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PRINCIPAL HOD LAB INCHARG Dr.S. D. Deshmukh MGM S Dr.V.M.Arole S.N.Deshmukh Jawaharlal Nehru Engineering College, PRINCIPAL HOD LAB INCHARG N-6, CIDCO, Aurangabad. Dr.S. LAB D. Deshmukh MANUAL Dr.V.M.Arole S.N.Deshmukh F. Y., B. TECH. ENGINEERING CHEMISTRY 2017-18 Lab In-charge: Dr. S. N. Deshmukh 1 Department of Chemistry, MGMs, Jawaharlal Nehru Engineering College, Aurangabad

MGM s Jawaharlal Nehru Engineering College, N-6, CIDCO, Aurangabad. Lab Manual of EnginEering Chemistry Academic Year: 2017-18 Lab In-charge Dr. S. N. Deshmukh HOD Dr. V. M. Arole 2 Department of Chemistry, MGMs, Jawaharlal Nehru Engineering College, Aurangabad

List of Experiments 1. To determine neutralization number of Oil. 2. To find the normality of hydrochloric acid and acetic acid by titrating the mix of HCl & CH 3 COOH against sodium hydroxide solution conduct metrically. 3. To determine the relative viscosity of given liquid with respect to water at room temperature by Ostwald s viscometer. 4. Determination of total hardness of water by EDTA method. 5. To find the normality and strength of given hydrochloric acid solution by titrating against standard sodium carbonate solution. 6. To determine the normality and strength of given KMnO4 solution by titrating it with Mohr s salt (Ferrous Ammonium Sulphate). 7. To determine molarity of hydrochloric acid ph metrically by using M/10 sodium hydroxide solution. 8. To determine the surface tension of given liquid at room temperature by Stalagmometer 3 Department of Chemistry, MGMs, Jawaharlal Nehru Engineering College, Aurangabad

Aim: To determine neutralization number of Oil. Experiment No: 01 Apparatus: Burette, pipette, conical flask, glass rod etc. Chemicals: Ethyl alcohol, Std. KOH solution, Oil, Phenolphthalein, Acetone, Benzene etc. Theory: The acid value of lubricating oil is defined as number of milligrams of KOH required to neutralize the free acid present in one gram of oil sample. In good lubricating oil acid value should minimum increase in acid value should be taken as an indicator of oxidation of oil which may lead to gum and sludge formation decides corrosion. A known weight of oil sample is dissolved in a suitable solvent and titrates with a standard alcoholic KOH solution. Reaction: H + + OH - H 2 O --------- (1) RCOOH + KOH RCOOK + H 2 O -------- (2) Procedure: 1) Weight exactly around 5 gr of the sample on watch glass and dissolved it in to 50 ml of neutral ethanol. 2) Heat the solution for 30 minute in water bath cool it and add 2 to 3 drops of Phenolphthalein indicator. 3) Titrate the solution with 0.1 N KOH till the color of solution is faint pink color. This is the end point of the titration. 4) The final reading of the burette is noted and the titration is repeated to get concordant values. 4 Department of Chemistry, MGMs, Jawaharlal Nehru Engineering College, Aurangabad

Observation Table: Sr. No Weight of Sample ( in gm) Burette reading (in ml) Mean 1 2 3 Formula: Neutralization number = Volume of 0.1 N KOH used in ml 5.6 Weight of sample taken Calculations: Result: Neutralization number of given Oil sample is mg of KOH. Questions: 1. Explain the properties of good lubricant. 2. Define term Neutralization number. 3. What happen? When acid value of lubricant is more than permissible value. 4. Why the acid value of lubricant is determined before using in lubrication process? 5 Department of Chemistry, MGMs, Jawaharlal Nehru Engineering College, Aurangabad

Experiment No: 02 Aim: To find the normality of hydrochloric acid and acetic acid by titrating the mix of HCl & CH 3 COOH against sodium hydroxide solution conductometrically. Apparatus: Conductometer, Magnetic stirrer, Beaker, Pipette, Burette, etc Chemicals: Hydrochloric acid, Acetic acid, Sodium hydroxide, distilled water etc. Theory: Conductometry can be used to determine the end point of a titration. This method is based on the measurement of conductance during the course of titration. The conductance varies differently before and after the equivalence point. This is due to the reason that electrical conductance of a solution depends upon the number of ions present and their ionic mobility s i.e. speeds. When conductance values plotted against volume of titrants added, U shape is obtain, the point of intersection of lines gives the end point. Reaction: Procedure: HCl + NaOH NaCl + H 2 0 CH 3 COOH + NaOH CH 3 COONa + H 2 0 1. Prepare the 10 ml mixture of 5ml hydrochloric acid solution and 5ml of acetic acid solution in a beaker. Add few ml of distilled water in it. 2. Immerse the conductivity cell in the solution so that the electrodes completely dip in solution. 3. Note down the conductance of solution. 4. From the burette add 0.3N NaOH solution in 0.5 ml lots with continuous stirring and measure the conductance of solution at each 0.5ml addition of NaOH. 5. Plot a graph between observed conductance values along y-axis against the volume of alkali added along x-axis. The end point of intersection gives the amount of alkali required for neutralization of acid. 6 Department of Chemistry, MGMs, Jawaharlal Nehru Engineering College, Aurangabad

Observation Table:- Sr.No. Volume of NaOH added (in ml) Observed conductance (in mhos) 1 0 ml 2 0.5 ml 3 1 ml 19 9 ml 20 9.5 ml Calculations: 1) N 1 V 1 = N2V2 2) N 3 V 3 = N 4 V 4 HCl = NaOH CH 3 COOH = NaOH N 1 5 = 0.3 V 2 N 3 5 = 0.3 V 4 3) Strength of HCl = N 1 Eq. Wt 4) Strength of CH 3 COOH = N 3 Eq. Wt Result: 1. Normality of given hydrochloric acid is = N 2. Normality of given acetic acid is =.. N 3. Strength of hydrochloric acid in given solution is =.. gr/lit 4. Strength of acetic acid in given solution is = gr/lit Questions: 1. What is mean by conductance? 2. How you can calculate the normality of acid by conductometrically. 3. Which acid first neutralize &why. 4. By plotting graph how you calculate normality of acids. 5. After neutralization of both acids excess of NaOH added what is the effect on conductance 7 Department of Chemistry, MGMs, Jawaharlal Nehru Engineering College, Aurangabad

Experiment No: 03 Aim: To determine the relative viscosity of given liquid with respect to water at room temperature by Ostwald s viscometer. Apparatus: Viscometer, stopwatch, beaker, water bath, thermometer etc. Chemicals: Dist. Water, ethanol acetone etc. Theory: The property of resistance to flow when a stress is applied to a liquid is called Viscosity. In the process of flow the molecule comprising the fluid move fast one another and viscosity arises from what can the termed the frictional effect of relative motion. When the liquid is flowing to a circular tube the flow pattern is called streamlines or viscous or laminar. The viscosity is increased by increasing molecular weight and decrease by increasing the temperature. Formula: n = l 2 / l 1 t 2 /t 1 n 1 Procedure: l 1 = Density of H 2 O at 25 o c l 2 = Density of given liquid at t o c n 1 = Viscosity of water at t o c n 2 = Viscosity of given liquid at t o c t 1 = Time flow of given liquid at t o c 1) Clean the viscometer with chromic acid and then wash thoroughly with distilled water. It & finally washed with acetone and dried. 2) A sufficient volume of distilled water is introduced by pipette in bulb B so that the bent Portion of tube and half or a little more than a half of bulb B is filled up. 3) Clamp the viscometer in quite vertical position. 4) Trough the rubber tube attach to upper arm of bulb A, suck up water until it rises above the upper mark C and allow it to flow under its own weight. 5) The time of flow of water from C to D is continued by starting the stop watch as the Meniscus just reaches upper mark C and stopping the watch as the meniscus just passes the lower mark D. 6) Take at least three reading of water at different temperature. Also take the similar reading of ethanol at various temperatures. 8 Department of Chemistry, MGMs, Jawaharlal Nehru Engineering College, Aurangabad

Observation Table: Sr. No Different liquids Temperature Flow of time in sec. Density Viscosity 1 Ethanol 25 o c 0.998 2 Ethanol 50 o c 0.985 3 Water 25 o c 0.786 0.8004 4 Water 50 o c 0.773 0.5083 Calculations: ƞ 25 o c= l 2 /l 1 t 2 /t 1 n 1 w ƞ 50 o c= l 2 /l 1 t 2 /t 1 n 1 w Result: The relative viscosity of the liquid with respective with water at 25 0 C temperature is poise and at 50 0 C temperature is poise Question: 1. Define term viscosity. 2. What is effect of molecular weight on viscosity 3. Explain the another method used for determination of viscosity of liquid, 9 Department of Chemistry, MGMs, Jawaharlal Nehru Engineering College, Aurangabad

Experiment No: 04 Aim: Determination of total hardness of water by EDTA method. Apparatus: Beaker, conical flask, burette, pipette, standard flask etc. Chemicals: Calcium carbonate, EDTA, Buffer solution, EBT dye etc. Theory: In hard water sample the total hardness can be determined by titrating the Ca2+ and Mg2+ present in an aliquot of the water sample at ph10 with EDTA using EBT indicator. Permanent hardness can be determined by precipitating the temporary hardness by prolonged boiling followed by titration with EDTA solution. The difference in the titre values corresponds to the temporary hardness of the water sample. When Eriochrome Black-T dye is added to the hard water at ph around 10 it gives wine red colored unstable complex with Ca2+ and Mg2+ ions of the sample water. Now when this wine redcolored complex is titrated against EDTA solution (of known strength) the color of the complex changes from wine red to original blue color showing the end point. Reaction: HO HO O C C O H 2 C C H 2 N H 2 C H 2 C H 2 C N H 2 C O C C O OH OH EDTA Ethylene diamine tetra-acetic acid Ca2+ + Erinchrome Black T Ca2+ Erinchrome Black T Complex Mg2+ Mg2+ of water Unstable complex (wine red) Ca2+ Mg2+ Erinchrome Black T Complex Ca2+ Mg2+ EDTA Complex + Erinchrome Black T Unstable complex (wine red) Blue (Stable complex) 10 Department of Chemistry, MGMs, Jawaharlal Nehru Engineering College, Aurangabad

Procedure: Standardization of EDTA solution with standard hard water: 1. Take 10 ml of standard hard water in a conical flask. 2. Add 3 ml of buffer solution and 2 to 3 drops of EBT indicator, the color of solution turns wine red. Titrate the flask solution against standard EDTA solution from the burette until the color changes from wine red to blue at the end point. Take at least two concordant readings. Let the volume of EDTA solution used = V 1 ml 3. Titrate similarly unknown hard water and find out volume of EDTA solution used. Let the volume of EDTA used with unknown hard water = V 2 ml 4. Take 250 ml of the hard water sample in 500 ml beaker & boil gently for about one hour, cool, filter into a 250 ml measuring flask & make the volume up to the mark with distilled water. Take 10 ml of this solution and proceed in the same way as in step (2). The volume of EDTA used (V 3 ) corresponds to permanent hardness of the water sample. Temporary hardness is calculated by subtracting permanent hardness from total hardness. Let volume used = V 3 ml Observation Table: 1. For standard Hard water: - Sr.No. Volume of Standard Hard Water taken in conical Flask A (ml) Volume of EDTA solution used up (ml) Mean (V 1 ml) 1 10 ml 2 10 ml 3 10 ml 2. For unknown Hard Water: - Sr.No. Volume of Sample Hard Water taken in conical Flask A (ml) Volume of EDTA solution used up (ml) Mean (V 2 ml) 1 10 ml 2 10 ml 3 10 ml 11 Department of Chemistry, MGMs, Jawaharlal Nehru Engineering College, Aurangabad

3. For Boiled Water: - Sr.No. Volume of Boiled Water taken in conical Flask A (ml) Volume of EDTA solution used up (ml) Mean (V 3 ml) 1 10 ml 2 10 ml 3 10 ml Calculations:- 1) Standardization of EDTA solution:- 2) Total Hardness:- 1 ml EDTA = 1 mg Ca ++ 1ml of 1M EDTA=100mg of CaCO 3 1ml of 1M EDTA=100mg of CaCO 3 V1 ml of 0.01M of EDTA=------of CaCO 3 =V 1 100 0.01 1 10ml of EDTA=------mg of CaCO 3 1000ml of EDTA=----- mg of CaCO 3 3) Permanent Hardness = 4) Temporary hardness = Total hard. - Permanent hard 1ml of 1M EDTA=100mg of CaCO 3 V2 ml of 0.01M of EDTA=------of CaCO 3 =V 2 100 0.01 1 10ml of EDTA=------mg of CaCO 3 1000ml of EDTA=----- mg of CaCO 3 Result: The given water sample contains, Temporary hardness =. ppm. Permanent Hardness = ppm. Total Hardness = ppm. 12 Department of Chemistry, MGMs, Jawaharlal Nehru Engineering College, Aurangabad

Questions: 1. What is the other name for temporary and permanent hardness? 2. What is mean by Hardness of water? 3. Which factor responsible for hardness. 4. What is unit of hardness? 5. Complete the reaction. Mg (HCO 3 ) 2 Boil? 13 Department of Chemistry, MGMs, Jawaharlal Nehru Engineering College, Aurangabad

Experiment No: 05 Aim: To find the normality and strength of given hydrochloric acid solution by titrating against standard sodium carbonate solution. Apparatus: Conical flask, Beaker, Pipette, Burette, Weighing balance, Std. flask etc Chemicals: Hydrochloric acid, Std. Sodium carbonate, Phenolphthalein indicator, distilled water etc. Theory: An acid base titration is the determination of the concentration of an acid or base by exactly neutralizing the acid or base with an acid or base of known concentration. This allows for quantitative analysis of the concentration of an unknown acid or base solution. It makes use of the neutralization reaction that occurs between acids and bases. Before starting the titration a suitable ph indicator must be chosen. The point at which the indicator changes color is called the end point. A suitable indicator should be chosen, preferably one that will experience a change in color (an end point) close to the equivalence point of the reaction. Reaction: 2 HCl + Na 2 CO 3 2 NaCl + H 2 0 + CO 2 Procedure: 1. A burette is washed with water and rinsed with the given Na 2 CO 3 solution. The burette is filled with the Na 2 CO 3 solution, the tap is opened and the nozzle of the burette also is filled with the base. After air bubbles have escaped, the level of the base is brought to the zero mark. 2. A pipette is washed with water and rinsed with the HCl solution. Pippet out 10 ml of HCl solution into a clean conical flask. 3. Add one or two drops of phenolphthalein to the solution in the conical flask. 4. Standard sodium carbonate solution from the burette is added to the HCl solution in the conical flask, drop by drop. Meanwhile the flask is kept gently shaking. 5. The addition of the sodium carbonate solution is stopped when the solution acquired light pink color. This is the end point of the titration. 6. The final reading of the burette is noted and the titration is repeated to get concordant values. 14 Department of Chemistry, MGMs, Jawaharlal Nehru Engineering College, Aurangabad

Observation Table: Sr. No Volume of HCl (in ml) Burette reading (in ml) Initial Final Difference Mean 1 2 3 Calculations: 1) N 1 V 1 = N 2 V 2 HCl = Na 2 CO 3 N 1 10 = 0.3 V 2 3) Strength of HCl = N 1 Eq. Wt Result: 5. The Normality of given hydrochloric acid is = N 6. Strength of hydrochloric acid in given solution is =.. gr/lit Question - 5. What is acid-base titration? 6. What is the role of indicator in acid base titration? 7. Give any two examples of inorganic acids and bases. 15 Department of Chemistry, MGMs, Jawaharlal Nehru Engineering College, Aurangabad

Experiment No: 06 Aim: To determine the normality and strength of given KMnO4 solution by titrating it with Mohr s salt (Ferrous Ammonium Sulphate). Apparatus: Conical flask, Beaker, Pipette, Burette, Weighing balance, Std. flask etc Chemicals: Sulphuric acid (dilute), Ferrous ammonium sulphate solution (N/10), KMnO 4 solution, Distiied water etc. Theory: Ferrous ammonium sulphate is a stable salt and is a primary standard. When Fe 2+ ions are titrated with permanganate solution, then it will get oxidized to Fe 3+ ions. Fe 2+ Fe 3+ - = 0.77 V The overall ionic equation of the titration can be obtained by adding two half reactions (oxidation half reaction and reduction half reaction). [Fe 2+ Fe 3+ + e - ] 5 MnO - 4 + 8 H + + 5e - Mn 2+ + 4H 2 O MnO - 4 + 8 H + + 5Fe 2+- 5Fe 3+ + Mn 2+ + 4H 2 O It is clear from the above equation that one mol of potassium permanganate reacts with 5 mol of ferrous ions. KMnO4 is pink in color and Mn (II) ions are almost colorless. Hence, KMnO4 itself act as an self indicator. As soon as the end point is reached, addition of few drops of FAS disappears the pink color of solution. Reaction: 2 KMnO 4 + 3 H 2 SO 4 K 2 SO 4 + 2MnSO 4 + 3H 2 O + 5[O] 2FeSO 4 (NH4) 2 SO 4.6H 2 O + H 2 SO 4 + [ O ] Fe 2 (SO 4 ) 3 + 2(NH 4 )2SO 4 + 13H 2 O] 5 MnO 4 - + 8 H + + 5Fe 2+- 5Fe 3+ + Mn 2+ + 4H 2 O 16 Department of Chemistry, MGMs, Jawaharlal Nehru Engineering College, Aurangabad

Procedure: 1. Rinse and fill the burette with the given Mohr s salt solution and set the initial burette reading as zero. 2. Pipette out 10 ml of the given KMnO 4 solution into a conical flask and add one test tube (~10ml) of dilute sulphuric acid into it. 3. Titrate it against the Mohr s salt solution till the pink color of the solution in the conical flask disappears. This is end point of titration. 4. The final reading of the burette is noted and the titration is repeated to get concordant values. Observation Table: Sr. No Volume of KMnO 4 Solution (in ml) Burette reading (in ml) Initial Final Difference Mean 1 2 3 Calculations: 1) N 1 V 1 = N2V2 KMnO 4 = Mohrs Salt N 1 10 = 0.1 V 2 2) Strength of KMnO 4 = N 1 Eq. Wt of KMnO 4 Result: 1. The Normality of given KMnO 4 is = N 2. Strength of KMnO 4 in given solution is =.. gr/lit 17 Department of Chemistry, MGMs, Jawaharlal Nehru Engineering College, Aurangabad

Experiment No: 07 Aim: To determine molarity of hydrochloric acid ph metrically by using M/10 sodium hydroxide solution. Apparatus: ph meter with glass electrode, Magnetic stirrer, Beaker, Pipette, Burette, etc Chemicals: Hydrochloric acid, Sodium hydroxide, distilled water etc. Theory: The ph value of solution is defined as negative logarithm of hydrogen ion concentration. It is expressed in gram/ion lit. ph = -log [H + ] Measurement of ph is also employed to monitor the course of acid-base titration. The ph value of solution at different stages of acid-base neutralization is determined and is plotted against the volume of acid / alkali added. On adding a base to an acid the ph rises slowly in the initial stages then it changes rapidly at the end point. The end point of titration can be detected, where the ph changes most rapidly. However the shape of inflection point and symmetry of the curve on its two sides depends upon ionization of acid and base used and on the basicity of acid and acidity of the base. Reaction:- Procedure: HCl + NaOH NaCl + H 2 0 1. Standardize the ph meter using buffer solution of different ph. 2. Clean the electrode by using distilled water and dry it. 3. Take 10 ml of hydrochloric acid solution in 100 ml beaker and immerse the electrode. 4. Set up burette containing standard sodium hydroxide solution. 5. Note down the initial ph of solution. 6. From the burette add 0.3 N NaOH solution in 0.5 ml lots with continuous stirring and measure the ph of solution at each 0.5ml addition of NaOH. 7. Plot a graph between ph values along y-axis against the volume of alkali added along x-axis. 8. The amount of alkali required for neutralization of acid is calculated from the graph. 18 Department of Chemistry, MGMs, Jawaharlal Nehru Engineering College, Aurangabad

Observation Table: Sr. No. Volume of NaOH added (in ml) ph of solution 1 0 ml 2 0.5 ml 3 1 ml 19 9 ml 20 9.5 ml Calculations: 1) M 1 V 1 = M 2 V 2 HCl = NaOH M 1 10 = 0.3 V 2 Result: Molarity of given hydrochloric acid is = M Questions: 1. Define the term ph? 2. What are the methods available for determining ph of solution? 3. How the ph of solution is determined using standard hydrogen electrode. 4. Give any four applications of ph metry. 19 Department of Chemistry, MGMs, Jawaharlal Nehru Engineering College, Aurangabad

Experiment No: 08 Aim: To determine the surface tension of given liquid at room temperature by stalagmometer. Apparatus: Stalagmometer, Specific gravity bottles, Piece of rubber tubing with screw clip. Chemicals: Given liquid, water etc. Theory: The Surface tension is the characteristic property of every liquid. It is due to intermolecular attractions among molecules of liquid. It is defined as the force in dynes acting at right angle to the surface of the liquid. The Surface tension of the given liquid is determined relative to water the room temperature by Stalagmometer. The number of drops for the same volume of water and the given liquid at are counted and let these be as n1 and n2 resp. Now if d1and d2 are densities of water and the given liquid the room temperature as determined separately by using specific gravity bottle or pyknometer, then the surface tension γ 2 of the given liquid can be calculated by using the formula; γ 2/ γ 1 = n 2 /n 1 d 1 /d 2 Where, n 1 =No. of drops of water counted n 2 = No. of drops of given liquid counted d 1 = Density of water d 2 = Density of given liquid γ 1 = Surface tension of water γ 2 = surface tension of given liquid Fig. 1 Stalagmometer Procedure: 1. Clean the Stalagmometer and specific gravity bottles first with chromic acid solution and wash finally with distilled water and then dry. 2. Immerse the lower end of Stalagmometer in a beaker containing distilled water, suck up water until it rises above the mark and tighten the screw of the screw-pinch. 3. Now loosen the screw of the screw-pinch carefully so that the liquid drops starts falling at an interval of about 2-3 seconds in successive drops. Counting of drops is started when the water 20 Department of Chemistry, MGMs, Jawaharlal Nehru Engineering College, Aurangabad

meniscus just reaches the upper mark and stopped when the meniscus just passes the lower mark. Repeat to get three readings and take the mean value. 4. Clean the Stalagmometer and dry it. Fill it with given liquid until it rises above the upper mark and count the number of drops as previously noted. 5. Clean and dry the specific gravity bottle and measure the density of liquid. Observation Table: Liquid Number of drops 1 2 3 Mean Value Water n 1 = Given liquid n 2 = Physical constants of water at different temperatures: Temperature Density Surface Tension dynes/cm Viscosity centipoise 22 C 0.9978 72.44 0.9579 23 C 0.9975 72.28 0.9358 24 C 0.9973 72.13 0.9142 25 C 0.9970 71.97 0.8970 26 C 0.9968 71.82 0.8737 27 C 0.9965 71.66 0.8545 28 C 0.9962 71.50 0.8360 Calculations: Result: γ 2/ γ 1 = n 2 /n 1 d 1 /d 2 The relative surface tension of liquid with respect to water at room temperature = - - - - dynes/cm 21 Department of Chemistry, MGMs, Jawaharlal Nehru Engineering College, Aurangabad

Questions: 1. Define surface tension 2. What are units of surface tension in C.G.S. and S.I. (M.K.S.) system? 3. What are cohesion and adhesion force? 4. What are the factors affecting the surface tension? 5. Define angle of contact. 22 Department of Chemistry, MGMs, Jawaharlal Nehru Engineering College, Aurangabad