PHYSICS PAPER 2. Name: Class: ( ) Question-Answer Book 2014-HFC PHY PAPER 2. Time allowed: ¾ hour This paper must be answered in English INSTRUCTIONS

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1 014-HF PHY PAPER Name: lass: ( ) HO FUNG OLLEGE (SPONSORE Y SIK SIK YUEN) FINAL EXAMINATION 014 PHYSIS PAPER Question-Answe ook Time allowe: ¾ hou This pape must be answee in English INSTRUTIONS (1) Afte the announcement of the stat of the examination, you shoul fist wite you name, class an class numbe in the spaces povie. () Attempt ALL questions. (3) Wite you answes to the stuctue questions in the ANSWER OOK povie. Fo multiple-choice questions, blacken the appopiate cicle with an H pencil. You shoul mak only ONE answe fo each question. If you mak moe than one answe, you will eceive NO MARKS fo that question. (4) Gaph pape an supplementay answe sheets will be povie on equest. Wite you pesonal infomation an mak the question numbe box on each sheet, an fasten them with sting INSIE the Answe ook. (5) The iagams in this pape ae NOT necessaily awn to scale. (6) The last two pages of this Question-Answe ook contain a list of ata, fomulae an elationships which you may fin useful. (7) No exta time will be given to caniates afte the Time is up announcement S5 SEON EXAM-PHY 1 1

2 Elective Section : Meical Physics Q.4: Multiple-choice questions 4.1 Which pat of the eye will change in shape accoing to the bightness of the envionment? A. conea A. iis. lens. eyeball 4. The longest focal length of a nomal eye. (1) occus when the peson views a istant object. () is about the length of the eyeball. (3) is about 5 cm. A. (1) only A. (3) only. (1) an () only. () an (3) only 4.3 The vision of a peson is coecte by using a lens of powe -6. Which of the following about the positions of the fa point an nea point befoe the coection is tue? Fa point / cm Nea point / cm A. 17 < 5 A. 17 > < 5. infinity 17

3 4.4 The iamete of the pupil of an eye is 1.5 mm. Estimate the minimum sepaation between two points which can be istinguishe by the peson. Assume the wavelength of light is 600 nm an the nea point istance is 5 cm. A. 0.1 mm A mm mm. 1. mm 4.5 A etecto is use to measue the soun intensity ue to a louspeake at istance. If the powe output of the louspeake is halve, what is the minimum istance that the etecto shoul move in oe to eceive the same soun intensity? A.. A. ( 1) The iagam shows the cuves of equal louness. What is the louness of a 10 khz soun with intensity level of 50? A. 30 phon A. 40 phon. 50 phon. 60 phon 4.7 The half-value thickness of a meium fo an ultasoun is 0 cm. What is the thickness of the meium to absob 90% of the enegy? A. 46 cm A. 50 cm. 66 cm. 90 cm 4.8 Which of the following affects the linea attenuation coefficient of ultasoun insie a meium?

4 A. fequency of the ultasoun A. intensity fo the ultasoun. thickness of meium. amplitue of the ultasoun 4.9 The iagam shows the oscilloscope isplay of an ultasoun scan of an ogan. The istance between bounaies P an Q is 6.4 mm. Given that the spee of ultasoun in the ogan is 1600 m s -1. What is the time base setting of the oscilloscope? A. 1 µs iv -1 A. µs iv µs iv µs iv The thickness of a laye of tissue is 1 mm. In an ultasoun imaging, which of the following pulse lengths can eveal both sies of the laye? (1) 0.6 mm () 1.5 mm (3).1 mm A. (1) only A. (3) only. (1) an () only. () an (3) only 4.11 The iagam shows the coe of an optical fibe suoune by a claing. The efactive inices of the coe an the claing ae 1.5 an 1.3 espectivley. What is the minimum angle of incience i fo a beam of light stiking the coe to ente into the claing? A. 4 o A. 48 o. 50 o. 60 o 4.1 Which of the following statements about the claing in an optical fibe is/ae tue? (1) The claing can incease the acceptance angle of an optical fibe. () The claing is opaque o silvey to incease eflection of light within the coe. (3) The claing pevents light cossing between fibes which ae in contact. A. (1) only A. (3) only. (1) an () only. () an (3) only

5 Stuctue question 1. The seveeness of myopia can be expesse in egee. One egee coespons to 0.01 powe of the lens neee to coect myopia. oth eyes of Pete suffe fom myopia with seveeness of 480 egee. (a) State the type of lens suitable fo Pete an etemine its focal length. ( maks) (b) What is the istance of the fathest object that can be viewe clealy by Pete without weaing glasses? ( maks) (c) If the nea point of Pete s unaie eyes is at istance of 10 cm, what is his nea point istance afte putting on the coecting lens? (3 maks)

6 . The table below shows the popeties of seveal iffeent meia in a boy. Figue 6.1 (a) alculate the acoustic impeance of the kiney tissue. (1 mak) (b) An ultasoun pulse is passing though a kiney-fat bounay. Fin the pecentage of intensity that can be tansmitte though the bounay. (3 maks) (c) Explain why ultasoun of low fequency shoul be use in examining the kiney. ( maks) () State TWO avantages in using ultasoun fo meical imaging.. ( maks) EN OF PAPER

7 ata mola gas constant Avogao constant acceleation ue to gavity univesal gavitational constant spee of light in vacuum chage of electon electon est mass pemittivity of fee space pemeability of fee space atomic mass unit astonomical unit light yea pasec Stefan constant Planck constant List of ata, fomulae an elationships 1 1 R= 8.31 J mol K 3 1 N A = mol g= 9.81 m s (close to the Eath) 11 G= N m kg 8 1 c= m s 19 e= m e = kg 1 1 ε 0 = N m 7 1 µ 0= 4π 10 H m 7 u= kg (1 u is equivalent to 931 MeV) 11 AU= m 15 ly= m 16 pc= m= 3.6 ly= 0665 AU 8 4 σ= W m K 34 h= J s Rectilinea motion Fo unifomly acceleate motion : v= u+ at 1 s= ut+ at v = u + as Mathematics Equation of a staight line y= mx+ c Ac length = θ Suface aea of cyline = πh+ π Volume of cyline = π h Suface aea of sphee = 4π Volume of sphee = Fo small angles, sin θ tanθ θ (in aians) Astonomy an Space Science U P f f GMm 4 σat v λ c λ = gavitational potential enegy = Stefan s law 0 0 Atomic Wol 1 e max opple effect m v = hf φ Einstein s photoelectic equation 4 1 mee 13.6 En= = ev n 8hε 0 n enegy level equation fo hyogen atom λ= h h p = mv e oglie fomula 1.λ θ Rayleigh citeion (esolving powe) Enegy an Use of Enegy Q t U P k ( T) A T H = ate of enegy tansfe by conuction k 1 ρav = themal tansmittance U-value 3 = maximum powe by win tubine Meical Physics 1.λ θ 1 powe f = powe of a lens Rayleigh citeion (esolving powe) L= 10log I I0 intensity level () Z= ρc acoustic impeance ( 1) ( + ) I Z Z α= = I Z Z I I e µx intensity eflection coefficient = tansmitte intensity though a meium

8 A1. E= mc T enegy tansfe uing heating Q1Q 1. F an cooling 4πε0 oulomb s law A. E= l m enegy tansfe uing change of Q. E= state 4πε0 A3. pv= nrt equation of state fo an ieal gas 3. Q V 4πε0 1 V A4. pv= Nmc kinetic theoy equation 4. E= 3 A5. 3RT EK= N A molecula kinetic enegy 5. I navq 6. R ρl A 1. v p F= m = Foce 7. R= R1+ R t t esistos in seies. moment= F moment of a foce = + R R R esistos in paallel 3. EP sin 3. mgh electic fiel stength ue to a point chage = electic potential ue to a point chage electic fiel between paallel plates (numeically) = geneal cuent flow equation = esistance an esistivity 1 = gavitational potential enegy 9. P= IV= I R powe in a cicuit 1 EK= mv kinetic enegy 10. F= Qv sinθ W P= Fv= t mechanical powe 11. F= Il sinθ v I a= = ω centipetal acceleation 1. V= nqt Hall voltage Gm1m µ 0I F= Newton s law of gavitation 13. = π 14. µ NI 0 l λ finge with in ouble-slit Φ y= 15. ε= N a intefeence t inuce e.m.f. θ= nλ iffaction gating equation Vs Ns 16. V N = equation fo a single lens u v f p foce on a moving chage in a magnetic fiel foce on a cuent-caying conucto in a magnetic fiel magnetic fiel ue to a long staight wie = magnetic fiel insie a long solenoi p atio of seconay voltage to pimay voltage in a tansfome E1. N= N0e kt law of aioactive ecay ln t E. 1 = half-life an ecay constant k E3. A= kn activity an the numbe of unecaye nuclei E4. E= mc mass-enegy elationship

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