Intermediate Algebra. 3.7 Variation. Name. Problem Set 3.7 Solutions to Every Odd-Numbered Problem. Date

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1 3.7 Variation 1. The variation equation is y = Kx. Substituting x = 2 and y = 10: 10 = K 2 K = 5 So y = 5x. Substituting x = 6: y = 5 6 = The variation equation is r = K s. Substituting s = 4 and r = 3:!3 = K 4 K =!12 So r =!12. Substituting s = 2: r =!12 s 2 =!6 5. The variation equation is d = Kr 2. Substituting r = 5 and d = 10: 10 = K = 25K K = 2 5 So d = 2 5 r 2. Substituting r = 10: d = 2 ( 5 10)2 = = The variation equation is y = K. Substituting x = 3 and y = 45: 2 x 45 = K = K 9 K = 405 So y = 405. Substituting x = 5: y = 405 = 405 x = The variation equation is z = Kxy 2. Substituting x = 3, y = 3, and z = 54: 54 = K 3 54 = 27K ( )( 3) 2 K = 2 So z = 2xy 2. Substituting x = 2 and y = 4: z = 2 2 ( ) 4 ( ) 2 = 64

2 11. The variation equation is I = K w 3. Substituting w = 1 2 and I = 32: 32 = K! 1$ " # 2% & 32 = K 1 / 8 K = 4 3 So I = 4 w 3. Substituting w = 1 3 : I = 4! " # 1$ 3% & 3 = 4 1 / 27 = The variation equation is z = Kyx 2. Substituting x = 3, y = 2, and z = 72: 72 = K 2 72 = 18K ( )( 3) 2 K = 4 So z = 4yx 2. Substituting x = 5 and y = 3: z = 4 3 ( ) 5 ( ) 2 = The variation equation is z = Kyx 2. Substituting x = 1, y = 5, and z = 25: 25 = K 5 25 = 5K ( )( 1) 2 K = 5 So z = 5yx 2. Substituting z = 160 and y = 8: 160 = 5 8 ( ) x = 40x 2 x 2 = 4 x = ±2

3 17. The variation equation is F = Km. Substituting F = 150, m = 240, and d = 8: 150 = K ( 240) = 240K K = 9600 K = 40 So F = 40m 40. Substituting m = 360 and d = 3: F = ( 360 ) = = The variation equation is F = Km 24 = K ( 20) = 20K 25 20K = 600 K = 30 So F = 30m. Substituting F = and m = 40: = ( ) = = 1200 = 64 d = ±8. Substituting F = 24, m = 20, and d = 5:

4 21. Let l represent the length and f represent the force. The variation equation is l = Kf. Substituting f = 5 and l = 3: 3 = K 5 K = 3 5 So l = 3 5 f. Substituting l = 10: 10 = 3 5 f 50 = 3 f f = 50 3 The force required is 50 3 pounds. 23. a. Let T represent the temperature and P represent the pressure. The variation equation is T = KP. Substituting T = 200 and P = 50: 200 = K 50 K = 4 The variation equation is T = 4P. b. Graphing the equation: c. Substituting T = 280: 280 = 4P P = 70 The pressure is 70 pounds per square inch.

5 25. Let v represent the volume and p represent the pressure. The variation equation is v = K p. Substituting p = 36 and v = 25: 25 = K 36 K = 900 The equation is v = 900. Substituting v = 75: p 75 = 900 p 75 p = 900 p = 12 The pressure is 12 pounds per square inch. 27. a. Let f represent the aperture and d represent the diameter. The variation equation is f = K d. Substituting f = 2 and d = 40: 2 = K 40 K = 80 The variation equation is f = 80 d. b. Graphing the equation: c. Substituting d = 10: f = f = 8 The f-stop is 8.

6 29. Let A represent the surface area, h represent the height, and r represent the radius. The variation equation is A = Khr. Substituting A = 94, r = 3, and h = 5: 94 = K 3 94 = 15K K = ( )( 5) The equation is A = The surface area is hr. Substituting r = 2 and h = 8: A = ( 15 8) ( 2) = square inches Let R represent the resistance, l represent the length, and d represent the diameter. The variation equation is R = Kl. Substituting R = 10, l = 100, and d = 0.01: 2 d 10 = K ( 100) 0.01 ( ) = 100K K = The equation is R = l Substituting l = 60 and d = 0.02: R = ( ) = 1.5. ( 0.02) 2 The resistance is 1.5 ohms. 33. a. Let P represent the period and L represent the length. The variation equation is P = K L. Substituting P = 2.1 and L = 100: 2.1 = K = 10K K = 0.21 The variation equation is P = 0.21 L. b. Graphing the equation:

7 c. Substituting L = 225: P = = 3.15 The period is 3.15 seconds. 35. Multiplying: 0.6( M! 70) = 0.6M! Multiplying: ( 4 x! 3) 4 x 2! 7x Simplifying: ( 4 x! 3) + 4 x 2! 7x Simplifying: 4 x 2 + 3x + 2 ( ) = 16x 3! 28x x! 12x x! 9 = 16x 3! 40x x! 9 ( ) = 4 x! x 2! 7x + 3 = 4 x 2! 3x ( ) + ( 2x 2! 5x! 6) = 4 x 2 + 3x x 2! 5x! 6 = 6x 2! 2x! Simplifying: 4 (!1) 2! 7 (!1) = 4( 1)! 7 (!1) = = 11

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