Can one hear the shape of a drum?

Similar documents
1 PYTHAGORAS THEOREM 1. Given a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Linear Algebra Introduction

Lecture 1 - Introduction and Basic Facts about PDEs

Review of Gaussian Quadrature method

Comparing the Pre-image and Image of a Dilation

Introduction to Olympiad Inequalities

Section 4.4. Green s Theorem

Green s Theorem. (2x e y ) da. (2x e y ) dx dy. x 2 xe y. (1 e y ) dy. y=1. = y e y. y=0. = 2 e

Hyers-Ulam stability of Pielou logistic difference equation

Discrete Structures Lecture 11

Bases for Vector Spaces

Plotting Ordered Pairs Using Integers

MATH34032: Green s Functions, Integral Equations and the Calculus of Variations 1

Lesson 2.1 Inductive Reasoning

A Study on the Properties of Rational Triangles

Part 4. Integration (with Proofs)

Notes on length and conformal metrics

Mid-Term Examination - Spring 2014 Mathematical Programming with Applications to Economics Total Score: 45; Time: 3 hours

State space systems analysis (continued) Stability. A. Definitions A system is said to be Asymptotically Stable (AS) when it satisfies

Technische Universität München Winter term 2009/10 I7 Prof. J. Esparza / J. Křetínský / M. Luttenberger 11. Februar Solution

SECTION A STUDENT MATERIAL. Part 1. What and Why.?

GM1 Consolidation Worksheet

Trigonometry Revision Sheet Q5 of Paper 2

CHENG Chun Chor Litwin The Hong Kong Institute of Education

MAT 403 NOTES 4. f + f =

QUADRATIC EQUATION. Contents

April 8, 2017 Math 9. Geometry. Solving vector problems. Problem. Prove that if vectors and satisfy, then.

Part I: Study the theorem statement.

arxiv: v1 [math.ca] 21 Aug 2018

p-adic Egyptian Fractions

Lecture 6: Coding theory

LESSON 11: TRIANGLE FORMULAE

6.5 Improper integrals

Partial Differential Equations

VECTOR ALGEBRA. Syllabus :

Finite State Automata and Determinisation

Intermediate Math Circles Wednesday 17 October 2012 Geometry II: Side Lengths

5. Every rational number have either terminating or repeating (recurring) decimal representation.

How do we solve these things, especially when they get complicated? How do we know when a system has a solution, and when is it unique?

u(x, y, t) = T(t)Φ(x, y) 0. (THE EQUATIONS FOR PRODUCT SOLUTIONS) Plugging u = T(t)Φ(x, y) in (PDE)-(BC) we see: There is a constant λ such that

4.5 JACOBI ITERATION FOR FINDING EIGENVALUES OF A REAL SYMMETRIC MATRIX. be a real symmetric matrix. ; (where we choose θ π for.

Green function and Eigenfunctions

Matrix Algebra. Matrix Addition, Scalar Multiplication and Transposition. Linear Algebra I 24

T b a(f) [f ] +. P b a(f) = Conclude that if f is in AC then it is the difference of two monotone absolutely continuous functions.

Functions. mjarrar Watch this lecture and download the slides

INTEGRATION. 1 Integrals of Complex Valued functions of a REAL variable

Electromagnetism Notes, NYU Spring 2018

PAIR OF LINEAR EQUATIONS IN TWO VARIABLES

Chapter 1: Fundamentals

A Lower Bound for the Length of a Partial Transversal in a Latin Square, Revised Version

Numbers and indices. 1.1 Fractions. GCSE C Example 1. Handy hint. Key point

Chapter 2 Finite Automata

The Dirichlet Problem in a Two Dimensional Rectangle. Section 13.5

Proportions: A ratio is the quotient of two numbers. For example, 2 3

18.06 Problem Set 4 Due Wednesday, Oct. 11, 2006 at 4:00 p.m. in 2-106

Lesson 2.1 Inductive Reasoning

Solutions to Assignment 1

Farey Fractions. Rickard Fernström. U.U.D.M. Project Report 2017:24. Department of Mathematics Uppsala University

Linear Inequalities. Work Sheet 1

10 Elliptic equations

PYTHAGORAS THEOREM WHAT S IN CHAPTER 1? IN THIS CHAPTER YOU WILL:

Math 360: A primitive integral and elementary functions

( ) { } [ ] { } [ ) { } ( ] { }

Final Exam Review. [Top Bottom]dx =

Chapter 4 State-Space Planning

CS 373, Spring Solutions to Mock midterm 1 (Based on first midterm in CS 273, Fall 2008.)

x = a To determine the volume of the solid, we use a definite integral to sum the volumes of the slices as we let!x " 0 :

The Regulated and Riemann Integrals

03. Early Greeks & Aristotle

arxiv: v1 [math.gr] 11 Jan 2019

More Properties of the Riemann Integral

MTH 505: Number Theory Spring 2017

Vectors , (0,0). 5. A vector is commonly denoted by putting an arrow above its symbol, as in the picture above. Here are some 3-dimensional vectors:

DEFINITION The inner product of two functions f 1 and f 2 on an interval [a, b] is the number. ( f 1, f 2 ) b DEFINITION 11.1.

Quadratic Forms. Quadratic Forms

Bridging the gap: GCSE AS Level

Chapter 14. Matrix Representations of Linear Transformations

are coplanar. ˆ ˆ ˆ and iˆ

Section 1.3 Triangles

g i fφdx dx = x i i=1 is a Hilbert space. We shall, henceforth, abuse notation and write g i f(x) = f

Is there an easy way to find examples of such triples? Why yes! Just look at an ordinary multiplication table to find them!

Factorising FACTORISING.

Global alignment. Genome Rearrangements Finding preserved genes. Lecture 18

Project 6: Minigoals Towards Simplifying and Rewriting Expressions

SUMMER KNOWHOW STUDY AND LEARNING CENTRE

Math Lecture 23

(a) A partition P of [a, b] is a finite subset of [a, b] containing a and b. If Q is another partition and P Q, then Q is a refinement of P.

Coalgebra, Lecture 15: Equations for Deterministic Automata

Sturm-Liouville Theory

KENDRIYA VIDYALAYA IIT KANPUR HOME ASSIGNMENTS FOR SUMMER VACATIONS CLASS - XII MATHEMATICS (Relations and Functions & Binary Operations)

Lecture 3 ( ) (translated and slightly adapted from lecture notes by Martin Klazar)

A B= ( ) because from A to B is 3 right, 2 down.

Nondeterministic Automata vs Deterministic Automata

CS 573 Automata Theory and Formal Languages

Section 3.2 Maximum Principle and Uniqueness

Probability. b a b. a b 32.

The Riemann-Stieltjes Integral

u(t)dt + i a f(t)dt f(t) dt b f(t) dt (2) With this preliminary step in place, we are ready to define integration on a general curve in C.

ODE: Existence and Uniqueness of a Solution

MA10207B: ANALYSIS SECOND SEMESTER OUTLINE NOTES

Transcription:

Cn one her the shpe of drum? After M. K, C. Gordon, D. We, nd S. Wolpert Corentin Lén Università Degli Studi di Torino Diprtimento di Mtemti Giuseppe Peno UNITO Mthemtis Ph.D Seminrs Mondy 23 My 2016

Motivtion: the wve eqution Ω R 2 open, ounded, nd pieewise regulr open set (think of memrne fixed t its oundry). We ll it domin. z(t, x, y) vertil displement of the memrne t the point (x, y) Ω for the time t. Ω Ω z stisfies the wve eqution : with the Lplin defined y: 2 z t 2 (t, x, y) = 2 ( z)(t, x, y) for (x, y) Ω, nd the Dirihlet oundry ondition: ( f )(x, y) = 2 f x (x, y) + 2 f (x, y), 2 y 2 z(t, x, y) = 0 for (x, y) Ω. The onstnt depends on the physil properties of the memrne. We hose the units so tht = 1.

Motivtion: sttionry solutions Sttionry solutions, or pure tones: eh point of the memrne goes up nd down in n hrmoni motion. We therefore look for solutions of the form z(t, x, y) = u(x, y) os(ω(t t 0)). The funtion u must stisfy u = λu in Ω; (1) u = 0 on Ω. (2) with λ = ω 2. We sy tht λ is Dirihlet eigenvlue if there exists non-zero solution u of (1) nd (2). We ll u eigenfuntion ssoited with λ, nd we ll eigenspe ssoited with λ the vetor spe of ll eigenfuntions.

Motivtion: sttionry solutions Sttionry solutions, or pure tones: eh point of the memrne goes up nd down in n hrmoni motion. We therefore look for solutions of the form z(t, x, y) = u(x, y) os(ω(t t 0)). The funtion u must stisfy u = λu in Ω; (1) u = 0 on Ω. (2) with λ = ω 2. We sy tht λ is Dirihlet eigenvlue if there exists non-zero solution u of (1) nd (2). We ll u eigenfuntion ssoited with λ, nd we ll eigenspe ssoited with λ the vetor spe of ll eigenfuntions. If we look t memrnes tht re free to move up nd down t the oundry, we otin the Neumnn eigenvlues: u = µu in Ω; (3) u ν = 0 on Ω. (4)

Exmple of squre memrne We ssume Ω = (0, L) 2 with L > 0 (squre memrne of side L). For ny pir (m, n) of positive integers, ( mπx ) ( nπy ) u m,n(x, y) := sin sin L L is n eigenfuntion, ssoited to the eigenvlue λ m,n = π2 L 2 (m2 + n 2 ).

Exmple of squre memrne We ssume Ω = (0, L) 2 with L > 0 (squre memrne of side L). For ny pir (m, n) of positive integers, ( mπx ) ( nπy ) u m,n(x, y) := sin sin L L is n eigenfuntion, ssoited to the eigenvlue λ m,n = π2 L 2 (m2 + n 2 ). With some Fourier nlysis, we n show tht ny eigenvlue is of the form λ m,n for some (m, n) N 2 1, nd tht n eigenfuntion for the Dirihlet prolem ssoited with λ m,n is liner omintion of the funtions u p,q stisfying p 2 + q 2 = m 2 + n 2. In prtiulr, ll the eigenspes re finite dimensionl.

Exmple of squre memrne We ssume Ω = (0, L) 2 with L > 0 (squre memrne of side L). For ny pir (m, n) of positive integers, ( mπx ) ( nπy ) u m,n(x, y) := sin sin L L is n eigenfuntion, ssoited to the eigenvlue λ m,n = π2 L 2 (m2 + n 2 ). With some Fourier nlysis, we n show tht ny eigenvlue is of the form λ m,n for some (m, n) N 2 1, nd tht n eigenfuntion for the Dirihlet prolem ssoited with λ m,n is liner omintion of the funtions u p,q stisfying p 2 + q 2 = m 2 + n 2. In prtiulr, ll the eigenspes re finite dimensionl. For the Neumnn eigenvlue prolem, we find u m,n(x, y) := os with (m, n) N 2 0. The sme results re true. ( mπx ) ( nπy ) os nd µ m,n = π2 L L L 2 (m2 + n 2 )

Some exmples for 50 = 7 2 + 1 2 = 5 2 + 5 2 () m = 7 nd n = 1 () m = 5 nd n = 5 () Liner omintion

Generliztion Theorem For generl domin Ω, there exists ountly mny eigenvlues, nd eh of the ssoited eigenspe is finite dimensionl. If we write the eigenvlues λ 1(Ω) λ 2(Ω) λ k (Ω)..., repeting them ording to the dimensions of the eigenspes, we hve lim k + λ k (Ω) = +. We n find sequene of ssoited eigenfuntions u 1, u 2,..., u k,... suh tht every solution z of the wve eqution n e written z(t, x, y) = + k=1 A k os( λ k t + ϕ k )u k (x, y). We hve the sme result for the Neumnn eigenvlues, with the sequene (µ k (Ω)) k 1. The sequene of ll the eigenvlues for domin is lled its (Dirihlet or Neumnn) spetrum.

Diret nd onverse spetrl prolems We dedue from the preeding theorem tht One n see the sound of drum. In prtiulr, if two domins Ω 1 nd Ω 2 re isometri, tht is to sy if there exists n isometry τ : R 2 R 2 ( length-preserving trnsformtion) suh tht τ(ω 1) = Ω 2, then Ω 1 nd Ω 2 re (Dirihlet-)isospetrl: λ k (Ω 1) = λ k (Ω 2) for ll k 1.

Diret nd onverse spetrl prolems We dedue from the preeding theorem tht One n see the sound of drum. In prtiulr, if two domins Ω 1 nd Ω 2 re isometri, tht is to sy if there exists n isometry τ : R 2 R 2 ( length-preserving trnsformtion) suh tht τ(ω 1) = Ω 2, then Ω 1 nd Ω 2 re (Dirihlet-)isospetrl: λ k (Ω 1) = λ k (Ω 2) for ll k 1. In its 1966 pper, Mrk K sked the onverse question: if we hve two domins Ω 1 nd Ω 2 tht re Dirihlet-isospetrl, re they isometri? This would men tht the spetrum of domin determines its shpe.

Diret nd onverse spetrl prolems We dedue from the preeding theorem tht One n see the sound of drum. In prtiulr, if two domins Ω 1 nd Ω 2 re isometri, tht is to sy if there exists n isometry τ : R 2 R 2 ( length-preserving trnsformtion) suh tht τ(ω 1) = Ω 2, then Ω 1 nd Ω 2 re (Dirihlet-)isospetrl: λ k (Ω 1) = λ k (Ω 2) for ll k 1. In its 1966 pper, Mrk K sked the onverse question: if we hve two domins Ω 1 nd Ω 2 tht re Dirihlet-isospetrl, re they isometri? This would men tht the spetrum of domin determines its shpe. In other words: Cn one her the shpe of drum?

Weyl s lw We define the ounting funtions ssoited with domin: N D (λ, Ω) := {k : λ k (Ω) < λ}; N N (λ, Ω) := {k : µ k (Ω) < λ}.

Weyl s lw We define the ounting funtions ssoited with domin: In prtiulr, N D (λ, (0, L) 2 ) = N D (λ, Ω) := {k : λ k (Ω) < λ}; N N (λ, Ω) := {k : µ k (Ω) < λ}. { (m, n) N 2 1 : { N N (λ, (0, L) 2 ) = (m, n) N 2 0 : } π 2 L 2 (m2 + n 2 ) < λ ; } π 2 L 2 (m2 + n 2 ) < λ ;

Weyl s lw We define the ounting funtions ssoited with domin: In prtiulr, N D (λ, (0, L) 2 ) = N D (λ, Ω) := {k : λ k (Ω) < λ}; N N (λ, Ω) := {k : µ k (Ω) < λ}. { (m, n) N 2 1 : { N N (λ, (0, L) 2 ) = (m, n) N 2 0 : In tht se we find, when λ +, } π 2 L 2 (m2 + n 2 ) < λ ; } π 2 L 2 (m2 + n 2 ) < λ ; N D (λ, (0, L) 2 ) N N (λ, (0, L) 2 ) L 2 4π λ = Are(Ω) λ. 4π λl/π

Weyl s lw We define the ounting funtions ssoited with domin: In prtiulr, N D (λ, (0, L) 2 ) = N D (λ, Ω) := {k : λ k (Ω) < λ}; N N (λ, Ω) := {k : µ k (Ω) < λ}. { (m, n) N 2 1 : { N N (λ, (0, L) 2 ) = (m, n) N 2 0 : In tht se we find, when λ +, N D (λ, (0, L) 2 ) N N (λ, (0, L) 2 ) L 2 4π λ = Are(Ω) λ. 4π Theorem (Hermnn Weyl, 1911) For generl domin, } π 2 L 2 (m2 + n 2 ) < λ ; } π 2 L 2 (m2 + n 2 ) < λ λl/π N D (λ, Ω) N N (λ, Ω) Are(Ω) λ when λ +. 4π ;

Proof of Weyl s lw : si priniples We now prove Weyl s lw for the Dirihlet eigenvlues. Disjoint union of domins If Ω = Ω Ω, the union eing disjoint (λ k (Ω)) k 1 = (λ k (Ω )) k 1 (λ k (Ω )) k 1 (µ k (Ω)) k 1 = (µ k (Ω )) k 1 (µ k (Ω )) k 1 (with repetition), nd therefore N D/N (λ, Ω) = N D/N (λ, Ω ) + N D/N (λ, Ω ).

Proof of Weyl s lw : si priniples We now prove Weyl s lw for the Dirihlet eigenvlues. Disjoint union of domins If Ω = Ω Ω, the union eing disjoint (λ k (Ω)) k 1 = (λ k (Ω )) k 1 (λ k (Ω )) k 1 (µ k (Ω)) k 1 = (µ k (Ω )) k 1 (µ k (Ω )) k 1 (with repetition), nd therefore N D/N (λ, Ω) = N D/N (λ, Ω ) + N D/N (λ, Ω ). Monotoniity priniple (Rihrd Cournt) If we dd Dirihlet ondition, ll the eigenvlues go up, nd therefore the ounting funtion goes down. If we reple Dirihlet ondition y Neumnn ondition, or if we dd Neumnn ondition, ll the eigenvlues go down, nd therefore the ounting funtion goes up.

Proof of Weyl s lw: inner nd outer pproximtion For given ε > 0, we find l > 0, Ω i nd Ω o suh tht Ω i is the reunion of n i squres of side l nd Ω 0 is the reunion of n o squres of side l; Ω i Ω Ω o; Are(Ω i ) (1 ε)are(ω) nd Are(Ω o) (1 + ε)are(ω). N D (λ, Ω) N D (λ, Ω i ) = n i N(λ, (0, l) 2 ) n il 2 4π (1 ε)are(ω) λ λ 4π

Proof of Weyl s lw: Dirihlet-Neumnn rketing For the outer pproximtion, we put Neumnn oundry ondition on the oundry of the squres. N D (λ, Ω) N N (λ, Ω o) = n on N (λ, (0, l) 2 ) nol2 4π We onlude tht (1 ε) Ω 4π N D (λ, Ω) N D (λ, Ω) lim inf lim sup λ + λ λ + λ We mke ε 0 nd we otin Weyl s lw. (1 + ε) Ω λ λ 4π (1 + ε) Ω. 4π

The Ryleigh-Fer-Krhn inequlity I Lord Ryleigh, 1877, in The theory of sound, volume I Of ll memrnes of equl re tht of irulr form s the grvest pith.

The Ryleigh-Fer-Krhn inequlity II Theorem (Georg Fer 1923, Edgr Krhn 1925-1926) If D Ω is disk with the sme re s the domin Ω, λ 1(D Ω ) λ 1(Ω), with equlity if, nd only if, Ω is isometri to D Ω. This inequlity n e dedued from the isoperimetri inequlity. Consequene: More preise formultion: One n her the shpe of irulr drum. Corollry (Spetrl rigidity of the disk) If domin Ω s the sme eigenvlues s disk D, then Ω is isometri to D.

One nnot her the shpe of drum Conjeture (Mrk K, 1966) One nnot her the shpe of drum. Theorem (Crolyn Gordon, Dvid We, nd Sott Wolpert, 1992) There exists pirs of domins tht re Dirihlet-isospetrl (i.e. λ k (Ω 1) = λ k (Ω 2) for ll k 1), nd lso Neumnn-isopetrl (i.e. µ k (Ω 1) = µ k (Ω 2) for ll k 1). A lot of different exmples hve een found sine then. We will study n exmple due to Peter Buser, John Conwy, nd Peter Doyle (1994), ut the tehniques re very generl.

Building lok C 75 60 45 A B

The reflexion priniple We reflet the tringle with respet to side. If u stisfies u = λu in the tringle, nd Dirihlet oundry ondition on the side, the ntisymmetri extension of u stisfies u = λu in the symmetrized domin. u u σ

The two domins 1 2 3 4 5 6 7 1 2 3 4 5 6 7 Ω 1 Ω 2

Deompositions nd trnsplnttions If u is funtion on Ω 1, we note u i, for i {1,..., 7}, the restrition of u to the tringle n i. We deompose in the sme wy ny funtion v on Ω 2 We n write this U = u 1 u 2 u 3 u 4 u 5 u 6 u 7 nd V = v 1 v 2 v 3 v 4 v 5 v 6 v 7. For ll i, j {1,..., 7}, there is unique isometry τ i,j of the tringle n i in Ω 1 to the tringle n j in Ω 2. There is unique trnsplnttion of u i to the tringle n j: u i τ 1 i,j. The ide of the proof is to strt from n eigenfuntion u in Ω 1, ssoited with λ, nd to onstrut n eigenfuntion v on Ω 2, ssoited with λ, using the trnsplnttions of the funtions u i.

Constrution of the glol trnsplnttion mpping 6 3 4 1 5 2 7 2 Ω 1 Ω 2

Constrution of the glol trnsplnttion mpping 6 3 4 1 5 2 7 2 1 Ω 1 Ω 2

Constrution of the glol trnsplnttion mpping 1 2 3 4 5 6 7 2 1 2 Ω 1 Ω 2

Constrution of the glol trnsplnttion mpping 1 2 3 4 5 6 7 2 1 3 2 Ω 1 Ω 2

Constrution of the glol trnsplnttion mpping 1 2 3 4 5 6 7 2 1 3 1 2 Ω 1 Ω 2

Constrution of the glol trnsplnttion mpping 1 2 3 4 5 6 7 2 +3 1 3 1 2 Ω 1 Ω 2

Constrution of the glol trnsplnttion mpping 1 2 3 4 5 6 7 2 +3 +4 1 3 1 2 Ω 1 Ω 2

Constrution of the glol trnsplnttion mpping 6 3 +6 7 3 4 1 2 7 5 2 5 7 1 4 +7 2 +3 +4 1 3 +5 1 2 +6 4 5 6 Ω 1 Ω 2

Mtrix representtion The glol trnsplnttion mpping n e represented y mtrix T suh tht V = TU. Here we hve: 0 1 1 1 0 0 0 1 0 1 0 1 0 0 1 0 0 1 0 0 1 T = 1 1 0 0 0 1 0. 0 0 1 0 0 1 1 0 1 0 0 1 0 1 0 0 0 1 1 1 0 This mtrix is invertile, so tht U = T 1 V. We find: 4 8 8 8 4 4 4 8 4 4 8 4 8 4 T 1 = 1 8 8 4 4 8 4 4 24 8 4 8 4 4 4 8. 4 8 4 4 4 8 8 4 4 4 8 8 4 8 4 4 8 4 8 8 4

End of the proof The mtrix representtion shows tht the glol trnsplnttion mpping is n invertile liner mpping. By onstrution, it sends n eigenspe for the Dirihlet eigenvlue prolem in Ω 1 into n eigenspe for the Dirihlet eigenvlue prolem in Ω 2. Proposition Any Dirihlet eigenvlue for the domin Ω 1 is lso Dirihlet eigenvlue for the domin Ω 2, with greter or equl multipliity. Using the trnsplnttion mpping defined y the mtrix T 1, we n exhnge the role of Ω 1 nd Ω 2. We onlude tht Ω 1 nd Ω 2 hve the sme Dirihlet eigenvlues, with the sme multipliities, tht is to sy they re Dirihlet-isospetrl. In the sme wy, we ould prove tht Ω 1 nd Ω 2 re Neumnn-isospetrl.

Open prolems Are there sets of more thn two isospetrl domins?

Open prolems Are there sets of more thn two isospetrl domins? Are there smooth isospetrl domins?

Open prolems Are there sets of more thn two isospetrl domins? Are there smooth isospetrl domins? Are there simply onneted isospetrl domins?

Open prolems Are there sets of more thn two isospetrl domins? Are there smooth isospetrl domins? Are there simply onneted isospetrl domins? Are there onvex isospetrl domins? The nswer to the lst question is positive if we llow mixed oundry onditions (Virginie Bonnillie-Noël, Bernrd Helffer, Thoms Hoffmnn-Ostenhof, 2009). Wht out the Dirihlet ondition?

Grzie per l ttenzione!