First Name Last Name Title Date. Alexandra Stambaugh Slow Light on Chip Dec 8th Ring Resonators and Optofluidics

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Lecture 24 Semiconductor Detectors - Photodetectors Principle of the pn junction photodiode Absorption coefficient and photodiode materials Properties of semiconductor detectors The pin photodiodes Avalanche photodiodes Schottky junction photodetector

First Name Last Name Title Date Alexandra Stambaugh Slow Light on Chip Dec 8th Gopikrishnan Gopalakrishnan Meena Ring Resonators and Optofluidics Dec 8th Md. Mahmudur Rahman ChromaBc dispersion in digital coherent receiver Dec 8th Venkateswara Penumuchu LEDs Efficiency for LighBng Dec 8th Golam Md. Imran Jeffery Hossain BertaloQo Challenges of hot electron extracbon and beyond WDM (Wavelength- Division MulBplexing) Heather Renee Sully OpBcal Fiber FabricaBon Dec 10th Dec 10th Dec 10th NiBsh Padgaonkar Photovoltaics Dec 10th Can Gao Synchronous Digital Hierarchy Dec 12th Avirudh Kaushik AMOLED Displays Dec 12th Tianchi Zeng Chip OpBcal InterconnecBon Dec 12th

i(t) Noise in Photodiodes What is the RMS of fluctuations? Constant illumination Noise current = Total RMS current fluctuations The dark current has shot noise or fluctuations about I d, i n-dark = (2eI d B) 1/2 B = Bandwidth Quantum noise is due to the photon nature of light and its effects are the same as shot noise. Photocurrent has quantum noise or shot noise i n-quantum = (2eI ph B) 1/2

Noise in Photodiodes Total shot noise current, i n i 2 n = i 2 + i 2 n dark n quantum i n = [2e(I d + I ph )B] 1/2 We can conceptually view the photodetector current as I d + I ph + i n This flows through a load resistor R L and voltage across R L is amplified by A to give V out The noise voltage (RMS) due to shot noise in PD = i n R L A

Noise in Photodiodes Total current flowing into R L has three components: I d = Dark current. In principle, we can subtract this or block it with a capacitor if I ph is an ac (transient) signal. I ph = Photocurrent. This is the signal. We need this. It could be a steady or varying (ac or transient) signal. i n = Total shot noise. Due to shot noise from I d and I ph. We cannot eliminate this.

Noise in Photodiodes

Noise in PD abd R L Power in shot noise in PD = i n2 R L = [2e(I d + I ph )B]R L Power in thermal fluctuations in R L = 4k B TB Important Note: Total noise is always found by first summing the average powers involved in individual fluctuations e.g. power in shot noise + power in thermal noise Noise in the amplifier A must also be included See advanced textbooks

Signal to Noise Ratio SNR = Signal Power Noise Power SNR = i 2 n R L I 2 ph R L + 4k B TB = [ 2e( I + I ) B] d I ph 2 ph + 4kBTB R L Important Note: Total noise is always found by first summing the average powers involved in individual fluctuations e.g. power in shot noise + power in thermal noise

Noise Equivalent Power Definition NEP = Input power forsnr =1 Bandwidth = P 1 B 1/2 NEP is defined as the required optical input power to achieve a SNR of 1 within a bandwidth of 1 Hz NEP = P 1 B = 1 1/2 R 2e(I d + I ph ) 1/2 Units for NEP are W Hz 1/2

Noise Equivalent Power Definition NEP = Input power forsnr =1 Bandwidth = P 1 B 1/2 NEP is defined as the required optical input power to achieve a SNR of 1 within a bandwidth of 1 Hz NEP = P 1 B = 1 1/2 R 2e(I d + I ph ) 1/2 Units for NEP are W Hz 1/2 Detectivit y = 1 NEP D * = 1/ 2 A NEP Specific detectivity D* cm Hz -1/2 W -1, or Jones

NEP and Dark Current

EXAMPLE: SNR of a receiver Solution (continued) Shot noise current from the detector = [2e(I d + I ph )B] 1/2 = 0.047 na = 1.29 na Thus, the noise contribution from R L is greater than that from the photodiode. The SNR is SNR Thermal Noise = 4k B TB R L 9 2 (5 10 A) = 9 2 (0.047 10 A) + (1.29 10 = 15.0 Generally SNR is quoted in decibels. We need 10log(SNR), or 10log(15.0) i.e., 11.8 db. Clearly, the load resistance has a dramatic effect on the overall noise performance. 1/2 9 A) 2

Linearly Polarized Light A linearly polarized wave has its electric field oscillations defined along a line perpendicular to the direction of propagation, z. The field vector E and z define a plane of polarization. The E-field oscillations are contained in the plane of polarization. A linearly polarized light at any instant can be represented by the superposition of two fields E x and E y with the right magnitude and phase

Circularly Polarized Light A right circularly polarized light. The field vector E is always at right angles to z, rotates clockwise around z with time, and traces out a full circle over one wavelength of distance propagated.

The Phase Difference Examples of linearly, (a) and (b), and circularly polarized light (c) and (d); (c) is right circularly and (d) is left circularly polarized light (as seen when the wave directly approaches a viewer)

Elliptically Polarized Light

Polarizers A polarizer allows field oscillations along a particular direction transmission axis to pass through Transmission axis (TA) The wire grid-acts as a polarizer There are many types of polarizers

Malus s Law I ( θ ) = I ( 0)cos 2 θ Randomly polarized light is incident on a Polarizer 1 with a transmission axis TA 1. Emerging light from Polarizer 1 is linearly polarized with E along TA 1. Light is incident on Polarizer 2 (analyzer) with a transmission axis TA 2 at an angle θ to TA 1. Detector measures the intensity of the incident light.

Optical Anisotropy A line viewed through a cubic sodium chloride (halite) crystal (optically isotropic) and a calcite crystal (optically anisotropic)

Optically Isotropic Materials Liquids, glasses and cubic crystals are optically anisotropic The refractive index is the same in all directions for all polarizations of the field Sodium chloride (halite) crystal

Many crystals are optically anisotropic This line is due to the extraordinary wave The calcite crystal has two refractive indices The crystal exhibits double refraction This line is due to the ordinary wave Photo by SK A calcite crystal

Uniaxial Birefringent Crsytal Images viewed through a calcite crystal have orthogonal polarizations. Two polaroid analyzers are placed with their transmission axes, along the long edges, at right angles to each other. The ordinary ray, undeflected, goes through the left polarizer whereas the extraordinary wave, deflected, goes through the right polarizer. The two waves therefore have orthogonal polarizations

Principal refractive indices of some optically isotropic and anisotropic crystals (near 589 nm, yellow Na-D line) Optically isotropic n = n o Glass (crown) 1.510 Diamond 2.417 Fluorite (CaF 2 ) 1.434 Uniaxial - Positive n o n e Ice 1.309 1.3105 Quartz 1.5442 1.5533 Rutile (TiO 2 ) 2.616 2.903 Uniaxial - Negative n o n e Calcite (CaCO 3 ) 1.658 1.486 Tourmaline 1.669 1.638 Lithium niobate (LiNbO 3 ) 2.29 2.20 Biaxial n 1 n 2 n 3 Mica (muscovite) 1.5601 1.5936 1.5977

Optical Indicatrix LEFT: Fresnel's ellipsoid (for n 1 = n 2 < n 3 ; quartz) RIGHT: An EM wave propagating along OP at an angle q to the optic axis.

Optical Indicatrix n e 1 ( θ ) 2 = cos n 2 2 o θ + sin n 2 2 e θ

Wave Propagation in a Uniaxial Crystal E o = E o -wave and E e = E e -wave (a) Wave propagation along the optic axis. (b) Wave propagation normal to optic axis.

Power Flow in Extraordinary Wave (a) Wavevector surface cuts in the xz plane for o- and e-waves. (b) An extraordinary wave in an anisotropic crystal with a k e at an angle to the optic axis. The electric field is not normal to k e. The energy flow (group velocity) is along S e which is different than k e.

Calcite Rhomb An EM wave that is off the optic axis of a calcite crystal splits into two waves called ordinary and extraordinary waves. These waves have orthogonal polarizations and travel with different velocities. The o-wave has a polarization that is always perpendicular to the optical axis.