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1 FinalExamlassWork nswer Section TRUE/FLSE 1. NS: T PTS: 1 IF: loom's Level 2 OK 1 NT:.4 2. NS: T PTS: 1 IF: loom's Level 2 OK 1 NT:.2 3. NS: T PTS: 1 IF: loom's Level 3 OK 1 NT:.1 ST: S NS: T PTS: 1 IF: loom's Level 2 OK 1 NT: UP.2.1 ST: S NS: T PTS: 1 IF: loom's Level 1 OK 1 NT: UP.2.1 ST: S NS: T PTS: 1 IF: loom's Level 1 OK 1 NT:.1 ST: S NS: T PTS: 1 IF: loom's Level 2 OK 1 NT:.3 ST: S NS: F basic solution contains more hydroxide ions than hydrogen ions. PTS: 1 IF: loom's Level 1 OK 1 NT: UP.2.3 ST: S NS: T PTS: 1 IF: loom's Level 1 OK 1 NT: UP.2.3 MULTIPLE HOIE 10. NS: Use GL law: P 1 V 1 = P 2 V 2 PTS: 1 IF: loom's Level 3 OK 2 NT: UP.2 UP NS: PTS: 1 IF: loom's Level 3 OK 2 NT: UP NS: Using harles s law,. First, convert the temperature to Kelvin. Then, use harles's law. lso, the value of T1, in Kelvin, is 459 and not 363. The value of T2 is 363 and not 459. orrect! First, convert the temperature to Kelvin. Then, calculate the volume using harles's law. PTS: 1 IF: loom's Level 2 OK 2 NT: UP.1 UP.3.4
2 TOP: pply the three gas laws to problems involving the pressure, temperature, and volume of a gas. KEY: harles's law MS: NS: Using harles s law,. First, convert the temperature to Kelvin. Then, use harles's law. lso, the value of T1, in Kelvin, is 303, and not 407. The value of T2 is 407, and not 303. orrect! First, convert the temperature to Kelvin. Then, use harles's law. PTS: 1 IF: loom's Level 2 OK 2 NT: UP.1 UP.3.4 TOP: pply the three gas laws to problems involving the pressure, temperature, and volume of a gas. KEY: harles's law MS: NS: Using the combined gas law equation,. First, convert the temperature to Kelvin. Then, use the combined gas law equation. orrect! The value of T1 in Kelvin is 299 K. ivide P1V1 by 299 K. PTS: 1 IF: loom's Level 2 OK 2 NT: UP.1 UP TOP: pply the combined gas law to problems involving pressure, temperature, and volume of a gas. KEY: The combined gas law MS: NS: Using the combined gas law equation,. First, convert the temperature to Kelvin. Then, use the combined gas law equation. orrect! The value of T1 in Kelvin is 305 and not 294. ivide P1V1 by 305 K. PTS: 1 IF: loom's Level 2 OK 2 NT: UP.1 UP TOP: pply the combined gas law to problems involving pressure, temperature, and volume of a gas. KEY: The combined gas law MS: NS: PTS: 1 IF: loom's Level 3 OK 2 NT: UP NS: PTS: 1 IF: loom's Level 3 OK 2
3 NT: UP NS: PTS: 1 IF: loom's Level 3 OK 2 NT: UP NS: PTS: 1 IF: loom's Level 3 OK 2 NT: UP NS: PTS: 1 IF: loom's Level 3 OK 2 NT: UP NS: Multiply the number of moles by the number of representative particles. orrect! Multiply the number of moles with the correct value of vogadro's number. The position of the decimal value is incorrect. PTS: 1 IF: loom's Level 1 OK 2 NT: UP.3 TOP: onvert moles to number of representative particles and number of representative particles to moles. KEY: onverting moles to representative particles MS: NS: Instead of multiplying the known number of moles of the element by vogadro's number, multiply it with the molar mass of the element. Instead of dividing the known number of moles of the element by vogadro's number, multiply it with the molar mass of the element. orrect! Multiply the known number of moles of the element by the molar mass of the element. PTS: 1 IF: loom's Level 1 OK 2 NT: UP.3.1 TOP: alculate the number of moles in a given mass of an element and the mass of a given number of moles of an element. KEY: Mole to mass conversion MS: NS: Multiply the number of atoms by the inverse of vogadro's number. Multiplying the number of atoms by the inverse of vogadro's number nullifies the power of the indices. orrect! ivide the number of atoms by vogadro's number. PTS: 1 IF: loom's Level 1 OK 2 NT: UP.3 TOP: onvert moles to number of representative particles and number of representative particles to moles.
4 KEY: onverting representative particles to moles MS: NS: orrect! Instead of dividing 425 g of calcium by vogadro's number, divide it by its molar mass. Multiply the known amount of calcium by the inverse of its molar mass. Instead of multiplying 425 g of calcium by vogadro's number, divide it by its molar mass. PTS: 1 IF: loom's Level 1 OK 2 NT: UP.3.1 TOP: alculate the number of moles in a given mass of an element and the mass of a given number of moles of an element. KEY: Mass to mole conversion MS: NS: The molar mass of a(oh) 2 is calculated after adding the masses of all the elements. There are two moles of oxygen in a calcium hydroxide molecule. The atomic mass of hydrogen is In a calcium hydroxide molecule, there are two moles of hydrogen. orrect! PTS: 1 IF: loom's Level 2 OK 2 NT:.3 TOP: alculate the molar mass of a compound. KEY: Molar mass MS: NS: Step 1: Step 2: The number of grams of sulfuric acid is 98.0 g. Multiply the molar mass by 2.25 moles of sulfuric acid. The atomic mass of oxygen is 16. orrect! PTS: 1 IF: loom's Level 2 OK 2 NT: UP.3 TOP: alculate the number of moles of a compound from a given mass of the compound, and the mass of a compound from a given number of moles of the compound. KEY: onverting moles of a compound to mass MS: NS: Step 1:
5 Step 2: The number of grams of potassium permanganate is g. orrect! The atomic mass of oxygen is 16. Multiply the molar mass by 2.20 moles of potassium permanganate. PTS: 1 IF: loom's Level 2 OK 2 NT: UP.3 TOP: alculate the number of moles of a compound from a given mass of the compound, and the mass of a compound from a given number of moles of the compound. KEY: onverting moles of a compound to mass MS: NS: PTS: 1 IF: loom's Level 3 OK 2 NT: UP.3 ST: S NS: PTS: 1 IF: loom's Level 3 OK 2 NT: UP.3 ST: S NS: PTS: 1 IF: loom's Level 3 OK 2 NT: UP.3.3 ST: S NS: PTS: 1 IF: loom's Level 3 OK 2 NT: UP.3.3 ST: S NS: PTS: 1 IF: loom's Level 3 OK 2 NT: UP.3.3 ST: S NS: The balanced chemical equation is. orrect! alculate the mass of Kl using the molar mass as a conversion factor. alance the equation correctly. onvert the grams of Kl to moles using the inverse of molar mass as the conversion factor. PTS: 1 IF: loom's Level 3 OK 2 NT: UP.1 UP.3.3 TOP: Use the steps to solve stoichiometric problems. KEY: Stoichiometric mass-to-mass conversion MS: NS: PTS: 1 IF: loom's Level 3 OK 2 NT:.1.2 ST: S NS: PTS: 1 IF: loom's Level 1 OK 1 NT:.3 ST: S NS: PTS: 1 IF: loom's Level 1 OK 1 NT:.3 ST: S NS: PTS: 1 IF: loom's Level 1 OK 1 NT:.3 ST: S NS: PTS: 1 IF: loom's Level 3 OK 1 NT:.3 ST: S
6 39. NS: PTS: 1 IF: loom's Level 3 OK 2 NT: UP.3.3 ST: S NS: PTS: 1 IF: loom's Level 3 OK 2 NT: UP.3.3 ST: S NS: PTS: 1 IF: loom's Level 3 OK 1 NT:.3 ST: S NS: PTS: 1 IF: loom's Level 3 OK 1 NT: UP.2.3 ST: S NS: The products of the double-replacement reaction between hydrogen bromide and sodium hydroxide are water and sodium bromide. The double-replacement reaction occurs as follows: (aq) + (aq) (l) + (aq) Sodium oxybromide cannot be formed in a double-replacement reaction. In a double-replacement reaction, only two different compounds are formed. Free hydroxyl ions are formed in a single-replacement reaction. orrect! PTS: 1 IF: loom's Level 2 OK 2 NT:.3 TOP: Predict whether reactions in aqueous solutions will produce a precipitate, water, or a gas. KEY: queous solutions MS: NS: PTS: 1 IF: loom's Level 2 OK 1 NT:.3.6 ST: S NS: PTS: 1 IF: loom's Level 2 OK 1 NT: UP ST: S NS: PTS: 1 IF: loom's Level 2 OK 1 NT:.1.2 ST: S NS: PTS: 1 IF: loom's Level 3 OK 2 NT:.1 ST: S NS: PTS: 1 IF: loom's Level 3 OK 2 NT: UP.2.2 ST: S NS: PTS: 1 IF: loom's Level 3 OK 2 NT: UP.2.2 ST: S NS: PTS: 1 IF: loom's Level 3 OK 2 NT: UP.2.2 ST: S NS: PTS: 1 IF: loom's Level 3 OK 2 NT: UP.2.2 ST: S NS: PTS: 1 IF: loom's Level 2 OK 2 NT:.1.2 ST: S NS: PTS: 1 IF: loom's Level 2 OK 2 NT:.1 ST: S NS: PTS: 1 IF: loom's Level 3 OK 2 NT:.1 ST: S NS: PTS: 1 IF: loom's Level 3 OK 2 NT:.1.2 ST: S NS: PTS: 1 IF: loom's Level 3 OK 2 NT:.2 ST: S
7 57. NS: PTS: 1 IF: loom's Level 3 OK 2 NT:.2 ST: S NS: PTS: 1 IF: loom's Level 3 OK 2 NT:.2 ST: S NS: PTS: 1 IF: loom's Level 3 OK 2 NT:.2 ST: S NS: PTS: 1 IF: loom's Level 3 OK 2 NT:.2 ST: S NS: PTS: 1 IF: loom's Level 1 OK 1 NT: UP.2 OMPLETION 62. NS: PTS: 1 IF: loom's Level 1 OK 2 NT:.3 TOP: alculate the molar mass of a compound. KEY: Molar mass MS: NS: hydrogen PTS: 1 IF: loom's Level 1 OK 1 NT:.2 TOP: lassify solutions as acidic, basic, or neutral. KEY: cidic solution MS: 1 SHORT NSWER 64. NS: 273 PTS: 1 IF: loom's Level 1 OK 1 NT: UP.3 ST: S NS: oyle s Law PTS: 1 IF: loom's Level 1 OK 2 NT: UP NS: ombined gas PTS: 1 IF: loom's Level 1 OK 1 NT: UP NS: volume, V - liters (L) pressure, P - atmosphere (1 atm=1.015x105n/m2) temperature, T - Kelvin (K) PTS: 1 IF: loom's Level 1 OK 1 NT: UP NS: Standard Temperature and Pressure PTS: 1 IF: loom's Level 1 OK 1 NT: UP.2.4.6
8 69. NS: a 3 (PO 4 ) 2 PTS: 1 IF: loom's Level 4 OK 2 NT: UP.2 PROLEM 70. NS: 4.22 L PTS: 1 IF: loom's Level 2 OK 2 NT: UP.1 UP TOP: pply the combined gas law to problems involving pressure, temperature, and volume of a gas. KEY: The combined gas law MS: 3 NOT: etermine the volume of the gas by using the combined gas law principle. The combined gas law equation is V2 = [V1*P1*(T2+273)]/ [P2*(T1+273)]. 71. NS: 8.79 g PTS: 1 IF: loom's Level 3 OK 2 NT:.2 TOP: ompare the properties of real and ideal gases. KEY: The ideal gas law - using molar mass MS: 3 NOT: The molar mass of gas is determined using the ideal gas law equation, PV = mrt/m. 72. NS: 2 H 3 O 2 PTS: 1 IF: loom's Level 3 OK 2 NT:.2 TOP: etermine the empirical and molecular formulas for a compound from mass percent and actual mass data. KEY: Empirical formula MS: 3 ESSY 73. NS: Fe 2 O Fe + 3O Particles: 2 atoms Fe, 3 atoms O, 3 atoms as reactants; 2 atoms Fe, 3 atoms O, 3 atoms as products Moles: 2 moles Fe, 3 moles O, 3 moles as reactants; 2 moles Fe, 3 moles O, 3 moles as products Mass: 1( ) + 3(12.01) = 2 (55.847) + 3 (84.027); g = PTS: 1 IF: loom's Level 6 OK 2 NT: UP.2.3 ST: S
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