Chezy s Resistance Coefficient in a Circular Conduit

Size: px
Start display at page:

Download "Chezy s Resistance Coefficient in a Circular Conduit"

Transcription

1 Send Orders for eprints to Te Open Civil Engineering Journal Cezy s esistance Coefficient in a Circular Conduit Open Access Bacir Acour esearc Laboratory in Subterranean and Surface Hydraulics University of Biskra PO Box 15 P Biskra Algeria Abstract: In te literature tere is no explicit metod for calculating te resistance coefficient of Cezy especially for a circular conduit. Existing relationsips are eiter implicit or do not take into account all parameters influencing tlow suc as kinematic viscosity or te slope of te conduit. In many practical cases one affects arbitrarily a constant valuor Cezy s coefficient. It is a pysically unjustified approac because Cezy s coefficient varies wit flow parameters especially tilling rate of te conduit and te absolute rougness. In tis paper simple and explicit relationsips are presented for te calculation of Cezy s resistance coefficient in a circular conduit. Tese relationsips ave been establised based on te roug model metod. Te Cezy s resistance coefficient is expressed in terms of known ydraulic parameters of tlow in a referential roug model. For fast calculation of Cezy s coefficient te simplified metod is te most appropriate since it requires only four parameters wic are te discarge te absolute rougness te slope and te kinematic viscosity. Te study also sows tat te Cezy s resistance coefficient reaces a maximum wose expression is well defined. Some examples are presented sowing ow to calculate Cezys coefficient in a circular conduit wit a minimum practical data. Keywords: Cezy s coefficient circular conduit discarge energy slope ydraulic radius roug model metod. 1. INTODUCTION eferring to te literature we can see tat few formulae exist for expressing Cezy s resistance coefficient C. Te most frequently cited are te old formulae of Guanguillet- Kutter [1] Bazin [2] and Powell []. Tese relationsips are well summarized and discussed by Cow []. Te Guanguillet-Kutter formula expresses C in terms of te ydraulic radius te coefficient of rougness n known as Kutter s n and te slope S. In Englis units tis formula is: C = S n n 1 S " Tis relationsip does not contain a term relating to te kinematic viscosity. Tus it can not be applied to te entire domain of turbulent flow. Its application seems to be restricted to te roug domain for wic te kinematic viscosity as no effect. Bazin formula expresses te coefficient C as a function of ydraulic radius but not of te slope S. Tis formula is: Address correspondence to tis autor at te esearc Laboratory in Subterranean and Surface Hydraulics University of Biskra PO Box 15 P Biskra Algeria; Tel: ; Fax: ; bacir.acour@laryss.net C = 87 1 m 2 Were m is a coefficient of rougness wose values are given by a table as a function of te type of te material forming te cannel or te conduit. As for te Guanguillet- Kutter formula Bazin formula contains no terms of kinematic viscosity. It does not terefore apply to te wole domain of turbulent flow. Te Powell formula is more complete as it contains te ydraulic radius te absolute rougness ε and te eynolds number. However tis formula is implicit expressing C as: C C = 2 log " According to tis relationsip C depends especially on te eynolds number and terefore on te kinematic viscosity ν. In tis relation tere is no term tat expresses te influence of te slope S on te coefficient C. Its application seems to be suitablor te entire domain of turbulent flow. It is interesting to note tat Powell formula contains te absolute rougness ε wic is a measurable parameter in practice. To determine te coefficient C by te Powell formula it is necessary to use a trial-and-error procedure. More recently Swamee and atie [5] ave attempted to propose a general relationsip for Cezy s coefficient C / Bentam Open

2 188 Te Open Civil Engineering Journal 2015 Volume 9 Bacir Acour applicable in te entire domain of turbulent flow and for all sapes of cannels and conduits. However tis relationsip is implicit requiring also a trial-and-error procedure especially wen te linear dimension of te cannel or conduit is not given or wen it comes to compute te normal dept of tlow. Swamee and atie suggested for C a logaritmic formula as: C = 2.57 " g ln gs Apart from its implicit form tis relationsip as te advantage of being very complete. All tlow parameters are included in tis relationsip. According to te literature several tests were performed on corrugated pipes or large scale rougness in cannels of non circular cross section tat ave not led to a convincing formula for Cezy s coefficient. Among tese studies we can mention tose of Streeter [6] Ead and al. [7] Pyle and Novak [8] Marone [9] Perry and al. [10] Naot and al. [11]. More recently Giustolisi [12] used a genetic programming to determine Cezy s resistance coefficient for full circular corrugated cannels. For commercial pipes or artificial cannels te literature does not indicate specific studies. Tat is wy tis article is proposed wic aims to establis simple relationsips for calculating Cezy s coefficient based on practical data. Te calculation approac is based on te roug model metod MM tat as been proven in te recent past by contributing successfully to te design of conduits and cannels and to te calculation of normal dept [1-25]. Two explicit metods of calculating Cezy s coefficient are proposed. Tirst metod considers tilling rate of te conduit wile te second one is more simplified. It takes no account of tilling rate of te conduit or its diameter. Bot metods give similar results. In tis article examples are provided to better appreciate te ease of te metod and calculation. 2. HYDAULIC POPETIES Te caracteristics of tlow in a circular conduit partially occupied Fig. 1 are in particular: y n Fig. 1. Flow in a circular conduit. 1. Te wetted area: D A = D 2 1 2" 2 1 2" cos1 " 1 " 5 It tus appears tat te wetted area is depending on te diameter D of te conduit and tilling rate = y n / D were y n is te normal dept. Eq. 5 can be written as: A = D 2 were: " " 6 " = cos 1 1 2" 7 " 1 " 2 1 2" " = 1 cos 1 1 2" For a circular conduit completely filled corresponding to = 1 one can deducrom Eq. 7 and Eq. 8 respectively tat "=1= and " = 1=1. 2. Te Wetted perimeter P = D cos 1 1 2" 9 Tis can be written simply as: P = D " 10. Te ydraulic radius = A / P is tus: = D " 11. GENEAL ELATIONSHIP OF CHEZY S ESIS- TANCE COEFFICIENT Cezy s relation gives te discarge Q as: Q = CA S 12 To igligt te variation of Cezy s coefficient based on all parameters governing tlow Acour and Bedjaoui formula [2] is very useful. Tis relationsip applicable to all geometric profiles was establised in te wole domain of turbulent flow encompassing smoot transition and roug regimes. According to Acour and Bedjaoui [2] te discarge Q is given by tollowing formula: " Q g A S log were S is te slope of te conduit is a eynolds number ε is te absolute rougness and g is te acceleration due to gravity. Te eynolds number is governed by tollowing equation: = 2 2 g S were ν is te kinematic viscosity. 8 1

3 Cezy s esistance Coefficient in a Circular Conduit Te Open Civil Engineering Journal 2015 Volume Inserting Eq. 11 into Eq. 1 leads to: g S D " / 2 15 For a circular conduit completely filled te ydraulic radius is = D /. Tus Eq. 1 becomes: g S D 16 Te subscript f refers to tull state of te conduit. Taking into account Eq. 16 Eq. 15 can be rewritten as: = " / 2 17 Comparing Eq. 12 and Eq. 1 it is obvious tat Cezy s coefficient is suc tat: C = C C g g " 2g log or in dimensionless form : " log Inserting Eq. 11 and Eq. 17 into Eq. 19 leads to: log. / It tus appears tat C depends on te relative rougness / D tilling rate and te eynolds number. Wen tese parameters are given relation 20 allows te explicit determination of te coefficient C. However wen it comes to design te conduit D is not a given data and only Q η S ε and ν are te known parameters. In tis case Eq. 20 does not allow determining explicitly te coefficient C. However tis problem can be solved using te roug model metod MM.. COMPUTATION OF CHEZY S ESISTANCE CO- EFFICIENT.1. Te oug Model Metod Te roug model is a circular conduit of diameter D greater tan D in wic tlow is caracterized by a friction factor f = 1 / 16 arbitrarily cosen. Tis ig friction factor implies tat tlow in te model is roug. In te roug model te discarge is Q te slope is S te kinematic viscosity is ν and tilling rate is. Taking into account tat Cezy s resistance coefficient in te roug model is C = 8g / f one may write: C = 8 2g = constant 21 According to te MM [1 2 25] D and D are related by tollowing equation: D = D 22 were is a non-dimensional correction factor of linear dimension less tan unity. It was demonstrated tat can be written as: = 16 f 1/5 2 = 1.5 "log / /./ "2 / 5 2 were and are respectively te ydraulic radius and te eynolds number in te roug model. Te Cezy s resistance coefficient C and triction factor f are as C = C = 8 8g / f. As a result Eq. 2 leads to: 2g 5 / 2 25 wic can be rewritten as: C = C 26 5 / 2 Inserting Eq. 11 and Eq. 17 into Eq. 2 leads to: - / D = 1.50"log / 1 / 2 0 / 1. "2 / 5 Combining Eq. 25 and Eq. 27 one can write: C = 5. g log. / Te eynolds number is given by Eq. 16 as: g S D Eq. 28 will be used wen te diameter D of te conduit is not a given data of te problem. Te coefficient C is explicitly calculated provided te discarge Q te slope S te absolute rougness ε and tilling rate η are given. To express te diameter D apply Cezy s relation to te roug model. Hence:

4 190 Te Open Civil Engineering Journal 2015 Volume 9 Bacir Acour Q = C A S 0 Taking into account Eq. 6 Eq. 11 and Eq. 21 Eq. 0 leads to: D = 2 " 0.6 Q ". g S - 1 Eq. 1 permits a direct determination of te diameter D since Q S and g are te known parameters of te problem. Tus all relationsips are establised for te explicit determination of te Cezy s coefficient C troug te following steps provided Q S g and are given: 1. For te given value of tilling rate compute " and " according to Eq. 7 and Eq. 8 respectively. 2. For te given values of Q S and g compute te diameter D of te roug model by applying Eq. 1.. For te given values of D S g and Eq. 29 gives te eynolds number.. Finally using Eq. 28 Cezy s resistance coefficient C is worked out for te known values of ε D and g..2. Example 1 For tollowing data compute Cezy s resistance coefficient: Q m / s = " 6 2 = 10 m / s. S = " 10 " = 10 m 0. 6 = 1. According to Eq. 7 and Eq. 8 " and " are respectively: " = cos 1 1 2" = = cos cos " = 1 " 1 cos 1 2 " " 1 2 " " = 1 = In accordance wit te relationsip 1 te diameter D of te roug model is: D = 2 " ["] 0.6 Q g S. - 0 " = " = m. Applying Eq. 29 te eynolds number is ten : = 2 = g S D " "6. Finally according to Eq. 28 te Cezy s resistance coefficient C is: C = 5. g log = 5. " 9.81 " [ ] / 2 log 10 / " " / 2 = m 0.5 / s 79.8 m 0.5 / s.. Simplified Metod In wat follows a simplified metod is proposed for fast calculation of Cezy s coefficient C wit a reduced number of data. Neiter te diameter D of te conduit nor tilling rate is required. Only four parameters are needed to evaluate Cezy s coefficient namely te discarge Q te slope S te absolute rougness ε and te kinematic viscosityν. All tese parameters are easily measurable in practice. Tis simplified metod also based on te teory of te roug model causes a maximum relative deviation of about 1.25 compared to te metod described in section.1. Tis relative deviation is less tan te relative error wit wic te absolute rougness is measured in practice. Assuming " and applying Eq. 1 for te roug model leads to: Q = 2 " " Were Q = Q / / 2 Q is te relative conductivity expressed as: 5 gs D 2

5 Cezy s esistance Coefficient in a Circular Conduit Te Open Civil Engineering Journal 2015 Volume Consider a referential roug model aving a diameter D equal to tat of tull-model state corresponding to = 1; Eq. 7 and Eq. 8 give respectively " = and " = 1. As a result Eq. 2 leads to Q = 2. For tis value of te relative conductivity Eq. 2 indicates a second value of tilling rate equal to " We tus obtain a roug model wit a diameter equal to tat of tull-model state caracterized by tilling rate " Consequently te wetted perimeter P and te ydraulic radius are given by Eq. 9 and Eq. 11 respectively as: P = 2.52D = 0.01D 5 Te diameter D of tull roug model is obtained for te relative conductivity Q = " Q D = 2 gs 2 implying wat follows: 6 Te calculation of Cezy s coefficient is readily carried out using tollowing steps: 1. Compute te diameter D of tull model using Eq Compute ten te wetted perimeter P and te ydraulic radius by te use of Eq. and Eq. 5 respectively.. Te eynolds number = Q / P in te roug model is ten worked out.. Wit te computed values of and e te nondimensional correction factor ψ is explicitly determined using Eq Finally Cezy s coefficient C is directly deduced from Eq Example 2 Let us consider te data of example 1 to compute Cezy s resistance coefficient using te simplified metod. Q = m " " 6 2 / s S = " 10 = 10 m = 10 m / s. 1. According to Eq. 6 te diameter D of tull roug model is: " Q D = 2 gs = " " "10 = m 2. Using Eq. and Eq. 5 te wetted perimeter P and te ydraulic radius are respectively: P = 2.52D = =.17116m = 0.01D = = m. Te eynolds number in te roug model is: = Q / P = " / " 10 6 = According to Eq. 2 te non-dimensional correction factor ψ is ten: = 1.5 "log / /./ "2 / 5 = 1.5 "log 10" / = "2 / 5 5. Using Eq. 25 te required value of Cezy s coefficient is: C = 8 2g = 8 " 2 " 9.81 = / / 2 m0.5 / s Tus comparing tis result wit tat obtained in example 1 we can observe tat te relative deviation is less tan 0.9 only. 5. MAXIMUM OF CHEZY S COEFFICIENT 5.1. General elationsip According to Eq. 20 te Cezy s resistance coefficient C depends on tree dimensionless variables namely te relative rougness / D tilling rate of te conduit and te eynolds number. Its grapical representation is not easy but it can be sown as an indication its variation for a fixed value of te relative rougness / D. Tis as been performed for different values of / D and for eynolds number varying between 10 and Among all te obtained graps tose of Figs. 1 and 2 are representative. Fig. 2 translates te variation of C / g versus tilling rate and te eynolds number for te value / D = 0 corresponding to a smoot

6 192 Te Open Civil Engineering Journal 2015 Volume 9 Bacir Acour f C/ g Fig. 2. Variation of C / g versus and according to Eq. 20 for / D = 0. Maximum value / g obtained for " f C/ g Fig.. Variation of C / g versus and according to Eq. 20 for / D = Maximum value / g obtained for " inner wall of te conduit. Fig. sows te variation of C / g versus tilling rate and te eynolds number for te value / D = corresponding to a state of te roug inner wall of te conduit. Te cosen values of te relative rougness / D correspond in fact to te extreme values of te Moody diagram. Fig. 2 clearly sows tat for a given value of te eynolds number C / g increases wit te increase of tilling rate up to a maximum value represented by te full sign on tigure. Beyond tis maximum value C / g decreases wit te increase of tilling rate and te decrease continues until tull state of te conduit corresponding to = 1. It sould also be noted tat watever te value of te cange in C / g according to is carried out rapidly at first and undergoes a sligt variation in a second time. Te rapid variation of C / g is observed for a narrow range of tat can be defined as 0 " 0.2. Beyond te value = 0. 2 C / g undergoes a very slow cange in a wide range of independently of te value of te eynolds number. Tis state of cange can also be seen in Fig. 2. It also indicates tat for te ig cosen rougness value / D = te variation curves of C / g versus are very close to eac oter and mergor te values Tis igligts te roug state of tlow were C / almost independent of te eynolds number 5 > 10. g is and depends solely on te value of tilling rate of te conduit. Te calculation reveals tat Cezy s coefficient is te samor te particular values = 0.5 and = 1. In te range 0.5 " " 1 tere are two normal depts for te same value of C wic is owever very close to te maximum value due to te low variation of te curve. Te most significant result obtained wen plotting te variation of C / number g as a function of and te eynolds lies in tact tat te maximum value is acieved for tilling rate " watever te value of te relative rougness / D and tat of te eynolds number. In oter words te maximum value of

7 Cezy s esistance Coefficient in a Circular Conduit Te Open Civil Engineering Journal 2015 Volume 9 19 C / g and tus C max. is acieved at normal dept y n 081D. For = tunction " defined by Eq. 8 takes tollowing value: " = 1 cos = Inserting tis value in Eq. 20 leads to: g or: = log g log wen / D and are te known parameters of te problem Eq. 8 permits a direct determination of te maximum Cezy s resistance coefficient. Wen te diameter D of te conduit is not given te determination of te maximum of Cezy s resistance coefficient is possible by te use of Eq. 28 in wic ϕη = Hence: = 5. g log According to Eq. 9 te maximum of Cezy s resistance coefficient is related to te known parameters of tlow in te roug model wic can be ten calculated in a simple manner even if te conduit diameter D is not given. Tollowing examples sow te steps for calculating te maximum of Cezy s resistance coefficient Example Compute te maximum value of Cezy s coefficient for tollowing data: " D = 1.5m ; = 10 m ; " 6 2 S = " 10 ; = 10 m / s 1. According to Eq. 16 te eynolds number e f tull state of te conduit is ten: = g S D for = " 2 " 9.81" " 10 " Finally applying Eq. 8 one may obtain: 10 6 = 2g log " 2 " 9.81 " log 10 / = m / s 5.. Example Compute te maximum value of Cezy s resistance coefficient in a circular conduit for tollowing data: Q m / s = " 6 2 = 10 m / s. S = " = " = 10 m 1. According to Eq. 7 and Eq. 8 " and " are respectively : " " 1 1 = cos 1 2 = cos = " 1 " 2 1 2" " = 1 cos 1 1 2" " 0.65 " " 1 2 " 0.65 = 1 cos " 0.65 = Eq. 1 gives te diameter D of te roug model as: D = 2 " " = Q ". g S " = m. According to Eq. 29 te eynolds number full state of te roug model is ten : = 2 = g S D " "6 for te

8 19 Te Open Civil Engineering Journal 2015 Volume 9 Bacir Acour. As a result Eq. 9 leads to: = 5. g log = 5. " 9.81 " log 10 / = 80 m 0. 5 / s 6. CONCLUSION Using te general discarge relationsip te expression of Cezy s coefficient C was establised for a circular conduit. Te obtained expression clearly sowed tat C depends on te relative rougness ε/d tilling rate η of te conduit and te eynolds number f caracterizing tull state of tlow. Tis in turn depends on te slope S te diameter D of te conduit and te kinematic viscosityν. All parameters influencing tlow are represented in te expression of C unlike current relationsips. Wen all tese parameters are given te resulting expression is used to calculate explicitly te required value of C. Wen te diameter D of te conduit is not a given data of te problem te explicit calculation of C is still possible troug te use of te roug model metod. C is ten expressed as a function of te known parameters of tlow in te roug model. In tis case te calculation of C requires te discarge Q te slope S te absolute rougness ε tilling rate η and te kinematic viscosity ν. Wen te user does not ave all te data of te problem te explicit calculation of C is still possible tanks to te simplified metod tat was clearly described. Tis metod uses te minimum measurable data in practice wic are te discarge Q te slope S te absolute rougness ε and kinematic viscosityν. Tis simplified metod gives very satisfactory results. Te paper was completed by te particular study of te coefficient C. Te grapical representation sowed a rapid increase in te range 0 < " 0.2. It also sowed a sligt increase in C beyond = 0. 2 and ten reaced a maximum at tilling rate η = C ten undergoes a sligt diminution to tull state of te conduit corresponding to = 1. ABBEVIATIONS A = Water area C = Cezy s coefficient D = Diameter of te conduit D = Diameter of te roug model D = Hydraulic diameter f = Friction factor g = Acceleration due to gravity S = Slope of te conduit P = Wetted perimeter Q = Discarge Q = elative conductivity = eynolds number f = eynolds number at tull state of te conduit = Hydraulic radius y n = Normal dept ε = Absolute rougness η = Filling rate equal to y / n ψ = Non-dimensional correction factor ν = kinematic viscosity CONFLICT OF INTEEST Te autor confirms tat tis article content as no conflict of interest. ACKNOWLEDGEMENTS Declared none. EFEENCES [1] E. Ganguillet and W. Kutter An investigation to establis a new general formula for uniform flow of water in canals and rivers Zeitscrift des Oesterreiciscen Ingenieur und Arcitekten Vereines vol. 21 no. 1 pp no.2- pp [2] H. Bazin Etude d une nouvellormule pour calculer le débit des canaux découverts Annales des ponts et causses vol. 1 ser.7 ème trimestre pp [].W. Powell esistance to flow in roug cannels Trans. Am. Geopys. Union vol. 1 no. pp [] V.T. Cow Ed. Open-Cannel Hydraulics. McGraw Hill: New York 197. [5] P. K. Swamee and P.N. atie Exact solutions for normal dept problem J. Hydraul. es. vol. 2 no. 5 pp [6] V.L. Streeter Frictional resistance in artificially rougened pipes Trans. ASCE vol. 101 pp [7] S.A. Ead N. ajaratnam C. Katopodis and F. Ade Turbulent open-cannel flow in circular corrugated culverts J. Hydraul. Eng. vol. 126 no. 10 pp [8]. Pyle and P. Novak Coefficient of friction in conduits wit large rougness J. Hydraul. es. vol. 19 no. 2 pp [9] V. Marone Le resistenze al movimento uniforme in un alveo ciuso o aperto di sezione rettangolare e scabrezza definita L Energia Elettrica vol. 1 pp [10] A.E. Perry W.H. Scofield and P.N. Joubert oug wall turbulent boundary layers J. Fluid Mec. vol. 7 no. 2 pp [11] D. Naot I. Nezu and H. Nakagawa Hydrodynamic Beaviour of Partly Vegetated Open Cannels J. Hydraul. Eng. vol. 122 no. 11 pp [12] O. Giustolisi Using genetic programming to determine Cezy resistance coefficient in corrugated cannels J. Hydroinf. vol. 6 no. pp [1] B. Acour and S. Setal Te roug model metod MM. application to te computation of normal dept in circular conduit Open Civil Eng. J. vol. 8 pp [1] B. Acour and M. iabi Design of a pressurized trapezoidal saped conduit using te roug model metod Part 1 Adv. Mater. es. vols pp [15] B. Acour Computation of normal dept in trapezoidal open cannel using te roug model metod Adv. Mater. es. vol pp D

9 Cezy s esistance Coefficient in a Circular Conduit Te Open Civil Engineering Journal 2015 Volume [16] M. iabi and B. Acour Design of a pressurized circular pipe wit bences using te roug model metod MM Adv. Mater. es. vol pp [17] B. Acour and A. Bedjaoui Design of a pressurized trapezoidal saped conduit using te roug model metod part 2 Appl. Mec. Mater. vol pp [18] B. Acour Computation of normal dept in orsesoe saped tunnel using te roug model metod Adv. Mater. es. vol pp [19] B. Acour Design of a pressurized rectangular conduit wit triangular bottom using te roug model metod Open Civil Eng. J. vol. 8 pp [20] B. Acour Computation of normal dept in parabolic cross sections using te roug model metod Open Civil Eng. J. vol. 8 pp [21] B. Acour Design of a pressurized rectangular-saped conduit using te roug model metod Appl. Mec. Mater. vol pp [22] B. Acour and M. Kattaoui Design of pressurized vaulted rectangular conduits using te roug model metod part 2 Adv. Mater. es. vol pp [2] B. Acour and A. Bedjaoui Discussion. exact solutions for normal dept problem J. Hydraul. es. vol. no. 5 pp [2] B. Acour and A. Bedjaoui Turbulent pipe-flow computation using te roug model metod MM J. Civil Eng. Sci. vol. 1 no. 1 pp [25] B. Acour Design of pressurized vaulted rectangular conduits using te roug model metod Adv. Mater. es. vol pp eceived: December evised: Marc Accepted: Marc Bacir Acour; Licensee Bentam Open. Tis is an open access article licensed under te terms of te Creative Commons Attribution Non-Commercial License ttp://creativecommons.org/licenses/ by-nc/.0/ wic permits unrestricted non-commercial use distribution and reproduction in any medium provided te work is properly cited.

A = h w (1) Error Analysis Physics 141

A = h w (1) Error Analysis Physics 141 Introduction In all brances of pysical science and engineering one deals constantly wit numbers wic results more or less directly from experimental observations. Experimental observations always ave inaccuracies.

More information

Distribution of reynolds shear stress in steady and unsteady flows

Distribution of reynolds shear stress in steady and unsteady flows University of Wollongong Researc Online Faculty of Engineering and Information Sciences - Papers: Part A Faculty of Engineering and Information Sciences 13 Distribution of reynolds sear stress in steady

More information

Hydraulic validation of the LHC cold mass heat exchanger tube.

Hydraulic validation of the LHC cold mass heat exchanger tube. Hydraulic validation o te LHC cold mass eat excanger tube. LHC Project Note 155 1998-07-22 (pilippe.provenaz@cern.c) Pilippe PROVENAZ / LHC-ACR Division Summary Te knowledge o te elium mass low vs. te

More information

Velocity distribution in non-uniform/unsteady flows and the validity of log law

Velocity distribution in non-uniform/unsteady flows and the validity of log law University of Wollongong Researc Online Faculty of Engineering and Information Sciences - Papers: Part A Faculty of Engineering and Information Sciences 3 Velocity distribution in non-uniform/unsteady

More information

Part 2: Introduction to Open-Channel Flow SPRING 2005

Part 2: Introduction to Open-Channel Flow SPRING 2005 Part : Introduction to Open-Cannel Flow SPRING 005. Te Froude number. Total ead and specific energy 3. Hydraulic jump. Te Froude Number Te main caracteristics of flows in open cannels are tat: tere is

More information

ADCP MEASUREMENTS OF VERTICAL FLOW STRUCTURE AND COEFFICIENTS OF FLOAT IN FLOOD FLOWS

ADCP MEASUREMENTS OF VERTICAL FLOW STRUCTURE AND COEFFICIENTS OF FLOAT IN FLOOD FLOWS ADCP MEASUREMENTS OF VERTICAL FLOW STRUCTURE AND COEFFICIENTS OF FLOAT IN FLOOD FLOWS Yasuo NIHEI (1) and Takeiro SAKAI (2) (1) Department of Civil Engineering, Tokyo University of Science, 2641 Yamazaki,

More information

Continuous formulation for bottom friction in free surface flows modelling

Continuous formulation for bottom friction in free surface flows modelling River Basin Management V 81 Continuous formulation for bottom friction in free surface flows modelling O. Maciels 1, S. Erpicum 1, B. J. Dewals 1, 2, P. Arcambeau 1 & M. Pirotton 1 1 HACH Unit, Department

More information

Theoretical Analysis of Flow Characteristics and Bearing Load for Mass-produced External Gear Pump

Theoretical Analysis of Flow Characteristics and Bearing Load for Mass-produced External Gear Pump TECHNICAL PAPE Teoretical Analysis of Flow Caracteristics and Bearing Load for Mass-produced External Gear Pump N. YOSHIDA Tis paper presents teoretical equations for calculating pump flow rate and bearing

More information

1 1. Rationalize the denominator and fully simplify the radical expression 3 3. Solution: = 1 = 3 3 = 2

1 1. Rationalize the denominator and fully simplify the radical expression 3 3. Solution: = 1 = 3 3 = 2 MTH - Spring 04 Exam Review (Solutions) Exam : February 5t 6:00-7:0 Tis exam review contains questions similar to tose you sould expect to see on Exam. Te questions included in tis review, owever, are

More information

1. Consider the trigonometric function f(t) whose graph is shown below. Write down a possible formula for f(t).

1. Consider the trigonometric function f(t) whose graph is shown below. Write down a possible formula for f(t). . Consider te trigonometric function f(t) wose grap is sown below. Write down a possible formula for f(t). Tis function appears to be an odd, periodic function tat as been sifted upwards, so we will use

More information

The Verlet Algorithm for Molecular Dynamics Simulations

The Verlet Algorithm for Molecular Dynamics Simulations Cemistry 380.37 Fall 2015 Dr. Jean M. Standard November 9, 2015 Te Verlet Algoritm for Molecular Dynamics Simulations Equations of motion For a many-body system consisting of N particles, Newton's classical

More information

Math 1241 Calculus Test 1

Math 1241 Calculus Test 1 February 4, 2004 Name Te first nine problems count 6 points eac and te final seven count as marked. Tere are 120 points available on tis test. Multiple coice section. Circle te correct coice(s). You do

More information

Derivatives of Exponentials

Derivatives of Exponentials mat 0 more on derivatives: day 0 Derivatives of Eponentials Recall tat DEFINITION... An eponential function as te form f () =a, were te base is a real number a > 0. Te domain of an eponential function

More information

CHAPTER (A) When x = 2, y = 6, so f( 2) = 6. (B) When y = 4, x can equal 6, 2, or 4.

CHAPTER (A) When x = 2, y = 6, so f( 2) = 6. (B) When y = 4, x can equal 6, 2, or 4. SECTION 3-1 101 CHAPTER 3 Section 3-1 1. No. A correspondence between two sets is a function only if eactly one element of te second set corresponds to eac element of te first set. 3. Te domain of a function

More information

232 Calculus and Structures

232 Calculus and Structures 3 Calculus and Structures CHAPTER 17 JUSTIFICATION OF THE AREA AND SLOPE METHODS FOR EVALUATING BEAMS Calculus and Structures 33 Copyrigt Capter 17 JUSTIFICATION OF THE AREA AND SLOPE METHODS 17.1 THE

More information

Combining functions: algebraic methods

Combining functions: algebraic methods Combining functions: algebraic metods Functions can be added, subtracted, multiplied, divided, and raised to a power, just like numbers or algebra expressions. If f(x) = x 2 and g(x) = x + 2, clearly f(x)

More information

1 The concept of limits (p.217 p.229, p.242 p.249, p.255 p.256) 1.1 Limits Consider the function determined by the formula 3. x since at this point

1 The concept of limits (p.217 p.229, p.242 p.249, p.255 p.256) 1.1 Limits Consider the function determined by the formula 3. x since at this point MA00 Capter 6 Calculus and Basic Linear Algebra I Limits, Continuity and Differentiability Te concept of its (p.7 p.9, p.4 p.49, p.55 p.56). Limits Consider te function determined by te formula f Note

More information

Hydraulic Evaluation of Discharge Over Rock Closing Dams on the Upper Mississippi River

Hydraulic Evaluation of Discharge Over Rock Closing Dams on the Upper Mississippi River ydraulic Evaluation of Discarge Over Rock Closing Dams on te Upper Mississippi River Jon endrickson, P.E. Senior ydraulic Engineer, St Paul District Introduction Prototype data was used for calibrating

More information

Chapter 2 Limits and Continuity

Chapter 2 Limits and Continuity 4 Section. Capter Limits and Continuity Section. Rates of Cange and Limits (pp. 6) Quick Review.. f () ( ) () 4 0. f () 4( ) 4. f () sin sin 0 4. f (). 4 4 4 6. c c c 7. 8. c d d c d d c d c 9. 8 ( )(

More information

Comment on Experimental observations of saltwater up-coning

Comment on Experimental observations of saltwater up-coning 1 Comment on Experimental observations of saltwater up-coning H. Zang 1,, D.A. Barry 2 and G.C. Hocking 3 1 Griffit Scool of Engineering, Griffit University, Gold Coast Campus, QLD 4222, Australia. Tel.:

More information

SECTION 3.2: DERIVATIVE FUNCTIONS and DIFFERENTIABILITY

SECTION 3.2: DERIVATIVE FUNCTIONS and DIFFERENTIABILITY (Section 3.2: Derivative Functions and Differentiability) 3.2.1 SECTION 3.2: DERIVATIVE FUNCTIONS and DIFFERENTIABILITY LEARNING OBJECTIVES Know, understand, and apply te Limit Definition of te Derivative

More information

Math 34A Practice Final Solutions Fall 2007

Math 34A Practice Final Solutions Fall 2007 Mat 34A Practice Final Solutions Fall 007 Problem Find te derivatives of te following functions:. f(x) = 3x + e 3x. f(x) = x + x 3. f(x) = (x + a) 4. Is te function 3t 4t t 3 increasing or decreasing wen

More information

MTH-112 Quiz 1 Name: # :

MTH-112 Quiz 1 Name: # : MTH- Quiz Name: # : Please write our name in te provided space. Simplif our answers. Sow our work.. Determine weter te given relation is a function. Give te domain and range of te relation.. Does te equation

More information

f a h f a h h lim lim

f a h f a h h lim lim Te Derivative Te derivative of a function f at a (denoted f a) is f a if tis it exists. An alternative way of defining f a is f a x a fa fa fx fa x a Note tat te tangent line to te grap of f at te point

More information

Section 2.7 Derivatives and Rates of Change Part II Section 2.8 The Derivative as a Function. at the point a, to be. = at time t = a is

Section 2.7 Derivatives and Rates of Change Part II Section 2.8 The Derivative as a Function. at the point a, to be. = at time t = a is Mat 180 www.timetodare.com Section.7 Derivatives and Rates of Cange Part II Section.8 Te Derivative as a Function Derivatives ( ) In te previous section we defined te slope of te tangent to a curve wit

More information

Some Review Problems for First Midterm Mathematics 1300, Calculus 1

Some Review Problems for First Midterm Mathematics 1300, Calculus 1 Some Review Problems for First Midterm Matematics 00, Calculus. Consider te trigonometric function f(t) wose grap is sown below. Write down a possible formula for f(t). Tis function appears to be an odd,

More information

Order of Accuracy. ũ h u Ch p, (1)

Order of Accuracy. ũ h u Ch p, (1) Order of Accuracy 1 Terminology We consider a numerical approximation of an exact value u. Te approximation depends on a small parameter, wic can be for instance te grid size or time step in a numerical

More information

Lecture XVII. Abstract We introduce the concept of directional derivative of a scalar function and discuss its relation with the gradient operator.

Lecture XVII. Abstract We introduce the concept of directional derivative of a scalar function and discuss its relation with the gradient operator. Lecture XVII Abstract We introduce te concept of directional derivative of a scalar function and discuss its relation wit te gradient operator. Directional derivative and gradient Te directional derivative

More information

Continuity and Differentiability Worksheet

Continuity and Differentiability Worksheet Continuity and Differentiability Workseet (Be sure tat you can also do te grapical eercises from te tet- Tese were not included below! Typical problems are like problems -3, p. 6; -3, p. 7; 33-34, p. 7;

More information

Solution for the Homework 4

Solution for the Homework 4 Solution for te Homework 4 Problem 6.5: In tis section we computed te single-particle translational partition function, tr, by summing over all definite-energy wavefunctions. An alternative approac, owever,

More information

2.11 That s So Derivative

2.11 That s So Derivative 2.11 Tat s So Derivative Introduction to Differential Calculus Just as one defines instantaneous velocity in terms of average velocity, we now define te instantaneous rate of cange of a function at a point

More information

Simulation and verification of a plate heat exchanger with a built-in tap water accumulator

Simulation and verification of a plate heat exchanger with a built-in tap water accumulator Simulation and verification of a plate eat excanger wit a built-in tap water accumulator Anders Eriksson Abstract In order to test and verify a compact brazed eat excanger (CBE wit a built-in accumulation

More information

A.P. CALCULUS (AB) Outline Chapter 3 (Derivatives)

A.P. CALCULUS (AB) Outline Chapter 3 (Derivatives) A.P. CALCULUS (AB) Outline Capter 3 (Derivatives) NAME Date Previously in Capter 2 we determined te slope of a tangent line to a curve at a point as te limit of te slopes of secant lines using tat point

More information

Section 15.6 Directional Derivatives and the Gradient Vector

Section 15.6 Directional Derivatives and the Gradient Vector Section 15.6 Directional Derivatives and te Gradient Vector Finding rates of cange in different directions Recall tat wen we first started considering derivatives of functions of more tan one variable,

More information

Numerical Differentiation

Numerical Differentiation Numerical Differentiation Finite Difference Formulas for te first derivative (Using Taylor Expansion tecnique) (section 8.3.) Suppose tat f() = g() is a function of te variable, and tat as 0 te function

More information

Problem Solving. Problem Solving Process

Problem Solving. Problem Solving Process Problem Solving One of te primary tasks for engineers is often solving problems. It is wat tey are, or sould be, good at. Solving engineering problems requires more tan just learning new terms, ideas and

More information

Logarithmic functions

Logarithmic functions Roberto s Notes on Differential Calculus Capter 5: Derivatives of transcendental functions Section Derivatives of Logaritmic functions Wat ou need to know alread: Definition of derivative and all basic

More information

Chapter 5 FINITE DIFFERENCE METHOD (FDM)

Chapter 5 FINITE DIFFERENCE METHOD (FDM) MEE7 Computer Modeling Tecniques in Engineering Capter 5 FINITE DIFFERENCE METHOD (FDM) 5. Introduction to FDM Te finite difference tecniques are based upon approximations wic permit replacing differential

More information

1. Which one of the following expressions is not equal to all the others? 1 C. 1 D. 25x. 2. Simplify this expression as much as possible.

1. Which one of the following expressions is not equal to all the others? 1 C. 1 D. 25x. 2. Simplify this expression as much as possible. 004 Algebra Pretest answers and scoring Part A. Multiple coice questions. Directions: Circle te letter ( A, B, C, D, or E ) net to te correct answer. points eac, no partial credit. Wic one of te following

More information

Click here to see an animation of the derivative

Click here to see an animation of the derivative Differentiation Massoud Malek Derivative Te concept of derivative is at te core of Calculus; It is a very powerful tool for understanding te beavior of matematical functions. It allows us to optimize functions,

More information

3. Gradually-Varied Flow

3. Gradually-Varied Flow 5/6/18 3. Gradually-aried Flow Normal Flow vs Gradually-aried Flow Normal Flow /g EGL (energy grade line) iction slope Geometric slope S Normal flow: Downslope component of weigt balances bed friction

More information

Introduction to Derivatives

Introduction to Derivatives Introduction to Derivatives 5-Minute Review: Instantaneous Rates and Tangent Slope Recall te analogy tat we developed earlier First we saw tat te secant slope of te line troug te two points (a, f (a))

More information

HOW TO DEAL WITH FFT SAMPLING INFLUENCES ON ADEV CALCULATIONS

HOW TO DEAL WITH FFT SAMPLING INFLUENCES ON ADEV CALCULATIONS HOW TO DEAL WITH FFT SAMPLING INFLUENCES ON ADEV CALCULATIONS Po-Ceng Cang National Standard Time & Frequency Lab., TL, Taiwan 1, Lane 551, Min-Tsu Road, Sec. 5, Yang-Mei, Taoyuan, Taiwan 36 Tel: 886 3

More information

MATH CALCULUS I 2.1: Derivatives and Rates of Change

MATH CALCULUS I 2.1: Derivatives and Rates of Change MATH 12002 - CALCULUS I 2.1: Derivatives and Rates of Cange Professor Donald L. Wite Department of Matematical Sciences Kent State University D.L. Wite (Kent State University) 1 / 1 Introduction Our main

More information

HEADLOSS ESTIMATION. Mekanika Fluida 1 HST

HEADLOSS ESTIMATION. Mekanika Fluida 1 HST HEADLOSS ESTIMATION Mekanika Fluida HST Friction Factor : Major losses Laminar low Hagen-Poiseuille Turbulent (Smoot, Transition, Roug) Colebrook Formula Moody diagram Swamee-Jain 3 Laminar Flow Friction

More information

On the Concept of Returns to Scale: Revisited

On the Concept of Returns to Scale: Revisited 3 J. Asian Dev. Stud, Vol. 5, Issue, (Marc 206) ISSN 2304-375X On te Concept of Returns to Scale: Revisited Parvez Azim Abstract Tis paper sows w it is tat in Economics text books and literature we invariabl

More information

Chapter 2 Limits and Continuity. Section 2.1 Rates of Change and Limits (pp ) Section Quick Review 2.1

Chapter 2 Limits and Continuity. Section 2.1 Rates of Change and Limits (pp ) Section Quick Review 2.1 Section. 6. (a) N(t) t (b) days: 6 guppies week: 7 guppies (c) Nt () t t t ln ln t ln ln ln t 8. 968 Tere will be guppies ater ln 8.968 days, or ater nearly 9 days. (d) Because it suggests te number o

More information

NOTES ON OPEN CHANNEL FLOW

NOTES ON OPEN CHANNEL FLOW NOTES ON OPEN CANNEL FLOW Prof. Marco Pilotti Facoltà di Ingegneria, Università degli Studi di Brescia Profili di moto permanente in un canale e in una serie di due canali - Boudine, 86 OPEN CANNEL FLOW:

More information

5.1 We will begin this section with the definition of a rational expression. We

5.1 We will begin this section with the definition of a rational expression. We Basic Properties and Reducing to Lowest Terms 5.1 We will begin tis section wit te definition of a rational epression. We will ten state te two basic properties associated wit rational epressions and go

More information

Week #15 - Word Problems & Differential Equations Section 8.2

Week #15 - Word Problems & Differential Equations Section 8.2 Week #1 - Word Problems & Differential Equations Section 8. From Calculus, Single Variable by Huges-Hallett, Gleason, McCallum et. al. Copyrigt 00 by Jon Wiley & Sons, Inc. Tis material is used by permission

More information

1. Questions (a) through (e) refer to the graph of the function f given below. (A) 0 (B) 1 (C) 2 (D) 4 (E) does not exist

1. Questions (a) through (e) refer to the graph of the function f given below. (A) 0 (B) 1 (C) 2 (D) 4 (E) does not exist Mat 1120 Calculus Test 2. October 18, 2001 Your name Te multiple coice problems count 4 points eac. In te multiple coice section, circle te correct coice (or coices). You must sow your work on te oter

More information

(a) At what number x = a does f have a removable discontinuity? What value f(a) should be assigned to f at x = a in order to make f continuous at a?

(a) At what number x = a does f have a removable discontinuity? What value f(a) should be assigned to f at x = a in order to make f continuous at a? Solutions to Test 1 Fall 016 1pt 1. Te grap of a function f(x) is sown at rigt below. Part I. State te value of eac limit. If a limit is infinite, state weter it is or. If a limit does not exist (but is

More information

NUMERICAL DIFFERENTIATION. James T. Smith San Francisco State University. In calculus classes, you compute derivatives algebraically: for example,

NUMERICAL DIFFERENTIATION. James T. Smith San Francisco State University. In calculus classes, you compute derivatives algebraically: for example, NUMERICAL DIFFERENTIATION James T Smit San Francisco State University In calculus classes, you compute derivatives algebraically: for example, f( x) = x + x f ( x) = x x Tis tecnique requires your knowing

More information

158 Calculus and Structures

158 Calculus and Structures 58 Calculus and Structures CHAPTER PROPERTIES OF DERIVATIVES AND DIFFERENTIATION BY THE EASY WAY. Calculus and Structures 59 Copyrigt Capter PROPERTIES OF DERIVATIVES. INTRODUCTION In te last capter you

More information

Polynomial Interpolation

Polynomial Interpolation Capter 4 Polynomial Interpolation In tis capter, we consider te important problem of approximatinga function fx, wose values at a set of distinct points x, x, x,, x n are known, by a polynomial P x suc

More information

The derivative function

The derivative function Roberto s Notes on Differential Calculus Capter : Definition of derivative Section Te derivative function Wat you need to know already: f is at a point on its grap and ow to compute it. Wat te derivative

More information

The Derivative The rate of change

The Derivative The rate of change Calculus Lia Vas Te Derivative Te rate of cange Knowing and understanding te concept of derivative will enable you to answer te following questions. Let us consider a quantity wose size is described by

More information

. h I B. Average velocity can be interpreted as the slope of a tangent line. I C. The difference quotient program finds the exact value of f ( a)

. h I B. Average velocity can be interpreted as the slope of a tangent line. I C. The difference quotient program finds the exact value of f ( a) Capter Review Packet (questions - ) KEY. In eac case determine if te information or statement is correct (C) or incorrect (I). If it is incorrect, include te correction. f ( a ) f ( a) I A. represents

More information

The entransy dissipation minimization principle under given heat duty and heat transfer area conditions

The entransy dissipation minimization principle under given heat duty and heat transfer area conditions Article Engineering Termopysics July 2011 Vol.56 No.19: 2071 2076 doi: 10.1007/s11434-010-4189-x SPECIAL TOPICS: Te entransy dissipation minimization principle under given eat duty and eat transfer area

More information

AN ANALYSIS OF AMPLITUDE AND PERIOD OF ALTERNATING ICE LOADS ON CONICAL STRUCTURES

AN ANALYSIS OF AMPLITUDE AND PERIOD OF ALTERNATING ICE LOADS ON CONICAL STRUCTURES Ice in te Environment: Proceedings of te 1t IAHR International Symposium on Ice Dunedin, New Zealand, nd t December International Association of Hydraulic Engineering and Researc AN ANALYSIS OF AMPLITUDE

More information

6. Non-uniform bending

6. Non-uniform bending . Non-uniform bending Introduction Definition A non-uniform bending is te case were te cross-section is not only bent but also seared. It is known from te statics tat in suc a case, te bending moment in

More information

Function Composition and Chain Rules

Function Composition and Chain Rules Function Composition and s James K. Peterson Department of Biological Sciences and Department of Matematical Sciences Clemson University Marc 8, 2017 Outline 1 Function Composition and Continuity 2 Function

More information

Differential Calculus (The basics) Prepared by Mr. C. Hull

Differential Calculus (The basics) Prepared by Mr. C. Hull Differential Calculus Te basics) A : Limits In tis work on limits, we will deal only wit functions i.e. tose relationsips in wic an input variable ) defines a unique output variable y). Wen we work wit

More information

Derivatives. By: OpenStaxCollege

Derivatives. By: OpenStaxCollege By: OpenStaxCollege Te average teen in te United States opens a refrigerator door an estimated 25 times per day. Supposedly, tis average is up from 10 years ago wen te average teenager opened a refrigerator

More information

REVIEW LAB ANSWER KEY

REVIEW LAB ANSWER KEY REVIEW LAB ANSWER KEY. Witout using SN, find te derivative of eac of te following (you do not need to simplify your answers): a. f x 3x 3 5x x 6 f x 3 3x 5 x 0 b. g x 4 x x x notice te trick ere! x x g

More information

1. State whether the function is an exponential growth or exponential decay, and describe its end behaviour using limits.

1. State whether the function is an exponential growth or exponential decay, and describe its end behaviour using limits. Questions 1. State weter te function is an exponential growt or exponential decay, and describe its end beaviour using its. (a) f(x) = 3 2x (b) f(x) = 0.5 x (c) f(x) = e (d) f(x) = ( ) x 1 4 2. Matc te

More information

Work and Energy. Introduction. Work. PHY energy - J. Hedberg

Work and Energy. Introduction. Work. PHY energy - J. Hedberg Work and Energy PHY 207 - energy - J. Hedberg - 2017 1. Introduction 2. Work 3. Kinetic Energy 4. Potential Energy 5. Conservation of Mecanical Energy 6. Ex: Te Loop te Loop 7. Conservative and Non-conservative

More information

HT TURBULENT NATURAL CONVECTION IN A DIFFERENTIALLY HEATED VERTICAL CHANNEL. Proceedings of 2008 ASME Summer Heat Transfer Conference HT2008

HT TURBULENT NATURAL CONVECTION IN A DIFFERENTIALLY HEATED VERTICAL CHANNEL. Proceedings of 2008 ASME Summer Heat Transfer Conference HT2008 Proceedings of 2008 ASME Summer Heat Transfer Conference HT2008 August 10-14, 2008, Jacksonville, Florida USA Proceedings of HT2008 2008 ASME Summer Heat Transfer Conference August 10-14, 2008, Jacksonville,

More information

Math 312 Lecture Notes Modeling

Math 312 Lecture Notes Modeling Mat 3 Lecture Notes Modeling Warren Weckesser Department of Matematics Colgate University 5 7 January 006 Classifying Matematical Models An Example We consider te following scenario. During a storm, a

More information

Exam 1 Review Solutions

Exam 1 Review Solutions Exam Review Solutions Please also review te old quizzes, and be sure tat you understand te omework problems. General notes: () Always give an algebraic reason for your answer (graps are not sufficient),

More information

Consider a function f we ll specify which assumptions we need to make about it in a minute. Let us reformulate the integral. 1 f(x) dx.

Consider a function f we ll specify which assumptions we need to make about it in a minute. Let us reformulate the integral. 1 f(x) dx. Capter 2 Integrals as sums and derivatives as differences We now switc to te simplest metods for integrating or differentiating a function from its function samples. A careful study of Taylor expansions

More information

MVT and Rolle s Theorem

MVT and Rolle s Theorem AP Calculus CHAPTER 4 WORKSHEET APPLICATIONS OF DIFFERENTIATION MVT and Rolle s Teorem Name Seat # Date UNLESS INDICATED, DO NOT USE YOUR CALCULATOR FOR ANY OF THESE QUESTIONS In problems 1 and, state

More information

Mathematics 5 Worksheet 11 Geometry, Tangency, and the Derivative

Mathematics 5 Worksheet 11 Geometry, Tangency, and the Derivative Matematics 5 Workseet 11 Geometry, Tangency, and te Derivative Problem 1. Find te equation of a line wit slope m tat intersects te point (3, 9). Solution. Te equation for a line passing troug a point (x

More information

Chapter 1 Functions and Graphs. Section 1.5 = = = 4. Check Point Exercises The slope of the line y = 3x+ 1 is 3.

Chapter 1 Functions and Graphs. Section 1.5 = = = 4. Check Point Exercises The slope of the line y = 3x+ 1 is 3. Capter Functions and Graps Section. Ceck Point Exercises. Te slope of te line y x+ is. y y m( x x y ( x ( y ( x+ point-slope y x+ 6 y x+ slope-intercept. a. Write te equation in slope-intercept form: x+

More information

SFU UBC UNBC Uvic Calculus Challenge Examination June 5, 2008, 12:00 15:00

SFU UBC UNBC Uvic Calculus Challenge Examination June 5, 2008, 12:00 15:00 SFU UBC UNBC Uvic Calculus Callenge Eamination June 5, 008, :00 5:00 Host: SIMON FRASER UNIVERSITY First Name: Last Name: Scool: Student signature INSTRUCTIONS Sow all your work Full marks are given only

More information

Time (hours) Morphine sulfate (mg)

Time (hours) Morphine sulfate (mg) Mat Xa Fall 2002 Review Notes Limits and Definition of Derivative Important Information: 1 According to te most recent information from te Registrar, te Xa final exam will be eld from 9:15 am to 12:15

More information

2.8 The Derivative as a Function

2.8 The Derivative as a Function .8 Te Derivative as a Function Typically, we can find te derivative of a function f at many points of its domain: Definition. Suppose tat f is a function wic is differentiable at every point of an open

More information

Cubic Functions: Local Analysis

Cubic Functions: Local Analysis Cubic function cubing coefficient Capter 13 Cubic Functions: Local Analysis Input-Output Pairs, 378 Normalized Input-Output Rule, 380 Local I-O Rule Near, 382 Local Grap Near, 384 Types of Local Graps

More information

A PHYSICAL MODEL STUDY OF SCOURING EFFECTS ON UPSTREAM/DOWNSTREAM OF THE BRIDGE

A PHYSICAL MODEL STUDY OF SCOURING EFFECTS ON UPSTREAM/DOWNSTREAM OF THE BRIDGE A PHYSICA MODE STUDY OF SCOURING EFFECTS ON UPSTREAM/DOWNSTREAM OF THE BRIDGE JIHN-SUNG AI Hydrotec Researc Institute, National Taiwan University Taipei, 1617, Taiwan HO-CHENG IEN National Center for Hig-Performance

More information

Section 2.1 The Definition of the Derivative. We are interested in finding the slope of the tangent line at a specific point.

Section 2.1 The Definition of the Derivative. We are interested in finding the slope of the tangent line at a specific point. Popper 6: Review of skills: Find tis difference quotient. f ( x ) f ( x) if f ( x) x Answer coices given in audio on te video. Section.1 Te Definition of te Derivative We are interested in finding te slope

More information

1 Calculus. 1.1 Gradients and the Derivative. Q f(x+h) f(x)

1 Calculus. 1.1 Gradients and the Derivative. Q f(x+h) f(x) Calculus. Gradients and te Derivative Q f(x+) δy P T δx R f(x) 0 x x+ Let P (x, f(x)) and Q(x+, f(x+)) denote two points on te curve of te function y = f(x) and let R denote te point of intersection of

More information

Excerpt from "Calculus" 2013 AoPS Inc.

Excerpt from Calculus 2013 AoPS Inc. Excerpt from "Calculus" 03 AoPS Inc. Te term related rates refers to two quantities tat are dependent on eac oter and tat are canging over time. We can use te dependent relationsip between te quantities

More information

= 0 and states ''hence there is a stationary point'' All aspects of the proof dx must be correct (c)

= 0 and states ''hence there is a stationary point'' All aspects of the proof dx must be correct (c) Paper 1: Pure Matematics 1 Mark Sceme 1(a) (i) (ii) d d y 3 1x 4x x M1 A1 d y dx 1.1b 1.1b 36x 48x A1ft 1.1b Substitutes x = into teir dx (3) 3 1 4 Sows d y 0 and states ''ence tere is a stationary point''

More information

How to Find the Derivative of a Function: Calculus 1

How to Find the Derivative of a Function: Calculus 1 Introduction How to Find te Derivative of a Function: Calculus 1 Calculus is not an easy matematics course Te fact tat you ave enrolled in suc a difficult subject indicates tat you are interested in te

More information

Open Channel Hydraulic

Open Channel Hydraulic Open Cannel Hydraulic Julien Caucat Associate Professor - Grenoble INP / ENSE3 - LEGI UMR 5519 julien.caucat@grenoble-inp.fr Winter session - 2015/2016 julien.caucat@grenoble-inp.fr Open Cannel Hydraulic

More information

ACCESS TO SCIENCE, ENGINEERING AND AGRICULTURE: MATHEMATICS 1 MATH00030 SEMESTER /2019

ACCESS TO SCIENCE, ENGINEERING AND AGRICULTURE: MATHEMATICS 1 MATH00030 SEMESTER /2019 ACCESS TO SCIENCE, ENGINEERING AND AGRICULTURE: MATHEMATICS MATH00030 SEMESTER 208/209 DR. ANTHONY BROWN 6. Differential Calculus 6.. Differentiation from First Principles. In tis capter, we will introduce

More information

Efficient algorithms for for clone items detection

Efficient algorithms for for clone items detection Efficient algoritms for for clone items detection Raoul Medina, Caroline Noyer, and Olivier Raynaud Raoul Medina, Caroline Noyer and Olivier Raynaud LIMOS - Université Blaise Pascal, Campus universitaire

More information

1 2 x Solution. The function f x is only defined when x 0, so we will assume that x 0 for the remainder of the solution. f x. f x h f x.

1 2 x Solution. The function f x is only defined when x 0, so we will assume that x 0 for the remainder of the solution. f x. f x h f x. Problem. Let f x x. Using te definition of te derivative prove tat f x x Solution. Te function f x is only defined wen x 0, so we will assume tat x 0 for te remainder of te solution. By te definition of

More information

Notes: DERIVATIVES. Velocity and Other Rates of Change

Notes: DERIVATIVES. Velocity and Other Rates of Change Notes: DERIVATIVES Velocity and Oter Rates of Cange I. Average Rate of Cange A.) Def.- Te average rate of cange of f(x) on te interval [a, b] is f( b) f( a) b a secant ( ) ( ) m troug a, f ( a ) and b,

More information

Bed form characteristics in a live bed alluvial channel

Bed form characteristics in a live bed alluvial channel Scientia Iranica A (2014) 21(6), 1773{1780 Sarif University of Tecnology Scientia Iranica Transactions A: Civil Engineering www.scientiairanica.com Bed form caracteristics in a live bed alluvial cannel

More information

2.1 THE DEFINITION OF DERIVATIVE

2.1 THE DEFINITION OF DERIVATIVE 2.1 Te Derivative Contemporary Calculus 2.1 THE DEFINITION OF DERIVATIVE 1 Te grapical idea of a slope of a tangent line is very useful, but for some uses we need a more algebraic definition of te derivative

More information

INTRODUCTION DEFINITION OF FLUID. U p F FLUID IS A SUBSTANCE THAT CAN NOT SUPPORT SHEAR FORCES OF ANY MAGNITUDE WITHOUT CONTINUOUS DEFORMATION

INTRODUCTION DEFINITION OF FLUID. U p F FLUID IS A SUBSTANCE THAT CAN NOT SUPPORT SHEAR FORCES OF ANY MAGNITUDE WITHOUT CONTINUOUS DEFORMATION INTRODUCTION DEFINITION OF FLUID plate solid F at t = 0 t > 0 = F/A plate U p F fluid t 0 t 1 t 2 t 3 FLUID IS A SUBSTANCE THAT CAN NOT SUPPORT SHEAR FORCES OF ANY MAGNITUDE WITHOUT CONTINUOUS DEFORMATION

More information

Chapters 19 & 20 Heat and the First Law of Thermodynamics

Chapters 19 & 20 Heat and the First Law of Thermodynamics Capters 19 & 20 Heat and te First Law of Termodynamics Te Zerot Law of Termodynamics Te First Law of Termodynamics Termal Processes Te Second Law of Termodynamics Heat Engines and te Carnot Cycle Refrigerators,

More information

Average Rate of Change

Average Rate of Change Te Derivative Tis can be tougt of as an attempt to draw a parallel (pysically and metaporically) between a line and a curve, applying te concept of slope to someting tat isn't actually straigt. Te slope

More information

Derivation Of The Schwarzschild Radius Without General Relativity

Derivation Of The Schwarzschild Radius Without General Relativity Derivation Of Te Scwarzscild Radius Witout General Relativity In tis paper I present an alternative metod of deriving te Scwarzscild radius of a black ole. Te metod uses tree of te Planck units formulas:

More information

3.4 Worksheet: Proof of the Chain Rule NAME

3.4 Worksheet: Proof of the Chain Rule NAME Mat 1170 3.4 Workseet: Proof of te Cain Rule NAME Te Cain Rule So far we are able to differentiate all types of functions. For example: polynomials, rational, root, and trigonometric functions. We are

More information

Critical control in transcritical shallow-water flow over two obstacles

Critical control in transcritical shallow-water flow over two obstacles Lougboroug University Institutional Repository Critical control in transcritical sallow-water flow over two obstacles Tis item was submitted to Lougboroug University's Institutional Repository by te/an

More information

3.1 Extreme Values of a Function

3.1 Extreme Values of a Function .1 Etreme Values of a Function Section.1 Notes Page 1 One application of te derivative is finding minimum and maimum values off a grap. In precalculus we were only able to do tis wit quadratics by find

More information

Key Concepts. Important Techniques. 1. Average rate of change slope of a secant line. You will need two points ( a, the formula: to find value

Key Concepts. Important Techniques. 1. Average rate of change slope of a secant line. You will need two points ( a, the formula: to find value AB Calculus Unit Review Key Concepts Average and Instantaneous Speed Definition of Limit Properties of Limits One-sided and Two-sided Limits Sandwic Teorem Limits as x ± End Beaviour Models Continuity

More information

Copyright c 2008 Kevin Long

Copyright c 2008 Kevin Long Lecture 4 Numerical solution of initial value problems Te metods you ve learned so far ave obtained closed-form solutions to initial value problems. A closedform solution is an explicit algebriac formula

More information