PART- A 1. (C) 2. (D) 3. (D) 4. (B) 5. (D) 6. (C) 7. (D) 8. (B) 9. (D) 10. (B) 11. (B) 12. (B) 13. (A) 14. (D)

Size: px
Start display at page:

Download "PART- A 1. (C) 2. (D) 3. (D) 4. (B) 5. (D) 6. (C) 7. (D) 8. (B) 9. (D) 10. (B) 11. (B) 12. (B) 13. (A) 14. (D)"

Transcription

1 PRACTICE TEST-4 KISHORE VAIGYANIK PROTSAHAN YOJANA (KVPY) 7 STREAM (SA)_ DATE : -9-7 ANSWER KEY PART- A. (C). (D) 3. (D) 4. (B) 5. (D) 6. (C) 7. (D) 8. (B) 9. (D). (B). (B). (B) 3. (A) 4. (D) 5. (C) 6. (B) 7. (A) 8. (A) 9. (D). (C). (D). (B) 3. (A) 4. (C) 5. (B) 6. (D) 7. (D) 8. (D) 9. (A) 3. (A) 3. (D) 3. (A) 33. (A) 34. (D) 35. (C) 36. (D) 37. (B) 38. (C) 39. (D) 4. (D) 4. (B) 4. (A) 43. (D) 44. (D) 45. (A) 46. (C) 47. (B) 48. (C) 49. (B) 5. (C) 5. (D) 5. (B) 53. (C) 54. (B) 55. (D) 56. (C) 57. (D) 58. (D) 59. (A) 6. (B) PART- B 6. (A) 6. (A) 63. (B) 64. (D) 65. (D) 66. (A) 67. (C) 68. (C) 69. (C) 7. (B) 7. (B) 7. (A) 73. (D) 74. (D) 75. (C) 76. (B) 77. (A) 78. (B) 79. (A) 8. (D) PAGE -

2 HINTS & SOLUTIONS PART- A MATHEMATICS. Note that this sum can be zeo only when n is of the fom 4k o 4K + 3 othewise sum is non-zeo. y x( 5, 5) 9 pais y x <3 8pais 55 pais y x <7 8pais y 3 x <7 pais 3. {D, E, F} {6, 4, } o {8, 6, 4} o {,, 4} {G, H, I, J} {7, 5, 3, } o {9, 7, 5, 3} {A, B, C} {, 8, 9} o {, 8, } o {,, } A + B + C 9 A 8, B, C 4. y k a(x b) eflecting about y k make it y k a(x b) thee (a + b + c + d + e + f) k 5. In witing fist hunded natual numbes each non-zeo digit is witten times, hence E() ( ) ( ) 5 () ()! 5.(5)! f(x) 5 5 g(x) M, N 5 P, Q 8. (a + bx + cx ) n eplacing x by x n x we get n b c a x x n x (ax + bx + c) n n x Hence coefficient of x coefficient of x n a c n PAGE -

3 9. Root the equation ae positive (as sum & poduct both ae positive) Let p, p, q N and g.c.d(p,q), be a oot of this equation q So we have ap bpq + aq p divides a and q also divides a (p, q) (, a), (a, ), (a, a) (, ) p q a o (as is not a oot) a Hence b a a + a b a + b is even (D). th n(n ) n(n ) tem of the sequence is and est all ae 's hence 34 n(n + ) 468 Hence Till fist (5) th tems thee ae 49 numbe of 's and 76 numbe of 's post this till (34) th tems all ae 's. Hence sum 49 + (85) a. S, also a S 4 ( ) (If <, S <,hence > & of couse < ).. Requied aea 4 (aea in fist quadant) {by symmety} In fist quadant equation is x + y Aea 4 Hence equied ae ( + ) 3. Given sum is coefficient of x in ( x) x 4. ab Given sum is coefficient of x in Hence if it is zeo then is odd. q a b b a (ab ) 9 ab 4 4 (x ) x (p + ) (q + ) ( + ) (pq + pq + q + p) + (p + q + ) + Hence equied (p + ) (q + ) ( + ),which is maximum when p, q, ae as close to each othe as possible two if them 3 & one is 4. Hence equied PAGE - 3

4 PHYSICS 6. Released enegy MeV. 7. Q measues acceleation of P to be zeo. Q measues velocity of P, i.e., to be constant. Hence Q obseves P to move along staight line. Fo P and Q to collide Q should obseve P to move along line PQ. Hence PQ should not otate. 8. x A cos wt (as it stats fom est at t ) A a A cos w...() A (a + b) Acosw...() Solving () and () fo A we get A a 3a b 9. Resultant Displacement y y + y fo y to be zeo (x 3t) (x + 3t 6) on solving (x 3 ) (t ) Theefoe, at x 3, esultant displacement is zeo fo all values of t.. v A cos37º v A 5 m/s and v A cos37º v B cos53º v B m/s. PAGE - 4

5 . tansitional k.e. otational k.e. mv I V Impulse eq. Fdt mv...() Fhdt mr...(3) 5 R dividing () and (3) h...(4) 5 V 5 R... () Solving () and (4) h R 5. Sping on the left of the block ae in seies, hence thee equivalent is K (K) (K) K K K Spings on the ight of the block ae in paallel, hence thee equivalent is K K + K 3K Now again both K and K ae in paallel K eq. K + K K + 3K 4K Hence, fequency is f 3. As p V T V 3 K eq M 4K M i.e. if tempeatue inceases, volume also inceases hence w.d. will be positive. 4. Fom (i) A and C both ae chaged, eithe positively o negatively. Fom (ii) Both D and E has no chage and fom (iii), A is positively chaged. Theefoe fom (i), B is negatively chaged. 5. Figue shows one of the legs of the mosquito landing upon the wate suface. Theefoe, T. a 8 W weight of the mosquito. 6. Given cicuit is equivalent to solve it can be calculated 7. It is clea fom the figue that acceleation does not change sign, i.e., does not change in diection. Only the magnitude of acceleation fist inceases and then deceases. Velocity keeps on inceasing. Hence displacement also keeps on inceasing. PAGE - 5

6 8. BE m.c [( ] u.c MeV 8.4 MeV. 9. v Ah dv v dh da dh A h t s t s A 5 /ºC. 3. Let S, L be the density of silve and liquid. Also m and V be the mass and volume of silve block. Tension in sting mg bouyant foce T S Vg L Vg ( S L ) Vg Also V m s T s S s mg (.7) N. CHEMISTRY 3. (4a + 96)g X 4 O 6 4a g X 4a g X 4 O 6 has g X 4a 96 4a 5.7 4a 96 a (B) All molecules do not have same speed thee is maxwell distibution of molecula speeds. (C) Vapou pessue is constant at constant tempeatue fo a substance. (D) Z V m,eal V,ideal m so V m. eal <.4 L m V,eal (.4L) (at STP) 34. E 3 E + E Theefoe, 3 Also, hc 3 hc hc + Thus, 3 So, 3 PAGE - 6

7 35. K.E. ev h h mev mev 36. NO sp NO 3 sp NO sp NO sp 37. A + B C + D t t eq x x + x + x ( x) ( x) x x + x x x 9 x 9 [D] + 9 [D] Li + O (g) Li O (excess) Na + O (g) Na O (excess) K + O (g) KO (excess) 39. Alcohols with fomula C4HO ae - n-butaniol o sec-butanol popan--ol 4. 3-Bomocyclohexa-,5-diene-,4-dicaboxylic acid 4. Only Ag +, Zn + and 3 Ga has the configuation s p 6 d (pseudo inet gas), Sn + has 8 + electon configuation, wheeas all othe K +, Mg +, S, O, N 3 and Cl has octet configuation. PAGE - 7

8 4. M f M V % w/v n L solute added V L M GMM solute.5..5 M %. Stength (g/l) M GMM solute g/l Mole faction of uea cannot be calculated as final density of the solution is not given. 43. Both OH and O(CH 3 ) has sp 3 hybidised "O" atom. Both OH and O(CH 3 ) has two lone pais but bond angle COC in O(CH 3 ) is geate than OH due to steic epulsion between two CH 3 goups. 45. CaC + H 3 O + Ca(OH) + C H (alkyne) Mg C + H O Mg(OH) + CH 4 Al 4 C 3 + H 3 O + Al(OH) 3 + CH 4 Be C + H 3 O+ Be(OH) + CH 4 PART- B MATHEMATICS 6. Let b n a n b n (b n ) (a n ) ( + b ) ( + b ) ( + b ).. i ( + b ) ( + b ) ( + b 4 )... n (b ) b (whee n tends to infinity) 3 6. Poduct of imaginay oots must also be intege (A) 63. y 4 x y 4 x So 4 x + z z 4 x 3 x 4 x 4 x 3 x + x 7 3 (4x x + 3 x) 3 7x (3 x) x 3x + 9 3x x 7x 4x x + 9 (x 3) x 3, y 5, z 5 3 xyz PAGE - 8

9 64. (a + b), (b + c), (c + d) ae in A.P. i.e. b + c (a + c) + (b + d) c b d (a b + c) If a + c b a, b, c, d ae in A.P. Numbe ae (34, 345,...,6789) o (357, 468, 3579) o 9 numbes If a + c b & c b d c 6 c 6 b a 5 & b + d (not possible) c 7 b a 6 & b + d 4 Numbes ae 47 c 8 b a 7 & b + d 6 Numbes ae 568, 358, 48 c 9 b a 8 & b + d 8 Numbes ae 889, 679, 469, 593 So total numbe f(x) ([k[x] k{x}] k[x]) (whee x [x] + {x}) k 4 (k[x] [k{x}] k[x]) (whee [x + m] [x] + m, m z) k 4 k [k{x}] [{x}] + [3{x}] + [4{x}] Note that as {x}, 4,, 4 3,, 3,, 3, 3, 3 4, 3, 4 Values of f(x) is,,, 4, 5, 6 Hence numbe of intege in ange is The equation of staight line AB is P mv + c () PHYSICS whee m is the slope and c is the intecept. Fo points A and B, we have and P mv + c P m(v ) + c P These equations give m and c 3 P V. nrt Now. PV nrt P Using this in eq () we have V () nr T (mv cv) T will be maximum if dt dv and d T dv. Diffeentiating eq () with espect to V and putting dt, we get dv m V + c c which gives V m T max c (3P ) 9 P V 4nRm 4nR P / V 4nR Thus, the coect choice is (A). PAGE - 9

10 67. T ma 3T a 3 mg g KE m a cos t 7 ; PE m a sin t KE PE m a (cos t sin t) m a cos t Angula fequency The time peiod T s 69. Fo sphee : T 4 S m C. Fo cube : d dt d T 4. S m.c dt d dt d dt sphee cube m sphee cube V m V [S 6a (4 )] 6 7. Toque about CM : F b. 4 I ( ) () () (g). 4 g 4I '' will be same fo all points. PAGE -

11 CHEMISTRY 7. [HS ] 8 a c K M 7. Hº xn Hº f [N H 4 ] [(94 + 8) ( )] Hº 338 kj 73. (A) º amine evolved N gas with NaNO /HCl. (B) Aomatic aldehyde does not give Fehling solution test. (C) OH gives iodofom test. (D) Since cabon is not pesent in H N NH, it does not gives lassigne's test. 74. H : s He : s, s Li : s, s, s Be : s, s, s, s B : s, s, s, s, p x p y C : s, s, s, s, p x p y N : s, s, s, s, p x p y, p z O : s, s, s, s, p z, p x p y, *p x p y F : s, s, s, s, p z, p x p y, *p x p y 75. Species lone pai on cental atom TeB : + BF : SNF 3 : XeF 3 : 3 Total Numbe of lone pai 6 N SNF 3 : F S F F PAGE -

ALL INDIA TEST SERIES

ALL INDIA TEST SERIES Fom Classoom/Integated School Pogams 7 in Top 0, in Top 00, 54 in Top 00, 06 in Top 500 All India Ranks & 4 Students fom Classoom /Integated School Pogams & 7 Students fom All Pogams have been Awaded a

More information

(n 1)n(n + 1)(n + 2) + 1 = (n 1)(n + 2)n(n + 1) + 1 = ( (n 2 + n 1) 1 )( (n 2 + n 1) + 1 ) + 1 = (n 2 + n 1) 2.

(n 1)n(n + 1)(n + 2) + 1 = (n 1)(n + 2)n(n + 1) + 1 = ( (n 2 + n 1) 1 )( (n 2 + n 1) + 1 ) + 1 = (n 2 + n 1) 2. Paabola Volume 5, Issue (017) Solutions 151 1540 Q151 Take any fou consecutive whole numbes, multiply them togethe and add 1. Make a conjectue and pove it! The esulting numbe can, fo instance, be expessed

More information

Narayana IIT Academy

Narayana IIT Academy INDIA Sec: S. IIT_IZ JEE-MAIN Date: 4--8 Time: 7: AM to : AM GTM-5 Max.Maks: 6 KEY SHEET MATHS 4 4 5 6 4 7 4 8 9 4 4 5 6 7 8 4 9 4 5 6 7 8 9 4 PHYSICS 4 4 5 6 7 4 8 9 4 4 4 4 4 44 45 46 47 4 48 49 5 5

More information

OSCILLATIONS AND GRAVITATION

OSCILLATIONS AND GRAVITATION 1. SIMPLE HARMONIC MOTION Simple hamonic motion is any motion that is equivalent to a single component of unifom cicula motion. In this situation the velocity is always geatest in the middle of the motion,

More information

2. Electrostatics. Dr. Rakhesh Singh Kshetrimayum 8/11/ Electromagnetic Field Theory by R. S. Kshetrimayum

2. Electrostatics. Dr. Rakhesh Singh Kshetrimayum 8/11/ Electromagnetic Field Theory by R. S. Kshetrimayum 2. Electostatics D. Rakhesh Singh Kshetimayum 1 2.1 Intoduction In this chapte, we will study how to find the electostatic fields fo vaious cases? fo symmetic known chage distibution fo un-symmetic known

More information

Physics 181. Assignment 4

Physics 181. Assignment 4 Physics 181 Assignment 4 Solutions 1. A sphee has within it a gavitational field given by g = g, whee g is constant and is the position vecto of the field point elative to the cente of the sphee. This

More information

Qualifying Examination Electricity and Magnetism Solutions January 12, 2006

Qualifying Examination Electricity and Magnetism Solutions January 12, 2006 1 Qualifying Examination Electicity and Magnetism Solutions Januay 12, 2006 PROBLEM EA. a. Fist, we conside a unit length of cylinde to find the elationship between the total chage pe unit length λ and

More information

(Sample 3) Exam 1 - Physics Patel SPRING 1998 FORM CODE - A (solution key at end of exam)

(Sample 3) Exam 1 - Physics Patel SPRING 1998 FORM CODE - A (solution key at end of exam) (Sample 3) Exam 1 - Physics 202 - Patel SPRING 1998 FORM CODE - A (solution key at end of exam) Be sue to fill in you student numbe and FORM lette (A, B, C) on you answe sheet. If you foget to include

More information

c) (6) Assuming the tires do not skid, what coefficient of static friction between tires and pavement is needed?

c) (6) Assuming the tires do not skid, what coefficient of static friction between tires and pavement is needed? Geneal Physics I Exam 2 - Chs. 4,5,6 - Foces, Cicula Motion, Enegy Oct. 10, 2012 Name Rec. Inst. Rec. Time Fo full cedit, make you wok clea to the gade. Show fomulas used, essential steps, and esults with

More information

Physics 2212 GH Quiz #2 Solutions Spring 2016

Physics 2212 GH Quiz #2 Solutions Spring 2016 Physics 2212 GH Quiz #2 Solutions Sping 216 I. 17 points) Thee point chages, each caying a chage Q = +6. nc, ae placed on an equilateal tiangle of side length = 3. mm. An additional point chage, caying

More information

RAO IIT ACADEMY / NSEP Physics / Code : P 152 / Solutions NATIONAL STANDARD EXAMINATION IN PHYSICS SOLUTIONS

RAO IIT ACADEMY / NSEP Physics / Code : P 152 / Solutions NATIONAL STANDARD EXAMINATION IN PHYSICS SOLUTIONS RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions NAONAL SANDARD EXAMNAON N PHYSCS - 5 SOLUONS RAO ACADEMY / NSEP Physics / Code : P 5 / Solutions NSEP SOLUONS (PHYSCS) CODE - P 5 ANSWER KEY & SOLUONS.

More information

Magnetic Dipoles Challenge Problem Solutions

Magnetic Dipoles Challenge Problem Solutions Magnetic Dipoles Challenge Poblem Solutions Poblem 1: Cicle the coect answe. Conside a tiangula loop of wie with sides a and b. The loop caies a cuent I in the diection shown, and is placed in a unifom

More information

ELECTROSTATICS::BHSEC MCQ 1. A. B. C. D.

ELECTROSTATICS::BHSEC MCQ 1. A. B. C. D. ELETROSTATIS::BHSE 9-4 MQ. A moving electic chage poduces A. electic field only. B. magnetic field only.. both electic field and magnetic field. D. neithe of these two fields.. both electic field and magnetic

More information

Chapter 13 Gravitation

Chapter 13 Gravitation Chapte 13 Gavitation In this chapte we will exploe the following topics: -Newton s law of gavitation, which descibes the attactive foce between two point masses and its application to extended objects

More information

Physics 2A Chapter 10 - Moment of Inertia Fall 2018

Physics 2A Chapter 10 - Moment of Inertia Fall 2018 Physics Chapte 0 - oment of netia Fall 08 The moment of inetia of a otating object is a measue of its otational inetia in the same way that the mass of an object is a measue of its inetia fo linea motion.

More information

Electrostatics. 1. Show does the force between two point charges change if the dielectric constant of the medium in which they are kept increase?

Electrostatics. 1. Show does the force between two point charges change if the dielectric constant of the medium in which they are kept increase? Electostatics 1. Show does the foce between two point chages change if the dielectic constant of the medium in which they ae kept incease? 2. A chaged od P attacts od R whee as P epels anothe chaged od

More information

15 B1 1. Figure 1. At what speed would the car have to travel for resonant oscillations to occur? Comment on your answer.

15 B1 1. Figure 1. At what speed would the car have to travel for resonant oscillations to occur? Comment on your answer. Kiangsu-Chekiang College (Shatin) F:EasteHolidaysAssignmentAns.doc Easte Holidays Assignment Answe Fom 6B Subject: Physics. (a) State the conditions fo a body to undego simple hamonic motion. ( mak) (a)

More information

Advanced Subsidiary GCE (H157) Advanced GCE (H557) Physics B (Advancing Physics) Data, Formulae and Relationships Booklet

Advanced Subsidiary GCE (H157) Advanced GCE (H557) Physics B (Advancing Physics) Data, Formulae and Relationships Booklet Advanced Subsidiay GCE (H57) Advanced GCE (H557) Physics B (Advancing Physics) Data, Fomulae and Relationships Booklet The infomation in this booklet is fo the use of candidates following the Advanced

More information

3.6 Applied Optimization

3.6 Applied Optimization .6 Applied Optimization Section.6 Notes Page In this section we will be looking at wod poblems whee it asks us to maimize o minimize something. Fo all the poblems in this section you will be taking the

More information

Phys102 Second Major-182 Zero Version Monday, March 25, 2019 Page: 1

Phys102 Second Major-182 Zero Version Monday, March 25, 2019 Page: 1 Monday, Mach 5, 019 Page: 1 Q1. Figue 1 shows thee pais of identical conducting sphees that ae to be touched togethe and then sepaated. The initial chages on them befoe the touch ae indicated. Rank the

More information

Chapter 5 Page 5.1 CHAPTER 5. r Force times distance has units of energy. Therefore, fxr=u, or f / is dimensionless.

Chapter 5 Page 5.1 CHAPTER 5. r Force times distance has units of energy. Therefore, fxr=u, or f / is dimensionless. Chapte 5 Page 5.1 CHAPTER 5 Poblem 5.1: 1 (a) u () 4 0.90.93 3.0 (b) Foce times distance has units of enegy. Theefoe, fx=u, o f/ is dimensionless. d f = d u 1 d f 4ε 1 = f = 4 ε1 d 13 f = 4 ε 1 f ε = 4

More information

Electrostatics (Electric Charges and Field) #2 2010

Electrostatics (Electric Charges and Field) #2 2010 Electic Field: The concept of electic field explains the action at a distance foce between two chaged paticles. Evey chage poduces a field aound it so that any othe chaged paticle expeiences a foce when

More information

Physics: Dr. F. Wilhelm E:\Excel files\130\m3a Sp06 130a solved.doc page 1 of 9

Physics: Dr. F. Wilhelm E:\Excel files\130\m3a Sp06 130a solved.doc page 1 of 9 Physics: D. F. Wilhelm E:\Excel files\130\m3a Sp06 130a solved.doc page 1 of 9 NAME:... POINTS:... D. Fitz Wilhelm, Diablo Valley College, Physics Depatment Phone: (95) 671-7309 Extension: 403 Midtem 3a,

More information

CHAPTER 10 ELECTRIC POTENTIAL AND CAPACITANCE

CHAPTER 10 ELECTRIC POTENTIAL AND CAPACITANCE CHAPTER 0 ELECTRIC POTENTIAL AND CAPACITANCE ELECTRIC POTENTIAL AND CAPACITANCE 7 0. ELECTRIC POTENTIAL ENERGY Conside a chaged paticle of chage in a egion of an electic field E. This filed exets an electic

More information

AP-C WEP. h. Students should be able to recognize and solve problems that call for application both of conservation of energy and Newton s Laws.

AP-C WEP. h. Students should be able to recognize and solve problems that call for application both of conservation of energy and Newton s Laws. AP-C WEP 1. Wok a. Calculate the wok done by a specified constant foce on an object that undegoes a specified displacement. b. Relate the wok done by a foce to the aea unde a gaph of foce as a function

More information

Physics Tutorial V1 2D Vectors

Physics Tutorial V1 2D Vectors Physics Tutoial V1 2D Vectos 1 Resolving Vectos & Addition of Vectos A vecto quantity has both magnitude and diection. Thee ae two ways commonly used to mathematically descibe a vecto. y (a) The pola fom:,

More information

Voltage ( = Electric Potential )

Voltage ( = Electric Potential ) V-1 of 10 Voltage ( = lectic Potential ) An electic chage altes the space aound it. Thoughout the space aound evey chage is a vecto thing called the electic field. Also filling the space aound evey chage

More information

PES 3950/PHYS 6950: Homework Assignment 6

PES 3950/PHYS 6950: Homework Assignment 6 PES 3950/PHYS 6950: Homewok Assignment 6 Handed out: Monday Apil 7 Due in: Wednesday May 6, at the stat of class at 3:05 pm shap Show all woking and easoning to eceive full points. Question 1 [5 points]

More information

Electricity Revision ELECTRICITY REVISION KEY CONCEPTS TERMINOLOGY & DEFINITION. Physical Sciences X-Sheets

Electricity Revision ELECTRICITY REVISION KEY CONCEPTS TERMINOLOGY & DEFINITION. Physical Sciences X-Sheets Electicity Revision KEY CONCEPTS In this session we will focus on the following: Stating and apply Coulomb s Law. Defining electical field stength and applying the deived equations. Dawing electical field

More information

Gauss Law. Physics 231 Lecture 2-1

Gauss Law. Physics 231 Lecture 2-1 Gauss Law Physics 31 Lectue -1 lectic Field Lines The numbe of field lines, also known as lines of foce, ae elated to stength of the electic field Moe appopiately it is the numbe of field lines cossing

More information

06 - ROTATIONAL MOTION Page 1 ( Answers at the end of all questions )

06 - ROTATIONAL MOTION Page 1 ( Answers at the end of all questions ) 06 - ROTATIONAL MOTION Page ) A body A of mass M while falling vetically downwads unde gavity beaks into two pats, a body B of mass ( / ) M and a body C of mass ( / ) M. The cente of mass of bodies B and

More information

To Feel a Force Chapter 7 Static equilibrium - torque and friction

To Feel a Force Chapter 7 Static equilibrium - torque and friction To eel a oce Chapte 7 Chapte 7: Static fiction, toque and static equilibium A. Review of foce vectos Between the eath and a small mass, gavitational foces of equal magnitude and opposite diection act on

More information

PHYS 1444 Lecture #5

PHYS 1444 Lecture #5 Shot eview Chapte 24 PHYS 1444 Lectue #5 Tuesday June 19, 212 D. Andew Bandt Capacitos and Capacitance 1 Coulom s Law The Fomula QQ Q Q F 1 2 1 2 Fomula 2 2 F k A vecto quantity. Newtons Diection of electic

More information

7.2. Coulomb s Law. The Electric Force

7.2. Coulomb s Law. The Electric Force Coulomb s aw Recall that chaged objects attact some objects and epel othes at a distance, without making any contact with those objects Electic foce,, o the foce acting between two chaged objects, is somewhat

More information

AP Physics 1 - Circular Motion and Gravitation Practice Test (Multiple Choice Section) Answer Section

AP Physics 1 - Circular Motion and Gravitation Practice Test (Multiple Choice Section) Answer Section AP Physics 1 - Cicula Motion and Gaitation Pactice est (Multiple Choice Section) Answe Section MULIPLE CHOICE 1. B he centipetal foce must be fiction since, lacking any fiction, the coin would slip off.

More information

When a mass moves because of a force, we can define several types of problem.

When a mass moves because of a force, we can define several types of problem. Mechanics Lectue 4 3D Foces, gadient opeato, momentum 3D Foces When a mass moves because of a foce, we can define seveal types of poblem. ) When we know the foce F as a function of time t, F=F(t). ) When

More information

1 2 U CV. K dq I dt J nqv d J V IR P VI

1 2 U CV. K dq I dt J nqv d J V IR P VI o 5 o T C T F 9 T K T o C 7.5 L L T V VT Q mct nct Q F V ml F V dq A H k TH TC dt L pv nt Kt nt CV ideal monatomic gas 5 CV ideal diatomic gas w/o vibation V W pdv V U Q W W Q e Q Q e Canot H C T T S C

More information

CAREER POINT TARGET IIT JEE CHEMISTRY, MATHEMATICS & PHYSICS HINTS & SOLUTION (B*) (C*) (D) MeMgBr 9. [A, D]

CAREER POINT TARGET IIT JEE CHEMISTRY, MATHEMATICS & PHYSICS HINTS & SOLUTION (B*) (C*) (D) MeMgBr 9. [A, D] CAREER PINT TARGET IIT JEE CEMISTRY, MATEMATICS & PYSICS RS -- I -A INTS & SLUTIN CEMISTRY Section I n +. [B] C n n + n + nc + (n + ) V 7 n + (n + ) / 7 n VC 4 n 4 alkane is C 6 a.[a] P + (v b) RT V at

More information

CHAPTER 25 ELECTRIC POTENTIAL

CHAPTER 25 ELECTRIC POTENTIAL CHPTE 5 ELECTIC POTENTIL Potential Diffeence and Electic Potential Conside a chaged paticle of chage in a egion of an electic field E. This filed exets an electic foce on the paticle given by F=E. When

More information

Substances that are liquids or solids under ordinary conditions may also exist as gases. These are often referred to as vapors.

Substances that are liquids or solids under ordinary conditions may also exist as gases. These are often referred to as vapors. Chapte 0. Gases Chaacteistics of Gases All substances have thee phases: solid, liquid, and gas. Substances that ae liquids o solids unde odinay conditions may also exist as gases. These ae often efeed

More information

Chapter 22 The Electric Field II: Continuous Charge Distributions

Chapter 22 The Electric Field II: Continuous Charge Distributions Chapte The lectic Field II: Continuous Chage Distibutions A ing of adius a has a chage distibution on it that vaies as l(q) l sin q, as shown in Figue -9. (a) What is the diection of the electic field

More information

, and the curve BC is symmetrical. Find also the horizontal force in x-direction on one side of the body. h C

, and the curve BC is symmetrical. Find also the horizontal force in x-direction on one side of the body. h C Umeå Univesitet, Fysik 1 Vitaly Bychkov Pov i teknisk fysik, Fluid Dynamics (Stömningsläa), 2013-05-31, kl 9.00-15.00 jälpmedel: Students may use any book including the textbook Lectues on Fluid Dynamics.

More information

EM-2. 1 Coulomb s law, electric field, potential field, superposition q. Electric field of a point charge (1)

EM-2. 1 Coulomb s law, electric field, potential field, superposition q. Electric field of a point charge (1) EM- Coulomb s law, electic field, potential field, supeposition q ' Electic field of a point chage ( ') E( ) kq, whee k / 4 () ' Foce of q on a test chage e at position is ee( ) Electic potential O kq

More information

EN40: Dynamics and Vibrations. Midterm Examination Thursday March

EN40: Dynamics and Vibrations. Midterm Examination Thursday March EN40: Dynamics and Vibations Midtem Examination Thusday Mach 9 2017 School of Engineeing Bown Univesity NAME: Geneal Instuctions No collaboation of any kind is pemitted on this examination. You may bing

More information

Physics 1C Fall 2011: Quiz 1 Version A 1

Physics 1C Fall 2011: Quiz 1 Version A 1 Physics 1C Fall 2011: Quiz 1 Vesion A 1 Depatment of Physics Physics 1C Fall Quate - 2011 D. Mak Paddock INSTRUCTIONS: 1. Pint you full name below LAST NAME FIRST NAME MIDDLE INITIAL 2. You code numbe

More information

Physics C Rotational Motion Name: ANSWER KEY_ AP Review Packet

Physics C Rotational Motion Name: ANSWER KEY_ AP Review Packet Linea and angula analogs Linea Rotation x position x displacement v velocity a T tangential acceleation Vectos in otational motion Use the ight hand ule to detemine diection of the vecto! Don t foget centipetal

More information

Physics 122, Fall October 2012

Physics 122, Fall October 2012 Today in Physics 1: electostatics eview David Blaine takes the pactical potion of his electostatics midtem (Gawke). 11 Octobe 01 Physics 1, Fall 01 1 Electostatics As you have pobably noticed, electostatics

More information

Physics 107 TUTORIAL ASSIGNMENT #8

Physics 107 TUTORIAL ASSIGNMENT #8 Physics 07 TUTORIAL ASSIGNMENT #8 Cutnell & Johnson, 7 th edition Chapte 8: Poblems 5,, 3, 39, 76 Chapte 9: Poblems 9, 0, 4, 5, 6 Chapte 8 5 Inteactive Solution 8.5 povides a model fo solving this type

More information

Algebra-based Physics II

Algebra-based Physics II lgebabased Physics II Chapte 19 Electic potential enegy & The Electic potential Why enegy is stoed in an electic field? How to descibe an field fom enegetic point of view? Class Website: Natual way of

More information

Today in Astronomy 142: the Milky Way s disk

Today in Astronomy 142: the Milky Way s disk Today in Astonomy 14: the Milky Way s disk Moe on stas as a gas: stella elaxation time, equilibium Diffeential otation of the stas in the disk The local standad of est Rotation cuves and the distibution

More information

anubhavclasses.wordpress.com CBSE Solved Test Papers PHYSICS Class XII Chapter : Electrostatics

anubhavclasses.wordpress.com CBSE Solved Test Papers PHYSICS Class XII Chapter : Electrostatics CBS Solved Test Papes PHYSICS Class XII Chapte : lectostatics CBS TST PAPR-01 CLASS - XII PHYSICS (Unit lectostatics) 1. Show does the foce between two point chages change if the dielectic constant of

More information

Exam 3, vers Physics Spring, 2003

Exam 3, vers Physics Spring, 2003 1 of 9 Exam 3, ves. 0001 - Physics 1120 - Sping, 2003 NAME Signatue Student ID # TA s Name(Cicle one): Michael Scheffestein, Chis Kelle, Paisa Seelungsawat Stating time of you Tues ecitation (wite time

More information

MAGNETIC FIELD INTRODUCTION

MAGNETIC FIELD INTRODUCTION MAGNETIC FIELD INTRODUCTION It was found when a magnet suspended fom its cente, it tends to line itself up in a noth-south diection (the compass needle). The noth end is called the Noth Pole (N-pole),

More information

Review for Midterm-1

Review for Midterm-1 Review fo Midtem-1 Midtem-1! Wednesday Sept. 24th at 6pm Section 1 (the 4:10pm class) exam in BCC N130 (Business College) Section 2 (the 6:00pm class) exam in NR 158 (Natual Resouces) Allowed one sheet

More information

Gauss s Law Simulation Activities

Gauss s Law Simulation Activities Gauss s Law Simulation Activities Name: Backgound: The electic field aound a point chage is found by: = kq/ 2 If thee ae multiple chages, the net field at any point is the vecto sum of the fields. Fo a

More information

Momentum is conserved if no external force

Momentum is conserved if no external force Goals: Lectue 13 Chapte 9 v Employ consevation of momentum in 1 D & 2D v Examine foces ove time (aka Impulse) Chapte 10 v Undestand the elationship between motion and enegy Assignments: l HW5, due tomoow

More information

Lab 10: Newton s Second Law in Rotation

Lab 10: Newton s Second Law in Rotation Lab 10: Newton s Second Law in Rotation We can descibe the motion of objects that otate (i.e. spin on an axis, like a popelle o a doo) using the same definitions, adapted fo otational motion, that we have

More information

Physics 1114: Unit 5 Hand-out Homework (Answers)

Physics 1114: Unit 5 Hand-out Homework (Answers) Physics 1114: Unit 5 Hand-out Homewok (Answes) Poblem set 1 1. The flywheel on an expeimental bus is otating at 420 RPM (evolutions pe minute). To find (a) the angula velocity in ad/s (adians/second),

More information

- 5 - TEST 1R. This is the repeat version of TEST 1, which was held during Session.

- 5 - TEST 1R. This is the repeat version of TEST 1, which was held during Session. - 5 - TEST 1R This is the epeat vesion of TEST 1, which was held duing Session. This epeat test should be attempted by those students who missed Test 1, o who wish to impove thei mak in Test 1. IF YOU

More information

Thomas Whitham Sixth Form Mechanics in Mathematics. Rectilinear Motion Dynamics of a particle Projectiles Vectors Circular motion

Thomas Whitham Sixth Form Mechanics in Mathematics. Rectilinear Motion Dynamics of a particle Projectiles Vectors Circular motion Thomas Whitham Sith om Mechanics in Mathematics Unit M Rectilinea Motion Dynamics of a paticle Pojectiles Vectos Cicula motion . Rectilinea Motion omation and solution of simple diffeential equations in

More information

Tutorial Exercises: Central Forces

Tutorial Exercises: Central Forces Tutoial Execises: Cental Foces. Tuning Points fo the Keple potential (a) Wite down the two fist integals fo cental motion in the Keple potential V () = µm/ using J fo the angula momentum and E fo the total

More information

13. Adiabatic Invariants and Action-Angle Variables Michael Fowler

13. Adiabatic Invariants and Action-Angle Variables Michael Fowler 3 Adiabatic Invaiants and Action-Angle Vaiables Michael Fowle Adiabatic Invaiants Imagine a paticle in one dimension oscillating back and foth in some potential he potential doesn t have to be hamonic,

More information

Cartesian Coordinate System and Vectors

Cartesian Coordinate System and Vectors Catesian Coodinate System and Vectos Coodinate System Coodinate system: used to descibe the position of a point in space and consists of 1. An oigin as the efeence point 2. A set of coodinate axes with

More information

AP Physics C: Electricity and Magnetism 2003 Scoring Guidelines

AP Physics C: Electricity and Magnetism 2003 Scoring Guidelines AP Physics C: Electicity and Magnetism 3 Scoing Guidelines The mateials included in these files ae intended fo use by AP teaches fo couse and exam pepaation; pemission fo any othe use must be sought fom

More information

Physics 235 Chapter 5. Chapter 5 Gravitation

Physics 235 Chapter 5. Chapter 5 Gravitation Chapte 5 Gavitation In this Chapte we will eview the popeties of the gavitational foce. The gavitational foce has been discussed in geat detail in you intoductoy physics couses, and we will pimaily focus

More information

11) A thin, uniform rod of mass M is supported by two vertical strings, as shown below.

11) A thin, uniform rod of mass M is supported by two vertical strings, as shown below. Fall 2007 Qualifie Pat II 12 minute questions 11) A thin, unifom od of mass M is suppoted by two vetical stings, as shown below. Find the tension in the emaining sting immediately afte one of the stings

More information

PHYS 1410, 11 Nov 2015, 12:30pm.

PHYS 1410, 11 Nov 2015, 12:30pm. PHYS 40, Nov 205, 2:30pm. A B = AB cos φ x = x 0 + v x0 t + a 2 xt 2 a ad = v2 2 m(v2 2 v) 2 θ = θ 0 + ω 0 t + 2 αt2 L = p fs µ s n 0 + αt K = 2 Iω2 cm = m +m 2 2 +... m +m 2 +... p = m v and L = I ω ω

More information

b) (5) What average force magnitude was applied by the students working together?

b) (5) What average force magnitude was applied by the students working together? Geneal Physics I Exam 3 - Chs. 7,8,9 - Momentum, Rotation, Equilibium Nov. 3, 2010 Name Rec. Inst. Rec. Time Fo full cedit, make you wok clea to the gade. Show fomulas used, essential steps, and esults

More information

Phys 201A. Homework 6 Solutions. F A and F r. B. According to Newton s second law, ( ) ( )2. j = ( 6.0 m / s 2 )ˆ i ( 10.4m / s 2 )ˆ j.

Phys 201A. Homework 6 Solutions. F A and F r. B. According to Newton s second law, ( ) ( )2. j = ( 6.0 m / s 2 )ˆ i ( 10.4m / s 2 )ˆ j. 7. We denote the two foces F A + F B = ma,sof B = ma F A. (a) In unit vecto notation F A = ( 20.0 N)ˆ i and Theefoe, Phys 201A Homewok 6 Solutions F A and F B. Accoding to Newton s second law, a = [ (

More information

SAMPLE QUIZ 3 - PHYSICS For a right triangle: sin θ = a c, cos θ = b c, tan θ = a b,

SAMPLE QUIZ 3 - PHYSICS For a right triangle: sin θ = a c, cos θ = b c, tan θ = a b, SAMPLE QUIZ 3 - PHYSICS 1301.1 his is a closed book, closed notes quiz. Calculatos ae pemitted. he ONLY fomulas that may be used ae those given below. Define all symbols and justify all mathematical expessions

More information

$ i. !((( dv vol. Physics 8.02 Quiz One Equations Fall q 1 q 2 r 2 C = 2 C! V 2 = Q 2 2C F = 4!" or. r ˆ = points from source q to observer

$ i. !((( dv vol. Physics 8.02 Quiz One Equations Fall q 1 q 2 r 2 C = 2 C! V 2 = Q 2 2C F = 4! or. r ˆ = points from source q to observer Physics 8.0 Quiz One Equations Fall 006 F = 1 4" o q 1 q = q q ˆ 3 4" o = E 4" o ˆ = points fom souce q to obseve 1 dq E = # ˆ 4" 0 V "## E "d A = Q inside closed suface o d A points fom inside to V =

More information

Prerna Tower, Road No 2, Contractors Area, Bistupur, Jamshedpur , Tel (0657) ,

Prerna Tower, Road No 2, Contractors Area, Bistupur, Jamshedpur , Tel (0657) , R Pena Towe, Road No, Contactos Aea, Bistupu, Jamshedpu 8, Tel (657)89, www.penaclasses.com IIT JEE Mathematics Pape II PART III MATHEMATICS SECTION I Single Coect Answe Type This section contains 8 multiple

More information

PROGRESS TEST-4 GR, GRK & GRS JEE MAIN PATTERN

PROGRESS TEST-4 GR, GRK & GRS JEE MAIN PATTERN PROGRESS TEST- GR, GRK & GRS JEE MIN PTTERN Test Date: -7-7 [ ] PT-IV (Main) GR, GRK & GRS_.7.7 PHYSIS. () mg mg m m. () If acceleation of block is a upwad along the incline, then acceleation of block

More information

(read nabla or del) is defined by, k. (9.7.1*)

(read nabla or del) is defined by, k. (9.7.1*) 9.7 Gadient of a scala field. Diectional deivative Some of the vecto fields in applications can be obtained fom scala fields. This is vey advantageous because scala fields can be handled moe easily. The

More information

Newton s Laws, Kepler s Laws, and Planetary Orbits

Newton s Laws, Kepler s Laws, and Planetary Orbits Newton s Laws, Keple s Laws, and Planetay Obits PROBLEM SET 4 DUE TUESDAY AT START OF LECTURE 28 Septembe 2017 ASTRONOMY 111 FALL 2017 1 Newton s & Keple s laws and planetay obits Unifom cicula motion

More information

763620SS STATISTICAL PHYSICS Solutions 2 Autumn 2012

763620SS STATISTICAL PHYSICS Solutions 2 Autumn 2012 763620SS STATISTICAL PHYSICS Solutions 2 Autumn 2012 1. Continuous Random Walk Conside a continuous one-dimensional andom walk. Let w(s i ds i be the pobability that the length of the i th displacement

More information

KEPLER S LAWS AND PLANETARY ORBITS

KEPLER S LAWS AND PLANETARY ORBITS KEPE S AWS AND PANETAY OBITS 1. Selected popeties of pola coodinates and ellipses Pola coodinates: I take a some what extended view of pola coodinates in that I allow fo a z diection (cylindical coodinates

More information

21 MAGNETIC FORCES AND MAGNETIC FIELDS

21 MAGNETIC FORCES AND MAGNETIC FIELDS CHAPTER 1 MAGNETIC ORCES AND MAGNETIC IELDS ANSWERS TO OCUS ON CONCEPTS QUESTIONS 1. (d) Right-Hand Rule No. 1 gives the diection of the magnetic foce as x fo both dawings A and. In dawing C, the velocity

More information

Extra notes for circular motion: Circular motion : v keeps changing, maybe both speed and

Extra notes for circular motion: Circular motion : v keeps changing, maybe both speed and Exta notes fo cicula motion: Cicula motion : v keeps changing, maybe both speed and diection ae changing. At least v diection is changing. Hence a 0. Acceleation NEEDED to stay on cicula obit: a cp v /,

More information

to point uphill and to be equal to its maximum value, in which case f s, max = μsfn

to point uphill and to be equal to its maximum value, in which case f s, max = μsfn Chapte 6 16. (a) In this situation, we take f s to point uphill and to be equal to its maximum value, in which case f s, max = μsf applies, whee μ s = 0.5. pplying ewton s second law to the block of mass

More information

Between any two masses, there exists a mutual attractive force.

Between any two masses, there exists a mutual attractive force. YEAR 12 PHYSICS: GRAVITATION PAST EXAM QUESTIONS Name: QUESTION 1 (1995 EXAM) (a) State Newton s Univesal Law of Gavitation in wods Between any two masses, thee exists a mutual attactive foce. This foce

More information

16.1 Permanent magnets

16.1 Permanent magnets Unit 16 Magnetism 161 Pemanent magnets 16 The magnetic foce on moving chage 163 The motion of chaged paticles in a magnetic field 164 The magnetic foce exeted on a cuent-caying wie 165 Cuent loops and

More information

AST 121S: The origin and evolution of the Universe. Introduction to Mathematical Handout 1

AST 121S: The origin and evolution of the Universe. Introduction to Mathematical Handout 1 Please ead this fist... AST S: The oigin and evolution of the Univese Intoduction to Mathematical Handout This is an unusually long hand-out and one which uses in places mathematics that you may not be

More information

Lecture 8 - Gauss s Law

Lecture 8 - Gauss s Law Lectue 8 - Gauss s Law A Puzzle... Example Calculate the potential enegy, pe ion, fo an infinite 1D ionic cystal with sepaation a; that is, a ow of equally spaced chages of magnitude e and altenating sign.

More information

Ch 13 Universal Gravitation

Ch 13 Universal Gravitation Ch 13 Univesal Gavitation Ch 13 Univesal Gavitation Why do celestial objects move the way they do? Keple (1561-1630) Tycho Bahe s assistant, analyzed celestial motion mathematically Galileo (1564-1642)

More information

Review for 2 nd Midterm

Review for 2 nd Midterm Review fo 2 nd Midtem Midtem-2! Wednesday Octobe 29 at 6pm Section 1 N100 BCC (Business College) Section 2 158 NR (Natual Resouces) Allowed one sheet of notes (both sides) and calculato Coves Chaptes 27-31

More information

AH Mechanics Checklist (Unit 2) AH Mechanics Checklist (Unit 2) Circular Motion

AH Mechanics Checklist (Unit 2) AH Mechanics Checklist (Unit 2) Circular Motion AH Mechanics Checklist (Unit ) AH Mechanics Checklist (Unit ) Cicula Motion No. kill Done 1 Know that cicula motion efes to motion in a cicle of constant adius Know that cicula motion is conveniently descibed

More information

Electric Field, Potential Energy, & Voltage

Electric Field, Potential Energy, & Voltage Slide 1 / 66 lectic Field, Potential negy, & oltage Wok Slide 2 / 66 Q+ Q+ The foce changes as chages move towads each othe since the foce depends on the distance between the chages. s these two chages

More information

CIRCULAR MOTION. Particle moving in an arbitrary path. Particle moving in straight line

CIRCULAR MOTION. Particle moving in an arbitrary path. Particle moving in straight line 1 CIRCULAR MOTION 1. ANGULAR DISPLACEMENT Intoduction: Angle subtended by position vecto of a paticle moving along any abitay path w..t. some fixed point is called angula displacement. (a) Paticle moving

More information

EXAM NMR (8N090) November , am

EXAM NMR (8N090) November , am EXA NR (8N9) Novembe 5 9, 9. 1. am Remaks: 1. The exam consists of 8 questions, each with 3 pats.. Each question yields the same amount of points. 3. You ae allowed to use the fomula sheet which has been

More information

Objectives: After finishing this unit you should be able to:

Objectives: After finishing this unit you should be able to: lectic Field 7 Objectives: Afte finishing this unit you should be able to: Define the electic field and explain what detemines its magnitude and diection. Wite and apply fomulas fo the electic field intensity

More information

Nuclear and Particle Physics - Lecture 20 The shell model

Nuclear and Particle Physics - Lecture 20 The shell model 1 Intoduction Nuclea and Paticle Physics - Lectue 0 The shell model It is appaent that the semi-empiical mass fomula does a good job of descibing tends but not the non-smooth behaviou of the binding enegy.

More information

SAMPLE QUESTION PAPER CLASS NAME & LOGO XII-JEE (MAINS)-YEAR Topic Names: Cicula motion Test Numbe Test Booklet No. 000001 110001 Wite/Check this Code on you Answe Sheet : IMPORTANT INSTRUCTIONS : Wite

More information

Hoizontal Cicula Motion 1. A paticle of mass m is tied to a light sting and otated with a speed v along a cicula path of adius. If T is tension in the sting and mg is gavitational foce on the paticle then,

More information

Gravitation. AP/Honors Physics 1 Mr. Velazquez

Gravitation. AP/Honors Physics 1 Mr. Velazquez Gavitation AP/Honos Physics 1 M. Velazquez Newton s Law of Gavitation Newton was the fist to make the connection between objects falling on Eath and the motion of the planets To illustate this connection

More information

Hopefully Helpful Hints for Gauss s Law

Hopefully Helpful Hints for Gauss s Law Hopefully Helpful Hints fo Gauss s Law As befoe, thee ae things you need to know about Gauss s Law. In no paticula ode, they ae: a.) In the context of Gauss s Law, at a diffeential level, the electic flux

More information

Chapter Sixteen: Electric Charge and Electric Fields

Chapter Sixteen: Electric Charge and Electric Fields Chapte Sixteen: Electic Chage and Electic Fields Key Tems Chage Conducto The fundamental electical popety to which the mutual attactions o epulsions between electons and potons ae attibuted. Any mateial

More information

F(r) = r f (r) 4.8. Central forces The most interesting problems in classical mechanics are about central forces.

F(r) = r f (r) 4.8. Central forces The most interesting problems in classical mechanics are about central forces. 4.8. Cental foces The most inteesting poblems in classical mechanics ae about cental foces. Definition of a cental foce: (i) the diection of the foce F() is paallel o antipaallel to ; in othe wods, fo

More information

Current, Resistance and

Current, Resistance and Cuent, Resistance and Electomotive Foce Chapte 25 Octobe 2, 2012 Octobe 2, 2012 Physics 208 1 Leaning Goals The meaning of electic cuent, and how chages move in a conducto. What is meant by esistivity

More information

! E da = 4πkQ enc, has E under the integral sign, so it is not ordinarily an

! E da = 4πkQ enc, has E under the integral sign, so it is not ordinarily an Physics 142 Electostatics 2 Page 1 Electostatics 2 Electicity is just oganized lightning. Geoge Calin A tick that sometimes woks: calculating E fom Gauss s law Gauss s law,! E da = 4πkQ enc, has E unde

More information