUBSERIES CONVERGENCE AND SEQUENCE-EVALUATION CONVERGENCE Mi-Hyug Cho, Hog Taek Hwag ad Wo Sok Yoo Abstract. We show a series of improved subseries
More informationIt is often useful to approximate complicated functions using simpler ones. We consider the task of approximating a function by a polynomial.
Taylor Polyomials ad Taylor Series It is ofte useful to approximate complicated fuctios usig simpler oes We cosider the task of approximatig a fuctio by a polyomial If f is at least -times differetiable
More informationRiemann Integral Oct 31, such that
Riem Itegrl Ot 31, 2007 Itegrtio of Step Futios A prtitio P of [, ] is olletio {x k } k=0 suh tht = x 0 < x 1 < < x 1 < x =. More suitly, prtitio is fiite suset of [, ] otiig d. It is helpful to thik of
More information9.5. Alternating series. Absolute convergence and conditional convergence
Chpter 9: Ifiite Series I this Chpter we will be studyig ifiite series, which is just other me for ifiite sums. You hve studied some of these i the pst whe you looked t ifiite geometric sums of the form:
More informationINSTRUCTOR: CEZAR LUPU. Problem 1. a) Let f(x) be a continuous function on [1, 2]. Prove that. nx 2 lim
WORKSHEET FOR THE PRELIMINARY EXAMINATION-REAL ANALYSIS (RIEMANN AND RIEMANN-STIELTJES INTEGRAL OF A SINGLE VARIABLE, INTEGRAL CALCULUS, FOURIER SERIES AND SPECIAL FUNCTIONS INSTRUCTOR: CEZAR LUPU Problem.
More informationb a 2 ((g(x))2 (f(x)) 2 dx
Clc II Fll 005 MATH Nme: T3 Istructios: Write swers to problems o seprte pper. You my NOT use clcultors or y electroic devices or otes of y kid. Ech st rred problem is extr credit d ech is worth 5 poits.
More informationA GENERAL METHOD FOR SOLVING ORDINARY DIFFERENTIAL EQUATIONS: THE FROBENIUS (OR SERIES) METHOD
Diol Bgoo () A GENERAL METHOD FOR SOLVING ORDINARY DIFFERENTIAL EQUATIONS: THE FROBENIUS (OR SERIES) METHOD I. Itroductio The first seprtio of vribles (see pplictios to Newto s equtios) is ver useful method
More information5. Solving recurrences
5. Solvig recurreces Time Complexity Alysis of Merge Sort T( ) 0 if 1 2T ( / 2) otherwise sortig oth hlves mergig Q. How to prove tht the ru-time of merge sort is O( )? A. 2 Time Complexity Alysis of Merge
More information1.3 Convergence Theorems of Fourier Series. k k k k. N N k 1. With this in mind, we state (without proof) the convergence of Fourier series.
.3 Covergece Theorems of Fourier Series I this sectio, we preset the covergece of Fourier series. A ifiite sum is, by defiitio, a limit of partial sums, that is, a cos( kx) b si( kx) lim a cos( kx) b si(
More informationAdditional Notes on Power Series
Additioal Notes o Power Series Mauela Girotti MATH 37-0 Advaced Calculus of oe variable Cotets Quick recall 2 Abel s Theorem 2 3 Differetiatio ad Itegratio of Power series 4 Quick recall We recall here
More informationPOINTWISE ASYMPTOTICS FOR ORTHONORMAL POLYNOMIALS AT THE ENDPOINTS OF THE INTERVAL VIA UNIVERSALITY
POINTWISE ASYMPTOTICS FOR ORTHONORMAL POLYNOMIALS AT THE ENDPOINTS OF THE INTERVAL VIA UNIVERSALITY D S LUBINSKY A We show tht uiverslity its d bouds for orthoorml polyomils imply poitwise symptotics for
More informationA NOTE ON SPECTRAL CONTINUITY. In Ho Jeon and In Hyoun Kim
Korea J. Math. 23 (2015), No. 4, pp. 601 605 http://dx.doi.org/10.11568/kjm.2015.23.4.601 A NOTE ON SPECTRAL CONTINUITY I Ho Jeo ad I Hyou Kim Abstract. I the preset ote, provided T L (H ) is biquasitriagular
More informationChapter 2 Infinite Series Page 1 of 9
Chpter Ifiite eries Pge of 9 Chpter : Ifiite eries ectio A Itroductio to Ifiite eries By the ed of this sectio you will be ble to uderstd wht is met by covergece d divergece of ifiite series recogise geometric
More information10.5 Power Series. In this section, we are going to start talking about power series. A power series is a series of the form
0.5 Power Series I the lst three sectios, we ve spet most of tht time tlkig bout how to determie if series is coverget or ot. Now it is time to strt lookig t some specific kids of series d we will evetully
More informationNotes on Dirichlet L-functions
Notes o Dirichlet L-fuctios Joth Siegel Mrch 29, 24 Cotets Beroulli Numbers d Beroulli Polyomils 2 L-fuctios 5 2. Chrcters............................... 5 2.2 Diriclet Series.............................
More information