Section 1 Momentum and Impulse. Chapter 6. Preview. Objectives Linear Momentum. Houghton Mifflin Harcourt Publishing Company

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Section 1 Momentum and Impulse Preview Objectives Linear Momentum

Section 1 Momentum and Impulse Objectives Compare the momentum of different moving objects. Compare the momentum of the same object moving with different velocities. Identify examples of change in the momentum of an object. Describe changes in momentum in terms of force and time.

Section 1 Momentum and Impulse Linear Momentum Momentum is defined as mass times velocity. Momentum is represented by the symbol p, and is a vector quantity. p = mv momentum = mass velocity

Section 1 Momentum and Impulse Momentum Click below to watch the Visual Concept. Visual Concept

Section 1 Momentum and Impulse Linear Momentum, continued Impulse The product of the force and the time over which the force acts on an object is called impulse. The impulse-momentum theorem states that when a net force is applied to an object over a certain time interval, the force will cause a change in the object s momentum. F t = p = mv f mv i force time interval = change in momentum

Section 1 Momentum and Impulse Impulse Click below to watch the Visual Concept. Visual Concept

Section 1 Momentum and Impulse Linear Momentum, continued Stopping times and distances depend on the impulse-momentum theorem. Force is reduced when the time interval of an impact is increased.

Section 1 Momentum and Impulse Impulse-Momentum Theorem

Section 1 Momentum and Impulse Impulse-Momentum Theorem Click below to watch the Visual Concept. Visual Concept

Section 2 Conservation of Momentum Preview Objectives Momentum is Conserved Sample Problem

Section 2 Conservation of Momentum Objectives Describe the interaction between two objects in terms of the change in momentum of each object. Compare the total momentum of two objects before and after they interact. State the law of conservation of momentum. Predict the final velocities of objects after collisions, given the initial velocities, force, and time.

Section 2 Conservation of Momentum Momentum is Conserved The Law of Conservation of Momentum: The total momentum of all objects interacting with one another remains constant regardless of the nature of the forces between the objects. m 1 v 1,i + m 2 v 2,i = m 1 v 1,f + m 2 v 2,f total initial momentum = total final momentum

Section 2 Conservation of Momentum Conservation of Momentum Click below to watch the Visual Concept. Visual Concept

Section 2 Conservation of Momentum Sample Problem Conservation of Momentum A 76 kg boater, initially at rest in a stationary 45 kg boat, steps out of the boat and onto the dock. If the boater moves out of the boat with a velocity of 2.5 m/s to the right,what is the final velocity of the boat?

Section 2 Conservation of Momentum Sample Problem, continued Conservation of Momentum 1. Define Given: m 1 = 76 kg m 2 = 45 kg v 1,i = 0 v 2,i = 0 v 1,f = 2.5 m/s to the right Unknown: v 2,f =?

Section 2 Conservation of Momentum Sample Problem, continued Conservation of Momentum 2. Plan Choose an equation or situation: Because the total momentum of an isolated system remains constant, the total initial momentum of the boater and the boat will be equal to the total final momentum of the boater and the boat. m 1 v 1,i + m 2 v 2,i = m 1 v 1,f + m 2 v 2,f

Section 2 Conservation of Momentum Sample Problem, continued Conservation of Momentum 2. Plan, continued Because the boater and the boat are initially at rest, the total initial momentum of the system is equal to zero. Therefore, the final momentum of the system must also be equal to zero. m 1 v 1,f + m 2 v 2,f = 0 Rearrange the equation to solve for the final velocity of the boat. m v v mv 2 2, f 1 1, f m 1 v m2 2, f 1, f

Section 2 Conservation of Momentum Sample Problem, continued Conservation of Momentum 3. Calculate Substitute the values into the equation and solve: v v 2, f 2, f 76 kg 2.5 m/s to the right 45 kg 4.2 m/s to the right

Section 2 Conservation of Momentum Sample Problem, continued Conservation of Momentum 4. Evaluate The negative sign for v 2,f indicates that the boat is moving to the left, in the direction opposite the motion of the boater. Therefore, v 2,f = 4.2 m/s to the left

Section 2 Conservation of Momentum Momentum is Conserved, continued Newton s third law leads to conservation of momentum During the collision, the force exerted on each bumper car causes a change in momentum for each car. The total momentum is the same before and after the collision.

Section 3 Elastic and Inelastic Collisions Preview Objectives Collisions Sample Problem

Section 3 Elastic and Inelastic Collisions Objectives Identify different types of collisions. Determine the changes in kinetic energy during perfectly inelastic collisions. Compare conservation of momentum and conservation of kinetic energy in perfectly inelastic and elastic collisions. Find the final velocity of an object in perfectly inelastic and elastic collisions.

Section 3 Elastic and Inelastic Collisions Collisions Perfectly inelastic collision A collision in which two objects stick together after colliding and move together as one mass is called a perfectly inelastic collision. Conservation of momentum for a perfectly inelastic collision: m 1 v 1,i + m 2 v 2,i = (m 1 + m 2 )v f total initial momentum = total final momentum

Section 3 Elastic and Inelastic Collisions Perfectly Inelastic Collisions Click below to watch the Visual Concept. Visual Concept

Section 3 Elastic and Inelastic Collisions Sample Problem Kinetic Energy in Perfectly Inelastic Collisions Two clay balls collide head-on in a perfectly inelastic collision. The first ball has a mass of 0.500 kg and an initial velocity of 4.00 m/s to the right. The second ball has a mass of 0.250 kg and an initial velocity of 3.00 m/s to the left.what is the decrease in kinetic energy during the collision?

Section 3 Elastic and Inelastic Collisions Sample Problem, continued Kinetic Energy in Perfectly Inelastic Collisions 1. Define Given: m 1 = 0.500 kg m 2 = 0.250 kg v 1,i = 4.00 m/s to the right, v 1,i = +4.00 m/s v 2,i = 3.00 m/s to the left, v 2,i = 3.00 m/s Unknown: KE =?

Section 3 Elastic and Inelastic Collisions Sample Problem, continued Kinetic Energy in Perfectly Inelastic Collisions 2. Plan Choose an equation or situation: The change in kinetic energy is simply the initial kinetic energy subtracted from the final kinetic energy. KE = KE i KE f Determine both the initial and final kinetic energy. 1 2 1 2 Initial: KEi KE1, i KE2, i m1v 1, i m2v 2, i 2 2 1 2 Final: KEf KE1, f KE2, f m1 m2 vf 2

Section 3 Elastic and Inelastic Collisions Sample Problem, continued Kinetic Energy in Perfectly Inelastic Collisions 2. Plan, continued Use the equation for a perfectly inelastic collision to calculate the final velocity. v f m 1 v 1,i m 2 v 2,i m 1 m 2

Section 3 Elastic and Inelastic Collisions Sample Problem, continued Kinetic Energy in Perfectly Inelastic Collisions 3. Calculate Substitute the values into the equation and solve: First, calculate the final velocity, which will be used in the final kinetic energy equation. v f v f (0.500 kg)(4.00 m/s) (0.250 kg)( 3.00 m/s) 0.500 kg 0.250 kg 1.67 m/s to the right

Section 3 Elastic and Inelastic Collisions Sample Problem, continued Kinetic Energy in Perfectly Inelastic Collisions 3. Calculate, continued Next calculate the initial and final kinetic energy. KE i KE f 1 2 1 2 0.500 kg 4.00 m/s 0.250 kg 3.00 m/s 5.12 J 2 2 1 2 0.500 kg 0.250 kg 1.67 m/s 1.05 J 2

Section 3 Elastic and Inelastic Collisions Sample Problem, continued Kinetic Energy in Perfectly Inelastic Collisions 3. Calculate, continued Finally, calculate the change in kinetic energy. KE KE KE 1.05 J 5.12 J f i KE 4.07 J 4. Evaluate The negative sign indicates that kinetic energy is lost.

Section 3 Elastic and Inelastic Collisions Elastic Collisions Elastic Collision A collision in which the total momentum and the total kinetic energy are conserved is called an elastic collision. Momentum and Kinetic Energy Are Conserved in an Elastic Collision m 1 v 1,i m 2 v 2,i m 1 v 1,f m 2 v 2,f 1 2 m v 2 1 1 1,i 2 m v 2 1 2 2,i 2 m v 2 1 1 1,f 2 m v 2 2 2,f

Section 3 Elastic and Inelastic Collisions Sample Problem, continued Elastic Collisions A 0.015 kg marble moving to the right at 0.225 m/s makes an elastic head-on collision with a 0.030 kg shooter marble moving to the left at 0.180 m/s. After the collision, the smaller marble moves to the left at 0.315 m/s. Assume that neither marble rotates before or after the collision and that both marbles are moving on a frictionless surface.what is the velocity of the 0.030 kg marble after the collision?

Section 3 Elastic and Inelastic Collisions Sample Problem, continued Elastic Collisions 1. Define Given: m 1 = 0.015 kg m 2 = 0.030 kg v 1,i = 0.225 m/s to the right, v 1,i = +0.225 m/s v 2,i = 0.180 m/s to the left, v 2,i = 0.180 m/s v 1,f = 0.315 m/s to the left, v 1,i = 0.315 m/s Unknown: v 2,f =?

Section 3 Elastic and Inelastic Collisions Sample Problem, continued Elastic Collisions 2. Plan Choose an equation or situation: Use the equation for the conservation of momentum to find the final velocity of m 2, the 0.030 kg marble. m 1 v 1,i + m 2 v 2,i = m 1 v 1,f + m 2 v 2,f Rearrange the equation to isolate the final velocity of m 2. m v m v m v m v v 2 2, f 1 1i, 2 2, i 1 1, f 2f, m v m v m v 1 1,i 2 2, i 1 1, f m 2

Section 3 Elastic and Inelastic Collisions v v v Sample Problem, continued Elastic Collisions 3. Calculate Substitute the values into the equation and solve: The rearranged conservation-of-momentum equation will 2, f 2, f allow you to isolate and solve for the final velocity. 0.015 kg 0.225 m/s 0.030 kg 0.180 m/s 0.015 kg 0.315 m/s 3 3 3 3.4 10 kg m/s 5.4 10 kg m/s 4.7 10 kg m/s 3 2.7 10 kg m/s 3.0 10 kg 2, f 2 v 2f, 2 9.0 10 m/s to the right 0.030 kg 0.030 kg

Section 3 Elastic and Inelastic Collisions Sample Problem, continued Elastic Collisions 4. Evaluate Confirm your answer by making sure kinetic energy is also conserved using these values. 1 2 1 2 1 2 1 2 m1v 1, i m2v 2, i m1v 1, f m2v 2, f 2 2 2 2 1 1 KEi 0.015 kg 0.225 m/s 0.030 kg 0.180 m/s 2 2 KE f 4 2 2 4 8.7 10 kg m /s 8.7 10 J 1 1 2 2 0.015 kg 0.315 m/s 0.030 kg 0.090 m/s 4 2 2 4 8.7 10 kg m /s 8.7 10 J 2 2 2 2

Section 3 Elastic and Inelastic Collisions Types of Collisions Click below to watch the Visual Concept. Visual Concept