Sample Teaching Sequence (Hong Kong Secondary 4 6 Chemistry)

Size: px
Start display at page:

Download "Sample Teaching Sequence (Hong Kong Secondary 4 6 Chemistry)"

Transcription

1 Revised (1 Sept 009 Sample Teahing Suene (Hong Kong Seondary 4 6 Chemistry Topi: Chemial Equilibrium Teahing Suene Content 1.1 Reversible reations Examples of reversible reation; forward reation; reverse reation; importane of reversible reations. 1. Charateristis of hemial uilibrium Dynami uilibrium; hanges in reatant and produt onentration with time; hanges in the rates of forward and reverse reations with time; uilibrium state. 1. The uilibrium law The uilibrium law; uilibrium onstant; uilibrium position; determination of uilibrium onstants. 1.4 Prediting the diretion of a reversible reation 1.5 Fator affeting the position of uilibrium Changing onentrations of reatants and/or produts Use the uilibrium onstant and reation quotient to predit the diretion in whih a reversible reation will proeed to reah uilibrium. Use the uilibrium onstant and reation quotient to analyze the effets of hanging onentrations: adding or removing reatants and produts; hanging volume or pressure in gaseous uilibria; adding inert gases to gaseous uilibria. Adding a atalyst Effet of atalysts on the rates of forward reation and reverse reation; effet of atalysts on uilibrium onstant and uilibrium position. Changing temperature Apply van t Hoff law qualitatively to predit the effet of hanging temperature on uilibrium onstant and uilibrium position. 1.6 Controlling reversible reations Maximum yield; ost-effetiveness; the Haber proess. For illustrative purposes, a sample of teahing and learning materials for Parts is presented on pp. -1. Derek Cheung 009 1

2 1.4 Prediting the Diretion of a Reversible Reation The uilibrium onstant, K, is 18 at a given temperature for the reation of iron(iii ions with thioyanate ions. Fe + (aq + NCS (aq Fe(NCS + (aq In a ertain experiment, mole of Fe + (aq, mole of NCS (aq, and mole of Fe(NCS + (aq are mixed in a.0-litre flask. Is the system at uilibrium? If it is not, in whih diretion will the system proeed to reah uilibrium? If the initial onentrations of Fe + (aq, NCS (aq, and Fe(NCS + (aq are substituted into the uilibrium onstant expression, the value obtained is greater than the uilibrium onstant [ Fe( NCS [ Fe [ NCS This indiates that the onentration of Fe(NCS + (aq is bigger than its onentration at uilibrium and the reversible reation is not at uilibrium. In order to reah uilibrium, the value must be restored to 18. This an be ahieved if some Fe(NCS + (aq ions reat (making the numerator smaller to produe Fe + (aq and NCS (aq ions (making the denominator bigger. Thus, although both forward and reverse reations our simultaneously, the reverse reation will predominate to derease the Fe(NCS + (aq onentration until uilibrium is established. When the reverse reation ours to a greater extent than the forward reation, we say that the reversible reation proeeds from right to left to reah uilibrium. The ratio of onentrations shown above is alled reation quotient,. The reation quotient expression has the same mathematial form as the uilibrium onstant expression but involves speifi onentrations that are not neessarily uilibrium onentrations. The subsript indiates that the reation quotient is a ratio of onentrations. We an apply the reation quotient to predit the diretion of a reversible reation. When a mixture ontains only reatants, is ual to zero. When only produts are present, is ual to an infinitely large value. When both reatants and produts are present and their onentrations remain onstant, is ual to K. The diretion in whih a reversible reation will proeed is shown in the following figure: Reatants only 0 At uilibrium K Produts only Reation proeeds to the right to reah uilibrium Reation proeeds to the left to reah uilibrium If is less than K, the reversible reation will proeed from left to right to form more produts until uilibrium is ahieved. If is greater than K, the reversible reation will proeed from right to left to form more reatants until uilibrium is ahieved. If is ual to K, the reversible reation is already at uilibrium and the onentrations of reatants and produts will not hange. Derek Cheung 009

3 Consider the reation: PCl 5 (g Cl (g + PCl (g K 1.5 at 60 o C If a.0-litre ontainer is found to ontain. moles of Cl (g, 1.5 moles of PCl (g, and.0 moles of PCl 5 (g, is the system at uilibrium? If it is not, in whih diretion will the system proeed to reah uilibrium? The onentration of a gas an be expressed as mol/l; that is, moles of the gas per litre oupied. The reation quotient expression for PCl 5 (g Cl (g + PCl (g is. 1.5 [ Cl [ PCl [ PCl Beause is less than K, the onentrations of Cl (g and PCl (g are not as large as they would be at uilibrium. Thus, the system is not at uilibrium. Although both forward and reverse reations our simultaneously, the forward reation will predominate until uilibrium is established. In other words, the reversible reation will proeed from left to right to reah uilibrium. 1. K 1.5 Reation proeeds to the right to reah uilibrium At 5 o C, K is 5 for the reation H (g + I (g HI(g. Predit how the reversible reation proeeds if [H 0.1 M, [I 0.14 M, and [HI 0.8 M. The reation quotient expression is [ HI [ H [ I ( (0.1(0.14 Beause is greater than K, the reversible reation is not at uilibrium and the reverse reation will predominate until uilibrium is established. Thus, the reversible reation will proeed from right to left to form more H and I moleules until uilibrium is ahieved. Derek Cheung 009

4 1.5 Fators Affeting the Position of Equilibrium One a reversible reation has reahed uilibrium, it remains at uilibrium until it is disturbed by hanges in onentration and/or temperature Changing Conentrations of Reatants and/or Produts Adding or Removing Reatants and Produts The way in whih the position of uilibrium alters by hanging onentration an be diretly predited from the properties of uilibrium onstant. Consider the following reversible reation in a test tube: H + (aq + CrO 4 (aq Cr O 7 (aq + H O(l yellow orange In aqueous solution, hromate ions, CrO - 4, and dihromate ions, Cr O - 7, exist. The uilibrium onstant expression for the reversible reation is K [ 7 4 [ Cr O + [ H CrO For a dilute solution, water onentration is not signifiantly hanged by the reation and does not appear in the uilibrium onstant expression. Imagine that the reation mixture is allowed to reah uilibrium at a given temperature. Suppose we now add a few drops of dilute H SO 4 (aq to the mixture and keep the temperature onstant. How will an inrease in H + (aq onentration affet the uilibrium position? Immediately after adding the extra H + (aq ions, before any hemial hanges our, is less than K due to an inrease in [H + (making the denominator of the expression bigger. [ CrO + [ H [ CrO 7 4 Beause is less than K, the reation mixture is no longer at uilibrium. The reversible reation will proeed from left to right to inrease the produt onentrations until uilibrium is re-established. Therefore, although both forward and reverse reations our, the forward reation will predominate until uilibrium is re-established (i.e., the forward reation and the reverse are ourring at ual rates. In the new uilibrium state, the onentration of dihromate ions, Cr O 7 -, are greater than it was initially. This indiates that the position of uilibrium has shifted to the produt side (i.e., to the right. The mixture beomes more orange in the new uilibrium state. (Carry out a demonstration experiment or insert a photo here Atmospheri arbon dioxide reats with water in rain to form arboni aid (H CO, whih ionizes into hydrogen ion and hydrogen arbonate ion: H CO (aq H + (aq + HCO (aq That is why normal rainwater is slightly aidi. The ph of natural, unpolluted rainwater is about 5.6, but rainwater with a ph below 5.6 is alled aid rain. The uilibrium onstant expression for the ionization reation is K + [ H [ HCO [ H CO Imagine that this reversible reation is allowed to reah uilibrium in a ontainer at a given temperature. Derek Cheung 009 4

5 Suppose we now add a few drops of NaOH(aq to the mixture and keep the temperature onstant. How will addition of NaOH(aq affet the uilibrium position? The reversible reation, H CO (aq H + (aq + HCO (aq, does not involve NaOH, but the OH (aq ions from NaOH an reat with H + (aq ions to form H O. Immediately after adding NaOH(aq, the H + (aq onentration in the mixture will derease. As a result, is less than K due to a derease in [H + (making the numerator of the expression smaller. + [ H [ HCO [ H CO Beause is less than K, the reation mixture is no longer at uilibrium. The reversible reation will proeed from left to right to inrease the produt onentrations until uilibrium is re-established. Therefore, although both forward and reverse reations our, the forward reation will predominate until uilibrium is re-established (i.e., the forward reation and the reverse are ourring at ual rates. In the new uilibrium state, the onentration of HCO - (aq ions is greater than it was initially. This indiates that the position of uilibrium has shifted to the produt side (i.e., to the right. Consider the uilibrium NO(g N (g + O (g in a sealed ontainer at a given temperature. Suppose that more oxygen gas is suddenly added to the uilibrium system at onstant temperature. How will an inrease in oxygen onentration affet the position of uilibrium? The uilibrium onstant expression for the reversible reation is [ N K [ [ O NO Immediately after adding the extra oxygen, before any hemial hanges our, is greater than K due to an inrease in [O (making the numerator of the expression bigger. [ N[ O [ NO Beause is greater than K, the reation mixture is no longer at uilibrium. The reverse reation will predominate until uilibrium is re-established. The position of uilibrium will shift to the reatant side (i.e., to the left and more NO moleules will be formed. Derek Cheung 009 5

6 For gaseous uilibrium systems, we need to pay speial attention to the onditions under whih the hange in onentration of reatants and/or produts is made beause volume of the ontainer will also affet onentration of a gaseous speies. However, the ontainer volume is not important if the number of moles of gaseous produts in the balaned uation is ual to the number of moles of gaseous reatants in the balaned uation. An example is N (g + O (g NO(g. Consider the reation CO(g + H (g CH 4 (g + H O(g at uilibrium in a ontainer fitted with a movable piston (i.e., the piston an move inwards and outwards. If a small amount of CO(g is suddenly added to the uilibrium mixture at onstant pressure and temperature, what will happen to the number of H O(g moleules when uilibrium is re-established? Atmospheri pressure Temperature regulator Mixer Constant temperature fluid The expression for this reversible reation is [ CH [ H n O CH 4 H O 4 [ CO[ H n n CO H n CH 4 CO H O H ( where [CH 4 is the onentration of CH 4, n CH4 is the number of moles of CH 4, is the ontainer volume, and so on. Immediately after adding the extra CO(g, before any hemial hanges our, the number of moles of CO, n o, will inrease. The ontainer volume,, also inreases beause the piston is movable and the hange is made at onstant pressure. But the numbers of moles of CH 4, H O, and H remain unhanged. Therefore, the new position of uilibrium will depend upon the ratio /n o in the above reation quotient expression. If the new ratio in the expression > the original ratio in the K expression, then > K ; the uilibrium position will shift to the reatant side (i.e., to the left. If the new ratio < the original ratio, then < K ; the uilibrium position will shift to the produt side (i.e., to the right. Thus, the position of uilibrium an be shifted to the left or right, depending upon the initial amount of CO in the uilibrium mixture. Derek Cheung 009 6

7 At a partiular temperature, the reation N (g + H (g NH (g is at uilibrium in a sealed ontainer with fixed volume. The uilibrium mixture ontains 0.45 M N, 1.1 M H, and 0.8 M NH. (a Calulate K. (b Calulate and predit what will happen if 0.0 mol/dm N is suddenly injeted into the ontainer at onstant temperature. [ NH (0.8 (a K 0. 1 [ N [ H (0.45(1.1 (b Immediately after adding the extra N gas, before any hemial hanges our, the onentration of N beomes ( M. The reation quotient expression is [ NH [ N [ H (0.8 (0.75( Beause < K, the uilibrium position will shift to the produt side (i.e., to the right to form more NH moleules. The reation N (g + H (g NH (g is at uilibrium in a ontainer fitted with a movable piston. Predit the diretion of the shift in uilibrium position if more N gas is suddenly added to the mixture at onstant pressure and temperature. The piston is movable. We need to onsider the hange in ontainer volume,, when writing the reation quotient expression. [ NH n [ N [ H nn nh NH NH N ( H Immediately after adding the extra N gas, before any hemial hanges our, the number of moles of N and the ontainer volume must inrease. The number of moles of H and the number of moles of NH remain unhanged. Therefore, the new position of uilibrium will depend upon the ratio, /n N, in the above reation quotient expression. If the new ratio, /n N, in the expression is greater than the original ratio in the K expression, then is greater than K and the position of uilibrium must shift to the left. If the new ratio is less than the original ratio, then is less than K and the position of uilibrium must shift to the right. Thus, the position of uilibrium an be shifted to the left or right, depending upon the initial amount of N in the uilibrium mixture. Derek Cheung 009 7

8 Changing olume or Pressure in Gaseous Equilibria The onentrations of reatants and produts in a gaseous uilibrium system an be hanged by hanging the volume of the reation ontainer, without adding or removing any reatants and produts. Imagine that the following reversible reation is at uilibrium in a ontainer. How will an inrease in ontainer volume affet its uilibrium position? SO (g + O (g SO (g We need to onsider the hange in ontainer volume,, when writing the reation quotient expression. The reation quotient expression is nso [ SO [ SO [ O n SO n O SO SO ( O The effet of an inrease in ontainer volume on this system an be diretly predited from the properties of uilibrium onstant and reation quotient. Immediately after the ontainer volume is inreased and before any hemial hanges our, the value of beomes bigger. Beause inreases, the numerator of the expression beomes bigger. is greater than K. The uilibrium position will shift to the left to form more SO and O moleules. However, onsider the following reversible reation: H (g + Br HBr(g Imagine that this reversible reation is at uilibrium in a ontainer. How will an inrease in ontainer volume affet its uilibrium position? The expression is nhbr [ HBr HBr [ H [ Br nh n ( ( Br n H n Beause ual numbers of moles of gaseous substanes appear on both sides of the balaned uation, the ontainer volume,, in the numerator and denominator anels out. Thus, hanging the ontainer volume does not affet the position of uilibrium. When the ontainer volume inreases, is still ual to K. That is, the system is still at uilibrium, and no shift in uilibrium position ours. Therefore, hanging ontainer volume will shift an uilibrium system only if the sum of the oeffiients for gaseous reatants in the balaned uation is different from the sum of the oeffiients for gaseous produts. Br The reation Cl (g + PCl (g PCl 5 (g is at uilibrium in a syringe. If the volume is dereased at onstant temperature by foring the plunger inwards, will the uilibrium shift to the left or right? Derek Cheung 009 8

9 The expression for the reation is npcl 5 [ PCl 5 [ Cl[ PCl ncl n PCl Cl PCl 5 ( PCl When the volume,, is dereased at onstant temperature, is less than K and thus the uilibrium must shift to the right to form more PCl 5 moleules. The reation CH 4 (g + Cl (g CH Cl(g + HCl(g is at uilibrium in a ontainer. Predit whether this uilibrium system will shift to the right, left, or not be affeted by an inrease in the ontainer volume. Changing the ontainer volume will not affet the uilibrium position beause the sum of the oeffiients for gaseous reatants in the balaned uation is ual to the sum of the oeffiients for gaseous produts. This predition is onfirmed by the expressions; the volume,, anels out in the expression. nch Cl nhcl [ CH Cl[ HCl [ CH 4[ Cl nch n 4 Cl CH Cl CH 4 HCl Cl The reation N O 4 (g NO (g is at uilibrium in a syringe. If the volume is dereased at onstant temperature by foring the plunger inwards, will the onentration of NO (g be higher or lower than the original onentration when uilibrium is re-established? The K and expressions are K [ NO [ N O 4 n NO [ NO NO [ N O n ( 4 N O 4 N O 4 When the volume,, is dereased at onstant temperature, is greater than K and thus the uilibrium must shift to the left. As a result, the number of N O 4 moleules will inrease. Beause the syringe volume is redued, the onentration of N O 4 in the new uilibrium mixture must inrease. To keep K onstant, the onentration of NO in the new uilibrium mixture must be higher than that in the initial uilibrium mixture. (Carry out a demonstration experiment or insert a photo here Derek Cheung 009 9

10 Adding Inert Gases to Gaseous Equilibria If the sum of the oeffiients for gaseous reatants in the balaned uation for a reversible reation is different from the sum of the oeffiients for gaseous produts, the position of uilibrium an be shifted by adding an inert gas at onstant pressure and temperature. As an example, onsider the following reversible reation: CO(g + Cl (g COCl (g Suppose that this reation is at uilibrium in a ontainer fitted with a movable piston. What will happen if some argon gas is added to the mixture at onstant pressure and temperature? The expression for the reation is ncocl n ncl CO COCl CO ( Cl Beause the piston is movable, the ontainer volume,, will inrease after argon gas is added. Thus, is greater than K. The uilibrium position will shift to the left to form more CO and Cl moleules. If the reation CO(g + Cl (g COCl (g is at uilibrium in a sealed ontainer with fixed volume, then adding an inert gas will not affet the value of any of the terms in the above expression. Thus, adding an inert gas at onstant volume and temperature will not affet the position of uilibrium. The reation CO(g + O (g CO (g is at uilibrium in a ontainer fitted with a movable piston at room temperature. What will happen if some nitrogen gas is added to the uilibrium mixture at onstant pressure and temperature? The expression for the reation is nco n n CO O CO CO ( O Nitrogen does not reat with any of the three gases at room temperature. Beause the piston is movable, the ontainer volume,, will inrease after nitrogen gas is added. Thus, is greater than K. The uilibrium position will shift to the left to form more CO and O moleules Adding a Catalyst A reversible reation an reah uilibrium more quikly in the presene of a atalyst. But addition of a atalyst to an uilibrium system does not affet its uilibrium onstant and uilibrium position beause the atalyst affets the ativation energy of both forward and reverse reations ually. Derek Cheung

11 1.5. Changing Temperature Although the values of K are unaffeted by hanges in onentration or by adding atalysts, hemists have found that when temperature hanges, the values of most K also hange. The values of K at different temperatures for two reversible reations are shown in the table below. The orresponding enthalpy hanges for the forward reations are also shown. N O 4 (g NO (g H 0 57 kj mol -1 NO(g N (g + O (g H kj mol -1 Temperature/K K Temperature/K K x x x x x x 10 In the uilibrium system N O 4 (g NO (g, olourless dinitrogen tetraoxide (N O 4 moleules dissoiate to form brown nitrogen dioxide (NO moleules and this forward reation is endothermi ( H 0 > 0. The intensity of brown olour an be used to measure the onentration of nitrogen dioxide in the uilibrium mixture. The uilibrium onstant inreases as the temperature inreases from 98 K to 600 K. This indiates that inreasing temperature an shift the uilibrium position to the right to form more NO moleules. Thus, if we allow this reversible reation to reah uilibrium in a sealed flask, inreasing the reation temperature will make the uilibrium mixture appear darker. (Carry out a demonstration experiment or insert a photo here In the uilibrium system NO(g N (g + O (g, the forward reation is exothermi ( H 0 < 0. The uilibrium onstant dereases as the temperature inreases from 98 K to 00 K. This indiates that inreasing temperature an shift the uilibrium position to the left to form more NO moleules. The uilibrium mixture will ontain more NO moleules at a higher temperature. Jaobus Henrius van t Hoff, a Duth hemist and the winner of the first Nobel Prize in hemistry, disovered the effets of hanging temperature on uilibrium position: Inreasing temperature will shift the uilibrium position of a reversible reation in the endothermi diretion, whilst dereasing temperature will shift the uilibrium position of a reversible reation in the exothermi diretion. van t Hoff ( The reation below is at uilibrium in a beaker. What will happen to the uilibrium position if the temperature of the mixture is inreased? Co(H O + 6 (aq + 4 Cl - (aq CoCl - 4 (aq + 6 H O(l H 0 > 0 pale pink deep blue Due to the presene of pink and blue ions, the uilibrium mixture is usually violet in olour. However, an inrease in temperature will shift the uilibrium position of the reversible reation in the endothermi diretion. The above thermohemial uation indiates that the forward reation is endothermi. Thus, Derek Cheung

12 the uilibrium position will shift to the right when temperature is inreased. The uilibrium mixture will appear dark blue at a higher temperature. (Carry out a demonstration experiment or insert a photo here The reation below is at uilibrium in a sealed flask. What will happen to the uilibrium position if the temperature of the mixture is inreased? SO (g + O (g SO (g H kj mol -1 The thermohemial uation indiates that the reverse reation is endothermi. Thus, the uilibrium position will shift to the left when temperature is inreased. The uilibrium mixture will ontain more SO and O moleules at a higher temperature. 1.6 Controlling Reversible Reations: The Haber Proess In 009, the world population is 6.79 billion. To make the large quantities of fertilizers needed for present-day agriulture, hemists synthesize ammonia from its elements: N (g + H (g NH (g H 0-9 kj mol -1 This famous reversible reation is known as the Haber proess. How an hemists obtain the maximum yield of ammonia in a reasonable time and at a reasonable ost? The forward reation is exothermi. Therefore, dereasing temperature an shift the uilibrium position to the right to yield more NH moleules. However, the reation is slow at low temperatures. To inrease the reation rate, a atalyst may be used. An effetive atalyst for the Haber proess is Fe O 4 mixed with KOH, Al O, and SiO. Beause the atalyst does not work below 400 o C, the operating temperature is usually about 450 o C. Should hemists use low or high pressure to inrease the yield of NH? We an apply the onept of reation quotient to predit the pressure that we should use. The reation quotient expression for the Haber proess is [ NH n [ N [ H nn nh NH NH N ( H To give the maximum yield of NH, we need to make smaller than K so that the uilibrium position shifts to the right. Sine the total volume,, is in the numerator, an inrease in pressure of the gaseous system will redue and thus make smaller than K. Therefore, the Haber proess is arried out at high pressure. But the higher the pressure, the greater the ost will be. The operating pressure is usually about 00 atm. The boiling point of NH (- o C is muh higher than that of N (-196 o C and H (-5 o C. To further shift the uilibrium position to the right, the produt gas is hilled to liquefy and remove NH gas from the reator. As a result, the number of moles of NH, n NH, dereases and is less than K. Derek Cheung 009 1

13 To summarize, the following onditions are used by hemists to produe ammonia by the Haber proess: Fe O 4 is used as a atalyst A relatively low temperature (450 o C High pressure (00 atm NH is ontinuously liquefied and removed ompressed N and H heating oil hot N and H reator with atalyst NH and unreated N and H reyling pump unreated N and H ooling oil Liquid NH storage tank Derek Cheung 009 1

Chapter 14. The Concept of Equilibrium and the Equilibrium Constant. We have for the most part depicted reactions as going one way.

Chapter 14. The Concept of Equilibrium and the Equilibrium Constant. We have for the most part depicted reactions as going one way. Chapter 14 The Conept of Equilibrium and the Equilibrium Constant In hapter 1 we dealt with Physial Equilibrium Physial Changes HO 2 (l) HO 2 (g) In hapter 14 we will learn about Chemial Equilibrium. We

More information

General Equilibrium. What happens to cause a reaction to come to equilibrium?

General Equilibrium. What happens to cause a reaction to come to equilibrium? General Equilibrium Chemial Equilibrium Most hemial reations that are enountered are reversible. In other words, they go fairly easily in either the forward or reverse diretions. The thing to remember

More information

Answer: Easiest way to determine equilibrium concentrations is to set up a table as follows: 2 SO 2 + O 2 2 SO 3 initial conc change

Answer: Easiest way to determine equilibrium concentrations is to set up a table as follows: 2 SO 2 + O 2 2 SO 3 initial conc change Problem #1 6 mol of SO and 4 mol of O are plaed into a 1 L flask at temperature, T. The equilibrium onentration of SO is found to be 4 mol/l. Determine K. SO (g) + O (g) SO (g) K = [SO ] / [SO ] [O ] Answer:

More information

Chapter 15: Chemical Equilibrium

Chapter 15: Chemical Equilibrium Chapter 5: Chemial Equilibrium ahoot!. At eq, the rate of the forward reation is the rate of the reverse reation. equal to, slower than, faster than, the reverse of. Selet the statement that BEST desribes

More information

Final Exam: know your section, bring your ID!

Final Exam: know your section, bring your ID! Chapter 15: Equilibrium Part 1 Read: BLB 15.1 3 HW: BLB 15:13,14, 21 Supplemental 15:1 4 Know: Chemial Equilibrium Catalysts Equilibrium Constant Equilibrium onstant expression Homogeneous/Heterogeneous

More information

Chapter 15 Chemical Equilibrium

Chapter 15 Chemical Equilibrium Chapter 5 Chemial Equilibrium 5. The Conept of Equilibrium Figure: 3. from Chemistry by MMurray & Fey Figure 3.(a) NO 4( g) NO( g) olorless brown we start with reatant, N O 4, so the solution is olorless

More information

2 How far? Equilibrium Answers

2 How far? Equilibrium Answers How far? Equilibrium Answers ratie: pages 37 39 1 Answer is D. Only a hange in temperature harges the value of the equilibrium onstant. Answer is D. [B] /[A] so [B] [A] or [B] [A] 1/ 3 Answer is B. Amounts

More information

CHAPTER 16. Basic Concepts. Basic Concepts. The Equilibrium Constant. Reaction Quotient & Equilibrium Constant. Chemical Equilibrium

CHAPTER 16. Basic Concepts. Basic Concepts. The Equilibrium Constant. Reaction Quotient & Equilibrium Constant. Chemical Equilibrium Proerties of an Equilibrium System CHAPTER 6 Chemial Equilibrium Equilibrium systems are DYNAMIC (in onstant motion) REVERSIBLE an be aroahed from either diretion Pink to blue Co(H O) 6 Cl ---> > Co(H

More information

Test bank chapter (14)

Test bank chapter (14) Test bank hater (14) Choose the most orret answer 1. Whih is the orret equilibrium onstant exression for the following reation? Fe 2 O 3 (s) + 3H 2 (g) 2Fe(s) + 3H 2 O(g) a) K = [Fe 2 O 3 ] [H 2 ] 3 /[Fe]

More information

MC Practice F2 Solubility Equilibrium, Ksp Name

MC Practice F2 Solubility Equilibrium, Ksp Name MC Pratie F Solubility Equilibrium, Ksp Name This is pratie - Do NOT heat yourself of finding out what you are apable of doing. Be sure you follow the testing onditions outlined below. DO NOT USE A CALCULATOR.

More information

REVIEW QUESTIONS Chapter 15

REVIEW QUESTIONS Chapter 15 hemistry 10 ANSWER EY REVIEW QUESTIONS hapter 15 1. A mixture of 0.10 mol of NO, 0.050 mol of H and 0.10 mol of HO is plaed in a 1.0-L flask and allowed to reah equilibrium as shown below: NO (g) + H (g)

More information

Chapter 13, Chemical Equilibrium

Chapter 13, Chemical Equilibrium Chapter 13, Chemial Equilibrium You may have gotten the impression that when 2 reatants mix, the ensuing rxn goes to ompletion. In other words, reatants are onverted ompletely to produts. We will now learn

More information

Chapter 15 Equilibrium. Reversible Reactions & Equilibrium. Reversible Reactions & Equilibrium. Reversible Reactions & Equilibrium 2/3/2014

Chapter 15 Equilibrium. Reversible Reactions & Equilibrium. Reversible Reactions & Equilibrium. Reversible Reactions & Equilibrium 2/3/2014 Amount of reatant/produt //01 quilibrium in Chemial Reations Lets look bak at our hypothetial reation from the kinetis hapter. A + B C Chapter 15 quilibrium [A] Why doesn t the onentration of A ever go

More information

SOLVED QUESTIONS 1 / 2. in a closed container at equilibrium. What would be the effect of addition of CaCO 3 on the equilibrium concentration of CO 2?

SOLVED QUESTIONS 1 / 2. in a closed container at equilibrium. What would be the effect of addition of CaCO 3 on the equilibrium concentration of CO 2? SOLVED QUESTIONS Multile Choie Questions. and are the veloity onstants of forward and bakward reations. The equilibrium onstant k of the reation is (A) (B) (C) (D). Whih of the following reations will

More information

Chapter 15 Equilibrium. Reversible Reactions & Equilibrium. Reversible Reactions & Equilibrium. Reversible Reactions & Equilibrium 5/27/2014

Chapter 15 Equilibrium. Reversible Reactions & Equilibrium. Reversible Reactions & Equilibrium. Reversible Reactions & Equilibrium 5/27/2014 Amount of reatant/produt 5/7/01 quilibrium in Chemial Reations Lets look bak at our hypothetial reation from the kinetis hapter. A + B C Chapter 15 quilibrium [A] Why doesn t the onentration of A ever

More information

2. Failure to submit this paper in its entirety at the end of the examination may result in disqualification.

2. Failure to submit this paper in its entirety at the end of the examination may result in disqualification. Memorial University of Newfoundland St. John s, Newfoundland and Labrador Chemistry 101 Intersession 007 Midterm Exam May 8 th, 007 Time: 0 Minutes Name: MUN #: Dr. Peter Warburton READ THE FOLLOWING CAREFULLY!

More information

CHAPTERS 8-12 BOOKLET-3

CHAPTERS 8-12 BOOKLET-3 CHEMISTRY XI CHAPTERS 8-1 BKLET- Contents: Page No. Chapter 8 Chemial Equilibrium 181-199 Chapter 9 Redox Reations 00-19 Chapter 10 s & p Blok Elements part 1 0-49 Chapter 11 s & p Blok Elements part 50-77

More information

Equilibrium 07 M07_CHSL_SB_IBD_9069_U07.indd /07/ :21

Equilibrium 07 M07_CHSL_SB_IBD_9069_U07.indd /07/ :21 07 Equilibrium Essential ideas 7.1 Many reations are reversible. These reations will reah a state of equilibrium when the rates of the forward reation and reverse reation are equal. The position of equilibrium

More information

Chemistry 12: Dynamic Equilibrium Practice Test

Chemistry 12: Dynamic Equilibrium Practice Test Chemistry 12: Dynamic Equilibrium Practice Test A. Multiple Choice: For each question, select the best answer and record your choice on the answer key provided. /25 1) A system at equilibrium is said to

More information

JF Physical Chemistry JF CH 1101: Introduction to Physical Chemistry.

JF Physical Chemistry JF CH 1101: Introduction to Physical Chemistry. JF Physial Chemistry 010-011. JF CH 1101: Introdution to Physial Chemistry. Dr Mike Lyons. Shool of Chemistry Trinity College Dublin. melyons@td.ie A ompendium of past examination questions set on Physial

More information

(b) Increase in pressure. (1)

(b) Increase in pressure. (1) 1 This question is about the equilibrium reaction between hydrogen and carbon dioxide. H 2 (g) + O 2 (g) H 2 O(g) + O(g) H = +40 kj mol 1 What effect would the following changes have on the rate of reaction

More information

91166 Demonstrate understanding of chemical reactivity Collated questions on equilibria

91166 Demonstrate understanding of chemical reactivity Collated questions on equilibria (2017:2) 91166 Demonstrate understanding of chemical reactivity Collated questions on equilibria The addition of a small amount of iron to a mixture of nitrogen and hydrogen gases helps to speed up the

More information

Module 4 Lesson 2 Exercises Answer Key squared square root

Module 4 Lesson 2 Exercises Answer Key squared square root Module Lesson Eerises Answer Key 1. The volume is 1 L so onentrations an be done by inspetion. Just substitute values and solve for K [ CO][ HO] K CO H (0.8)(0.8) (0.55) (0.55) K 0.659. [CH ][HS] K [H

More information

Chapter 15. Chemical Equilibrium

Chapter 15. Chemical Equilibrium Chapter 15. Chemical Equilibrium 15.1 The Concept of Equilibrium Consider colorless frozen N 2 O 4. At room temperature, it decomposes to brown NO 2. N 2 O 4 (g) 2NO 2 (g) At some time, the color stops

More information

Chapter 15 Equilibrium

Chapter 15 Equilibrium Chapter 15. Chemical Equilibrium Common Student Misconceptions Many students need to see how the numerical problems in this chapter are solved. Students confuse the arrows used for resonance ( )and equilibrium

More information

QUESTIONS: Equilibria AS & AS

QUESTIONS: Equilibria AS & AS QUESTION (2012:2) Phosphorus pentachloride gas, PCl 5 (g), decomposes to form phosphorus trichloride gas, PCl 3 (g), and chlorine gas, Cl 2 (g). The equilibrium can be represented as: PCl 5 (g) Ý PCl 3

More information

Chapter 15 Equilibrium

Chapter 15 Equilibrium Chapter 15. Chemical Equilibrium Common Student Misconceptions Many students need to see how the numerical problems in this chapter are solved. Students confuse the arrows used for resonance ( )and equilibrium

More information

Chemistry 12 Provincial Workbook Unit 02: Chemical Equilibrium. Multiple Choice Questions

Chemistry 12 Provincial Workbook Unit 02: Chemical Equilibrium. Multiple Choice Questions R. Janssen, MSEC Chemistry 1 Provincial Workbook (Unit 0), P. 1 / 63 Chemistry 1 Provincial Workbook Unit 0: Chemical Equilibrium 1. Consider the following... Multiple Choice Questions Which of the following

More information

When a reversible reaction occurs in a closed system an equilibrium is formed, in which the original reactants and products formed coexist.

When a reversible reaction occurs in a closed system an equilibrium is formed, in which the original reactants and products formed coexist. When a reversible reaction occurs in a closed system an equilibrium is formed, in which the original reactants and products formed coexist. At equilibrium there is a state of balance between the concentrations

More information

8. The table below describes two different reactions in which Reaction 1 is faster. What accounts for this observation? Reaction 1 Reaction 2.

8. The table below describes two different reactions in which Reaction 1 is faster. What accounts for this observation? Reaction 1 Reaction 2. Public Review - Rates and Equilibrium June 2005 1. What does X represent in the diagram below? (A) activation energy for the forward reaction (B) activation energy for the reverse reaction (C) heat of

More information

Part II SECTION I : One or more options correct Type

Part II SECTION I : One or more options correct Type [1] JEE Advaned 2013/ Paper -2 Part II SECTION I : One or more options orret Type This setion ontains 8 multiple hoie questions. Eah question has four hoies (A), (B), (C) and (D), out of whih ONE or MORE

More information

Chapter 15. Chemical Equilibrium

Chapter 15. Chemical Equilibrium Chapter 15. Chemical Equilibrium 15.1 The Concept of Equilibrium Consider colorless frozen N 2 O 4. At room temperature, it decomposes to brown NO 2. N 2 O 4 (g) 2NO 2 (g) At some time, the color stops

More information

Kinetics & Equilibrium Review Packet. Standard Level. 1. Which quantities in the enthalpy level diagram are altered by the use of a catalyst?

Kinetics & Equilibrium Review Packet. Standard Level. 1. Which quantities in the enthalpy level diagram are altered by the use of a catalyst? Kinetics & Equilibrium Review Packet Standard Level 1. Which quantities in the enthalpy level diagram are altered by the use of a catalyst? Enthalpy I II III Time A. I and II only B. I and III only C.

More information

Unit 2 Pre-Test Reaction Equilibrium

Unit 2 Pre-Test Reaction Equilibrium Unit 2 Pre-Test Reaction Equilibrium Multiple Choice Identify the choice that best completes the statement or answers the question. 1. Consider the following equilibrium system: 2HF(g) F 2(g) + H 2 (g)

More information

Notation 2, 8, 1 2, 8, 2 2, 8

Notation 2, 8, 1 2, 8, 2 2, 8 Page 90 Atomi struture 2 1 a Contains 3 protons (1); and 4 neutrons (1) Page 90 Eletroni struture 2 a 2, 8 Type of reation Ionisation Nulear fission Nulear fusion Change in mass of nuleus Stays the same

More information

January 03, Ch 13 SB equilibrium.notebook

January 03, Ch 13 SB equilibrium.notebook Ch 13: Chemical Equilibrium exists when 2 opposing reactions occur simultaneously at the same rate (dynamic rather than static) Forward rate = reverse rate https://www.youtube.com/watch?v=wld_imyqagq The

More information

6. Which expression correctly describes the equilibrium constant for the following reaction? 4NH 3 (g) + 5O 2 (g) 4NO(g) + 6H 2 O(g)

6. Which expression correctly describes the equilibrium constant for the following reaction? 4NH 3 (g) + 5O 2 (g) 4NO(g) + 6H 2 O(g) 1. Which of the following can we predict from an equilibrium constant for a reaction? 1. The extent of a reaction 2. Whether the reaction is fast or slow 3. Whether a reaction is exothermic or endothermic

More information

Chapter 15 Equilibrium

Chapter 15 Equilibrium Chapter 15. Chemical Equilibrium 15.1 The Concept of Equilibrium Chemical equilibrium is the point at which the concentrations of all species are constant. A dynamic equilibrium exists when the rates of

More information

KINETICS OF IRON OXIDE DIRECT REDUCTION BY COAL E.R. ABRIL 1

KINETICS OF IRON OXIDE DIRECT REDUCTION BY COAL E.R. ABRIL 1 KINETICS OF IRON OXIDE DIRECT REDUCTION BY COAL E.R. ABRIL 1 CIMM- Av.Velez Sarsfield 1561 C.P.5000 Córdoba, Argentina. aabril@intiemor.gov.ar Abstrat - A new interpretation to the kinetis of iron oxide

More information

CHEMICAL EQUILIBRIUM. I. Multiple Choice 15 marks. 1. Reactions that can proceed in both the forward and reverse directions are said to be:

CHEMICAL EQUILIBRIUM. I. Multiple Choice 15 marks. 1. Reactions that can proceed in both the forward and reverse directions are said to be: Name: Unit Test CHEMICAL EQUILIBRIUM Date: _ 50 marks total I. Multiple Choice 15 marks 1. Reactions that can proceed in both the forward and reverse directions are said to be: A. complete B. reversible

More information

CHAPTER 15 PRINCIPLES OF CHEMICAL EQUILIBRIUM

CHAPTER 15 PRINCIPLES OF CHEMICAL EQUILIBRIUM CHAPTER 15 PRINCIPLES OF CHEMICAL EQUILIBRIUM PRACTICE EXAMPLES 1A 1B (E) The reation is as follows: Cu (aq) Sn (aq) Cu (aq) Sn (aq) Therefore, the equilibrium exression is as follows: Cu Sn Cu Sn Rearranging

More information

Chapter 9. Chemical Equilibrium

Chapter 9. Chemical Equilibrium Chapter 9. Chemical Equilibrium 9.1 The Nature of Chemical Equilibrium -Approach to Equilibrium [Co(H 2 O) 6 ] 2+ + 4 Cl- [CoCl 4 ] 2- + 6 H 2 O Characteristics of the Equilibrium State example) H 2 O(l)

More information

Equilibrium and Reaction Rate

Equilibrium and Reaction Rate Equilibrium and Reaction Rate Multiple Choice Questions - Answers 1. Activation energy could be considered as the minimum energy required to do which of these? A. change the orientation of the reactant

More information

Equilibrium & Reaction Rate

Equilibrium & Reaction Rate Equilibrium & Reaction Rate 1. One of the important reactions in coal gasification is the catalytic methanation reaction: CO(g) + H (g) H O(g) + CH 4 (g) H 06 kj a) Predict the direction in which this

More information

AS Paper 1 and 2 Kc and Equilibria

AS Paper 1 and 2 Kc and Equilibria AS Paper 1 and 2 Kc and Equilibria Q1.When one mole of ammonia is heated to a given temperature, 50 per cent of the compound dissociates and the following equilibrium is established. NH 3(g) ½ N 2 (g)

More information

CHEMICAL EQUILIBRIUM. Chapter 15

CHEMICAL EQUILIBRIUM. Chapter 15 Chapter 15 P a g e 1 CHEMICAL EQUILIBRIUM Examples of Dynamic Equilibrium Vapor above a liquid is in equilibrium with the liquid phase. rate of evaporation = rate of condensation Saturated solutions rate

More information

CHEMICAL EQUILIBRIUM. Chapter 16. Pb 2+ (aq) + 2 Cl (aq) e PbCl 2 (s) PLAY MOVIE Brooks/Cole - Cengage

CHEMICAL EQUILIBRIUM. Chapter 16. Pb 2+ (aq) + 2 Cl (aq) e PbCl 2 (s) PLAY MOVIE Brooks/Cole - Cengage 1 CHEMICAL EQUILIBRIUM Chapter 16 PLAY MOVIE Pb 2+ (aq) + 2 Cl (aq) e PbCl 2 (s) Properties of an Equilibrium Equilibrium systems are DYNAMIC (in constant motion) REVERSIBLE can be approached from either

More information

Gas Phase Equilibrium

Gas Phase Equilibrium Gas Phase Equilibrium Chemical Equilibrium Equilibrium Constant K eq Equilibrium constant expression Relationship between K p and K c Heterogeneous Equilibria Meaning of K eq Calculations of K c Solving

More information

1. The Haber- Bosch Process 2. K eq

1. The Haber- Bosch Process 2. K eq Chemistry 12 Equilibrium III Name: Date: Block: 1. The Haber- Bosch Process 2. K eq The Haber- Bosch Process Almost all of the world s ammonia is produced via the Haber- Bosch process and almost all of

More information

Le Châtelier s Principle. 19 Copyright Pearson Education, Inc., or its affiliates. All Rights Reserved. Equilibrium: Le Châtelier s Principle

Le Châtelier s Principle. 19 Copyright Pearson Education, Inc., or its affiliates. All Rights Reserved. Equilibrium: Le Châtelier s Principle Factors Affecting : Le Châtelier s Principle Pressure Factors Affecting : Le Châtelier s Principle Pressure When volume decreases, the pressure increases. systems in which some reactants and products are

More information

ELECTROCHEMISTRY Lecture/Lession Plan -1

ELECTROCHEMISTRY Lecture/Lession Plan -1 Chapter 4 ELECTROCHEMISTRY Leture/Lession Plan -1 ELECTROCHEMISTRY 4.1 Conept of eletrohemistry Eletrohemistry is a branh of hemistry where we will study how hemial energy an be transformed into eletrial

More information

CHEMICAL EQUILIBRIUM. 6.3 Le Chatelier s Principle

CHEMICAL EQUILIBRIUM. 6.3 Le Chatelier s Principle CHEMICAL EQUILIBRIUM 6.3 Le Chatelier s Principle At the end of the lesson, students should be able to: a) State Le Chatelier s principle b) Explain the effect of the following factors on a system at equilibrium

More information

15.1 The Concept of Equilibrium

15.1 The Concept of Equilibrium Lecture Presentation Chapter 15 Chemical Yonsei University 15.1 The Concept of N 2 O 4 (g) 2NO 2 (g) 2 Chemical equilibrium occurs when a reaction and its reverse reaction proceed at the same rate. The

More information

All reversible reactions reach an dynamic equilibrium state. H 2 O+ CO H 2 +CO 2. Rate of reverse reaction (H 2 + CO 2 )

All reversible reactions reach an dynamic equilibrium state. H 2 O+ CO H 2 +CO 2. Rate of reverse reaction (H 2 + CO 2 ) 4.2 Equilibria Many reactions are reversible + 3H 2 2NH 3 All reversible reactions reach an dynamic equilibrium state. Dynamic equilibrium occurs when forward and backward reactions are occurring at equal

More information

Equilibrium Multiple Choice

Equilibrium Multiple Choice Equilibrium Multiple Choice January 1999 7. Consider the following graph: When equilibrium is reached, the rate of the forward reaction is A. 0.00 mol/min B. 0.25mol/min C. 1.0 mol/min D. 3.0 mol/min 8.

More information

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. A) B) 1588 C) 397 D) 28 E) 0.

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. A) B) 1588 C) 397 D) 28 E) 0. Exam Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) The value of Keq for the equilibrium 1) H2 (g) + I2 (g) 2 HI (g) is 794 at 25 C. What

More information

Section 7.2: Equilibrium Law and the Equilibrium Constant Tutorial 1 Practice, page (a) 2 CO 2 (g) #!!"

Section 7.2: Equilibrium Law and the Equilibrium Constant Tutorial 1 Practice, page (a) 2 CO 2 (g) #!! Section 7.: Equilibrium Law and the Equilibrium Constant Tutorial Practice, page 4. (a) CO (g) #!!"! CO(g) + O (g) Products: CO(g); O (g) Reactant: CO (g) [CO [O Equilibrium law equation: [CO (b) Cl (g)

More information

K P VERSUS K C PROPERTIES OF THE EQUILIBRIUM CONSTANT

K P VERSUS K C PROPERTIES OF THE EQUILIBRIUM CONSTANT K P VERSUS K C 1. What are the units of K p and K c for each of the following? a) 2H 2 S(g) 2H 2 (g) + S 2 (g) b) 4NH 3 (g) + 3O 2 (g) 2N 2 (g) + 6H 2 O(g) 2. What are the units of K p and K c for each

More information

III. SURFACE PROPERTIES III.A. SURFACE TENSION SURFACE PROPERTIES

III. SURFACE PROPERTIES III.A. SURFACE TENSION SURFACE PROPERTIES III. SURFACE PROPERTIES III.A. SURFACE TENSION GOAL: To investigate the influene of the solution onentration and/or the kind of the solute on the surfae tension INTRODUCTION Liquids tend to adopt shapes

More information

Improvements in the Modeling of the Self-ignition of Tetrafluoroethylene

Improvements in the Modeling of the Self-ignition of Tetrafluoroethylene Exerpt from the Proeedings of the OMSOL onferene 010 Paris Improvements in the Modeling of the Self-ignition of Tetrafluoroethylene M. Bekmann-Kluge 1 *,. errero 1, V. Shröder 1, A. Aikalin and J. Steinbah

More information

Chemical Equilibrium

Chemical Equilibrium Chemical Equilibrium Concept of Equilibrium Equilibrium Constant Equilibrium expressions Applications of equilibrium constants Le Chatelier s Principle The Concept of Equilibrium The decomposition of N

More information

The Extent of Chemical Reactions

The Extent of Chemical Reactions Equilibrium: The Extent of Chemical Reactions The Equilibrium State and the Equilibrium Constant The Reaction Quotient and the Equilibrium Constant Equilibrium: The Extent of Chemical Reactions Expressing

More information

1. a. The rates of the forward and reverse reactions are equal at equilibrium.

1. a. The rates of the forward and reverse reactions are equal at equilibrium. CHATER THIRTEEN CHEMICAL EQUILIBRIUM For Review 1. a. The rates of the forward and reverse reactions are equal at equilibrium. b. There is no net change in the composition (as long as temperature is constant).

More information

Chapter 15 Equilibrium

Chapter 15 Equilibrium Chapter 15. Chemical Equilibrium Sample Exercise 15.1 (p. 632) Write the equilibrium expression for K eq for these three reactions: a) 2 O 3(g) 3 O 2(g) b) 2 NO (g) + Cl 2(g) 2 NOCl (g) c) Ag + (aq) +

More information

AP Chemistry Chapter 16 Assignment. Part I Multiple Choice

AP Chemistry Chapter 16 Assignment. Part I Multiple Choice Page 1 of 7 AP Chemistry Chapter 16 Assignment Part I Multiple Choice 1984 47. CH 4 (g) + 2 O 2 (g) CO 2 (g) + 2 H 2 O(l) H = 889.1 kj H f H 2 O(l) = 285.8 kj mol 1 H f CO 2 (g) = 393.3 kj mol 1 What is

More information

Chemical Equilibrium. Professor Bice Martincigh. Equilibrium

Chemical Equilibrium. Professor Bice Martincigh. Equilibrium Chemical Equilibrium by Professor Bice Martincigh Equilibrium involves reversible reactions Some reactions appear to go only in one direction are said to go to completion. indicated by All reactions are

More information

CHEMICAL EQUILIBRIA. Dynamic Equilibrium Equilibrium involves reversible reactions which do not go to completion.

CHEMICAL EQUILIBRIA. Dynamic Equilibrium Equilibrium involves reversible reactions which do not go to completion. CHEMICAL EQUILIBRIA Dynamic Equilibrium Equilibrium involves reversible reactions which do not go to completion. If we consider a reaction between A and B to form C and D which is reversible. When A and

More information

Chemical Equilibrium: Ch Dynamic Equilibrium. Dynamic Equilibrium. Three Approaches to Equilibrium The Equilibrium Constant Expression

Chemical Equilibrium: Ch Dynamic Equilibrium. Dynamic Equilibrium. Three Approaches to Equilibrium The Equilibrium Constant Expression Chemical Equilibrium: Ch. 15 15-1 Dynamic Equilibrium 15- The Equilibrium Constant Expression 15- Relationships Involving Equilibrium Constants 15-4 The Magnitude of an Equilibrium Constant 15-5 The Reaction

More information

3. Indicate the mass action expression for the following reaction: 2X(g) + Y(g) 3W(g) + V(g) a) [X] 2 [Y][W] 3 [V] [W] 3 [V] [X] 2 [Y] [3W][V] [2X][Y]

3. Indicate the mass action expression for the following reaction: 2X(g) + Y(g) 3W(g) + V(g) a) [X] 2 [Y][W] 3 [V] [W] 3 [V] [X] 2 [Y] [3W][V] [2X][Y] 1. Which of the following statements concerning equilibrium is not true? a) A system that is disturbed from an equilibrium condition responds in a manner to restore equilibrium. b) Equilibrium in molecular

More information

Chapter 6: Chemical Equilibrium

Chapter 6: Chemical Equilibrium Chapter 6: Chemical Equilibrium 6.1 The Equilibrium Condition 6.2 The Equilibrium Constant 6.3 Equilibrium Expressions Involving Pressures 6.4 The Concept of Activity 6.5 Heterogeneous Equilibria 6.6 Applications

More information

Chemistry (Physical chemistry) Lecture 10.

Chemistry (Physical chemistry) Lecture 10. Chemistry (Physial hemistry) Leture 0. EPM, semester II by Wojieh Chrzanowsi, PhD, DS Wyłady współfinansowane ze środów Unii Europejsiej w ramah EFS, UDA-POKL 04.0.02.-00-37/-00 Absolwent Wydziału Chemiznego

More information

F322: Chains, Energy and Resources Rates and Equilibria

F322: Chains, Energy and Resources Rates and Equilibria F322: Chains, Energy and Resources 2.3.2 Rates and Equilibria 1. Dilute aqueous hydrogen peroxide, H 2 O 2 (aq), is used to sterilise contact lenses. Dilute H 2 O 2 (aq) slowly decomposes at room temperature

More information

1.0 L container NO 2 = 0.12 mole. time

1.0 L container NO 2 = 0.12 mole. time CHEM 1105 GAS EQUILIBRIA 1. Equilibrium Reactions - a Dynamic Equilibrium Initial amounts: = mole = 0 mole 1.0 L container = 0.12 mole moles = 0.04 mole 0 time (a) 2 In a 1.0 L container was placed 4.00

More information

(b) Describe, and explain, what would happen to the position of the NO 2 /N 2 O 4 equilibrium if the following changes are made

(b) Describe, and explain, what would happen to the position of the NO 2 /N 2 O 4 equilibrium if the following changes are made 1. Nitrogen dioxide, NO 2, and dinitrogen tetroxide, N 2 O 4, take part in the following equilibrium. 2NO 2 (g) N 2 O 4 (g) ΔH = 58 kj mol 1 (a) State le Chatelier s principle. (b) Describe, and explain,

More information

CHEMICAL EQUILIBRIA: GENERAL CONCEPTS

CHEMICAL EQUILIBRIA: GENERAL CONCEPTS CHEMICAL EQUILIBRIA: GENERAL CONCEPTS THE NATURE OF THE EQUILIBRIUM STATE: Equilibrium is the state where the concentrations of all reactants and products remain constant with time. (in stoichiometry,

More information

DYNAMIC EQUILIBRIUM STUDY GUIDE multiple choice

DYNAMIC EQUILIBRIUM STUDY GUIDE multiple choice DYNAMIC EQUILIBRIUM STUDY GUIDE multiple choice Multiple Choice Section: This study guide is a compilation of questions from provincial exams since April 1994. I urge you to become intimately familiar

More information

C h a p t e r 13. Chemical Equilibrium

C h a p t e r 13. Chemical Equilibrium C h a p t e r 13 Chemical Equilibrium Chemical equilibrium is achieved when: the rates of the forward and reverse reactions are equal and the concentrations of the reactants and products remain constant

More information

Chapter 15 Chemical Equilibrium

Chapter 15 Chemical Equilibrium Equilibrium To be in equilibrium is to be in a state of balance: Chapter 15 Chemical Equilibrium - Static Equilibrium (nothing happens; e.g. a tug of war). - Dynamic Equilibrium (lots of things happen,

More information

Le Châtelier's Principle. Chemical Equilibria & the Application of Le Châtelier s Principle to General Equilibria. Using Le Châtelier's Principle

Le Châtelier's Principle. Chemical Equilibria & the Application of Le Châtelier s Principle to General Equilibria. Using Le Châtelier's Principle Chemical Equilibria & the Application of Le Châtelier s Principle to General Equilibria CHEM 107 T. Hughbanks Le Châtelier's Principle When a change is imposed on a system at equilibrium, the system will

More information

Q1. (a) State what is meant by the term activation energy of a reaction. (1)

Q1. (a) State what is meant by the term activation energy of a reaction. (1) Q1. (a) State what is meant by the term activation energy of a reaction. (c) State in general terms how a catalyst increases the rate of a chemical reaction. The curve below shows the Maxwell Boltzmann

More information

Equilibrium Written Response

Equilibrium Written Response Equilibrium Written Response January 1998 2. Consider the following equilibrium: CS2 (g) + 3Cl2 (g) CCl4 (g) + S2Cl2 (g) ΔH = -238 kj a) Sketch a potential energy diagram for the reaction above and label

More information

Chemical Kinetics and Equilibrium

Chemical Kinetics and Equilibrium Chemical Kinetics and Equilibrium 1 Which statement incorrectly describes a chemical reaction approaching equilibrium? As a chemical reaction approaches equilibrium, the net change in the amount of reactants

More information

Write equilibrium law expressions from balanced chemical equations for heterogeneous and homogeneous systems. Include: mass action expression.

Write equilibrium law expressions from balanced chemical equations for heterogeneous and homogeneous systems. Include: mass action expression. Equilibrium 1 UNIT 3: EQUILIBRIUM OUTCOMES All important vocabulary is in Italics and bold. Relate the concept of equilibrium to physical and chemical systems. Include: conditions necessary to achieve

More information

Chemical reactions with large K c (also K p) effectively go 100% to products.

Chemical reactions with large K c (also K p) effectively go 100% to products. th 7 Homework: Reading, M&F, ch. 13, pp. 506-524 (applications of equilibrium constants, Le Chatelier s Principle). Problems: Nakon, ch. 17, #9, 10, 12-15, 17, 24, 34; M&F, ch. 13, #41, 42, 44, 49, 51,

More information

(g) + 3 H 2. (g) 2 NH 3. 1) Only gases and dissolved species appear in an equilibrium expression. 4 NH 3. O(g) K c = (s) + 2N 2.

(g) + 3 H 2. (g) 2 NH 3. 1) Only gases and dissolved species appear in an equilibrium expression. 4 NH 3. O(g) K c = (s) + 2N 2. Chapter 16: Chemical Equilibrium What is meant by an equilibrium system? What is an equilibrium expression? N 2 +3 H 2 2 NH 3 1) Only gases and dissolved species appear in an equilibrium expression. 4

More information

Replacement of gas phase with liquid, for hexamine production

Replacement of gas phase with liquid, for hexamine production Proeedings of the International Conferene on Ciruits, Systems, Signals Replaement of gas phase with liquid, for hexamine prodution Anita Kovač Kralj¹ Davorin Kralj² Faulty of Chemistry and Chemial Engineering,

More information

Case Study: The Industrial Manufacture of Ammonia The Haber Process

Case Study: The Industrial Manufacture of Ammonia The Haber Process Case Study: The Industrial Manufacture of Ammonia The Haber Process In the Haber Process, ammonia (NH3) is synthesised from nitrogen and hydrogen gases: N 2 (g) + 3H 2 (g) Ý 2NH3(g), ΔH = 92.4 kjmol -1

More information

Which of the following factors will not alter the position of equilibrium?

Which of the following factors will not alter the position of equilibrium? 86 N( g) + 3H $ ( g) NH3 ( g) Which of the following factors will not alter the position of uilibrium? A a pressure decrease B a temperature increase C the presence of a catalyst D the addition of more

More information

Determination of the reaction order

Determination of the reaction order 5/7/07 A quote of the wee (or amel of the wee): Apply yourself. Get all the eduation you an, but then... do something. Don't just stand there, mae it happen. Lee Iaoa Physial Chemistry GTM/5 reation order

More information

Chapter 6: Chemical Equilibrium

Chapter 6: Chemical Equilibrium Chapter 6: Chemical Equilibrium 6.1 The Equilibrium Condition 6. The Equilibrium Constant 6.3 Equilibrium Expressions Involving Pressures 6.4 The Concept of Activity 6.5 Heterogeneous Equilibria 6.6 Applications

More information

Chapter Test A. Chapter: Chemical Equilibrium

Chapter Test A. Chapter: Chemical Equilibrium Assessment Chapter Test A Chapter: Chemical Equilibrium In the space provided, write the letter of the term or phrase that best completes each statement or best answers each question. 1. A 15.0 ml volume

More information

REACTION EQUILIBRIUM

REACTION EQUILIBRIUM REACTION EQUILIBRIUM A. REVERSIBLE REACTIONS 1. In most spontaneous reactions the formation of products is greatly favoured over the reactants and the reaction proceeds to completion (one direction). In

More information

Chemical Equilibrium. A state of no net change in reactant & product concentrations. There is a lot of activity at the molecular level.

Chemical Equilibrium. A state of no net change in reactant & product concentrations. There is a lot of activity at the molecular level. Chemical Equilibrium A state of no net change in reactant & product concentrations. BUT There is a lot of activity at the molecular level. 1 Kinetics Equilibrium For an elementary step in the mechanism:

More information

c) Explain the observations in terms of the DYNAMIC NATURE of the equilibrium system.

c) Explain the observations in terms of the DYNAMIC NATURE of the equilibrium system. Chemical Equilibrium - Part A: 1. At 25 o C and 101.3 kpa one mole of hydrogen gas and one mol of chlorine gas are reacted in a stoppered reaction vessel. After a certain time, three gases are detected

More information

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. A) 1588 B) C) 28 D) 397 E) 0.

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. A) 1588 B) C) 28 D) 397 E) 0. Chapter 15 MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) The value of Keq for the equilibrium 1) H2 (g) + I2 (g) 2 HI (g) is 794 at 25 C. What

More information

All reversible reactions reach an dynamic equilibrium state.

All reversible reactions reach an dynamic equilibrium state. 11. Equilibrium II Many reactions are reversible + 3 2NH 3 All reversible reactions reach an dynamic equilibrium state. Dynamic equilibrium occurs when forward and backward reactions are occurring at equal

More information

AP Chemistry Practice Problems Module 9: Kinetics and Equilibrium

AP Chemistry Practice Problems Module 9: Kinetics and Equilibrium AP Chemistry Practice Problems Module 9: Kinetics and Equilibrium The headings on these problems correspond to the headings on your content pages. You should work on these throughout the unit. Be sure

More information

Chapter 13: Chemical Equilibrium

Chapter 13: Chemical Equilibrium Chapter 13: Chemical Equilibrium May 5 2:04 PM 13.1 The Equilibrium Condition When you finish this section you will be able to list some characteristics of reactions at equilibrium. Chemical equilibrium

More information

Name Chem 6 Section #

Name Chem 6 Section # Equilibrium Constant and its Meaning 1. Write the expressions for K eq for the following reactions. a) CH 4 (g) + 2 H 2 S(g) CS 2 (g) + 4 H 2 (g) b) 2 N 2 O 5 (g) 4 NO 2 (g) + O 2 (g) c) 3 O 2 (g) 2 O

More information