ENERGY TRANSFER BY WORK: Electrical Work: When N Coulombs of electrical charge move through a potential difference V

Similar documents
AE1104 Physics 1. List of equations. Made by: E. Bruins Slot

King Fahd University of Petroleum & Minerals

ME 2322 Thermodynamics I PRE-LECTURE Lesson 10 Complete the items below Name:

ME Thermodynamics I

Delft University of Technology DEPARTMENT OF AEROSPACE ENGINEERING

Engineering Thermodynamics. Chapter 6. Entropy: a measure of Disorder 6.1 Introduction

Dishwasher. Heater. Homework Solutions ME Thermodynamics I Spring HW-1 (25 points)

CHAPTER 7 ENTROPY. Copyright Hany A. Al-Ansary and S. I. Abdel-Khalik (2014) 1

ME 2322 Thermodynamics I PRE-LECTURE Lesson 23 Complete the items below Name:

Chapter 7. Entropy: A Measure of Disorder

Chapter 7. Entropy. by Asst.Prof. Dr.Woranee Paengjuntuek and Asst. Prof. Dr.Worarattana Pattaraprakorn

Entropy and the Second Law of Thermodynamics

Today lecture. 1. Entropy change in an isolated system 2. Exergy

ME 200 Thermodynamics 1 Fall 2017 Exam 3

Lecture 44: Review Thermodynamics I

Chapter 5: The First Law of Thermodynamics: Closed Systems

Entropy and the Second Law of Thermodynamics

Week 5. Energy Analysis of Closed Systems. GENESYS Laboratory

Thermodynamics is the Science of Energy and Entropy

Lecture 35: Vapor power systems, Rankine cycle

SOLUTION: Consider the system to be the refrigerator (shown in the following schematic), which operates over a cycle in normal operation.

The First Law of Thermodynamics. By: Yidnekachew Messele

first law of ThermodyNamics

ECE309 INTRODUCTION TO THERMODYNAMICS & HEAT TRANSFER. 20 June 2005

Previous lecture. Today lecture

Dr Ali Jawarneh. Hashemite University

(1)5. Which of the following equations is always valid for a fixed mass system undergoing an irreversible or reversible process:

Chapter 1: Basic Definitions, Terminologies and Concepts

ME 354 THERMODYNAMICS 2 MIDTERM EXAMINATION. Instructor: R. Culham. Name: Student ID Number: Instructions

Chapter 5. Mass and Energy Analysis of Control Volumes. by Asst. Prof. Dr.Woranee Paengjuntuek and Asst. Prof. Dr.Worarattana Pattaraprakorn

Thermodynamics II. Week 9

ME 201 Thermodynamics

I. (20%) Answer the following True (T) or False (F). If false, explain why for full credit.

5/6/ :41 PM. Chapter 6. Using Entropy. Dr. Mohammad Abuhaiba, PE

Exergy and the Dead State

ME 2322 Thermodynamics I PRE-LECTURE Lesson 23 Complete the items below Name:

CLAUSIUS INEQUALITY. PROOF: In Classroom

III. Evaluating Properties. III. Evaluating Properties

Chapter 5. Mass and Energy Analysis of Control Volumes

Number of extra papers used if any

KNOWN: Data are provided for a closed system undergoing a process involving work, heat transfer, change in elevation, and change in velocity.

CHAPTER 8 ENTROPY. Blank

Chapter 4. Energy Analysis of Closed Systems

ME Thermodynamics I. Lecture Notes and Example Problems

CONCEPTS AND DEFINITIONS. Prepared by Engr. John Paul Timola


In the next lecture...

ECE309 INTRODUCTION TO THERMODYNAMICS & HEAT TRANSFER. 13 June 2007

Where F1 is the force and dl1 is the infinitesimal displacement, but F1 = p1a1

2-21. for gage pressure, the high and low pressures are expressed as. Noting that 1 psi = kpa,

Outline. Property diagrams involving entropy. Heat transfer for internally reversible process

Chapter 8. The increased awareness that the world s energy EXERGY: A MEASURE OF WORK POTENTIAL. Objectives

Thermodynamics I Spring 1432/1433H (2011/2012H) Saturday, Wednesday 8:00am - 10:00am & Monday 8:00am - 9:00am MEP 261 Class ZA

ENT 254: Applied Thermodynamics

Lecture 38: Vapor-compression refrigeration systems

Thermodynamics: An Engineering Approach Seventh Edition Yunus A. Cengel, Michael A. Boles McGraw-Hill, Chapter 7 ENTROPY

20 m neon m propane. g 20. Problems with solutions:

ME 200 Final Exam December 14, :00 a.m. to 10:00 a.m.

ENTROPY. Chapter 7. Mehmet Kanoglu. Thermodynamics: An Engineering Approach, 6 th Edition. Yunus A. Cengel, Michael A. Boles.

Eng Thermodynamics I conservation of mass; 2. conservation of energy (1st Law of Thermodynamics); and 3. the 2nd Law of Thermodynamics.

ME 201 Thermodynamics

Chapter 6. Using Entropy

Non-Newtonian fluids is the fluids in which shear stress is not directly proportional to deformation rate, such as toothpaste,

CHEMICAL ENGINEERING THERMODYNAMICS. Andrew S. Rosen

Unit B-1: List of Subjects

Find: a) Mass of the air, in kg, b) final temperature of the air, in K, and c) amount of entropy produced, in kj/k.

Circle your instructor s last name

+ m B1 = 1. u A1. u B1. - m B1 = V A. /v A = , u B1 + V B. = 5.5 kg => = V tot. Table B.1.

MAE 320 HW 7B. 1e. For an isolated system, please circle the parameter which will change with time. (a) Total energy;

CHAPTER 5 MASS AND ENERGY ANALYSIS OF CONTROL VOLUMES

c Dr. Md. Zahurul Haq (BUET) Thermodynamic Processes & Efficiency ME 6101 (2017) 2 / 25 T145 = Q + W cv + i h 2 = h (V2 1 V 2 2)

Thermodynamics: An Engineering Approach Seventh Edition in SI Units Yunus A. Cengel, Michael A. Boles McGraw-Hill, 2011.

Isentropic Efficiency in Engineering Thermodynamics

MAE 11. Homework 8: Solutions 11/30/2018

SUMMARY AND CONCEPTS FOR. Introduction to Engineering Thermodynamics by Sonntag and Borgnakke First edition. Wiley 2001

PTT 277/3 APPLIED THERMODYNAMICS SEM 1 (2013/2014)

Reading Problems , 8-34, 8-50, 8-53, , 8-93, 8-103, 8-118, 8-137

MAE 110A. Homework 3: Solutions 10/20/2017

The exergy of asystemis the maximum useful work possible during a process that brings the system into equilibrium with aheat reservoir. (4.

Chapter 1 Introduction and Basic Concepts

Thermodynamics of solids 5. Unary systems. Kwangheon Park Kyung Hee University Department of Nuclear Engineering

Chapter 7. Dr Ali Jawarneh. Department of Mechanical Engineering Hashemite University

BME-A PREVIOUS YEAR QUESTIONS

Week 2. Energy, Energy Transfer, And General Energy Analysis

Entropy balance special forms. Quasiequilibrium (QE) process. QE process is reversible. dt Tk = = +

Thermodynamics Lecture Series

- Apply closed system energy balances, observe sign convention for work and heat transfer.

Thermodynamics ENGR360-MEP112 LECTURE 3

THERMODYNAMICS NOTES. These notes give a brief overview of engineering thermodynamics. They are based on the thermodynamics text by Black & Hartley.

Second Law of Thermodynamics -

Engineering Thermodynamics

8.21 The Physics of Energy Fall 2009

2. Describe the second law in terms of adiabatic and reversible processes.

ME 200 Thermodynamics 1 Spring Exam 2

Name: I have observed the honor code and have neither given nor received aid on this exam.

MAE 320 THERODYNAMICS FINAL EXAM - Practice. Name: You are allowed three sheets of notes.

Chapter 5 MASS AND ENERGY ANALYSIS OF CONTROL VOLUMES

THERMODYNAMICS, FLUID AND PLANT PROCESSES. The tutorials are drawn from other subjects so the solutions are identified by the appropriate tutorial.

ME6301- ENGINEERING THERMODYNAMICS UNIT I BASIC CONCEPT AND FIRST LAW PART-A

Ttions, and its relation to states of matter. This chapter covers the

Transcription:

Weight, W = mg Where m=mass, g=gravitational acceleration ENERGY TRANSFER BY WOR: Sign convention: Work done on a system = (+) Work done by a system = (-) Density, ρ = m V kg m 3 Where m=mass, V =Volume Specific volume, v = V m = ρ Specific gravity, SG = Where r HO =000 kg/m 3 P gage = P Abs P atm m 3 kg Variation of pressure with depth: Apply between two pots the same fluid. Where below refers to pot at lower elevation and above at higher elevation P below = P above + ρg z The absolute and gage pressures a liquid open to the atmosphere at a depth of h from the free surface are: etic Energy: Where m=mass, V=velocity Potential Energy: P = P atm + ρgh E = m V ρ ρ H O P vac = P atm P abs P gage = ρgh ke = V PE = mgz pe = gz Where m=mass, g=gravitational acceleration, z=elevation SPECIFIC HEAT RELATIONS FOR IDEAL GAS: c v = δu u = u u = c v T dt δt v c p = δh δt p h = h h = c p T dt Variation of spec. heats with T is smooth and may be approx. as lear over small T terval. Can replace specific heat with C avg, yieldg: Electrical Work: When N Coulombs of electrical charge move through a potential difference V W e = VN In the rate form, W e = VI = I R = V R Electrical work done durg a time terval t: Where W e is the electrical power and I is the current. W e = VI dt Or when V and I rema constant durg terval t: W e = VI t Mechanical Forms of Work: W = Fs W = Fds Work done by a constant force, F on a body displaced a distance s Boundary Work: W b = Pdv Constant P process: W b = P(V V ) Polytropic process: W b = P V P V n Shaft Work: W sh = π n T (kw) Where n is the number of revolutions per unit time Sprg Work: W sprg = k x x Where x and x are the itial and fal displacements of the sprg. Polytropic Ideal Gas process: Polytropic Isothermal Ideal Gas process: INTERNAL ENERGY, ENTHALPY & SPECIFIC HEATS OF SOLIDS & LIQUIDS For an compressible substance: c p = c v = c u = u u = c avg T T h = u + v P c avg T T + v P W b = mr(t T ) n W b = PV ln V V = mrt o ln V V (W) Durg actual exp/comp process of gases, P and V are related by PV n =C. Where n and C are constants therefore between states, ideal gas, closed C = P V = P V = mrt 0 V V = P P u u = c v,avg T T, h h = c p,avg (T T ) c p = c v + R kj kg, k c p c v

P-v Diagram T-v Diagram SUPERHEATED STATE Region to the right of sat vap le & at a T above T cr To determe if S.H. P<P sat at given T T> T sat at given P v>v g at given P or T u> u g at given P or T h> h g at given P or T s> s g at given P or T COMPRESSED LIQUID STATE Region to the left of the Sat Liq le In the absence of C.L. data treat a C.L. as a Sat liq at given T To determe if C.L. P>P sat at given T T< T sat at given P v< v f at given P or T u< u f at given P or T h< h f at given P or T s< s f at given P or T Quality, x = y f y f@t Where y is v, u, s or h Quality, x = 0 SATURATED LIQUID-VAPOR MIXTURE STATE Region under the dome To determe the proportion of liquid and vapor phases the mixture, fd quality, x x = m vapor m total, Quality, 0 < x < To fd v, h, u, s at state. Where y is v, u, s or h y = y f + x y g y f To determe if Sat Liq-vap Mixture. v f v v g u f u u g h f h h g s f s s g m total= mliq +m vap =m f +m g

POWER CYCLES: Expandg the equation: (m m ) =

HEAT ENGINES Thermal Efficiency of HE, th th = W net, Q = Q Q W net, = Q Q ENERGY BALANCE: CLOSED SYSTEM E sys = E E U + E + PE = E E Expandg both the left and right side of the equation: SIMPLIFY ENERGY BALANCE FOR CLOSED SYSTEM Step : Defe system of terest and simplify E-bal. Step : If Stationary then E= PE=0 Step 3: Determe if have Q or Q if Adiabatic Q=0 Step 4: Determe if have W b, W paddle, W electrical m u u + m V V + mg z z = (Q +W ) (Q + W ) HEAT PUMP: REFRIGERATOR: The objective of a HP is to keep a warm space warm Coefficient of Performance for HP, COP HP COP HP = COP HP = Desired put Required put = Q L = COP HP = COP R + W net, The objective of a Refrigerator is to keep a cold space cold Q L / ENERGY BALANCE: OPEN SYSTEM, STEADY STATE E sys = E E Expandg the equation: Q + W + m(h + V MASS BALANCE: OPEN SYSTEM, STEADY STATE m sys = m Sce m sys =0 for SS 0 = m m m Sce E sys = 0 for SS 0 = E E + gz) = Q + W + m(h + V mass flow rate, m = ρva For Steady, compressible flow: V = V ENERGY BALANCE: OPEN SYSTEM, UNSTEADY-FLOW + gz) Volumetric flow rate, V = VA = m/ρ CARNOT REFRIGERATOR COP R,REV = T L /T H CARNOT REFIGERATION CYCLE COP R = COP R = Desired put Required put = Q l W net, Q l = Q L Q L / E sys = E E U + E + PE = E E Expandg the equation: U + E + PE = Q + W + MASS BALANCE: OPEN SYSTEM, UNSTEADY-FLOW m(h + V + gz) (Q + W + m(h + V + gz)) m sys = (m m ) = th < th,rev Irreversible HE = th,rev Reversible HE CARNOT HEAT ENGINE: th,rev = T L T H CARNOT HEAT PUMP: COP HP,REV = T L /T H Q L REV = T L T H > th,rev Impossible HE CARNOT HE CYCLE

ENTROPY, S: ds = δq T INT REV FIND THE CHANGE IN ENTROPY: S = S S = INCREASE OF ENTROPY PRINCIPLE: S SYS = S S = δq T INTERNALLY REVERSIBLE ISOTHERMAL HEAT TRANSFER : S = Q T O S gen = 0 > 0 Irreversible Reversible < 0 Impossible ISENTROPIC PROCESS: INT REV δq T + S gen A ternally reversible, adiabatic process S = 0 or S = S ENTROPY CHANGE OF LIQUIDS AND SOLIDS: S S = dt c(t) T c avgln T T Where c avg is the average specific heat of the substance over the given temperature terval SPECIAL CASE: ISENTROPIC LIQUIDS & SOLIDS S S = c avg ln T T = 0 T = T ISENTROPIC EFFICIENCIES OF STEADY-FLOW DEVICES TURBINE T = Actual Turbe Work Isentropic Turbe Work = w a h h a w s h h s COMPRESSOR Isentropic Compressor Work T = Actual Compressor Work ENTROPY CHANGE OF IDEAL GAS: CONSTANT SPECIFIC HEAT (Approximate Analysis: for when T is small < 300 ) S S = c v,avg ln T T + R ln v v S S = c p,avg ln T T R ln P P ISENTROPIC PROCESS OF IDEAL GAS: CONSTANT SPECIFIC HEAT T T S=CONST = v v T T S=CONST = P P P P S=CONST = v v k (k )/ GENERAL ENTROPY BALANCE S sys = S S + S gen k Mechanisms of Entropy Transfer = Q and m = w s w a h s h h a h R/c v = k ENTROPY BALANCE: OPEN SYSTEM S sys = S S = + m T i s i m e s e + S gen ENTROPY BALANCE: OPEN SYSTEM-STEADY FLOW 0 = + m T i s i m e s e + S gen NOZZLE Actual E a nozzle exit N = Isentropic E at nozzle exit = V a = h h a V S h h s PUMP P = w s w a = v(p P ) h a h ENTROPY CHANGE OF IDEAL GAS: VARIABLE SPECIFIC HEAT (Exact Analysis: for when T is large & specific heats vary non-learly w/ T range) S S = S S R ln P P ISENTROPIC PROCESS OF IDEAL GAS: VARIABLE SPECIFIC HEAT P P S=CONST = P r P r v v S=CONST = v r v r ENTROPY BALANCE: CLOSED SYSTEM S sys = S S = + S T gen ENTROPY BALANCE: ADIABATIC CLOSED SYSTEM S sys = S gen ENTROPY BALANCE: ADIABATIC CLOSED SYSTEM AND SURROUNDINGS S gen = S sur = Q surr T surr S = S system + S surroundgs