RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions NAONAL SANDARD EXAMNAON N PHYSCS - 5 SOLUONS
RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions NSEP SOLUONS (PHYSCS) CODE - P 5 ANSWER KEY & SOLUONS. (C). (). (D). (C) 5. () 6. (C) 7. () 8. () 9. (D). (D). (A). (A). (). () 5. (A) 6. (D) 7. (A) 8. (A) 9. (D). (C). (C). (). (C). (D) 5. () 6. () 7. (C) 8. (C) 9. (A). (C). (). (C). (C). (C) 5. (All Options ae wong) 6. (A) 7. () 8. (A) 9. (C). (C). (A). (C). (D). (C) 5. () 6. (C) 7. (C) 8. () 9. (D) 5. () 5. (A) 5. (C) 5. () 5. (A) 55. () 56. (D) 57. (A) 58. (D) 59. (D) 6. (D) 6. (A, ) 6. (A, D) 6. (A, C, D) 6. (A, C, D) 65. (C) 66. (A,, C, D) 67. (A, C) 68. (A, C) 69. (A,, C, D) 7. (, C)
. (C) d log RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions log SOLUONS. () Dimension fomula de is same is cuent density. dt. (D) m m x m Gm m m x Gm x x Gm m mo xm m m m Gm m m G m m
RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions. (C) 5. () N m R sin mg s mg mg m R sin eff s g g R sin eff sin cos g g R cos eff k g e R cos y x x dy x dx at, dy dx tan tan 7.56 7 Resin m Resin 6. (C) dy dx V Vx Vy Vx 7. () Vy V hust acting on the small element of width dx df xg P dx atm gx F df Patm x g F Patm P g hust at bottom atm x dx
P g g atm RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions g Patm g Patm g g g g 5 5 8. () Equivalent length of a physical pendulum mcm moment of inetia of a disc about it axis cm M R R So moment of inetia about oute adius R M cm M R R M R M cm R R M R R MR M R R R R R R R R R R R R 5
9. (D) Final length of Aluminium RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions 6 A 5 6 5 A A R t t ac angle R A R t R t 6 6 9 H R t R t 5 5 5 5 R R t R 5R t 5 t R 5R t 5t R t t R..cm. (D) g g g n m mg mg g m mg mg g g 6
RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions n m. g g..8.8.8.8.8.8.6.8. (A) N m cos mg sin F m mg cos tan. g mg m sin m mg sin F cos v' mv mg sin N cos mv mv mg sin mg cos cos cos v' v v tan. g 7
RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions v' v v.,. g.8 g g g sin g cos.8g cos.8g cos sin cos.8 cos.8cos tan.8.8..8.8.8.6.6.55.8. (A) Foce between two magnetic dipoles C F H C nitial C Final H mg mg 5 56..96 65. () Electic field at a distance E Foce at a distance x g F F q x wok done to displaced fom q x dx 8
. () q n RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions q n wok done = change in K.E. q n q n cos m V 5 m m' g m' g mg m' m m' mass of scale m mass of body 5 m' g m mg vg V g V g m' g V g V g m' g V m V 6 mg 9
5. (A) Heat absobed = Heat ejected. 6. (D) S s Ss.5 RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions 5.5.5 S cos s c..5kj Kg k V V avs ms R M R M V P 7. (A) 8R M V V V ms avs p unit 6 J 6 unit 6 J fo one yea 6 65 m6 m 56. JKg efficiency of engine M 5 6 8 5 So the total coal eq. 5 56.5.65
RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions 8. (A) 6 6 Voltage (V) 5 volt V volt V R e R e V R e R e R e Re R e R e R e 5 5 5 A divisions A A.A divisions division division 9. (D).5 V.5 V = m.5 V.5 V t q CE e RC q t E e c RC t.5.5 e RC t e RC t e RC t n RC t RC n C=F.5.5 5 nitial i 6
. (C). (C) + + + + + + + + + + + + + + + RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions + + + + + + + + + + + c change gets non-unifomly distibuted on the inne suface of the shell. g g. t t t. t 6 6 t t. t 9.97999 6.5. () Ultasonic is not connected. (C) M M cm H magnet M magnet cm magnetcm H 8 magnet 8 H eath magnet Noth N S S
RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions. (D) 5 5 velocity of image ˆ ˆ 5 i j k 5 5 5 ˆ i ˆj k 5 5 5. () cos cos cos 6.9 6. () Glass =.5 t n =.8 7. (C) 55 t 99.67 nm.8 9 t 99.67 m t.m 6.99 m K M L L Souce Capacitance doesnot coespond to sping constant K.
8. (C) 9. (A) souce Rms RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions V 5 5 9 Vsouce 5.8 ms Vsouce Vms.5.8 max 7.6 t RC q CE e RC RC. 6 q 6.5 e. e q 5 q q t e C C RC V 5 6.88 t e 6. t ms. (C) ntenal point R Extenal point. () Coil A Coil f = 5 = ma V = 5 volt z V souce dz V
RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions d V V souce V V souce Mi sin wt d E M dt iw cos wt. (C) the second case the two coils ae in phase opposition and they have unequal numbe of tuns.. (C) Nstable N N od N pessue e t t ln ln ln t t t ln t e t ln ln t t e / / / t 57 6. (C) uth table A Y t will at like NAND gate. 5. No Matching ma ma a a m m a 5
RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions ma ma ma a a m ma ma ma ma 6. (A) Let e = coefficient of estitution. (consevation of enegy) mgh m.6 u 7. e 7. collision h = 6cm v h m mgh h e 7. e.6 6 8 otal distance h e h e h e h e h 6 8.6 e e e e....6 G. P. e.6 e m e.6 e.6.6 % loss in K.E in st impact m u v mu u 6%.8 u 6
RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions 7. () g F g m g d, whee A and ae constant as i incease, A - i decease and hence incease. A i Coect option is () 8. (A) hee is no diffeence in thei fequencies. 9. (C) hc Fo cut off KEe evnm 8eV 8 nm. nm. (C) Equation of the seconday cell must be less than that of the pimay cell.. (A) nsulato. (C) R P. G. L R L.5.6 b R 5 R.. (D) oth ae unimpotant with espects to the pote timete. 7
RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions. (C) Cuent emains same thougouts the wie. 5. () P has longe jockey distance. 6. (C) t is geate than the jockey will shown deflection. Si,ilaly if R is lage cuent will not pass though the pimay cicuit. 7. (C) Fo cm deviation the voltage changes by V.6 V 6 R 6A 8. () Enegy tansfe max m when fequency matches. 9. (D) Resonance occus in max m enegy tansfe and also in same phase. 5. () Same Fequency (F ). 5. (A) his pendulum having max m amplitude has same Fequency and is in phase max m %. Enegy tansfe occus both ae exteme positions PE PE dive K A K A M W A M W A M M8.6 M M 8.6.58M M.5 M M K MW 8
RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions 5. (C) L g ln ln ln L ln g D DL L L L L g D 5. () Damped oscillations 5. (A) A A e t ln A ln A t L g g 55. () Resistive foce Velocity fom Stokes Law. 56. (D) m f So, V So, f 5 6 f New position u = cm So, 5 V ' 6 u ' 6 V ' So vitual lage at 6 cm fom lens. 9
RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions 57. (A) Focal length of Concave lens = cm Focal length of Convex lens = cm cm f f f eq now, u cm v? feq cm m v v 6 v cm 58. (D) f = f cm 7 cm v u f u cm cm v v 8 v v fo Concave lens : u v? f v v V 7 So eal & 57 cm fom object. cm
59. (D) fo lens. Case : in ai f f f eq RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions f eq cl [Constants]. [Constants] f eq. [Constants] now magnitude in same but sign changes. So,. el..8 M el.8 M.5 6. (D) When sunlight is coming fo suface. [Refaction] V V fom nd suface f R R R R cm V V V 7
V 7 RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions V 7 7 V cm a fo light going fom wate to ai fo suface : / V V 7 Refaction fom suface b V b 7 b 7 7 b 8cm So option (D) 6. (A, ) nitial c.m. (,) So, x cm m mx 5m m mx m m m m 5m m mx x Same y y cm So initial, Final c.m. (, ) x cm m my m m m m m mx' 5m m m mx' x' y cm m my ' y ' 5m (,) m m m (,)
final, P,, P RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions 5 displacement P P i ˆ So magnitude 5 unit Paallel to x axis. Option A, 6. (A, D) Velocity of when it eaches A. V u as V.6 u m / sec a m / sec g.6 V.6 V.6 m / sec kg V = m/sec kg 6 cm A now collision V V So momentum consevation V V V ' V ' A A A.6 m / sec befoecollision m / sec VA ' afte collision V '.6 V ' V ' A Vsap VA ' V ' e V V V V '. VA A app A. '. m / sec So V '. m / sec So Rebounds V A ' V '.6 V ' V '.6 A
Distance tavelled by (A) RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions () a g m / sec a m / sec VA So,. m / sec V. d V A a d..6 d.m d.m So sepaation =. +. =.5 M = 5 cm So option A, D 6. (A, C, D) So, Mg ma mg ma a g upwad Option (A) toque about cente of disc. R R mg mg R R mgr mr g R mgr option dl mgr dt option - D Mg Mg 6. (A, C, D) oi d. ˆ 8 o A J J. ˆ 8 C J J
6 RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions 8 i i 8 D i i A C option A 8 8 A i J 5 8 i J 8 A 8 A C D i So, (A,C,D) Option C 65. (C) V = m/sec V =.m/sec - 5 mm - - = =.5 m = = m AV = AV V n V n V V.5 n 5 Plants Option -C Fo a plant wate volume AV t hou 7sec. 7 7 6 M 6 5.6 M 5 V.5 M m V t.5.5 t 5
66. (A,, C, D) he cicuit is half wave ectifie. RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions Only Half wave will pass though. So, (,C) Max output voltage will be V 67. (A, C) Fo He oiling poit of wate 7k oiling poit of wate N =? So, P P 7 5 7 7.6K 5 Vapou pessue of He & O will be diffeent at same tempeatue so O will not give same esult. 68. (A, C) fo wate is inceased when tempweatue is deceased density so density so so speed So speed by ight in medium will decease. A & C 69. (A,, C, D) Example of faunhofte diffaction as the sceen is so fa so all A,,C,D. 7. (, C) at y ymax K. E P. E max y y K. E max, PE So C 6