Atomic Spectroscopy II

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Applied Spectroscopy Atomic Spectroscopy II Multielectron Atoms Recommended Reading: Banwell And McCash Chapter 5

The Building-Up (aufbau) Principle How do the electrons in multi-electron atoms get distributed among the orbitals? Basic rules: ) Pauli s principle: no two electrons can have the same set of quantum numbers, i.e. the same values for n, l, m, m s. Example: s orbital, n =, l = 0, m l = 0: only quantum number that can be different is the m s which can have the values +/ and -/. s (or ns ) orbital can only hold two electrons with opposite spins. s orbital the electrons can have the quantum numbers (n =, l = 0, m l = 0, m s = +/ ) and (n =, l = 0, m l = 0, m s = -/ ) Example: a p-orbital, np, l =, m l = -, 0, +, and m s = ±½. so allowed quantum numbers are: (n, l =, m l = -, m s = ±½. ) So p-orbital can hold 6 electrons. (n, l =, m l = 0, m s = ±½. ) Three with spin up and three with (n, l =, m l = +, m s = ±½. ) spin down.

) Electrons tend to occupy the orbital with the lowest energy available Orbitals have the following order in energy and fill up in this order: s < s < p < 3s < 3p < 4s < 3d < 4p < 5s < 4d <. (some exceptions) When the s orbital is full ( He, electrons) the next electron will go into the s orbital (Li, Be), then the p orbitals (B, C, N, O, F, Ne) and so on. 3) Hund s principle: electrons tend to occupy degenerate orbitals singly with their spins parallel. Example: when a p x orbital contains an electron the next electron goes into p y or p z orbital with its spin parallel to the electron in the p x orbital. When a set of orbitals of given n and l is filled it forms a closed shell. Examples: s orbital in He, the s orbital of Be, the p6 orbital of Ne

Atom s s p 3s configuration Hydrogen s Helium s Closed Lithium s s Berylium s s Closed Boron s s p Carbon s s p Nitrogen s s p 3 Oxygen s s p 4 Fluorine s s p 5 Neon s s p 6 Closed Sodium s s p 6 3s Magnesium s s p 6 3s Closed etc Electronic structure of first atoms in the periodic table.

A closed shell orbital makes no contribution to the angular momentum of an atom. For example consider a filled s orbital, ns : each s electron has l = 0, so total orbital angular momentum is L = l + l = 0 + 0 = 0 total spin angular momentum is S = s + s = / + (-/) = 0 Total angular momentum is J = L + S = 0

The Spectrum of Alkali Metals The alkali metals, Lithium Li, Sodium Na, potassium K, Rubidium Rb, Cesium Cs, occupy column of the periodic table (underneath H). All have a closed inner core and a single outer s- electron Li: s s [He] s Na: s s p 6 3s [Ne] 3s K: s s p 6 3s 3p 6 4s [Ar] 4s Superficially all resemble the hydrogen atom. To a first approximation we can ignore the angular momentum of the closed shell core and deal with the spin and orbital momentum of the outer electron. By analogy with the hydrogen atom, we expect the p, d, f,... levels to be split into doublets because of the coupling between l and s.

Example: Spectrum of Lithium

Energy Levels of Alkali atoms Outer ns electron Charge = -e Nucleus: Charge = +Ze Closed Shell of core electrons. Charge = -(Z-)e The (Z-) core electrons screen the outer s-electron from the Z positive charges in the nucleus. At large distances from the nucleus the s-electron experiences a potential e Close to the nucleus the V(r) = larger 4πεor electron sees the full potential Ze V(r) = small r 4πεor

This potential is always greater than the corresponding potential for the hydrogen atom stronger Coulomb attraction energy levels in alkali halides lie at lower energies than the corresponding energy level in hydrogen, e.g. energy of p level in Li < energy of p in H, etc. We can write the potential as V(r) = Zeff e 4πε r o all r Where Z eff is the effective nuclear charge seen by the outer s-electron, which will depend on the quantum numbers n and l each orbital will have a different value of Z eff. = Z σ( n,l ) Z eff where σ(n, l) is the screening parameter. Then, by analogy with the hydrogen atom [ ( )] Z σ n, l En, l = hcr n This model works well for x-ray spectra transitions involving inner shell electrons. This approach is logical and is analogous with the derivation of the energy levels in H....

historically the spectra of the alkali metals were explained using a formula very similar to that used by Balmer to explain the spectrum of hydrogen En, l = hcr = hcr [ ] n * n δl where n* = (n - δ l ) is the principal quantum number and δ l is called the quantum defect. Note that n* is not necessarily an integer! From this expression we can then calculate the wavenumber of transitions in the alkali metals Δε = E E hc ( ) ε - ε = n n cm ~ ν = R cm [ ] [ ] n δ( l) n δ( l) The quantum defects are determined by measurement from the spectra of the alkali metals.

Quantum Defect Table of experimentally determined quantum defects in Alkali Metals s p d f l = 0 l = l = l = 3 Li s 0.40 0.04 0.00 0.00 Na 3s.35 0.85 0.0 0.00 K 4s.9.7 0.5 0.00 Rb 5s 3.3.66.34 0.0 Cs 6s 4.06 3.59.46 0.0 Examples: The Cs 6s electron has an effective principal quantum number n* = n - δ(s) = (6-4.06) =.94 Cs 6d electron has an effective principal quantum number n* = n - δ(d) = (6 -.46) = 3.54 K 4p electron has an effective principal quantum number n* = n - δ(p) = (4 -.7) =.9 Using this table of quantum defects we can then calculate the energy levels and then work out the energies of transitions in these metals.

Example: the 3p 3s transition in Na, (strong yellow line) First find the quantum defects for the 3p and 3s states δ(s) =.35 and δ(p) = 0.85 Then E3p = hcrna E 3s = hcrna 3 0.85 3 From which E E [ ] [ ] 3.35 [ 3 0.85] [.35] ~ 3s 3p ν = = R Na cm =.6964cm hc Where we have used R Na µ M m = Na R = Na e R m m e e ( ) M + m Na e We can also calculate the ionization potentials as follows I P = hcr [ n δ( l) ]

Example: For Na n = 3 and δ(s) =.35 IP ( 3s) = hcrna = [ 3.35] 5.4eV In a similar manner the ionization potentials for the outer s-electrons in the other Alkali metals are: Li Na K Rb Cs I p (ev) 5.39 5.4 4.34 4.8 3.89 Note that this is the ionization potential from the ground state. It is also possible to calculate the ionization potentials for excited states, for example, the ionization potential for the (excited) 5p state in K would be IP ( 5p) = hcrk [ 5.7]

Term Symbols for Alkalis Since we are dealing with a single outer s-electron, these should be the same as those for Hydrogen Ground state has a single s-electron ns l = 0, s = / S / Excited states are: n s l = 0, s = /, j = / S / n p l =, s = /, j = /, 3/ P /, P 3/ n d l =, s = /, j = 3/, 5/ D 3/, D 5/ and so on Absorption Spectroscopy: Pass light through alkali vapor and measure amount of absorption at each wavelength. At room (or low temp) all atoms will be in the S / ground state. From selection rules, only n 0 s np transitions allowed, where n 0 is the principal quantum number of ground state electron, (n 0 = for Li, n 0 = 3 for Na etc.) only one series of lines seen in absorption spectra of alkalis

For example, in Li the following absorptions can take place: s p, 3p, 4p, terms involved are n 0 S / n P /, n P 3/ each line will be a doublet due to the fine structure. This is called the Principal Series. Emission Spectroscopy Excite alkali vapour by heating it or by passing an electrical discharge through it. Atoms will emit as they decay back to the ground state. The principal series is also seen in emission as the excited np electrons return to the n 0 s ground state. The strongest emission line always corresponds to the n 0 p n 0 s transition this is called the resonance line. For example, in Na the 3p 3s transition gives rise to a doublet at 589.0 and 589.6 nm, this transition gives Na street lights their characteristic yellow color. Atom n 0 cm - nm Table of Resonance Line wavenumbers and wavelengths: Li 4904 670.0 Na 3 6956 589.0 6973 589.6 K 4 985 769.9 3043 766.5

Resonance Lines

Other transition lines are also observed in emission spectra of the alkalis, including: Sharp Series ns n 0 p terms involved are n S / n 0 P /, n 0 P 3/ Diffuse Series nd n 0 p terms involved are n D 3/ n 0 P /, n 0 P 3/ n D 5/ n 0 P 3/ Fundamental Series nf n 0 d terms involved are n F 5/ n 0 D 3/, n 0 D 5/ n F 7/ n 0 D 5/

Sodium Energy Levels and Emission Lines Note that fine structure is not shown in this diagram, so splitting of the p, d, f levels due to l- s coupling is not shown Fundamental Sharp Diffuse Principal

Lithium Energy Levels and Emission Lines Fundamental Sharp Diffuse Principal