Div. 1 Div. 2 Div. 3 Div.4 8:30 am 9:30 pm 12:30 pm 3:30 pm Han Xu Ruan Pan

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Write Down Your NAME, Last First Circle Your DIVISION Div. 1 Div. 2 Div. 3 Div.4 8:30 am 9:30 pm 12:30 pm 3:30 pm Han Xu Ruan Pan ME315 - Heat and Mass Transfer School of Mechanical Engineering Purdue University Final Exam December 13, 2017 Read Instructions Carefully: Write your name on each page and circle your division number. Equation sheet and tables are attached to this exam. Three pages of US letter-size crib sheets are allowed. No books, notes, and other materials are allowed. ME Exam Calculator Policy is enforced. Only TI-30XIIS and TI-30XA are allowed. Power off all other digital devices, such as computer/tablet/phone and smart watch/glasses. Keep all the pages in order. You are asked to write your assumptions and answers to sub-problems in designated areas. Write on front side of the page only. If needed, you can insert extra pages but mark this clearly in the designated areas. Performance 1 25 2 25 3 25 4 25 Total 100

Circle your division: 1 2 3 4 Name Problem 1 [25 points] (a) [6 points] Consider a system consisting of two solid slabs, each of thickness L. The first slab is insulated on the left side, and a uniform volumetric heat generation at a rate (qq ) occurs in it. The thermal conductivity of the second slab is twice that of the thermal conductivity of the first slab. Assume one-dimensional heat conduction, steady-state conditions, and perfect contact between the two slabs. Sketch the temperature distribution through the two slabs, labeling correctly important slopes. L L k k 1 2 T q x k = 2k 2 1 x Page 2 of 5

Circle your division: 1 2 3 4 Name Problem 1 continued (b) [6 points] Two rectangular fins built from the same material are designed such that they have the same cross sectional area but different aspect ratio. Fin 1 has w1=10 cm and t1=2 mm, and Fin 2 has w2=5 cm and t2=4 mm. Both fins have the same length L and can be assumed as long fins. Apparently both fins use the same amount of materials to make, but which fin design is more effective in enhancing heat transfer? Justify your answer. Page 3 of 5

Circle your division: 1 2 3 4 Name Problem 1 continued (c) [7 points] A cup of hot coffee is initially at a uniform temperature of 80 C, while the ambient air is at a constant temperature of 25 C. Assume the paper cup to be a cylinder with diameter of 6 cm and height of 10cm, and neglect heat transfer from the top and bottom surfaces. The convective heat transfer coefficient h outside of the cup is 10W/m 2 -K. The thermal conductivity of coffee can be assumed as that of water, 0.67W/m-K. The conduction resistance of the cup wall can be neglected. Can you assume the temperature of the coffee to be uniform as it cools down? Justify your answer. Page 4 of 5

Circle your division: 1 2 3 4 Name Problem 1 continued (d) [6 points] Water is supplied at a flow rate m and temperature Ti to a circular tube of diameter D. Different boundary conditions are applied at different locations along the length of the tube: Section A: uniform heat flux, q w Section B: insulated Section C: uniform wall temperature Tw with a value equal to the wall temperature at the end of Section A Qualitatively sketch the mean water temperature along the tube. Describe the key features of your curves of each section. LA LB LC m D xo x1 x2 section A section B section C x3 T x Page 5 of 5

Problem 3 [25 points] Inside a large room, a small thin flat plate is fully coated with an opaque layer of paint, horizontally placed under direct sun light through a small open window. The backside of the plate is thermally insulated. The sun is known to have a surface temperature of Tsun=5800K and the solar irradiation onto the plate surface is known as GS=500W/m 2. The ambient air temperature is T =300K with a natural convective heat transfer coefficient of h=10w/(m 2 K). The room wall also has a temperature of Tsurr=300K and an emissivity of εsurr=0.5. At a certain time instant, the plate has at a uniform temperature of TS=320K. The paint surface is diffuse and its spectral emissivity is known to be: εε λλ = 0.2 ffffff 0 λλ 1 μμμμ. 0.8 ffffff λλ > 1 μμμμ (a) Calculate the total surface emissivity (ε) of the plate. (b) Calculate the total absorptivity of the plate to solar radiation (αs) and the total absorptivity of the plate to radiation from the wall of the room (αsurr). (c) Calculate the total irradiation (G) onto the plate and the total radiosity (J) of the plate (W/m 2 ). (d) Calculate the net heat flux of the plate at this moment (W/m 2 ). Blackbody Radiation Functions (Table 12.2 from Textbook)

Circle your division: 1 2 3 4 Name Problem 3 continued List your assumptions below. [3 pts] No conductions Very large room with isothermal surface temperature Constant parameters Uniform irradiation and radiosity for the plate surface Uniform plate temperature, etc. (Note: It is not steady state. Not grey surfaces. ) Start you answer to part (a) here. [5 pts] ε = ε F + ε (1 F ) = 0.2 0 + 0.8 1 = 0.8 T (0 1 um) (0 1 um)@320 K (1 um ) (0 1 um)@320k Start you answer to part (b) here. [6 pts] α = α F + α (1 F ) = 0.2 0.72 + 0.8 0.28 = 0.368 ; S (0 1 um) (0 1 um)@5800 K (1 um ) (0 1 um)@5800k α = α F + α (1 F ) = 0.2 0 + 0.8 1 = 0.8 ; surr (0 1 um) (0 1 um)@300 K (1 um ) (0 1 um)@300k Page 2 of 3

Circle your division: 1 2 3 4 Name Problem 3 continued Start your answer to part 3(c) here: [6 pts] W G = G + G = 500 + E (300 K) = 959 S Surr b 2 m ; J = E+ ρ G + ρ G = ε E ( T ) + (1 ε ) G + (1 ε ) G S S Surr Surr T b S S S Surr Surr = 0.8 E (320 K) + (1 0.368) 500 + (1 0.8) E (300 K) b W = 883 2 m b Start your answer to part 3(d) here: [5 pts] The net heat flux out of the plate: net W m. ( ) ( S ) ( 883 959) 10 (320 300) 124 2 q = J G + ht T = + = Page 3 of 3