radians A function f ( x ) is called periodic if it is defined for all real x and if there is some positive number P such that:
|
|
- Gertrude Baker
- 5 years ago
- Views:
Transcription
1 Fourier Series. Graph of y Asix ad y Acos x Amplitude A ; period 36 radias. Harmoics y y six is the first harmoic y y six is the th harmoics 3. Periodic fuctio A fuctio f ( x ) is called periodic if it is defied for all real x ad if there is some positive umber P such that: f ( x) f ( x+ P) ; P period. A Fourier series is a represetatio employed to express periodic fuctio f ( x ) defied i a iterval, say (, ) a liear relatio betwee the sies ad cosies of the same period. 5. Fourier series for fuctios of period is give by, f ( x) a + acosx+ acosx+ a3cos3x+ + a cosx + + b six+ b six+ b si3x+ + b six + 3 a + { a cosx+ b si x} where the value of the coefficiets a, a ad b are determied by, a f ( xdx ) mea value of f ( x ) over a period. a f ( x)cos xdx mea value of f ( x)cos x over a period b f( x)sixdx mea value of f ( x)six over a period
2 It ca also be expressed i compoud sie terms f ( x) a + c si( x α ) + a where c a + b ad α arcta b 6. he Fourier series expasio ad the determiatio of Fourier s costats is valid uder the assumptio that the give periodic fuctio f ( x ) satisfy the Dirichlet s coditios. his is to esure that the sum o the R.H.S. has a limit as ad, is equal to f ( x ) at ay poit x whe f ( x ) beig cotiuous, ad is equal to ( ) ( ) f x f x + whe there is a fiite discotiuity at the poit x. 7. Dirichlet coditios (a) he fuctio f ( x ) must be defied ad sigle-valued. (b) f ( x ) must be cotiuous or have a fiite umber of fiite discotiuities withi a period iterval. (c) f ( x ) ad f '( x ) must be piecewise cotiuous i the periodic iterval. 8. Sum of Fourier series (a) at ay cotiuous poit, x Let f ( x) y, the at x x, Fourier series of f ( x ) coverge to the value f ( x) y. (b) at a fiite discotiuity, x + + Let f ( x ) y ad f ( x+ ) y, he at x x, Fourier series for f ( x ) coverges to the value { f( x ) + + f( x + )} + ( y + y).
3 9. Odd ad eve fuctios (a) Eve fuctio: (i) f ( x) f ( x) (ii) the graph is symmetric about y axis (iii) (b) Odd fuctio: a a a f( xdx ) f( xdx ) (i) f ( x) f ( x) (ii) the graph is symmetric about origi. a (iii) f ( xdx ) a Product of odd ad eve fuctios (eve) (eve) (eve) (eve) (odd) (odd) (odd) (eve) (odd) (odd) (odd) (eve).. Sie series ad cosie series If f ( x ) is eve, the series cotais cosie terms oly (icludig a ) For example, give a periodic eve fuctio with period, the Fourier series is as followig, f ( x) a + a cosx b six + where a f ( x) dt a f( x)cos tdt b
4 If f ( x ) is odd, the series cotais sie terms oly. For example, give a periodic odd fuctio with period, the Fourier series is as followig, f ( x) a + a cosx b six + where a a b f( x)sixdx. Half-rage series period For a fuctio f ( x ) of period, defied over the rage to, ca be cosidered as half of a eve fuctio, or half of a odd fuctio. (a) Whe we cosidered it as half of a eve fuctio, the it ca be represeted as halfrage cosie series, f ( x) a a cosx + where a f( x) dx a f( x)cos xdx
5 (b) Whe we cosidered it as half of a odd fuctio, the it ca be represeted as half-rage sie series, f ( x) b six where b f( x)sixdx. Series cotaiig oly odd harmoics or oly eve harmoics If f ( x) f ( x+ ) the Fourier series cotais eve harmoics oly. If f ( x) f( x+ ) the Fourier series cotais odd harmoics oly. 3. Liearity Property If f ( x) gx ( ) + hx ( ), where gx ( ) ad hx ( ) are periodic fuctios of period, with Fourier expasio: gx ( ) a cos si + a x + b x hx ( ) α cosx six + α + β the Fourier series for f ( x ) is give by, f ( x) ( a + α ) + ( a α )cos x ( b β )six + + +
6 . Fourier series for periodic fuctios f (t) with period f () t a + { a cosωt b si ωt} + a f () t dt ω ω f() t dt a f ()cos t ωtdt ω ω f()cos t ω tdt b f()si t ω tdt ω ω f()si t ω tdt where ω i.e. ω 5. Fourier series for eve fuctio ad odd fuctio. Half-rage series period f () t a + { a cosωt b si ωt} + (a) For Eve fuctio or half-rage cosie series a / f () t dt / a f ()cos t ωtdt b
7 (b) For odd fuctio or half-rage sie series a a / b f()si t ω tdt
8 Example (Fourier Series) Example Let f ( x ) be a periodic fuctio with period defie as followig: ( ) ( ) ( + ) f x x,if < x<, f x f x. Expad f ( x ) i a Fourier series. Solutio Fourier series, [figure] f ( x) a + a cosx+ bsi x Let fid the a first, d + ( ) a f x dx, where i this case, we choose d. (Why?) d f ( x) dx xdx x. he, fid a, where,,3,. d + a f ( x) cosxdx xcos xdx d xsix si x d x, use itegratio by parts here xsix cos x + ( ) ( ) ( ) ( ) ( ) si cos si cos +
9 he, fid b, where,,3, d + b f ( x) sixdx xsi xdx d cosx cos x x d x, use itegratio by parts here xcosx si x + ( ) ( ) ( ) ( ) cos si cos si + +. ( ) Fially, substitute a,, a b ito the Fourier series, f ( x) a + a cosx+ bsi x ( ) + ( cos ) x+ si x si x six+ six+ si3x+ six+ 3 Example Fid Fourier series for f ( ) Solutio ( ) ( + ) x, where x,if < x<, f ( x) + x,if < x <, f x f x. [figure] From the graph, ca be observed that the graph is symmetric respected to y -axis, so f ( x ) is a eve fuctio. he, the Fourier series expasio of f ( ) x oly cotai
10 costat ad cosie terms (sice it is a eve fuctio), which is havig the followig structure, f ( x) a + a cos x. Let fid the a first, a f ( x) dx f ( x) dx ( x) dx x x. he, fid a, where,,3,. a f ( x) cosxdx ( x) cosxdx ( x) si x si x d x, use itegratio by parts here ( ) x si x cos x + cos ( ) ( ) ( ) ( ) si( ) cos( ) si( ) cos( ) ( ( )),if is odd ( ( + )),if is eve,if is odd a,if is eve Fially, substitute a, a ito the Fourier series,
11 f ( x) a + a cos x a + acosx+ acosx+ a3cos3x+ acosx+ + cosx+ ( cos ) x+ cos3x+ ( cos ) x+ 3 cosx+ cos3x+ cos5x+ cos7x Example 3 Give a periodic fuctio f ( x ) defied as Solutio,if < x <, f ( x),if < x <, f x f x. ( ) ( + ) [figure] From the graph, ca be observed that the graph is symmetric respected to origi, so f ( x ) is a odd fuctio. he, the Fourier series expasio of f ( x ) oly cotai sie terms (sice it is a odd fuctio), which is havig the followig structure, ( ) f x b si x, where,,3,. b f ( x) sixdx ( si ) xdx cosx cos cos + ( ) ( ) cos ( ) ( ( )),if is odd ( ( + )),if is eve
12 ,if is odd b,if is eve Fially, substitute b ito the Fourier series, ( ) f x b si x b six+ b six+ b si3x+ b six+ 3 six+ ( si ) x+ si3x+ ( si ) x+ 3 six+ si3x+ si5x+ si7x Example Fid Fourier series for f ( x ), where Solutio,if < x <, f ( x),if < x<,,if < x <, f x f x. ( ) ( + ) [figure] From the graph, ca be observed that the graph is symmetric respected to y -axis, so f ( x ) is a eve fuctio. he, the Fourier series expasio of f ( ) x oly cotai costat ad cosie terms (sice it is a eve fuctio), which is havig the followig structure, f ( x) a + a cos x. First, fid the a,
13 a f ( x) dx ( d ) x ( d ) x +. he, fid a, where,,3,. a f ( x) cosxdx ( cos ) xdx ( cos ) xdx + 8 si x 8 si si ( ) 8 ( ),if,5,9,3, 8 ( ),if 3,7,,5, 8 ( ),if is eve 8,if,5,9,3, 8 a,if 3,7,,5,,if is eve Fially, substitute a, a ito the Fourier series, f ( x) a + a cos x a + acosx+ acosx+ a3cos3x+ acosx+ a5cos5x ( ) + cosx+ ( cos ) x+ cos3x+ ( cos ) x+ cos5x cosx cos3x+ cos5x cos7x+ cos9x cosx
14 Example 5 (Liearity property of Fourier Series) Use the aswer from example ad the liearity property of Fourier series, write the g x is a periodic Fourier series expasio of the periodic fuctio g( x ). Give that ( ) fuctio with period, ad it s graph from < x < is as followig figure, Solutio he graph of f ( ) [figure] x i example is as followig: [figure] From the graph of g( x ) ad f ( x ), ca be observed that ( ) shifted dow uit of f ( x ) vertically. Mathematical, this meas that, g( x) f ( x) he, Fourier series of g( x ) ca be obtaied by the liearity properties, F { g( x) } F { f ( x) } F f ( x) + F { } { } g x ca be obtaied by 8 + cosx cos3x+ cos5x cos7x cosx cos3x+ cos5x cos7x Example 6 (Liearity Property) Give a periodic fuctio f ( x ) defie by,,< x < f ( x), < x < f x f x ( ) ( + ) (a) Sketch f ( x ) for < x <. (b) By subtractig the fuctio f ( x ) by uit (that is, by shiftig the graph of f ( x ) vertically dowward by uit), a odd fuctio is obtaied. Deoted the shirted g x. fuctio as ( ) Expad the shifted fuctio, g( x ) i a Fourier series.
15 (c) Hece, write the Fourier series for f ( x ) based o the liearity property of Solutio Fourier series. (a) (b) [figure] [figure] Sice the graph of g( x ) is symmetric respected to origi, this mea that ( ) a odd fuctio, therefore, the Fourier series expasio of g( x ) oly cotais sie terms oly ad havig the followig structure, ( ) g x b si x, where,,3,. b g( x) sixdx ( si ) xdx ( ) ( ) cosx cos cos + cos ( ) ( ( )),if is odd ( ( + )),if is eve,if is odd b,if is eve Fially, substitute b ito the Fourier series, ( ) g x b si x b six+ b six+ b si3x+ b six+ 3 six+ ( si ) x+ si3x+ ( si ) x+ 3 g( x) six+ si3x+ si5x+ si7x g x is
16 (b) Sice the graph of g( x ) ca be obtaied from f ( ) dowward, this mea, mathematically, the relatio for f ( x ) ad ( ) ( ) ( ) ( ) ( ) g x f x f x g x + By the liearity property, F { f ( x) } F g( x) F g( x) { } { } F { } + + x by shifted uit vertically g x is, six+ si3x+ si5x+ si7x f ( x) + six+ si3x+ si5x+ si7x Example: A fuctio f ( ) f ( x) x is defied by x,< x< 8 x, < x < 8 Show that the half-rage sie series for f ( ) f 3 x si si 8 ( x) x over the iterval [,8] is Solutio Half rage sie series of f ( x ), ( ) si ω, where ( ) f x b x b f x siω xdx, ω he half period, 8, 6, so, ω x b f ( x) si xdx f ( x) si dx ω 6 8 x 8 x xsi dx ( 8 x) si dx I + J
17 8 x 8 x I x cos cos dx x 8 8 x x cos si cos + si + ( )( ) ( ) si ( ) 8 6 cos + si ( ) 8 8 x 8 8 x J ( 8 x) cos cos ( dx) x 8 8 x ( 8 x) cos si ( )( ) ( ) si( ) cos + si ( ) 8 6 cos + si b I + J 3 si ( ) ( ) cos + si cos si + + ( ) ( ) Half rage sie series of f ( x ), ( ) f x b si ω x 3 si si ωx, ω 8 3 ( ) x si si ( Show ). 8 8
18 Example Give a periodic fuctio defied by si x, < x<, f ( x) si x, < x <, f x f x+. ( ) ( ) Expad f ( x ) i a Fourier series. Solutio [figure] Observed that the graph is symmetric respected to y -axis, so f ( x ) is a eve fuctio. he, the Fourier series expasio of f ( x ) oly cotai costat ad cosie terms (sice it is a eve fuctio), which is havig the followig structure, f ( x) a + a cos x. First, fid the a, a f ( x) dx sixdx [ cos x]. he, fid a, where,,3,. a f ( x) cosxdx sixcosxdx six si x six ( cosxdx) cosx cos x ( ) + cosx ( sixdx) + ( cos ) + sixcosxdx cos ( ) + a
19 a ( cos ) a si x ( cos ) ( ),if is eve, ( )( ) + ( ( ) ),if is odd,, ( + )( ),if is eve, a ( )( ) +,if is odd,, a sixcosxdx Fially, substitute a, a, a (where ) ito the Fourier series, f ( x) a + a cos x a + acosx+ acosx+ a3cos3x+ acosx+ a5cos5x+ + ( ) + cosx+ ( ) + cosx+ ( cos5 ) x cosx+ cosx+ cos6x+ cos8x
20 Fourier Series Exercises. Determie the Fourier series for the fuctio defied by f(x) x ; for ( < x < ) f(x) f(x + ).. State whether each of the followig products is odd, eve, or either. Assume that all the fuctios are defied over < x <. (a) x 3 cos x (b) x si 3x (c) si x si 3x (d) x e x (e) (x + 5) cos x (f) si x cos x 3. A fuctio f(x) is defied by f(x) x f(x) f(x + ). ; for < x < Express the fuctio (a) as a half-rage cosie series, (b) as a half-rage sie series.. A fuctio f(t) is defied by f(t) ; for < t < f(t) t ; for < t < f(t) f(t + ). Determie its Fourier series. 5. A periodic fuctio f(x) is defied by f(x) x ; for ( < x < ) f(x) f(x + ). Determie the Fourier series up to ad icludig the third harmoics.
21 6. Determie the Fourier series represetatio of the fuctio f(x) defied by f(t) 3 ; for ( < t < ) f(t) 5 ; for ( < t < ) f(t) f(t + ). 7. Determie the half-rage cosie series for the fuctio f(x) si x defied i the rage < x <. 8. A fuctio is defied by f(x) + x ; for ( < x < ) f(x) x ; for ( < x < ) f(x) f(x + ). Obtai the Fourier series. 9. A periodic fuctio is defied by f(x) A si x ; for ( < x < ) f(x) A si x ; for ( < x < ) f(x) f(x + ). Determie its Fourier series up to ad icludig the fourth harmoic.. Determie the Fourier series to represet a half-wave rectifier output curret, i amperes, defied by i f(t) A si ωt ; for ( < t < ) f(t) ; for ( < t < ) f(t) f(t + ).
Fourier Series and their Applications
Fourier Series ad their Applicatios The fuctios, cos x, si x, cos x, si x, are orthogoal over (, ). m cos mx cos xdx = m = m = = cos mx si xdx = for all m, { m si mx si xdx = m = I fact the fuctios satisfy
More informationChapter 6 Infinite Series
Chapter 6 Ifiite Series I the previous chapter we cosidered itegrals which were improper i the sese that the iterval of itegratio was ubouded. I this chapter we are goig to discuss a topic which is somewhat
More informationSignal Processing in Mechatronics. Lecture 3, Convolution, Fourier Series and Fourier Transform
Sigal Processig i Mechatroics Summer semester, 1 Lecture 3, Covolutio, Fourier Series ad Fourier rasform Dr. Zhu K.P. AIS, UM 1 1. Covolutio Covolutio Descriptio of LI Systems he mai premise is that the
More informationCHAPTER 5: FOURIER SERIES PROPERTIES OF EVEN & ODD FUNCTION PLOT PERIODIC GRAPH
CHAPTER : FOURIER SERIES PROPERTIES OF EVEN & ODD FUNCTION POT PERIODIC GRAPH PROPERTIES OF EVEN AND ODD FUNCTION Fuctio is said to be a eve uctio i: Fuctio is said to be a odd uctio i: Fuctio is said
More informationChapter 4. Fourier Series
Chapter 4. Fourier Series At this poit we are ready to ow cosider the caoical equatios. Cosider, for eample the heat equatio u t = u, < (4.) subject to u(, ) = si, u(, t) = u(, t) =. (4.) Here,
More informationPLEASE MARK YOUR ANSWERS WITH AN X, not a circle! 1. (a) (b) (c) (d) (e) 3. (a) (b) (c) (d) (e) 5. (a) (b) (c) (d) (e) 7. (a) (b) (c) (d) (e)
Math 0560, Exam 3 November 6, 07 The Hoor Code is i effect for this examiatio. All work is to be your ow. No calculators. The exam lasts for hour ad 5 mi. Be sure that your ame is o every page i case pages
More informationFourier Series and the Wave Equation
Fourier Series ad the Wave Equatio We start with the oe-dimesioal wave equatio u u =, x u(, t) = u(, t) =, ux (,) = f( x), u ( x,) = This represets a vibratig strig, where u is the displacemet of the strig
More informationSequences and Series of Functions
Chapter 6 Sequeces ad Series of Fuctios 6.1. Covergece of a Sequece of Fuctios Poitwise Covergece. Defiitio 6.1. Let, for each N, fuctio f : A R be defied. If, for each x A, the sequece (f (x)) coverges
More informationSUMMARY OF SEQUENCES AND SERIES
SUMMARY OF SEQUENCES AND SERIES Importat Defiitios, Results ad Theorems for Sequeces ad Series Defiitio. A sequece {a } has a limit L ad we write lim a = L if for every ɛ > 0, there is a correspodig iteger
More informationMath 12 Final Exam, May 11, 2011 ANSWER KEY. 2sinh(2x) = lim. 1 x. lim e. x ln. = e. (x+1)(1) x(1) (x+1) 2. (2secθ) 5 2sec2 θ dθ.
Math Fial Exam, May, ANSWER KEY. [5 Poits] Evaluate each of the followig its. Please justify your aswers. Be clear if the it equals a value, + or, or Does Not Exist. coshx) a) L H x x+l x) sihx) x x L
More informationSolutions to Final Exam Review Problems
. Let f(x) 4+x. Solutios to Fial Exam Review Problems Math 5C, Witer 2007 (a) Fid the Maclauri series for f(x), ad compute its radius of covergece. Solutio. f(x) 4( ( x/4)) ( x/4) ( ) 4 4 + x. Sice the
More information62. Power series Definition 16. (Power series) Given a sequence {c n }, the series. c n x n = c 0 + c 1 x + c 2 x 2 + c 3 x 3 +
62. Power series Defiitio 16. (Power series) Give a sequece {c }, the series c x = c 0 + c 1 x + c 2 x 2 + c 3 x 3 + is called a power series i the variable x. The umbers c are called the coefficiets of
More information1.3 Convergence Theorems of Fourier Series. k k k k. N N k 1. With this in mind, we state (without proof) the convergence of Fourier series.
.3 Covergece Theorems of Fourier Series I this sectio, we preset the covergece of Fourier series. A ifiite sum is, by defiitio, a limit of partial sums, that is, a cos( kx) b si( kx) lim a cos( kx) b si(
More informationMa 530 Introduction to Power Series
Ma 530 Itroductio to Power Series Please ote that there is material o power series at Visual Calculus. Some of this material was used as part of the presetatio of the topics that follow. What is a Power
More information: Transforms and Partial Differential Equations
Trasforms ad Partial Differetial Equatios 018 SUBJECT NAME : Trasforms ad Partial Differetial Equatios SUBJECT CODE : MA 6351 MATERIAL NAME : Part A questios REGULATION : R013 WEBSITE : wwwharigaeshcom
More informationMath 113, Calculus II Winter 2007 Final Exam Solutions
Math, Calculus II Witer 7 Fial Exam Solutios (5 poits) Use the limit defiitio of the defiite itegral ad the sum formulas to compute x x + dx The check your aswer usig the Evaluatio Theorem Solutio: I this
More informationx x x Using a second Taylor polynomial with remainder, find the best constant C so that for x 0,
Math Activity 9( Due with Fial Eam) Usig first ad secod Taylor polyomials with remaider, show that for, 8 Usig a secod Taylor polyomial with remaider, fid the best costat C so that for, C 9 The th Derivative
More informationMa 4121: Introduction to Lebesgue Integration Solutions to Homework Assignment 5
Ma 42: Itroductio to Lebesgue Itegratio Solutios to Homework Assigmet 5 Prof. Wickerhauser Due Thursday, April th, 23 Please retur your solutios to the istructor by the ed of class o the due date. You
More informationMath 61CM - Solutions to homework 3
Math 6CM - Solutios to homework 3 Cédric De Groote October 2 th, 208 Problem : Let F be a field, m 0 a fixed oegative iteger ad let V = {a 0 + a x + + a m x m a 0,, a m F} be the vector space cosistig
More informationMath 21B-B - Homework Set 2
Math B-B - Homework Set Sectio 5.:. a) lim P k= c k c k ) x k, where P is a partitio of [, 5. x x ) dx b) lim P k= 4 ck x k, where P is a partitio of [,. 4 x dx c) lim P k= ta c k ) x k, where P is a partitio
More information3. Z Transform. Recall that the Fourier transform (FT) of a DT signal xn [ ] is ( ) [ ] = In order for the FT to exist in the finite magnitude sense,
3. Z Trasform Referece: Etire Chapter 3 of text. Recall that the Fourier trasform (FT) of a DT sigal x [ ] is ω ( ) [ ] X e = j jω k = xe I order for the FT to exist i the fiite magitude sese, S = x [
More informationf(x)g(x) dx is an inner product on D.
Ark9: Exercises for MAT2400 Fourier series The exercises o this sheet cover the sectios 4.9 to 4.13. They are iteded for the groups o Thursday, April 12 ad Friday, March 30 ad April 13. NB: No group o
More informationMTH 142 Exam 3 Spr 2011 Practice Problem Solutions 1
MTH 42 Exam 3 Spr 20 Practice Problem Solutios No calculators will be permitted at the exam. 3. A pig-pog ball is lauched straight up, rises to a height of 5 feet, the falls back to the lauch poit ad bouces
More informationCALCULUS BASIC SUMMER REVIEW
CALCULUS BASIC SUMMER REVIEW NAME rise y y y Slope of a o vertical lie: m ru Poit Slope Equatio: y y m( ) The slope is m ad a poit o your lie is, ). ( y Slope-Itercept Equatio: y m b slope= m y-itercept=
More informationNumerical Methods in Fourier Series Applications
Numerical Methods i Fourier Series Applicatios Recall that the basic relatios i usig the Trigoometric Fourier Series represetatio were give by f ( x) a o ( a x cos b x si ) () where the Fourier coefficiets
More informationENGI Series Page 6-01
ENGI 3425 6 Series Page 6-01 6. Series Cotets: 6.01 Sequeces; geeral term, limits, covergece 6.02 Series; summatio otatio, covergece, divergece test 6.03 Stadard Series; telescopig series, geometric series,
More information19 Fourier Series and Practical Harmonic Analysis
9 Fourier Series ad Practica Harmoic Aaysis Eampe : Obtai the Fourier series of f ( ) e a i. a Soutio: Let f ( ) acos bsi sih a a a a a a e a a where a f ( ) d e d e e a a e a f ( ) cos d e cos d ( a cos
More informationWe are mainly going to be concerned with power series in x, such as. (x)} converges - that is, lims N n
Review of Power Series, Power Series Solutios A power series i x - a is a ifiite series of the form c (x a) =c +c (x a)+(x a) +... We also call this a power series cetered at a. Ex. (x+) is cetered at
More informationMAT 271 Project: Partial Fractions for certain rational functions
MAT 7 Project: Partial Fractios for certai ratioal fuctios Prerequisite kowledge: partial fractios from MAT 7, a very good commad of factorig ad complex umbers from Precalculus. To complete this project,
More informationMATH4822E FOURIER ANALYSIS AND ITS APPLICATIONS
MATH48E FOURIER ANALYSIS AND ITS APPLICATIONS 7.. Cesàro summability. 7. Summability methods Arithmetic meas. The followig idea is due to the Italia geometer Eresto Cesàro (859-96). He shows that eve if
More informationMath 105: Review for Final Exam, Part II - SOLUTIONS
Math 5: Review for Fial Exam, Part II - SOLUTIONS. Cosider the fuctio f(x) = x 3 lx o the iterval [/e, e ]. (a) Fid the x- ad y-coordiates of ay ad all local extrema ad classify each as a local maximum
More informationMH1101 AY1617 Sem 2. Question 1. NOT TESTED THIS TIME
MH AY67 Sem Questio. NOT TESTED THIS TIME ( marks Let R be the regio bouded by the curve y 4x x 3 ad the x axis i the first quadrat (see figure below. Usig the cylidrical shell method, fid the volume of
More informationAP Calculus Chapter 9: Infinite Series
AP Calculus Chapter 9: Ifiite Series 9. Sequeces a, a 2, a 3, a 4, a 5,... Sequece: A fuctio whose domai is the set of positive itegers = 2 3 4 a = a a 2 a 3 a 4 terms of the sequece Begi with the patter
More information2. Fourier Series, Fourier Integrals and Fourier Transforms
Mathematics IV -. Fourier Series, Fourier Itegrals ad Fourier Trasforms The Fourier series are used for the aalysis of the periodic pheomea, which ofte appear i physics ad egieerig. The Fourier itegrals
More information(A sequence also can be thought of as the list of function values attained for a function f :ℵ X, where f (n) = x n for n 1.) x 1 x N +k x N +4 x 3
MATH 337 Sequeces Dr. Neal, WKU Let X be a metric space with distace fuctio d. We shall defie the geeral cocept of sequece ad limit i a metric space, the apply the results i particular to some special
More informationThe z-transform. 7.1 Introduction. 7.2 The z-transform Derivation of the z-transform: x[n] = z n LTI system, h[n] z = re j
The -Trasform 7. Itroductio Geeralie the complex siusoidal represetatio offered by DTFT to a represetatio of complex expoetial sigals. Obtai more geeral characteristics for discrete-time LTI systems. 7.
More informationTR/46 OCTOBER THE ZEROS OF PARTIAL SUMS OF A MACLAURIN EXPANSION A. TALBOT
TR/46 OCTOBER 974 THE ZEROS OF PARTIAL SUMS OF A MACLAURIN EXPANSION by A. TALBOT .. Itroductio. A problem i approximatio theory o which I have recetly worked [] required for its solutio a proof that the
More informationSOLUTIONS TO EXAM 3. Solution: Note that this defines two convergent geometric series with respective radii r 1 = 2/5 < 1 and r 2 = 1/5 < 1.
SOLUTIONS TO EXAM 3 Problem Fid the sum of the followig series 2 + ( ) 5 5 2 5 3 25 2 2 This series diverges Solutio: Note that this defies two coverget geometric series with respective radii r 2/5 < ad
More informationA) is empty. B) is a finite set. C) can be a countably infinite set. D) can be an uncountable set.
M.A./M.Sc. (Mathematics) Etrace Examiatio 016-17 Max Time: hours Max Marks: 150 Istructios: There are 50 questios. Every questio has four choices of which exactly oe is correct. For correct aswer, 3 marks
More informationIt is often useful to approximate complicated functions using simpler ones. We consider the task of approximating a function by a polynomial.
Taylor Polyomials ad Taylor Series It is ofte useful to approximate complicated fuctios usig simpler oes We cosider the task of approximatig a fuctio by a polyomial If f is at least -times differetiable
More informationf(x) dx as we do. 2x dx x also diverges. Solution: We compute 2x dx lim
Math 3, Sectio 2. (25 poits) Why we defie f(x) dx as we do. (a) Show that the improper itegral diverges. Hece the improper itegral x 2 + x 2 + b also diverges. Solutio: We compute x 2 + = lim b x 2 + =
More informationPAPER : IIT-JAM 2010
MATHEMATICS-MA (CODE A) Q.-Q.5: Oly oe optio is correct for each questio. Each questio carries (+6) marks for correct aswer ad ( ) marks for icorrect aswer.. Which of the followig coditios does NOT esure
More informationTaylor Series (BC Only)
Studet Study Sessio Taylor Series (BC Oly) Taylor series provide a way to fid a polyomial look-alike to a o-polyomial fuctio. This is doe by a specific formula show below (which should be memorized): Taylor
More informationZeros of Polynomials
Math 160 www.timetodare.com 4.5 4.6 Zeros of Polyomials I these sectios we will study polyomials algebraically. Most of our work will be cocered with fidig the solutios of polyomial equatios of ay degree
More informationIntegrable Functions. { f n } is called a determining sequence for f. If f is integrable with respect to, then f d does exist as a finite real number
MATH 532 Itegrable Fuctios Dr. Neal, WKU We ow shall defie what it meas for a measurable fuctio to be itegrable, show that all itegral properties of simple fuctios still hold, ad the give some coditios
More informationTime-Domain Representations of LTI Systems
2.1 Itroductio Objectives: 1. Impulse resposes of LTI systems 2. Liear costat-coefficiets differetial or differece equatios of LTI systems 3. Bloc diagram represetatios of LTI systems 4. State-variable
More informationFunctions of Bounded Variation and Rectifiable Curves
Fuctios of Bouded Variatio ad Rectifiable Curves Fuctios of bouded variatio 6.1 Determie which of the follwoig fuctios are of bouded variatio o 0, 1. (a) fx x si1/x if x 0, f0 0. (b) fx x si1/x if x 0,
More informationAssignment 1 : Real Numbers, Sequences. for n 1. Show that (x n ) converges. Further, by observing that x n+2 + x n+1
Assigmet : Real Numbers, Sequeces. Let A be a o-empty subset of R ad α R. Show that α = supa if ad oly if α is ot a upper boud of A but α + is a upper boud of A for every N. 2. Let y (, ) ad x (, ). Evaluate
More informationOrthogonal Functions
Royal Holloway Uiversity of odo Departet of Physics Orthogoal Fuctios Motivatio Aalogy with vectors You are probably failiar with the cocept of orthogoality fro vectors; two vectors are orthogoal whe they
More informationZ ß cos x + si x R du We start with the substitutio u = si(x), so du = cos(x). The itegral becomes but +u we should chage the limits to go with the ew
Problem ( poits) Evaluate the itegrals Z p x 9 x We ca draw a right triagle labeled this way x p x 9 From this we ca read off x = sec, so = sec ta, ad p x 9 = R ta. Puttig those pieces ito the itegralrwe
More informationMIDTERM 3 CALCULUS 2. Monday, December 3, :15 PM to 6:45 PM. Name PRACTICE EXAM SOLUTIONS
MIDTERM 3 CALCULUS MATH 300 FALL 08 Moday, December 3, 08 5:5 PM to 6:45 PM Name PRACTICE EXAM S Please aswer all of the questios, ad show your work. You must explai your aswers to get credit. You will
More informationMATH 2300 review problems for Exam 2
MATH 2300 review problems for Exam 2. A metal plate of costat desity ρ (i gm/cm 2 ) has a shape bouded by the curve y = x, the x-axis, ad the lie x =. (a) Fid the mass of the plate. Iclude uits. Mass =
More informationDe Moivre s Theorem - ALL
De Moivre s Theorem - ALL. Let x ad y be real umbers, ad be oe of the complex solutios of the equatio =. Evaluate: (a) + + ; (b) ( x + y)( x + y). [6]. (a) Sice is a complex umber which satisfies = 0,.
More informationMath 113 Exam 3 Practice
Math Exam Practice Exam 4 will cover.-., 0. ad 0.. Note that eve though. was tested i exam, questios from that sectios may also be o this exam. For practice problems o., refer to the last review. This
More informationMATH301 Real Analysis (2008 Fall) Tutorial Note #7. k=1 f k (x) converges pointwise to S(x) on E if and
MATH01 Real Aalysis (2008 Fall) Tutorial Note #7 Sequece ad Series of fuctio 1: Poitwise Covergece ad Uiform Covergece Part I: Poitwise Covergece Defiitio of poitwise covergece: A sequece of fuctios f
More informationBeyond simple iteration of a single function, or even a finite sequence of functions, results
A Primer o the Elemetary Theory of Ifiite Compositios of Complex Fuctios Joh Gill Sprig 07 Abstract: Elemetary meas ot requirig the complex fuctios be holomorphic Theorem proofs are fairly simple ad are
More informationIt is always the case that unions, intersections, complements, and set differences are preserved by the inverse image of a function.
MATH 532 Measurable Fuctios Dr. Neal, WKU Throughout, let ( X, F, µ) be a measure space ad let (!, F, P ) deote the special case of a probability space. We shall ow begi to study real-valued fuctios defied
More informationSection A assesses the Units Numerical Analysis 1 and 2 Section B assesses the Unit Mathematics for Applied Mathematics
X0/70 NATIONAL QUALIFICATIONS 005 MONDAY, MAY.00 PM 4.00 PM APPLIED MATHEMATICS ADVANCED HIGHER Numerical Aalysis Read carefully. Calculators may be used i this paper.. Cadidates should aswer all questios.
More informationAxioms of Measure Theory
MATH 532 Axioms of Measure Theory Dr. Neal, WKU I. The Space Throughout the course, we shall let X deote a geeric o-empty set. I geeral, we shall ot assume that ay algebraic structure exists o X so that
More information( ) = p and P( i = b) = q.
MATH 540 Radom Walks Part 1 A radom walk X is special stochastic process that measures the height (or value) of a particle that radomly moves upward or dowward certai fixed amouts o each uit icremet of
More informationName: Math 10550, Final Exam: December 15, 2007
Math 55, Fial Exam: December 5, 7 Name: Be sure that you have all pages of the test. No calculators are to be used. The exam lasts for two hours. Whe told to begi, remove this aswer sheet ad keep it uder
More informationChapter 7 z-transform
Chapter 7 -Trasform Itroductio Trasform Uilateral Trasform Properties Uilateral Trasform Iversio of Uilateral Trasform Determiig the Frequecy Respose from Poles ad Zeros Itroductio Role i Discrete-Time
More informationAdditional Notes on Power Series
Additioal Notes o Power Series Mauela Girotti MATH 37-0 Advaced Calculus of oe variable Cotets Quick recall 2 Abel s Theorem 2 3 Differetiatio ad Itegratio of Power series 4 Quick recall We recall here
More informationSummary: CORRELATION & LINEAR REGRESSION. GC. Students are advised to refer to lecture notes for the GC operations to obtain scatter diagram.
Key Cocepts: 1) Sketchig of scatter diagram The scatter diagram of bivariate (i.e. cotaiig two variables) data ca be easily obtaied usig GC. Studets are advised to refer to lecture otes for the GC operatios
More informationMath 132, Fall 2009 Exam 2: Solutions
Math 3, Fall 009 Exam : Solutios () a) ( poits) Determie for which positive real umbers p, is the followig improper itegral coverget, ad for which it is diverget. Evaluate the itegral for each value of
More informationChapter 4 : Laplace Transform
4. Itroductio Laplace trasform is a alterative to solve the differetial equatio by the complex frequecy domai ( s = σ + jω), istead of the usual time domai. The DE ca be easily trasformed ito a algebraic
More informationMAT1026 Calculus II Basic Convergence Tests for Series
MAT026 Calculus II Basic Covergece Tests for Series Egi MERMUT 202.03.08 Dokuz Eylül Uiversity Faculty of Sciece Departmet of Mathematics İzmir/TURKEY Cotets Mootoe Covergece Theorem 2 2 Series of Real
More informationReview Problems 1. ICME and MS&E Refresher Course September 19, 2011 B = C = AB = A = A 2 = A 3... C 2 = C 3 = =
Review Problems ICME ad MS&E Refresher Course September 9, 0 Warm-up problems. For the followig matrices A = 0 B = C = AB = 0 fid all powers A,A 3,(which is A times A),... ad B,B 3,... ad C,C 3,... Solutio:
More information1 1 2 = show that: over variables x and y. [2 marks] Write down necessary conditions involving first and second-order partial derivatives for ( x0, y
Questio (a) A square matrix A= A is called positive defiite if the quadratic form waw > 0 for every o-zero vector w [Note: Here (.) deotes the traspose of a matrix or a vector]. Let 0 A = 0 = show that:
More informationLecture 7: Fourier Series and Complex Power Series
Math 1d Istructor: Padraic Bartlett Lecture 7: Fourier Series ad Complex Power Series Week 7 Caltech 013 1 Fourier Series 1.1 Defiitios ad Motivatio Defiitio 1.1. A Fourier series is a series of fuctios
More informationPRELIM PROBLEM SOLUTIONS
PRELIM PROBLEM SOLUTIONS THE GRAD STUDENTS + KEN Cotets. Complex Aalysis Practice Problems 2. 2. Real Aalysis Practice Problems 2. 4 3. Algebra Practice Problems 2. 8. Complex Aalysis Practice Problems
More informatione to approximate (using 4
Review: Taylor Polyomials ad Power Series Fid the iterval of covergece for the series Fid a series for f ( ) d ad fid its iterval of covergece Let f( ) Let f arcta a) Fid the rd degree Maclauri polyomial
More informationHOMEWORK #10 SOLUTIONS
Math 33 - Aalysis I Sprig 29 HOMEWORK # SOLUTIONS () Prove that the fuctio f(x) = x 3 is (Riema) itegrable o [, ] ad show that x 3 dx = 4. (Without usig formulae for itegratio that you leart i previous
More information8. Applications To Linear Differential Equations
8. Applicatios To Liear Differetial Equatios 8.. Itroductio 8.. Review Of Results Cocerig Liear Differetial Equatios Of First Ad Secod Orders 8.3. Eercises 8.4. Liear Differetial Equatios Of Order N 8.5.
More informationAns: a n = 3 + ( 1) n Determine whether the sequence converges or diverges. If it converges, find the limit.
. Fid a formula for the term a of the give sequece: {, 3, 9, 7, 8 },... As: a = 3 b. { 4, 9, 36, 45 },... As: a = ( ) ( + ) c. {5,, 5,, 5,, 5,,... } As: a = 3 + ( ) +. Determie whether the sequece coverges
More informationn 3 ln n n ln n is convergent by p-series for p = 2 > 1. n2 Therefore we can apply Limit Comparison Test to determine lutely convergent.
06 微甲 0-04 06-0 班期中考解答和評分標準. ( poits) Determie whether the series is absolutely coverget, coditioally coverget, or diverget. Please state the tests which you use. (a) ( poits) (b) ( poits) (c) ( poits)
More informationSingular Continuous Measures by Michael Pejic 5/14/10
Sigular Cotiuous Measures by Michael Peic 5/4/0 Prelimiaries Give a set X, a σ-algebra o X is a collectio of subsets of X that cotais X ad ad is closed uder complemetatio ad coutable uios hece, coutable
More informationSCORE. Exam 2. MA 114 Exam 2 Fall 2017
Exam Name: Sectio ad/or TA: Do ot remove this aswer page you will retur the whole exam. You will be allowed two hours to complete this test. No books or otes may be used. You may use a graphig calculator
More informationMath 110 Assignment #6 Due: Monday, February 10
Math Assigmet #6 Due: Moday, February Justify your aswers. Show all steps i your computatios. Please idicate your fial aswer by puttig a box aroud it. Please write eatly ad legibly. Illegible aswers will
More informationProblem Cosider the curve give parametrically as x = si t ad y = + cos t for» t» ß: (a) Describe the path this traverses: Where does it start (whe t =
Mathematics Summer Wilso Fial Exam August 8, ANSWERS Problem 1 (a) Fid the solutio to y +x y = e x x that satisfies y() = 5 : This is already i the form we used for a first order liear differetial equatio,
More informationCarleton College, Winter 2017 Math 121, Practice Final Prof. Jones. Note: the exam will have a section of true-false questions, like the one below.
Carleto College, Witer 207 Math 2, Practice Fial Prof. Joes Note: the exam will have a sectio of true-false questios, like the oe below.. True or False. Briefly explai your aswer. A icorrectly justified
More informationMath 116 Final Exam December 12, 2014
Math 6 Fial Exam December 2, 24 Name: EXAM SOLUTIONS Istructor: Sectio:. Do ot ope this exam util you are told to do so. 2. This exam has 4 pages icludig this cover. There are 2 problems. Note that the
More information1. (25 points) Use the limit definition of the definite integral and the sum formulas 1 to compute
Math, Calculus II Fial Eam Solutios. 5 poits) Use the limit defiitio of the defiite itegral ad the sum formulas to compute 4 d. The check your aswer usig the Evaluatio Theorem. ) ) Solutio: I this itegral,
More informationECEN 644 HOMEWORK #5 SOLUTION SET
ECE 644 HOMEWORK #5 SOUTIO SET 7. x is a real valued sequece. The first five poits of its 8-poit DFT are: {0.5, 0.5 - j 0.308, 0, 0.5 - j 0.058, 0} To compute the 3 remaiig poits, we ca use the followig
More informationChapter 10 Partial Differential Equations and Fourier Series
Math-33 Chapter Partial Differetial Equatios November 6, 7 Chapter Partial Differetial Equatios ad Fourier Series Math-33 Chapter Partial Differetial Equatios November 6, 7. Boudary Value Problems for
More informationContinuous Functions
Cotiuous Fuctios Q What does it mea for a fuctio to be cotiuous at a poit? Aswer- I mathematics, we have a defiitio that cosists of three cocepts that are liked i a special way Cosider the followig defiitio
More informationSeunghee Ye Ma 8: Week 5 Oct 28
Week 5 Summary I Sectio, we go over the Mea Value Theorem ad its applicatios. I Sectio 2, we will recap what we have covered so far this term. Topics Page Mea Value Theorem. Applicatios of the Mea Value
More information1 lim. f(x) sin(nx)dx = 0. n sin(nx)dx
Problem A. Calculate ta(.) to 4 decimal places. Solutio: The power series for si(x)/ cos(x) is x + x 3 /3 + (2/5)x 5 +. Puttig x =. gives ta(.) =.3. Problem 2A. Let f : R R be a cotiuous fuctio. Show that
More informationMATH 10550, EXAM 3 SOLUTIONS
MATH 155, EXAM 3 SOLUTIONS 1. I fidig a approximate solutio to the equatio x 3 +x 4 = usig Newto s method with iitial approximatio x 1 = 1, what is x? Solutio. Recall that x +1 = x f(x ) f (x ). Hece,
More informationEngineering Mathematics (21)
Egieerig Mathematics () Zhag, Xiyu Departmet of Computer Sciece ad Egieerig, Ewha Womas Uiversity, Seoul, Korea zhagy@ewha.ac.kr Fourier Series Sectios.-3 (8 th Editio) Sectios.- (9 th Editio) Fourier
More informationLøsningsførslag i 4M
Norges tekisk aturviteskapelige uiversitet Istitutt for matematiske fag Side 1 av 6 Løsigsførslag i 4M Oppgave 1 a) A sketch of the graph of the give f o the iterval [ 3, 3) is as follows: The Fourier
More informationMath 10A final exam, December 16, 2016
Please put away all books, calculators, cell phoes ad other devices. You may cosult a sigle two-sided sheet of otes. Please write carefully ad clearly, USING WORDS (ot just symbols). Remember that the
More informationMA131 - Analysis 1. Workbook 9 Series III
MA3 - Aalysis Workbook 9 Series III Autum 004 Cotets 4.4 Series with Positive ad Negative Terms.............. 4.5 Alteratig Series.......................... 4.6 Geeral Series.............................
More informationTopic 1 2: Sequences and Series. A sequence is an ordered list of numbers, e.g. 1, 2, 4, 8, 16, or
Topic : Sequeces ad Series A sequece is a ordered list of umbers, e.g.,,, 8, 6, or,,,.... A series is a sum of the terms of a sequece, e.g. + + + 8 + 6 + or... Sigma Notatio b The otatio f ( k) is shorthad
More informationUniversity of Colorado Denver Dept. Math. & Stat. Sciences Applied Analysis Preliminary Exam 13 January 2012, 10:00 am 2:00 pm. Good luck!
Uiversity of Colorado Dever Dept. Math. & Stat. Scieces Applied Aalysis Prelimiary Exam 13 Jauary 01, 10:00 am :00 pm Name: The proctor will let you read the followig coditios before the exam begis, ad
More informationMath 116 Practice for Exam 3
Math 6 Practice for Exam Geerated October 0, 207 Name: SOLUTIONS Istructor: Sectio Number:. This exam has 7 questios. Note that the problems are ot of equal difficulty, so you may wat to skip over ad retur
More informationThe Z-Transform. (t-t 0 ) Figure 1: Simplified graph of an impulse function. For an impulse, it can be shown that (1)
The Z-Trasform Sampled Data The geeralied fuctio (t) (also kow as the impulse fuctio) is useful i the defiitio ad aalysis of sampled-data sigals. Figure below shows a simplified graph of a impulse. (t-t
More informationMath 116 Practice for Exam 3
Math 6 Practice for Eam 3 Geerated April 4, 26 Name: SOLUTIONS Istructor: Sectio Number:. This eam has questios. Note that the problems are ot of equal difficulty, so you may wat to skip over ad retur
More informationPRACTICE FINAL/STUDY GUIDE SOLUTIONS
Last edited December 9, 03 at 4:33pm) Feel free to sed me ay feedback, icludig commets, typos, ad mathematical errors Problem Give the precise meaig of the followig statemets i) a f) L ii) a + f) L iii)
More informationFINALTERM EXAMINATION Fall 9 Calculus & Aalytical Geometry-I Questio No: ( Mars: ) - Please choose oe Let f ( x) is a fuctio such that as x approaches a real umber a, either from left or right-had-side,
More information