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Shun Lee Catholic Secondary School S.3 Physics 2nd Term Test (2016-17) Level : Secondary 3 Subject : Physics Date : 6 April 2016 (Thursday) Time : 11:15 a.m. - 11:35 a.m. Time Allowed : 20 minutes Full Mark : 20 Name: Class: ( ) Mark: /20 Parent s signature: Question-Answer Book Instructions 1. Name, class and class number should be written in the boxes provided after the announcement of the start of the test; otherwise, mark(s) will be deducted. 2. When told to open this paper, you should check that all the questions are there. Look for the words END OF PAPER after the last question. 3. This paper consists of TWO sections, Section A and Section B. Section A (Multiple Choice Questions) carries 4 marks and Section B (Short Questions) carries 16 marks. 4. Answer ALL questions in each section. Write your answers in the spaces provided in this Question-Answer Book. P. 1

Section A Multiple Choice Questions (4 marks, 1 mark each) Choose the BEST answer for questions 1 to 4. Question 1 Which of the following will produce the best thermometer? 1. Big bulb 2. Small bulb 3. Big bore 4. Small bore 5. Thick glass wall for stem 6. Thin glass wall for stem 7. Thick glass wall for bulb 8. Thin glass wall for bulb A. 1, 3, 5,, 7 B. 2, 4,, 6, 8 C. 2, 3, 6, 7 D. 1, 4, 5, 8 <ANS> Question 2 An electric heater supply supplies 21000 J of energy to a tank of water in 5 minutes. heater. Find the power of the A. 70 W <ANS> B. 4 200 W C. 105 000 W D. 6 300 000 W Question 3 Given the specific heat capacity of water is 4200 Jkg -1 C -1. The heat released by a tank of water when it cools down from 60 C to 50 C is 21000 J. Find the mass of water. A. 0.1 kg B. 0.083 kg C. 0.5 kg <ANS> D. 5 kg Question 4 In physics laboratory, there are two identical beakers of water at different temperatures, labelled as P and Q. For tank P, temperature of water at 80 C falls to 60 C. For tank Q, temperature of water at 40 C falls to 20 C. Which takes shorter time to complete the temperature fall? Why? Takes shorter time Reason A. Q Higher initial temp B. P larger temperature difference with the surroundings C. P Higher average molecular potential energy D. Q High average molecular kinetic energy Ans: B P. 2

Shun Lee Catholic Secondary School S.3 2nd Term Physics Test (2016 2017) Name: Class: S.3 ( ) Section A Multiple Choice Questions (4 marks, 1 mark each) 1. D 2. A 3. C 4. B 5. Section B Short Questions (16 marks): A list of useful formulae and equation can be found on the last page. Numerical answers without a PROPER UNIT will score no marks. Question 5. Convert (a) 37 C to temperature in Fahrenheit. (2 marks) (b) 100 C into Kelvin temperature. (2 marks) 37 (9/5) + 32 = 98.6 F 100 +273 = 373K Question 6. When ice melts, the average molecular potential energy (a) while the average molecular kinetic energy (b). (2 marks) increases, remains unchanged (a) increases (b) remains unchanged (b) (b) Question 7. The diagram shows the setup to find the specific heat capacity of a aluminium block. (a) A stirrer is used in a similar experiment to determine the specific heat capacity of water but not in this experiment. Explain briefly why a stirrer is not necessary in this experiment. (2 marks) Metals, such as aluminium, are good conductors (of heat). The temperature inside the block is already uniform. (Accepted but not good answers: The aluminium block conducts heat to different parts rapidly / To unify / uniform the temperature) Teacher should give a tick with a cross P. 3

(b) State ONE precaution in experimental procedure to measure the final temperature accurately. (1 mark) Measure the highest temperature reached after the heater is turned off. Add oil, as it is not purely experimental procedure, and it is not done against measuring the final temperature accurately (c) The experimental results are listed below: Initial joulemeter reading: 97600 J Final joulemeter reading: 12300 J Initial temperature: 18 C Final temperature: 25 C (i) Calculate the amount of heat supplied to the metal block. (2 marks) 112300 97600 = 14700 J (ii) The mass of the metal block is 2.2 kg. Calculate the specific heat capacity of the metal block. (2 marks) 14700 / (2.2) (25-18) = 954 Jkg -1 C (iii) The standard value of the specific heat capacity of the metal block is 900 Jkg -1 C -1. Give one reason why the calculated value is different. Explain briefly your answer. (2 marks) There is heat loss to the surroundings So, energy absorbed by the metal block is less than answer in (b)(i) / more energy has to be supplied (to increase the temperature of the metal block) (iv) Suggest ONE modification of the above setup to obtain a better experimental result. (1 mark) Wrap the block with cotton wool, or Any other reasonable answer towel, which is a easily available heat insulator heat-proof materials add oil as it may have been added, you cannot tell if it was already added. cotton should be cotton wool End of Paper P. 4

List of equations and formulae Temperature conversion between different scales C = 5 (F 32) 9 or F = 9 C + 32. Equation (1) 5 K = C + 273. Equation (4) Thermometer Reading X = L X L 0 L 100 L 0 100 C. Equation (2) slope = L T L 0 T OR L 100 L 0 100. Equation (3) Power and Heat supplied Q = Pt. Equation (5) Heat Capacity (of an object) Q = C T. Equation (6) C = Q T. Equation (7) Specific Heat Capacity (of a pure substance) c = Heat Capacity C mass = Q m T Equation (8) Q = mc T. Equation (9) Mixing by Conservation of Energy Heat loss by hot object(s) = heat gain by cold object(s). Equation (10) P. 5

Shun Lee Catholic Secondary School S.3 Physics 2nd Term Test (2016-17) Marking Scheme 1. D 2. A 3. C 4. B @ 1 mark Numerical answers without a PROPER UNIT should score no marks. 5. (a) 37 (9/5) + 32 1M = 98.6 F (b) 100 +273 1M = 373K 6. increases remains unchanged 7. (a) Metals, such as aluminium, are good conductors (of heat). The temperature inside the block is already uniform. (Accepted but not good answers: The aluminium block conducts heat to different parts rapidly / To unify / uniform the temperature) Teacher should give a tick with a cross (b) Measure the highest temperature reached after the heater is turned off. Add oil, as it is not purely experimental procedure, and it is not done against measuring the final temperature accurately (c)(i) 112300 97600 1M = 14700 J (ii) 14700 / (2.2) (25-18) 1M = 954 Jkg -1 C -1 (iii) There is heat loss to the surroundings. So, energy absorbed by the metal block is less than answer in (b)(i) / more energy has to be supplied (to increase the temperature of the metal block) (iv) Wrap the block with cotton wool, or any other reasonable answer towel, which is a easily available heat insulator heat-proof materials add oil as it may have been added, you cannot tell if it was already added. cotton should be cotton wool END P. 6