NEET UG 2013, Physics Question Paper (Date of Examination: )
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1 TAGET Publications NEET UG Question Pape NEET UG, Question Pape (Date of Examination: 5-5-) Class XI NEET XII NEET Unit No. Unit name Question No. Total No. of Questions I Physical Wold and Measuement II Scalas and Vectos III Motion in One Dimension IV Laws of Motion 4, 5 V Motion in Two Dimensions VI Wok, Enegy and Powe 6, 7 VII otational Motion 8, 9 VIII Gavitation, IX Elasticity X Viscosity XI Suface Tension XII Heat 4, 5 XIII Themodynamics 6, 7 XIV Kinetic Theoy of Gases 8, 9 XV Oscillations XVI Wave Mechanics,, I Electostatics, 4 II Cuent Electicity 5, 6, 7 III Magnetic effect of electic cuent 8, 9 IV Magnetism V Electomagnetic induction and Altenating cuent, VI Electomagnetic waves VII ay Optics 9, 4 VIII Wave Optics 4, 4 IX X Intefeence of light Diffaction and Polaisation of light XI Dual natue of matte and adiation 7, 8 XII Atoms and Nuclei, 4, 5, 6 4 XIII Electonic Devices 4, 44, 45 Total Total Total 45
2 W Code NEET UG Question Pape TAGET Publications. In an expeiment fou quantities a, b, c and d ae measued with pecentage eo %, %, % and 4% espectively. Quantity P is calculated as follows : ab P % eo in P is cd 4% () % (C) 7% (D) 4%.. ab Given that: P cd a eo contibuted by a a % % b eo contibuted by b b % 4% c eo contibuted by c c d eo contibuted by d d 4% Pecentage eo in P is given as, p (eo contibuted by a)+(eo contibuted by b)+(eo contibuted by c)+(eo contibuted by d) p % + 4% + % + 4% 4%. The velocity of a pojectile at the initial point A is ( i ˆ j ˆ) Y + m/s. Its velocity (in m/s) at point is A X i ˆ j ˆ () i ˆ + j (C) i ˆ j ˆ (D) i ˆ + j. (C). j ˆ ˆ i j ˆ ˆ i Hoizontal (X) component emains the same while the vetical (Y) component changes. i ˆ j ˆ m/s Theefoe, velocity at ( )
3 TAGET Publications NEET UG Question Pape. A stone falls feely unde gavity. It coves distances h, h and h in the fist 5 seconds, the next 5 seconds and the next 5 seconds espectively. The elation between h, h and h is h h h h () h h (C) h h and h h (D) h h h 5. (). At point A, u A u h gt h t 5s 5 h t 5s C h 5 m h Now, v u + gt + (5) t 5s D v 5 m/s At point, final velocity fom A to initial velocity at h ut + gt Now, h 75 m v u + gt 5 + (5) v m/s Similaly, At point C, we get, h 65 m h : h : h 5 : 75 : 65 : : 5 i.e., h h h 5 4. Thee blocks with masses m, m and m ae connected by stings, as shown in the figue. Afte an upwad foce F is applied on block m, the masses move upwad at constant speed v. What is the net foce on the block of mass m? (g is the acceleation due to gavity) F v m Zeo () mg (C) mg (D) 6 mg Since all thee blocks ae moving up with a constant speed v, acceleation a is zeo. We know, F ma F [ a ] net foce is zeo. 5. The uppe half of an inclined plane of inclination θ is pefectly smooth while lowe half is ough. A block stating fom est at the top of the plane will again come to est at the bottom, if the coefficient of fiction between the block and lowe half of the plane is given by µ tanθ m m () µ tanθ 5. (C) 5. We know that, v u + as.() Now, initial velocity at midpoint u L g sinθ And final velocity fo the lowe half v (C) µ tan θ (D) µ tan θ
4 W Code NEET UG Question Pape TAGET Publications At lowe half acceleation g sin θ µg cos θ and s L Fom equation (), L/ g L sin θ [g sin θ µg cos θ] L g L sin θ gl sin θ µgl cos θ gl sin θ µgl cos θ µ tan θ L/ θ 6. A unifom foce of ( i ˆ ˆj ) position ( i ˆ + kˆ) mete to position ( 4i ˆ j ˆ kˆ) + newton acts on a paticle of mass kg. Hence the paticle is displaced fom + mete. The wok done by the foce on the paticle is 9 J () 6 J (C) J (D) 5 J 6. i ˆ + ˆj 6. F ( ) i ˆ+ j ˆ kˆ S We know, W F S + i ˆ+ j ˆ kˆ ( i ˆ ˆj ) W 9 J 7. An explosion beaks a ock into thee pats in a hoizontal plane. Two of them go off at ight angles to each othe. The fist pat of mass kg moves with a speed of ms and the second pat of mass kg moves with 8 ms speed. If the thid pat flies off with 4 ms speed, then its mass is kg () 5 kg (C) 7 kg (D) 7 kg 7. () 7. Fom law of consevation of momentum, P+ P+ P Let P and P go off at ight angles to each othe. P P + P m 4 ( ) + ( 8) + 6 m 4 m 5 kg 4
5 TAGET Publications NEET UG Question Pape 8. A od PQ of mass M and length L is hinged at end P. The od is kept hoizontal by a massless sting tied to point Q as shown in figue. When sting is cut, the initial angula acceleation of the od is P Q L g L Fo the od PQ, () g L (C) g L (D) g L ML α T L Now, T Mg ML α Mg L α g L P L/ Mg Q 9. A small object of unifom density olls up a cuved suface with an initial velocity v. It eaches up to a v maximum height of with espect to the initial position. The object is 4g ing () Solid sphee (C) Hollow sphee (D) Disc 9. (D) 9. Velocity of the small object is given as, gh v k + v gv k 4g + + k k ut k I M I M I M disc 5
6 W TAGET Publications Code NEET UG Question Pape. A body of mass 'm' taken fom the eath's suface to the height equal to twice the adius () of the eath. The change in potential enegy of body will be mg () mg. (). The change in potential enegy is given as, U U f U i GMm + GMm GMm GMm GM m GMm (C) mg (D) mg U mg. Infinite numbe of bodies, each of mass kg ae situated on x-axis at distance m, m, 4 m, 8 m,... espectively, fom the oigin. The esulting gavitational potential due to this system at the oigin will be G () 8 G (C) 4 G (D) 4G. (D). Gavitational potential is given as, GM V V GM G G 4 8 V 4G. The following fou wies ae made of the same mateial. Which of these will have the lagest extension when the same tension is applied? Length 5 cm, diamete.5 mm () Length cm, diamete mm (C) Length cm, diamete mm (D) Length cm, diamete mm.. Young s Modulus fo a wie is given as, Mg L Y LA 6 L Mg L YA L L A L Now, is maximum fo L 5cm and diamete.5 mm. A Hence, option is coect.
7 TAGET Publications NEET UG Question Pape. The wettability of a suface by a liquid depends pimaily on Viscosity () Suface tension (C) Density (D) Angle of contact between the suface and the liquid. (D). The wettability of a suface of liquid depends on angle of contact between suface and liquid. 4. The mola specific heats of an ideal gas at constant pessue and volume ae denoted by C p and C v espectively. If C and is the univesal gas constant, then C v is equal to + γ (γ ) () (C) γ (γ ) (D) γ 4. () 4. Diffeence between two mola specific heat is given as, C P C v Cp Cv Cv Cv Cv γ Cv C v γ 5. A piece of ion is heated in a flame. It fist becomes dull ed then becomes eddish yellow and finally tuns to white hot. The coect explanation fo the above obsevation is possible by using Stefan's Law () Wien's displacement Law (C) Kichoff's Law (D) Newton's Law of cooling 5. () 5. Fom Wien s displacement law, λ m T λ m T constant 6. A gas is taken though the cycle A C A, as shown. What is the net wok done by the gas? P( 5 Pa) A C V ( m ) J () J (C) Zeo (D) J 6. () 6. We know, Wok done Aea unde P V cuve. 5 4 W J 5 7
8 W Code NEET UG Question Pape TAGET Publications 7. Duing an adiabatic pocess, the pessue of a gas is found to be popotional to the cube of its tempeatue. Cp The atio of fo the gas is C v 4 () (C) 7. (D) 7. Fo an adiabatic pocess, P T γ/γ Given that, P T γ γ γ γ γ 5 (D) γ 8. In the given (V T) diagam, what is the elation between pessues P and P? V P P θ θ T P P () P > P (C) P < P (D) Cannot be pedicted 8. (C) 8. Assuming the gaph fo a gas of given mass, we have, PV n T V T P Fom the gaph, V T tan θ P tan θ as angle θ inceases, tan θ inceases and pessue diceases. P > P 9. The amount of heat enegy equied to aise the tempeatue of g of Helium at NTP, fom T K to T K is 8 N ak (T T ) () N ak (T T ) (C) 4 N ak (T T ) (D) 4 N T ak T 9. 8
9 TAGET Publications 9. Amount of enegy equied is given as, f f E nt NK( T T) f E ( n NA) k ( T T) Whee N n. N A k oltzmann constant. E nn A K ( T T ) [ f fo H e ] m Now, n M 4 E NA k( T T) A ( T ) 4 8 NEET UG Question Pape. A wave tavelling in the +ve x-diection having displacement along y-diection as m, wavelength π m and fequency of Hz is epesented by π y sin(x t) () y sin(πx πt) (C) y sin(πx πt) (D) y sin(πx + πt).. y a sin (kx ωt).() Now, k π π λ π ω π.v π. π a m. Substituting these in equation (), π y sin x t π y sin [x t]. If we study the vibation of a pipe open at both ends, then the following statement is not tue Open end will be anti-node. () Odd hamonics of the fundamental fequency will be geneated. (C) All hamonics of the fundamental fequency will be geneated. (D) Pessue change will be maximum at both ends.. (D). The ai column in a pipe open at both ends can vibate in a numbe of diffeent modes subjected to the bounday condition that thee must be an antinode at the open end. Hence option is coect. The atio of fequency when pipe is open at both the ends is given as, ν : ν : ν : 4 ν : 5 ν v whee ν L oth odd as well even i.e., All hamonics ae pesent. Hence, option () and (C) ae coect Pessue vaiation is minimum at antinode option (D) is incoect. 9
10 W Code NEET UG Question Pape TAGET Publications. A souce of unknown fequency gives 4 beats/s, when sounded with a souce of known fequency 5 Hz. The second hamonic of the souce of unknown fequency gives five beats pe second, when sounded with a souce of fequency 5 Hz. The unknown fequency is 54 Hz () 46 Hz (C) 4 Hz (D) 6 Hz.. ν a 5 ± 4 54 Hz o 46 Hz ν b 5 ± 5 58 Hz o 58 Hz Now, ν b ν a Which is 58 (54) ν 54 Hz. Two pith balls caying equal chages ae suspended fom a common point by stings of equal length, the equilibium sepaation between them is. Now the stings ae igidly clamped at half the height. The equilibium sepaation between the balls now become (). (). In the equilibium position, T cos θ mg Kq T sin θ F e Kq tan θ mg / Kq i.e., y mg mg y Kq y / Now, the equilibium sepaation fo (y/) is, / y / ( ) y (C) 4. A, and C ae thee points in a unifom electic field. The electic potential is θ T sin θ y/ T T cos θ θ mg F e (D) C A E Maximum at A () Maximum at (C) Maximum at C (D) Same at all the thee points A, and C 4. ()
11 TAGET Publications 4. NEET UG Question Pape dv E d i.e., electic field is diected along deceasing potential. V > V C > V P Potential is maximum at. 5. A wie of esistance 4 Ω is stetched to twice its oiginal length. The esistance of stetched wie would be Ω () 4 Ω (C) 8 Ω (D) 6 Ω 5. (D) 5. Let be the esistance and l be the oiginal length. At constant volume, l esistance of stetched wie is, 4 4(4) 6Ω 6. The intenal esistance of a. V cell which gives a cuent of. A though a esistance of Ω is. Ω ().5 Ω (C).8 Ω (4). Ω 6. () 6. E I Ω 7. The esistances of the fou ams P, Q, and S in a Wheatstone's bidge ae ohm, ohm, ohm and 9 ohm, espectively. The e.m.f. and intenal esistance of the cell ae 7 volt and 5 ohm espectively. If the galvanomete esistance is 5 ohm, the cuent dawn fom the cell will be. A (). A (C). A (D). A 7. () 7. Fo a alanced wheatstone s idge, P Q S Equivalent esistance eq 4 6 Ω Now, eff V Now, I A eff (+ )(+ 9) ( )
12 W Code NEET UG Question Pape TAGET Publications 8. When a poton is eleased fom est in a oom, it stats with an initial acceleation a towads west. When it is pojected towads noth with a speed v it moves with an initial acceleation a towad west. The electic and magnetic fields in the oom ae ma ma ma ma west, up () west, down e ev e ev ma (C) e 8. () 8. Electic field ma east, ev ma up (D) e Foce Chage ma (in west diection) e Magnetic foce F m ma ma ma (in west diection) ma east, ev down v is diected towads west. Since, v is diected towads noth fo positive chage, is diected vetically down. Now, Fm q v ma ev ma (vetically down) ev 9. A cuent loop in a magnetic field Expeiences a toque whethe the field is unifom o non unifom in all oientations () Can be in equilibium in one oientation (C) Can be in equilibium in two oientations, both the equilibium states ae unstable (D) Can be in equilibium in two oientations, one stable while the othe is unstable 9. (D) 9. M When θ (paallel) it is in stable equilibium. When θ 6 (anti-paallel), it is in unstable equilibium.. A ba magnet of length l and magnetic dipole moment M is bent in the fom of an ac as shown in figue. The new magnetic dipole moment will be 6. () M () π M (C) π M (D) M
13 TAGET Publications. L π NEET UG Question Pape L π M m m L π 6 M π [ M ml]. A wie loop is otated in a magnetic field. The fequency of change of diection of the induced e.m.f. is Once pe evolution () Twice pe evolution (C) Fou times pe evolution (D) Six times pe evolution. (). e + t e NωA sinωt e changes diection twice pe evolution.. A coil of self-inductance L is connected in seies with a bulb and an AC souce. ightness of the bulb deceases when Fequency of the AC souce is deceased () Numbe of tuns in the coil is educed (C) A capacitance of eactance XC XL is included in the same cicuit (D) An ion od is inseted in the coil. (D). Impedance is given as, + XL Z + (L πf) If fequency is deceased, impedance deceases. If numbe of tuns deceases, self inductance deceases and thus impedance deceases. At esonance, X C X L and impedance deceases. When ion od is inseted, impedance inceases and hence cuent deceases.. The condition unde which a micowave oven heats up a food item containing wate molecules most efficiently is The fequency of the micowaves must match the esonant fequency of the wate molecules () The fequency of the micowaves has no elation with natual fequency of wate molecules (C) Micowaves ae heat waves, so always poduce heating (D) Infa-ed waves poduce heating in a micowave oven.. In pesence of micowave, wate molecules oscillate in an electic field of micowave esulting in geneation of heat. Amplitude of oscillation will be maximum when fequency of micowave match the esonant fequency of wate molecules.
14 W Code 4 λ l Fo alme seies, () λ b λ b 6 5 λl 4 λ 5 b NEET UG Question Pape TAGET Publications 4. atio of longest wavelengths coesponding to Lyman and alme seies in hydogen spectum is () (C) (D) Fo Lyman seies, () λ l 4 n 4 Longest wavelength coesponding to alme Longest wavelength coesponding to Lyman n n n 5. The half life of a adioactive isotope X is yeas. It decays to anothe element Y which is stable. The two elements X and Y wee found to be in the atio : 7 in a sample of a given ock. The age of the ock is estimated to be 4 yeas () 6 yeas (C) 8 yeas (D) yeas 5. () 5. N N (+ 7) 8 () n n () n t T t [Half life of X T yeas] t 6 yeas 6. A cetain mass of Hydogen is changed to Helium by the pocess of fusion. The mass defect in fusion eaction is.866 u. The enegy libeated pe u is (given u 9 MeV).67 MeV () 6.7 MeV (C) MeV (D).5 MeV 6. (C) 6. Mass defect m.866 u Total enegy E mc MeV 6.68 MeV Enegy libeated pe nucleon E A MeV
15 TAGET Publications NEET UG Question Pape 7. Fo photoelectic emission fom cetain metal the cut-off fequency is ν. If adiation of fequency ν impinges on the metal plate, the maximum possible velocity of the emitted electon will be (m is the electon mass) hν (m) () 7. (C) 7. Cut off fequency is given as ν Wok function φ hν Now, E K.E. + φ v hν mv + hν mv hν hν mv hν hν m hν m (C) hν m (D) hν m 8. The wavelength λ e of an electon and λ p of a photon of same enegy E ae elated by λ p λ e () λ p λ e (C) λ p λ e (D) λ p de oglie s wavelength fo an electon, λ e h me λ e i.e., λ e E o e λ E.() wavelength of photon is given as, λ p hc E i.e., λ p E. () Fom () and (), we have, λe λ p 9. A plano-convex lens fits exactly into a planoconcave lens. Thei plane sufaces ae paallel to each othe. If lenses ae made of diffeent mateials of efactive indices µ and µ and is the adius of cuvatue of the cuved suface of the lenses, then the focal length of the combination is () (C) (D) (µ + µ ) (µ µ ) (µ µ ) (µ µ ) 9. (C) 9. Focal length of fist lens, (µ ) f µ Focal length of second lens, (µ ) f ( µ ) So focal length of the combination, 5
16 W Code + f f f µ µ f f µ µ µ ( µ ) NEET UG Question Pape TAGET Publications 4. Fo a nomal eye, the conea of eye povides a conveging powe of 4 D and the least conveging powe of the eye lens behind the conea is D. Using this infomation, the distance between the etina and the conea - eye lens can be estimated to be 5 cm ().5 cm (C).67 cm (D).5 cm 4. (C) 4. lens + conea foms an image of distance object at etina. conveging powe (4+) D 6 D Fom Lens equation, 6 v v 5 cm v.67 cm. 4. In Young s double slit expeiment, the slits ae mm apat and ae illuminated by photons of two wavelengths λ Å and λ Å. At what minimum distance fom the common cental bight finge on the sceen m fom the slit will a bight finge fom one intefeence patten coincide with a bight finge fom the othe? 8 mm () 6 mm (C) 4 mm (D) mm 4. () nλd nλd 4. d d n n λ λ A A 5 6 n 5 and n 6 nλd 5 Theefoe, x 6 m 6 mm d 4. A paallel beam of fast moving electons is incident nomally on a naow slit. A fluoescent sceen is placed at a lage distance fom the slit. If the speed of the electons is inceased, which of the following statements is coect? Diffaction patten is not obseved on the sceen in the case of electons. () The angula width of the cental maximum of the diffaction patten will incease. (C) The angula width of the cental maximum will decease. (D) The angula width of the cental maximum will be unaffected. 4. (C) 4. h Now, λ mv 6 λ v Theefoe, as speed of electon inceases, its de-oglie wavelength deceases.
17 TAGET Publications Angula width fo cental maximum is given as, ω λ d NEET UG Question Pape ω λ v if speed of electon inceases, angula width of cental maximum will deceases. 4. In a n-type semiconducto, which of the following statement is tue? Electons ae majoity caies and tivalent atoms ae dopants () Electon ae minoity caies and pentavalent atoms ae dopants (C) Holes ae minoity caies and pentavalent atoms ae dopants (D) Holes ae majoity caies and tivalent atoms ae dopants 4. (C) 4. In N-type semiconductos, minoity caies ae holes, majoity caies ae electons and pentavalent atoms ae dopants. 44. In a common emitte (CE) amplifie having a voltage gain G, the tansisto used has tansconductance. mho and cuent gain 5. If the above tansisto is eplaced with anothe one with tansconductance. mho and cuent gain, the voltage gain will be G ().5 G (C) G (D) 5 4 G 44. o 44. A v β in IC o I in Ico Vin g m o A v g m. AV A gm. g. V A V m A V G. 45. The output (X) of the logic cicuit shown in figue will be A X X A. () X A. (C) X A. (D) X A+ 45. (C) 45. A Y X X A A A A y A. A. 7
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