4) Give the total number of electron domains and the hybridization for Xe in XeF 4. a) 6, sp 3 d 2 b) 4, sp 2 c) 5, sp 3 d d) 6, sp 3 e) 4, sp 3

Size: px
Start display at page:

Download "4) Give the total number of electron domains and the hybridization for Xe in XeF 4. a) 6, sp 3 d 2 b) 4, sp 2 c) 5, sp 3 d d) 6, sp 3 e) 4, sp 3"

Transcription

1 1) The hybridization that allows the formation of 2 π bonds from unhybridized p-orbitals is a) sp b) sp 2 c) sp 3 d) sp 3 d e) sp 3 d 2 2) Electrons in bonds may become delocalized between more than two atoms.. Electrons in bonds remain localized between two atoms a) sigma, pi b) sigma, sigma c) pi, sigma d) pi, pi e) ionic, sigma 3) An antibonding MO the corresponding bonding MO a) is always lower in energy than b) can accommodate more electrons than c) can accommodate fewer electrons than d) is always higher in energy than e) is always degenerate with 4) Give the total number of electron domains and the hybridization for Xe in XeF 4. a) 6, sp 3 d 2 b) 4, sp 2 c) 5, sp 3 d d) 6, sp 3 e) 4, sp 3 5) If a carbon-carbon bond contains two π bonds, it is classified as a bond. a) single b) double c) triple d) this is impossible for carbon e) carbon has no d-electrons so a bond will not form 6) CsCl crystallizes in a unit cell that contains the Cs + ion at the center of a cube that has a Cl ion at each corner. Each unit cell contains Cs + ion and Cl ion, respectively. a) 1, 8 b) 1, 1 c) 2, 1 d) 2, 2 e) 2, 4 7) The formula for bis(ethylenediamine)dihydroxomanganese (IV) chloride is. a) [Mn(OH) 2 (en) 3 ]Cl 3 b) [Mn(O) 2 (en)]cl c) [Mn(OH) 2 (en)]cl 2 d) [Mn(OH) 2 (en) 2 ]Cl 2 e) [Mg(OH) 2 (en) 2 ]Cl 3 8) The name of the compound [Ni(F) 2 (NH 3 )(H 2 O)](NO 3 ) 2 is a) difluorotriammineaquanickel(ii) nitrate b) difluoroammineaquanickel(iv) nitrate c) ammineaquadifluoronickel(iv) nitrate d) difluoroammineaquanickelate(iv) nitrate e) ammineaquadifluoronickelate(ii) nitrate 9) Ni in the complex ion [Ni(NH 3 ) 3 ] 2+ has d-electrons. a) 6 b) 3 c) 7 d) 4 e) 8 10) Ru forms octahedral complexes with CN = 6; one of its compounds contains Ru, 3 Cl, and 5 H 2 O. The addition of AgNO 3 solution to a solution of this complex results in the formation of 2 mol solid AgCl. Write the formula for the coordination compound, showing which ligands are likely to be present in the coordination sphere and which are not. a) [Ru(H 2 O) 5 ]Cl 3 b) [Ru(H 2 O) 5 Cl]Cl 2 c) [Ru(H 2 O)Cl 2 ]Cl 4H 2 O d) [Ru(Cl) 2 ]Cl 5H 2 O 11) Solutions of [Co(NH 3 ) 6 ] 2+, [Co(H 2 O) 6 ] 2+, and [Fe(SCN)] 2+ are colored. One is pink one is red and one is blue. Based on the spectrochemical series, the colors of [Co(NH 3 ) 6 ] 2+, [Co(H 2 O) 6 ] 2+, and [Fe(SCN)] 2+, in order, are. a) pink, red, blue b) red, pink, blue c) blue, pink, red

2 d) blue, red, pink e) red, blue, pink Questions consider the MO diagram below. σ* 1s σ 1s 12) The bond order for HeH is. a) 0 b) 0.5 c) 1 d) 1.5 e) 2 13) If an electron is moved from a lower to a higher energy orbital, the molecule must a) become more stable b) become as stable as H 2 c) not exist The diagram below shows two compounds, A and B; Use this diagram to answer questions A B σ* 2p π* 2p π 2p σ 2p σ* 2s σ 2s 14) The identities of A and B could reasonably be a) O 2 +, C 2 + b) NO, C 2 c) C 2 +, C 2 d) NO, OF + 15) Compound (A/B) is more paramagnetic and compound (A/B) has a longer bond a) A, A b) A,B c) B, B d) B, A 16) For the complexes [Cu(NO 2 ) 2 ] compared to [Cu(en) 2 ] 2+, the chelate effect predicts that a) [Cu(NO 2 ) 2 ] is more stable than [Cu(en) 2 ] 2+ b) [Cu(NO 2 ) 2 ] is less stable than [Cu(en) 2 ] 2+. c) [Cu(NO 2 ) 2 ] has the same stability as [Cu(en) 2 ] 2+ d) cannot predict without knowing the equilibrium constant e) cannot predict without knowing G 17) Why can NH 3 serve as a ligand but BH 3 cannot? a) B has no d-orbitals b) NH 3 is more abundant than BH 3 c) NH 3 is a gas d) B lacks a lone pair e) B is much smaller than N 18) The oxyhemoglobin molecule, with O 2 bound to iron, is a low-spin Fe(II) complex; it has unpaired d-electrons. The deoxyhemoglobin molecule, without the O 2 molecule is a high-spin Fe(II) complex; it has unpaired d-electrons. a) 0, 4 b) 2, 4 c) 4, 0 d) 4, 2 e) 0, 2 1

3 19-20) (Record this answer in two places (for both #19 and 20); this counts double credit 19) Bond angle 1 around N) is ; bond angle 2 (around C) is. H N C=O H H a) 90, 180 b) 109.5, 120 c) 120, 120 d) 109.5, e) 109.5, ) Record same answer as for # ) Record this answer in two places (for both #21 and 22); this counts double credit 21) Assume a metal atom can be represented as spheres as shown in the drawing below. If each atom has a radius of 1.24Å, the length of a side in the unit cell is Å. Exam 3B 14) The name of the compound [Ni(F) 2 (NH 3 )(H 2 O)](NO 3 ) 2 is a) difluorotriammineaquanickel(ii) nitrate b) difluoroammineaquanickel(iv) nitrate c) ammineaquadifluoronickel(iv) nitrate d) difluoroammineaquanickelate(iv) nitrate e) ammineaquadifluoronickelate(ii) nitrate 15) Ni in the complex ion [Ni(H 2 O) 4 ] 4+ has d-electrons. a) 6 b) 3 c) 7 d) 4 e) 8 16) Give the total number of electron domains and the hybridization for Xe in XeF 4. a) 4, sp 3 b) 4, sp 2 c) 5, sp 3 d d) 6, sp 3 e) 6, sp 3 d 2 17) If a carbon-carbon bond contains only one π bond, it is a bond. a) single b) double c) triple d) this is impossible for carbon e) carbon has no d-electrons so a bond will not form 18) Ru forms octahedral complexes with CN = 6; one of its compounds contains Ru, 4 Cl, and 5 H 2 O. The addition of AgNO 3 solution to a solution of this complex results in the formation of 3 mol solid AgCl. Write the formula for the coordination compound, showing which ligands are likely to be present in the coordination sphere and which are not. a) [Ru(H 2 O) 5 Cl]Cl 3 b) [Ru(H 2 O) 5 Cl 2 ]Cl 2 c) [Ru(H 2 O)Cl 3 ]Cl 4H 2 O d) [Ru(Cl)]Cl 3 5H 2 O 6-7) (Record this answer in two places (for both #6 and 7); this counts double credit) 6) Bond angle 1 (around N) is ; bond angle 2 (around C) is. H N C N H a) 90, 180 b) 109.5, 120 c) 120, 120 d) 109.5, e) 109.5, 180 7) Record same answer as for #6. 2

4 8) The hybridization that allows the formation of only 1 π bond from unhybridized p-orbitals is a) sp b) sp 2 c) sp 3 d) sp 3 d e) sp 3 d 2 9) Why can NH 3 serve as a ligand in a complex ion but BH 3 cannot? a) B has no d-orbitals b) NH 3 is more abundant than BH 3 c) NH 3 is a gas d) B lacks a lone pair e) B is much smaller than N 10) Electrons in bonds remain localized between two atoms. Electrons in bonds may become delocalized between more than two atoms. a) sigma, sigma b) sigma, pi c) pi, pi d) pi, sigma e) ionic, sigma 11) A bonding MO the corresponding antibonding MO a) is always lower in energy than b) can accommodate more electrons than c) can accommodate fewer electrons than d) is always higher in energy than e) is always degenerate with 12) Solutions of [Co(H 2 O) 6 ] 2+, [Fe(SCN)] 2+, and [Co(NH 3 ) 6 ] 2+ are colored. One is pink one is red and one is blue. Based on the spectrochemical series, the colors of [Co(H 2 O) 6 ] 2+, [Fe(SCN)] 2+, and [Co(NH 3 ) 6 ] 2+, in order, are. a) pink, blue, red b) red, blue, pink c) blue, pink, red d) blue, red, pink e) red, pink, blue Questions consider the MO diagram below. σ* 1s σ 1s 13) The bond order for HeH + is. a) 0 b) 1 c) 0.5 d) 1.5 e) 2 14) The ion HeH a) does not exist b) is more stable than HeH + c) is more stable than He 2 15) The absorbance spectrum (below) shows that the predominant color absorbed by this substance is and the color we would see when looking at the substance is. a) Yellow, violet b) Orange-red, blue-green c) Red, green d) Blue-green, orange-red e) Green, red Absorbance Wavelength, nm 3

5 The diagram below shows two compounds, A and B; Use this diagram to answer questions A B σ* 2p π* 2p π 2p σ 2p σ* 2s σ 2s 16) The identities of A and B could reasonably be a) O 2 +, C 2 + b) NO, C 2 c) C 2 +, C 2 d) NO, OF + 17) Compound (A/B) is less paramagnetic and compound (A/B) has a shorter bond a) A, A b) A,B c) B, B d) B, A 18) A compound crystallizes in a unit cell that contains the Rb + ion at the center of a cube that has a F ion at each corner. Each unit cell contains Rb + ion and F ion, respectively. a) 1, 8 b) 1, 1 c) 2, 1 d) 2, 2 e) 2, 4 19) The formula for bis(ethylenediamine)dihydroxomanganese (IV) chloride is. a) [Mn(OH) 2 (en) 3 ]Cl 3 b) [Mn(O) 2 (en)]cl c) [Mn(OH) 2 (en)]cl 2 d) [Mn(OH) 2 (en) 2 ]Cl 2 e) [Mg(OH) 2 (en) 2 ]Cl 3 20) For the complexes [Cu(NO 2 ) 2 ] compared to [Cu(en) 2 ] 2+, the chelate effect predicts that a) [Cu(NO 2 ) 2 ] is more stable than [Cu(en) 2 ] 2+ b) [Cu(NO 2 ) 2 ] has the same stability as [Cu(en) 2 ] 2+ c) [Cu(NO 2 ) 2 ] is less stable than [Cu(en) 2 ] 2+. d) cannot predict without knowing the equilibrium constant e) cannot predict without knowing G 21) The oxyhemoglobin molecule, with O 2 bound to iron, is a low-spin Fe(II) complex; it has unpaired d-electrons. The deoxyhemoglobin molecule, without the O 2 molecule is a high-spin Fe(II) complex; it has unpaired d-electrons. a) 0, 4 b) 2, 4 c) 4, 0 d) 4, 2 e) 0, ) Record this answer in two places (for both #22 and 23); this counts double credit. 22) Assume a metal atom can be represented as spheres as shown in the drawing below. If each atom has a radius of 1.78Å, the length of a side in the unit cell is Å. a) 1.80 b) 1.58 c) 1.89 d) 5.03 e) ) Record same answer as #22. 4

Chapter 9. Covalent Bonding: Orbitals

Chapter 9. Covalent Bonding: Orbitals Chapter 9 Covalent Bonding: Orbitals Chapter 9 Table of Contents 9.1 Hybridization and the Localized Electron Model 9.2 The Molecular Orbital Model 9.3 Bonding in Homonuclear Diatomic Molecules 9.4 Bonding

More information

Chapter 25 Transition Metals and Coordination Compounds Part 2

Chapter 25 Transition Metals and Coordination Compounds Part 2 Chapter 25 Transition Metals and Coordination Compounds Part 2 Bonding in Coordination Compounds Valence Bond Theory Coordinate covalent bond is between: completely filled atomic orbital and an empty atomic

More information

Chapter 21 Transition Metals and Coordination Chemistry

Chapter 21 Transition Metals and Coordination Chemistry Chapter 21 Transition Metals and Coordination Chemistry Some History In the 19 th century, chemists started to prepare colored compounds containing transition metals and other substances like ammonia,

More information

Chapter 21 Transition Metals and Coordination Chemistry

Chapter 21 Transition Metals and Coordination Chemistry Chapter 21 Transition Metals and Coordination Chemistry Some History In the 19 th century, chemists started to prepare colored compounds containing transition metals and other substances like ammonia,

More information

I. Multiple Choice Questions (Type-I) ] 2+, logk = [Cu(NH 3 ) 4 O) 4. ] 2+, logk = 8.9

I. Multiple Choice Questions (Type-I) ] 2+, logk = [Cu(NH 3 ) 4 O) 4. ] 2+, logk = 8.9 Unit 9 COORDINATION COORDINA COMPOUNDS I. Multiple Choice Questions (Type-I) 1. Which of the following complexes formed by Cu 2+ ions is most stable? (i) Cu 2+ + 4NH 3 [Cu(NH 3 ] 2+, logk = 11.6 (ii) Cu

More information

Chapter 9: Molecular Geometries and Bonding Theories Learning Outcomes: Predict the three-dimensional shapes of molecules using the VSEPR model.

Chapter 9: Molecular Geometries and Bonding Theories Learning Outcomes: Predict the three-dimensional shapes of molecules using the VSEPR model. Chapter 9: Molecular Geometries and Bonding Theories Learning Outcomes: Predict the three-dimensional shapes of molecules using the VSEPR model. Determine whether a molecule is polar or nonpolar based

More information

The Transition Elements and Coordination Compounds

The Transition Elements and Coordination Compounds Chapter 22 The Transition Elements and Coordination Compounds Concept Check 22.1 Another complex studied by Werner had a composition corresponding to the formula PtCl 4 2KCl. From electrical-conductance

More information

Chapter 9. Covalent Bonding: Orbitals

Chapter 9. Covalent Bonding: Orbitals Chapter 9 Covalent Bonding: Orbitals EXERCISE! Draw the Lewis structure for methane, CH 4. What is the shape of a methane molecule? tetrahedral What are the bond angles? 109.5 o H H C H H Copyright Cengage

More information

CHEM Practice Final Exam 2014

CHEM Practice Final Exam 2014 Final Exam 2 1. Which of the following would you expect to have the highest boiling point? a. I 2 b. F 2 c. Cl 2 d. Br 2 e. All of the above have the same boiling point. 2. Which of the compounds below

More information

Chapter 9 practice questions

Chapter 9 practice questions Class: Date: Chapter 9 practice questions Multiple Choice Identify the choice that best completes the statement or answers the question. 1. All of the following statements concerning valence bond (VB)

More information

Transition Metals and Coordination Chemistry. 1. In the transition metals section chemical similarities are found within a and across a.

Transition Metals and Coordination Chemistry. 1. In the transition metals section chemical similarities are found within a and across a. Transition Metals and Coordination Chemistry 1. In the transition metals section chemical similarities are found within a and across a. 2. What are 2 transition metals that have unique electron configurations?

More information

Crystal Field Theory. 2. Show the interaction between the d-orbital and the negative point charge ligands

Crystal Field Theory. 2. Show the interaction between the d-orbital and the negative point charge ligands 1. What is the crystal field model? Crystal Field Theory It is a model that views complex ions as being held together ionically (this is not actually the case, but it allows for a simplification of the

More information

VERSION B Yellow. perm. version. name. Chem 1C - Spring exam 2

VERSION B Yellow. perm. version. name. Chem 1C - Spring exam 2 Chem 1C - Spring 2010 - exam 2 VERSION B Yellow ON YOUR SCANTRON: BUBBLE IN YOUR 7 DIDGIT PERM (Leaving the last three digits blank) BUBBLE IN THE VERSION: B WRITE YOUR NAME AT THE END, HAND IN ONLY THE

More information

16. NO 3, 5 + 3(6) + 1 = 24 e. 22. HCN, = 10 valence electrons

16. NO 3, 5 + 3(6) + 1 = 24 e. 22. HCN, = 10 valence electrons Solution to Chapts 9 & 10 Problems: 16. N 3, 5 + 3(6) + 1 = 24 e 22. HCN, 1 + 4 + 5 = 10 valence electrons Assuming N is hybridized, both C and N atoms are sp hybridized. The C H bond is formed from overlap

More information

Molecular Geometry and Bonding Theories. Chapter 9

Molecular Geometry and Bonding Theories. Chapter 9 Molecular Geometry and Bonding Theories Chapter 9 Molecular Shapes CCl 4 Lewis structures give atomic connectivity; The shape of a molecule is determined by its bond angles VSEPR Model Valence Shell Electron

More information

Chapter 9. Molecular Geometry and Bonding Theories

Chapter 9. Molecular Geometry and Bonding Theories Chapter 9. Molecular Geometry and Bonding Theories PART I Molecular Shapes Lewis structures give atomic connectivity: they tell us which atoms are physically connected to which atoms. The shape of a molecule

More information

Chapter 4. Molecular Structure and Orbitals

Chapter 4. Molecular Structure and Orbitals Chapter 4 Molecular Structure and Orbitals Chapter 4 Table of Contents (4.1) (4.2) (4.3) (4.4) (4.5) (4.6) (4.7) Molecular structure: The VSEPR model Bond polarity and dipole moments Hybridization and

More information

Cr(II) or Cr 2+ Consider the octahedral complex Cr[(en) 3 ] 2+ Octahedral complex with 4 d electrons. Octahedral complex with 4 d electrons

Cr(II) or Cr 2+ Consider the octahedral complex Cr[(en) 3 ] 2+ Octahedral complex with 4 d electrons. Octahedral complex with 4 d electrons Cr [Ar] 4s 1 3d 5 Cr 2+ [Ar] 3d 4 Consider the octahedral complex Cr[(en) 3 ] 2+ Cr(II) or Cr 2+ Pairing energy Octahedral complex with 4 d electrons Octahedral complex with 4 d electrons Δ is large Δ

More information

1. [7 points] Which element is oxidized in the reaction below? + O 2 + H 2 O

1. [7 points] Which element is oxidized in the reaction below? + O 2 + H 2 O 1. [7 points] Which element is oxidized in the reaction below? K 2 CrO 4 (aq) + BaCl 2 (aq) BaCrO 4 (s) + 2KCl a. Cl b. Cr c. O d. Ba e. This is not an oxidation-reduction reaction 2. [7 points] What are

More information

Chemical Bonding II: Molecular Geometry and Hybridization of Atomic Orbitals Chapter 10

Chemical Bonding II: Molecular Geometry and Hybridization of Atomic Orbitals Chapter 10 Chemical Bonding II: Molecular Geometry and Hybridization of Atomic Orbitals Chapter 10 Linear Trigonal 180 o planar 120 o Tetrahedral 109.5 o Trigonal Bipyramidal 120 and 90 o Octahedral 90 o linear Linear

More information

AP CHEMISTRY: BONDING THEORIES REVIEW KEY p. 1

AP CHEMISTRY: BONDING THEORIES REVIEW KEY p. 1 AP CHEMISTRY: BONDING THEORIES REVIEW KEY p. 1 1) a) O-H PC b) Cs-Cl I c) H-Cl PC d) Br-Br NPC 2) differences in electronegativity determines amount of ity O3 0, P8 0, NO.5, CO2 1.0, CH4.4, H2S.4 answer

More information

Coordination Inorganic Chemistry

Coordination Inorganic Chemistry Coordination Inorganic Chemistry Practice Exam Coordination Chem Name (last) (irst) Read all questions before you start. Show all work and explain your answers to receive full credit. Report all numerical

More information

Week 13 Transition metals

Week 13 Transition metals Week 13 Transition metals Q UEST IO N 1 a. Write the electron configurations for the following atoms: Fe, Co, Ni, Ti. You can use the inert gas core abbreviation. b. Write the election configurations for

More information

Chemistry: The Central Science. Chapter 9: Molecular Geometry and Bonding Theory

Chemistry: The Central Science. Chapter 9: Molecular Geometry and Bonding Theory Chemistry: The Central Science Chapter 9: Molecular Geometry and Bonding Theory The shape and size of a molecule of a particular substance, together with the strength and polarity of its bonds, largely

More information

Chapter 10 Chemical Bonding II

Chapter 10 Chemical Bonding II Chapter 10 Chemical Bonding II Valence Bond Theory Valence Bond Theory: A quantum mechanical model which shows how electron pairs are shared in a covalent bond. Bond forms between two atoms when the following

More information

Chapter 19: Phenomena

Chapter 19: Phenomena Chapter 19: Phenomena Phenomena: Transition metal complexes are often used in paints for coloration due to their wide range of colors. Using the data below identify any patterns in the colors of compounds.

More information

Chemistry 1B. Fall Topics Lectures Coordination Chemistry

Chemistry 1B. Fall Topics Lectures Coordination Chemistry Chemistry 1B Fall 2016 Topics Lectures 17-18 Coordination Chemistry 1 LISTEN UP!!! WE WILL ONLY COVER LIMITED PARTS OF CHAPTER 19 (940-944;952-954;963-970) 2 good reasons for studying coordination chemistry

More information

Chapter 9 - Covalent Bonding: Orbitals

Chapter 9 - Covalent Bonding: Orbitals Chapter 9 - Covalent Bonding: Orbitals 9.1 Hybridization and the Localized Electron Model A. Hybridization 1. The mixing of two or more atomic orbitals of similar energies on the same atom to produce new

More information

Lecture Presentation. Chapter 10 Chemical Bonding II: Molecular Shapes, Valence Bond Theory, and Molecular Orbital Theory

Lecture Presentation. Chapter 10 Chemical Bonding II: Molecular Shapes, Valence Bond Theory, and Molecular Orbital Theory Lecture Presentation Chapter 10 Chemical Bonding II: Molecular Shapes, Valence Bond Theory, and Molecular Orbital Theory Predicting Molecular Geometry 1. Draw the Lewis structure. 2. Determine the number

More information

Chapter 9. Molecular Geometry and Bonding Theories

Chapter 9. Molecular Geometry and Bonding Theories Chapter 9. Molecular Geometry and Bonding Theories 9.1 Molecular Shapes Lewis structures give atomic connectivity: they tell us which atoms are physically connected to which atoms. The shape of a molecule

More information

Dr. Fred O. Garces Chemistry 201

Dr. Fred O. Garces Chemistry 201 23.4 400! 500! 600! 800! The relationship between Colors, Metal Complexes and Gemstones Dr. Fred O. Garces Chemistry 201 Miramar College 1 Transition Metal Gems Gemstone owe their color from trace transition-metal

More information

Transition Metals. Tuesday 09/22/15. Tuesday, September 22, 15

Transition Metals. Tuesday 09/22/15. Tuesday, September 22, 15 Transition Metals Tuesday 09/22/15 Agenda Topic 13.2 - Colored Complexes Topic 13.1 - First Row Transition Elements handout (this will be classwork for Wednesday & Thursday) The Periodic Table - The Transition

More information

Topics Coordination Complexes Chemistry 1B-AL, Fall 2016

Topics Coordination Complexes Chemistry 1B-AL, Fall 2016 Chemistry 1B Fall 2016 Topics Lectures 17-18 Coordination Chemistry 1 LISTEN UP!!! WE WILL ONLY COVER LIMITED PARTS OF CHAPTER 19 (940-944;952-954;963-970) 2 Page 1 good reasons for studying coordination

More information

Chapter 9 Molecular Geometry and Bonding Theories

Chapter 9 Molecular Geometry and Bonding Theories Chapter 9 Molecular Geometry and Bonding Theories 9.1 Molecular Shapes Lewis structures give atomic connectivity (which atoms are physically connected). By noting the number of bonding and nonbonding electron

More information

VERSION A White. perm. version. name. Chem 1C - Spring exam 2

VERSION A White. perm. version. name. Chem 1C - Spring exam 2 Chem 1C - Spring 2010 - exam 2 VERSION A White ON YOUR SCANTRON: BUBBLE IN YOUR 7 DIDGIT PERM (Leaving the last three digits blank) BUBBLE IN THE VERSION: A WRITE YOUR NAME AT THE END, HAND IN ONLY THE

More information

Chapter 19: Phenomena

Chapter 19: Phenomena Chapter 19: Phenomena Phenomena: Transition metal complexes are often used in paints for coloration due to their wide range of colors. Using the data below identify any patterns in the colors of compounds.

More information

Chapter 10 Practice Problems

Chapter 10 Practice Problems Chapter 10 Practice Problems Q 10.1 0-1 -1-1 S +2 +2 S S +2 0-1 -1-1 0 C in S - 6 6 1 2 1 2 C in S = 6 4 1 4 0 2 C S 6 0 1 8 2 2 Q 10.2 Correct Answer: B Two oxygen atoms will have a formal charge of 1

More information

MOLECULAR ORBITAL DIAGRAM KEY

MOLECULAR ORBITAL DIAGRAM KEY 365 MOLECULAR ORBITAL DIAGRAM KEY Draw molecular orbital diagrams for each of the following molecules or ions. Determine the bond order of each and use this to predict the stability of the bond. Determine

More information

CHAPTER TEN MOLECULAR GEOMETRY MOLECULAR GEOMETRY V S E P R CHEMICAL BONDING II: MOLECULAR GEOMETRY AND HYBRIDIZATION OF ATOMIC ORBITALS

CHAPTER TEN MOLECULAR GEOMETRY MOLECULAR GEOMETRY V S E P R CHEMICAL BONDING II: MOLECULAR GEOMETRY AND HYBRIDIZATION OF ATOMIC ORBITALS CHAPTER TEN CHEMICAL BONDING II: AND HYBRIDIZATION O ATOMIC ORBITALS V S E P R VSEPR Theory In VSEPR theory, multiple bonds behave like a single electron pair Valence shell electron pair repulsion (VSEPR)

More information

Molecular shape is determined by the number of bonds that form around individual atoms.

Molecular shape is determined by the number of bonds that form around individual atoms. Chapter 9 CH 180 Major Concepts: Molecular shape is determined by the number of bonds that form around individual atoms. Sublevels (s, p, d, & f) of separate atoms may overlap and result in hybrid orbitals

More information

Chapter 9 Molecular Geometry and Bonding Theories

Chapter 9 Molecular Geometry and Bonding Theories Lecture Presentation Chapter 9 Geometry James F. Kirby Quinnipiac University Hamden, CT Shapes Lewis Structures show bonding and lone pairs, but do not denote shape. However, we use Lewis Structures to

More information

Chemical Bonding II: Molecular Geometry and Hybridization of Atomic Orbitals

Chemical Bonding II: Molecular Geometry and Hybridization of Atomic Orbitals Chemical Bonding II: and ybridization of Atomic rbitals Chapter 10 Valence shell electron pair repulsion (VSEPR) model: Predict the geometry of the molecule from the electrostatic repulsions between the

More information

Orbitals and energetics

Orbitals and energetics Orbitals and energetics Bonding and structure Molecular orbital theory Crystal field theory Ligand field theory Provide fundamental understanding of chemistry dictating radionuclide complexes Structure

More information

Chapter 10 Theories of Covalent Bonding

Chapter 10 Theories of Covalent Bonding Chapter 10 Theories of Covalent Bonding 1 Atomic Orbitals Molecules Bonding and 2 Molecular Structure Questions How are molecules held together? Why is O 2 paramagnetic? And how is this property connected

More information

Chapter 9. Chemical Bonding II: Molecular Geometry and Bonding Theories

Chapter 9. Chemical Bonding II: Molecular Geometry and Bonding Theories Chapter 9 Chemical Bonding II: Molecular Geometry and Bonding Theories Topics Molecular Geometry Molecular Geometry and Polarity Valence Bond Theory Hybridization of Atomic Orbitals Hybridization in Molecules

More information

Chapter 9. Molecular Geometries and Bonding Theories. Lecture Presentation. John D. Bookstaver St. Charles Community College Cottleville, MO

Chapter 9. Molecular Geometries and Bonding Theories. Lecture Presentation. John D. Bookstaver St. Charles Community College Cottleville, MO Lecture Presentation Chapter 9 Theories John D. Bookstaver St. Charles Community College Cottleville, MO Shapes The shape of a molecule plays an important role in its reactivity. By noting the number of

More information

RDCH 702 Lecture 4: Orbitals and energetics

RDCH 702 Lecture 4: Orbitals and energetics RDCH 702 Lecture 4: Orbitals and energetics Molecular symmetry Bonding and structure Molecular orbital theory Crystal field theory Ligand field theory Provide fundamental understanding of chemistry dictating

More information

Bonding in Coordination Compounds. Crystal Field Theory. Bonding in Transition Metal Complexes

Bonding in Coordination Compounds. Crystal Field Theory. Bonding in Transition Metal Complexes Bonding in Transition Metal Complexes 1) Crystal Field Theory (ligand field theory) Crystal Field Theory Treat igands as negative charges (they repel the e- in the d orbitals deals only with d orbitals

More information

Chapter 9. Covalent Bonding: Orbitals. Copyright 2017 Cengage Learning. All Rights Reserved.

Chapter 9. Covalent Bonding: Orbitals. Copyright 2017 Cengage Learning. All Rights Reserved. Chapter 9 Covalent Bonding: Orbitals Chapter 9 Table of Contents (9.1) (9.2) (9.3) (9.4) (9.5) (9.6) Hybridization and the localized electron model The molecular orbital model Bonding in homonuclear diatomic

More information

Chapter 10. VSEPR Model: Geometries

Chapter 10. VSEPR Model: Geometries Chapter 10 Molecular Geometry VSEPR Model: Geometries Valence Shell Electron Pair Repulsion Theory Electron pairs repel and get as far apart as possible Example: Water Four electron pairs Farthest apart

More information

NAME: SECOND EXAMINATION

NAME: SECOND EXAMINATION 1 Chemistry 64 Winter 1994 NAME: SECOND EXAMINATION THIS EXAMINATION IS WORTH 100 POINTS AND CONTAINS 4 (FOUR) QUESTIONS THEY ARE NOT EQUALLY WEIGHTED! YOU SHOULD ATTEMPT ALL QUESTIONS AND ALLOCATE YOUR

More information

Ch. 23: Transition metals and Coordination Chemistry

Ch. 23: Transition metals and Coordination Chemistry Ch. 23: Transition metals and Coordination Chemistry Learning goals and key skills: Determine the oxidation number and number of d electrons for metal ions in complexes Name coordination compounds given

More information

Chapter 24. Transition Metals and Coordination Compounds. Lecture Presentation. Sherril Soman Grand Valley State University

Chapter 24. Transition Metals and Coordination Compounds. Lecture Presentation. Sherril Soman Grand Valley State University Lecture Presentation Chapter 24 Transition Metals and Coordination Compounds Sherril Soman Grand Valley State University Gemstones The colors of rubies and emeralds are both due to the presence of Cr 3+

More information

Chapter 23. Transition Metals and Coordination Chemistry ( 전이금속과배위화학 ) Lecture Presentation

Chapter 23. Transition Metals and Coordination Chemistry ( 전이금속과배위화학 ) Lecture Presentation Lecture Presentation Chapter 23 and Coordination Chemistry ( 전이금속과배위화학 ) John D. Bookstaver St. Charles Community College Cottleville, MO 1 Most metals, including transition metals, are found in solid

More information

Chemistry 6 10:00 Section Time limit = 3 hours Spring There are two sections to this exam. Please read the instructions carefully.

Chemistry 6 10:00 Section Time limit = 3 hours Spring There are two sections to this exam. Please read the instructions carefully. Chemistry 6 10:00 Section Final Exam Time limit = 3 hours Spring 2005 Name There are two sections to this exam. Please read the instructions carefully. In the first section, there are 13 multiple choice

More information

CHEM N-3 November Transition metals are often found in coordination complexes such as [NiCl 4 ] 2. What is a complex?

CHEM N-3 November Transition metals are often found in coordination complexes such as [NiCl 4 ] 2. What is a complex? CHEM100 014-N-3 November 014 Transition s are often found in coordination complexes such as [NiCl 4 ]. What is a complex? 8 A complex contains a cation surrounded by ligands which bond to the cation using

More information

Molecular Geometry. Dr. Williamson s Molecular Geometry Notes. VSEPR: Definition of Terms. Dr. V.M. Williamson Texas A & M University Student Version

Molecular Geometry. Dr. Williamson s Molecular Geometry Notes. VSEPR: Definition of Terms. Dr. V.M. Williamson Texas A & M University Student Version Molecular Geometry Dr. V.M. Williamson Texas A & M University Student Version Valence Shell Electron Pair Repulsion- VSEPR 1. Valence e- to some extent 2. Electron pairs move as far away as possible to

More information

Molecular Geometry. Dr. Williamson s Molecular Geometry Notes. VSEPR: Definition of Terms. VSEPR: Electronic Geometries VSEPR

Molecular Geometry. Dr. Williamson s Molecular Geometry Notes. VSEPR: Definition of Terms. VSEPR: Electronic Geometries VSEPR Molecular Geometry Dr. V.M. Williamson Texas A & M University Student Version Valence Shell Electron Pair Repulsion- VSEPR 1. Valence e- to some extent 2. Electron pairs move as far away as possible to

More information

Chapter 10. VSEPR Model: Geometries

Chapter 10. VSEPR Model: Geometries Chapter 10 Molecular Geometry VSEPR Model: Geometries Valence Shell Electron Pair Repulsion Theory Electron pairs repel and get as far apart as possible Example: Water Four electron pairs Two bonds Two

More information

Chemistry 1B. Fall Lectures Coordination Chemistry

Chemistry 1B. Fall Lectures Coordination Chemistry Chemistry 1B Fall 2013 Lectures 13-14 Coordination Chemistry 1 LISTEN UP!!! WE WILL ONLY COVER LIMITED PARTS OF CHAPTER 19 (940-944;952-954;963-970) 2 good reasons for studying coordination chemistry a

More information

Andrew Rosen *Note: If you can rotate a molecule to have one isomer equal to another, they are both the same

Andrew Rosen *Note: If you can rotate a molecule to have one isomer equal to another, they are both the same *Note: If you can rotate a molecule to have one isomer equal to another, they are both the same *Note: For hybridization, if an SP 2 is made, there is one unhybridized p orbital (because p usually has

More information

CHEM 115 EXAM #3 Practice Exam Fall 2013

CHEM 115 EXAM #3 Practice Exam Fall 2013 Name CHEM 115 EXAM #3 Practice Exam Fall 2013 Circle the correct answer. (numbers 1-9, 3 points each) 1. Choose the correct statement about the compound SO 2. a. the S O bonds are ionic in character b.

More information

Chemistry 1000 Lecture 26: Crystal field theory

Chemistry 1000 Lecture 26: Crystal field theory Chemistry 1000 Lecture 26: Crystal field theory Marc R. Roussel November 6, 18 Marc R. Roussel Crystal field theory November 6, 18 1 / 18 Crystal field theory The d orbitals z 24 z 16 10 12 8 0 0 10 10

More information

CHM2045 S13: Exam # MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

CHM2045 S13: Exam # MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. CHM2045 S13: Exam #2 2013.03.01 MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) How would replacing one of benzene's C atoms and the H atom attached

More information

Ch. 9- Molecular Geometry and Bonding Theories

Ch. 9- Molecular Geometry and Bonding Theories Ch. 9- Molecular Geometry and Bonding Theories 9.0 Introduction A. Lewis structures do not show one of the most important aspects of molecules- their overall shapes B. The shape and size of molecules-

More information

Chapter 10: Chemical Bonding II: Molecular Shapes; VSEPR, Valence Bond and Molecular Orbital Theories

Chapter 10: Chemical Bonding II: Molecular Shapes; VSEPR, Valence Bond and Molecular Orbital Theories C h e m i s t r y 1 A : C h a p t e r 1 0 P a g e 1 Chapter 10: Chemical Bonding II: Molecular Shapes; VSEPR, Valence Bond and Molecular Orbital Theories Homework: Read Chapter 10: Work out sample/practice

More information

Chm December 2008

Chm December 2008 Inorganic Exam 3 Chm 451 4 December 2008 Name: Instructions. Always show your work where required for full credit. 1. (15 pts) True/False a T F Ionization energy decreases as one moves down from Li to

More information

Electronic structure Crystal-field theory Ligand-field theory. Electronic-spectra electronic spectra of atoms

Electronic structure Crystal-field theory Ligand-field theory. Electronic-spectra electronic spectra of atoms Chapter 19 d-metal complexes: electronic structure and spectra Electronic structure 19.1 Crystal-field theory 19.2 Ligand-field theory Electronic-spectra 19.3 electronic spectra of atoms 19.4 electronic

More information

a. Orange b. Green c. Red d. Yellow e. Colorless, because the crystal field splitting is so large that the absorption is shifted into the ultraviolet

a. Orange b. Green c. Red d. Yellow e. Colorless, because the crystal field splitting is so large that the absorption is shifted into the ultraviolet 1. [6 points] The complex [Ni(NH 3 ) 6 ] 2+ has a blue-violet color. What color would you expect for [Ni(H 2 O) 6 ] 2+? a. Orange b. Green c. Red d. Yellow e. Colorless, because the crystal field splitting

More information

Test bank for Chemistry The Central Science 10th Edition by Brown, LeMay, Bursten

Test bank for Chemistry The Central Science 10th Edition by Brown, LeMay, Bursten Test bank for Chemistry The Central Science 10th Edition by Brown, LeMay, Bursten Chapter 9, Molecular Geometry and Bonding Theories Multiple-Choice and Bimodal 1) For a molecule with the formula A) linear

More information

Chemistry 1B. Fall Lectures Coordination Chemistry

Chemistry 1B. Fall Lectures Coordination Chemistry Chemistry 1B Fall 2012 Lectures 13-14 Coordination Chemistry 1 LISTEN UP!!! WE WILL ONLY COVER LIMITED PARTS OF CHAPTER 19 (pp. 933-937; 946-948; 958-966) [940-944;952-954;963-970] 7th 2 good reasons for

More information

Chapter 21: Transition Metals and Coordination Chemistry

Chapter 21: Transition Metals and Coordination Chemistry Chapter 21: Transition Metals and Coordination Chemistry Mg, Cr, V, Co Pt Fe complexes O2 Mo and Fe complexes: nitrogen fixation Zn: 150 Cu, Fe: Co: B12 21.1 Transition Metals show great similarities within

More information

Coordination chemistry and organometallics

Coordination chemistry and organometallics Coordination chemistry and organometallics Double salt and Complex salt A salt that keeps its identity only in solid state is called a double salt. In solution they dissociate into component ions. E.g.:

More information

Chapter 23 Transition Metals and Coordination Chemistry

Chapter 23 Transition Metals and Coordination Chemistry Lecture Presentation Chapter 23 and Coordination Chemistry James F. Kirby Quinnipiac University Hamden, CT Color Catalysts Magnets 23.1 The 1036 Why are of Interest? Biological roles Coordination compounds

More information

Chemistry 121: Topic 4 - Chemical Bonding Topic 4: Chemical Bonding

Chemistry 121: Topic 4 - Chemical Bonding Topic 4: Chemical Bonding Topic 4: Chemical Bonding 4.0 Ionic and covalent bonds; Properties of covalent and ionic compounds 4.1 Lewis structures, the octet rule. 4.2 Molecular geometry: the VSEPR approach. Molecular polarity.

More information

Periodicity HL (answers) IB CHEMISTRY HL

Periodicity HL (answers) IB CHEMISTRY HL Periodicity HL (answers) IB CHEMISTRY HL 13.1 First row d-block elements Understandings: Transition elements have variable oxidation states, form complex ions with ligands, have coloured compounds, and

More information

m measured m if 100%ionic

m measured m if 100%ionic μ = q r %ionic character = 1 Debye = 3.34 x 10 30 C m m measured m if 100%ionic 100% Scoring: Six points each for questions 1 through 23; two points each for questions 24 through 32. Directions: n the

More information

401 Unit 3 Exam Spring 2018 (Buffers, Titrations, Ksp, & Transition Metals)

401 Unit 3 Exam Spring 2018 (Buffers, Titrations, Ksp, & Transition Metals) Seat# : 401 Unit 3 Exam Spring 2018 (Buffers, Titrations, Ksp, & Transition Metals) Multiple Choice Identify the letter of the choice that best completes the statement or answers the question. (3 pts each)

More information

Chemical Bonding II: Molecular Geometry and Hybridization of Atomic Orbitals

Chemical Bonding II: Molecular Geometry and Hybridization of Atomic Orbitals Chemical Bonding II: Molecular Geometry and Hybridization of Atomic Orbitals Chapter 10 Copyright The McGraw-Hill Companies, Inc. Permission required for reproduction or display. 1 Valence shell electron

More information

Chapter 23 Transition Metals and Coordination Chemistry

Chapter 23 Transition Metals and Coordination Chemistry Chapter 23 Transition Metals and Coordination Chemistry Many compounds of transition metals are colored (used in paints and to stain glass; produce color in gemstones). 23.1 The Transition Metals Most

More information

Version 188 Exam 2 mccord (51600) 1

Version 188 Exam 2 mccord (51600) 1 Version 188 Exam 2 mccord (51600) 1 This print-out should have 35 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. l I l l 001 3.0 points

More information

Coordination Compounds

Coordination Compounds Coordination Compounds 1. What is a coordination compound composed of? a. Metal Ion b. Ligand c. Counter Ion 2. What is a complex ion? The metal ion and ligand combination. 3. What is a counter ion? An

More information

- an approach to bonding that is useful for making estimates of E of orbitals in coordination complexes

- an approach to bonding that is useful for making estimates of E of orbitals in coordination complexes 10.4 Angular Overlap - an approach to bonding that is useful for making estimates of E of orbitals in coordination complexes - estimate the strength of interaction b/w ligand orbitals & metal d orbitals

More information

CHEMISTRY. Chapter 10 Theories of Bonding and Structure. The Molecular Nature of Matter. Jespersen Brady Hyslop SIXTH EDITION

CHEMISTRY. Chapter 10 Theories of Bonding and Structure. The Molecular Nature of Matter. Jespersen Brady Hyslop SIXTH EDITION CHEMISTRY The Molecular Nature of Matter SIXTH EDITION Jespersen Brady Hyslop Chapter 10 Theories of Bonding and Structure Copyright 2012 by John Wiley & Sons, Inc. Molecular Structures Molecules containing

More information

Covalent Bonding: Orbitals

Covalent Bonding: Orbitals Hybridization and the Localized Electron Model Covalent Bonding: Orbitals A. Hybridization 1. The mixing of two or more atomic orbitals of similar energies on the same atom to produce new orbitals of equal

More information

Review Outline Chemistry 1B, Fall 2012

Review Outline Chemistry 1B, Fall 2012 Review Outline Chemistry 1B, Fall 2012 -------------------------------------- Chapter 12 -------------------------------------- I. Experiments and findings related to origin of quantum mechanics A. Planck:

More information

Chemical Bonding Chapter 9

Chemical Bonding Chapter 9 Chemical Bonding Chapter 9 Covalent Bonds and Ionic Bonds: Octet Rule Explain each of the following observations in terms of the "octet rule": Na atoms and Cl atoms will combine to form NaCl. Why does

More information

Chapter 10. Structure Determines Properties! Molecular Geometry. Chemical Bonding II

Chapter 10. Structure Determines Properties! Molecular Geometry. Chemical Bonding II Chapter 10 Chemical Bonding II Structure Determines Properties! Properties of molecular substances depend on the structure of the molecule The structure includes many factors, including: the skeletal arrangement

More information

Chapter 9. Molecular Geometries and Bonding Theories. Lecture Presentation. John D. Bookstaver St. Charles Community College Cottleville, MO

Chapter 9. Molecular Geometries and Bonding Theories. Lecture Presentation. John D. Bookstaver St. Charles Community College Cottleville, MO Lecture Presentation Chapter 9 Theories John D. Bookstaver St. Charles Community College Cottleville, MO Shapes The shape of a molecule plays an important role in its reactivity. By noting the number of

More information

Molecular Structure and Orbitals

Molecular Structure and Orbitals CHEM 1411 General Chemistry Chemistry: An Atoms First Approach by Zumdahl 2 5 Molecular Structure and Orbitals Chapter Objectives: Learn the basics of Valence Bond Theory and Molecular Orbital Theory and

More information

Chapter 10 Chemical Bonding II: Molecular Shapes, Valence Bond Theory, and Molecular Orbital Theory

Chapter 10 Chemical Bonding II: Molecular Shapes, Valence Bond Theory, and Molecular Orbital Theory 10.1 Artificial Sweeteners: Fooled by Molecular Shape 425 10.2 VSEPR Theory: The Five Basic Shapes 426 10.3 VSEPR Theory: The Effect of Lone Pairs 430 10.4 VSEPR Theory: Predicting Molecular Geometries

More information

Advanced Inorganic Chemistry

Advanced Inorganic Chemistry Advanced Inorganic Chemistry Orgel Diagrams Correlation of spectroscopic terms for d n configuration in O h complexes Atomic Term Splitting of the weak field d n ground state terms in an octahedral ligand

More information

Assignment 09 A. 2- The image below depicts a seesaw structure. Which of the following has such a structure?

Assignment 09 A. 2- The image below depicts a seesaw structure. Which of the following has such a structure? Assignment 09 A 1- Give the total number of electron domains, the number of bonding and nonbonding domains, and the molecular geometry, respectively, for the central atom of P 3. a) four electron domains,

More information

Chapter 9 Molecular Geometry Valence Bond and Molecular Orbital Theory

Chapter 9 Molecular Geometry Valence Bond and Molecular Orbital Theory Chapter 9 Molecular Geometry Valence Bond and Molecular Orbital Theory Chapter Objectives: Learn the basics of Valence Bond Theory and Molecular Orbital Theory and how they are used to model covalent bonding.

More information

Crystal Field Theory

Crystal Field Theory Crystal Field Theory It is not a bonding theory Method of explaining some physical properties that occur in transition metal complexes. Involves a simple electrostatic argument which can yield reasonable

More information

Chemistry 201: General Chemistry II - Lecture

Chemistry 201: General Chemistry II - Lecture Chemistry 201: General Chemistry II - Lecture Dr. Namphol Sinkaset Chapter 23 Study Guide Concepts 1. In the transition metals, the ns orbital fills before the (n-1)d orbitals. However, the ns orbital

More information

Instant download Test bank for Chemistry The Central Science 10th Edition by Brown, LeMay, Bursten CLICK HERE

Instant download Test bank for Chemistry The Central Science 10th Edition by Brown, LeMay, Bursten CLICK HERE Chemistry, 10e (Brown) Chapter 9, Molecular Geometry and Bonding Theories Instant download Test bank for Chemistry The Central Science 10th Edition by Brown, LeMay, Bursten CLICK HERE http://testbankair.com/download/test-bank-for-chemistry-the-central-science-10th-edition-by-brown-lemay-bursten/

More information

CO-ORDINATION COMPOUNDS

CO-ORDINATION COMPOUNDS Unit - 9 CO-ORDINATION COMPOUNDS QUESTIONS VSA QUESTIONS (1 - MARK QUESTIONS) 1. Define the term coordination compound? 2. Write the names of counter ions in (i) Hg [Co (SCN and (ii) [Pt(NH 3. 3. Write

More information

Chemistry 1A, Spring 2007 Midterm Exam 2 March 5, 2007 (90 min, closed book)

Chemistry 1A, Spring 2007 Midterm Exam 2 March 5, 2007 (90 min, closed book) Chemistry 1A, Spring 2007 Midterm Exam 2 March 5, 2007 (90 min, closed book) Name: KEY SID: TA Name: 1.) Write your name on every page of this exam. 2.) This exam has 40 multiple choice questions. Fill

More information

Coordination Chemistry II: Bonding

Coordination Chemistry II: Bonding d x2-y2 b 1g e g d x2-y2 b 1g D 1 t 2 d xy, d yz, d zx D t d d z2, d x2-y2 D o d z2 a 1g d xy D 2 d z2 b 2g a 1g e d z2, d x2-y2 d xy, d yz, d zx d xy b 2g D 3 t 2g e g d yz, d zx e g d yz, d zx 10 Coordination

More information