Reaction Kinetics: Elementary Ideas

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Reaction Kinetics: Elementary Ideas 5th February 00 Rate Laws Returning to our hypothetical model reaction: ν i i + ν j j ν k k + ν l l In practice, the rate of reaction is treated as follows, thus introducing the concept of the rate constant, k: definition of variables: R = k N reactants i= [i] γ i i k = rate constant (sometimes called rate coefficient; can be determined experimentally; can be estimated theoretically transition state theory) [i] = concentration of REACTANT species i γ i = Reaction order of REACTANT species i At this time, we are NOT associating the species reactant order γ i to stoichiometric coefficient! p = Σ i γ i = overall reaction order NOTE: at this point, the experimental rate equation is written with species reaction orders that have NO inherent relation to the stoichiometric coefficients (ν i, ν j, ν k, etc) of the chemical reaction of interest!

Elementary Reactions Consider the following overall reaction: N O 5 NO + O The predicted rate law for this reaction (which happens to be in good agreement with experiment) is: rate = k k k + k [N O 5 ] = k effective [N O 5 ] () We observe that the overall rate is NOT second order in [N O 5 ] as one might quickly jump to conclude. This is because the mechanism underlying this overall chemical transformation is complex; that is, there are several mechanistic steps involved, with certain intermediates involved as well. We will say more about reaction mechanisms later. For the present, we mention them in order to emphasize that the stoichiometric coefficients of the chemical reaction are tied to the reaction order only for elementary reactions or reaction steps. 3 Integrated Rate Equations and Analysis for Elementary Reactions I. Zero th Order Reactions (rare) The rate of reaction is independent of instantaneous reactant concentration: A products Rate = k = d[a] () [A] t = [A] o kt (3) The rate constant, k, has units of (concentration/time). The reaction halflife, t /, is the time necessary for one-half of the reactant species to be consumed is given by: t / = [A] o k The units of the rate constant k are in concentration per unit of time ( [moles/liter]/sec ). ()

II. First-Order Reactions A products The reaction rate for a First-Order reaction is proportional to the first power of the concentration of the reacting species (order=). Rate = k [A] = d[a] (5) Integrating this straightforwardly, keeping in mind the initial concentration of A, [A] o is defined (boundary condition for solving differential equation): [A] t = [A] o e kt (6) In order to determine if a reaction is First order, using experimental data, we can manipulate the exponential form just determined into a linear form to make analysis easier. Taking the natural logarith (natural log) of both sides to arrive at: ln [A] t = ln [A] o kt (7) (show plot of linear form here) The half-life of such a reaction is given by: t / = ln k = 0.693 k (8) Using the last relationship, one can reciprocally determine the rate constant knowing the half-life of a reaction or other physicochemical process. Examples:. decay of radioactive nuclei (carbon dating). fluorescence decay of electronically excited molecules 3. chemical reactions (as we ll see 3

later). others III. Second Order Reactions The rate of a second-order reaction is overall, and depends on either a single reactant species (to order ) or on two different reactant species, each with order dependence (recall the definition of reaction order as the sum of the individual species reaction orders). Let s consider the two cases individually. a). Second order in one reactant A products (A+A products ) Rate = k [A] = d[a] (9) Performing the integration: [A] = [A] o + kt (0) Be careful of the factor of often easily overlooked in the treatment of this reaction. (show figure of /conca versus t : straight line) The half-life for this reaction is given by: t = k [A] o () Second order reaction in two reactant species If the reaction is given by: A + B products the reaction rate is given by:

Rate = k [A] [B] = d[a] () We obtain for the integrated rate equation: kt = ([A] o [B] o ) ln[a] [B] o [A] o [B] [A] o [B] o (3) We can now consider two special cases: [A] o = [B] o Because of the one-to-one stoichiometry, we can say for all time [A]=[B] The integrated rate law is like that for nd order in one component [B] o <<< [A] o : we can consider reactant A in excess (it essentially remains constant) [B] = [B] o e k t () k = k[a] o This is pseudo-st order (species B undergoing transformation in a sea of A ) Determining Reaction Orders In order to determine reaction orders,we can play some games with initial concentrations, excesses of species, etc. In order to do this, we need to measure concentrations (or amounts) as a function of time. Quench the reaction, measure concentrations For gases, measure pressure versus time Spectroscopically follow reactant/product species 5

. Analyzing data.. Reactions with reactant A products a. Plot or analyze the time behavior of the concentration; A vs. time ln[a] vs. time /[A] vs. time plot to see which dependence give straight line b. Half-life method: measure the relation between t st order t nd order t [A] 0 o [A] o c. Multiple Life-times (t 3 st order t 3 nd order t 3 and t = ln k t 3 t = = 3 [A] ok t 3 t = 3 and [A] o ) (at t 3, [A] = 0.5[A] o ).. Reactions with more than reactant A + B + C products a. Initial Rate Method (vary initial concentrations of a species and measure initial rates) For [A] o [A] t t=0 = R o k[a] α o [B] β o [C] γ o For [A] o [A] t t=0 = k[a] α o [B] β o [C] γ o Experimentally determine: R o = ( ) [A]o α Consider the following cases for the scenario: [A] o = 0.5[A] o if Ro = α = 0 if Ro if Ro if Ro = α = = α = = α = [A] o 6

b. Flooding or Isolation Let [A] o << [B] o, [C] o (flood system with B and C) Then [B] [B] o and [C] [C] o Thus d[a] k [A] α (5) k = k[b] β o [C] γ o the reaction is made to be pseudo-α order with one reactant 7