Pendulum in Orbit. Kirk T. McDonald Joseph Henry Laboratories, Princeton University, Princeton, NJ (December 1, 2017)

Similar documents
Classical Mechanics Homework set 7, due Nov 8th: Solutions

Physics 181. Assignment 4

Translation and Rotation Kinematics

AST 121S: The origin and evolution of the Universe. Introduction to Mathematical Handout 1

HW Solutions # MIT - Prof. Please study example 12.5 "from the earth to the moon". 2GmA v esc

AY 7A - Fall 2010 Section Worksheet 2 - Solutions Energy and Kepler s Law

Circular Motion & Torque Test Review. The period is the amount of time it takes for an object to travel around a circular path once.

MASSACHUSETTS INSTITUTE OF TECHNOLOGY Physics Department. Problem Set 10 Solutions. r s

= 4 3 π( m) 3 (5480 kg m 3 ) = kg.

Mechanics Physics 151

AH Mechanics Checklist (Unit 2) AH Mechanics Checklist (Unit 2) Circular Motion

OSCILLATIONS AND GRAVITATION

ASTR415: Problem Set #6

Newton s Laws, Kepler s Laws, and Planetary Orbits

Chapter 13 Gravitation

Physics 161 Fall 2011 Extra Credit 2 Investigating Black Holes - Solutions The Following is Worth 50 Points!!!

Objective Notes Summary

Central Force Problem. Central Force Motion. Two Body Problem: Center of Mass Coordinates. Reduction of Two Body Problem 8.01 W14D1. + m 2. m 2.

PHYSICS NOTES GRAVITATION

Exam 3: Equation Summary

10. Force is inversely proportional to distance between the centers squared. R 4 = F 16 E 11.

Principles of Physics I

ω = θ θ o = θ θ = s r v = rω

Experiment 09: Angular momentum

F 12. = G m m 1 2 F 21 = F 12. = G m 1m 2. Review. Physics 201, Lecture 22. Newton s Law Of Universal Gravitation

Chapter 12. Kinetics of Particles: Newton s Second Law

Extra notes for circular motion: Circular motion : v keeps changing, maybe both speed and

A New Approach to General Relativity

Physics 506 Winter 2006 Homework Assignment #9 Solutions

Unit 6 Test Review Gravitation & Oscillation Chapters 13 & 15


Between any two masses, there exists a mutual attractive force.

b) (5) What average force magnitude was applied by the students working together?

Physics 2001 Problem Set 5 Solutions

Physics 235 Chapter 5. Chapter 5 Gravitation

- 5 - TEST 1R. This is the repeat version of TEST 1, which was held during Session.

DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS

KEPLER S LAWS AND PLANETARY ORBITS

Exam 3: Equation Summary

m1 m2 M 2 = M -1 L 3 T -2

F(r) = r f (r) 4.8. Central forces The most interesting problems in classical mechanics are about central forces.

d 2 x 0a d d =0. Relative to an arbitrary (accelerating frame) specified by x a = x a (x 0b ), the latter becomes: d 2 x a d 2 + a dx b dx c

Galaxy Disks: rotation and epicyclic motion

Chapter 7-8 Rotational Motion

Chap 5. Circular Motion: Gravitation

Tutorial Exercises: Central Forces

Problems with Mannheim s conformal gravity program

Rotational Motion. Every quantity that we have studied with translational motion has a rotational counterpart

Magnetic Dipoles Challenge Problem Solutions

COLLISIONLESS PLASMA PHYSICS TAKE-HOME EXAM

Practice. Understanding Concepts. Answers J 2. (a) J (b) 2% m/s. Gravitation and Celestial Mechanics 287

you of a spring. The potential energy for a spring is given by the parabola U( x)

Uniform Circular Motion

Qualifying Examination Electricity and Magnetism Solutions January 12, 2006

The Schwartzchild Geometry

Central Force Motion

Appendix B The Relativistic Transformation of Forces

Stress, Cauchy s equation and the Navier-Stokes equations

Dynamics of Rotational Motion

Mechanics and Special Relativity (MAPH10030) Assignment 3

GENERAL RELATIVITY: THE GEODESICS OF THE SCHWARZSCHILD METRIC

Chapter 13: Gravitation

Physics 111. Ch 12: Gravity. Newton s Universal Gravity. R - hat. the equation. = Gm 1 m 2. F g 2 1. ˆr 2 1. Gravity G =

arxiv: v1 [physics.pop-ph] 3 Jun 2013

THE LAPLACE EQUATION. The Laplace (or potential) equation is the equation. u = 0. = 2 x 2. x y 2 in R 2

Circular-Rotational Motion Mock Exam. Instructions: (92 points) Answer the following questions. SHOW ALL OF YOUR WORK.

Chapter 5 Force and Motion

Chapter 5 Force and Motion

PROBLEM SET #3A. A = Ω 2r 2 2 Ω 1r 2 1 r2 2 r2 1

06 - ROTATIONAL MOTION Page 1 ( Answers at the end of all questions )

When a mass moves because of a force, we can define several types of problem.

! E da = 4πkQ enc, has E under the integral sign, so it is not ordinarily an

Universal Gravitation

Physics: Work & Energy Beyond Earth Guided Inquiry

Homework 7 Solutions

6.4 Period and Frequency for Uniform Circular Motion

To Feel a Force Chapter 7 Static equilibrium - torque and friction

Galilean Transformation vs E&M y. Historical Perspective. Chapter 2 Lecture 2 PHYS Special Relativity. Sep. 1, y K K O.

SIO 229 Gravity and Geomagnetism. Lecture 6. J 2 for Earth. J 2 in the solar system. A first look at the geoid.

b) (5) What is the magnitude of the force on the 6.0-kg block due to the contact with the 12.0-kg block?

Ch 13 Universal Gravitation

AP * PHYSICS B. Circular Motion, Gravity, & Orbits. Teacher Packet

Gravitation. Chapter 12. PowerPoint Lectures for University Physics, Twelfth Edition Hugh D. Young and Roger A. Freedman. Lectures by James Pazun

Chapter 4. Newton s Laws of Motion

DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS

Right-handed screw dislocation in an isotropic solid

Physics 161: Black Holes: Lecture 5: 22 Jan 2013

From Newton to Einstein. Mid-Term Test, 12a.m. Thur. 13 th Nov Duration: 50 minutes. There are 20 marks in Section A and 30 in Section B.

KEPLER S LAWS OF PLANETARY MOTION

MAGNETIC FIELD INTRODUCTION

Physics C Rotational Motion Name: ANSWER KEY_ AP Review Packet

Computation of the Locations of the Libration Points in the Relativistic Restricted Three-Body Problem

Force of gravity and its potential function

Solving Problems of Advance of Mercury s Perihelion and Deflection of. Photon Around the Sun with New Newton s Formula of Gravity

Spherical Solutions due to the Exterior Geometry of a Charged Weyl Black Hole

Geometry of the homogeneous and isotropic spaces

S7: Classical mechanics problem set 2

c) (6) Assuming the tires do not skid, what coefficient of static friction between tires and pavement is needed?

PHYSICS 220. Lecture 08. Textbook Sections Lecture 8 Purdue University, Physics 220 1

From Gravitational Collapse to Black Holes

Transcription:

1 Poblem Pendulum in Obit Kik T. McDonald Joseph Heny Laboatoies, Pinceton Univesity, Pinceton, NJ 08544 (Decembe 1, 2017) Discuss the fequency of small oscillations of a simple pendulum in obit, say, about the Eath, supposing that the point of suppot of the pendulum is much moe massive than the bob of the pendulum, and the suppot point is in a cicula obit. 2 Solution The suppot point is taken to be at adius R fom the cente of the (spheical) Eath whose mass is M. Then, this point moves with angula velocity Ω = GM/R 3 = g/r with espect to an inetial fame which the cente of the Eath is at est, whee g = GM/R 2 is the acceleation due to gavity at adius R. 1 We ae pehaps most inteested in the motion as would be epoted by an obseve at the point of suppot of the pendulum, so we wok in a otating fame, centeed on the Eath, whose angula velocity is Ω, which is pependicula to the plane of the obit of the suppot point. Of couse, the suppot point is at est in this fame. We use a ectangula coodinate system centeed on the suppot point (O in the figue above, fom [1]), with the z-axis along the vecto R fom the cente of the Eath to the 1 Note that the angula velocity of small oscillations of a pendulum of length l is ω = g/l if its suppot point is at est in an inetial fame with acceleation g due to gavity. 1

suppot point, and the x-axis in the plane of the obit of the latte. Then, the angula velocity of the otating fame is Ω =Ωŷ. The (simple) pendulum has length l andabobofmassm, and is at position x =(x, y, z) whee x 2 + y 2 + z 2 = l 2. The distance fom the cente of the Eath to the bob is x E = R + x =(x, y, z + R), x E R + z. (1) The foces in the otating fame on the bob ae that due to gavity, GMm x E x 3 E centifugal foce, Coiolis foce, = m Ω2 R 3 x E m ( Ω2 x E m x 3 Ω2 1 3z ) (x ˆx + y ŷ + R(1 + z/r) ẑ) E (1 + z/r) 3 R m Ω 2 (x ˆx + y ŷ +(R 2z) ẑ), (2) m Ω (Ω x E )=m Ω 2 [x ˆx +(R + z) ẑ], (3) 2m Ω ẋ =2m Ω(ż ˆx ẋ ẑ), (4) and the tension T = T x in the massless od/sting of the pendulum. To avoid need fo knowledge of the constaint foce T, we conside the toque, τ = x F total, and angula momentum, L = x mẋ of the bob, about the suppot point, dl dt = mx ẍ = m[(y z zÿ) ˆx +(zẍ x z) ŷ +(xÿ yẍ) ẑ] = τ = x m[ Ω 2 y ŷ +3Ω 2 z ẑ +2Ω(ż ˆx ẋ ẑ) T ˆx] = m[ω 2 (yz ˆx xy ẑ)+3ω 2 (yz ˆx xz ŷ) 2Ω(yẋ ˆx +(xẋ zż) ŷ + yż ẑ)]. (5) Hence, the equations of motion can be witten as y z zÿ = 4Ω 2 yz 2Ω yẋ, (6) zẍ x z = 3Ω 2 xz 2Ω(xẋ zż), (7) xÿ yẍ = Ω 2 xy 2Ω yż. (8) The conditions fo equilibium, at which all time deivatives vanish, ae xy = yz = xz =0. These ae satisfied at the six locations (±l, 0, 0), (0, ±l, 0) and (0, 0, ±l) of the bob, as shown in the figue on p. 1. 2.1 The Equilibia at (±l,0, 0) ae Unstable Fo motion nea these equilibium points, both ẋ and ẍ ae small. Fo motion in the x-y plane (with z = 0), eq. (8) implies that ÿ = Ω 2 y,sosmall oscillations can exist in y. Howeve, fo motion in the x-z plane (with y = 0), eq. (7) implies that z =4Ω 2 z,soany small petubation in z would gow exponentially with time. Hence, these equilibia ae unstable. 2

2.2 The Equilibia at (0, ±l, 0) ae Unstable Fo motion nea these equilibium points, both ẏ and ÿ ae small. Fo motion in the x-y plane (with z = 0), eq. (8) implies that ẍ =Ω 2 x,soanysmall petubation in x would gow exponentially with time. Fomotioninthey-z plane (with x = 0), eq. (6) implies that z =4Ω 2 z,soanysmall petubation in z would gow exponentially with time. Hence, these equilibia ae unstable. 2.3 The Equilibia at (0, 0, ±l) ae Stable Fo motion nea these equilibium points, both ż and z ae small. Fomotioninthex-z plane (with y = 0), eq. (7) implies that ẍ = 3Ω 2 x, 2 so small oscillations in x can exist with angula fequency ω xz = 3Ω = 3g/R. Fomotioninthey-z plane (with x = 0), eq. (6) implies that ÿ = 4Ω 2 y,sosmall oscillations in y can exist with angula fequency ω yz =2Ω=2 g/r. That the two fequencies ω xz and ω yz ae diffeent is a consequence of the diffeent symmeties of the gavitational and centifugal foces; the fome is spheically symmetic while the latte is axially symmetic (about y). The peiods 2π/ 3Ω and π/ω of these oscillations ae independent of the length l of the pendulum, and ae of the same ode as the peiod 2π/Ω ( 90 min) of the (low-eath-) obital motion. 3 Hence, astonauts in a space station would tend to say that a pendulum does not oscillate (accoding to thei expectations of peiod 2π l/g = l/r 2π/Ω 1s fom expeience on Eath). 4 The equations of motion fo oscillations in the x-z o y-z planes have no tems (at fist ode in ẋ o ẏ) associated with the Coiolis foce, so the small oscillations of a pendulum in obit do not exhibit the pecession fist discussed by Foucault [3]. Howeve, since the fequencies of oscillation in x-z and y-z planes ae incommensuate, the geneal motion of the pendulum ove long times would be consideed as chaotic by an astonaut, even fo small oscillations (unless the oscillation wee puely in the x-z o in the y-z planes). A Appendix: Shote Deivation of Motion in the Plane of the Obit of the Suppot Point A somewhat biefe deivation was given in Appendix 17 of [4], using consevation of enegy, E = T + V, to deduce the motion in the plane of the obit of the suppot point fom the time deivative Ė = T + V =0. 2 Thee is also a second-ode, Coiolis tem 2Ω(ż xẋ/l) that we neglect fo small oscillations in the x-z plane about (0, 0, ±l). 3 These esults agee with those found in [1], whee a cleve vaiant of Lagange s method was employed using a Lagange multiplie, consideing the elation x 2 +y 2 +z 2 = l 2 to be a constaint. Lagange s method was also used in [2], fo spheical coodinates. 4 See, fo example, https://www.quoa.com/would-a-pendulum-swing-in-obit. 3

The potential enegy V of the bob of mass m at distance fom the cente of the Eath is, in the otating fame whee the centifugal can be elated to the centifugal potential, 5 V = GMm m(ω )2 2 ( ) ( mω 2 2 2 + R3, V mω 2 ṙ R3 2 ), (9) whee the appoximation holds fo a pendulum of length l R. Anticipating that the pendulum might oscillate about the vetical fom the cente of the Eath to the suppot point, we use a spheical coodinate system (ρ, θ, φ) (in the otating fame) whose oigin is at the suppot point, whose z-axis points away fom the cente of the Eath, and with φ =0andπ in the plane of the obit of the suppot point. Then, the kinetic enegy of the bob of the pendulum of length l is T = ml2 2 ( θ 2 + φ 2 sin 2 θ), T = ml 2 ( θ θ + φ φ sin 2 θ + φ 2 θ sin 2θ). (10) Futhemoe, to a vey good appoximation, = R + l cos θ, soṙ = l θ sin θ, and { } V mω 2 Rl θ 1 sin θ 1+(l/R)cosθ + 3mΩ 2 l 2 sin θ cos θ. (11) [1 + (l/r)cosθ] 2 Then, fo motion in the plane of the obit of the suppot point, φ =0, Fo θ = ɛ o π + ɛ and small ɛ, wehavethat 0= T + V = ml 2 θ( θ +3Ω 2 sin θ cos θ). (12) 0 ɛ +3Ω 2 ɛ. (13) The the angula velocity of small oscillations of the pendulum in the plane of the obit of the suppot point, about eithe θ =0oπ, is 3Ω = 3g/R, as found peviously in sec. 2.3. Note how eq. (12) also shows that θ = π and 3π/2 coespond to the unstable equilibia of sec. 2.1. Refeences [1] J.L. Synge, On the Behaviou, Accoding to Newtonian Theoy, of a Plumb Line o Pendulum Attached to an Atificial Satellite, Poc. Roy. Iish Acad. A 60, 1 (1959), http://physics.pinceton.edu/~mcdonald/examples/mechanics/synge_piaa_60_1_59.pdf [2] L. Blitze, Equilibium and stability of a pendulum in an obiting spaceship, Am.J. Phys. 47, 241 (1979), http://physics.pinceton.edu/~mcdonald/examples/mechanics/blitze_ajp_47_241_79.pdf 5 Both the Coiolis foce and the tension in the od/sting of the pendulum do no wok, and so do not contibute to the potential enegy in the otating fame. 4

[3] L. Foucault, Démonstation physique du mouvement de otation de la tee au moyen du pendule, Comptes Rendus Acad. Sci. 32, 135 (1851), http://physics.pinceton.edu/~mcdonald/examples/mechanics/foucault_cas_32_135_51.pdf [4] E.J. van de Heide and M. Kuijff, StaTack: A swinging tethe assisted e-enty fo the Intenational Space Station, Eu. Space Agency, EWP 1883 (1996), http://physics.pinceton.edu/~mcdonald/examples/mechanics/vandeheide_ewp_96.pdf 5