Problem Set. Assigned October 18, 2013 Due Friday, October 25, Please show all work for credit

Size: px
Start display at page:

Download "Problem Set. Assigned October 18, 2013 Due Friday, October 25, Please show all work for credit"

Transcription

1 Problem Set Assigned October 18, 2013 Due Friday, October 25, 2013 Please show all work for credit To hand in: Thermodynamic Relations 1. The shells of marine organisms contain CaCO 3 largely in the crystalline form known as calcite. There is a second crystalline form of CaCO 3 known as aragonite. (a) Based on the thermodynamic and physical properties given for these two crystalline forms, would you expect calcite in nature to convert spontaneously to aragonite given sufficient time? Justify your answer. (b) Will the conversion proposed in part (a) be favored or opposed by increasing the pressure? Explain. (c) What pressure should be just sufficient to make this conversion spontaneous at 25 C? (d) Will increasing the temperature favor the conversion? Explain. 2. The temperature of a typical laboratory freezer unit is -20 C. If liquid water in a completely filled, closed container is placed in the freezer, estimate the maximum pressure developed in the container at equilibrium. The enthalpy of fusion of water may be taken as kj kg -1, independent of temperature and pressure, and the densities of ice and liquid water at -20 C are and 1.00 g cm -3, respectively. Free energy of mixing processes 3. Atkins Ch. 5: Ex. 5.2 (b)

2 4. Atkins Ch. 5: Ex. 5.9 (b) 5. Engel P 6.29 A sample containing 2.25mol of He (1bar, 298K) is mixed with 3.00mol of Ne (1 bar, 298K) and 1.75mol of Ar(1 bar, 298K). Calculate G mixing and S mixing. Equilibrium 6. Atkins Ch. 6: Ex. 6.2 (b) 7. Engle P.6.18 Protein denaturing Many biological macromolecules undergo a transition called denaturation. Denaturation is a process whereby a structured, biological active molecule, called the native form, unfolds or becomes unstructured and biologically inactive. The equilibrium is native(folded) denatured(unfolded) For a protein at ph = 2, the enthalpy change associated with denaturation is H = kj mol 1 and the entropy change is S = 1.3 kj K 1 mol 1. a. Calculate the Gibbs energy change for the denaturation of the protein at ph = 2 and T = 303 K. Assume the enthalpy and entropy are temperature independent between and 303 K. b. Calculate the equilibrium constant for the denaturation of protein at ph = 2 and T = 303 K. c. Based on your answers for parts (a) and (b), is protein structurally stable at ph = 2 and T = 303 K?

3 Substance 8. Engle - P.6.25 Pentene isomers At 25 C, values for the formation enthalpy and Gibbs energy and log 10 K P for the formation reactions of the various isomers of C 5 H 10 in the gas phase are given by the following table: H f kj mol 1 G f kj mol 1 log 10 K P A = 1-pentene B = cis-2-pentene C = trans-2-pentene D = 2-methyl-1-butene E = 3-methyl-1-butene F = 2-methyl-2-butene G = cyclopentane Consider the equilibrium A B C D E F G, which might be established using a suitable catalyst. a. Calculate the mole ratios A/G, B/G, C/G, D/G, E/G, and F/G present at equilibrium at 25 C. b. Do the ratios of part (a) depend on the total pressure? c. Calculate the mole percentages of the various species in the equilibrium mixture. 9. Engle P.6.34 Gas reaction Calculate K P at 475 K for the reaction NO(g) + 1/2 O 2 (g) NO 2 (g) assuming that H reaction is constant over the interval from 298 to 600 K. Do you expect K P to increase or decrease as the temperature is increased to 550 K? 10. Engle P.6.40 Calcium carbonate decomposition Ca(HCO 3 ) 2 (s) decomposes at elevated temperatures according to the stoichiometric equation Ca(HCO 3 ) 2 (s) CaCO 3 (s) + H 2 O(g) + CO 2 (g). a. If pure Ca(HCO 3 ) 2 (s) is put into a sealed vessel, the air is pumped out, and the vessel and its contents are heated, the total pressure is bar. Determine K P under these conditions. b. If the vessel initially also contains bar H 2 O(g), what is the partial pressure of CO 2 (g) at equilibrium?

4 11. Oxides of sulfur are important in atmospheric pollution, arising particularly from burning coal. Use the thermodynamic data at 25 C given in the table below to answer the following questions. (a) In air, the oxidation of SO 2 can occur: 1/2O 2 (g)+so 2 (g)=so 3 (g). Calculate the standard Gibbs free energy for this reaction at 25 C. (b) Find the equilibrium ratio of partial pressures of SO 3 (g) to SO 2 (g) in air at 25 C; the partial pressure of O 2 (g) is 0.21 atm. (c) SO 3 (g) can react with H 2 O(g) to form sulfuric acid, H 2 SO 4 (g). Air that is in equilibrium with liquid water at 25 C has a partial pressure of H 2 O(g) of atm. Find the equilibrium ratio of partial pressures of H 2 SO 4 (g) to SO 3 (g) in air at 25 C. 12. What is the pressure of CO(g) in equilibrium with the CO 2 (g) and O 2 (g) in the atmosphere at 25 C? The partial pressure of O 2 (g) is 0.2 atm, and the partial pressure of CO 2 (g) is 3 atm. CO is extremely poisonous because it forms a very strong complex with hemoglobin. Should you worry? Extras practice for exam, do not hand in Thermodynamic Relations 13. Atkins P.3.30 Joule coefficient derivation 14. Atkins P.3.24 Ideal gas derivation 15. Atkins - E.3.22(b) - Free energy of isothermal process

5 16. Engle P.6.23 Glucose breakdown Under anaerobic conditions, glucose is broken down in muscle tissue to form lactic acid according to the reaction: C 6 H 12 O 6 2 CH 3 CHOHCOOH. Thermodynamic data at T = 298 K for glucose and lactic acid are given below. H f kj mol 1 C P,m J K 1 mol 1 S (J K 1 mol 1 ) Glucose Lactic Acid Calculate G at T = 298 K and T = 310. K. Assume all heat capacities are constant from T = 298 K to T = 310.K. 17. Engle P.6.24 Protein denaturing* At T = 298 K and ph=3 chymotrypsinogen denatures with G = 30.5 kj mol 1, H = 163 kj mol 1, and C P,m = 8.36 kj K 1 mol 1. Determine G for the denaturation of chymotrypsinogen at T = 320. K and ph=3. Assume C P,m is constant between T = 298 K and T = 320. K. Free energy of mixing processes 18. Engle P.6.31 Gas mixture* A gas mixture with 4 mol of Ar, x moles of Ne, and y moles of Xe is prepared at a pressure of 1 bar and a temperature of 298 K. The total number of moles in the mixture is three times that of Ar. Write an expression for G mixing in terms of x. At what value of x does G mixing have its minimum value? Calculate G mixing for this value of x. 19. Atkins Ch. 5: Ex (b)* Equilibrium 20. Engle P.6.26 Temperature dependent enthalpy error* In this problem, you calculate the error in assuming that H reaction is independent of T for a specific reaction. The following data are given at 25 C:

6 H f G f C P,m kj mol 1 kj mol 1 J K 1 mol 1 CuO(s) Cu(s) O 2 (g) a. From Equation (6.71), K P T f K P T 0 d ln K P 1 R T f T 0 H reaction T 2 To a good approximation, we can assume that the heat capacities are independent of temperature over a limited range in temperature, giving H reaction T H reaction T 0 C P T T 0 where C P v i C P,m i. By integrating Equation (6.71), show that ln K P T ln K P T 0 H reaction T 0 R T 0 C P R 1 T 1 T 0 1 T 1 T C P 0 R ln T T 0 b. Using the result from part (a), calculate the equilibrium pressure of oxygen over copper and CuO(s) at 1200 K. How is this value related to K P for the reaction ( ) ( ) ( )? c. What value would you obtain if you assumed that H reaction were constant at its value for K up to 1200 K? 21. Atkins Ch. 6: Ex. 6.3 (b) dt i

2SO 2(g) + O 2(g) Increasing the temperature. (Total 1 mark) Enthalpy data for the reacting species are given in the table below.

2SO 2(g) + O 2(g) Increasing the temperature. (Total 1 mark) Enthalpy data for the reacting species are given in the table below. Q1.Which change would alter the value of the equilibrium constant (K p) for this reaction? 2SO 2(g) + O 2(g) 2SO 3(g) A Increasing the total pressure of the system. Increasing the concentration of sulfur

More information

Introduction to Chemical Thermodynamics. (10 Lectures) Michaelmas Term

Introduction to Chemical Thermodynamics. (10 Lectures) Michaelmas Term Introduction to Chemical Thermodynamics Dr. D. E. Manolopoulos First Year (0 Lectures) Michaelmas Term Lecture Synopsis. Introduction & Background. Le Chatelier s Principle. Equations of state. Systems

More information

Introduction to Chemical Thermodynamics. D. E. Manolopoulos First Year (13 Lectures) Michaelmas Term

Introduction to Chemical Thermodynamics. D. E. Manolopoulos First Year (13 Lectures) Michaelmas Term Introduction to Chemical Thermodynamics D. E. Manolopoulos First Year (13 Lectures) Michaelmas Term Lecture Synopsis 1. Introduction & Background. Le Chatelier s Principle. Equations of state. Systems

More information

Ch 9 Practice Problems

Ch 9 Practice Problems Ch 9 Practice Problems 1. One mole of an ideal gas is expanded from a volume of 1.50 L to a volume of 10.18 L against a constant external pressure of 1.03 atm. Calculate the work. (1 L atm = 101.3 J) A)

More information

CHEM J-11 June /01(a)

CHEM J-11 June /01(a) CHEM1001 2014-J-11 June 2014 22/01(a) Combustion of 15.0 g of coal provided sufficient heat to increase the temperature of 7.5 kg of water from 286 K to 298 K. Calculate the amount of heat (in kj) absorbed

More information

Tutorial 1 (not important for 2015)

Tutorial 1 (not important for 2015) Tutorial 1 (not important for 2015) 1 st Law of thermodynamics and other basic concepts Do No. 5 (05-03-2015) 1. One mole of an ideal gas is allowed to expand against a piston which supports 41 atm pressures.

More information

Thermodynamics. Thermodynamics of Chemical Reactions. Enthalpy change

Thermodynamics. Thermodynamics of Chemical Reactions. Enthalpy change Thermodynamics 1 st law (Cons of Energy) Deals with changes in energy Energy in chemical systems Total energy of an isolated system is constant Total energy = Potential energy + kinetic energy E p mgh

More information

AP Chemistry Chapter 16 Assignment. Part I Multiple Choice

AP Chemistry Chapter 16 Assignment. Part I Multiple Choice Page 1 of 7 AP Chemistry Chapter 16 Assignment Part I Multiple Choice 1984 47. CH 4 (g) + 2 O 2 (g) CO 2 (g) + 2 H 2 O(l) H = 889.1 kj H f H 2 O(l) = 285.8 kj mol 1 H f CO 2 (g) = 393.3 kj mol 1 What is

More information

January 03, Ch 13 SB equilibrium.notebook

January 03, Ch 13 SB equilibrium.notebook Ch 13: Chemical Equilibrium exists when 2 opposing reactions occur simultaneously at the same rate (dynamic rather than static) Forward rate = reverse rate https://www.youtube.com/watch?v=wld_imyqagq The

More information

AP* Thermodynamics Free Response Questions page 1. Essay Questions

AP* Thermodynamics Free Response Questions page 1. Essay Questions AP* Thermodynamics Free Response Questions page 1 Essay Questions 1991 The reaction represented above is a reversible reaction. BCl 3 (g) + NH 3 (g) Cl 3 BNH 3 (s) (a) Predict the sign of the entropy change,

More information

Gravity is a force which keeps us stuck to the earth. The Electrostatic force attracts electrons to protons in an atom.

Gravity is a force which keeps us stuck to the earth. The Electrostatic force attracts electrons to protons in an atom. Energy Relations in Chemistry: Thermochemistry The Nature of Energy Sugar you eat is "combusted" by your body to produce CO 2 and H 2 O. During this process energy is also released. This energy is used

More information

Chemistry 1A, Spring 2007 Midterm Exam 3 April 9, 2007 (90 min, closed book)

Chemistry 1A, Spring 2007 Midterm Exam 3 April 9, 2007 (90 min, closed book) Chemistry 1A, Spring 2007 Midterm Exam 3 April 9, 2007 (90 min, closed book) Name: KEY SID: TA Name: 1.) Write your name on every page of this exam. 2.) This exam has 34 multiple choice questions. Fill

More information

Name AP CHEM / / Collected AP Exam Essay Answers for Chapter 16

Name AP CHEM / / Collected AP Exam Essay Answers for Chapter 16 Name AP CHEM / / Collected AP Exam Essay Answers for Chapter 16 1980 - #7 (a) State the physical significance of entropy. Entropy (S) is a measure of randomness or disorder in a system. (b) From each of

More information

Enthalpy, Entropy, and Free Energy Calculations

Enthalpy, Entropy, and Free Energy Calculations Adapted from PLTL The energies of our system will decay, the glory of the sun will be dimmed, and the earth, tideless and inert, will no longer tolerate the race which has for a moment disturbed its solitude.

More information

Problem Set #10 Assigned November 8, 2013 Due Friday, November 15, 2013 Please show all work for credit To Hand in

Problem Set #10 Assigned November 8, 2013 Due Friday, November 15, 2013 Please show all work for credit To Hand in Problem Set #10 Assigned November 8, 2013 Due Friday, November 15, 2013 Please show all work for credit To Hand in 1. 2. 1 3. 4. The vapor pressure of an unknown solid is approximately given by ln(p/torr)

More information

I PUC CHEMISTRY CHAPTER - 06 Thermodynamics

I PUC CHEMISTRY CHAPTER - 06 Thermodynamics I PUC CHEMISTRY CHAPTER - 06 Thermodynamics One mark questions 1. Define System. 2. Define surroundings. 3. What is an open system? Give one example. 4. What is closed system? Give one example. 5. What

More information

Thermodynamics is the study of the relationship between heat and other forms of energy that are involved in a chemical reaction.

Thermodynamics is the study of the relationship between heat and other forms of energy that are involved in a chemical reaction. Ch 18 Thermodynamics and Equilibrium Thermodynamics is the study of the relationship between heat and other forms of energy that are involved in a chemical reaction. Internal Energy (U) Internal energy

More information

UNIT 15: THERMODYNAMICS

UNIT 15: THERMODYNAMICS UNIT 15: THERMODYNAMICS ENTHALPY, DH ENTROPY, DS GIBBS FREE ENERGY, DG ENTHALPY, DH Energy Changes in Reactions Heat is the transfer of thermal energy between two bodies that are at different temperatures.

More information

Physical Chemistry I Exam points

Physical Chemistry I Exam points Chemistry 360 Fall 2018 Dr. Jean M. tandard October 17, 2018 Name Physical Chemistry I Exam 2 100 points Note: You must show your work on problems in order to receive full credit for any answers. You must

More information

Thermochemistry Chapter 8

Thermochemistry Chapter 8 Thermochemistry Chapter 8 Thermochemistry First law of thermochemistry: Internal energy of an isolated system is constant; energy cannot be created or destroyed; however, energy can be converted to different

More information

Chem 1B Dr. White 1 Chapter 17: Thermodynamics. Review From Chem 1A (Chapter 6, section 1) A. The First Law of Thermodynamics

Chem 1B Dr. White 1 Chapter 17: Thermodynamics. Review From Chem 1A (Chapter 6, section 1) A. The First Law of Thermodynamics Chem 1B Dr. White 1 Chapter 17: Thermodynamics Review From Chem 1A (Chapter 6, section 1) A. The First Law of Thermodynamics 17.1 Spontaneous Processes and Entropy A. Spontaneous Change Chem 1B Dr. White

More information

3. Indicate the mass action expression for the following reaction: 2X(g) + Y(g) 3W(g) + V(g) a) [X] 2 [Y][W] 3 [V] [W] 3 [V] [X] 2 [Y] [3W][V] [2X][Y]

3. Indicate the mass action expression for the following reaction: 2X(g) + Y(g) 3W(g) + V(g) a) [X] 2 [Y][W] 3 [V] [W] 3 [V] [X] 2 [Y] [3W][V] [2X][Y] 1. Which of the following statements concerning equilibrium is not true? a) A system that is disturbed from an equilibrium condition responds in a manner to restore equilibrium. b) Equilibrium in molecular

More information

Chem 152 Final. You will have 1 hour and 50 minutes. Do not begin the exam until you are instructed to start. Best of luck.

Chem 152 Final. You will have 1 hour and 50 minutes. Do not begin the exam until you are instructed to start. Best of luck. Chem 152 Final Section: Name: You will have 1 hour and 50 minutes. Do not begin the exam until you are instructed to start. Best of luck. Question 1 /80 Question 2 /20 Question 3 /20 Question 4 /20 Question

More information

Name: Thermochemistry. Practice Test C. General Chemistry Honors Chemistry

Name: Thermochemistry. Practice Test C. General Chemistry Honors Chemistry Name: Thermochemistry C Practice Test C General Chemistry Honors Chemistry 1 Objective 1: Use the relationship between mass, specific heat, and temperature change to calculate the heat flow during a chemical

More information

10-1 Heat 10-2 Calorimetry 10-3 Enthalpy 10-4 Standard-State Enthalpies 10-5 Bond Enthalpies 10-6 The First Law of Thermodynamics

10-1 Heat 10-2 Calorimetry 10-3 Enthalpy 10-4 Standard-State Enthalpies 10-5 Bond Enthalpies 10-6 The First Law of Thermodynamics Chapter 10 Thermochemistry 10-1 Heat 10-2 Calorimetry 10-3 Enthalpy 10-4 Standard-State Enthalpies 10-5 Bond Enthalpies 10-6 The First Law of Thermodynamics OFB Chap. 10 1 Chapter 10 Thermochemistry Heat

More information

BCIT Fall Chem Exam #2

BCIT Fall Chem Exam #2 BCI Fall 2016 Chem 3310 Exam #2 Name: Attempt all questions in this exam. Read each question carefully and give a complete answer in the space provided. Part marks given for wrong answers with partially

More information

Chem 401 Unit 1 Exam: Thermodynamics & Kinetics (Nuss: Spr 2018)

Chem 401 Unit 1 Exam: Thermodynamics & Kinetics (Nuss: Spr 2018) Date: Exam # Chem 401 Unit 1 Exam: Thermodynamics & Kinetics (Nuss: Spr 2018) Multiple Choice Identify the choice that best completes the statement or answers the question. (3 pts each) 1. Which of the

More information

Chapter 8 Thermochemistry: Chemical Energy

Chapter 8 Thermochemistry: Chemical Energy Chapter 8 Thermochemistry: Chemical Energy 國防醫學院生化學科王明芳老師 2011-11-8 & 2011-11-15 Chapter 8/1 Energy and Its Conservation Conservation of Energy Law: Energy cannot be created or destroyed; it can only be

More information

Thermodynamic and Stochiometric Principles in Materials Balance

Thermodynamic and Stochiometric Principles in Materials Balance Thermodynamic and Stochiometric Principles in Materials Balance Typical metallurgical engineering problems based on materials and energy balance NiO is reduced in an open atmosphere furnace by excess carbon

More information

Chapter 19 Chemical Thermodynamics Entropy and free energy

Chapter 19 Chemical Thermodynamics Entropy and free energy Chapter 19 Chemical Thermodynamics Entropy and free energy Learning goals and key skills: Understand the meaning of spontaneous process, reversible process, irreversible process, and isothermal process.

More information

The table shows three possible reversible reactions that he could use. The enthalpy changes are also shown. O(g) CO 2. (g) + 4H 2.

The table shows three possible reversible reactions that he could use. The enthalpy changes are also shown. O(g) CO 2. (g) + 4H 2. 1 A manufacturer investigates some reactions that produce hydrogen. The table shows three possible reversible reactions that he could use. The enthalpy changes are also shown. Reaction Equation H in kj/mol

More information

Last Name or Student ID

Last Name or Student ID 10/06/08, Chem433 Exam # 1 Last Name or Student ID 1. (3 pts) 2. (3 pts) 3. (3 pts) 4. (2 pts) 5. (2 pts) 6. (2 pts) 7. (2 pts) 8. (2 pts) 9. (6 pts) 10. (5 pts) 11. (6 pts) 12. (12 pts) 13. (22 pts) 14.

More information

1. The reaction between solid barium hydroxide and solid ammonium chloride can be represented by the equation below.

1. The reaction between solid barium hydroxide and solid ammonium chloride can be represented by the equation below. 1. The reaction between solid barium hydroxide and solid ammonium chloride can be represented by the equation below. Ba(OH) 2 (s) + 2NH 4 Cl(s) BaCl 2 (s) + 2NH 3 (g) + 2H 2 O(l) ΔH ο = +51.1 kj mol 1

More information

Unit F FR Practice General Equilibrium (pg 1 of 26)

Unit F FR Practice General Equilibrium (pg 1 of 26) Unit F FR Practice General Equilibrium (pg 1 of 26) 1. Answer the following questions about glucose, C6H12O6, an important biochemical energy source. (a) Write the empirical formula of glucose. In many

More information

Name TA Name Lab Section # ALL work must be shown to receive full credit. Due at the beginning of lecture on Wednesday, October 31, 2001.

Name TA Name Lab Section # ALL work must be shown to receive full credit. Due at the beginning of lecture on Wednesday, October 31, 2001. Chem 1515 Problem Set #8 Fall 2001 Name TA Name Lab Section # ALL work must be shown to receive full credit. Due at the beginning of lecture on Wednesday, October 31, 2001. PS8.1. A 1.00 liter container

More information

Chapter 11 Spontaneous Change and Equilibrium

Chapter 11 Spontaneous Change and Equilibrium Chapter 11 Spontaneous Change and Equilibrium 11-1 Enthalpy and Spontaneous Change 11-2 Entropy 11-3 Absolute Entropies and Chemical Reactions 11-4 The Second Law of Thermodynamics 11-5 The Gibbs Function

More information

Chpt 19: Chemical. Thermodynamics. Thermodynamics

Chpt 19: Chemical. Thermodynamics. Thermodynamics CEM 152 1 Reaction Spontaneity Can we learn anything about the probability of a reaction occurring based on reaction enthaplies? in general, a large, negative reaction enthalpy is indicative of a spontaneous

More information

Class work on Calorimetry. January 11 and 12, 2011

Class work on Calorimetry. January 11 and 12, 2011 Class work on Calorimetry January 11 and 12, 2011 Name 1. The number of calories needed to raise the temperature of 100 grams of water 10 degrees Celsius is the same as the number of calories needed to

More information

Useful Information to be provided on the exam: 1 atm = 760 mm Hg = 760 torr = lb/in 2 = 101,325 Pa = kpa. q = m C T. w = -P V.

Useful Information to be provided on the exam: 1 atm = 760 mm Hg = 760 torr = lb/in 2 = 101,325 Pa = kpa. q = m C T. w = -P V. Chem 101A Study Questions, Chapters 5 & 6 Name: Review Tues 10/25/16 Due 10/27/16 (Exam 3 date) This is a homework assignment. Please show your work for full credit. If you do work on separate paper, attach

More information

10-1 Heat 10-2 Calorimetry 10-3 Enthalpy 10-4 Standard-State Enthalpies 10-5 Bond Enthalpies 10-6 The First Law of Thermodynamics

10-1 Heat 10-2 Calorimetry 10-3 Enthalpy 10-4 Standard-State Enthalpies 10-5 Bond Enthalpies 10-6 The First Law of Thermodynamics Chapter 10 Thermochemistry 10-1 Heat 10-2 Calorimetry 10-3 Enthalpy 10-4 Standard-State Enthalpies 10-5 Bond Enthalpies 10-6 The First Law of Thermodynamics OFB Chap. 10 1 OFB Chap. 10 2 Thermite Reaction

More information

UNIT ONE BOOKLET 6. Thermodynamic

UNIT ONE BOOKLET 6. Thermodynamic DUNCANRIG SECONDARY ADVANCED HIGHER CHEMISTRY UNIT ONE BOOKLET 6 Thermodynamic Can we predict if a reaction will occur? What determines whether a reaction will be feasible or not? This is a question that

More information

Entropy. Spontaneity. Entropy. Entropy mol of N 2 at 1 atm or 1 mol of N 2 at atm. process a process that occurs without intervention

Entropy. Spontaneity. Entropy. Entropy mol of N 2 at 1 atm or 1 mol of N 2 at atm. process a process that occurs without intervention Entropy Spontaneity process a process that occurs without intervention can be fast or slow Entropy (s) the measure of molecular randomness or disorder Think of entropy as the amount of chaos Entropy Predict

More information

Chemistry 425 September 29, 2010 Exam 1 Solutions

Chemistry 425 September 29, 2010 Exam 1 Solutions Chemistry 425 September 29, 2010 Exam 1 Solutions Name: Instructions: Please do not start working on the exam until you are told to begin. Check the exam to make sure that it contains exactly 6 different

More information

First Law of Thermodynamics: energy cannot be created or destroyed.

First Law of Thermodynamics: energy cannot be created or destroyed. 1 CHEMICAL THERMODYNAMICS ANSWERS energy = anything that has the capacity to do work work = force acting over a distance Energy (E) = Work = Force x Distance First Law of Thermodynamics: energy cannot

More information

Quantitative Relationships in Chemical Reactions Chapter 7

Quantitative Relationships in Chemical Reactions Chapter 7 Quantitative Relationships in Chemical Reactions Chapter 7 The burning of charcoal releases heat (thermal energy) that grills our food. But the combustion of charcoal and fossil fuels also releases CO

More information

(g) + 2H 2. (g) CH [1] (g) H 2. Explain, with a calculation, whether this reaction is feasible at 25 C [3]

(g) + 2H 2. (g) CH [1] (g) H 2. Explain, with a calculation, whether this reaction is feasible at 25 C [3] 1 This question looks at two reactions involving sulfur compounds (a) Hydrogen reacts with carbon disulfide as shown below 4H 2 + CS 2 CH 4 + 2H 2 S For this reaction, ΔH = 234 kj mol 1 and ΔS = 164 J

More information

Q1. (a) State what is meant by the term activation energy of a reaction. (1)

Q1. (a) State what is meant by the term activation energy of a reaction. (1) Q1. (a) State what is meant by the term activation energy of a reaction. (c) State in general terms how a catalyst increases the rate of a chemical reaction. The curve below shows the Maxwell Boltzmann

More information

Properties of Matter

Properties of Matter Properties of Matter Chapter 4 Hein and Arena Version 1.0 Eugene Passer Chemistry Department Bronx Community 1 College John Wiley and Sons, Inc Properties of Substances 2 Properties of a Substance A property

More information

Contents and Concepts

Contents and Concepts Contents and Concepts 1. First Law of Thermodynamics Spontaneous Processes and Entropy A spontaneous process is one that occurs by itself. As we will see, the entropy of the system increases in a spontaneous

More information

For more info visit

For more info visit Basic Terminology: Terms System Open System Closed System Isolated system Surroundings Boundary State variables State Functions Intensive properties Extensive properties Process Isothermal process Isobaric

More information

CHM 1046 FINAL REVIEW

CHM 1046 FINAL REVIEW CHM 1046 FINAL REVIEW Prepared & Presented By: Marian Ayoub PART I Chapter Description 6 Thermochemistry 11 States of Matter; Liquids and Solids 12 Solutions 13 Rates of Reactions 18 Thermodynamics and

More information

General Chemistry I Final Exam 100 pts Fall 2010

General Chemistry I Final Exam 100 pts Fall 2010 General Chemistry I Final Exam 100 pts Fall 2010 Name This is a closed-book exam: the only reference materials you may use are a periodic table of the elements, a table of enthalpies of formation, and

More information

CHEM N-2 November 2014

CHEM N-2 November 2014 CHEM1612 2014-N-2 November 2014 Explain the following terms or concepts. Le Châtelier s principle 1 Used to predict the effect of a change in the conditions on a reaction at equilibrium, this principle

More information

(E) half as fast as methane.

(E) half as fast as methane. Name AP Chem / / AP Chem Practice Exam #2 Part I: 40 Questions, 40 minutes, Multiple Choice, No Calculator Allowed Bubble the correct answer on the BLUE SIDE of your scantron for each of the following.

More information

AP CHEMISTRY NOTES 4-1 THERMOCHEMISTRY: ENTHALPY AND ENTROPY

AP CHEMISTRY NOTES 4-1 THERMOCHEMISTRY: ENTHALPY AND ENTROPY AP CHEMISTRY NOTES 4-1 THERMOCHEMISTRY: ENTHALPY AND ENTROPY Reaction Rate how fast a chemical reaction occurs Collision Theory In order for a chemical reaction to occur, the following conditions must

More information

Contents and Concepts

Contents and Concepts Contents and Concepts 1. First Law of Thermodynamics Spontaneous Processes and Entropy A spontaneous process is one that occurs by itself. As we will see, the entropy of the system increases in a spontaneous

More information

Contents and Concepts

Contents and Concepts Contents and Concepts 1. First Law of Thermodynamics Spontaneous Processes and Entropy A spontaneous process is one that occurs by itself. As we will see, the entropy of the system increases in a spontaneous

More information

Contents. Content Guidance. Questions & Answers. Getting the most from this book... 4 About this book... 5

Contents. Content Guidance. Questions & Answers. Getting the most from this book... 4 About this book... 5 Contents Getting the most from this book... 4 About this book.... 5 Content Guidance Atomic structure......................................... 6 Amount of substance....................................

More information

B 2 Fe(s) O 2(g) Fe 2 O 3 (s) H f = -824 kj mol 1 Iron reacts with oxygen to produce iron(iii) oxide as represented above. A 75.

B 2 Fe(s) O 2(g) Fe 2 O 3 (s) H f = -824 kj mol 1 Iron reacts with oxygen to produce iron(iii) oxide as represented above. A 75. 1 2004 B 2 Fe(s) + 3 2 O 2(g) Fe 2 O 3 (s) H f = -824 kj mol 1 Iron reacts with oxygen to produce iron(iii) oxide as represented above. A 75.0 g sample of Fe(s) is mixed with 11.5 L of O 2 (g) at 2.66

More information

Name: Score: /100. Part I. Multiple choice. Write the letter of the correct answer for each problem. 3 points each

Name: Score: /100. Part I. Multiple choice. Write the letter of the correct answer for each problem. 3 points each Name: Score: /100 Part I. Multiple choice. Write the letter of the correct answer for each problem. 3 points each 1. Which of the following contains the greatest number of moles of O? A) 2.3 mol H 2 O

More information

Section 1 - Thermochemistry

Section 1 - Thermochemistry Reaction Energy Section 1 - Thermochemistry Virtually every chemical reaction is accompanied by a change in energy. Chemical reactions usually absorb or release energy as heat. You learned in Chapter 12

More information

10.02 PE Diagrams. 1. Given the equation and potential energy diagram representing a reaction:

10.02 PE Diagrams. 1. Given the equation and potential energy diagram representing a reaction: 10.02 PE Diagrams 1. Given the equation and potential energy diagram representing a reaction: 3. Given the potential energy diagram and equation representing the reaction between substances A and D : If

More information

Practice Questions Placement Exam for Entry into Chemistry 120

Practice Questions Placement Exam for Entry into Chemistry 120 Practice Questions Placement Exam for Entry into Chemistry 120 Potentially Useful Information Avogadro's number = 6.0221420 10 23 h = 6.6260688 10 34 J s c = 2.9979246 10 8 m/s 1amu = 1.6605387 10 27 kg

More information

Chapter 19 Chemical Thermodynamics Entropy and free energy

Chapter 19 Chemical Thermodynamics Entropy and free energy Chapter 19 Chemical Thermodynamics Entropy and free energy Learning goals and key skills: Explain and apply the terms spontaneous process, reversible process, irreversible process, and isothermal process.

More information

Apply the concept of percent yield to stoichiometric problems. Methanol can be produced through the reaction of CO and H 2 in the presence of a

Apply the concept of percent yield to stoichiometric problems. Methanol can be produced through the reaction of CO and H 2 in the presence of a Apply the concept of percent yield to stoichiometric problems. Methanol can be produced through the reaction of CO and H 2 in the presence of a catalyst. CO (g) + H 2 (g) CH 3 OH (l) If 75.0 g of CO reacts

More information

Thermochemistry. Energy. 1st Law of Thermodynamics. Enthalpy / Calorimetry. Enthalpy of Formation

Thermochemistry. Energy. 1st Law of Thermodynamics. Enthalpy / Calorimetry. Enthalpy of Formation THERMOCHEMISTRY Thermochemistry Energy 1st Law of Thermodynamics Enthalpy / Calorimetry Hess' Law Enthalpy of Formation The Nature of Energy Kinetic Energy and Potential Energy Kinetic energy is the energy

More information

0. Graphite is thermodynamically less stable that diamond under standard conditions. 1. True 2. False

0. Graphite is thermodynamically less stable that diamond under standard conditions. 1. True 2. False 0. Graphite is thermodynamically less stable that diamond under standard conditions. 1. True 2. False 1. Which statement would be the best interpretation of the First Law of Thermodynamics? 1. The total

More information

Sections A. Hess s Law Grade 12. Energetics. Instructions: Please complete questions: 1-9 for homework

Sections A. Hess s Law Grade 12. Energetics. Instructions: Please complete questions: 1-9 for homework Hess s Law Grade 2 Energetics Instructions: Please complete questions: - 9 for homework Sections A. The H Ө values for the formation of two oxides of nitrogen are given below. 2 N 2 (g) + O 2 (g) NO 2

More information

CHEM Exam 2 - October 11, INFORMATION PAGE (Use for reference and for scratch paper)

CHEM Exam 2 - October 11, INFORMATION PAGE (Use for reference and for scratch paper) CHEM 5200 - Exam 2 - October 11, 2018 INFORMATION PAGE (Use for reference and for scratch paper) Constants and Conversion Factors: R = 0.082 L-atm/mol-K = 8.31 J/mol-K = 8.31 kpa-l/mol-k 1 L-atm = 101

More information

CYL Classical Thermodynamics Sample Problems

CYL Classical Thermodynamics Sample Problems CYL110 2012-2013 Classical Thermodynamics Sample Problems 1. Dieterici s equation of state for a gas is P (V b) exp(a/rv T ) = RT, where a, b, and R are constants. Determine ( V/ T ), ( T/ P ), and ( P/

More information

Thermodynamics Review 2014 Worth 10% of Exam Score

Thermodynamics Review 2014 Worth 10% of Exam Score Thermodynamics Review 2014 Worth 10% of Exam Score Name: Period: 1. Base your answer to the following question on the diagram shown below. 4. The heat of combustion for is kcal. What is the heat of formation

More information

3.2.2 Kinetics. Effect of temperature. 145 minutes. 145 marks. Page 1 of 22

3.2.2 Kinetics. Effect of temperature. 145 minutes. 145 marks. Page 1 of 22 3.. Kinetics Effect of temperature 145 minutes 145 marks Page 1 of Q1. (a) State what is meant by the term activation energy of a reaction. (b) (c) State in general terms how a catalyst increases the rate

More information

CHEMISTRY 202 Hour Exam II. Dr. D. DeCoste T.A (60 pts.) 31 (20 pts.) 32 (40 pts.)

CHEMISTRY 202 Hour Exam II. Dr. D. DeCoste T.A (60 pts.) 31 (20 pts.) 32 (40 pts.) CHEMISTRY 202 Hour Exam II October 27, 2015 Dr. D. DeCoste Name Signature T.A. This exam contains 32 questions on 11 numbered pages. Check now to make sure you have a complete exam. You have two hours

More information

and mol of Cl 2 was heated in a vessel of fixed volume to a constant temperature, the following reaction reached equilibrium.

and mol of Cl 2 was heated in a vessel of fixed volume to a constant temperature, the following reaction reached equilibrium. Q1. When a mixture of 0.45 mol of PCl and 0.68 mol of Cl was heated in a vessel of fixed volume to a constant temperature, the following reaction reached equilibrium. PCl + Cl PCl 5 H = 9 kj mol 1 At equilibrium,

More information

I. Multiple Choice Questions (Type-I)

I. Multiple Choice Questions (Type-I) I. Multiple Choice Questions (Type-I) 1. Thermodynamics is not concerned about. (i) energy changes involved in a chemical reaction. the extent to which a chemical reaction proceeds. the rate at which a

More information

11B, 11E Temperature and heat are related but not identical.

11B, 11E Temperature and heat are related but not identical. Thermochemistry Key Terms thermochemistry heat thermochemical equation calorimeter specific heat molar enthalpy of formation temperature enthalpy change enthalpy of combustion joule enthalpy of reaction

More information

The underlying prerequisite to the application of thermodynamic principles to natural systems is that the system under consideration should be at equilibrium. http://eps.mcgill.ca/~courses/c220/ Reversible

More information

Chapter 9. Chemical Equilibrium

Chapter 9. Chemical Equilibrium Chapter 9. Chemical Equilibrium 9.1 The Nature of Chemical Equilibrium -Approach to Equilibrium [Co(H 2 O) 6 ] 2+ + 4 Cl- [CoCl 4 ] 2- + 6 H 2 O Characteristics of the Equilibrium State example) H 2 O(l)

More information

Chapter 15 Equilibrium

Chapter 15 Equilibrium Chapter 15. Chemical Equilibrium Sample Exercise 15.1 (p. 632) Write the equilibrium expression for K eq for these three reactions: a) 2 O 3(g) 3 O 2(g) b) 2 NO (g) + Cl 2(g) 2 NOCl (g) c) Ag + (aq) +

More information

Exam 3, Ch 7, 19, 14 November 9, Points

Exam 3, Ch 7, 19, 14 November 9, Points Chem 30 Name Exam 3, Ch 7, 9, 4 November 9, 206 00 Points Please follow the instructions for each section of the exam. Show your work on all mathematical problems. Provide answers with the correct units

More information

(g) 2NH 3. (g) ΔH = 92 kj mol 1

(g) 2NH 3. (g) ΔH = 92 kj mol 1 1 The uses of catalysts have great economic and environmental importance For example, catalysts are used in ammonia production and in catalytic converters (a) Nitrogen and hydrogen react together in the

More information

3.2.2 Kinetics. Maxwell Boltzmann distribution. 128 minutes. 128 marks. Page 1 of 16

3.2.2 Kinetics. Maxwell Boltzmann distribution. 128 minutes. 128 marks. Page 1 of 16 3.2.2 Kinetics Maxwell Boltzmann distribution 128 minutes 128 marks Page 1 of 16 Q1. The diagram shows the Maxwell Boltzmann distribution for a sample of gas at a fixed temperature. E a is the activation

More information

CHEM 1423 Chapter 17 Homework Questions TEXTBOOK HOMEWORK

CHEM 1423 Chapter 17 Homework Questions TEXTBOOK HOMEWORK CHEM 1423 Chapter 17 Homework Questions TEXTBOOK HOMEWORK 17.29 At 425 o C, Kp = 4.18x10-9 for the reaction 2HBr(g) H 2 (g) + Br 2 (g) In one experiment, 0.20 atm of HBr(g), 0.010 atm of H 2 (g), and 0.010

More information

CHEMISTRY 107 Section 501 Final Exam Version A December 11, 2017 Dr. Larry Brown

CHEMISTRY 107 Section 501 Final Exam Version A December 11, 2017 Dr. Larry Brown NAME: (print) UIN #: CHEMISTRY 107 Section 501 Final Exam Version A December 11, 2017 Dr. Larry Brown This is a 2-hour exam and contains 21 multiple-choice questions and 5 free response problems. Point

More information

AP Questions: Thermodynamics

AP Questions: Thermodynamics AP Questions: Thermodynamics 1970 Consider the first ionization of sulfurous acid: H2SO3(aq) H + (aq) + HSO3 - (aq) Certain related thermodynamic data are provided below: H2SO3(aq) H + (aq) HSO3 - (aq)

More information

Exam 4, Ch 14 and 15 December 7, Points

Exam 4, Ch 14 and 15 December 7, Points Chem 130 Name Exam 4, Ch 14 and 15 December 7, 2016 100 Points Please follow the instructions for each section of the exam. Show your work on all mathematical problems. Provide answers with the correct

More information

CHEM Exam 3 - March 30, Given in the individual questions on this test.

CHEM Exam 3 - March 30, Given in the individual questions on this test. CHEM 3530 - Exam 3 - March 30, 2018 Constants and Conversion Factors NA = 6.02x10 23 mol -1 R = 8.31 J/mol-K = 8.31 kpa-l/mol-k 1 bar = 100 kpa = 750 torr 1 kpa = 7.50 torr 1 J = 1 kpa-l 1 kcal = 4.18

More information

Name: General Chemistry Chapter 11 Thermochemistry- Heat and Chemical Change

Name: General Chemistry Chapter 11 Thermochemistry- Heat and Chemical Change Name: General Chemistry Chapter 11 Thermochemistry- Heat and Chemical Change Notepack 1 Section 11.1: The Flow of Energy Heat (Pages 293 299) 1. Define the following terms: a. Thermochemistry b. Energy

More information

CH1101 Physical Chemistry Tutorial 1. Prof. Mike Lyons.

CH1101 Physical Chemistry Tutorial 1. Prof. Mike Lyons. CH111 Physical Chemistry Tutorial 1. Prof. Mike Lyons. CH111 Section A Annual 1 Internal Energy Units: Joules J Internal Energy (U) : total kinetic & potential energy of system. e.g. Gas in container with

More information

Learning Check. How much heat, q, is required to raise the temperature of 1000 kg of iron and 1000 kg of water from 25 C to 75 C?

Learning Check. How much heat, q, is required to raise the temperature of 1000 kg of iron and 1000 kg of water from 25 C to 75 C? Learning Check q = c * m * ΔT How much heat, q, is required to raise the temperature of 1000 kg of iron and 1000 kg of water from 25 C to 75 C? (c water =4.184 J/ C g, c iron =0.450 J/ C g) q Fe = 0.450

More information

CH 221 Sample Exam Exam II Name: Lab Section:

CH 221 Sample Exam Exam II Name: Lab Section: Exam II Name: Lab Section: Part I: Multiple Choice Questions (100 Points) Use a scantron sheet for Part I. There is only one best answer for each question. 1. When methanol undergoes complete combustion,

More information

In previous chapters we have studied: Why does a change occur in the first place? Methane burns but not the reverse CH 4 + 2O 2 CO 2 + 2H 2 O

In previous chapters we have studied: Why does a change occur in the first place? Methane burns but not the reverse CH 4 + 2O 2 CO 2 + 2H 2 O Chapter 19. Spontaneous Change: Entropy and Free Energy In previous chapters we have studied: How fast does the change occur How is rate affected by concentration and temperature How much product will

More information

Chemistry 122 (Tyvoll) EXAMINATION II KEY November 4, 2005

Chemistry 122 (Tyvoll) EXAMINATION II KEY November 4, 2005 Chemistry 122 (Tyvoll) EXAMINATION II KEY November 4, 2005 Part I. Multiple Choice (3 points each -- Total points = 45) 1. The activation energy for a chemical reaction is 1. the energy produced when bonds

More information

Chapter 7 Chemical Reactions: Energy, Rates, and Equilibrium

Chapter 7 Chemical Reactions: Energy, Rates, and Equilibrium Chapter 7 Chemical Reactions: Energy, Rates, and Equilibrium Introduction This chapter considers three factors: a) Thermodynamics (Energies of Reactions) a reaction will occur b) Kinetics (Rates of Reactions)

More information

CHEMISTRY. Section II (Total time 95 minutes) Part A Time 55 minutes YOU MAY USE YOUR CALCULATOR FOR PART A.

CHEMISTRY. Section II (Total time 95 minutes) Part A Time 55 minutes YOU MAY USE YOUR CALCULATOR FOR PART A. CHEMISTRY Section II (Total time 95 minutes) Part A Time 55 minutes YOU MAY USE YOUR CALCULATOR FOR PART A. CLEARLY SHOW THE METHOD USED AND THE STEPS INVOLVED IN ARRIVING AT YOUR ANSWERS. It is to your

More information

Q1. (a) Explain the meaning of the terms mean bond enthalpy and standard enthalpy of formation. Mean bond enthalpy

Q1. (a) Explain the meaning of the terms mean bond enthalpy and standard enthalpy of formation. Mean bond enthalpy Q1. (a) Explain the meaning of the terms mean bond enthalpy and standard enthalpy of formation. Mean bond enthalpy......... Standard enthalpy of formation............ (5) (b) Some mean bond enthalpies

More information

General Chemistry I Concepts

General Chemistry I Concepts Thermodynamics Thermodynamics The Three Laws of Thermodynamics (18.1) Spontaneous Processes (18.2) Entropy (18.3) The Second Law of Thermodynamics (18.4) Gibbs Free Energy (18.5) Free Energy and Chemical

More information

CY 102: Physical Chemistry End Semester May 3, 2004

CY 102: Physical Chemistry End Semester May 3, 2004 CY 102: Physical Chemistry End Semester May 3, 2004 Answer All Questions R = (8.314 J = 0.0821 atm dm 3 ) K -1 mol -1 Trouton s constant = 88 J K -1 mol -1 F = 96,500 Cmol -1. Question 1: Fill in the blanks

More information

Chapter 4. Chemical Quantities and Aqueous Reactions

Chapter 4. Chemical Quantities and Aqueous Reactions Chapter 4 Chemical Quantities and Aqueous Reactions Stoichiometry The study of the numerical relationship between chemical quantities in a chemical reaction Making Pizza The number of pizzas you can make

More information

P(N,V,T) = NRT V. = P(N,V,T) dv

P(N,V,T) = NRT V. = P(N,V,T) dv CHEM-443, Fall 2016, Section 010 Student Name Quiz 1 09/09/2016 Directions: Please answer each question to the best of your ability. Make sure your response is legible, precise, includes relevant dimensional

More information