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1 HEIGHTS AND DISTANCES 1. If te angle of elevation of cloud from a point meters aove a lake is and te angle of depression of its reflection in te lake is cloud is., prove tat te eigt of te Ans : If te angle of elevation of cloud from a point n meters aove a lake is and te angle of depression of its reflection in te lake is β, prove tat te eigt of te tan β + tanα cloud is tan β tanα Let AB e te surface of te lake and Let p e an point of oservation suc tat AP meters. Let c e te position of te cloud and c e its reflection in te lake. Ten CPM and MPC 1 β. Let CM x. Ten, CB CM + MB CM + PA x + CM In CPM, we ave tan PM x tan AB [ PM AB] AB x cot In PMC, we ave C' M tanβ PM..1 x + 2 tanβ [Θ C MC B+BM x + + n] AB AB (x + 2) cot β From 1 & 2 x cot (x + 2) cot β 49
2 x (cot - cot β) 2 cot β (on equating te values of AB) tan β tanα 2 x x tanα tan β tan β tanα + tan β tan β 2 tanα x tan β tanα Hence, te eigt CB of te cloud is given y CB is given y CB x + 2 tanα CB + tan β tanα 2 tanα + tan β tanα (tanα + tan β ) CB- tan β tanα tan β tanα 2. From an aero plane vertically aove a straigt orizontal road, te angles of depression of two consecutive milestones on opposite sides of te aero plane are oserved to e α and β. Sow tat te eigt of te aero plane aove te road is. Let P Q e QB e x Given : AB 1 mile QB x AQ (1- x) mile in PAQ PQ Tan α AQ Tan α 1 x 1 x Tanα.1 In PQB Tan β x x Tanβ Sustitute for x in equation (1) 1 + Tanβ Tanα 50
3 Tanβ Tanα 1 Tan β + Tanα TanβTanα. Two stations due sout of a tower, wic leans towards nort are at distances a and from its foot. If α and β e te elevations of te top of te tower from te situation, prove tat its inclination θ to te orizontal given y Let AB e te leaning tower and C and D e te given stations. Draw BL DA produced. Ten, BAL 0, BCA α, BDC a and DA. Let AL x and BL In rigt ALB, we ave : AL x Cot θ Cot θ BL x Cot θ x cot θ..(i) In rigt BCL, we ave : CL Cot α a + x cot α BL a (cot α - cot θ) a (cotα cotθ )...(ii) In rigt BDL, we ave : DL DA + cot β cot β BL BLAL + x cot β + x cot β ((cot β - cot θ) (cot β cotθ ) [using (i)]..(iii) equating te value of in (ii) and (iii), we get: a (cotα cotθ ) (cot β cotθ ) 51
4 a cot β - a cot θ cot α - cot θ ( a) cot θ cot α - a cotβ cotα a cot βθ cot θ ( a) 4. Te angle of elevation of te top of a tower from a point on te same level as te foot of te tower is α. On advancing p meters towards te foot of te tower, te angle of elevation ecomes β. sow tat te eigt of te tower is given y 5. A oy standing on a orizontal plane finds a ird flying at a distance of 100m from im at an elevation of 0 0. A girl standing on te roof of 20 meter ig uilding finds te angle of elevation of te same ird to e Bot te oy and te girl are on opposite sides of te ird. Find te distance of te ird from te girl. ( 42.42m) In rigt ACB AC Sin 0 AB 1 AC AC 100 AC 50m AF (50 20) 0m In rigt AFE AF Sin 45 AE AE AE x m 6. From a window x meters ig aove te ground in a street, te angles of elevation and depression of te top and te foot of te oter ouse on te opposite side of te street are α and β respectively. Sow tat te eigt of te opposite ouse is Meters. Let AB e te ouse and P e te window Let BQ x PC x Let AC a 52
5 PQ In PQB, tan θ or tan θ QB x x cot θ tanθ AC a In PAC, tan θ or tan θ PC x a x tan θ > ( cot θ) tan θ tan θ cot θ. te eigt of te tower AB AC + BC a + tan θ cot θ + (tanθ cot θ + 1) 7. Two sips are sailing in te sea on eiter side of a ligtouse; te angles of depression of two sips as oserved from te top of te ligtouse are 60 0 and 45 0 respectively. If te distance etween te sips is meters, find te eigt of te ligtouse. (200m) In rigt ABC Tan 60 BC BC H BC In rigt ABD Tan 45 BD BD BC + BD 200 BC + BC 200 BC 200( ( 1+ ) 1+ BC m eigt of ligt ouse 200m 5
6 8. A round alloon of radius a sutends an angle θ at te eye of te oserver wile te angle of elevation of its centre is Φ. Prove tat te eigt of te center of te alloon is a sin θ cosec Φ /2. Let θ e te centre of te allon of radius r and p te eye of te oserver. Let PA, PB e tangents from P to allong. Ten APB θ. APO BPO 2 θ Let OL e perpendicular from O on te orizontal PX. We are given tat te angle of te elevation of te centre of te allon is φ i.e., OPL φ θ OA In OAP, we ave sin 2 OP θ a sin 2 OP θ OP a cosec 2 OL In OP L, we ave sinφ OP OL OP sin φ a cosec 2 φ sin θ. Hence, te eigt of te center of te alloon is a sin θ cosec Φ /2. 9. Te angle of elevation of a jet figter from a point A on te ground is After a fligt of 15 seconds, te angle of elevation canges to 0 0. If te jet is flying at a speed of 720 km/r, find te constant eigt at wic te jet is flying.(use 1.72 ( 2598m) 6 km / r 10m / sec 720 km / 10 x Speed 200 m/s Distance of jet from AE speed x time 200 x m tan 60 o AC oppositeside BC adjacentside AC BC BC AC 54
7 AC ED (constant eigt) BC ED.1 tan 0 o ED oppositeside BC + CD adjacentside 1 ED BC BC ED BC BC (from equation 1) BC BC BC BC BC 000 BC BC 1500 m ED BC (from equation 1) x 1.72 ED 2598m Te eigt of te jet figter is 2598m. 10. A vertical post stands on a orizontal plane. Te angle of elevation of te top is 60 o and tat of a point x metre e te eigt of te post, ten prove tat Self Practice 2 x. 11. A fire in a uilding B is reported on telepone to two fire stations P and Q, 10km apart from eac oter on a straigt road. P oserves tat te fire is at an angle of 60 o to te road and Q oserves tat it is an angle of 45 o to te road. Wic station sould send its team and ow muc will tis team ave to travel? (7.2km) Self Practice 12. A ladder sets against a wall at an angle α to te orizontal. If te foot is pulled away from te wall troug a distance of a, so tat is slides a distance down te wall cosα cos β a making an angle β wit te orizontal. Sow tat. sin β sinα Let CB x m. Lengt of ladder remains same 55
8 CB Cos α CA x Cos α x cos α ED AC Let Ed e ED AC (1) DC + CB cos β ED a + x cos β a + x cos β x cos β a (2) from (1) & (2) cos α cos β - a cos α - cos β - a -a (cosα - cosβ)...() AE + EB Sin α AC + EB Sin α Sin α EB EB Sin α...(4) EB Sin β DE EB Sin β EB Sin β From (4) & (5) (5) Sin β Sin α sin α Sin β - (Sin β - Sin α)...(6) Divide equation () wit equation (6) a (cosα cos β ) (sin β Sinα) a Cosα Cosβ Sinβ Sinα 56
9 1. Two stations due sout of a leaning tower wic leans towards te nort are at distances a and from its foot. If α, β e te elevations of te top of te tower cotα acot β from tese stations, prove tat its inclination ϕ is given y cotϕ. a Let AE x, BE BE Tan φ AE x 1 x x tanφ x cot φ BE tan α CE a + x a + x cot α x cot α - a BE tan β DE + x +x cot β x cot β from 1 and 2 cot φ cot α - a ( cot φ + cot α ) a a cot φ + cotα from 1 and cot φ cot β - ( cot φ - cot β) cot φ + cot β from 4 and 5 a cot φ + cotα cot φ + cot β a (cot β - cot φ ) ( cot α - cot φ ) - a cot φ + cot φ cot α - a cot β ( a) cot φ cot α - a cot β 57
10 cot α - a cot β cot φ a 14. In Figure, wat are te angles of depression from te oserving positions O 1 and O 2 of te oject at A? Self Practice ( 0 o,45 o ) 15. Te angle of elevation of te top of a tower standing on a orizontal plane from a point A is α. After walking a distance d towards te foot of te tower te angle d of elevation is found to e β. Find te eigt of te tower. ( ) cotα cot β Let BC x AB tan β CB tan β x x tan β x cot β (1) AB tan α DC + CB tan α d + x d + x cotα tan α x cot α - d (2) from 1 and 2 cot β cot α - d (cot α - cot β ) d d cot α cot β 58
11 16. A man on a top of a tower oserves a truck at an angle of depression α were 1 tanα and sees tat it is moving towards te ase of te tower. Ten minutes 5 later, te angle of depression of te truck is found to e β were tan β 5, if te truck is moving at a uniform speed, determine ow muc more time it will take to reac te ase of te tower minutes600sec A Let te speed of te truck e x m/sec CDBC-BD In rigt triangle ABC tanα BC 1 tanα 5 BC 5. 1 In rigt triangle ABD tanβ BD C α D β B 5BD ( tan β 5 ) CDBC-BD ( CD600x ) 600x 5BD-BD BD150x 150x Time taken x 150 seconds Time taken y te truck to reac te tower is 150 sec. 59
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