Complete Tripartite Graphs and their Competition Numbers

Size: px
Start display at page:

Download "Complete Tripartite Graphs and their Competition Numbers"

Transcription

1 Complete Tripartite Graphs and their Competition Numbers Jaromy Kuhl Department of Mathematics and Statistics University of West Florida Jaromy Kuhl (UWF) Competition Numbers 1 / 16

2 Competition Graphs Definition 1 Let D = (V, A) be a digraph. The competition graph of D is the simple graph G = (V, E) where {u, v} E if and only if N + (u) N + (v). Jaromy Kuhl (UWF) Competition Numbers 2 / 16

3 Competition Graphs Definition 1 Let D = (V, A) be a digraph. The competition graph of D is the simple graph G = (V, E) where {u, v} E if and only if N + (u) N + (v). The competition graph of D is denoted C(D). Jaromy Kuhl (UWF) Competition Numbers 2 / 16

4 Competition Graphs Definition 1 Let D = (V, A) be a digraph. The competition graph of D is the simple graph G = (V, E) where {u, v} E if and only if N + (u) N + (v). The competition graph of D is denoted C(D). Which graphs are competition graphs? Jaromy Kuhl (UWF) Competition Numbers 2 / 16

5 Let S = {S 1,..., S m } be a family of cliques in a graph G. Jaromy Kuhl (UWF) Competition Numbers 3 / 16

6 Let S = {S 1,..., S m } be a family of cliques in a graph G. S is an edge clique cover of G provided {u, v} E(G) if and only if {u, v} S i. Jaromy Kuhl (UWF) Competition Numbers 3 / 16

7 Let S = {S 1,..., S m } be a family of cliques in a graph G. S is an edge clique cover of G provided {u, v} E(G) if and only if {u, v} S i. θ e (G) = min{ S : S is an edge clique cover of G}. Jaromy Kuhl (UWF) Competition Numbers 3 / 16

8 Which graphs are competition graphs of acyclic digraphs? Jaromy Kuhl (UWF) Competition Numbers 4 / 16

9 Which graphs are competition graphs of acyclic digraphs? For sufficiently large k, G I k is the competition graph of an acyclic digraph. Jaromy Kuhl (UWF) Competition Numbers 4 / 16

10 Which graphs are competition graphs of acyclic digraphs? For sufficiently large k, G I k is the competition graph of an acyclic digraph. Definition 2 The competition number of G is k(g) = min{k : G I k is the competition graph of an acyclic digraph} Jaromy Kuhl (UWF) Competition Numbers 4 / 16

11 A digraph D = (V, A) is acyclic if and only if there is an ordering v 1, v 2,..., v n of the vertices in V such that if (v i, v j ) A, then i < j. Jaromy Kuhl (UWF) Competition Numbers 5 / 16

12 A digraph D = (V, A) is acyclic if and only if there is an ordering v 1, v 2,..., v n of the vertices in V such that if (v i, v j ) A, then i < j. G is the competition graph of an acyclic digraph if and only if there is an ordering v 1,..., v n and there is an edge clique cover {S 1,..., S n } such that S i {v 1,..., v i 1 } for each i. Jaromy Kuhl (UWF) Competition Numbers 5 / 16

13 Theorem 1 k(k n,n ) = n 2 2n + 2 Jaromy Kuhl (UWF) Competition Numbers 6 / 16

14 Theorem 1 k(k n,n ) = n 2 2n + 2 Theorem 2 k(k n,n,n ) = n 2 3n + 4 Jaromy Kuhl (UWF) Competition Numbers 6 / 16

15 Theorem 1 k(k n,n ) = n 2 2n + 2 Theorem 2 k(k n,n,n ) = n 2 3n + 4 Theorem 3 For positive integers x, y and z where 2 x y z, { yz 2y z + 4, if x = y k(k x,y,z ) = yz z y x + 3, if x y Jaromy Kuhl (UWF) Competition Numbers 6 / 16

16 Theorem 4 If n 5 is odd, then n 2 4n + 7 k(k 4 n ) n 2 4n + 8. Theorem 5 If n is prime and m n, then k(k m n ) n 2 2n + 3. Jaromy Kuhl (UWF) Competition Numbers 7 / 16

17 Theorem 6 k(k n,n,n ) = n 2 3n + 4 Proof. Let L be the latin square of order n such that (a, b, c) L if and only if c a + b 1 mod n. Consider the cliques (1, 1, 1), (2, n, 1), (1, n, n), (n, 1, n), (n, 2, 1), (1, 2, 2), and (n 1, 2, n), (2, n 1, n), (1, n 1, n 1), (n 2, 2, n 1), (2, n 2, n 1), (1, n 2, n 2),... Jaromy Kuhl (UWF) Competition Numbers 8 / 16

18 Consider K x,y,z (x y z). Jaromy Kuhl (UWF) Competition Numbers 9 / 16

19 Consider K x,y,z (x y z). Definition 3 An r-multi latin square of order n is an n n array of nr symbols such that each symbol appears once in each row and column and each cell contains r symbols. Jaromy Kuhl (UWF) Competition Numbers 9 / 16

20 K 2,4,6 Jaromy Kuhl (UWF) Competition Numbers 10 / 16

21 K 2,4,6 1,2 4,5 3,7 6,8 5,6 7,8 1,2 3,4 7,8 2,3 4,6 1,5 3,4 1,6 5,8 2,7 Jaromy Kuhl (UWF) Competition Numbers 10 / 16

22 K 2,4,6 1,2 4,5 3,7 6,8 5,6 7,8 1,2 3,4 7,8 2,3 4,6 1,5 3,4 1,6 5,8 2,7 1,2 4, ,4 1,6 5 2 Jaromy Kuhl (UWF) Competition Numbers 10 / 16

23 K 2,4,6 1,2 4,5 3,7 6,8 5,6 7,8 1,2 3,4 7,8 2,3 4,6 1,5 3,4 1,6 5,8 2,7 1,2 4, ,4 1,6 5 2 F = { (1, 1, 1), (1, 1, 2), (1, 2, 4), (1, 2, 5), (1, 3, 3), (1, 4, 6), (2, 1, 3), (2, 1, 4), (2, 2, 1), (2, 2, 6), (2, 3, 5), (2, 4, 2), Jaromy Kuhl (UWF) Competition Numbers 10 / 16

24 K 2,4,6 1,2 4,5 3,7 6,8 5,6 7,8 1,2 3,4 7,8 2,3 4,6 1,5 3,4 1,6 5,8 2,7 1,2 4, ,4 1,6 5 2 F = { (1, 1, 1), (1, 1, 2), (1, 2, 4), (1, 2, 5), (1, 3, 3), (1, 4, 6), (2, 1, 3), (2, 1, 4), (2, 2, 1), (2, 2, 6), (2, 3, 5), (2, 4, 2), (1, 5), (1, 6), (3, 1), (3, 2), (4, 3), (4, 4), (2, 2), (2, 3), (3, 4), (3, 6), (4, 1), (4, 5)} Jaromy Kuhl (UWF) Competition Numbers 10 / 16

25 Let q and r be positive integers such that z = qy + r. Jaromy Kuhl (UWF) Competition Numbers 11 / 16

26 Let q and r be positive integers such that z = qy + r. Let L be a (q + 1)-multi latin square of order y. Jaromy Kuhl (UWF) Competition Numbers 11 / 16

27 Let q and r be positive integers such that z = qy + r. Let L be a (q + 1)-multi latin square of order y. Let R = {r i : 1 i x} be a set of rows and let S = {s i : 1 i z} be a set of z symbols. Jaromy Kuhl (UWF) Competition Numbers 11 / 16

28 Let q and r be positive integers such that z = qy + r. Let L be a (q + 1)-multi latin square of order y. Let R = {r i : 1 i x} be a set of rows and let S = {s i : 1 i z} be a set of z symbols. Set L(R, C, S ) = {(r i, c j, s k ) : (r i, c j, s k ) L, r i R, s k S }. Jaromy Kuhl (UWF) Competition Numbers 11 / 16

29 Let q and r be positive integers such that z = qy + r. Let L be a (q + 1)-multi latin square of order y. Let R = {r i : 1 i x} be a set of rows and let S = {s i : 1 i z} be a set of z symbols. Set L(R, C, S ) = {(r i, c j, s k ) : (r i, c j, s k ) L, r i R, s k S }. Lemma 1 The family F = { (i, j, k) : (r i, c j, s k ) L(R, C, S )} { (j, k) : (r i, c j, s k ) L(R \ R, C, S )} is an edge clique cover of K x,y,z. Moreover, θ(k x,y,z ) = yz. Jaromy Kuhl (UWF) Competition Numbers 11 / 16

30 Theorem 7 For positive integers x, y and z where 2 x y z, { yz 2y z + 4, if x = y k(k x,y,z ) = yz z y x + 3, if x y Jaromy Kuhl (UWF) Competition Numbers 12 / 16

31 Theorem 7 For positive integers x, y and z where 2 x y z, { yz 2y z + 4, if x = y k(k x,y,z ) = yz z y x + 3, if x y Let L be a (q + 1)-multi latin square of order y such that (i, j, k) L if and only if i + j 1 k mod y. Jaromy Kuhl (UWF) Competition Numbers 12 / 16

32 Theorem 7 For positive integers x, y and z where 2 x y z, { yz 2y z + 4, if x = y k(k x,y,z ) = yz z y x + 3, if x y Let L be a (q + 1)-multi latin square of order y such that (i, j, k) L if and only if i + j 1 k mod y. Let R = {r 1,..., r x 1, r y } and let S = {s 1,..., s z }. Jaromy Kuhl (UWF) Competition Numbers 12 / 16

33 Example: x = 3, y = 5, z = 13 1,6,11 2,7,12 3,8,13 4,9,14 5,10,15 2,7,12 3,8,13 4,9,14 5,10,15 1,6,11 3,8,13 4,9,14 5,10,15 1,6,11 2,7,12 4,9,14 5,10,15 1,6,11 2,7,12 3,8,13 5,10,15 1,6,11 2,7,12 3,8,13 4,9,14 Jaromy Kuhl (UWF) Competition Numbers 13 / 16

34 Example: x = 3, y = 5, z = 13 1,6,11 2,7,12 3,8,13 4,9,14 5,10,15 2,7,12 3,8,13 4,9,14 5,10,15 1,6,11 3,8,13 4,9,14 5,10,15 1,6,11 2,7,12 4,9,14 5,10,15 1,6,11 2,7,12 3,8,13 5,10,15 1,6,11 2,7,12 3,8,13 4,9,14 1,6,11 2,7,12 3,8,13 4,9 5,10 2,7,12 3,8,13 4,9 5,10 1,6,11 5,10 1,6,11 2,7,12 3,8,13 4,9 Jaromy Kuhl (UWF) Competition Numbers 13 / 16

35 Case 1: x = y 1 = {u 1, v 1, w 1 }, 2 = {u 2, v y, w 1 }, 3 = {u 1, v y, w y }, 4 = {u y, v 1, w y }, 5 = {u y, v 2, w 1 }, 6 = {u 1, v 2, w 2 } Jaromy Kuhl (UWF) Competition Numbers 14 / 16

36 Case 1: x = y 1 = {u 1, v 1, w 1 }, 2 = {u 2, v y, w 1 }, 3 = {u 1, v y, w y }, 4 = {u y, v 1, w y }, 5 = {u y, v 2, w 1 }, 6 = {u 1, v 2, w 2 } 0 s y 4: 3s+7 = {u y s 1, v 2, w y s }, 3s+8 = {u 2, v y s 1, w y s }, and 3s+9 = {u 1, v y s 1, w y s 1 } Jaromy Kuhl (UWF) Competition Numbers 14 / 16

37 Case 1: x = y 1 = {u 1, v 1, w 1 }, 2 = {u 2, v y, w 1 }, 3 = {u 1, v y, w y }, 4 = {u y, v 1, w y }, 5 = {u y, v 2, w 1 }, 6 = {u 1, v 2, w 2 } 0 s y 4: 3s+7 = {u y s 1, v 2, w y s }, 3s+8 = {u 2, v y s 1, w y s }, and 3s+9 = {u 1, v y s 1, w y s 1 } 0 s z y 1: 3y 2+s = {u, v, w y+s+1 } Jaromy Kuhl (UWF) Competition Numbers 14 / 16

38 Case 2: x < y 1 = {u x, v 1, w y }, 2 = {v 2, w y }, 3 = {u x, v 2, w 1 }, 4 = {u 1, v 1, w 1 }, 5 = {u 1, v 2, w 2 }, 6 = {u 2, v 1, w 2 }, 7 = {u 2, v y, w 1 } Jaromy Kuhl (UWF) Competition Numbers 15 / 16

39 Case 2: x < y 1 = {u x, v 1, w y }, 2 = {v 2, w y }, 3 = {u x, v 2, w 1 }, 4 = {u 1, v 1, w 1 }, 5 = {u 1, v 2, w 2 }, 6 = {u 2, v 1, w 2 }, 7 = {u 2, v y, w 1 } 0 s y x 1: 2s+8 = {u x, v y s, w y s 1 }, and 2s+9 = {u 1, v y s 1, w y s 1 } Jaromy Kuhl (UWF) Competition Numbers 15 / 16

40 0 s x 4: 3s+2(y x)+8 = {u x s 1, v 2, w x s }, 3s+2(y x)+9 = {u 2, v x s 1, w x s }, and 3s+2(y x)+10 = {u 1, v x s 1, w x s 1 } 0 s z y 1: 2y+x 1+s = {u, v, w y+s+1 } Jaromy Kuhl (UWF) Competition Numbers 16 / 16

On completing partial Latin squares with two filled rows and at least two filled columns

On completing partial Latin squares with two filled rows and at least two filled columns AUSTRALASIAN JOURNAL OF COMBINATORICS Volume 68(2) (2017), Pages 186 201 On completing partial Latin squares with two filled rows and at least two filled columns Jaromy Kuhl Donald McGinn Department of

More information

x 9 or x > 10 Name: Class: Date: 1 How many natural numbers are between 1.5 and 4.5 on the number line?

x 9 or x > 10 Name: Class: Date: 1 How many natural numbers are between 1.5 and 4.5 on the number line? 1 How many natural numbers are between 1.5 and 4.5 on the number line? 2 How many composite numbers are between 7 and 13 on the number line? 3 How many prime numbers are between 7 and 20 on the number

More information

Part 23. Latin Squares. Contents. 1 Latin Squares. Printed version of the lecture Discrete Mathematics on 4. December 2012

Part 23. Latin Squares. Contents. 1 Latin Squares. Printed version of the lecture Discrete Mathematics on 4. December 2012 Part 23 Latin Squares Printed version of the lecture Discrete Mathematics on 4. December 2012 Tommy R. Jensen, Department of Mathematics, KNU 23.1 Contents 1 Latin Squares 1 2 Orthogonal Latin Squares

More information

Coloring. Basics. A k-coloring of a loopless graph G is a function f : V (G) S where S = k (often S = [k]).

Coloring. Basics. A k-coloring of a loopless graph G is a function f : V (G) S where S = k (often S = [k]). Coloring Basics A k-coloring of a loopless graph G is a function f : V (G) S where S = k (often S = [k]). For an i S, the set f 1 (i) is called a color class. A k-coloring is called proper if adjacent

More information

Latin Squares and Orthogonal Arrays

Latin Squares and Orthogonal Arrays School of Electrical Engineering and Computer Science University of Ottawa lucia@eecs.uottawa.ca Winter 2017 Latin squares Definition A Latin square of order n is an n n array, with symbols in {1,...,

More information

Construction of latin squares of prime order

Construction of latin squares of prime order Construction of latin squares of prime order Theorem. If p is prime, then there exist p 1 MOLS of order p. Construction: The elements in the latin square will be the elements of Z p, the integers modulo

More information

Problem Set 5 Solutions

Problem Set 5 Solutions Problem Set 5 Solutions Section 4.. Use mathematical induction to prove each of the following: a) For each natural number n with n, n > + n. Let P n) be the statement n > + n. The base case, P ), is true

More information

C 7 -DECOMPOSITIONS OF THE TENSOR PRODUCT OF COMPLETE GRAPHS

C 7 -DECOMPOSITIONS OF THE TENSOR PRODUCT OF COMPLETE GRAPHS Discussiones Mathematicae Graph Theory 37 (2017) 523 535 doi:10.7151/dmgt.1936 C 7 -DECOMPOSITIONS OF THE TENSOR PRODUCT OF COMPLETE GRAPHS R.S. Manikandan Department of Mathematics Bharathidasan University

More information

Additional Practice Lessons 2.02 and 2.03

Additional Practice Lessons 2.02 and 2.03 Additional Practice Lessons 2.02 and 2.03 1. There are two numbers n that satisfy the following equations. Find both numbers. a. n(n 1) 306 b. n(n 1) 462 c. (n 1)(n) 182 2. The following function is defined

More information

On the Existence of Transversals in r-multi Latin Squares

On the Existence of Transversals in r-multi Latin Squares On the Existence of Transversals in r-multi Latin Squares By Michael John Harris B.S. (Mathematics), Southern Polytechnic State University, 1998 B.S. (Computer Engineering), Southern Polytechnic State

More information

Mathematical Induction Assignments

Mathematical Induction Assignments 1 Mathematical Induction Assignments Prove the Following using Principle of Mathematical induction 1) Prove that for any positive integer number n, n 3 + 2 n is divisible by 3 2) Prove that 1 3 + 2 3 +

More information

(4.2) Equivalence Relations. 151 Math Exercises. Malek Zein AL-Abidin. King Saud University College of Science Department of Mathematics

(4.2) Equivalence Relations. 151 Math Exercises. Malek Zein AL-Abidin. King Saud University College of Science Department of Mathematics King Saud University College of Science Department of Mathematics 151 Math Exercises (4.2) Equivalence Relations Malek Zein AL-Abidin 1440 ه 2018 Equivalence Relations DEFINITION 1 A relation on a set

More information

Ma/CS 6a Class 28: Latin Squares

Ma/CS 6a Class 28: Latin Squares Ma/CS 6a Class 28: Latin Squares By Adam Sheffer Latin Squares A Latin square is an n n array filled with n different symbols, each occurring exactly once in each row and exactly once in each column. 1

More information

Solutions to Practice Final

Solutions to Practice Final s to Practice Final 1. (a) What is φ(0 100 ) where φ is Euler s φ-function? (b) Find an integer x such that 140x 1 (mod 01). Hint: gcd(140, 01) = 7. (a) φ(0 100 ) = φ(4 100 5 100 ) = φ( 00 5 100 ) = (

More information

Nordhaus-Gaddum Theorems for k-decompositions

Nordhaus-Gaddum Theorems for k-decompositions Nordhaus-Gaddum Theorems for k-decompositions Western Michigan University October 12, 2011 A Motivating Problem Consider the following problem. An international round-robin sports tournament is held between

More information

1 I A Q E B A I E Q 1 A ; E Q A I A (2) A : (3) A : (4)

1 I A Q E B A I E Q 1 A ; E Q A I A (2) A : (3) A : (4) Latin Squares Denition and examples Denition. (Latin Square) An n n Latin square, or a latin square of order n, is a square array with n symbols arranged so that each symbol appears just once in each row

More information

The candidates are advised that they must always show their working, otherwise they will not be awarded full marks for their answers.

The candidates are advised that they must always show their working, otherwise they will not be awarded full marks for their answers. MID SWEDEN UNIVERSITY TFM Examinations 2006 MAAB16 Discrete Mathematics B Duration: 5 hours Date: 7 June 2006 There are EIGHT questions on this paper and you should answer as many as you can in the time

More information

Automata Theory for Presburger Arithmetic Logic

Automata Theory for Presburger Arithmetic Logic Automata Theory for Presburger Arithmetic Logic References from Introduction to Automata Theory, Languages & Computation and Constraints in Computational Logic Theory & Application Presented by Masood

More information

Circles & Interval & Set Notation.notebook. November 16, 2009 CIRCLES. OBJECTIVE Graph a Circle given the equation in standard form.

Circles & Interval & Set Notation.notebook. November 16, 2009 CIRCLES. OBJECTIVE Graph a Circle given the equation in standard form. OBJECTIVE Graph a Circle given the equation in standard form. Write the equation of a circle in standard form given a graph or two points (one being the center). Students will be able to write the domain

More information

Mathathon Round 1 (2 points each)

Mathathon Round 1 (2 points each) Mathathon Round ( points each). A circle is inscribed inside a square such that the cube of the radius of the circle is numerically equal to the perimeter of the square. What is the area of the circle?

More information

5. Partitions and Relations Ch.22 of PJE.

5. Partitions and Relations Ch.22 of PJE. 5. Partitions and Relations Ch. of PJE. We now generalize the ideas of congruence classes of Z to classes of any set X. The properties of congruence classes that we start with here are that they are disjoint

More information

Pairs of a tree and a nontree graph with the same status sequence

Pairs of a tree and a nontree graph with the same status sequence arxiv:1901.09547v1 [math.co] 28 Jan 2019 Pairs of a tree and a nontree graph with the same status sequence Pu Qiao, Xingzhi Zhan Department of Mathematics, East China Normal University, Shanghai 200241,

More information

Discrete Structures, Final Exam

Discrete Structures, Final Exam Discrete Structures, Final Exam Monday, May 11, 2009 SOLUTIONS 1. (40 pts) Short answer. Put your answer in the box. No partial credit. [ ] 0 1 (a) If A = and B = 1 0 [ ] 0 0 1. 0 1 1 [ 0 1 1 0 0 1 ],

More information

Ma/CS 6a Class 28: Latin Squares

Ma/CS 6a Class 28: Latin Squares Ma/CS 6a Class 28: Latin Squares By Adam Sheffer Latin Squares A Latin square is an n n array filled with n different symbols, each occurring exactly once in each row and exactly once in each column. 1

More information

Math Homework # 4

Math Homework # 4 Math 446 - Homework # 4 1. Are the following statements true or false? (a) 3 5(mod 2) Solution: 3 5 = 2 = 2 ( 1) is divisible by 2. Hence 2 5(mod 2). (b) 11 5(mod 5) Solution: 11 ( 5) = 16 is NOT divisible

More information

Lecture 5: Latin Squares and Magic

Lecture 5: Latin Squares and Magic Latin Squares Instructor: Padraic Bartlett Lecture 5: Latin Squares and Magic Week Mathcamp 0 Today s application is to magic! Not the friendship kind though ; instead we re going to talk about magic squares

More information

MATH 2200 Final Review

MATH 2200 Final Review MATH 00 Final Review Thomas Goller December 7, 01 1 Exam Format The final exam will consist of 8-10 proofs It will take place on Tuesday, December 11, from 10:30 AM - 1:30 PM, in the usual room Topics

More information

McGill University Faculty of Science. Solutions to Practice Final Examination Math 240 Discrete Structures 1. Time: 3 hours Marked out of 60

McGill University Faculty of Science. Solutions to Practice Final Examination Math 240 Discrete Structures 1. Time: 3 hours Marked out of 60 McGill University Faculty of Science Solutions to Practice Final Examination Math 40 Discrete Structures Time: hours Marked out of 60 Question. [6] Prove that the statement (p q) (q r) (p r) is a contradiction

More information

Hadamard matrices and strongly regular graphs with the 3-e.c. adjacency property

Hadamard matrices and strongly regular graphs with the 3-e.c. adjacency property Hadamard matrices and strongly regular graphs with the 3-e.c. adjacency property Anthony Bonato Department of Mathematics, Wilfrid Laurier University, Waterloo, Ontario, Canada, N2L 3C5 abonato@wlu.ca

More information

On the Dynamic Chromatic Number of Graphs

On the Dynamic Chromatic Number of Graphs On the Dynamic Chromatic Number of Graphs Maryam Ghanbari Joint Work with S. Akbari and S. Jahanbekam Sharif University of Technology m_phonix@math.sharif.ir 1. Introduction Let G be a graph. A vertex

More information

PROBLEMS ON LINEAR ALGEBRA

PROBLEMS ON LINEAR ALGEBRA 1 Basic Linear Algebra PROBLEMS ON LINEAR ALGEBRA 1. Let M n be the (2n + 1) (2n + 1) for which 0, i = j (M n ) ij = 1, i j 1,..., n (mod 2n + 1) 1, i j n + 1,..., 2n (mod 2n + 1). Find the rank of M n.

More information

Number Theory and Graph Theory

Number Theory and Graph Theory 1 Number Theory and Graph Theory Chapter 5 Additional Topics By A. Satyanarayana Reddy Department of Mathematics Shiv Nadar University Uttar Pradesh, India E-mail: satya8118@gmail.com 2 Module-2: Pythagorean

More information

Remarks on the Thickness of K n,n,n

Remarks on the Thickness of K n,n,n Remarks on the Thickness of K n,n,n Yan Yang Department of Mathematics Tianjin University, Tianjin 30007, P.R.China yanyang@tju.edu.cn Abstract The thickness θ(g) of a graph G is the minimum number of

More information

a 2 + b 2 = (p 2 q 2 ) 2 + 4p 2 q 2 = (p 2 + q 2 ) 2 = c 2,

a 2 + b 2 = (p 2 q 2 ) 2 + 4p 2 q 2 = (p 2 + q 2 ) 2 = c 2, 5.3. Pythagorean triples Definition. A Pythagorean triple is a set (a, b, c) of three integers such that (in order) a 2 + b 2 c 2. We may as well suppose that all of a, b, c are non-zero, and positive.

More information

Maximum Alliance-Free and Minimum Alliance-Cover Sets

Maximum Alliance-Free and Minimum Alliance-Cover Sets Maximum Alliance-Free and Minimum Alliance-Cover Sets Khurram H. Shafique and Ronald D. Dutton School of Computer Science University of Central Florida Orlando, FL USA 3816 hurram@cs.ucf.edu, dutton@cs.ucf.edu

More information

Proof of a generalization of Aztec diamond theorem

Proof of a generalization of Aztec diamond theorem Proof of a generalization of Aztec diamond theorem Institute for Mathematics and its Applications University of Minnesota Minneapolis, MN 55455 December 5, 2014 Aztec Diamond Theorem Definition The Aztec

More information

0 Sets and Induction. Sets

0 Sets and Induction. Sets 0 Sets and Induction Sets A set is an unordered collection of objects, called elements or members of the set. A set is said to contain its elements. We write a A to denote that a is an element of the set

More information

Discrete Math, Spring Solutions to Problems V

Discrete Math, Spring Solutions to Problems V Discrete Math, Spring 202 - Solutions to Problems V Suppose we have statements P, P 2, P 3,, one for each natural number In other words, we have the collection or set of statements {P n n N} a Suppose

More information

MATH CSE20 Homework 5 Due Monday November 4

MATH CSE20 Homework 5 Due Monday November 4 MATH CSE20 Homework 5 Due Monday November 4 Assigned reading: NT Section 1 (1) Prove the statement if true, otherwise find a counterexample. (a) For all natural numbers x and y, x + y is odd if one of

More information

Decomposing oriented graphs into transitive tournaments

Decomposing oriented graphs into transitive tournaments Decomposing oriented graphs into transitive tournaments Raphael Yuster Department of Mathematics University of Haifa Haifa 39105, Israel Abstract For an oriented graph G with n vertices, let f(g) denote

More information

Discrete Mathematics. The edge spectrum of the saturation number for small paths

Discrete Mathematics. The edge spectrum of the saturation number for small paths Discrete Mathematics 31 (01) 68 689 Contents lists available at SciVerse ScienceDirect Discrete Mathematics journal homepage: www.elsevier.com/locate/disc The edge spectrum of the saturation number for

More information

A Level. A Level Mathematics. Proof by Contradiction (Answers) AQA, Edexcel, OCR. Name: Total Marks:

A Level. A Level Mathematics. Proof by Contradiction (Answers) AQA, Edexcel, OCR. Name: Total Marks: AQA, Edexcel, OCR A Level A Level Mathematics Proof by Contradiction (Answers) Name: Total Marks: A1 Proof Answers AQA, Edexcel, OCR 1) Prove that there is an infinite amount of prime numbers. Assume there

More information

Counterexamples to the List Square Coloring Conjecture

Counterexamples to the List Square Coloring Conjecture Counterexamples to the List Square Coloring Conjecture Boram Park National Institute for Mathematical Sciences (NIMS), Korea Joint work with Seog-Jin Kim Konkuk University, Korea Introduction Definition.

More information

Note on group distance magic complete bipartite graphs

Note on group distance magic complete bipartite graphs Cent. Eur. J. Math. 12(3) 2014 529-533 DOI: 10.2478/s11533-013-0356-z Central European Journal of Mathematics Note on group distance magic complete bipartite graphs Research Article Sylwia Cichacz 1 1

More information

Sydney University Mathematical Society Problems Competition Solutions.

Sydney University Mathematical Society Problems Competition Solutions. Sydney University Mathematical Society Problems Competition 005 Solutions 1 Suppose that we look at the set X n of strings of 0 s and 1 s of length n Given a string ɛ = (ɛ 1,, ɛ n ) X n, we are allowed

More information

Practice problems for first midterm, Spring 98

Practice problems for first midterm, Spring 98 Practice problems for first midterm, Spring 98 midterm to be held Wednesday, February 25, 1998, in class Dave Bayer, Modern Algebra All rings are assumed to be commutative with identity, as in our text.

More information

CO PRIME PATH DECOMPOSITION NUMBER OF A GRAPH

CO PRIME PATH DECOMPOSITION NUMBER OF A GRAPH An. Şt. Univ. Ovidius Constanţa Vol. 19(1), 011, 3 36 CO PRIME PATH DECOMPOSITION NUMBER OF A GRAPH K. NAGARAJAN and A. NAGARAJAN Abstract A decomposition of a graph G is a collection ψ of edge-disjoint

More information

2013 University of New South Wales School Mathematics Competition

2013 University of New South Wales School Mathematics Competition Parabola Volume 49, Issue (201) 201 University of New South Wales School Mathematics Competition Junior Division Problems and s Problem 1 Suppose that x, y, z are non-zero integers with no common factor

More information

Basic Proof Examples

Basic Proof Examples Basic Proof Examples Lisa Oberbroeckling Loyola University Maryland Fall 2015 Note. In this document, we use the symbol as the negation symbol. Thus p means not p. There are four basic proof techniques

More information

Maximal non-commuting subsets of groups

Maximal non-commuting subsets of groups Maximal non-commuting subsets of groups Umut Işık March 29, 2005 Abstract Given a finite group G, we consider the problem of finding the maximal size nc(g) of subsets of G that have the property that no

More information

Consider an infinite row of dominoes, labeled by 1, 2, 3,, where each domino is standing up. What should one do to knock over all dominoes?

Consider an infinite row of dominoes, labeled by 1, 2, 3,, where each domino is standing up. What should one do to knock over all dominoes? 1 Section 4.1 Mathematical Induction Consider an infinite row of dominoes, labeled by 1,, 3,, where each domino is standing up. What should one do to knock over all dominoes? Principle of Mathematical

More information

arxiv: v2 [math.gr] 17 Dec 2017

arxiv: v2 [math.gr] 17 Dec 2017 The complement of proper power graphs of finite groups T. Anitha, R. Rajkumar arxiv:1601.03683v2 [math.gr] 17 Dec 2017 Department of Mathematics, The Gandhigram Rural Institute Deemed to be University,

More information

Sets of MOLSs generated from a single Latin square

Sets of MOLSs generated from a single Latin square Sets of MOLSs generated from a single Latin square Hau Chan and Dinesh G Sarvate Abstract The aim of this note is to present an observation on the families of square matrices generated by repeated application

More information

Proofs. Methods of Proof Divisibility Floor and Ceiling Contradiction & Contrapositive Euclidean Algorithm. Reading (Epp s textbook)

Proofs. Methods of Proof Divisibility Floor and Ceiling Contradiction & Contrapositive Euclidean Algorithm. Reading (Epp s textbook) Proofs Methods of Proof Divisibility Floor and Ceiling Contradiction & Contrapositive Euclidean Algorithm Reading (Epp s textbook) 4.3 4.8 1 Divisibility The notation d n is read d divides n. Symbolically,

More information

4 Powers of an Element; Cyclic Groups

4 Powers of an Element; Cyclic Groups 4 Powers of an Element; Cyclic Groups Notation When considering an abstract group (G, ), we will often simplify notation as follows x y will be expressed as xy (x y) z will be expressed as xyz x (y z)

More information

Department of Mathematics and Statistics Math B: Discrete Mathematics and Its Applications Test 1: October 19, 2006

Department of Mathematics and Statistics Math B: Discrete Mathematics and Its Applications Test 1: October 19, 2006 Department of Mathematics and Statistics Math 1019 3.0 B: Discrete Mathematics and Its Applications est 1: October 19, 2006 Name: (Last/amily) (irst) Student No. Instructions: 1. his test has 8 questions

More information

Vector Spaces 4.1 Vectors in n Spaces

Vector Spaces 4.1 Vectors in n Spaces Vector Spaces 4.1 Vectors in n Spaces September 27 Goals Get familar with real n spaces R n, like R 2, R 3. Get familiar with some of the properties of the real n spaces R n. Justify why points in R n

More information

Outline. We will now investigate the structure of this important set.

Outline. We will now investigate the structure of this important set. The Reals Outline As we have seen, the set of real numbers, R, has cardinality c. This doesn't tell us very much about the reals, since there are many sets with this cardinality and cardinality doesn't

More information

HOMEWORK #2 - MATH 3260

HOMEWORK #2 - MATH 3260 HOMEWORK # - MATH 36 ASSIGNED: JANUARAY 3, 3 DUE: FEBRUARY 1, AT :3PM 1) a) Give by listing the sequence of vertices 4 Hamiltonian cycles in K 9 no two of which have an edge in common. Solution: Here is

More information

Some Edge-magic Cubic Graphs

Some Edge-magic Cubic Graphs Some Edge-magic Cubic Graphs W. C. Shiu Department of Mathematics Hong Kong Baptist University 4 Waterloo Road, Kowloon Tong Hong Kong, China. and Sin-Min Lee Department of Mathematics and Computer Science

More information

Decomposition of Complete Tripartite Graphs Into 5-Cycles

Decomposition of Complete Tripartite Graphs Into 5-Cycles Decomposition of Complete Tripartite Graphs Into 5-Cycles E.S. MAHMOODIAN MARYAM MIRZAKHANI Department of Mathematical Sciences Sharif University of Technology P.O. Box 11365 9415 Tehran, I.R. Iran emahmood@irearn.bitnet

More information

Discrete Math I Exam II (2/9/12) Page 1

Discrete Math I Exam II (2/9/12) Page 1 Discrete Math I Exam II (/9/1) Page 1 Name: Instructions: Provide all steps necessary to solve the problem. Simplify your answer as much as possible. Additionally, clearly indicate the value or expression

More information

40th International Mathematical Olympiad

40th International Mathematical Olympiad 40th International Mathematical Olympiad Bucharest, Romania, July 999 Determine all finite sets S of at least three points in the plane which satisfy the following condition: for any two distinct points

More information

Number Theory and Graph Theory

Number Theory and Graph Theory 1 Number Theory and Graph Theory Chapter 1 Introduction and Divisibility By A. Satyanarayana Reddy Department of Mathematics Shiv Nadar University Uttar Pradesh, India E-mail: satya8118@gmail.com 1 DIVISION

More information

Mathematical Induction

Mathematical Induction Mathematical Induction Let s motivate our discussion by considering an example first. What happens when we add the first n positive odd integers? The table below shows what results for the first few values

More information

Incidence Structures Related to Difference Sets and Their Applications

Incidence Structures Related to Difference Sets and Their Applications aòµ 05B30 ü èµ Æ Òµ 113350 Æ Æ Ø Ø K8: 'u8'é(9ùa^ = Ø K8: Incidence Structures Related to Difference Sets and Their Applications úôœææ Æ Ø ž

More information

Peter J. Dukes. 22 August, 2012

Peter J. Dukes. 22 August, 2012 22 August, 22 Graph decomposition Let G and H be graphs on m n vertices. A decompostion of G into copies of H is a collection {H i } of subgraphs of G such that each H i = H, and every edge of G belongs

More information

d 2 -coloring of a Graph

d 2 -coloring of a Graph d -coloring of a Graph K. Selvakumar and S. Nithya Department of Mathematics Manonmaniam Sundaranar University Tirunelveli 67 01, Tamil Nadu, India E-mail: selva 158@yahoo.co.in Abstract A subset S of

More information

On the oriented chromatic index of oriented graphs

On the oriented chromatic index of oriented graphs On the oriented chromatic index of oriented graphs Pascal Ochem, Alexandre Pinlou, Éric Sopena LaBRI, Université Bordeaux 1, 351, cours de la Libération 33405 Talence Cedex, France February 19, 2006 Abstract

More information

M-saturated M={ } M-unsaturated. Perfect Matching. Matchings

M-saturated M={ } M-unsaturated. Perfect Matching. Matchings Matchings A matching M of a graph G = (V, E) is a set of edges, no two of which are incident to a common vertex. M-saturated M={ } M-unsaturated Perfect Matching 1 M-alternating path M not M M not M M

More information

PGSS Discrete Math Solutions to Problem Set #4. Note: signifies the end of a problem, and signifies the end of a proof.

PGSS Discrete Math Solutions to Problem Set #4. Note: signifies the end of a problem, and signifies the end of a proof. PGSS Discrete Math Solutions to Problem Set #4 Note: signifies the end of a problem, and signifies the end of a proof. 1. Prove that for any k N, there are k consecutive composite numbers. (Hint: (k +

More information

X-MA2C01-1: Partial Worked Solutions

X-MA2C01-1: Partial Worked Solutions X-MAC01-1: Partial Worked Solutions David R. Wilkins May 013 1. (a) Let A, B and C be sets. Prove that (A \ (B C)) (B \ C) = (A B) \ C. [Venn Diagrams, by themselves without an accompanying logical argument,

More information

Figure 9.1: A Latin square of order 4, used to construct four types of design

Figure 9.1: A Latin square of order 4, used to construct four types of design 152 Chapter 9 More about Latin Squares 9.1 Uses of Latin squares Let S be an n n Latin square. Figure 9.1 shows a possible square S when n = 4, using the symbols 1, 2, 3, 4 for the letters. Such a Latin

More information

Symmetry. PlayMath, Summer, 2018

Symmetry. PlayMath, Summer, 2018 This essay is about the use of symmetry in solving algebra and geometry problems From Wikipedia we learn that symmetry (from Greek symmetra measure together ) generally conveys two primary meanings The

More information

UAB MATH TALENT SEARCH

UAB MATH TALENT SEARCH NAME: GRADE: SCHOOL NAME: 2011-2012 UAB MATH TALENT SEARCH This is a two hour contest. Answers are to be written in the spaces provided on the test sheet. There will be no credit if the answer is incorrect.

More information

School of Mathematics

School of Mathematics School of Mathematics Programmes in the School of Mathematics Programmes including Mathematics Final Examination Final Examination 06 22498 MSM3P05 Level H Number Theory 06 16214 MSM4P05 Level M Number

More information

NORTHWESTERN UNIVERSITY Thrusday, Oct 6th, 2011 ANSWERS FALL 2011 NU PUTNAM SELECTION TEST

NORTHWESTERN UNIVERSITY Thrusday, Oct 6th, 2011 ANSWERS FALL 2011 NU PUTNAM SELECTION TEST Problem A1. Let a 1, a 2,..., a n be n not necessarily distinct integers. exist a subset of these numbers whose sum is divisible by n. Prove that there - Answer: Consider the numbers s 1 = a 1, s 2 = a

More information

HAMILTON CYCLES IN CAYLEY GRAPHS

HAMILTON CYCLES IN CAYLEY GRAPHS Hamiltonicity of (2, s, 3)- University of Primorska July, 2011 Hamiltonicity of (2, s, 3)- Lovász, 1969 Does every connected vertex-transitive graph have a Hamilton path? Hamiltonicity of (2, s, 3)- Hamiltonicity

More information

AND OCCUPANCY PROBLEMS

AND OCCUPANCY PROBLEMS COMBINATIONS, COMPOSITIONS AND OCCUPANCY PROBLEMS MORTON ABRAMSON York University, Downsview, Toronto, Canada Let r < k be positive integers,, INTRODUCTION By a composition of k into r parts (an r-composition

More information

New quasi-symmetric designs constructed using mutually orthogonal Latin squares and Hadamard matrices

New quasi-symmetric designs constructed using mutually orthogonal Latin squares and Hadamard matrices New quasi-symmetric designs constructed using mutually orthogonal Latin squares and Hadamard matrices Carl Bracken, Gary McGuire Department of Mathematics, National University of Ireland, Maynooth, Co.

More information

Rainbow matchings and rainbow connectedness

Rainbow matchings and rainbow connectedness Rainbow matchings and rainbow connectedness Alexey Pokrovskiy arxiv:1504.05373v1 [math.co] 21 Apr 2015 Methods for Discrete Structures, Freie Universität, Berlin, Germany. Email: alja123@gmail.com Keywords:

More information

Lesson 4: The Perfect Rectangle

Lesson 4: The Perfect Rectangle Exploratory Activity 1. What questions do you have about this magazine cover? 2. The bottom right square is 81 square units and the smallest square is 1 square unit. The rest of the figure is made of squares.

More information

CS Homework Chapter 6 ( 6.14 )

CS Homework Chapter 6 ( 6.14 ) CS50 - Homework Chapter 6 ( 6. Dan Li, Xiaohui Kong, Hammad Ibqal and Ihsan A. Qazi Department of Computer Science, University of Pittsburgh, Pittsburgh, PA 560 Intelligent Systems Program, University

More information

Probabilistic Proofs of Existence of Rare Events. Noga Alon

Probabilistic Proofs of Existence of Rare Events. Noga Alon Probabilistic Proofs of Existence of Rare Events Noga Alon Department of Mathematics Sackler Faculty of Exact Sciences Tel Aviv University Ramat-Aviv, Tel Aviv 69978 ISRAEL 1. The Local Lemma In a typical

More information

Unit 3 Factors & Products

Unit 3 Factors & Products 1 Unit 3 Factors & Products General Outcome: Develop algebraic reasoning and number sense. Specific Outcomes: 3.1 Demonstrate an understanding of factors of whole number by determining the: o prime factors

More information

Induced Saturation of Graphs

Induced Saturation of Graphs Induced Saturation of Graphs Maria Axenovich a and Mónika Csikós a a Institute of Algebra and Geometry, Karlsruhe Institute of Technology, Englerstraße 2, 76128 Karlsruhe, Germany Abstract A graph G is

More information

Graphs with Integer Matching Polynomial Roots

Graphs with Integer Matching Polynomial Roots Graphs with Integer Matching Polynomial Roots S. Akbari a, P. Csikvári b, A. Ghafari a, S. Khalashi Ghezelahmad c, M. Nahvi a a Department of Mathematical Sciences, Sharif University of Technology, Tehran,

More information

Latin squares: Equivalents and equivalence

Latin squares: Equivalents and equivalence Latin squares: Equivalents and equivalence 1 Introduction This essay describes some mathematical structures equivalent to Latin squares and some notions of equivalence of such structures. According to

More information

OQ4867. Let ABC be a triangle and AA 1 BB 1 CC 1 = {M} where A 1 BC, B 1 CA, C 1 AB. Determine all points M for which ana 1...

OQ4867. Let ABC be a triangle and AA 1 BB 1 CC 1 = {M} where A 1 BC, B 1 CA, C 1 AB. Determine all points M for which ana 1... 764 Octogon Mathematical Magazine, Vol. 24, No.2, October 206 Open questions OQ4867. Let ABC be a triangle and AA BB CC = {M} where A BC, B CA, C AB. Determine all points M for which 4 s 2 3r 2 2Rr AA

More information

18.S34 linear algebra problems (2007)

18.S34 linear algebra problems (2007) 18.S34 linear algebra problems (2007) Useful ideas for evaluating determinants 1. Row reduction, expanding by minors, or combinations thereof; sometimes these are useful in combination with an induction

More information

M381 Number Theory 2004 Page 1

M381 Number Theory 2004 Page 1 M81 Number Theory 2004 Page 1 [[ Comments are written like this. Please send me (dave@wildd.freeserve.co.uk) details of any errors you find or suggestions for improvements. ]] Question 1 20 = 2 * 10 +

More information

REFINEMENTS OF SOME PARTITION INEQUALITIES

REFINEMENTS OF SOME PARTITION INEQUALITIES REFINEMENTS OF SOME PARTITION INEQUALITIES James Mc Laughlin Department of Mathematics, 25 University Avenue, West Chester University, West Chester, PA 9383 jmclaughlin2@wcupa.edu Received:, Revised:,

More information

Some Basic Logic. Henry Liu, 25 October 2010

Some Basic Logic. Henry Liu, 25 October 2010 Some Basic Logic Henry Liu, 25 October 2010 In the solution to almost every olympiad style mathematical problem, a very important part is existence of accurate proofs. Therefore, the student should be

More information

arxiv: v2 [math.co] 24 May 2018

arxiv: v2 [math.co] 24 May 2018 An approximate version of a conjecture of Aharoni and Berger arxiv:1609.06346v2 [math.co] 24 May 2018 Alexey Pokrovskiy ETH Zürich. May 28, 2018 Abstract Aharoni and Berger conjectured that in every proper

More information

Name (please print) Mathematics Final Examination December 14, 2005 I. (4)

Name (please print) Mathematics Final Examination December 14, 2005 I. (4) Mathematics 513-00 Final Examination December 14, 005 I Use a direct argument to prove the following implication: The product of two odd integers is odd Let m and n be two odd integers Since they are odd,

More information

Introduction to Mathematical Analysis I. Second Edition. Beatriz Lafferriere Gerardo Lafferriere Nguyen Mau Nam

Introduction to Mathematical Analysis I. Second Edition. Beatriz Lafferriere Gerardo Lafferriere Nguyen Mau Nam Introduction to Mathematical Analysis I Second Edition Beatriz Lafferriere Gerardo Lafferriere Nguyen Mau Nam Introduction to Mathematical Analysis I Second Edition Beatriz Lafferriere Gerardo Lafferriere

More information

(vi) xry iff x y 2 (see the previous exercise); (iii) xry iff xy 0;

(vi) xry iff x y 2 (see the previous exercise); (iii) xry iff xy 0; Final: Practice problems Relations Properties Exercise: For the following relations on Z, investigate the four basic properties. (i) arb iff a = b ; (v) arb iff a = b+; (ii) arb iff a b; (vi) arb iff a

More information

Groups and Symmetries

Groups and Symmetries Groups and Symmetries Definition: Symmetry A symmetry of a shape is a rigid motion that takes vertices to vertices, edges to edges. Note: A rigid motion preserves angles and distances. Definition: Group

More information

Strong Mathematical Induction

Strong Mathematical Induction Strong Mathematical Induction Lecture 23 Section 5.4 Robb T. Koether Hampden-Sydney College Mon, Feb 24, 2014 Robb T. Koether (Hampden-Sydney College) Strong Mathematical Induction Mon, Feb 24, 2014 1

More information

STEP Support Programme. Hints and Partial Solutions for Assignment 17

STEP Support Programme. Hints and Partial Solutions for Assignment 17 STEP Support Programme Hints and Partial Solutions for Assignment 7 Warm-up You need to be quite careful with these proofs to ensure that you are not assuming something that should not be assumed. For

More information