Lesson #15. Section BME 373 Electronics II J.Schesser

Similar documents
Chapter 8. Root Locus Techniques

Chapter 9. Design via Root Locus

, where. This is a highpass filter. The frequency response is the same as that for P.P.14.1 RC. Thus, the sketches of H and φ are shown below.

Name Student ID. A student uses a voltmeter to measure the electric potential difference across the three boxes.

Lecture 13 - Boost DC-DC Converters. Step-Up or Boost converters deliver DC power from a lower voltage DC level (V d ) to a higher load voltage V o.

Chapter 9: Controller design. Controller design. Controller design

Section I5: Feedback in Operational Amplifiers

Root locus ( )( ) The given TFs are: 1. Using Matlab: >> rlocus(g) >> Gp1=tf(1,poly([0-1 -2])) Transfer function: s^3 + 3 s^2 + 2 s

EEO 401 Digital Signal Processing Prof. Mark Fowler

Control Systems Engineering ( Chapter 7. Steady-State Errors ) Prof. Kwang-Chun Ho Tel: Fax:

EE 221 Practice Problems for the Final Exam

Grumman F-14 Tomcat Control Design BY: Chike Uduku

Homework 12 Solution - AME30315, Spring 2013

Solution to HW14 Fall-2002

ECE 2100 Circuit Analysis

Part a: Writing the nodal equations and solving for v o gives the magnitude and phase response: tan ( 0.25 )

1. Introduction: A Mixing Problem

Chapter 9: Quantization of Light

EE/ME/AE324: Dynamical Systems. Chapter 8: Transfer Function Analysis

Analog Electronic Circuits. Prof. Mor M. Peretz

Analysis and Optimization of Monolithic RF Downconversion Receivers

Lab 11 LRC Circuits, Damped Forced Harmonic Motion

376 CHAPTER 6. THE FREQUENCY-RESPONSE DESIGN METHOD. D(s) = we get the compensated system with :

ECE 2100 Circuit Analysis

CHAPTER 14 SIGNAL GENERATORS AND WAVEFORM-SHAPING CIRCUITS

ELG4139: Op Amp-based Active Filters

Potential and Capacitance

Lead/Lag Compensator Frequency Domain Properties and Design Methods

Lecture 8. PID control. Industrial process control ( today) PID control. Insights about PID actions

ME 375 FINAL EXAM Wednesday, May 6, 2009

GUC (Dr. Hany Hammad) 9/19/2016

Section 5.8 Notes Page Exponential Growth and Decay Models; Newton s Law

Systems Analysis and Control

Series and Parallel Resonances

ELEC 372 LECTURE NOTES, WEEK 11 Dr. Amir G. Aghdam Concordia University

CHAPTER 5. Solutions for Exercises

Chapter 9 Compressible Flow 667

Limitations for Op Amps due to input signal

The bending of a wave around an obstacle or the edges of an opening is called diffraction.

Lecture 20a. Circuit Topologies and Techniques: Opamps

Q1. A) 48 m/s B) 17 m/s C) 22 m/s D) 66 m/s E) 53 m/s. Ans: = 84.0 Q2.

Fields and Waves I. Lecture 3

CHAPTER 11. Solutions for Exercises. (b) An inverting amplifier has negative gain. Thus L

which represents a straight line whose slope is C 1.

Session #22: Homework Solutions

제어이론복습 강의보조자료. 박상혁

ENGI 4430 Parametric Vector Functions Page 2-01

A NEW APPROACH TO OPERATIONAL MODAL ANALYSIS BASED ON MULTIVARIABLE TRANSMISSIBILITY FUNCTIONS

Fourier Analysis, Low Pass Filters, Decibels

Philadelphia University Faculty of Engineering Communication and Electronics Engineering

ME 3600 Control Systems Frequency Domain Analysis

ECEN620: Network Theory Broadband Circuit Design Fall 2018

Q1. A string of length L is fixed at both ends. Which one of the following is NOT a possible wavelength for standing waves on this string?

Department of Mechanical Engineering Massachusetts Institute of Technology Modeling, Dynamics and Control III Spring 2002

SIMON FRASER UNIVERSITY School of Engineering Science ENSC 320 Electric Circuits II. Solutions to Assignment 3 February 2005.

Supplementary Course Notes Adding and Subtracting AC Voltages and Currents

Physics 11 HW #9 Solutions

First and Second Order Circuits. Claudio Talarico, Gonzaga University Spring 2015

The pn Junction. Φ = n. 2.1 The pn junction under forward bias (steady-state)

Massachusetts Institute of Technology 2.71/2.710 Optics Spring 2014 Solution for HW2

Lyapunov Stability Stability of Equilibrium Points

6. Frequency Response

3.6 Condition number and RGA

Chapter 5. Root Locus Techniques

Calculus Placement Review. x x. =. Find each of the following. 9 = 4 ( )

39th International Physics Olympiad - Hanoi - Vietnam Theoretical Problem No. 1 /Solution. Solution

G(s) = 1 s by hand for! = 1, 2, 5, 10, 20, 50, and 100 rad/sec.

Improving Power System Transient Stability with Static Synchronous Series Compensator

Given the following circuit with unknown initial capacitor voltage v(0): X(s) Immediately, we know that the transfer function H(s) is

Lecture 4. Chapter 11 Nise. Controller Design via Frequency Response. G. Hovland 2004

NUMBERS, MATHEMATICS AND EQUATIONS

Unit-I (Feedback amplifiers) Features of feedback amplifiers. Presentation by: S.Karthie, Lecturer/ECE SSN College of Engineering

ELG3150 DGD 6 P9.5; P9.7; P9.13; P9.18; AP9.5; DP9.2

Exam 1 Solutions. Prof. Darin Acosta Prof. Selman Hershfield February 6, 2007

Lecture 7: Damped and Driven Oscillations

Thermochemistry. Thermochemistry

Impedance matching concept given ZL, design a matching network to have in=0 or selected value. matching. Zin (=Z Z o )

Edexcel GCSE Physics

Microelectronic Circuits II. Ch 8 : Frequency Response

Delhi Noida Bhopal Hyderabad Jaipur Lucknow Indore Pune Bhubaneswar Kolkata Patna Web: Ph:

Chapter 30. Inductance

Dr. Kasra Etemadi February 27, 2007

(b) Using the ideal gas equation of state, and noting that the total mass of gas occupies the same total volume at the final state as initially: where

ω r. Chapter 8 (c) K = 100 ω ζ M ω

( ) ( ) ( ) ( ) ( z) ( )

Orthogonal Signals With orthogonal signals, we select only one of the orthogonal basis functions for transmission:

55:041 Electronic Circuits

R10 JNTUWORLD B 1 M 1 K 2 M 2. f(t) Figure 1

Stability of Operational amplifiers

Digital Control System

Lecture 5 Introduction to control

Copyright Paul Tobin 63

SKEE 3143 CONTROL SYSTEM DESIGN. CHAPTER 3 Compensator Design Using the Bode Plot

Mitigation of Stability Problem in a Boost Converter having an Input Filter.

15.0 g Cr = 21.9 g Cr O g Cr 4 mol Cr mol Cr O

Homework Assignment No. 3 - Solutions

Sections 15.1 to 15.12, 16.1 and 16.2 of the textbook (Robbins-Miller) cover the materials required for this topic.

Main Menu. SEG Houston 2009 International Exposition and Annual Meeting. Summary

6. Negative Feedback in Single- Transistor Circuits

CHAPTER 6 WORK AND ENERGY

Transcription:

Feedack and Ocillatr Len # Tranient and Frequency Repne Sectin 9.6- BME 373 Electrnic II J.Scheer 78

Cled-Lp Gain in the Frequency Dmain ume that th the pen-lp gain, and the eedack, β are unctin requency and we apply the Laplace tranrm cmplex variale σ: Therere, β the zer are the value which h atiy the ple are the value which atiy β BME 373 Electrnic II J.Scheer 79

Ple Slutin t β deine the tranient repne the ampliier Thee lutin can e either real r cmplex value Fr real value ± σ, the tranient repne will have the rm exp ± σt and will dampen ut - σ with time cntant /σ r grw σ Ple which are negative are deirale ecaue the tranient repne die ut; while ple which are pitive are undeirale ecaue will caue the ampliier t unctin uncntrllaly. BME 373 Electrnic II J.Scheer 8

Cmplex Plane Cmplex Numer and Phar Ntatin Im σ cmplex numer σ tan σ Phar -σ θ Re Nte that ple in the right hand plane will have pitive real part and the tranient t repne will grw expnentially BME 373 Electrnic II J.Scheer 8

Cmplex Plane Cmplex Cnugate Ple -σ θ Im Re a σ * σ σ tan σ * σ tan σ Cmplex cnugate yield tranient repne the rm : * ± e σt ct Bin t Ple in the right hand plane will grw while ple in the let hand plane dampen BME 373 Electrnic II J.Scheer 8

Tranient Slutin in the Cmplex Plane t t 3 3 - - - 8 -. -. 3 - - - -8-6 -4 - Mt deirale lutin ince tranient repne die ut quickly. 3 -. - t. t 6 3 -. 4 t σ 3 - - 3 t t Nte: Cnugate nt hwn BME 373 Electrnic II J.Scheer 83

Frequency Repne Plt the magnitude netwrk unctin a a unctin Sketch the magnitude y: Calculate the magnitude r and I there are real ple, etimate the reakpint requencie a / pk and the value the magnitude the netwrk unctin I there are cmplex ple, etimate the maximum the netwrk unctin at the value Imaginary part r each ple Set the unctin t zer at the zer the netwrk unctin Fr netwrk unctin with nly real ple: The with ple urthet rm the rigin have higher 3-dB cut requencie Fr netwrk unctin with cmplex ple: gain peak will ccur at the imaginary part the ple The gain peak will e maller r the ple where the real part σ i greater than the imaginary part. BME 373 Electrnic II J.Scheer 84

Example # Ω h Repne Frequency in / v in v ut C L R C in LC CR in repne damped inuid tranient ±.4 4 li BME 373 Electrnic II J.Scheer 8 lim

Example # Cntinued Etimated 6 Calculated 4 3 3 BME 373 Electrnic II J.Scheer 86

E l # R F Example # 7 Ω h Repne Frequency in / v in v ut LC CR C L R C in 4 7 LC CR in 4 lim decaying expnential repne tranient, 7.4*.39 9 4 4 4 BME 373 Electrnic II J.Scheer 87 decaying expnential.67.4*.39

Example # Cntinued.67 Etimated..8 Calculated.6.4. 4 6 8 BME 373 Electrnic II J.Scheer 88

Example #3 h / Repne Frequency in Ω v in v ut LC CR CR C L R R in LC CR in repne damped inuid tranient ±.998 4 li BME 373 Electrnic II J.Scheer 89 repne damped inuid tranient ± lim

Example #3 Cntinued.998 Etimated. Calculated.8.6.4. 3 BME 373 Electrnic II J.Scheer 9

Eect Feedack n Ple Lcatin Single Ple mpliier the rm : an ampliier i Let' aume that the pen - circuit gain ] [ β β π π dding eedack t the ampliier : ] [ π β π π β π, where : β β π π β β BME 373 Electrnic II J.Scheer 9

Example # Study the requency repne an ampliier with pen-lp mid-and gain and reak requency z r eedack β.,. and d Withut eedack : lg lg db z With β.: β. db 99.9 lg lg99.9 4 β. k z With β.: db β. lg β k z With β : β db BME 373 Electrnic II J.Scheer lg β M z 9

Example # Cntinued Gain-Bandwidth Prduct db β.... z. E6 E7 β, β β β Nte that a the eedack i increaed i.e., β increae the ple mve urther away rm the rigin. Fr ingle ple ampliier, thi al implie that the tranient time cntant decreae ince τ /π. BME 373 Electrnic II J.Scheer 93

Example #a Fr the Single Ple ampliier, ind the ple r the pen lp gain. Prepare a Bde Plt Find the Gain-Bandwidth Prduct v i - M Ω Rpk Ω R Ω v x v i - v Cp - x v - - 7.96 µf v v v x v v i 3 C C p R C p 7.96x 6 p R p p v i R C 7.96x p p 3 v v v 7.96x 3 lg db db z 7.96x 3 π BME 373 Electrnic II J.Scheer v z 3 π 7.96x z Mz 94

Example # Uing the ampliier in in the llwing eedack circuit, calculate: β Cled-lp gain at DC Cled-lp lp andwidth k β. k 99k β. 99.9 3 3 β kz v i -- v v i -- -- - 99k k -- v BME 373 Electrnic II J.Scheer 9

Gain and Phae Margin Staility Feedack mpliier Examine the Cled-lp gain a a unctin requency Fr a given requency, β -, then the cled-lp l gain will e ininite i.e., a ple at π Nte that withut a urce ignal, then the input ignal equal the eedack ignal and v in -β v ut When the phae β 8 i β <, the lped ignal decay in amplitude Stale i β >, the lped ignal grw in amplitude - Untale We deine Gain Margin, which i the amunt in db gain elw db when the phae β 8. The larger the gain margin the mre tale the ampliier i.e., the ple are deeper int the let hand -plane. We deine the Phae Margin, which i deined at the requency, pm, at which β pm i unity and i equal t the dierence etween the phae β pm and 8. The larger the phae margin the mre tale the ampliier. BME 373 Electrnic II J.Scheer 96

Staility a Feedack mpliier β db - βα φ Phae deg 36 z.e.e.e4.e6.e8.e 8 - -3-4 -8 - -36 PM 8-68 PM 76.6 kz kz π 3 β. GM -9dB GM 73 kz BME 373 Electrnic II J.Scheer 97

Tranient trepne Prlem: 9.8-9 mewrk Eect Feedack n Ple Lcatin Prlem: 9.63-66 Gain and Phae Margin Prlem: 9.7-7373 BME 373 Electrnic II J.Scheer 98