Chapter 2 Section 2.1 Practice Exercises x 2 x + 3 1

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1 Intermediate Algebra 7th Edition Martin Gay SOLUTIONS MANUAL Full download at: Intermediate Algebra 7th Edition Martin Gay TEST BANK Full download at: Chapter 2 Section 2.1 Practice Exercises x 2 x x + 7 = x = x 2 x x = x = x = x x 12 x 2 = 12 x = x = = 3 2.5t = 3 2.5t = 2.5t 0.5 = 2.5t 12 x ( x 2) = 3( x + 3) x x + 2 = 3x x + 2 = 3x x + 2 3x = 3x x 8x + 2 = 12 8x = x = = t 3. 8x x = 5x x 2 x 4 = x x 4 x = x + 11 x 3x 4 = 11 3x = x = 15 3 x 15 = 3 3 8x = x = x 0.03 = 0.2 x (0.15x 0.03) = 100(0.2 x ) 100(0.15x) 100(0.03) = 100(0.2 x) + 100(0.12) 15x 3 = 20 x x 20 x = x = 5 5x = ( x 5) = 6 x 3 5 x 15 = 5 5 3x 15 = 6 x 3 3x 15 6 x = 6 x 3 6 x 3x 15 = 3 3x = x 3 = 4( x + 5) 4 x 3 = 4 x + 20 x = 3 3x = 12 3 x = 12 4 x 3 4 x = 4 x x 3 = x = 4

2 5. y y 1 = y y 1 = y 2 20 y 5 = 5 10 y 4 y = 5 6 y = 5 6 y 5 = 6 6 y = 5 6 This equation is false no matter what value the variable x might have. Thus, there is no solution. The solution set is { } or. 9. 5x 2 = 3 + 5( x 1) 5x 2 = 3 + 5x 5 5x 2 = 2 + 5x 5x = 2 + 5x + 2 5x = 5x 5x 5x = 5x 5x 0 = 0 Since 0 = 0 is a true statement for every value of x, all real numbers are solutions. The solution set is the set of all real numbers or {x x is a real number}. 26 Copyright 2017 Pearson Education, Inc.

3 ISM: Intermediate Algebra Vocabulary, Readiness & Video Check Equations with the same solution set are called equivalent equations. 2. A value for the variable in an equation that makes the equation a true statement is called a solution of the equation. 3. By the addition property of equality, y = 3 and y 7 = 3 7 are equivalent equations. 4. By the multiplication property of equality, 5. 2y = 3 and 2 y = x 5 3 expression 6. 2(x 3) = 7 equation x + 1 = 2 x x x equation expression are equivalent equations. 9. The addition property of equality allows us to add the same number to (or subtract the same number from) both sides of an equation and have an equivalent equation. The multiplication property of equality allows us to multiply (or divide) both sides of an equation by the same nonzero number and have an equivalent equation. 10. distributive property 11. to make the calculations less tedious 12. When solving a linear equation and all variable terms subtract out and: a. you have a true statement, then the equation has all real numbers for which the equation is defined as solutions. b. you have a false statement, then the equation has no solution. Chapter 2: Equations, Inequalities, and Problem Solving Exercise Set x = 18 2 x 2 = 18 2 x = 9 Check: 2 x = 18 2( 9) = 18 True The solution is = y = y = y Check: 25 = y = 25 True The solution is y 8.6 = 6.3 y = y = 2.3 Check: y 8.6 = = 6.3 True The solution is y 3 = y 5y 3y = y = 14 2 y = y = 7 Check: 5y 3 = y 5(7) (7) = 32 True The solution is x = x 10.3 = x = x = x = 2.1 Check: x = (2.1) = 2.3 True The solution is 2.1.

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5 Chapter 2: Equations, Inequalities, and Problem Solving x + 14 = 6 x x 6 x = x = 6 2 x = (3n 2) n = 11(n 1) 12n + 8 n = 11n n + 8 = 11n n + 11n = 11 8 ISM: Intermediate Algebra 2 2 2n = 3 x = 3 Check: 4 x + 14 = 6 x + 8 4(3) (3) + 8 Check: 3 n = (3n 2) n = 11(n 1) 26 = 26 True The solution is x 15x + 8 = 4 x x + 8 = 4 x x 4 x = = 6 x = True Check: x = 5 The solution is 3. 13x 15x + 8 = 4 x (5) 15(5) + 8 4(5) x x 5 The solution is 5. 2 = 2 True x + x = x x = x + 6 5x = 0 x = 0 Check: 6 + 3x + x = x = x x = x + 4 x = x = 25 x = (0) = 6 True The solution is (4 x + 3) = 7 x + 5 8x + 6 = 7 x + 5 x + 6 = 5 x = 1 Check: 2(4 x + 3) = 7 x + 5 2(4( 1) + 3) 7( 1) + 5 2( 1) = 2 True The solution is x = 4( x 5) 6 x = 4 x 20 2 x = 20 x = 10 Check: 6 x = 4( x 5) 6( 10) 4( 10 5) Check: x + x = = True 0 = 60 True The solution 6 is ( 1 5 ) 6

6 26. T h e s o l u t i o n i s r r = r r = 10(7) (4r) r = 70 8r r = 70 7r = 70 r = 10

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8 ISM: Intermediate Algebra Chapter 2: Equations, Inequalities, and Problem Solving Check: 4r r = Check: 2 z = z + z (10) = 7 True The solution is h h = h + h 1 = h + 3(h 1) = h + 3h 3 = 3 4h 1 = 3 4h = 4 h = 1 Check: 2 + h + h 1 = ( 1 ) The solution is = 5 True (2 x + 3) = 0.1(2 x + 3) 10[2.4(2 x + 3)] = 10[ 0.1(2 x + 3)] 48x + 72 = 2 x 3 50 x = 75 x = 1.5 Check: 2.4(2 x + 3) = 0.1(2 x + 3) 2.4(2( 1.5) + 3) 0.1(2( 1.5) + 3) 2.4( 3 + 3) 0.1( 3 + 3) 2.4(0) 0.1(0) 0 = 0 True The solution is 1.5. The solution is = 3 3 True 36. 6(4n + 4) = 8(3 + 3n) 24n + 24 = n 24n n = n 24n x = 0.1x (0.3x + 2.4) = 10(0.1x + 4) 3x + 24 = 1x x = 16 x = 8 Check: 0.3x = 0.1x (8) (8) = 4.8 True The solution is z + 7 z 1 2 = z z = 8 z + z z = 8z + 4(z 1) 2z = 8z + 4z 4 2z 9 = 12z 4 10 z = 5 1 z = 2 24 = 24 0 = 0 Therefore, all real numbers are solutions ( x + 2) + 4 = 4 x 8 4 x = 4 x 8 4 x + 12 = 4 x 8 12 = 8 This is false for any x. Therefore, no solution exists, ( x 4) + x = 6( x 2) 8 5x 20 + x = 6 x x 20 = 6 x = 20 This is true for all x. Therefore, all real numbers are solutions ( x 2) = 8( x 3) + x 9 x 18 = 8x 24 + x 9 x 18 = 9 x = 24 This is false for any x. Therefore, no solution exists,. Copyright 2017 Pearson Education, Inc. 29

9 Chapter 2: Equations, Inequalities, and Problem Solving ISM: Intermediate Algebra 44. a + 7 = a + 7 = a + 7 = 20 2a = 13 a = x 7 = 2 x 7 4 x 2 x = x = 0 x = x + 2( x + 4) = 5( x + 1) + 3 3x + 2 x + 8 = 5x x + 8 = 5x = 0 Therefore, all real numbers are solutions. 50. (w + 0.2) = 0.3(4 w) w 0.2 = w w + 0.3w = w = 1.4 w = (8 + 2c) = (3c 5) c = c = c c = c c = c = c = c 54. 9c 3(6 5c) = c 2(3c + 9) 9c c = c 6c 18 24c 18 = 5c 18 24c + 5c = c = 0 c = 0 30 Copyright 2017 Pearson Education, Inc.

10 ISM: Intermediate Algebra Chapter 2: Equations, Inequalities, and Problem Solving x 2( x + 4) = 8( x 2) x 2 x 8 = 8x x 8 = 8x 10 8x 8x = = 2 This is false for any x. Therefore, the solution set is. n n = n n = (n + 1) 8(2 n) = 4(5) 3n n = 20 11n 13 = 20 11n = 33 n = y 18 4 y = 12 y 13 6 y 18 = 12 y 13 6 y 12 y = y = 5 5 y = (2 x 3) (10 x + 7) 2 = (12 x 5) (4 x + 9) 1 8x x 7 2 = 12 x x x + 3 = 16 x 5 2 x = 8 x = (2 y 1) 2 = (3y 5) (2 y 1) 2 = 10 1 (3y 5) (2 y 1) 20 = 5(3y 5) y 22 = 15y y = 27 y 27 = [8 4(n 2)] + 5n = [5(1 n) 6n] 3[8 4n + 8] + 5n = [5 5n 6n] 3(16 4n) + 5n = (5 11n) 48 12n + 5n = n 48 7n = 10 22n 15n = n = Sum means to add: The sum of 8 and a number: 8 + x Copyright 2017 Pearson Education, Inc. 31

11 Chapter 2: Equations, Inequalities, and Problem Solving ISM: Intermediate Algebra 70. The difference means to subtract. The difference of 8 and a number: 8 x 72. Two more than three times a number: 3x ( 4) = 12 not 12; 3( x 4) = 10 3x + 12 = 10 3x = 2 3 x 2 = 3 3 x = x + 7 = x + 21 not x + 7; 3 x 5x + 7 = x + 7 = 3 5x 3 3 x + 21 = 5x 21 = 4 x 21 4 x = = x x 3 = 5x 3 Since the two sides of the equation are identical, the equation is true for any value of x. All real numbers are solutions x 2 = 5x 7 Subtracting 2 from a number and subtracting 7 from the same number will not result in equal numbers for any value of x. There is no solution. 82. answers may vary 84. answers may vary y 10 = 1.1y y = 1.1y + 22 From this we see that K = x + 4 = x x + 4 = 6 x 6 3 x + 24 = 2 x From this we see that K = answers may vary 32 Copyright 2017 Pearson Education, Inc.

12 ISM: Intermediate Algebra Chapter 2: Equations, Inequalities, and Problem Solving x x 3 = 6 x( x + 4) + x 2 7 x x 3 = 6 x x + x 2 7 x x 3 = 7 x x 2 x 3 = 24 x 3 = 22 x x = x( x + 1) + 16 = x( x + 5) x 2 + x + 16 = x 2 + 5x x + 16 = 5x 16 = 4 x x = y = y = Check: y = (5.217) = True x = x = x = x = 9.62 Check: 1.25x = (9.62) = 8.15 True Section 2.2 Practice Exercises 1. a. In words: first integer plus second odd integer plus third odd integer Translate: x + (x + 2) + (x + 4) Then x + (x + 2) + (x + 4) = x + x x + 4 = 3x + 6 b. In words: side + side + side + side Translate: x + 2x + (x + 2) + (2x 3) Then x + 2x + (x + 2) + (2x 3) = x + 2x + x x 3 = 6x 1 Copyright 2017 Pearson Education, Inc. 33

13 Chapter 2: Equations, Inequalities, and Problem Solving ISM: Intermediate Algebra 2. If x = number of passengers at Los Angeles International Airport, in millions, then x = passengers at Chicago s O Hare airport, and 2x 31.9 = passengers at Atlanta s Hartsfield-Jackson airport. In words: passengers at + passengers + passengers at Los Angeles at O Hare Hartsfield-Jackson Translate: x + (x + 3.1) + (2x 31.9) Then x + (x + 3.1) + (2x 31.9) = x + x x 31.9 = 4x Let x = the first number, then 3x 8 = the second number, and 5x = the third number. The sum of the three numbers is 118. x + (3x 8) + 5x = 118 x + 3x + 5x 8 = x 8 = x = 126 x = 14 The numbers are 14, 3x 8 = 3(14) 8 = 34, and 5x = 5(14) = Let x = the original price. Then 0.4x = the discount. The original price, minus the discount, is equal to $270. x 0.4 x = x = 270 x = 270 = The original price was $ Let x = width, then 2x 16 = length. The perimeter is 160 inches. 2( x) + 2(2 x 16) = x + 4 x 32 = x 32 = x = 192 x = 32 2x 16 = 2(32) 16 = 48 The width is 32 inches and the length is 48 inches. 6. Let x = first odd integer, then x + 2 = second odd integer, and x + 4 = third odd integer. The sum of the integers is 81. x + ( x + 2) + ( x + 4) = 81 3x + 6 = 81 3x = 75 x = 25 x + 2 = 27 x + 4 = 29 The integers are 25, 27, and 29. Vocabulary, Readiness & Video Check % of a number > the number % of a number < the number. 34 Copyright 2017 Pearson Education, Inc.

14 ISM: Intermediate Algebra Chapter 2: Equations, Inequalities, and Problem Solving % of a number = the number % of a number > the number. First Integer All Described Integers 5. Four consecutive integers 6. Three consecutive odd integers 7. Three consecutive even integers 8. Four consecutive even integers 9. Three consecutive integers 10. Three consecutive even integers 11. Four consecutive integers 12. Three consecutive odd integers 31 31, 32, 33, , 33, , 20, , 94, 96, 98 y y, y + 1, y + 2 z (z is even) z, z + 2, z + 4 p p, p + 1, p + 2, p + 3 s (s is odd) s, s + 2, s distributive property 14. The original application asks you to find three numbers. The solution x = 45 only gives you the first number. You need to INTERPRET this result. Exercise Set The perimeter is the sum of the lengths of the four sides. x + ( x 5) + x + ( x 5) = x + x + x + x 5 5 = 4 x Let x = first odd integer, then x + 2 = second odd integer, and x + 4 = third odd integer. x + ( x + 2) + ( x + 4) = x + x + x = 3x Find the sum of y quarters worth 25 each, 7y dimes worth 10 each, and (2y 1) nickels worth 5 each. 25y + 10(7 y) + 5(2 y 1) = 105y 25y y + 10 y 5 The total amount is (105y 5) cents. 8. 4x + 5(3x 15) = 4x + 15x 75 = 19x The length of the side denoted by? is = 8. Similarly, the length of the unmarked side is (x + 14) (x + 8) = x + 14 x 8 = 6. The perimeter of the floor plan is 18 + (x + 8) (x + 14) = 2x + 64 Copyright 2017 Pearson Education, Inc. 35

15 Chapter 2: Equations, Inequalities, and Problem Solving 12. Let x = the number. 2( x + 3) = 5x 1 4 x 2 x + 6 = x 1 x = 7 The number is Let x = the first number, then x 6 = the second number, and 2x = the third number. x + ( x 6) + 2 x = x 6 = x = 312 x = 78 x 6 = 72 2x = 156 The numbers are 78, 72, and % of 70 = = = 7 7 million acres are not federally owned % of 881 = Approximately 284 tornadoes occurred in the United States during June Let x be the number of people employed in the restaurant industry. Then x is 10% of 147 million. x = 0.10(147 million) = 14.7 million There were 14.7 million people employed in the restaurant industry in the U.S. in From the circle graph, 39% of time is spent on role-specific tasks. 39% of 47 = An average worker would spend 18.3 hours on role-specific tasks. 24. The percents in the circle graph sum to 100% x x = 100 3x + 58 = 100 3x = 42 x = 14 2x = 2(14) = 28 28% of an average worker s time at work is spent on x + x + ( x + 10) = 180 5x + 10 = 180 5x = 170 x = 34 3x = 3(34) = 102 x + 10 = = 44 The angles measure 34, 44, and 102. ISM: Intermediate Algebra 28. (2 x) + (3.5x) + (3x + 7) = x + 7 = x = 68 x = 8 2x = 2(8) = x = 3.5(8) = 28 3x + 7 = 3(8) + 7 = 31 The sides measure 16 centimeters, 28 centimeters, and 31 centimeters x + (9.2 x 3) + 7.3x + (9.2 x 3) = x 6 = x = 330 x = x = 7.3(10) = x 3 = 9.2(10) 3 = 89 The sides measure 73 feet, 73 feet, 89 feet, and 89 feet. 32. Let x = the first odd integer, then x + 2 = the second odd integer and x + 4 = the third odd integer. x + x x + 4 = 327 3x + 6 = 327 3x = 321 x = 107 The numbers are 107, 109, Let x = first integer, then x + 1 = second integer, and x + 2 = third integer. x + ( x + 1) + 3( x + 2) = 2637 x + x x + 6 = x + 7 = x = 2630 x = 526 x + 1 = 527 x + 2 = 528 The score for Alabama was 526, for Louisiana was 527, and for Michigan was x + (3x 11) + (2 x + 11) = 66 x + 3x x + 11 = 66 6 x = 66 x = 11 3x 11 = 3(11) 11 = 22 2x + 11 = 2(11) + 11 = Copyright 2017 Pearson Education, Inc.

16 ISM: Intermediate Algebra Year Percent of Increase in Social Network Users Predicted Percent of Increase 2015 x 11% x 11 22% x % Total 66% 38. Let x be the decline in the number of travel agent jobs (in hundreds). Then x 17 is the decline in the number of reporter or correspondent jobs and 2x 21 is the decline in the number of flight attendant jobs. x + ( x 17) + (2 x 21) = 318 x + x x 21 = x 38 = 318 Chapter 2: Equations, Inequalities, and Problem Solving 44. Let x be the population in This population, decreased by 1.96%, is the 2014 population of 80.9 million. x x = x = 80.9 x 82.5 The population of Germany in 2004 was 82.5 million. 46. Let x be the size of the workforce prior to layoffs. 0.15x = 11, 000 x 73, 333 Prior to layoffs, Dana s workforce was 73,333 people. 48. Let x = measure of complement; then 2x + 30 = measure of angle. x + 2 x + 30 = 90 4 x = 356 3x = 60 x = 89 x = 20 x 17 = = 72 2x + 30 = 2(20) + 30 = 70 2x 21 = 2(89) 21 = 157 The angles measure 20 and 70. The predicted declines are: travel agent jobs: 89 hundred; 50. Let x = base angle; then 3x 10 = third angle. reporter or correspondent jobs: 72 hundred 2 x + 3x 10 = 180 flight attendant jobs: 157 hundred 5x 10 = Let x be the number of seats in Gillette Stadium. Then x + 11,200 is the number of seats in AT&T Stadium and x 3800 is the number of seats at CenturyLink Field. x + ( x + 11, 200) + ( x 3800) = 213, 800 x + x + 11, x 3800 = 213, 800 3x = 213, 800 3x = 206, 400 x = 68, 800 x + 11,200 = 68, ,200 = 80,000 x 3800 = 68, = 65,000 Gillette Stadium seats 68,800, AT&T Stadium seats 80,000, and CenturyLink Field seats 65, Let x be the price of the textbook before tax. x x = x = x The human anatomy book cost $ before tax. 5x = 190 x = 38 3x 10 = = 104 The angles measure 38, 38, and Let x = length of side of pentagon, then x + 7 = length of side of square. 5x = 4( x + 7) 5x = 4 x + 28 x = 28 x + 7 = = 35 The pentagon has a side length of 28 inches and the square has a side length of 35 inches. 54. Let x = first integer, then x + 1 = second integer, and x + 2 = third integer, and x + 3 = fourth integer. ( x + 1) + ( x + 3) = x + 4 = x = 106 x = 53 x + 1 = 54 x + 2 = 55 x + 3 = 56 The integers are 53, 54, 55, and 56. Copyright 2017 Pearson Education, Inc. 37

17 Chapter 2: Equations, Inequalities, and Problem Solving 56. Let x be the payroll for the Montreal Canadiens. Then x 5,049,585 was the payroll for the San Jose Sharks. x + ( x 5, 049, 585) = 129, 215, x 5, 049, 585 = 129, 215, x = 134, 265, 304 x = 67,132, 652 x 5, 049, 585 = 67,132, 652 5, 049, 585 = 62, 083, 067 The payroll for the Montreal Canadiens was $67,132,652 and the payroll for the San Jose Sharks was $62,083, Let x be the number of passengers at Los Angeles International Airport, in millions. Then x is the number of passengers at Chicago s O Hare airport, and 2x 31.9 is the number of passengers at Atlanta s Hartsfield- Jackson airport. x + ( x + 3.1) + (2 x 31.9) = x 28.8 = x = x = 63.7 x = = x 31.9 = 2(63.7) 31.9 = 95.5 The numbers of passengers are: Los Angeles: 63.7 million; Chicago: 66.8 million; Atlanta: 95.5 million 60. ( x + 2) + 2 x + x + (2 x 3) = x 1 = x = 111 x = 18.5 x + 2 = = x = 2(18.5) = 37 2x 3 = 2(18.5) 3 = 34 The bases measure 18.5 meters and 37 meters, and the sides measure 20.5 meters and 34 meters. 62. Let x be the energy cost of an LED bulb. Then x + 26 is the energy cost of a CFL bulb, and 6x + 18 is the energy cost of an incandescent bulb. x + ( x + 26) + (6 x + 18) = 476 8x + 44 = 476 8x = 432 x = 54 x + 26 = = 80 6x + 18 = 6(54) + 18 = 342 The energy costs are: LED bulb: $54 CFL bulb: $80 Incandescent bulb: $342 ISM: Intermediate Algebra 64. Let x be the number of medals won by the Netherlands. Then Canada won x + 1 medals and Norway won x + 2 medals. x + ( x + 1) + ( x + 2) = 75 3x + 3 = 75 3x = 72 x = 24 x + 1 = = 25 x + 2 = = 26 In the 2014 winter Olympics, the Netherlands won 24 medals, Canada won 25 medals, and Norway won 26 medals. 66. Let x = height, then 2x + 12 = length. 2( x) + 2(2 x + 12) = x + 4 x + 24 = x + 24 = x = 288 x = 48 2x + 12 = 2(48) + 12 = 108 The height is 48 inches and the length is 108 inches ab + 6bc = 0( 1) + 6( 1)(9) = 0 6(9) = 54 2n 2 + 3m 2 = 2( 2) 2 + 3(7) 2 = 2(4) + 3(49) = = lwh = 1 (37.8)(5.6)(7.9) = answers may vary 76. Let x be the measure of an angle. Then its complement measures (90 x) and its supplement measures (180 x). 180 x = 2(90 x) x = 180 2x x = x x = 230 x = 50 The angle measures y = 80.6x y = 80.6(17) The average number of cigarettes smoked by an American adult is predicted to be 684 in Copyright 2017 Pearson Education, Inc.

18 ISM: Intermediate Algebra 80. The average number of cigarettes smoked daily in 2017 is predicted to be This does not represent the average number of cigarettes smoked by an American smoker, because it is the average for all Americans, both smokers and non-smokers. 82. Let x be the first odd integer. Then x + 2 is the next consecutive odd integer. 7 x = 5( x + 2) x = 5x x = 5x x = x = 32 No such odd integers exist. R = C 60 x = 50 x x = 5000 x = x = 50(500) = 25, = 30, computer boards must be sold to break even. It costs $30,000 to produce the 500 boards. 86. The company makes a profit if it makes and sells more products than the break-even number. Section 2.3 Practice Exercises 1. I = PRT I = PRT PR PR I = T or T = PR I PR 2. 7 x 2 y = 5 7 x 2 y 7 x = 5 7 x 2 y = 5 7 x 2 y = 5 7 x 2 2 y = 7 x Chapter 2: Equations, Inequalities, and Problem Solving 3. A = P + Prt A P = P + Prt P A P = Prt A P Prt = Pt Pt A P A P = r or r = Pt Pt 4. Let P = 8000, r = 6% = 0.06, t = 4, n = 2. nt r A = P 1 + n A = A = 8000(1.03) 8 A 8000( ) A 10, Russ will have $10, in his account. 5. Let d = 190 and r = 7.5. d = rt 190 = 7.5t 190 = 7.5t = t 3 They spent 25 1 hours cycling, or 25 hours 3 20 minutes. Vocabulary, Readiness & Video Check x + y = 5 y = 5 2 x 2. 7 x y = 3 y = 3 7 x y = x or y = 7 x 3 3. a 5b = 8 a = 5b r + s = 10 s = 10 7r 5. 5 j + k h = 6 5 j + k = h + 6 k = h 5 j + 6 Copyright 2017 Pearson Education, Inc. 39

19 Chapter 2: Equations, Inequalities, and Problem Solving 6. w 4 y + z = 0 w + z = 4 y z = 4 y w 7. That the specified variable will equal some expression and that this expression should not contain the specified variable. 8. The only way to check the solution is in the formula used, because if the wrong formula is used, a wrong answer may seem to check correctly. Exercise Set W = gh W = gh h h W = g 10. y = mx + b y b = mx y b mx = m m x = y b m A = Prt + P A = P(rt + 1) A P(rt + 1) = rt + 1 rt + 1 A P = rt + 1 A = 5H (b + B) A = 5Hb + 5HB A 5HB = 5Hb A 5HB = 5Hb ISM: Intermediate Algebra h 5H 5H g = W h 4. V = lwh V lwh = wh wh 16. A 5HB = b 5H b = A 5HB 5H S = 2πr 2 + 2πrh V = l S 2 r 2 2 rh wh π = π l = V S 2πr 2 2πrh = wh 6. 2 x + 3y = 17 2 x + 3y 2 x = 17 2 x 3y = 17 2 x 3y = 17 2 x 2πr S 2πr 2 2πr h = = h 2πr S 2πr 2 2πr 3 3 y = 17 2 x 3 8. A = 3M 2 N A + 2N = 3M 2N = 3M A 2 N = 3M A 2 2 N = 3M A A = P(1 + rt) A = P + Prt A P = Prt A P Prt = Pr Pr A P = t Pr t = A P Pr

20 Intermediate Algebra 7th Edition Martin Gay SOLUTIONS MANUAL Full download at: Intermediate Algebra 7th Edition Martin Gay TEST BANK Full download at: intermediate algebra 7th edition pdf intermediate algebra 7th edition answers intermediate algebra 7th edition access code intermediate algebra 7th edition pdf free intermediate algebra 7th edition pearson beginning algebra 7th edition pdf beginning algebra 7th edition martin-gay pdf intermediate algebra martin-gay 6th edition