Symmetrical Components 1

Similar documents
8 THREE PHASE A.C. CIRCUITS

Dorf, R.C., Wan, Z. T- Equivalent Networks The Electrical Engineering Handbook Ed. Richard C. Dorf Boca Raton: CRC Press LLC, 2000

1 PYTHAGORAS THEOREM 1. Given a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

I1 = I2 I1 = I2 + I3 I1 + I2 = I3 + I4 I 3

Project 6: Minigoals Towards Simplifying and Rewriting Expressions

Section 1.3 Triangles

Introduction to Olympiad Inequalities

Polynomials. Polynomials. Curriculum Ready ACMNA:

Polyphase Systems. Objectives 23.1 INTRODUCTION

Linear Algebra Introduction

1.3 SCALARS AND VECTORS

Tutorial Worksheet. 1. Find all solutions to the linear system by following the given steps. x + 2y + 3z = 2 2x + 3y + z = 4.

Polyphase Systems 22.1 INTRODUCTION

9.4. The Vector Product. Introduction. Prerequisites. Learning Outcomes

12.4 Similarity in Right Triangles

LESSON 11: TRIANGLE FORMULAE

4. UNBALANCED 3 FAULTS

I 3 2 = I I 4 = 2A

Lecture 3. In this lecture, we will discuss algorithms for solving systems of linear equations.

ELE B7 Power System Engineering. Unbalanced Fault Analysis

Introduction to Algebra - Part 2

2.4 Linear Inequalities and Interval Notation

A Study on the Properties of Rational Triangles

Chapter 9 Definite Integrals

Triangles The following examples explore aspects of triangles:

PYTHAGORAS THEOREM WHAT S IN CHAPTER 1? IN THIS CHAPTER YOU WILL:

2. VECTORS AND MATRICES IN 3 DIMENSIONS

Bases for Vector Spaces

NON-DETERMINISTIC FSA

Discrete Structures Lecture 11

Part I: Study the theorem statement.

Numbers and indices. 1.1 Fractions. GCSE C Example 1. Handy hint. Key point

Solutions for HW9. Bipartite: put the red vertices in V 1 and the black in V 2. Not bipartite!

STRAND J: TRANSFORMATIONS, VECTORS and MATRICES

3 Angle Geometry. 3.1 Measuring Angles. 1. Using a protractor, measure the marked angles.

Designing Information Devices and Systems I Anant Sahai, Ali Niknejad. This homework is due October 19, 2015, at Noon.

5. Every rational number have either terminating or repeating (recurring) decimal representation.

Non Right Angled Triangles

Spacetime and the Quantum World Questions Fall 2010

THE PYTHAGOREAN THEOREM

Duality # Second iteration for HW problem. Recall our LP example problem we have been working on, in equality form, is given below.

Homework Solution - Set 5 Due: Friday 10/03/08

How do we solve these things, especially when they get complicated? How do we know when a system has a solution, and when is it unique?

CS 491G Combinatorial Optimization Lecture Notes

CS 573 Automata Theory and Formal Languages

Review of Gaussian Quadrature method

IEEE PES Boston Chapter. Protection Engineering Course Series. Instructor: Dean V. Sorensen (National Grid)

1B40 Practical Skills

Vectors. a Write down the vector AB as a column vector ( x y ). A (3, 2) x point C such that BC = 3. . Go to a OA = a

Lecture 08: Feb. 08, 2019

EE 330/330L Energy Systems (Spring 2012) Laboratory 1 Three-Phase Loads

Lesson 2: The Pythagorean Theorem and Similar Triangles. A Brief Review of the Pythagorean Theorem.

CHENG Chun Chor Litwin The Hong Kong Institute of Education

arxiv: v1 [math.ca] 21 Aug 2018

#A42 INTEGERS 11 (2011) ON THE CONDITIONED BINOMIAL COEFFICIENTS

AP Calculus BC Chapter 8: Integration Techniques, L Hopital s Rule and Improper Integrals

Lecture 2e Orthogonal Complement (pages )

April 8, 2017 Math 9. Geometry. Solving vector problems. Problem. Prove that if vectors and satisfy, then.

Trigonometry Revision Sheet Q5 of Paper 2

Electrical Circuits II (ECE233b)

Matrices SCHOOL OF ENGINEERING & BUILT ENVIRONMENT. Mathematics (c) 1. Definition of a Matrix

Estimation of Sequence Components using Magnitude Information

Matrix Algebra. Matrix Addition, Scalar Multiplication and Transposition. Linear Algebra I 24

Minimal DFA. minimal DFA for L starting from any other

State space systems analysis (continued) Stability. A. Definitions A system is said to be Asymptotically Stable (AS) when it satisfies

Designing Information Devices and Systems I Spring 2018 Homework 7

Intermediate Math Circles Wednesday 17 October 2012 Geometry II: Side Lengths

set is not closed under matrix [ multiplication, ] and does not form a group.

Chapter 8 Roots and Radicals

Lecture 6: Coding theory

Things to Memorize: A Partial List. January 27, 2017

Probability. b a b. a b 32.

ILLUSTRATING THE EXTENSION OF A SPECIAL PROPERTY OF CUBIC POLYNOMIALS TO NTH DEGREE POLYNOMIALS

Reflection Property of a Hyperbola

Factorising FACTORISING.

378 Relations Solutions for Chapter 16. Section 16.1 Exercises. 3. Let A = {0,1,2,3,4,5}. Write out the relation R that expresses on A.

6.5 Improper integrals

Surds and Indices. Surds and Indices. Curriculum Ready ACMNA: 233,

Section 4: Integration ECO4112F 2011

CSCI 340: Computational Models. Kleene s Theorem. Department of Computer Science

Bridging the gap: GCSE AS Level

CS 373, Spring Solutions to Mock midterm 1 (Based on first midterm in CS 273, Fall 2008.)

1 ELEMENTARY ALGEBRA and GEOMETRY READINESS DIAGNOSTIC TEST PRACTICE

Magnetically Coupled Coil

u( t) + K 2 ( ) = 1 t > 0 Analyzing Damped Oscillations Problem (Meador, example 2-18, pp 44-48): Determine the equation of the following graph.

Behavior Composition in the Presence of Failure

The University of Nottingham SCHOOL OF COMPUTER SCIENCE A LEVEL 2 MODULE, SPRING SEMESTER MACHINES AND THEIR LANGUAGES ANSWERS

1 From NFA to regular expression

Instructions. An 8.5 x 11 Cheat Sheet may also be used as an aid for this test. MUST be original handwriting.

Torsion in Groups of Integral Triangles

Resistive Network Analysis

September 13 Homework Solutions

Chapter 4 Contravariance, Covariance, and Spacetime Diagrams

A study of Pythagoras Theorem

TOPIC: LINEAR ALGEBRA MATRICES

Power System Representation and Equations. A one-line diagram of a simple power system

1 Nondeterministic Finite Automata

Designing Information Devices and Systems I Fall 2016 Babak Ayazifar, Vladimir Stojanovic Homework 6. This homework is due October 11, 2016, at Noon.

More on automata. Michael George. March 24 April 7, 2014

Designing Information Devices and Systems I Discussion 8B

Transcription:

Symmetril Components. Introdution These notes should e red together with Setion. of your text. When performing stedy-stte nlysis of high voltge trnsmission systems, we mke use of the per-phse equivlent iruit. Also, when performing symmetril fult (three-phse fult) nlysis of high-voltge trnsmission systems, we mke use of the per-phse equivlent iruit. But for unsymmetril fults (single line to ground, two line to ground, nd line to line) nlysis, the three phses no longer see the sme impedne, whih violtes the si requirement of per-phse nlysis (phses must e lned).

There is very elegnt pproh ville for nlyzing unsymmetri three-phse iruits. The pproh ws developed y mn nmed Chrles Fortesue nd reported in fmous pper in 98. It is now lled the method of symmetril omponents. We will spend little time studying this method in order to understnd how to use it in unsymmetril fult nlysis. Chrles Le Geyt FORTESCUE Professor ws orn out 878 in Keewntin, Northwest Territories, Cnd. Hudson By Ftory where the Hyes River enters Hudson By He immigrted in 9 to USA. He ppered in the ensus on April 93 in Pittsurgh, USA. Chrles died on 4 Deemer 936 in Pittsurgh, USA. The Chrles LeGeyt Fortesue Sholrship ws estlished in 939 t MIT s memoril to Chrles LeGeyt in reognition of his vlule ontriutions to the field of eletril engineering Chrles LeGeyt Fortesue, orn t York Ftory, Mnito, 876, son of hief ftor of Hudson By Compny-ws the first eletril engineering grdute of Queen's University. After grdution Fortesue joined Westinghouse Eletri nd Mnufturing Compny t Est Pittsurgh nd ttined universl fme for his ontriutions to the engineering priniples nd nlysis of power trnsmission nd distriution systems. He is espeilly noted for development of polyphse systems nlysis y the symmetril omponents method. He mde his wy, evenutlly, to MIT where he eme very well known nd respeted professor. Its fsinting tht Ceil Lewis Fortesue orn 88 lso eme Professor of Eletril Engineering in London University, in the sme period. One wonders if they herd out eh other? Chrles Le Geyt FORTESCUE Professor nd Louise Cmeron WALTER were mrried out 95. Louise Cmeron WALTER3 ws orn out 885 in Pennsylvnni, USA. She ws Sulptor Chrles Le Geyt FORTESCUE Professor nd Louise Cmeron WALTER hd the following hildren: Jne Fithful FORTESCUE.

. Symmetril Components: Motivtion Def: A symmetril set of phsors hve equl mgnitude & re º out of phse. Gol: Deompose set of three unsymmetril phsors into One unsymmetri ut equl set of 3 Two symmetril sets of 3 3

Then we n nlyze eh set individully nd use superposition to otin the omposite result. In wht follows, we demonstrte tht: Step : An unsymmetril set, not summing to, n e deomposed into two unsymmetril sets: o n equl set nd n o unsymmetril set tht does sum to ; Step : An unsymmetril set tht sums to n e deomposed into two symmetril sets Step : Consider set of phsors tht do not dd to zero (euse of different mgnitudes or euse of ngulr seprtion different thn º or euse of oth). Assume tht they hve phse sequene --. Add them up, s in Fig., i.e., R () 4

-- -- R Fig. : Addition of Unsymmetril Phsors So we see from () tht R () Define: R 3 (3) Then: 3 (4) (5) Define: Then: A B C (6) 5

A B C (7) Conlusion: We otin n unsymmetril set of voltges tht sum to y sutrting from eh originl phsor, where is /3 of the resultnt phsor, illustrted in Fig.. C A -- R B - =- R /3 Fig. : Sutrting from unsymmetril phsors Step : How to deompose A, B, nd C into two symmetril sets? Cn we deompose A, B, C into -- symmetril sets? As test, try to dd ny -- symmetril sets nd see wht you get. See Fig. 3. 6

-- -- C -- B A Fig. 3: Adding symmetril -- sets Note tht in dding the phsor sets, we dd the two -phse phsors, the two -phse phsors, nd the two -phse phsors. One n oserve from Fig. 3 tht the resultnt phsor set, denoted y the solid lines, re in ft symmetril! 7

It is possile to prove mthemtilly tht the sum of ny -- symmetril sets is lwys nother symmetril set. Let s try different thing. Let s try to dd two symmetril sets, ut let s hve one e -- (lled positive sequene) nd nother e -- (lled negtive sequene). As efore, in dding the phsor sets, we dd the two -phse phsors, the two - phse phsors, nd the two -phse phsors. The result of our efforts in shown in Fig. 4. 8

-- -- -- C B A Fig. 4: Adding symmetril -- set to symmetril -- set The resultnt phsor set is unsymmetril! We n gurntee tht the three phsors in this unsymmetril phsor set sums to zero, sine we otined it y dding two phsor sets tht sum to zero, i.e., 9

+ + = + + = ------------------- (8) A + B + C = Now onsider Fig. 4 gin. Assume tht someone hnds you the unsymmetril set of phsors A, B, nd C. Cn you deompose them into the two symmetril sets? Cn you e ssured tht two suh symmetril sets exist? The nswer is yes, you n e ssured tht two suh symmetril sets exist. Fortesue s pper ontins the proof. I simply rgue tht the three phsors given in Fig. 4, A, B, nd C, re quite generl (there is nothing speil out them), with the single exeption tht they sum to zero.

Clim: We n represent ANY unsymmetril set of 3 phsors tht sum to s the sum of onstituent symmetril sets: A positive (--) sequene set nd A negtive (--) sequene set. Given this lim, then the following theorem holds. Theorem: We n represent ANY unsymmetril set of 3 phsors s the sum of 3 onstituent sets, eh hving 3 phsors: A positive (--) sequene set nd A negtive (--) sequene set nd An equl set These three sets we will ll, respetively, Positive,, Negtive,, zero,, sequene omponents.

The implition of this theorem is tht ny unsymmetril set of 3 phsors,, n e written in terms of the ove sequene omponents in the following wy: (9) We n write the equtions of (9) in more ompt fshion, ut first, we must desrie mthemtil opertor tht is essentil. 3. The α-opertor To egin on fmilir ground, we re ll onversnt with the opertor j whih is used in omplex numers. Rememer tht j is tully vetor with mgnitude nd n ngle: j 9 ()

In the sme wy, we re going to define the α opertor s: -.5 + j.866 It is esy to show the following reltions: () 3 (3) 4 (4) We lso hve tht: 6 (5) s illustrted in Fig. 5. () +α α Fig. 5: Illustrtion of +α Note tht 4 6 (6) 3

Similrly, we my show tht: 6 (7) 3 3 (8) 33 (9) 35 () 3 5 () And there re mny more reltions like this tht re sometimes helpful when deling with symmetril omponents. (See the text lled Anlysis of fulted power systems y Pul Anderson, pg. 7.) 4. Symmetril omponents: the mth We repet equtions (9) elow for onveniene: (9) 4

We n relte the three different quntities hving the sme supersript. Zero sequene quntities: These quntities re ll equl, i.e., () Positive sequene quntities: The reltion etween these quntities n e oserved immeditely from the phsor digrm nd n e expressed using the α-opertor. -- Fig. 6: Positive sequene omponents (3) 5

Negtive sequene quntities: The reltion etween these quntities n e oserved immeditely from the phsor digrm nd n e expressed using the α-opertor. -- Fig. 8: Negtive sequene omponents (4) Now let s use equtions (), (3), nd (4) to express the originl phsors,, in terms of only the -phse omponents,,, i.e., we will eliminte the -phse omponents,, 6

7 nd the -phse omponents,, This results in (9) So we hve written the quntities (phse quntities) in terms of the +- quntities (sequene quntities) of the -phse. We n write this in mtrix form s: (5) Defining

8 A (6) we see tht eq. (5) n e written s: A (7) We my lso otin the +- (sequene) quntities from the (phse) quntities: A (8) where 3 A (9)

Equtions -9 hold for Line-to-line voltges Line-to-neutrl voltges Line urrents Phse urrents 9