Addendum. Addendum. Vector Review. Department of Computer Science and Engineering 1-1
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1 Addedum Addedum Vetor Review Deprtmet of Computer Siee d Egieerig -
2 Coordite Systems Right hded oordite system Addedum y z Deprtmet of Computer Siee d Egieerig -
3 -3 Deprtmet of Computer Siee d Egieerig Addedum Vetor Arithmeti [ ] [ ] [ ] [ ] [ ] [ ] z y z y z z y y z z y y z y z y s s s s
4 Vetor gitude The mgitude legth of vetor is: Addedum v y v + v + v z A vetor with legth. is lled uit vetor We lso ormlize vetor to mke it uit vetor: v v Deprtmet of Computer Siee d Egieerig -4
5 Dot Produt Addedum i i + y y + z z osθ Deprtmet of Computer Siee d Egieerig -5
6 -6 Deprtmet of Computer Siee d Egieerig Addedum Dot Produt T z z y y i i + + osθ [ ] z y z y
7 Emple: Agle Betwee Vetors Addedum How do you fid the gle θ etwee vetors d? θ Deprtmet of Computer Siee d Egieerig -7
8 -8 Deprtmet of Computer Siee d Egieerig Addedum Emple: Agle Betwee Vetors os os os θ θ θ θ
9 Dot Produts with Geerl Vetors Addedum The dot produt is slr vlue tht tells us somethig out the reltioship etwee two vetors If > the θ < 9º If < the θ > 9º If the θ 9º or oe or more of the vetors is degeerte,, Deprtmet of Computer Siee d Egieerig -9
10 Dot Produts with Oe Uit Vetor Addedum If u. the u is the legth of the projetio of oto u u u Deprtmet of Computer Siee d Egieerig -
11 Emple: Diste to Ple Addedum A ple is desried y poit p o the ple d uit orml. Fid the diste from poit to the ple p Deprtmet of Computer Siee d Egieerig -
12 Emple: Diste to Ple Addedum The diste is the legth of the projetio of -p oto : dist p -p p Deprtmet of Computer Siee d Egieerig -
13 Dot Produts with Uit Vetors Addedum < < θ - < <. - os θ Deprtmet of Computer Siee d Egieerig -3
14 -4 Deprtmet of Computer Siee d Egieerig Addedum [ ] y y z z y z z y z y z y k j i Cross Produt
15 Properties of the Cross Produt Addedum is vetor perpediulr to oth d, i the diretio defied y the right hd rule si θ re of prllelogrm if d re prllel Deprtmet of Computer Siee d Egieerig -5
16 Emple: Norml of Trigle Addedum Fid the uit legth orml of the trigle defied y 3D poits,, d Deprtmet of Computer Siee d Egieerig -6
17 Emple: Norml of Trigle Addedum - - Deprtmet of Computer Siee d Egieerig -7
18 Emple: Are of Trigle Fid the re of the trigle defied y 3D poits,, d Addedum Deprtmet of Computer Siee d Egieerig -8
19 Emple: Are of Trigle Addedum re - - Deprtmet of Computer Siee d Egieerig -9
20 Emple: Aligmet to Trget Addedum A ojet is t positio p with uit legth hedig of h. We wt to rotte it so tht the hedig is fig some trget t. Fid uit is d gle θ to rotte roud. t p h Deprtmet of Computer Siee d Egieerig -
21 Emple: Aligmet to Trget Addedum h h t p t p t-p t θ os h t p t p p h θ Deprtmet of Computer Siee d Egieerig -
22 Addedum Addedum Crmer s Rule Deprtmet of Computer Siee d Egieerig -
23 This is gret method. Addedum Crmer s Rule is et wy to evlute systems d if you put the work i ow you ll do fie. It e used for y size y, 3 y 3 or eve lrger system. It is esy to memorize d fst. I m goig to show you where Crmer s Rule omes from; ut first, some defiitios Deprtmet of Computer Siee d Egieerig -3
24 Defiitios Determit squre rry Addedum d Order Determit y rry 3 rd Order Determit 3 y 3 rry Elemets The thigs i the rry Deprtmet of Computer Siee d Egieerig -4
25 Wht does determit look like? A d order determit looks like this Addedum Ad the vlue of the determit d e Digol dow right digol dow left d e e d Deprtmet of Computer Siee d Egieerig -5
26 Emples Evlute Addedum Deprtmet of Computer Siee d Egieerig -6
27 Why is this useful for systems? Addedum ets work through elimitio emple usig ll vriles; the we see how the determit will e useful i solvig. Deprtmet of Computer Siee d Egieerig -7
28 Addedum + y d + ey f ets elimite y e + ey y e d + ey f e d e f e d e f e f e d ook fmilir? f d e e Deprtmet of Computer Siee d Egieerig -8
29 Addedum If you pply the sme proess ut elimite y f e d d y d f d e So, wht does Crmer s Rule sy? Deprtmet of Computer Siee d Egieerig -9
30 Crmer s Rule + y Give system d + ey f Reple solutios i olum to solve for f d e e Wht do you thik is the trik? y d d f e Addedum Reple solutios i y olum to solve for y Deomitors re oeffiiet determits Deprtmet of Computer Siee d Egieerig -3
31 Emples Solve usig Crmer s Rule Addedum y 9 y Deprtmet of Computer Siee d Egieerig -3
32 Crmer s Rule i Geerl Addedum Crmer's Rule: For the system of equtios A y, where A is osigulr mtri, the solutio for the ith edogeous vrile, i, is i A i / A where the mtri A i represets mtri tht is idetil to the mtri A ut for the replemet of the ith olum with the vetor y. Deprtmet of Computer Siee d Egieerig -3
33 -33 Deprtmet of Computer Siee d Egieerig Addedum ier Systems i tri Form O
34 Solutio of ier Systems Eh side of the equtio Addedum A C e multiplied y A - : A A A Due to the defiitio of A - : A A I Therefore the solutio of is: A Deprtmet of Computer Siee d Egieerig -34
35 Cosistey Solvility A - does ot eist for every A Addedum The lier system of equtios A hs solutio, or sid to e osistet IFF Rk{A}Rk{A } A system is iosistet whe Rk{A}<Rk{A } Rk{A} is the mimum umer of lierly idepedet olums or rows of A. Rk e foud y usig ERO Elemetry Row Oprtios or ECO Elemetry olum opertios. Deprtmet of Computer Siee d Egieerig -35
36 Elemetry row d olum opertios th for CS eture 36 Deprtmet of Computer Siee d Egieerig Addedum The followig opertios pplied to the ugmeted mtri [A ], yield equivlet lier system Iterhges: The order of two rows/olums e hged Slig: ultiplyig row/olum y ozero ostt Sum: The row e repled y the sum of tht row d ozero multiple of y other row. Oe use ERO d ECO to fid the Rk s follows: ERO miimum # of rows with t lest oe ozero etry or ECO miimum # of olums with t lest oe ozero etry -36
37 -37 Deprtmet of Computer Siee d Egieerig Addedum A iosistet emple: Geometri iterprettio ERO:ultiply the first row with - d dd to the seod row Rk{A} Rk{A } > Rk{A} 3 4
38 Uiqueess of solutios Addedum The system hs uique solutio IFF Rk{A}Rk{A } is the order of the system Suh systems re lled full-rk systems Deprtmet of Computer Siee d Egieerig -38
39 -39 Deprtmet of Computer Siee d Egieerig Addedum Full-rk systems If Rk{A} Det{A} A - eists Uique solutio 4
40 Rk defiiet mtries If Rk{A}m< Det{A} A is sigulr so ot ivertile ifiite umer of solutios -m free vriles uder-determied system Addedum th for Cosistet CS so solvle Rk{A}Rk{A } Deprtmet of Computer Siee d Egieerig -4
41 -4 Deprtmet of Computer Siee d Egieerig Addedum Ill-oditioed system of equtios A smll devitio i the etries of A mtri, uses lrge devitio i the solutio
42 Ill-oditioed otiued... Addedum A lier system of equtios is sid to e ill-oditioed if the oeffiiet mtri teds to e sigulr th for CS eture 4 Deprtmet of Computer Siee d Egieerig -4
43 -43 Deprtmet of Computer Siee d Egieerig Addedum Gussi Elimitio By usig ERO, mtri A is trsformed ito upper trigulr mtri ll elemets elow digol Bk sustitutio is used to solve the upper-trigulr system i i i i ii i i O O ERO i i i ii i ~ ~ ~ ~ ~ O O Bk sustitutio
44 Pivotl Elemet Addedum Pivotl elemet O The first oeffiiet of the first row pivot is used to zero out first oeffiiets of other rows. I terms of umeril stility it is usully est to use the lrgest elemet i the olum, i.e. m k j k jk th for CS eture Deprtmet of Computer Siee d Egieerig -44
45 -45 Deprtmet of Computer Siee d Egieerig Addedum First step of elimitio , 3, 3, / / / m m m O First row, multiplied y pproprite ftor is sutrted from other rows.
46 -46 Deprtmet of Computer Siee d Egieerig Addedum th for CS Seod step of elimitio O Pivotl elemet The seod oeffiiet pivot of the seod row is used to zero out seod oeffiiets of other rows.
47 -47 Deprtmet of Computer Siee d Egieerig Addedum Seod step of elimitio , 3 3, / / m m O Seod row, multiplied y pproprite ftor is sutrted from other rows ERO.
48 Gussio elimitio lgorithm Addedum Defie umer of steps s p pivotl row For p,- For rp+ to p p m / r, p p rp rp pp m p+ p p r r r, p p For p+ to p+ p m p r r r, p p Deprtmet of Computer Siee d Egieerig -48
49 -49 Deprtmet of Computer Siee d Egieerig Addedum Bk sustitutio lgorithm O Filly, the followig system is otied:
50 -5 Deprtmet of Computer Siee d Egieerig Addedum Bk sustitutio lgorithm [ ],,, K + i i k k i ik i i i ii i The swer is otied s followig:
51 -5 Deprtmet of Computer Siee d Egieerig Addedum U deompositio R O If we ow defie mtri R d other mtri l ij with k kk k ik ik l the we get: A R
52 U deompositio Addedum Note tht the mtries R d re upper d lower trigulr mtries. Hee, we solve the lier equtio system i two steps: R Solvig these two systems e hieved similr to the usig similr lgorithm we used for k sustitutio. Also ote tht solvig the system of lier equtios for differet solutios does ot require repetitio of the Gussi elimitio lgorithm. Deprtmet of Computer Siee d Egieerig -5
53 Cholesky deompositio If the mtri A is symmetri, solutio for the U deompositio is eve esier sie there eist the followig deompositio for those mtries: where A C T C Addedum C O O O Deprtmet of Computer Siee d Egieerig -53
54 -54 Deprtmet of Computer Siee d Egieerig Addedum Cholesky deompositio How we ompute C? et us look t the equtio: Hee: O O O O O O l k kk k j jl jk kl kl k j jl jk kl k j jk kk kk k j jk jk kk < for
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