Using Potential Energy

Similar documents
B 20 kg. 60 kg A. m s, m k

Picking Coordinate Axes

1. A man pulls himself up the 15 incline by the method shown. If the combined mass of the man and cart is 100 kg, determine the acceleration of the

AQA Maths M2. Topic Questions from Papers. Circular Motion. Answers

SOLUTIONS TO CONCEPTS CHAPTER 6

Homework 3 MAE 118C Problems 2, 5, 7, 10, 14, 15, 18, 23, 30, 31 from Chapter 5, Lamarsh & Baratta. The flux for a point source is:

DYNAMICS. Kinetics of Particles: Newton s Second Law VECTOR MECHANICS FOR ENGINEERS: Ninth Edition CHAPTER. Ferdinand P. Beer E. Russell Johnston, Jr.

CHAPTER 29 ELECTRIC FIELD AND POTENTIAL EXERCISES

CHAPTER? 29 ELECTRIC FIELD AND POTENTIAL EXERCISES = 2, N = (5.6) 1 = = = = = Newton

U>, and is negative. Electric Potential Energy

Energy Dissipation Gravitational Potential Energy Power

Section 35 SHM and Circular Motion

Topic 6b Finite Difference Approximations

Answers to test yourself questions

SOLUTIONS TO CONCEPTS CHAPTER 11

GEOMETRY Properties of lines

DEPARTMENT OF CIVIL AND ENVIRONMENTAL ENGINEERING FLUID MECHANICS III Solutions to Problem Sheet 3

10.3 The Quadratic Formula

(a) Counter-Clockwise (b) Clockwise ()N (c) No rotation (d) Not enough information

Spring-Pendulum Dynamic System

EN40: Dynamics and Vibrations. Midterm Examination Tuesday March

does NOT exist. WHAT IF THE NUMBER X APPROACHES CANNOT BE PLUGGED INTO F(X)??????

Chapter 7. Kleene s Theorem. 7.1 Kleene s Theorem. The following theorem is the most important and fundamental result in the theory of FA s:

X Fx = F A. If applied force is small, book does not move (static), a x =0, then f=f s

106 PHYS - CH6 - Part2

Phys101 Lecture 4,5 Dynamics: Newton s Laws of Motion

Chapter Primer on Differentiation

Homework: 5, 9, 19, 25, 31, 34, 39 (p )

Solutions to Midterm Physics 201

1 Lecture 13: The derivative as a function.

On my honor, I have neither given nor received unauthorized aid on this examination.

Differentiation Rules c 2002 Donald Kreider and Dwight Lahr

ME 236 Engineering Mechanics I Test #4 Solution

Problem Set 5: Universal Law of Gravitation; Circular Planetary Orbits

13.5. Torsion of a curve Tangential and Normal Components of Acceleration

Mark Scheme (Results) January 2008

Lecture 4. Electric Potential

Moment of inertia - Steiner's theorem

Physics Honors. Final Exam Review Free Response Problems

University of Alabama Department of Physics and Astronomy PH 101 LeClair Summer Exam 1 Solutions

0.1 Differentiation Rules

HOMEWORK HELP 2 FOR MATH 151

INTRODUCTION AND MATHEMATICAL CONCEPTS

Chapter 21: Electric Charge and Electric Field

Radial geodesics in Schwarzschild spacetime

6. Gravitation. 6.1 Newton's law of Gravitation

Lecture 10. Solution of Nonlinear Equations - II

Econ 401A Three extra questions John Riley. Homework 3 Due Tuesday, Nov 28

Electric Potential and Energy

SECTION 2.1 BASIC CALCULUS REVIEW

This immediately suggests an inverse-square law for a "piece" of current along the line.

Chapter 2 Differentiation

Derivatives of trigonometric functions

Tutorial on Strehl ratio, wavefront power series expansion, Zernike polynomials expansion in small aberrated optical systems By Sheng Yuan

10 m, so the distance from the Sun to the Moon during a solar eclipse is. The mass of the Sun, Earth, and Moon are = =

Differential Calculus: Differentiation (First Principles, Rules) and Sketching Graphs (Grade 12) *

PHY 5246: Theoretical Dynamics, Fall Assignment # 5, Solutions. θ = l mr 2 = l

Chapter 1. Model Theory

Chapter 2. Review of Newton's Laws, Units and Dimensions, and Basic Physics

Exam 1: Tomorrow 8:20-10:10pm

ELECTROSTATICS. 4πε0. E dr. The electric field is along the direction where the potential decreases at the maximum rate. 5. Electric Potential Energy:

Electric Potential. and Equipotentials

1 Review: Volumes of Solids (Stewart )

Ch 26 - Capacitance! What s Next! Review! Lab this week!

Math Week 5 concepts and homework, due Friday February 10

WordsWorth Plus 1 to 26

Physics 111. Uniform circular motion. Ch 6. v = constant. v constant. Wednesday, 8-9 pm in NSC 128/119 Sunday, 6:30-8 pm in CCLIR 468

School of Electrical and Computer Engineering, Cornell University. ECE 303: Electromagnetic Fields and Waves. Fall 2007

Forging Analysis - 2. ver. 1. Prof. Ramesh Singh, Notes by Dr. Singh/ Dr. Colton

Chapter 28 Sources of Magnetic Field

Chapter 2. Numerical Integration also called quadrature. 2.2 Trapezoidal Rule. 2.1 A basic principle Extending the Trapezoidal Rule DRAWINGS

(A) 6.32 (B) 9.49 (C) (D) (E) 18.97

4.2 - Richardson Extrapolation

PhyzExamples: Advanced Electrostatics

Problem Set 7: Potential Energy and Conservation of Energy AP Physics C Supplementary Problems

CHAPTER 18: ELECTRIC CHARGE AND ELECTRIC FIELD

OH BOY! Story. N a r r a t iv e a n d o bj e c t s th ea t e r Fo r a l l a g e s, fr o m th e a ge of 9

The Wave Equation I. MA 436 Kurt Bryan

1. Viscosities: μ = ρν. 2. Newton s viscosity law: 3. Infinitesimal surface force df. 4. Moment about the point o, dm

Topics for Review for Final Exam in Calculus 16A

INTRODUCTION AND MATHEMATICAL CONCEPTS

2.3. Applying Newton s Laws of Motion. Objects in Equilibrium

1 Using Integration to Find Arc Lengths and Surface Areas

2.11 That s So Derivative

Electricity & Magnetism Lecture 6: Electric Potential

Rules of Differentiation

A 2 ab bc ca. Surface areas of basic solids Cube of side a. Sphere of radius r. Cuboid. Torus, with a circular cross section of radius r

Equations to Calculate Characteristic Frequencies of Multiple Chamber Aligned in Parallel Cavity Resonator (MCAP-CR)

1 Power is transferred through a machine as shown. power input P I machine. power output P O. power loss P L. What is the efficiency of the machine?

Physics 1502: Lecture 2 Today s Agenda

Math 242: Principles of Analysis Fall 2016 Homework 7 Part B Solutions

On the Eötvös effect

Optimization. x = 22 corresponds to local maximum by second derivative test

1 ode.mcd. Find solution to ODE dy/dx=f(x,y). Instructor: Nam Sun Wang

Chapter 1 Functions and Graphs

Homework Set 4 Physics 319 Classical Mechanics. m m k. x, x, x, x T U x x x x l 2. x x x x. x x x x

Chapter 36. a λ 2 2. (minima-dark fringes) Diffraction and the Wave Theory of Light. Diffraction by a Single Slit: Locating the Minima, Cont'd

Fluids & Bernoulli s Equation. Group Problems 9

COMP 465: Data Mining More on PageRank

(4.2) -Richardson Extrapolation

Transcription:

Using Potentil Enegy You ve job poviing te engineeing elp o n citect in Coloo. You e cuently esigning cble tow to pull sies up ill so tey cn si own. e custoe woul lie te cble tow to pull sie upill t constnt cceletion o te botto ecing spee o 6 /s t te top. You nee to eteine wt type o cble you soul pucse. e ill is 5 long n incline t egees o te oizontl. By esuing sie spees on ownill un, you now tee is iction oce o 5 between te sis n te snow inepenent o te sie s weigt. FOCUS v o = F =5 Question: t is te oce on te cble? Appoc: o 5 v = 6 /s Use consevtion o enegy to elte te inl spee n te oces. Inclue te Et in te syste n use gvittionl potentil enegy Initil tie: just te gbs te ope t botto Finl tie: just s sie gets to te top e ope oce (), n te ictionl oce () ve coponents long te isplceent. Enegy tnse occus Coose one xis long te si slope Migt nee to estite ss o sie PHYSICS DESCRIPIO Fee boy ig y i Enegy ig vi = xi Foce ig Syste: sie + Et x get untity: oizontl initil stte Enegy tnse inl stte y i = = v = 6 /s vi = = 5 = 5 Geoety v Quntittive eltionsips: Consevtion o Enegy E - Ei = Einput - Eoutput Syste enegy is inetic + potentil E i = KE i + GPE i = + E = KE + GPE = v + g Enegy tnsee to n o syste Einput = Eoutput = l = l = l = l = l = l = Consevtion o Enegy v +g- = - Pln: Fin Consevtion o enegy v +g- = - Fin sin = 3, eutions v + gsin = - v +gsin + = ee to estite te sie s ss i it oes not cncel out. Mss o sie oes not cncel Estite it t g, v +gsin + = Cec units [] = [oce], [] = [oce], [g sin ] = [oce] [ v ] = [ss] [ / s ] [] = [ss] [cceletion] = [oce] o ll units e oce units = ( 5 ) ( g) (6 / s ) + ( g) (9.8 / s ) sin + (5 ) 36 + 335 + 5 = = 5 Se s beoe

A ien s cil is plying wit toy cs n you ecie to elp by builing loop-te-loop tc. You stt c on te enty tc bove te igest point on te cicul pt o te tc. e c goes own te enty tc oun te cicle n up n exit tc. Bse on te stting eigt o te c, you ecie to clculte te spee o te c wee it entes te cicul pt o te tc s well s t te top o te cicul pt o te tc n on te exit tc c bove wee you stte. v = c Exple v c c b v b Use consevtion o enegy. syste: object + Et E i = KE i +PE i Fo to b E i = g E = v b E - E i = DE tnse DE tnse = v b - g = v b = E = KE +PE g Assue iction n i esistnce not ipotnt Initil tie t top o entnce p. Assue te c stts o est. Finl tie t botto o cicle. Fo to c E i = g E = v c + g c v c + g c - g = v c = g - g c Fo to E i = g E = v + g v + g - g = v v = v c = g - c = g - g ( ) g( - ) > not possible Mxiu eigt wen KE = All enegy is PE Mxiu eigt is initil eigt i initil KE = o enegy input Exple You copny s been ie to esign stunt o new ice sow. e st o te sow entes by iing on sle wic stts o est t te top o cuve ice tc bove te suce o te ice in. e tc les own to te in n, t tt point, becoes veticl cicle wic etuns gin to te in. You job is to clculte te xiu ius o te cicle so tt tis ing loop-te-loop cn be one witout injuing te ig pice st. Assue tt you cn neglect iction n i esistnce s ist ppoxition. v o = v t t is te lgest ius suc tt cicul otion is possible? = v Mxiu ius ens iniu cceletion Acceletion cnnot be slle tn g t top o cicle Get cceletion o oces on sle. Get velocito consevtion o enegy Syste: sle + Et Gvittionl potentil enegy Initil tie: stt t top o tc. Finl tie: t top o cicle Ignoe iction, i esistnce v Fee-boy Dig o sle t top o cicle F G F y = y iniu cceletion ens iniu oce Initil Enegy v o = = = v o = =? F y = -F G - F y (in iu ) = F G -g= - (iniu) = g Finl Enegy y t v t y t = v t =? E i = KE i +PE i = g E = KE + PE = v t + gyt

Consevtion o Enegy: E - E i = E in - E out v t +gy t -g = get: Fin v t + g( )- g = v t +g Fin v t = v t Fin g = ( ) - g = v t 3 3, 3 eutions o [3] into [] g = v t g = v t g + g ( )-g = + ( ) - = 5 = = 8 Into [] units e o bot sies istnce units e xiu eigt o te sle wen tvelling oun te cicle is 6, less tn te initil eigt o. is is esonble since soe o te initil potentil enegy s becoe inetic enegy t te top o te cicle. Exple A sie stts o est on te slope on suit n ten sis ove two successively lowe ills o eigt n. e lowest ill is essentilly sei-cicle centee t eigt. e sie wnts to leve te lowest ill t its top n ly toug te i n ss you ow up te slope to stt gliing own te ill. Assue iction n i esistnce e negligible. v o = t is te initil eigt o te sie to leve te secon ill t its top? Sie stys on ill i te oces on te sie give te cceletion necessy to go in cicle. = v Get te spee on te top o te ill o consevtion o enegy. Syste: sie + Et Initil tie: stt on slope Finl tie : top o n ill Get te necessy cceletion o oces v Fee-boy Dig o sie on top o lst ill I sie leves te ill = - g = - Initil Enegy v o = - = - Fo te sie to ollow te cicul ill =? v o = = =? E i = KE i +PE i = g DE tnse = = v Finl Enegy v v =? E = KE + PE = v Consevtion o Enegy E - E i = DE tnse v -g = tget: Fin v - g = Fin v = v Fin g = 3, 3 eutions [3] into [] [] [3] [] g = v g = v g - g = = into [] v coect units bot sies e istnces = 5 bove te top o te ill But tt will not get you ove te st ill ee to be t eigt o t lest up te slope

Exple Fo you lbotoy expeience, you now it is iicult to esue te coeicient o inetic iction between two suces. One o you lb ptnes suggest using sping to popel bloc up p incline t n ngle o te oizontl tt you esue. e bloc is to be el ginst sping, copessing te sping istnce o its elxe position tt you esue. en te bloc is elese, te sping expns n puses te bloc upw long te p. e bloc leves te sping, going istnce up te incline tt you lso esue? You cn lso esue te ss o te bloc n te sping constnt. ill tis poceue give you wt you wnt? v o = v = t is te coeicient o inetic iction? Fee boy ig µ Use consevtion o enegy: syste: bloc, Et, n sping Potentil Enegy: sping, gvittionl Enegy tnse: iction Initil tie: just te elese o copesse sping Finl tie: just wen bloc stops Get ictionl oce o ynics - y = y = -g cos = +z z o +z z z o Initil ie Finl ie v = x o x s E i = KE i + PE i = x E = KE + PE = g Consevtion o Enegy: tget: v o = Enegy nse v x o E out = x g - = - x g - = - x E - E i = E in - E out Fin = Fin -g cos = Fin g - = - Fin sin = Geoety Pln [4] [] [] [3], 4, 4 eutions Execute te pln o te botto up. Put [4] into [3] n solve o g sin - = - - g sin + = Put into [] long wit [] n solve o - g sin + = g cos -g sin + = g cos cec units [ oce ] + oce is tn ce [ is tn ce] [ ] [ oce ] Coect, s no units = [ ] How to Solve Pobles Using Enegy. Pictue te sitution t is te syste? How is it oving? Is tee enegy tnse? t pt oes te object tvel? Is tee potentil enegy? Ceully ientiy te initil tie n te inl tie you wnt to consie. Cn you ccount o ll o te enegy o you syste t tose ties? KE + PE Cn you ccount o ll enegy tnses between tose ties? l E = tnse F l l o

. Deine you untities wit espect to coointe syste. Me sue you now wic iection is + n wic is -. Foce, position Use you eine untities to wite own te consevtion o enegy eution o you syste. Keep tc o te signs. Keep tc o te tget untity. Do you nee to now nyting else in ition to consevtion o enegy? 3. Ientiy ll in you consevtion o enegy eution n elte te by eutions to ote inotion o pinciples pysics. 4. Solve te syste o eutions to get you tget untity. 5. Cec you nswe Coect units? Resonble bevio o vlue? Di you nswe te uestion? Foce lws Kinetics