# Lesson 4: Numbers Raised to the Zeroth Power

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1 Student Outcomes Students know that a number raised to the zeroth power is equal to one. Students recognize the need for the definition to preserve the properties of exponents. Classwork Concept Development (5 minutes) Let us summarize our main conclusions about exponents. For any numbers x, y any positive integers m, n, the following holds x m x n = x m+n (1) (x m ) n = x mn (2) For any numbers x, y, any positive integers m, n, the following holds (1) x m x n = x m+n (x m ) n = x mn (2) ( xy ) n =x n y n. (3) 1 Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.

2 And if we assume x>0 in equation (4) y>0 in equation (5) below, then we also have x m x n x m n,m>n (4) ( x y ) n = xn y n. (5) There is an obvious reason why the x in (4) the y in (5) must be nonzero: we cannot divide by 0. However, the reason for further restricting x exponents have been defined. This will be done in high school. y to be positive is only given when fractional We group equations (1) (3) together because they are the foundation on which all the results about exponents rest. When they are suitably generalized, as will be done below, they will imply (4) (5). Therefore, we concentrate on (1) (3). The most important feature of (1) (3) is that they are simple they are formally (symbolically) natural. Mathematicians want these three identities to continue to hold for all exponents n, without the restriction that n be positive integers because of these two desirable qualities. We will have to do it one step at a time. Our goal in this grade is to extend the validity of (1) (3) to all integers n. Exploratory Challenge (10 minutes) The first step in this direction is to introduce the definition of the 0 th exponent of a positive number then use it to prove that (1) (3) remain valid when n are not just positive integers but all whole numbers (including 0 ). Since our goal is to make sure (1) (3) remain valid even when m n may be 0, the very definition of the 0 th exponent of a number must pose no obvious contradiction to (1) (3). With this in mind, let us consider what it means to raise a positive number x to the zeroth power. For example, what should 3 0 mean? 2

3 Students will likely respond that 3 0 should equal 0. When they do, demonstrate why that would contradict our existing understing of properties of exponents using (1). Specifically, if m is a positive integer we let 3 0 =0, then 3 m 3 0 =3 m+0, but since we let 3 0 =0 it means that the left side of the equation would equal zero. That creates a 0 3 m+0 contradiction because Therefore, letting 3 0 =0 will not help us to extend (1) (3) to all whole numbers n. Next, students may say that we should let 3 0 =3. Show the two problematic issues this would lead to. First, we have already learned that by definition x 1 = x in Lesson 1, we do not want to have two powers that yield the same result. Second, it would violate the existing rules we have developed: Looking specifically at (1) again, if we let 3 0 =3, then 3 m 3 0 =3 m+0, but m 3 3 m 3 0 =3 3 3 m+1 which is a contradiction again. If we believe that equation (1) should hold even when the same as 3 2 = ; therefore, after multiplying both sides by the number MP. definition: the same way, our belief that (1) should hold when either conclusion that we should define x 0 =1 for any nonzero n=0, then, for example, = , which is 1 3 2, we get 1=3 0. In m or n is 0 would lead us to the x. Therefore, we give the following 3

4 Definition: For any positive number x, we define x 0 =1. Students will need to write this definition of x 0 in the lesson summary box on their classwork paper. Exploratory Challenge 2 (10 minutes) MP. Now that x n is defined for all whole numbers whole numbers n. n, check carefully that (1) (3) remain valid for all Have students independently complete Exercise 1; provide correct values for proceeding. (Development of cases (A) (C)). n before Exercise 1 List all possible cases of whole numbers m n for identity (1). More precisely, when m>0 n>0, we already know that (1) is correct. What are the other possible cases of n for which (1) is yet to be verified? m>0 n=0 Case (A): m=0 n> 0 Case (B): Case (C): m=n=0 Model how to check the validity of a statement using Case (A) with equation (1) as part of Exercise 2. Have students work independently or in pairs to check the validity of (1) in Case (B) Case (C) to complete Exercise 2. Next, have students check the validity of equations (2) (3) using Cases (A) (C) for Exercises 3 4. Exercise 2 Check that equation (1) is correct for each of the cases listed in Exercise 1. Case (A): x m x 0 =x m? Yes, because x m x 0 =x m 1=x m. Case (B): x 0 x n =x n? Yes, because x 0 x n =1 x n =x n. Case (C): x 0 x 0 =x 0? Yes, because x 0 x 0 =1 1= x 0. Exercise 3 Do the same with equation (2) by checking it case-by-case. 4

5 Case (A): (x m ) 0 =x 0 m? Yes, because x m is a number, a number raised to a zero power is 1. 1=x 0 =x 0 m. So, the left side is 1. The right side is also 1 because x 0 m =x 0 =1. Case (B): (x 0 ) n =x n 0? Yes, because by definition x 0 =1 1 n =1, so the left side is equal to 1. The right side is equal to x 0 =1, so both sides are equal. Case (C): (x 0 ) 0 =x 0 0? Yes, because by definition of the zeroth power of x, both sides are equal to 1. Exercise 4 Do the same with equation (3) by checking it case-by-case. Case (A): ( xy ) 0 = x 0 y 0? Yes, because the left side is 1 by the definition of the zeroth power while the right side is 1 1=1. Case (B): Since n>0, we already know that (3) is valid. Case (C): This is the same as Case (A), which we have already shown to be valid. Exploratory Challenge 3 (5 minutes) Students will practice writing numbers in exped notation in Exercises 5 6. Students will use the definition of x 0, for any positive number x, learned in this lesson. Clearly state that you want to see the ones digit multiplied by That is the Scaffolding: important part of the exped notation. This will lead to the use of negative powers of 10 for decimals in Lesson 5. You may need to remind students how to write numbers in exped form with Exercise 5. Exercise 5 Write the exped form of 8,374 using exponential notation. 5

6 8,374=( )+ ( )+( )+( ) Exercise 6 Write the exped form of 6,985,062 using exponential notation. 6,985,062=( )+( )+ ( )+( )+ ( )+ ( )+( ) Closing (3 minutes) Summarize, or have students summarize, the lesson. The rules of exponents that students have worked on prior to today only work for positive integer exponents; now those same rules have been extended to all whole numbers. The next logical step is to attempt to extend these rules to all integer exponents. Exit Ticket (2 minutes) Fluency Exercise (10 minutes) Sprint: Rewrite expressions with the same base for positive exponents only. Make sure to tell the students that all letters within the problems of the sprint are meant to denote numbers. This exercise can be administered at any point during the lesson. Refer to the Sprints Sprint Delivery Script sections in the Module Overview for directions to administer a Sprint. 6

7 Name Date Exit Ticket Simplify the following expression as much as possible = Let a b be two numbers. Use the distributive law then the definition of zeroth power to show that the numbers (a 0 +b 0 )a 0 (a 0 +b 0 )b 0 are equal. 7

8 Exit Ticket Sample Solutions Simplify the following expression as much as possible = =4 0 1=1 1=1 Let a b be two numbers. Use the distributive law then the definition of zeroth power to show that the numbers (a 0 +b 0 )a 0 (a 0 +b 0 )b 0 are equal. (a 0 +b 0 )a 0 =a 0 a 0 +b 0 a 0 a a 0 b 0 a 0 +a 0 b (a 0 +b 0 )b 0 =a 0 b 0 +b 0 b 0 a 0 b 0 +b 0+0 a 0 b 0 +b Since both numbers are equal to 2, they are equal. Problem Set Sample Solutions Let x, y be numbers (x, y 0). Simplify each of the following expressions of numbers. 1. y 12 = y y y =

9 (7 ( ) 4 ) 0 = 7 0 ( ) ( ) = x 41 y15 15 y x = x41 y y 15 x 41 x41 y15 41 x y 15 x y x 0 y 0 9

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