Probabilistic Reasoning. Doug Downey, Northwestern EECS 348 Spring 2013
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1 Probabilistic Reasoning Doug Downey, Northwestern EECS 348 Spring 2013
2 Limitations of logic-based agents Qualification Problem Action s preconditions can be complex Action(Grab, t) => Holding(t).unless gold is slippery or nailed down or too heavy or our hands are full or Brittleness One contradiction in KB => KB entails everything
3 Limitations of logic-based agents Qualification Problem Action s preconditions can be complex Action(Grab, t) => Holding(t).unless gold is slippery or nailed down or too heavy or our hands are full or Brittleness P(success) = 0.97 One contradiction in KB => KB entails everything Instead of a a, P(a) + P( a) = 1
4 Event space Events E.g. for dice, = {1, 2, 3, 4, 5, 6} Set of measurable events S 2 E.g., = event we roll an even number = {2, 4, 6} S S must: Contain the empty event and the trivial event Be closed under union & complement, S S and S - S
5 Probability Distributions Can visualize probability as fraction of area
6 Probability Distributions A probability distribution P over (, S) is a mapping from S to real values such that: P( ) 0 P( ) = 1, S = P( ) = P( ) + P( )
7 Probability: Interpretations & Interpretations Frequentist Bayesian/subjective Motivation Why use probability for subjective beliefs? Beliefs that violate the axioms can lead to bad decisions regardless of the outcome [de Finetti, 1931] Example: P(A) = 0.6, P(not A) = 0.8? Example: P(A) > P(B) and P(B) > P(A)?
8 Random Variables A random variable is a function from to a value A short-hand for referring to attributes of events. E.g., your grade in this course Let = set of possible scores on hmwks and test Cumbersome to have separate events GradeA, GradeB, GradeC So instead define a random variable Grade Deterministic function from to {A, B, C}
9 Distributions P(Intelligence) High Low P(Grade) A B C Called marginal because they apply to only one r.v.
10 Joint Distribution P(Intelligence, Grade) Grade=A Grade=B Grade=C Intelligence=Low Intelligence=High
11 Joint Distribution Grade Intelligence Low High A B C Joint Distribution specified with 2*3 1 = 5 values
12 Joint Distribution Grade Intelligence Low High A B C P(Grade = A, Intelligence = Low)? 0.07
13 Joint Distribution Grade Intelligence Low High A B C P(Grade = A)? = 0.25
14 Joint Distribution Grade Intelligence Low High A B C P(Grade = A Intelligence = High)? = 0.37 => Given the joint distribution, we can compute probabilities for any proposition by summing events.
15 Conditional Probability P(Grade = A Intelligence = High) = 0.6 the probability of getting an A given only Intelligence = High, and nothing else. If we know Motivation = High or OtherInterests = Many, the probability of an A changes even given high Intelligence Formal Definition: P( ) = P(, ) / P( ) When P( ) > 0
16 Conditional Probability Grade Intelligence Low High A B C P(Grade = A Intelligence = High)? P(Grade = A, Intelligence = High) = 0.18 P(Intelligence = High) = = 0.30 => P(Grade = A Intelligence = High) = 0.18/0.30 = 0.6
17 Conditional Probability Grade Intelligence Low High A B C P(Intelligence Grade = A)? Intelligence Low High
18 Conditional Probability Grade Intelligence Low High A B C P(Intelligence Grade)? Actually three separate distributions, one for each Grade value (has three independent parameters total)
19 Chain Rule E.g., P(Grade=B, Int. = High) = P(Grade=B Int.= High)P(Int. = High) Can be used for distributions P(A, B) = P(A B)P(B)
20 Queries Given subsets of random variables Y and E, and assignments e to E Find P(Y E = e) Answering queries = inference The whole point of probabilistic models, more or less P(Disease Symptoms) P(StockMarketCrash RecentPriceActivity) P(CodingRegion DNASequence) P(PlayTennis Weather) (the other key task is learning)
21 Answering Queries: Summing Out Grade Intelligence = Low Intelligence=High Time=Lots Time=Little Time=Lots Time=Little A B C P(Grade Time = Lots)? v Val Intelligen P Grade, Intelligen ce v ce Time Lots
22 Answering Queries: Solved? Given the joint distribution, we can answer any query by summing but, joint distribution of 500 Boolean variables has 2^500-1 parameters (about 10^150) For non-trivial problems (~25 boolean r.v.s or more), using the joint distribution requires Way too much computation to compute the sum Way too many observations to learn the parameters Way too much space to store the joint distribution
23 Conditional Independence (1 of 3) Independence P(A, B) = P(A)*P(B), denoted A B E.g. consecutive dice rolls Gambler s fallacy Rare in (real) applications
24 Conditional Independence (2 of 3) Conditional Independence P(A, B C) = P(A C) P (B C), denoted (A B C) Much more common E.g., (GetIntoNU GetIntoStanford Application), but NOT (GetIntoNU GetIntoStanford)
25 Conditional Independence (3 of 3) How does Conditional Independence save the day? P(NU, Stanford, App) = P(NU Stanford, App)*P(Stanford App)*P(App) Now, (A B C) means P(A B, C) = P(A C) So since (NU Stanford App), we have P(NU, Stanford, App) = P(NU App)*P(Stanford App)*P(App) Say App {Good, Bad} and School {Yes, No, Wait} All we need is 4+4+1=9 numbers (vs. 3*3*2-1=17 for the full joint) Full joint has size exponential in # of r.v.s Conditional independence eliminates this!
26 Bayes Rule P(A B) = P(B A) P(A) / P(B) Example: P(symptom disease) = 0.95, P(symptom disease) = 0.05 P(disease = ) P(disease symptom) = P(symptom disease)*p(disease) P(symptom) = 0.95* = * *0.9999
27 What have we learned? Probability a calculus for dealing with uncertainty Built from small set of axioms (ignore at your peril) Joint Distribution P(A, B, C, ) Specifies probability of all combinations of r.v.s Intractable to compute exhaustively for non-trivial problems Conditional Probability P(A B) Specifies probability of A given B Conditional Independence Can radically reduce number of variable combinations we must assign unique probabilities to. Bayes Rule
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