Mighty Minds National Skills Test - Calculator - Year 9

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Mighty Minds National Skills Test - Calculator - Year 9 Yr 9 Calculator - M1 Individual Item Descriptions and Information Generated 31/03/2015 5:06pm

Item Topic No. of Q for Topic Sub Topic No. of Q for Sub Topic Item Description Related Lessons 1 Algebra Function and 6 Formulation 3 Students were required to formulate an expression for the area of a composite shape where dimensions were provided as a mixture of whole numbers and pronumerals. Model answer - Total area = 2x x; Area of pool = 3 7; Area of grassed space = 2x 2-21 2 Space 7 Shape 3 Students were required to identify a correctly drawn line of symmetry in irregular shapes. Model answer - Shape B can be folded along the line and remain symmetrical. 3 Number 11 2 Students were required to evaluate several rules to determine which was correct for a given table of values. Model answer - Rule: y = 2x. Proof using first three values: 0 = 2 x 0; 0.5 = 2 x 0.25; 1 = 2 x 0.5 Page 2 of 10

4 Algebra Function and 6 Evaluation 3 Students were required to substitute a whole number for a pronumeral in a given algebraic expression involving multiplication. Model answer - 2 7 = 14 5 Space 7 Shape 3 Students were required to use their understanding of the properties of triangles to identify an equilateral triangle. Model answer - Unknown angle: 180-60 - 60 = 60 6 Number 11 Operations and Indices 1 Students were required to use their knowledge of operations and indices to identify which of several algebraic expressions was equal to a provided algebraic expression. Model answer - w(w x w) + 15 = w 3 + 15 7 Algebra Function and 6 Evaluation 3 Students were required to substitute a decimal for a pronumeral in a given algebraic expression involving multiplication and subtraction. Model answer - y = 18-5 x 5.25; y = 18-26.25; y = -8.25 Page 3 of 10

8 Measurement Chance 8 Dimension 3 Students were required to calculate circumference when provided with the diameter of a circle. Model answer - Circumference = 2 radius; 2 (72/2); 2 36 =226.08 226 cm 9 Number 11 Ratio and Proportion 3 Students were required to determine the change in area of a rectangle when provided with the increase in side lengths. Model answer - 7 x 4 = 28; 8 x 4 = 32; 28 x 32 = 896, which is 16 times larger than 7 x 8 = 56 10 Measurement Chance 8 Dimension 3 Students were required to use information relating to area to calculate an unknown. Model answer - 18 m 2 for 6 wooden tiles; 18/6 = 3 m 2 per tile; 6 8 = 48 tiles in total; 6 tiles are wooden; 48-6 = 42 ceramic tiles; 42 3 = 126 m 2 11 Measurement Chance 8 Data 2 Students were required to determine which of several statements was true in relation to a provided graph. Model answer - $X > $Y; Xkm < Ykm Page 4 of 10

12 Number 11 Fractions 2 Students were required to determine which of several shapes covered a specific fraction of a 3 x 3 grid. Model answer - Two-sixths is the same as one-third 13 Measurement Chance 8 Data 2 Students were required to calculate the mean, median and mode for a provided set of data. Model answer - Mean: (1 + 1 + 2 + 3 + 3 + 3 + 4 + 5 + 6 + 6)/11 = 3.1; Median: 6th number = 3; Mode = 3; Therefore, mean > median = mode 14 Measurement Chance 8 Time 1 Students were required to calculate the difference between two different times. Model answer - 24 minutes until 6am; 8 hours until 2pm; 27 minutes until 2:27pm; 8 hours and 24 + 27 = 51 minutes Page 5 of 10

15 Measurement Chance 8 Chance 1 Students were required to calculate the chance of an event occuring as a percentage, using information provided in the form of a word question. Model answer - Remaining afternoons of TV watching = 2; Remaining afternoons in Mon-Fri period = 4; Chance of watching TV tomorrow = 2/4 or 50% 16 Number 11 Fractions 2 Students were required to determine the half-way point between (or average of) two fractions. Model answer - (3.25 + 7.75)/2; 11/2 = 5.5 17 Number 11 Money 2 Students were required to use division and subtraction to solve a worded problem involving money. Model answer - $42/24 = $1.75 per working day; $3.70 - $1.75 = $1.95 saving per day 18 Algebra Function and 6 Formulation 3 Students were required to use a percentage increase to calculate an unknown. Model answer - 649 x 1.065 = 691.185, which is closest to 690 Page 6 of 10

19 Number 11 Percentages 1 Students were required to calculate a percentage when given information in a worded problem. Model answer - 19/50 x 100% = 38% 20 Number 11 Ratio and Proportion 3 Students were required to calculate a proportion from a given ratio. Multiplication and division of whole numbers was required. Model answer - 7x + 2x = 252; 9x = 252; x = 252/9; x = 28; 2 28 = 56 motorbikes 21 Space 7 Angles 2 Students were required to calculate an unknown angle using their knowledge of the interior angles of a triangle and the angles which make up a straight line. Model answer - Angle MNL: 180-51 - 56 = 73 ; Angle ONP: 180-73 - 83 = 24 Page 7 of 10

22 Space 7 Coordinates and Map Skills 2 Students were required to use their knowledge of compass points and angles of rotation to answer a map-based question. Model answer - 315 anti-clockwise turn is the same as 360-315 = 45 clockwise turn 23 Space 7 Coordinates and Map Skills 2 Students were required to locate coordinates on a map. Model answer - 71/2 = x, 4 =y. These co-ordinates plot within the white space that represents Horse Lake. 24 Space 7 Angles 2 Students were required to use their knowledge of interior angles of regular shapes (triangles, squares and pentagons) to determine an unknown angle. Model Answer - Each interior angle of a square = 90 ; Each interior angle of a triangle adds up to 180 ; 180 3 = 60 ; Each interior angle of a pentagon adds up tp 540 ; 540 5 = 108 ; Angle XYZ = 360-90 - 2 60-108 = 42 25 Space 7 Shape 3 Students were required to recognise the net of a 3D prism. Page 8 of 10

26 Number 11 Ratio and Proportion 3 Students were required to use their knowledge of similar triangles and ratio and proportion to determine an unknown value. Model answer - 5 : 9 = scale factor of 1.8; 1.8 1.1 = 1.98 m 27 Algebra Function and 6 Formulation 3 Students were required to evaluate several expressions to determine which successfully expressed information provided in the form of a diagram. Model answer - If n = 4, h = 70; If n = 6, h = 90; 10 4 + 30 = 70; 10 6 + 30 = 90 28 Algebra Function and 6 Evaluation 3 Students were required to substitute a whole number for a pronumeral in a given algebraic expression involving multiplication and indices. Model answer - E = 0.4 472; E = 0.4 2209; E = 883.6 29 Number 11 Money 2 Students were required to calculate the affordable number of picture frames given a specific budget. Page 9 of 10

30 Measurement Chance 8 Dimension 3 Students were required to calculate the surface area of a prism from a given diagram accompanied with information. Model answer - Rectangular faces: 2 (5 8) + 6 8; 2 40 + 48 = 128m 2; Triangular faces: 2 x 12m 2 = 24m 2; Total surface area = 128 + 24 = 152m 2 31 Measurement Chance 8 Rates 1 Students were required to calculate an unknown distance when provided with a rate (speed) and a diagram displaying distances. Model answer - Total length walked = 3 5 = 15km; 15-1.11-3.16-3.24-4.13 = 3.36km (car park to café and café to carpark); 3.36/2 = 1.68 km 32 Number 11 2 Students were required to use the rule and first four numbers of a sequence to find the sixth number in the sequence. Model answer - 1814 6 + 2 = 10886; 10886 6 + 2 = 65318 Page 10 of 10